Option (d) acetylcholine is the right answer.
Acetylcholine is the chemical compound released by the motor-neuron axon terminals.
Acetylcholine:The parasympathetic nervous system, a portion of the autonomic nervous system (a branch of the peripheral nervous system), which contracts smooth muscles, widens blood vessels, increases body secretions, and decreases heart rate, uses acetylcholine as its primary neurotransmitter.The function of Acetylcholine: Acetylcholine is used at the neuromuscular junctions in the somatic nervous system to start motor neurons firing and control voluntary movements.Chemically speaking, acetylcholine is an organic chemical that is an ester of acetic acid and choline.
Process of acetylcholine:Choline acetyltransferase catalyzes the reaction in which acetyl coenzyme A (acetyl CoA, which is made from glucose) and choline are combined to form acetylcholine (CAT). Acetylcholine is one of the neuron's transmitters, and the existence of CAT in a neuron is clear evidence of this.To learn more about motor-neuron axon terminals visit:
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7. Which functional group is present in the following molecule?
A. An acid
B An aldehyde
C. An amide
D. An alcohol
Answer:
An amide.
Explanation:
Amides are functional groups, in which a carbonyl atom is linked by a single bond to a nitrogen atom and either a hydrogen or a carbon atom. These defining traits single this functional group out as an amide.
Two molecules of mercury oxide decompose into 2 molecules of mercury and 1 molecule of oxygen gas. Which of the following
equations correctly describes this reaction?
(A) Pro(s)-> Pr(s) + O(g)
(B) Mc₂O(s)-> 2 Mc(s) + O(g)
(C) 2 MnO(s)-> 2 Mn(s) + 20(g)
(D) 2 HgO(s)-> 2 Hg(1) + O₂(8)
Select one:
O a. A
O b. B
OC. C
O d. D
Answer:
D
Explanation:
Mercury is Hg. Most of these reaction do not involve Hg. Only D correctly shows a balanced equation with mercury (Hg).
(A) Pro(s)-> Pr(s) + O(g)
(B) Mc₂O(s)-> 2 Mc(s) + O(g)
(C) 2 MnO(s)-> 2 Mn(s) + 20(g)
(D) 2 HgO(s)-> 2 Hg(1) + O₂(8)
A solution is made by dissolving 6.93 grams of lead(II) nitrate into about 50 mL of water. The volume is then precisely brought up to 100 mL and the solution is saved as stock solution. A 50.0 mL aliquot* of this stock solution is then titrated with 0.222 M sodium phosphate. What would be the minimum number of milliliters (mL) of the the phosphate solution that are needed to completely precipitate (knock out) all the lead in this aliquot? (tolerance is ±0.1 mL)
6.32mL of phosphate solution is needed to completely neutralize the lead in this reaction.
What is a neutralization reaction?A neutralization reaction is defined as the reaction between an strong acid and strong base to produce a salt and water.
The process of the reacting given volume of acids or bases for the determination of the concentration or volume of the acid or base which is required for neutralization is known as titration in volumetric analysis.
The formula used to determine the volume of the acid is given below:
(Ca × Va) /(Cb × Vb) = Na/Nb
where,
where Ca is the concentration of lead nitrate
Cb is the concentration of sodium phosphate
Va is the volume of lead nitrate
Vb is the volume of sodium phosphate
Na is the moles of lead nitrate
Nb is the moles of sodium phosphate
Concentration of lead nitrate = m/V
= 6.931/(0.1 × 331.2)
= 0.0281 M
Ca = 0.222M
Cb = 0.0281M
Na = Nb = 1
Va = ( 0.0281 × 50) /0.222
= 6.32 mL.
Thus, 6.32mL of phosphate solution is needed to completely neutralize the lead in this reaction.
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What products are formed in the following reaction
The correct product from this reaction is the structure in option D.
What is a secondary amine?An amine is a compound that contains an alkyl group and an amino group. We know that we can obtain an amine from ammonia by replacing one or more hydrogen atoms with alkyl groups.
The compound as shown here is a secondary amine because two hydrogen atoms have been replaced with alkyl groups. We know that the reaction between the HCl and the amine produces an ionic compound owing to the fact that the nitrogen and the hydrogen from HCl are involved in a Dative bond.
As such, the correct product from this reaction is the structure in option D.
