The specific heat of the metal, given the data from the question is 0.60 J/gºC
Data obtained from the questionThe following data were obtained from the question:
Mass of metal (M) = 74 gTemperature of metal (T) = 94 °CMass of water (Mᵥᵥ) = 120 g Temperature of water (Tᵥᵥ) = 26.5 °C Equilibrium temperature (Tₑ) = 32 °C Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC Specific heat capacity of metal (C) =? How to determine the specific heat capacity of the metalThe specific heat capacity of the sample of gold can be obtained as follow:
According to the law of conservation of energy, we have:
Heat loss = Heat gain
MC(T –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)
74 × C(94 – 32) = 120 × 4.184 (32 – 26.5)
C × 4588 = 2761.44
Divide both side by 4588
C = 2761.44 / 4588
C = 0.60 J/gºC
Thus, the specific heat capacity of the metal is 0.60 J/gºC
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What is the structure of polypropylene
The Structure of polypropylene(C3H6)n is linear.
The chemical formula for polypropylene is (C3H6)n.It is a polymer with complex structure and also known as polypropene. Polypropylene is similar to polyethylene which belongs to polyolefin groups. Generally the polymers are synthesized from the polymerization process.What is polymerization?The process in which atom or small molecules joined together repeatedly to form a polymer with complex structure is called as polymerization.
The repeated unit of atom or small molecule is called monomer
Structure of polypropylenePolypropylene is synthesized from the polymerization of propylene which is the monomer unit.
It has a linear structure made of propylene hydrocarbon units.
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How many grams in 1.61 x 1023 molecules of water (H2O)
Taking into account the definition of Avogadro's number and molar mass, 4.806 grams of water are present in 1.61×10²³ molecules.
Definition of Avogadro's NumberAvogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
Definition of molar massThe molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
Mass of waterTaking into account the definition of Avogadro's Number, you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of water, then 1.61×10²³ molecules are contained in how many moles of water?
amount of moles of water= (1.61×10²³ molecules× 1 mole)÷ 6.023×10²³ molecules
amount of moles of water= 0.267 moles
Now, taking into account the definition of molar mass, and knowing that the molar mass of water is 18 g/mole, you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 18 grams, 0.267 moles of the compound contains how much mass?
[tex]mass= \frac{0.267 molesx 18 grams}{1 mole}[/tex]
mass= 4.806 grams
Finally, 4.806 grams of water are present in 1.61×10²³ molecules.
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If 40g KCI are dissolved in 100g of water at 20 degrees C, what type of solution does
it form?
Answer:
neutral
Explanation:
dss
If you burn 9.1 L of octane gas (C8H18), how many liters of steam will you produce?
From the stoichiometry of the reaction, the volume of the steam produced is 82.9 L
What is combustion?The term combustion is the term that is used to describe the kind of reaction that occurs when a substance is being burnt in oxygen. It is an oxidation reaction and the octane is burnt to produce carbon dioxide and steam.
We can try to write down the equation of the reaction as follows;
2C8H18(g) + 25O2(g) ------> 16CO2(g) + 18H2O(g)
Now 1 mole of octane gas occupies 22.4 L
x moles of octane gas occupies 9.1 L
x = 9.1 L * 1 mole /22.4 L
x = 0.41 moles
Now;
2 mole of octane gas produces 18 moles of steam
0.41 moles of octane gas produces 0.41 moles * 18 moles/2 mole
= 3.7 moles
1 mole of steam occupies 22.4 L
3.7 moles of steam occupies 3.7 moles * 22.4 L/1 mole
= 82.9 L
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Identify the type of compound that would have the following properties?
Conducts electricity when melted or dissolved in water.
High Melting Point
Usually a Solid
Group of answer choices
A. Ionic
B. Metallic
C. Covalent
D. Molecular
Answer:
The correct answer is A
Explanation:
Ionic compounds conduct electricity when molten (liquid) or in an aqueous solution because their ions are free to move from place to place
hope it will help you
hope it will help you
Question 21
Which of the following salts will produce an acidic solution?
K2CO3
Sr(CIO4)2
KBr
NH41
NaNO3
Answer:
NH4
Explanation:
its an acid duhhhhhhhhh
Select which of the following characteristics match with the correct state of matter.
No definite shape
Highly compressible
Definite volume
Low density
The gases have no definite shape, low density, and are highly compressible while the liquids only have a definite volume but no definite shape.
