what is 23,995 rounded to the nearest ten​

Based on the task content given; the solution to the equation for x 3 1/2(2 1/5x - 4 2/3) - 5 5/6 = 0 is 2 203/231

3 1/2(2 1/5x - 4 2/3) - 5 5/6 = 0

(3 1/2 × 2 1/5x) - (3 1/2 × 4 2/3) - 5 5/6 = 0

(7/2 × 11/5x) - (7/2 × 14/3) - 35/6 = 0

77/10x - 98/6 - 35/6 = 0

77/10x = 98/6 + 35/6

77/10x = 98+35 / 6

77/10x = 133/6

x = 133/6 ÷ 77/10

= 133/6 × 10/77

= 1330/462

x = 2 406/462

= 2 203/231

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Answer: 389 is the square root.

Answer:

389 is the square root

Step-by-step explanation:

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Answer: -2

Step-by-step explanation:

The graph passes through (-2, 3) and (4, -9).

So, the average rate of change is [tex]\frac{-9-3}{4-(-2)}=\boxed{-2}[/tex]

Answer:

3.36 cm

Step-by-step explanation:

24 - 5 1/2 = 18.5

To find the distance on the map, we can set up a proportion:

1 cm / 5.5 miles = x cm / 18.5 miles

5.5 times 37/11 equals to 18.5; 1 times 37/11 is approximately equals to 3.36 cm (rounded to the nearest hundredths).

Answer:

Step-by-step explanation:

The area of the shaded region is 8.1838. The area of the shaded region is calculated by subtracting the area of the triangle from the area of the sector of the circle.

The area of the sector of a circle with a radius 'r' and an angle of sector 'θ' is

A = (θ/360) πr² sq. units

The area of the triangle with measures of two sides and an angle between them is

A = 1/2 × a × b × sinC sq. units

Where a and b are the lengths of sides and ∠C is the angle between those sides.

It is given that,

The area of the sector shown in the diagram is 78.6794 cm² and the area of the triangle is 70.4956 cm².

Then to calculate the area of the shaded region, subtract the area of the sector and the area of the triangle. I.e.,

Area of the shaded region = Area of the sector - Area of the triangle

⇒ 78.6794 - 70.4956

⇒ 8.1838 cm²

Therefore, the required area of the shaded region is 8.1838 sq. cm.

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The simplification of a³ - 1000b³ and 64a³ - 125b³ is (a - 10b) × (a² + 10ab + 100b²) and 4a - 5b) • (16a² + 20ab + 25b²) respectively.

Question 1: a³ - 1000b³

a³ - b³

= (a-b) × (a² +ab +b²)

So,

(a - 10b) × (a² + 10ab + 100b²)

Question 2: 64a³ - 125b³

a³ - b³

= (a-b) × (a² +ab +b²)

So,

(4a - 5b) • (16a² + 20ab + 25b²)

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The correct proportion that can be used to find the actual distance  represented by 5 inches on the map is start fraction over 50 end fraction=start fraction 50 over 5 end fraction which is 3/50=5/x.

Given that 3 inches on a map represents 50 miles.

We are told to find the proportion which can be used to represent 5 inches.

Multiplication is basically finding the product of two numbers but it can be used to convert the units also.

If 3 inches represents 50 miles then,

1 mile=50/3

Multiply both sides by 5.

5 miles=5*50/3

If we see the options then we will get that the most appropriate and correct option which represents 5 inches is that start fraction over 50 end fraction=start fraction 50 over 5 end fraction which is 3/50=5/x.

Hence the correct proportion that can be used to find the actual distance represented by 5 inches on the map is start fraction over 50 end fraction=start fraction 50 over 5 end fraction which is 3/50=5/x.

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Answer:

B

Step-by-step explanation:

3/50 = 5/x

With the use of formula, the amount of Iodine-125 that would remain in the tumor after 60 days is 0.45 grams

First analyze the problem and represent them in exponential function. The decay rate is different from increase rate with minus and plus sign.

Given that a tumor is injected with 0.9 grams of Iodine-125, which has a decay rate of 1.15% per day. Let

An exponential model representing the amount of Iodine-125 remaining in the tumor after t days will be

A = I( 1 - R%)^t

Let us use the formula to find the amount of Iodine-125 that would remain in the tumor after 60 days by substituting all the given parameters into the formula

A = 0.9 ( 1 - 1.15/100)^60

A = 0.9 ( 1 - 0.0115)^60

A = 0.9 ( 0.9885)^60

A = 0.9 x 0.4995

A = 0.45 grams

Therefore, the amount of Iodine-125 that would remain in the tumor after 60 days is 0.45 grams

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The probability that exactly 3 of the chosen sandwiches are turkey is; 0.004

We are given;

Total number of sandwiches = 15

Number of sandwiches that were turkey = 6

Now, she selects 6 of the sandwiches and we want to find the probability that exactly 3 are turkey.

Now, number of ways of selecting 6 sandwiches is; 15C6

Number of ways of selecting 3 turkey's out of the 6 chosen is; 6C3

Thus, the probability that exactly 3 of the chosen sandwiches are turkey is; 6C3/15C6 = 20/5005 = 0.004

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The area based on the information illustrated will be 825 unit².

