Using f(x), what is the equation that represents g(x)?
Og(x) = log5 (x) - 3
O
g(x) = log5 (x) +3
Og(x) = log5 (x-3)
Og(x) = logs(x + 3)

Answer:

130 degrees

Step-by-step explanation:

We know (x-10)+(2x+10) is 180 degrees.

So first we need to find x. (x-10)+(2x+10)=3x

3x=180

x=60

Angle TRV is 2x+10.

If we input 60 in the place of x, it is 2(60)+10=120+10=130.

The answer is 130 degrees.

Answer: (2,9)

Step-by-step explanation:

The point lies in the region that is shaded by both inequalities.

Answer:

A

Step-by-step explanation:

f(-3) = 2^-3

to get rid of a negative in an exponent, move the whole thing to the denominator.

1/(2^3)

2^3 = 2×2×2

1/(2×2×2)

1/8

The box and whisker plot is plotted with minimum value 24, maximum value 58, first quartile 29, third quartile 52 and median 40.

Given that, the ages of 15 music teachers in a school district are 24, 26, 27, 29, 29, 32, 37, 40, 40, 41, 45, 52, 56, 56, 58.

A box and whisker plot also called a box plot displays the five-number summary of a set of data. The five-number summary is the minimum, first quartile, median, third quartile, and maximum. In a box plot, we draw a box from the first quartile to the third quartile. A vertical line goes through the box at the median.

Minimum value = 24

Maximum value = 58

First quartile = 29

Third quartile = 52

Median = 40

Therefore, the box and whisker plot is plotted with minimum value 24, maximum value 58, first quartile 29, third quartile 52 and median 40.

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Answer:

15740000 million dollars in profit in year 4

Step-by-step explanation:

Now since you didn't provide the table, im going to have to assume the years are going to be the X while the Y is going to be profit.

Using the equation you provided y=-0.34x^2+4.43x +3.46, we can simply put 4 as our x value (since x represents years) and we would get 15.74. Now you have to remember to convert it into millions to show the profit so 15.74 times 1,000,000 would be 15740000 million dollars

The bar which Adelina should buy is super power brand because it cost less than feel great energy bar at $1.45 per bar

Feel great energy bars = Total cost / number of bars

= $18 / 12

= $1.5 per bar

Super power brand = Total cost / number of bars

= $21.75 / 15

= $1.45 per bar

Therefore, the bar which Adelina should buy is super power brand because it cost less than feel great energy bar at $1.45 per bar

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Answer:

x = 5, y =2

Step-by-step explanation:

I guess the question is saying x+y = 7 and 3x-2y = 11?

then there are multiple ways but

I will multiply the first one by 2 so 2x+2y = 14

you add the equations to get 5x = 25 so x = 5 plug x into the first equation you get y = 2

if that isn't what the question means just comment and I'll change it

Answer:

23. 216
24. 56

25. 52

for 26, 27 i'll try to calculate the answer, sorry

The numbers are 14.42 and 3.6055.

It is the whole which is to be divided into different equal parts. For example, if 10 divided by 2 is 5, then 10 is the dividend here, which is divided into two equal parts whereas 2 is the divisor, the quotient is 5 and the remainder is 0.

We can write the system of equations

x*y=52   .......(1)

[tex]\frac{x}{y}[/tex]=4         ........(2)

We can use substitution to solve

From equation (2) we get,

x = 4y     .......(3)

now substitute in equation (1)

4y*y = 52

[tex]4y^{2} = 52[/tex]

[tex]y^{2} = \frac{52}{4}[/tex]

[tex]y = \sqrt{13}[/tex]

y = 3.605

We can solve for x = ?

from equation (3)

x = 4y

x = 4*3.605

x =   14.42  

Hence, The numbers are 14.42 and 3.6055.

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Split up the interval [0, 3] into 3 equally spaced subintervals of length [tex]\Delta x = \frac{3-0}3 = 1[/tex]. So we have the partition

[0, 1] U [1, 2] U [2, 3]

The left endpoint of the [tex]i[/tex]-th subinterval is

[tex]\ell_i = i - 1[/tex]

where [tex]i\in\{1,2,3\}[/tex].

Then the area is given by the definite integral and approximated by the left-hand Riemann sum

[tex]\displaystyle \int_0^3 f(x) \, dx \approx \sum_{i=1}^3 f(\ell_i) \Delta x \\\\ ~~~~~~~~~~ = \sum_{i=1}^3 (i-1)^3 \\\\ ~~~~~~~~~~ = \sum_{i=0}^2 i^3 \\\\ ~~~~~~~~~~ = 0^3 + 1^3 + 2^3 = \boxed{9}[/tex]

Answer:

step 3

Step-by-step explanation:

he should have subtracted 9 to the outside.

whatever you do to the inside you must do to the opposite to the outside

so your final form must be -7(x-3)^2 + 8

Using the Laplace transform, the value of y' + y = (t − 1), y(0) = 5 is y(t) = 5e ^ -t + u (t - 1)e^(1-t)