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Calculate the kf of ag(nh3)2 from ag (aq) e- ⇋ ag(s) e0= 0. 81 v ag(nh3)2 (aq) e- ⇋ ag(s) 2nh3(aq) e0= 0. 39 v enter number as e notation (e. g. 2. 34e6 or 4. 56e-4)
The kf of Ag(NH₃)₂ for the given equation is 2.786 x 10⁷.
What is kf value?kf value can be calculated by dividing the molal concentration with the freezing point of depression.
The reaction are given:
Ag+(aq) + e- ⇋ Ag(s) E0= 0.81 V
Ag(NH₃)₂ +(aq) + e- ⇋ Ag(s) + 2NH₃(aq) E0= 0.37 V
To get Kf of Ag(NH₃)₂ we will rearrange the above written equations
a. Ag +(aq) + e- ⇋ Ag(s) E0= 0.81 V
b. Ag(s) + 2NH₃(aq) ⇋ Ag(NH₃)₂ +(aq) + e- E0= - 0.37 V
Adding equation (a) and equation (b) we will get
Ag +(aq) + 2NH₃(aq) ⇋ Ag(NH₃)₂ + (aq) Eo = 0.81 -0.37 = 0.44 V
By the Ernst equation,
E = E° - 0.0591 logkf
Now Kf is calculated at equilibrium and at equilibrium E = 0,
The number of transfer of electron is 1 ( 1 e-) , n=1
E° = 0.44 V
Substituting all the values in Ernst equation
0 - 0.44 - 0.0591/ 1 logkf
logkf = 0.44/ 0.0591
kf = 10 (0.44/ 0.0591)
Kf = 2.786 x 10⁷
Hence, Kf of Ag(NH₃)₂ for the given equation is 2.786 x 10⁷.
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Which one of these molecules can be a reactant in a friedel-crafts reaction? a) aniline b) benzenesulfonic acid c) chloroethene d) bromobenzene e) p-bromonitrobenzen
The molecules can be a reactant in a Friedel-crafts reaction will be aniline .
The Lewis acid as well as the chlorine atom of such acid chloride form a complex during the Friedel-Crafts acylation reaction. Cleaving the complex's C-Cl link produces an acylium ion. The acylium ion undergoes resonance stabilized but also has a positive electrical charge upon that carbon atom.
The Friedel-Crafts alkylation reaction, an electrophilic aromatic substitution process, may add an alkyl to a benzene molecule. One illustration is the insertion of a methyl group into a benzene ring.
Therefore, the molecules can be a reactant in a Friedel-crafts reaction will be aniline .
Hence, the correct answer will be option (a)
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What process involves the addition of a hydrogen molecule to compounds containing multiple bonds?
The process which involves the addition of a hydrogen molecule to compounds containing multiple bonds will be known as hydrogenation reaction.
Unsaturated hydrocarbons are transformed into saturated hydrocarbons by the addition process when they interact with hydrogen gas and nickel. The term "hydrogenation reaction" is also employed to describe this process.
In the production of fats and oils, hydrogenation seems to be crucial for two reasons. It increases the oil's oxidative stability and turns liquid oils become semisolid or plastic fats for use in shortenings as well as margarine, among other things.
Therefore, the process which involves the addition of a hydrogen molecule to compounds containing multiple bonds will be known as hydrogenation reaction.
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number of oxygen atoms in 16 g of So2??
Now , we know that one mole of SO² Contains 2 Moles ( two ) of atoms of oxygen . Hence , 16 Grams of SO² Contains 0.5 Mole(s) of Oxygen
0.5
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Which spectroscopic tool would be best for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane?
1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.
The preferred method for determining or validating the structure of organic molecules or those containing protons is H NMR. When compared to other nuclei, a solution-state proton spectrum may be obtained relatively quickly, and it contains a wealth of knowledge regarding a compound's structure.
It can be calculated by simply counting the number of unique hydrogens on one side of the symmetry plane will give you the count of signals individual molecules emit in a 1H NMR spectrum.
Therefore, 1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.
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15. conjugated dienes routinely undergo 1,2 and 1,4 addition reactions with a variety of electrophilic reagents; this suggests that ___ are likely intermediates during these reactions
Conjugated dienes routinely undergo 1,2 and 1,4 addition reactions with a variety of electrophilic reagents; this suggests that electrophilic reagents are likely intermediates during these reactions.
Two double bonds and one single bond divide a conjugated diene into two halves. Nonconjugated (Isolated) Dienes have more than one single bond separating two double bonds. Two double bonds are joined to the same atom to form cumulated dienes.
