The reaction is at equilibrium. Option C
What is the equilibrium constant?The term equilibrium constant refers to a value that shows the extent to which reactants are converted into products in the reaction.
We know that;
∆G =∆G'° + RT In Keq
∆G'° = −4.40 kJ/mol
R = 8.314 J/K/mol
T = 25 + 273 = 298 K
Thus;
∆G = −4.40 * 10^3 + (8.314 * 298 * ln[2.90 * 10^-3/0.490 * 10^-3]
∆G = −4.40 * 10^3 + 4.40 * 10^3
∆G = 0
Hence, the reaction is at equilibrium.
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1) Consider the following metabolic reaction:
2-Phosphoglycerate ® 3-Phosphoglycerate DG°' = −4.40 kJ/mol
What can be said about this reaction when the concentration of 2-phosphoglycerate is 0.490 mM and the concentration of 3-phosphoglycerate is 2.90 mM at 25°C?
I. This reaction is endergonic under these conditions.
II. This reaction is exergonic under these conditions.
III. This reaction is at equilibrium under these conditions.
IV. This reaction is not favorable under standard conditions.
A) I, IV
B) II only
C) III only
D) IV only
E) None of the above
2) Consider the following metabolic reaction:
A solution is prepared by dissolving 117 grams of salt (NaCl) in 250 milliliters of water (H₂O). What is
the molarity of the solution?
A. 0.47 M NaCl
B. 8.0 x 10-3 M NaCl
C. 8.0 M NaCl
D. 468 M NaCl
Taking into account the definition of molarity, the molarity of the solution is 8 M.
Definition of molarityMolar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
[tex]Molarity=\frac{number of moles}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
Molarity of the solution in this caseIn this case, you know:
number of moles= 117 grams×[tex]\frac{1 mole}{58.45 grams}[/tex]= 2 moles, where 58.45 [tex]\frac{grams}{mole}[/tex] is the molar mass of NaClvolume= 250 mL= 0.250 L (being 1000 mL= 1 L)Replacing in the definition of molarity:
[tex]Molarity=\frac{2 moles}{0.250 L}[/tex]
Solving:
Molarity= 8 [tex]\frac{moles}{liter}[/tex]= 8 M
Finally, the molarity of the solution is 8 M.
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How many moles of iron iii oxide can be prepared from 6 moles of oxygen?
Answer:
6molO2 3/2O22Fe=4,5024molFe .
Explanation:
You have to start with the balanced chemical equation. Iron is just Fe. Oxygen in nature is found as an O2 molecule.
2Fe(s)+3/2O2(g) Fe2O3(s)
If you check the balance. There are two Fe on both sides of the equation and three O on both sides, so it’s balanced.
Now use the stoichiometric ratios (the coefficients of the balanced chemical equation) to convert 6 mol of oxygen to iron.
6molO2 3/2O22Fe=4.5024molFe .
These coefficients can be used as conversion factors when it comes to substance moles.
Some of you may insist that a balanced chemical reaction must have whole numbers. This is not really necessary. The reaction I wrote above is a named type of reaction, called Fe2O3 formation. In this type of reaction, there must be a mole of product so that it requires that sometimes there are fractional numbers for the coefficients in the reagents.
But, just for the argument, let’s rebalance the equation for integer coefficients only.
4Fe(s)+3O2(g) 2Fe2O3(s)
We are now using the coefficients as conversion factors, as we have done before.
Which of the given ions have the same ground state electron configuration: s2-, n3-, mg2 , and br-? a. s2-, n3-, mg2 , and br- b. s2-, n3-, and br- c. n3- and mg2 d. s2- and br- e. mg2 and br-
N3- and Mg2 ions have the same ground-state electron configuration.
Ground-state electron configuration:Understanding molecule bonding, characteristics, and structures begin with understanding ground state electron configurations. The ground state electron configuration provides insight into a wide range of atomic properties, including the electrons in an atom, distinct orbitals, and hybridization.
The ground state of an atom's electrons is the lowest energy state that is feasible for that atom since, throughout the cosmos, a system's natural state is to use the least amount of energy.