Your information is incomplete. Therefore, an overview will be given. It should be noted that area simply means the quantity which expresses the extent of the region on a plane as well as a curved surface. Based on this information, it should be noted that the area of a rectangle is given as:

Area = Length × Width

Let's assume that the width is 25 units and the length is given as 33 units.

Then, the area will be:

= Length × Width

= 33 × 25

= 825 units²

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Using the z-distribution, it is found that since the p-value of the test is less than 0.05, we reject the null hypothesis and find that there is enough evidence to conclude that the true proportion of all life insurance claims made to this company that are settled within 30 days is less than 85%.

At the null hypothesis, it is tested if there is not enough evidence that the proportion is below 85%, that is:

[tex]H_0: p \geq 0.85[/tex]

At the alternative hypothesis, it is tested if there is enough evidence that the proportion is below 85%, that is:

[tex]H_0: p < 0.85[/tex]

The test statistic is given by:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

In which:

For this problem, the parameters are:

[tex]p = 0.85, n = 250, \overline{p} = \frac{203}{250} = 0.812[/tex]

Hence the test statistic is:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

[tex]z = \frac{0.812 - 0.85}{\sqrt{\frac{0.85(0.15)}{250}}}[/tex]

z = -1.68

Using a z-distribution calculator, with a left-tailed test, as we are testing if the proportion is less than a value, and z = -1.68, the p-value is of 0.0465.

Since the p-value of the test is less than 0.05, we reject the null hypothesis and find that there is enough evidence to conclude that the true proportion of all life insurance claims made to this company that are settled within 30 days is less than 85%.

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If the probability of 1 is 0.5; 2 is 0.12; 3 is 0.12; 4 is 0.12; 5 is 0.12 then the graph is somewhat positively skewed and then becomes constant.

Given the probability of 1 is 0.5; 2 is 0.12; 3 is 0.12; 4 is 0.12; 5 is 0.12.

We are required to find whether the graph is constant,symmetric ,negatively skewed or positively skewed.

We can say that the graph is somewhat positively skewed and then it becomes constant.

Positively skewed graph is a graph in which more values exist at the left side of the graph means the tail is started in end.

Constant graph is a graph in which all the values are equal to each other.

In our case except the probability of 1 all the values are 0.12 and the probability of 1 is 0.5.

Hence if the probability of 1 is 0.5; 2 is 0.12; 3 is 0.12; 4 is 0.12; 5 is 0.12 then  the graph is somewhat positively skewed and then constant.

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Answer:

constant

Step-by-step explanation:

Answer:

  H

Step-by-step explanation:

Plane K is shown with two lines. Points on one of them are A, B, G. Points on the other one are G, M, N.

The point in plane K that is not shown on any line is point H.

A 0.13 sec and a 86 kVp technical changes are the changes that would have to produce the radiographic density and the contrast that are more similar to the original.

The radio graphic density can de defined to be the total amount or the overall darkening that can be found in a particular radiograph. This is usually known to have a certain type of density range that lies between  0.3 to 2.0 density.

When there is a density that is less than 0.3, the problem is basically because there is the issue of the density which would be found at the base and the fact that the film that is being used has fog in it.

It is known that based on the values that we have here the density and contrast would have to be of the given kvp of 86 and 0.13 seconds in order to be said to be similar to the original.

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The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

The function is positive when g(x) > 0.

Then we need to solve:

∛(x - 3) > 0

We can directly remove the cubic root, because it does not affect the sign of the argument, then:

x - 3 > 0

x > 3

The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

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The interval which the function is positive is (3, ∝)

The equation of the function is given as:

g(x) =∛x - 3

Set the radical greater than 0

x - 3 > 0

Add 3 to both sides of the inequality

x > 3

Express as an interval notation

(3, ∝)

Hence, the interval which the function is positive is (3, ∝)

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Answer: [tex]\Large\boxed{A.~y=3x+4}[/tex]

Step-by-step explanation:

Given information

Slope = 3

Point = (-3, -5)

Given the format of the equation

Slope-intercept form: y = mx + b

Substitute values into the equation

y = (3)x + b

y = 3x + b

Substitute the given point into the equation to get the value of [ b ]

(-5) = 3(-3) + b

-5 = -9 + b

b = -5 + 9

b = 4

Therefore, the equation of the line is [tex]\Large\boxed{y=3x+4}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

10

Step-by-step explanation:

the sequence follows the rule of adding the number and then the number -1 depending on the number before it. for example, you can see in order to get from 2 to 2, it adds 0 or subtracts by 0. After that to get from 2 to 4, you add 2. After that, you subtract 1 from 2 and you subtract that number which is 1 from 4 to get 3 and so on. Following that rule, you get 10 as the next number in the sequence

Answer:

5w^2 + 6w - 32

Step-by-step explanation:

Subtract as needed and combine like terms

(-2w^2 + 6w - 19) - (-7w^2 +13) dont forget to distribute the negative

so you get this:

-2w^2 + 7w^2 = 5w^2

6w

-19 - 13 = - 32

your answer is 5w^2 + 6w - 32

hope this helps :)

Hi :)

Let's solve by combining like terms

Combining like terms means you add or subtract

Solve by combining like terms

[tex]\implies\darkblue\sf{-2w^2+6w-19-(-7w^2+13)}\\\implies\darkblue\sf{-2w^2+6w-19+7w^2-13}\\\implies\darkblue\sf{-2w^2+7w^2+6w-19-13}\\\implies\darkblue\sf{\underline{5w^2+6w-32}}[/tex]

[tex]\tt{Learn\:More;Work\:Harder}[/tex]

:)

Answer: B

Step-by-step explanation:

[tex]\frac{4+5i}{4i}\\ \\ =\frac{1}{4} \left(\frac{4+5i}{i} \right)\\\\=\frac{1}{4}((-i)(4+5i))\\\\=\frac{1}{4}(-4i-5i^2)\\\\=\frac{5-4i}{4}[/tex]

A null hypothesis (H₀) can be defined the opposite of an alternate hypothesis (H₁) and it asserts that two (2) possibilities are the same.

The test statistics can be calculated by using this formula:

[tex]t=\frac{x\;-\;u}{\frac{\delta}{\sqrt{n} } }[/tex]

Where:

For this study, we should use t-test and the null and alternative hypotheses would be given by:

H₀: μ = 7

H₁: μ < 7

[tex]t=\frac{6.3\;-\;7}{\frac{1.3}{\sqrt{13} } }\\\\t=\frac{-0.7}{\frac{1.3}{3.6056 } }[/tex]

t = -0.7/0.3606

t = -1.941.

For the p-value, we have:

P-value = P(t < -1.9412)

P-value = 0.0381.

Therefore, the p-value (0.0381) is greater than α = 0.01. Based on this, we should fail to reject the null hypothesis.

Thus, the final conclusion is that the data suggest the population mean is not significantly lower than 7 at α = 0.01, so there is statistically insignificant evidence to conclude that the population mean waiting time to be admitted into the hospital from the emergency room for patients at rural hospitals is equal to 7 hours.

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The ratio of grenadine syrup to 7-Up will be 1:8.

From the information given, we are told that Shirley Temple" drink is made by a 5 mixing 2 cups of 7-Up with 4 tablespoons of grenadine syrup.

The ratio of grenadine syrup to 7-Up will be:

4 tablespoon : 2 cups

Note that 1 cup = 16 teaspoon

4 : (2 × 16)

= 4:32

= 1:8

Therefore, the ratio of grenadine syrup to 7-Up will be 1:8.

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Based on the stem and leaf plots given, the correct stem and leaf plot for the first table on per capita income is the third stem and leaf diagram.

For the table on the basketball tornament, the correct stem and leaf plot would be the last one.

First look at the key to the bottom right of the plot to see how to interpret the data.

The key on the third stem and lead plot says 1 I 2 = 12,000. This means that every steam and lead pairing is in thousands.

Based on the income per capita being in thousands, this is the most likely stem and lead plot for the first table on income per capita.

The second table about basketball tornament appearances is on single and double digits. Only a small stem and leaf key will do.

Look at the number of appearances. The minimum is 1. On a stem and leaf, this is shown as 0 I 1. Options A and B don't have this so we go to Options C and D.

As established, Option C is for data in their thousands so it is out. The correct stem and leaf plot is therefore Option D.

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πx

Step-by-step explanation:

well pi is defined as the ratio of a circle's circumference to its diameter so just πx

The correct answer is  If x + 1 is odd, then x is even.

The converses of the conditional statement:

"If q then p" provides the converse statement to the conditional expression "If p then q."

The converse of the conditional statement is  If x + 1 is odd, then x is even.

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the answer is (-4,-1) and (1,-5)

Answer:

D

Step-by-step explanation:

x²-4x-12≤0

x²-6x+2x-12≤0

x(x-6)+2(x-6)≤0

(x-6)(x+2)≤0

x=6,-2

∴ value of x lies between -2 & 6

Check the picture below.

[tex]\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h~~=height\\ a,b=\stackrel{parallel~sides}{bases~\hfill }\\[-0.5em] \hrulefill\\ a=5\\ b=9\\ h=7 \end{cases}\implies \begin{array}{llll} A=\cfrac{7(5+9)}{2}\implies A=\cfrac{7(14)}{2} \\\\\\ A=49 \end{array}[/tex]

The answer is 235 because the weight is placed at the fulcrum

Linear equations are equations that have constant average rates of change, slope or gradient

The linear equation is given as:

T = 235 + 980d

A linear equation is represented as:

T = b + md

Where m represents the slope

So, we have

m = 980

This means that 980 represents the amount of Torque per meter

When the weight is placed at the fulcrum, the value of d is 0

So, we have

T = 235 + 980d

Evaluate

T = 235 + 980 * 0

This gives

T = 235

Hence, the answer is 235 because the weight is placed at the fulcrum

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