Reagents that function by acquiring electrons or sharing electrons that once belonged to a foreign molecule are referred to as electrophilic reagents, or electrophiles, in some cases. Electrophiles are molecules with a positive charge and a lack of electrons that can react by exchanging electron pairs with nucleophiles, which have many electrons. Epoxides, hydroxy amines, nitroso and azoxy derivatives, nitrenium ions, and elemental sulfur are significant electrophiles.
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A current of 5. 68 a is passed through a Fe(NO3)2 solution. How long, in hours, would this current have to be applied to plate out 7. 20 g of iron?
There are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
Calculation ,
Given ; Current ( I ) = 5. 68 A
In [tex]Fe(NO_{3} )_{2}[/tex] , the valancy of Fe is +2 .
2 moles of [tex]e^{-}[/tex] are required for the decomposition of 1 mole of Fe .
7. 20 g of Fe in moles = 7. 20 g /55.845 g/mol =0.12 mole
x moles of [tex]e^{-}[/tex] are required for the decomposition of 0.128 mole of Fe .
moles of [tex]e^{-}[/tex] are required = 0.256 moles
Charge on 1 mole of [tex]e^{-}[/tex] = 96500 C
Charge on 0.256 mole of [tex]e^{-}[/tex] = 24704 C
Current ( I )= Q/t
t =Q / I = 24704 C/5. 68 A = 4349 sec = 1.2 hr
Therefore , there are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
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The materials in the flux covering on an electrode determine the electrical characteristics of the electrode.
a. true
b. false
Answer:
a. true
Explanation:
It is true that, the materials in the flux covering on an electrode determine the electrical characteristics of the electrode.
If 160 grams of a 200-gram sample of gold-198 decay in 6.25 days, what is the half-life of gold-198?
The half-life of gold-198 is 2.77 days
Given:
mass of gold sample = 200-gram
mass of decay sample = 160 grams
time taken to decay = 6.25 days
To Find:
the half-life of gold-198
Solution: The amount of time it takes to disintegrate by half an initial amount. For a given reaction, a reactant's half-life t1/2 is the time it takes for its concentration to reach a value which is the arithmetic mean of its initial and final (equilibrium) value.
Since Au-198 is 200 g originally and it decays to 160 g, so 40g left
the fraction decay is 40/200 = 0.2
the time base is 6.25 days
ln0.2/6.25 = -0.25
k=ln2/half life therefore half-life = ln2/k = ln2/0.25
half life = 2.77 days
So, half life of gold is 2.77 days
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A 20. 0 l cylinder of oxygen gas is at a temperature of 27. 0°c and a pressure of 5. 00 atm. what is the density of the oxygen gas in the cylinder?
A 20. 0 l cylinder of oxygen gas is at a temperature of 27. 0°c and a pressure of 5. 00 atm. The density of the oxygen gas in the cylinder is 1.24 atm
The physical force applied to an object is referred to as pressure. Per unit area, a perpendicular force is delivered to the surface of the objects. F/A is the fundamental formula for pressure (Force per unit area). Pascals are a unit of pressure (Pa). Absolute, atmospheric, differential, and gauge pressures are different types of pressure.
By pressing a knife on some fruit, one can get a straightforward illustration of pressure. The surface won't be cut if you press the flat section of the knife against the fruit. The force is dispersed over a wide area (low pressure).
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The average atomic mass of lithium is 6.94 amu. Based on the atomic masses of the two isotopes of lithium, how do the relative abundances of the isotopes compare?
Answer:
Answer:
a) The relative abundance of Li-6 =0.0749 = 7.49%
The relative abundance of Li-7 =1 - 0.0749 = 0.9251 =92.51%
b) The fraction of sample of lithium atoms with exact mass of 6.941 amu is 0.
The relative abundance of ⁶Li is around 0.076, and the relative abundance of ⁷Li is approximately 0.924.
To determine the relative abundances of isotopes, we need to compare the atomic masses of the isotopes and their average atomic mass.
Lithium has two stable isotopes: lithium-6 (⁶Li) and lithium-7 (⁷Li). The atomic masses of these isotopes are approximately 6.015 amu and 7.016 amu, respectively.
The average atomic mass of lithium, given as 6.94 amu, is a weighted average of the masses of the two isotopes, taking into account their relative abundances.