Aufbau-Principle: If you have a lot of luggage, you'll probably choose the room that is closest to the ground floor in a hotel without an elevator. The Aufbau principle demonstrates the identical behavior of electrons in the ground state. According to the Aufbau principle, electrons first occupy lower energy orbitals before moving on to higher energy orbitals.
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Libr (s) → li (aq) br- (aq) δh = -48. 8 kj/mol in a coffee-cup calorimeter you dissolve 21. 4 g of this salt in 111 g of water at 25. 1 oc. what will be the final temperature of the solution formed?
Final temperature of the solution formed is 50.93ºC
As we know,
heat = mass x specific heat x change in temperature
q = mC∆T
where, m = 111 g water
C = 4.184 J/g/deg
∆T = ?
To find heat we need to first find moles Libr used in this reaction:
21.4 g Libr x 1 mole/86.84 g = 0.246 moles
Therefore,
q = 0.246 moles x (-48.8) kJ/mol = -12.00 kJ = -12000 J (since it is negative, this indicates an exothermic reaction, so temperature of solution will increase).
-12000 J = (111g)(4.184 J/g/deg)(∆T)
∆T = -25.83 degrees
Final temperature = 25.1º - (-25.83º) = 50.93ºC
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Explain how the data answered the essential question. What can you conclude from the experiment? Use the following questions to guide your thinking:
Does the filament with the anther rise above the stigma?
If the pollen is located above the stigma, the flower is generally self-pollinated. If the pollen is below the stigma, the flower is generally cross-pollinated. Based on this information, is your flower self-pollinated or cross-pollinated?
Answer:
sorry i don't know this question of answer
Two cars A and B are moving in opposite directions with the velocity of 20m/s and 6m/s respectively Calculate the relative of car A with respect to car B If they move in the same velocity what will be the relative velocity of CarA with respect to Car B
The relative velocity is described as the velocity of an object with respect to another viewer. It is the time rate of shift of relative position of one object with respect to another object.
How to find out the Relative Velocity of car A and car B ?a) Velocity of car A (Va) = 20m/s
Velocity of car B (Vb) = -6m/s
To find the Relative Velocity, we should apply the formula as,
Relative Velocity of car A and car B = Vab
Vab = Va - Vb
Vab = 20 - (-6)
Vab = 20+6
Vab = 26m/s
b). if Velocity of car A = Velocity of car B
Va = Vb
In this case,
Relative Velocity = Vab
Vab = Va - Vb
(since Va = Vb)
Vab = 0m/s
Hence, the Relative Velocity in a). is 26m/s and in b). is 0m/s.
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What are crime scenes that you can do with a friend for fun. Friend in crime
1. I think r0b a bank would be such a rush. Imagine r0b a bank, driving a souped up getaway vehicle, and then successfully escaping with loads of cash...., that would be such an adrenaline rush.
2. Nationwide animal release. Just ninja into pounds and shelters and set them all free. It'd get to the point that they'd have to get armed guards. Soon wild packs of pugs and Chihuahuas roam freely claiming their territory against man.
3. Putting glitter bombs in mailboxes. Not sending but personally taping it in there so it goes off when opened.
If 0. 5371 g of zn was plated onto an electrode, how much charge (in coulombs) was used to reduce the zn2+ to zn(s)?
The amount of charge required to reduce Zn²⁺ to Zn is 1585.26 coulomb.
What is electrolysis?The process that has been equipped with the use of electric current to break the chemical compound and deposited at the constituent electrodes is termed as electrolysis.
The reaction of reduction of Zn can be given as:
Zn²⁺ + 2e⁻ → Zn (s)
Molar mass of Zn = 65.39 g
The equivalent of Zn²⁺ has been:
Equivalent = atomic mass/equivalent weight
Equivalent Zn²⁺ = 65.39/32.69
Equivalent Zn²⁺ = 2 mol
1 equivalent = 1 F charge used
2 mol equivalent = 2 F charge used
Charge in coulomb can be given as:
1 Faraday = 96500 coulomb
2 F = 96500 * 2 coulomb
2 F = 1,93,000 coulomb
The moles of Zn to be deposited is:
Moles = weight /molar weight
Moles = 0.5371 g/ 65.39 g/mol
Moles = 0.00821 mol
Therefore, the charge used for the deposition of 0.00821 mol is:
Charge = 0.00821 * 1,93,000 coulomb
Charge = 1585.26 coulomb
1585.26 coulomb charge was used to reduce the Zn²⁺ to Zn.