Laplace rework is an critical rework approach that is in particular useful in fixing linear normal equations. It unearths very huge applications in  regions of physics, electrical engineering, control optics, arithmetic and sign processing.

y' + y = (t − 1)

y (0) = 5

Taking the Laplace transformation of the differential equation

⇒sY(s) - y (0) + Y(s) = e-s

⇒(s + 1)Y(s) = (5+ e^-s)/s + 1

⇒y(t) = L^-1{5/s+1} + {e ^-s/s + 1}

⇒y(t) = 5 e^-t + u(t -1)e^1-t

The Laplace remodel method, the feature within the time area is transformed to a Laplace characteristic within the frequency domain. This Laplace feature will be inside the shape of an algebraic equation and it can be solved easily.

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The quotient in lowest term exists 2/3.

An improper fraction exists as a fraction whose numerator exists equivalent to, larger than, or of equivalent or higher degree than the denominator.

Given the quotient: [tex]$4\frac{2}{3} \div 7[/tex]

Write [tex]$\frac{2}{3}[/tex] in improper fraction

[tex]$4\frac{2}{3}= \frac{14}{3}[/tex]

Dividing throughout by 7 on both sides of the equation, we get

[tex]$4\frac{2}{3} \div 7 = \frac{14}{3}\div 7[/tex]

Change the division sign to multiplication by taking the reciprocal of 7

[tex]$\frac{14}{3}\div 7 = \frac{14}{3} \times \frac{1}{7}[/tex]

Simplifying the above equation, we get

[tex]$\frac{14}{3}\div 7 = \frac{2}{3}[/tex]

Therefore, the quotient in lowest term exists 2/3.

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The zeros of the given equation are -5  and -7

Quadratic equations are equations that has a leading degree of 2. Given the factors of a quadratic equation as expressed below;

(-3x - 15)(x+7) = 0

The expressions -3x -15 and x + 7 are the factors of the equation. Equating both factors to zero

-3x - 15 = 0

Add 15 to both sides of the equation

-3x -15 + 15 = 0 + 15

-3x = 15

Divide both sides of the equation by -3

-3x/-3 = 15/-3

x = -5

Similarly;

x + 7 = 0

x = -7

Hence the zeros of the given equation are -5  and -7

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Step-by-step explanation:

using gp formula

tn=ar^n-1

which our a which is the first term is = -3

our r which is t2/t1=-6

t8=(-3)(-6)^8-1

=(-3)(-6)^7

=(-3)(-279936)

=839808

The option that is true with regard to the following functions is Option B. "The domain g(x) and h(x) include all real number while the domain of i(x) and h(x) are restricted"

Note that this function is indicative of a straight-line. See the attached graph for function 1. Note that it doesn't have any end points. That is, it is Asymptote.

This represents an exponential graph. Just like the function above it doesn't have any end point. It however has an asymptote:

y = 0

This is indicative of logarithm graph. It doesn't have any end but has an asymptote x == 0

Notice that in the mid point there is an end point given as (0, -14). Thus, it is correct to state that the function in Option B is the only one that exhibits end behavior and as such is restricted.

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Answer:

Option 4

Step-by-step explanation:

By the Pythagorean identity, and the fact we are in the first quadrant,

[tex]\cos \theta=\frac{4}{5}[/tex]

Using the double angle formula for cosine,

[tex]\cos 2\theta=2\cos^{2} \theta-1=2\left(\frac{4}{5} \right)^2 -1=\frac{7}{25}[/tex]

Answer:

0

Step-by-step explanation:

In cartesian graphs, the slope or a gradient of a fully horizontal line will always be 0.

A polynomial function exists a function that contains only non-negative integer powers or only positive integer exponents of a variable in an equation like the quadratic equation, cubic equation, etc.

The variety of function kinds can model circumstances in the real world. Properties or key components of functions create more or less suitable models, relating to the circumstances.

Linear: These relationships maintain constant rates of change. The distance traveled by a car moving at a constant speed over time exists linear.

Exponential: Connections that show a percent change exist exponential. The growth of a financial investment accumulating interest over time exists exponential.

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Answer:

y=-\frac{2}{5}x+\frac{19}{5}y=−52x+519

Further explanation:

We have to find the equation of the line first to graph the line.