Let's assume the relative abundance of ⁶Li is x (in decimal form) and the relative abundance of ⁷Li is (1 - x). The average atomic mass equation can be set up as:
(6.015 amu * x) + (7.016 amu * (1 - x)) = 6.94 amu
Simplifying the equation:
6.015x + 7.016 - 7.016x = 6.94
Combining like terms:
-0.001x = -0.076
Dividing both sides by -0.001:
x ≈ 0.076
Therefore, the relative abundance of lithium-6 (⁶Li) is approximately 0.076, and the relative abundance of lithium-7 (⁷Li) is approximately (1 - 0.076) = 0.924.
In summary, the relative abundance of ⁶Li is around 0.076, and the relative abundance of ⁷Li is approximately 0.924.
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What are the atomic number and atomic mass number of fluorine atoms with nine protons and ten neutrons
Answer:
Atomic Number = 9
Mass Number = 19
Explanation:
The atomic number is the total amount of protons in an atom's nucleus. Therefore, if a fluorine atom has 9 protons, the atomic number is 9.
The mass number is the total amount of protons and neutrons in an atom's nucleus. Therefore, if a fluorine atom has 9 protons and 10 neutrons, the mass number is 19 (9 + 10 = 19).
Solute s has a distribution constant of 5. 0 between water (phase 1) and hexane (phase 2). calculate the concentration of solute s in hexane if [s]water is 0. 011 m.
Solute s has a distribution constant of 5. 0 between water (phase 1) and hexane (phase 2), then the concentration of solute s in hexane if [s]water is 0. 011 m is 0.055m.
What is partition Coefficent?It is defined as the ratio of the concentration of solute in two immiscible ( or slightly miscible liquid) in two solids, when they are in equilibrium across the interface between them.
What is concentration?It is defined as the ratio of number of moles of compound to the volume of compound.
Solute S has a partition coefficient of 5 between water and hexane
Partition coefficient Kd = 5.0
Now we calculate the concentration of S in hexane
[hexane]/[water] = Kd
[Hexane]= 5.0 × (water)
[Hexane] = 5 × (0. 011)
[Hexane] = 0.055 m
Thus, we found that the concentration of solute of hexane if water is 0.011m is 0.055m.
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A liquid that occupies a
volume of 3.23 L has a mass of
3.188 kg.
What is the density of this
liquid
in kg/L?
A. 1.01 kg/L
C. 0.04 kg/L
B. 10.3 kg/L
D. 0.987 kg/L
Answer:
D
Explanation:
You are looking for kg / L
3.188 kg / 3.23 L = .987 kg/L
If you attempt to produce work using the formation reaction of methanol (CH3OH), and the reaction is carried out reversibly, what is the minimum amount of heat wasted?
The minimum amount of heat wasted in the production of methanol is 239kJ/mol of heat.
What is the heat wasted?Now we know that the enthalpy is the heat that is released or absorbed in a reaction. The reaction involves the combination of reactants that leads to the formation of the product(s).
Now we know that the production of methanol leads to the evolution of about 239kJ/mol of heat. This heat is wasted as it goes to no good use but is just lost to the environment.
As such, the minimum amount of heat wasted in the production of methanol is 239kJ/mol of heat.
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number of atoms in 10g of compound is 30.066×10^23. find the molecular mass of compound?
The molecular mass of a 10g compound that has 30.066 × 10²³ atoms is 2.00g/mol.
How to calculate molecular mass?The molecular mass of a substance can be calculated by dividing the mass of the substance by the number of moles.
molecular mass = mass ÷ no of moles
However, the number of moles of the substance must first be calculated by dividing the number of atoms by Avogadro's number.
no of moles = 30.066 × 10²³ ÷ 6.02 × 10²³
no of moles = 4.99moles
molecular mass = 10g ÷ 4.99 moles = 2.00 g/mol
Therefore, the molecular mass of a 10g compound that has 30.066 × 10²³ atoms is 2.00g/mol.
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Suppose protons were emitted rather than electrons. How would this affect the experiment?
Suppose protons were emitted rather than electrons then it affects the experiment as the mean velocity of proton will be less then mean velocity electron .
The mass of proton is greater than the mass of electrons but charge of electron is equal to the charge of proton . So , due to difference in the mass of electron and proton there will be some effects. We can conserve the electric energy which is equal to the qe .
The kinetic energy = 1/2[tex]mv^{2}[/tex]
Now changing the electric potential energy into kinetic energy
v = √2qe/m
The mean velocity of proton will be less then mean velocity electron .