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Identify the classification of milk. group of answer choices aerosol solid aerosol foam emulsion solid emulsion
Milk is an example of solid emulsion. Hence, option D is correct.
What is emulsion?An emulsion is defined as a colloid consisting of two or more non-homogenous type of liquids in which one of the liquid contains the dispersion of the different form of liquids.
Emulsion consist of a dispersion of two liquids that are immiscible with each other.
One of the liquids act as the dispersion medium and the other will act as the dispersed phase.
Emulsions are colloids in which both the dispersed phase and dispersion medium are liquids.
Types of Emulsion:
Oil in water (O/W)In this type of emulsion, the oil will be the dispersed phase and water will be the dispersion medium. Example of o/w emulsion is milk.2. Water in oil (W/O)
In this type, water will be the dispersed phase and oil will be the dispersion medium. Margarine is an example of water in oil emulsion.Milk is an example of solid emulsion. Hence, option D is correct.
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In a combustion chamber, ethane (c2h6) is burned at a rate of 9 kg/h with air that enters the combustion chamber at a rate of 176 kg/h. determine the percentage of excess air used during this process
The percentage of excess air used during combustion process of ethane will be 37 %.
Burning, also known as combustion, would be a high-temperature highly exothermic chemical process that occurs when an oxidant, typically atmospheric oxygen, interacts with a fuel to generate oxidized, frequently gaseous products in a mixture known as smoke.
Calculation of percentage of air .
[tex]C_{2} H_{6} + (1-x)+a(O_{2} +3.76N_{2} )=bCO_{2} + cH_{2} O + axO_{2} + 3.76dN_{2} .[/tex]
Mair=Mair/Rin
[tex]( MN)O_{2}[/tex] + [tex](MN)N_{2}[/tex]÷ [tex](MN)O_{2}[/tex] + [tex](MN)N_{2}[/tex] +[tex](MN)C_{2} H_{6} .[/tex]
33 . 3.25(1-x) + 28 × 13.16(1-x) ÷ 33 × 3.25(1-x) + 28 × 13.16(1-x). + 30.1
= 176/176+8
X= 0.37
0.37 × 100
X= 37%
Therefore, the percentage of excess air used during combustion process of ethane will be 37 %.
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Compared with the energy it takes to separate oxygen and hydrogen from water, how much energy is released when they recombine?.
The same amount of energy released when they recombine
Yes, the energy required to separate water into O2 and H2 is at least equal to the energy released when these gases come together to form water.
What is the process for separating water into it's constituents ?The process of separating water into hydrogen and oxygen is known as electrolysis. This reaction occurs in a device known as an electrolyzer.
This is around 260 kJ per mole of water, or just under 5 eV per water molecule (4 electrons times 1.23 V). One litre of water would require at least 16 MJ (4.4 kWh) in order to be split, which is more energy than would be required to send one litre of water into deep space.Learn more about Electrolysis here:
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How much energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°c and completely vaporize the sample?
The 7160 cal energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°C and completely vaporize the sample.
Calculation,
Given data,
Mass of the ice = 10 g
Temperature of ice = 0. 0°C
The ice at 0. 0°C is to be converted into water at 0. 0°CHeat required at this stage = mas of the ice ×latent heat of fusion of ice
Heat required at this stage = 10 g×80 = 800 cal
The temperature of the water is to be increased from 0. 0°C to 100. 0°CHeat required for this = mass of the ice×rise in temperature×specific heat of water
Heat required for this = 10 g×100× 1 = 1000 cal
This water at 100. 0°C is to be converted into vapor.Heat required for this = Mass of water× latent heat
Heat required for this = 10g ×536 =5360 cal
Total energy or heat required = sum of all heat = 800 +1000+ 5360 = 7160 cal
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Heliox is a mixture of helium and oxygen gas used to help patients with breathing difficulties. It is also used for scuba diving. The total pressure in a tank of heliox is 208 atm. If the mole fraction of o2 is 0. 220, what is the partial pressure of he in the tank?.