What is a Matter?Any substance which has mass and occupies space is called matter. Commonly, there are three states of matter that are:
Solid - Solids have a rigid shape, definite volume, and high density.Liquid - Liquids have definite volume but no definite shape. They take the shape of the container in which they are placed.Gas - Gases have neither definite shape nor definite volume and have low density. They completely occupy the container in which they are placed.There are other two states of matter that are Plasma and man-made Bose-Einstein condensates. They are not so common.
Plasma is commonly found in the universe. Stars are the superheated balls of the plasma.
Thus, gases have no definite shape, low density, and are highly compressible. On the other hand, the liquids only have a definite volume but no definite shape.
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At the equivalence point of a titration of the [H+] concentration is equal to:
Group of answer choices
A. 1 x 107 M
B. 7
C. [OH-]
D. 1 x 10-7 M
B. At the equivalence point of a titration of the [H+] concentration is equal to 7.
What is equivalence point of a titration?The equivalence point of a titration is a point in titration at which the amount of titrant added is just enough to completely neutralize the analyte solution.
At the equivalence point in an acid-base titration, moles of base equals moles of acid and the solution only contains salt and water.
At the equivalence point, equal amounts of H+ and OH- ions combines as shown below;
H⁺ + OH⁻ → H₂O
The pH of resulting solution is 7.0 (neutral).
Thus, the pH at the equivalence point for this titration will always be 7.0.
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What is an alkaline
Answer:
is a solution whose pH is above 7or is a basic solution
Water is a(n)______ molecule, and it easily dissolves _______ molecules.
A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.
Br2(g) + I2(g) ↔ 2IBr(g)
When the mixture has come to equilibrium, the concentration of iodine monobromide is 1.190 M. What is the equilibrium constant for this reaction at 350°C?
The equilibrium constant for this reaction at 350°C is determined as 5.85.
Concentration of each componentconcentration of bromine, C(Br) = 0.6 mol/1 = 0.6
concentration of iodine, C(I) = 1.6 mol/1 = 1.6
Create an ICE tableWhat is ICE table?An ICE table is a tabular system of keeping track of changing concentrations in an equilibrium reaction.
ICE is an abbreviation that stands for initial, change, equilibrium.
Create ICE table for the reactants and products formed;
Br2(g) + I2(g) ↔ 2IBr(g)
I 0.6 1.6 0
C -1.19 -1.19 1.19
E 0.6 - 1.19 1.6 - 1.19 1.19
E = -0.59 0.41 1.19
Equilibrium constantThe equilibrium constant is calculated as follows;
KC = [IBr]²/[Br][I]
KC = (1.19²) / (0.59 x 0.41)
KC = 5.85
Thus, the equilibrium constant for this reaction at 350°C is determined as 5.85.
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A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.
Br2(g) + I2(g) ↔ 2IBr(g)
When the mixture has come to equilibrium, the concentration of iodine monobromide is
1.190 M. What is the equilibrium constant for this reaction at 350°C? Show step-by step explanation.
A) 3.55 × 10^3
B) 1.24
C) 1.47
D) 282
E) 325
The equilibrium constant for this reaction at 350°C is D. 282.
Equilibrium constantA dynamic chemical system approaches chemical equilibrium constant when enough time has passed and its composition no longer exhibits any discernible propensity to change further. The equilibrium constant of a chemical reaction is the value of its reaction quotient in this condition. The equilibrium constant is independent of the initial analytical concentrations of the reactant and product species in the mixture for a specific set of reaction conditions. Understanding equilibrium constants is crucial for comprehending many chemical systems as well as biological processes like the transport of oxygen by hemoglobin in the blood and the maintenance of acid-base homeostasis in the human body. There are many different kinds of equilibrium constants, including stability constants, formation constants, binding constants, association constants, and dissociation constants.
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A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.
Br2(g) + I2(g) ↔ 2IBr(g)
When the mixture has come to equilibrium, the concentration of iodine monobromide is
1.190 M. What is the equilibrium constant for this reaction at 350°C? Show step-by step explanation.
A) 3.55 × 10^3
B) 1.24
C) 1.47
D) 282
E) 325
The reaction of charcoal (carbon) and oxygen is sped up by grinding the charcoal into a fine powder. This is an example of:
Group of answer choices
A. All of the above
B. Increasing concentration to increase reaction rate
C. Increasing temperature to increase reaction rate
D. increasing surface area to increase reaction rate
Answer:
D
Explanation:
Grinding to a powder increases the surface area of the charcoal .