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The hydrogen gas produced is collected over water at 25.0 oC. The volume of the gas is 7.80 L, and the total pressure in the gas collection vessel is 0.980 atm. Calculate the mass of zinc metal that reacted in grams.
Answer:
20.4 grams Zn
Explanation:
To find the mass, you first need to find the moles. This can be found using the Ideal Gas Law equation:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)
-----> T = temperature (K)
Before you can plug the values into the equation, you need to convert Celsius to Kelvin.
P = 0.980 atm R = 0.08206 atm*L/mol*K
V = 7.80 L T = 25.0 °C + 273.15 = 298.15 K
n = ? moles
PV = nRT
(0.980 atm)(7.80 L) = n(0.08206 atm*L/mol*K)(298.15 K)
7.644 = n(24.466)
0.312 moles = n
Now that you have the number of moles, you can convert it to grams using the atomic mass of zinc. The final answer should have 3 sig figs to match the sig figs in the given values.
Atomic Mass (Zn): 65.380 g/mol
0.312 moles Zn 65.380 grams
------------------------- x ------------------------- = 20.4 grams Zn
1 mole
Butane reacts with oxygen gas to form carbon dioxide and water vapor as shown below:
2C₂H₁o + 130₂-8CO₂ + 10H₂O
a. If 20 g of butane were used in the experiment how many litres of water would be produced at SATP?
b. How many litres of oxygen would be consumed in this experiment?
c. If conditions were converted from SATP to STP, how many litres of water would now be produced?
A. The volume of water (in litres) produced at SATP is 42.73 L
B. The volume of oxygen consumed in the experiment is 55.55 L
C. If the conditions were converted from SATP to STP, the volume of water (in litres) produced is 38.64 L
How to determine the mole of C₂H₁₀ Mass of C₂H₁₀ = 20 gMolar mass of C₂H₁₀ = (12×4) + (10×1) = 58 g/molMole of C₂H₁₀ = ?Mole = mass / molar mass
Mole of C₂H₁₀ = 20 / 58
Mole of C₂H₁₀ = 0.3448 mole
A. How to determine the volume of water (in litres) produced at SATPBalanced equation
2C₄H₁₀ + 13O₂ -> 8CO₂ + 10H₂O
From the balanced equation above,
2 moles of C₄H₁₀ reacted to produce 10 moles of water.
Therefore,
0.3448 mole of C₄H₁₀ will react to produce = (0.3448 × 10) / 2 = 1.724 mole of water
Thus, the volume of water (in litres) produced at SATP can be obtained by using the ideal gas equation as follow:
Number of mole of water (n) = 1.724 molePressure (P) = SATP = 0.987 atm Temperature (T) = SATP = 298 KGas constant (R) = 0.0821 atm.L/Kmol Volume of water produced (V) =?PV = nRT
Divide both sides by P
V = nRT / P
V = (1.724 × 0.0821 × 298) / 0.987
Volume of water produced at SATP = 42.73 L
B. How to determine the volume of oxygen consumedBalanced equation
2C₄H₁₀ + 13O₂ -> 8CO₂ + 10H₂O
From the balanced equation above,
2 moles of C₄H₁₀ reacted with 13 moles of O₂
Therefore,
0.3448 mole of C₄H₁₀ will react with = (0.3448 × 13) / 2 = 2.2412 moles of O₂
Thus, the volume of O₂ (in litres) consumed at SATP can be obtained by using the ideal gas equation as follow:
Number of mole of O₂ (n) = 2.2412 molesPressure (P) = SATP = 0.987 atm Temperature (T) = SATP = 298 KGas constant (R) = 0.0821 atm.L/Kmol Volume of O₂ consumed (V) =?PV = nRT
Divide both sides by P
V = nRT / P
V = (2.2412 × 0.0821 × 298) / 0.987
Volume of O₂ consumed = 55.55 L
C. How to determine the volume of water (in litres) produced at STPNumber of mole of water (n) = 1.724 molePressure (P) = STP = 1 atm Temperature (T) = STP = 273 KGas constant (R) = 0.0821 atm.L/Kmol Volume of water produced (V) =?PV = nRT
Divide both sides by P
V = nRT / P
V = (1.724 × 0.0821 × 273) / 1
Volume of water produced at STP = 38.64 L
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_________ is generally an intermolecular force, and __________ is only an intramolecular attractive force.
Hydrogen bonding is generally an intermolecular force, and covalent bonding is only an intramolecular attractive force.