Partial pressure of helium gas in the tank is 162.24 atm.
Partial Pressure:
A partial pressure is the imaginary pressure that a gas would have if it were to occupy the complete volume of the initial mixture by itself at the same temperature. Each gas in a mixture of gases has a partial pressure.
Explanation:
Total pressure in Heloix (P) = 208 atm
The mole fraction of an individual gas component in an ideal gas mixture can be expressed in terms of the component's partial pressure or the moles of the component
Mole fraction of oxygen (X₀) = 0.220
The sum of the mole fractions of all the components present must equal 1.
Mole fraction of helium (Xₐ) = 1-(X₀) = 1- 0.220= 0.78
According to Dalton's law of partial pressure.
Partial pressure of an individual gas component in an ideal gas can be obtained using this expression:
Partial pressure of oxygen gas in Heloix: P*X₀ = 208 * 0.22 = 45.76 atm
Partial pressure of helium gas in Heloix: P*Xₐ = 208 * 0.78 = 162.24 atm
Partial pressure of helium gas is 162.24 atm.
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Ulfuric acid is found in some types of batteries. What volume of 3.50 m h2so4 is required to prepare 250.0 ml of 1.25 m h2so4?
The volume sulfuric acid will be 89.3mL.
Volume will be determined by the molarity relation. The quantity of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a component per liter of a solution would be known as molarity. The molar concentration of any solution would be another name for molarity.
The volume can be calculated by using molarity formula:
[tex]M_{1} V_{1} = M_{2} V_{2}[/tex]
Given data:
[tex]M_{1}[/tex] = 3.50 m
[tex]M_{2}[/tex] = 1.25 m
[tex]V_{1}[/tex]= 250.0 ml
Put the value of given data in above formula:
[tex]M_{1} V_{1} = M_{2} V_{2}[/tex]
( 3.50 m) ( 250 mL) = ( 1.25 m) [tex]V_{2}[/tex]
[tex]V_{2}[/tex] = 89.3mL
Therefore, the volume sulfuric acid will be 89.3mL.
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Isotopes have question 2 options: a) a different number of neutrons in their nuclei. b) a different number of protons in their nuclei. c) a different number of electrons. d) different numbers of both protons and neutrons in their nuclei.
Answer:
A
Explanation:
Isotopes are atoms of the same element with the same number of protons and electrons but different numbers of neutrons.
Isotopes can also be defined as atoms of the same element with the same atomic number but different mass numbers e.g isotopes of chlorine, oxygen and so on.Oxygen for instance has three isotopes with the same atomic number,8 and different mass numbers,16,17 and 18.
For the lead storage battery, the chemical reaction is: pb pbo2 2 h2so4 2 pbso4 2 h2o the pb in this voltaic cell acts as:_______
The lead (Pb) in the lead storage battery act as an anode
What is Voltaic Cell?
A voltaic cell or galvanic cell is an electrochemical cell that uses chemical reactions to produce electrical energy.
Parts of voltaic cell
Anode where oxidation occursCathode where reduction occursIn lead storage battery, the following reactions occur:
At anode:
[tex]Pb(s) + H_2SO_{4} + H_2O(l) \rightarrow2e^- + PbSO_{4} (s) + H_3O^+(aq)[/tex]
At Cathode:
[tex]PbO_2(s) + H_2SO_4(aq) + 3H_3O+(aq) + 2e^- \rightarrow PbSO_4(s) + 5H_2O(l)[/tex]
Overall reaction:
[tex]Pb(s) + PbO_2(s) + 2H_2SO_4 (aq.) \rightarrow PbSO_4(s) + 2H_2O(l)[/tex]
Hence, Pb acts as an anode and [tex]PbO_2[/tex] as a cathode.
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The pH of an aqueous solution is determined to be 3. What is the hydronium ion concentration of the
solution?
A. [H3O+] = 1 x 10-³ M
B. [H3O+] = 3 x 10-³ M
[H3O+] = 1 x 10-11 M
D. [H3O+] = 3 x 10-11 M
Considering the definition of pH, the hydronium ion concentration [H₃O⁺] of the solution is 1×10⁻³ M.