The reaction of charcoal (carbon) and oxygen is sped up by grinding the charcoal into a fine powder. This is an example of increasing surface area to increase reaction rate. Option D is the answer.
Reason for the grindingGrinding charcoal into a fine powder enhances its reactivity by increasing surface area. This finer texture promotes more frequent collisions between charcoal particles and oxygen molecules, facilitating faster chemical reactions.
The heightened contact points enable efficient utilization of reactants, optimizing resource consumption. Shorter diffusion paths within smaller particles expedite reactant diffusion, aiding quicker reaction rates.
Additionally, the augmented surface area promotes efficient heat transfer, crucial in reactions involving temperature changes.
Grinding charcoal amplifies the reaction rate by maximizing interaction opportunities, accelerating the conversion of charcoal and oxygen into products.
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whats 21-4/1002-730+83920/839
The answer will be - 1.67 x [tex]10^{-6[/tex]
Mathematical operationsThe problem can be solved by using the rule of BODMAS.
21-4/1002-730+83920/839
First, the operation is divided into 3 parts
21-41002-730+83920839For the first part:
21 - 4 = 17
For the second part:
1002-730+83920
According to BODMAS, addition operations come before subtractions.
So, the operation becomes (1002)-(730+83920)
= (1002) - (84650)
= -83648
The entire operation becomes 17/-83648/839
17/-83648 x 1/839 = -17/70180672
= - 1.67 x [tex]10^{-6[/tex]
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A nitric acid solution that is 70.0% HNO3 (by mass) contains:
Question 8 options:
70.0 g HNO3 and 100.0 g water
70.0 mol HNO3
70.0 g HNO3 and 30.0 g water
70.0 g HNO3 and 70.0 g water
none of the above
Answer:
Correct answer is option C
70.0 g HNO3 and 30.0 g water
A 7.74 L balloon is filled with water at 3.88 atm. If the balloon is squeezed into a 0.23 L beaker and does NOT burst, what is the pressure of water in the balloon?
Answer:
131 atm
Explanation:
To find the new pressure, you need to use Boyle's Law:
P₁V₁ = P₂V₂
In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new pressure (P₂) by plugging the given values into equation and simplifying.
P₁ = 3.88 atm P₂ = ? atm
V₁ = 7.74 L V₂ = 0.23 L
P₁V₁ = P₂V₂ <----- Boyle's Law
(3.88 atm)(7.74 L) = P₂(0.23 L) <----- Insert values
30.0312 = P₂(0.23 L) <----- Simplify left side
131 = P₂ <----- Divide both sides by 0.23
Chromium metal can be produced by the following reaction:
3Si + 2Cr2O3 - 4Cr + 3SiO2
In an experiment where there is an excess of cr2o3, what mass (in grams) of cr can be produced from 0.250 moles of si?
Answer:
17.3 g Cr
Explanation:
To find the mass of chromium, you need to (1) convert moles Si to moles Cr (using the mole-to-mole ratio from equation coefficients) and then (2) convert moles Cr to grams Cr (using the atomic mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (0.250).
3 Si + 2 Cr₂O₃ ---> 4 Cr + 3 SiO₂
^ ^
Atomic Mass (Cr): 51.996 g/mol
0.250 moles Si 4 moles Cr 51.996 g
------------------------- x -------------------- x ------------------- = 17.3 g Cr
3 moles Si 1 mole
If the energy difference between two electronic states is 214.68 kJ / mol , calculate the frequency of light emitted when an electron drops from higher to lower state. Planck's constant , h = 39.79 × 1/10¹⁴ kJ sec per mol .
[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Here we go ~
Energy difference btween the two electronic states can be expressed as :
[tex]{ \qquad \sf \dashrightarrow \: \Delta E = h\nu} [/tex]
[ h = planks constant,[tex]{\: \nu } [/tex]= frequency ]
[tex] \qquad \sf \dashrightarrow \:214.68 = 39.79 \times 10 {}^{ - 14} \times \nu[/tex]
[tex]\qquad \sf \dashrightarrow \: \nu = \cfrac{214.68}{39.79 \times 10 {}^{ - 4} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \nu = \cfrac{214.68}{39.79 } \times 10 {}^{14} [/tex]
[tex]\qquad \sf \dashrightarrow \: \nu \approx 5.395 \times10 {}^{14} \:\:hertz[/tex]
The equilibrium constant for reaction (1) below is 276. Under the same conditions, what is the equilibrium constant of reaction (2) ? (Think about the basic definition !)