When a hydrogen atom gets bound to a powerfully electronegative atom and is in close proximity to some other electronegative atom with such a single electron pairs, a hydrogen bond occurs as an intermolecular force (IMF).
The three types of intermolecular interactions include dipole-dipole, London dispersion, and hydrogen bonding forces. Metal bonds, ionic bonds, as well as covalent bonds are mostly the three types of intramolecular forces.
Therefore, Hydrogen bonding is generally an intermolecular force, and covalent bonding is only an intramolecular attractive force.
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How much energy, in kilojoules, is required to melt 20 kg of ice at 0°C?
The energy required to melt 20 kg of ice at 0°C is 6.68 kJ.
The enthalpy change for melting of an ice is called the enthalpy of fusion. Its value is 6.02 kJ/mol. This means for every mole of ice we must apply 6.02 kJ of heat for melting. The calculation of heat is done by following equation.
q = n×ΔH
q is heat n is number of molesΔH is change in enthapyin this problem we need to calculate heat needed to melt 20grams of ice at 0°C .
Calculation of moles of water,
Number of moles of water (n) = given mass/ molar mass = 20g/18.02g/mol
Number of moles of water (n) = 1.109 mole
heat or energy required = q = n×ΔH = 1.109 mole× 6.02 kJ/mol = 6.68 kJ
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What substance is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, cabr2(l)cabr2(l), and molten magnesium iodide, mgi2(l)mgi2(l)? assume standard conditions
Mg (Magnesium) is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, CaBr₂ (l) and molten magnesium iodide, MgI₂ (l).
What is Anode and cathode ?The anode in the cell has been the negative electrode and attracts the positive ions in the solution. The cathode has been the positive electrode, and attract negative ions.
What is Electrolysis of Calcium Bromide ?In electrolysis of Calcium bromide, Calcium will form at the cathode and Bromine will form at the anode.
The reaction is as follows:
2Br⁻ (aq) → Br₂ (g) + 2e⁻
What is Electrolysis of Magnesium Iodide ?In electrolysis of magnesium Iodide, Magnesium will form at the anode Iodine will form at the cathode.
The reaction is as follows:
2I⁻ (aq) → I₂ (g) + 2e⁻
Thus from the above conclusion we can say that Mg (Magnesium) is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, CaBr₂ (l) and molten magnesium iodide, MgI₂ (l).
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3) During a chemical reaction, atoms are ________. A) destroyed B) created C) rearranged D) destroyed and created
Answer: C- rearranged
Explanation:
Answer:
C
Explanation:
Write an equation to represent the following reaction:
Borax is heated with CoO
The equation of the reaction is; B2O3 + CoO -----> Co(BO2)2.
What is a reaction?The term chemical reaction has to do with the interaction between reactants in order to yield products. We know that when a chemical reaction occurs, the reactants are rearranged to form the products.
Now the first step in this reaction is that the Borax is heated to form boric anhydride (B2O3). Thus compound now reacts with cobalt II oxide as follows; B2O3 + CoO -----> Co(BO2)2.
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Calculate the average acceleration from the following data points: v1 = 150 m/s, v2 = 975 m/s, t1 = 15 s, t2 = 55 s
The average acceleration from the following data points is 20.625 m/s^2.
We know that average acceleration = change in speed / change in time
here,
change in speed = v2-v1
= 975-150
= 825 m/s
change in time = t2 - t1
= 55 - 15
= 40 s
now, putting all the values, average acceleration = 825 / 40
= 20.625 m/ s^2 .
what is acceleration?
The rate at which an entity's velocity with regard to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.
The SI unit of acceleration is metre per second square (m/s^2).
An average acceleration the speed at which velocity changes, the evolution of velocity through time, or the instantaneous acceleration ( acceleration at a given moment ) .
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The use of phenol (carbolic acid) as a surgical wound disinfectant was first practiced by?
The use of phenol (carbolic acid) as a surgical wound disinfectant was first practiced by Joseph Lister.
Who was Joseph Lister?
Joseph Lister was a surgeon, scientist, pathologist, etc. He was famous for the discovery of the prevention of infection in wounds. He first used phenol as a disinfectant agent for wounds.
Phenol is an inorganic compound, it is white crystalline and solid. It was used by Joseph Lister as an agent for a disinfectant agent. He discovered the safer medical procedure.
Thus, Joseph Lister was the first to utilize phenol (carbolic acid) to sterilize surgical wounds.
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