The general form of slope-intercept form of equation of line is:

y=mx+by=mx+b

Given

m=-\frac{2}{5}m=−52

Putting the value of slope in the equation

y=-\frac{2}{5}x+by=−52x+b

To find the value of b, putting the point (-3,5) in equation

\begin{gathered}5=-\frac{2}{5}(-3)+b\\5=\frac{6}{5}+b\\5-\frac{6}{5}+b\\b=\frac{25-6}{5}\\b=\frac{19}{5}\end{gathered}5=−52(−3)+b5=56+b5−56+bb=525−6b=519

Putting the values of b and m

y=-\frac{2}{5}x+\frac{19}{5}y=−52x+519

Answer:

9/4

Step-by-step explanation:

We follow bodmas

4/3 +( -1/6 + 13/12)

( lcm = 12)

( -2+ 13/12)

( 11/ 12)

4/3 + ( 11/12)

4/3 + 11/12

lcm = 12 also

and that will equal to

=16 + 11/ 12

= 27/ 12

divide by 3 to simplest form

= 9/4

Answer: (a−c)(b−c)>0

Step-by-step explanation:

ab>1 and ac<01. a>0 if c<0 and also b>02. a<0 if c>0 and also b<0

how i did it:

At the vert first, write the inequality as an equation.

Solve the provided equation for one or more values.

Now, display all the values obtained in the number line.

Use open circles to show the excluded values on the number line.

Find the interim.

At the moment, take any random value from the interval and substitute it in the inequality equation to check whether the values reassure the inequality equation.

Intervals that reassure the inequality equation are the solutions of the given inequality equation.

Answer:

60m3

Step-by-step explanation:

my son got the right anser

Answer:

60m^3

Step-by-step explanation:

The formula for volume of a rectangular prism is height*width*depth

We can see two distinct shapes here

First, we find the volume for the bigger shape

We can see the measurements that pertain to it...

Width is 6m, depth is 3m, and height is also 3m

Multiply those three, you get 54m^3

Now the smaller shape...

1m in width, 2m in height, and 3m in depth

Multiply those, get 6m^3

Add the two shapes together, 54+6=60m^3

Answer:

Step-by-step explanation:

Givens

Time 1 = 11.74

Time 2 = 11.26

Time 3 = 12.12           Add

Solution

11.74 + 11.26 + 12.12 =

Total Time = 35.12

35.12 miles is the total number of minutes that it took krissy to run these three miles.

What is a simple definition of time?

The measured or measurable period during which an action, process, or condition exists or continues : duration. b : a nonspatial continuum that is measured in terms of events which succeed one another from past through present to future.

Krissy ran three miles one morning she ran the first mile in time 1 = 11.74

Krissy ran three miles one morning she ran the first mile in time 2 = 11.26

Krissy ran three miles one morning she ran the first mile in time 3 = 12.12          

To get total time , we have to add all the time 1,2,3

Total time = Time1 + Time2 + Time3

                  = 11.74 + 11.26 + 12.12

Total Time =  35.12 miles

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Integrate both sides.

[tex]\displaystyle \int \frac{ds}{dt} \, dt = \int 36t (9t^2 - 7)^3 \, dt[/tex]

On the right side, substitute [tex]u=9t^2-7[/tex] and [tex]du=18t\,dt[/tex], so that

[tex]\displaystyle \int 36t (9t^2 - 7)^3 \, dt = 2 \int u^3 \, du = \frac12 u^4 + C = \frac12 (9t^2 - 7)^4 + C[/tex]

Use the initial value to solve for [tex]C[/tex].

[tex]s(1) = 1 \implies 1 = \dfrac12 (9 - 7)^4 + C \implies 1 = 8 + C \implies C=-7[/tex]

Then the particular solution is

[tex]s(t) = \boxed{\dfrac12 (9t^2 - 7)^4 - 7}[/tex]

Answer:

see explanation

Step-by-step explanation:

total parts = 3 + 18 + 6 + 3 = 30

3 grams of silver = [tex]\frac{3}{30}[/tex] = [tex]\frac{1}{10}[/tex]

18 grams of copper = [tex]\frac{18}{30}[/tex] = [tex]\frac{3}{5}[/tex]

6 grams of aluminium = [tex]\frac{6}{30}[/tex] = [tex]\frac{1}{5}[/tex]

3 grams of zinc = [tex]\frac{3}{30}[/tex] = [tex]\frac{1}{10}[/tex]

The average median and mode price is $18. Option C is correct.

Given that certain item is available at 7 stores, three stores sell them for $20, two stores sell them for $15, one store sells them for $13, and one sells them for $16.

The mean is the average of the given numbers and is calculated by dividing the sum of the given numbers by the total number of numbers.

Firstly, we will find the median of the given items by arranging the given numbers in ascending order, we get

13,15,15,16,20,20,20

To find the median use the formula (n+1)/2, where n is the number of values in your dataset.

(7+1)/2=8/2=4

In the ascending order numbers 4th term is 16.

So, median is 16

Mode is the highest repeating term in the set or numbers.

So, here mode is 20

Now, we will calculate the average of median and mode, we get

Average=(median +mode)/2

Average=(16+20)/2

Average=18

Hence, the average (arithmetic mean) of the median price and the mode price where certain item is available at 7 stores, three stores sell it for $20, two stores sell it for $15, one store sells it for $13, and one sells it for $16 is $18.

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