Definition of pHpH is the Hydrogen Potential. It is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
Mathematically, pH is calculated as the negative base 10 logarithm of the activity of hydrogen ions:
pH= - log [H⁺]= -log [H₃O⁺]
The numerical scale that measures the pH of substances includes the numbers from 0 to 14. The pH value 7 corresponds to neutral substances. Acidic substances are those with a pH lower than 7, while basic substances have a pH higher than 7.
Hydronium ion concentrationIn this case, being pH= 3, you can replace this value in the definition of pH:
3= -log [H₃O⁺]
Solving:
[H₃O⁺]= 10⁻³ M
[H₃O⁺]= 1×10⁻³ M
Finally, the hydronium ion concentration [H₃O⁺] of the solution is 1×10⁻³ M.
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Compute the theoretical density of zns given that the zn-s distance and bond angle are 0. 234 nm and 109. 5o, respectively? The atomic weights of zinc and sulfur are 65. 41 g/mol and 32. 06 g/mol.
Density of ZnS given that the zn-s distance and bond angle are 0. 234 nm and 109. 5o, respectively if the atomic weights of zinc and sulfur are 65. 41 g/mol and 32. 06 g/mol. is 4.1109 g/cm³
For density In the crystal structure, we determine the angle's value for one set of ZnS bonds. θ θ + ∅ + 90° = 180° θ = 90° - ∅ θ = 90° - (109.5° / 2) After determining that = 35.25°, we derive the value of x from the geometry: distance angle d = 0.234 x = dsin = 0.234 sin35.25°) = 0.135 nm = 0.135 107 cm; following this, we get the length of the unit cell: a = 4x a = 4(0.135) a = 0.54 nm = 0.54 107 cm; and The formula for n' is (number of corner atoms in unit ell contribution of each corner atom in unit cell) + (number of face center atoms in unit cell contribution of each face center atom in unit cell). n' = 8 × 1/8) + (6 × 1/2) = 1 + 3 = 4
Density = P = [4( 65.41 + 32.06)] / [ ( 0.54 × 10⁻⁷ )³ × (6.023 × 10²³)] = 389.88 / 94.84 = 4.1109 g/cm³
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If a buffer is composed of 34. 63 ml of 0. 139 m acetic acid and 36. 50 ml of 0. 182 m sodium acetate, how many ml of 0. 100 m hcl can be added before the buffer capacity is reached?
The volume is the product of the molar concentration and the moles of the substance. The volume of hydrochloric acid that can be added to the buffer is 0.066 L.
What is a buffer?A buffer is a constant solution with a proton or hydrogen ion concentration with an acid, base, or salt dissolved in them.
The chemical reaction between hydrochloric acid and sodium acetate is given as,
HCl + CH₃Coo-Na → CH₃CooH + NaCl
From above the initials moles of acetic acid are given as,
Moles = molarity × volume
= 0.139 M × 0.0346 L
= 0.0048 moles
The initials moles of sodium acetate are given as,
M = 0.182 M × 0.0365 L
= 0.0066 moles
As it is known that the ratio of the buffer capacity is 10 for sodium acetate and acetic acid so,
Moles sodium acetate ÷ Moles Acetic acid = 10
(0.0066 moles + X) ÷ (0.0048 moles - X) = 10
Here, X is the moles of HCl and is calculated as,
0.0066 moles + X = 0.048 moles - 10X
11 X = 0.048 ÷ 0.0066
11 X = 7.27
X = 0.66 moles
The volume of 0.100 HCl with 0.66 moles is:
Volume = moles × molarity
= 0.100 × 0.66
= 0.066 L
Therefore, 0.066 L of 0.100 M HCl is required to reach the buffer capacity.
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the graph below shows a reaction with a catalyst. How did the addition of the cataalyst change the graph
Answer:
Section 2 will decrease.
Explanation:
A catalyst is a substance that increases the rate of the chemical reaction without taking part in the overall reaction. Catalysts speed up a reaction by lowering the activation energy needed for a reaction to take place. The activation energy is the minimum energy necessary for a reaction to take place. As such, when a catalyst is added, the activation energy (or the potential energy) needed to start the reaction decreases. This shows itself in the graph by decreasing the "hump" in Section 2.
It should be noted that Sections 1 and 3 will remain the same. This is because the energy of the reactants and products does not change regardless of a catalyst being present.
What is the kb of the base po−34 given that a 0. 48m solution of the base has a ph of 12. 70? the equation described by the kb value is:___________
The equation described by the kb value is 5.21 x [tex]10^-^3[/tex].
The potential of Hydrogen is what pH is formally known as. The negative logarithm of the concentration of H+ ions is known as pH. Thus, the definition of pH as the amount of hydrogen is provided. The hydrogen ion concentration in a solution is described by the pH scale, which also serves as a gauge for the solution's acidity or basicity.
Assuming PO₄³⁻ (the phosphate anion).
PO₄³- + H₂O ==> HPO₄²⁻ + OH⁻
Kb = [HPO₄²⁻][OH⁻] / [PO₄³⁻]
We can find the [OH⁻] from the pH of 12.70.
pH + pOH = 14
14.0 - 12.7 = 1.3 = pOH
[OH] = 1x[tex]10^-^1^.^3[/tex]
[OH-] = 5.0x[tex]10^-^2[/tex] M
[HPO₄²⁻] = 5.0x[tex]10^-^2[/tex] M
Kb = (5.0x[tex]10^-^2[/tex])2 / 0.48
= 2.5x[tex]10^-^3[/tex] / 0.48
Kb = 5.21 x [tex]10^-^3[/tex]
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What is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided?
Mass percentages of the the elements in the compound is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided.
What is Empirical Formula ?The Empirical formula is the simplest whole number ratio of atoms present in given compound.
What is Molecular formula of Compound ?Molecular Formula = Empirical Formula × n
n = [tex]\frac{\text{Molar Mass}}{\text{Empirical Formula weight}}[/tex]
Thus from the above conclusion we can say that Mass percentages of the the elements in the compound is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided.
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If 30. 0 ml of 0. 150 m CaCl2 is added to 15. 0 ml of 0. 100 m AgNo3, what is the mass in grams of AgCl precipitate?
The mass of AgCl precipitated is 0.215g.
What do you mean by precipitation?Precipitate is to form an insoluble compound either by reacting two salts or by changing the temperature to affect the solubility of the compound.
To calculate mass of AgCl precipitate -
The first step is to make a balanced chemical equation.
2AgNO3 + CaCl2 ---> 2AgCl + Ca(NO3)2
Molecular Weights:
CaCl2 = 110.98 g/mol
AgNO3 =170.01g/mol
AgCl= 143.45 g/mol
Volume:
CaCl2: 30.0mL=0.03L
AgNO3: 15.0mL=0.015 L
mole CaCl2 = 30/1000 x 0.2 =0.006
mole AgNO3 =15/1000 x 0.1 = 0.0015
CaCl2 is in excess so 0.0015 mole AgCl will form
0.0015 x 143.5 = 0.215g
The 0.215 mass in grams of AgCl will precipitate.
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The iodine test is used to test for the presence of starch which is a type of ___________ treated with an iodine solution, the starch reacts with the iodine solution and produces a ___________ color.
A. protein, blue-purple
B. protein, yellow
C. carbohydrate, yellow
D carbohydrate, blue-purple
When
Answer:
D. carbohydrate, blue-purple
Explanation:
Carbohydrates are one of many types of macronutrients found in certain foods and drink. For example, sugars, starches, and fibers are carbohydrates.
When starch is present, using an iodine solution will turn it blue-black or purple. If starch is NOT present, it will stay orange or yellow. The reason starch reacts with iodine is due to the amylose present in starch. Iodine is not soluble in water, so it's dissolved along with potassium iodide that forms a triiodide molecule. That then enters the helical structure of amylose and changes its color.
WHAT IS PRECIPITATION REACTION
A precipitation reaction exists in which dissolved substances react to create one (or more) solid products.
What is a Precipitation in a Reaction?A precipitation reaction exists in which dissolved substances react to create one (or more) solid products. Many reactions of this kind concern the exchange of ions between ionic compounds in an aqueous solution and exist sometimes directed as double displacement, double replacement, or metathesis reactions.
A precipitation reaction exists as a chemical reaction happening in an aqueous solution where two ionic bonds integrate, resulting in the construction of an insoluble salt which is named precipitates.
Some examples exist reactions between calcium chloride (CaCl2) and potassium hydroxide(KOH), which result in the appearance of calcium hydroxide which stands as an insoluble salt. The reaction between silver nitrate (AgNO3) and sodium chloride (NaCl), results in the construction of silver chloride (AgCl) exists an insoluble salt.
In an aqueous solution, precipitation stands the procedure of converting a dissolved substance into an insoluble solid from a super-saturated solution. The solid formed exists named the precipitate.
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8.0 liters I2 forms at STP. How many moles of KI were required for the reaction?
Answer:
0.71 moles KI
Explanation:
At STP, there should be 1.0 moles at 22.4 L. However, there are only 8.0 L of I₂. Therefore, we must set up a proportion to find the correct moles of I₂.
[tex]\frac{1 mole}{22.4 L} =\frac{? moles}{8.0 L}[/tex] <----- Proportion
[tex]8.0 = 22.4(? moles)[/tex] <----- Cross multiply
[tex]0.36 = ? moles[/tex] <----- Divide both sides by 22.4
To find the moles of KI, you can use the mole-to-mole ratio from the balanced equation coefficients. The final answer should have 2 sig figs.
2 KI(aq) + Cl₂(g) ---> 2KCl(aq) + 1 I₂(g)
^ ^
0.36 moles I₂ 2 moles KI
---------------------- x -------------------- = 0.71 moles KI
1 mole I₂
Answer: 0.71 moles KI
Explanation:
What descriptive term is applied to the type of diene represented by 1,5-octadiene?
The descriptive term that is applied to the type of diene represented by 1,5-octadiene is isolated diene. The correct option is C.
What is diene?Diene is a compound that contains two or more double bonds, usually carbon bonds, which are separated by a single bond. They are covalent compounds. Alkene units are surely present in these compounds, whose quantity is two.
1,5-octadiene is a polymer of diene, which are generally elastomers, and they made of vulcanized rubber. They are isolated diene.
Thus, the correct option is C) Isolated diene.
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The question is incomplete. The complete question is given below:
A) Conjugated diene.
B) Cumulated diene.
C) Isolated diene.
D) Alkynyl diene.
E) None of the above.
Draw the highest energy transition state in the solvolysis of (ch3)3c-i in ch3oh
The highest energy transition state in the solvolysis of [tex](CH_{3} )_{3} CI[/tex] in [tex]CH_{3} OH[/tex] is given as ,
The mechanism of solvolysis of tert-butyl iodide follow nucleophilic substitution reaction . The nucleophilc substitution reaction are two types one unimolecular and second bimolecular nucleophilc substitution .
The mechanism of solvolysis of tert-butyl iodide follows unimolecular nucleophilic substitution reaction in which carbocation is the intermediate which as a transition state of it. The carbocation formed by solvolysis of tert-butyl iodide is 3° carbocation or tertiary carbocation which is most stable. The methanol as neutral nucleophile and oxygen of methanol attack at carbocation intermediate.
Therefore , the highest energy transition state in the solvolysis of [tex](CH_{3} )_{3} CI[/tex] in [tex]CH_{3} OH[/tex] is given .
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Draw the mechanism for the interconversion of α-d-glucose and β-d-glucose in dilute hcl
The mechanism for the interconversion of α-d-glucose and β-d-glucose in dilute HCl include the proton transfer in first step and nucleophilic attack in second step.
What is Proton Transfer ?In the first step oxygen donates its lone pair of electron to hydrogen of HCl. There is removal of water molecule from the substance α-d-glucose.
What is Nucleophilic Substitution ?The organic reaction where one nucleophile replaces another is called nucleophilic substitution reaction. These reaction takes place in aromatic compounds, acyl compounds and aliphatic compounds. SN¹ reactions are nucleophilic substitution reaction.
Thus from the above conclusion we can say that The mechanism for the interconversion of α-d-glucose and β-d-glucose in dilute HCl include the proton transfer in first step and nucleophilic attack in second step.
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The process where a substance goes directly from a solid state to a gaseous form is known as:____.
Answer:
sublimation because it's has changed from solid to gaseous