(1) 1/2 X2(g) + 1/2 Y2(g) ↔ XY(g)
(2) 2XY(g) ↔ X2(g) + Y2(g)
The equilibrium constant of the reaction is 76176.
What is the equilibrium constant?In chemistry, the equilibrium constant is used to show the extent to which we can convert reactants to products in a given chemical process. A large value of the equilibrium constant shows that most of the reactants are converted into products under the given conditions. A small value of the equilibrium constant shows that most of the reactants are not converted into products.
Thus, if we have the reactions;
(1) 1/2 X2(g) + 1/2 Y2(g) ↔ XY(g)
(2) 2XY(g) ↔ X2(g) + Y2(g)
It then follows that;
K1 = [XY]/[X2]^1/2 [Y2]^1/2
K2 = [XY]^2/[X2] [Y2]
It is clear that;
K2 = (K1)^2
K2 = (276)^2
K2 = 76176
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Which element belongs to the p6-block of the periodic table?
Oalkaline earth metals
Ohalogens
alkali metals
Onoble gases
Which of the following materials is the least porous?
loosely packed gravel
unsorted sand and rock
large pebbles and boulders
sorted sand and rock
Answer:
The answer is The unsorted sand and rock is the least porous.
Answer:
large pebbles and boulders
is there any methods to determine number of water crystallization?
Answer:
In the formula, we can see that for each unit of copper(II) sulfate, there are five molecules of water associated with it. One way to determine the amount of water of crystallization in a hydrated salt is to use volatilization gravimetry
If an electron falls from the n = 2 to the n = 1 energy levels in a Hydrogen atom what wavelength of light is emitted?
Group of answer choices
A. 122 nm
B. 1024 nm
C. 97 nm
D. 103 nm
A. The wavelength of light that is emitted is 122 nm.
What is wavelength?
Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire.
Wavelength of light is emittedWhen an electron falls from the n = 2 to the n = 1 energy levels in a Hydrogen atom, the wavelength of light is emitted is calculated as follows;
¹/λ = R(1/n₁² - 1/n₂²)
¹/λ = 109677(1/1 - 1/2²)
¹/λ = 109677(1 - ¹/₄)
¹/λ = 82,257.25
λ = 1/8,225.25
λ = 1.22 x 10⁻⁵ cm
λ = 1.22 x 10⁻⁷ m
λ = 122 nm
Thus, the wavelength of light that is emitted is 122 nm.
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QUESTION 16
What is the product of the following reaction?
+ H₂(g) → ?
Answer:
n2(g)+3h2(g)→2nh3(g) balanced
Explanation:
Wayne Breslyn
Write the balanced redox reaction Fe2+ and MnO4
Answer:
The balanced equation is 5Fe2++MnO-4+8H+→5Fe3++Mn2++4H2O .
Explanation:
˙˚ʚ(´◡`)ɞ˚˙
Answer:
5Fe2++MnO-4+8H+→5Fe3++Mn2++4H2O .
Explanation:
When potassium permanganate is stirred in water, it turns to purple. How would
you describe whether this mixture is a suspension or a solution?
The energy required for the hypothetical reaction
2A+B⇌2C+2D
is 309 kJ as written.
How much heat is absorbed when 2.60 mol of A reacts?
Express your answer to three significant figures and include the appropriate unit.
Answer:
402 kJ
Explanation:
Because the energy of the reaction is positive, the reaction is endothermic. This means energy is a reactant.
You can determine how much energy/heat is absorbed using the balanced chemical equation. You can convert the moles A using the ratio composed of the coefficient in front of A and the energy required for each reaction.
2A + B + 309 kJ ⇌ 2C + 2D
2.60 moles A 309 kJ
---------------------- x -------------------- = 402 kJ
2 moles A
The density of molybdenum is 10.28 g/cm^3 and it crystallizes in the face centered cubic unit cell. Calculate the edge length of the unit cell. (The atomic mass of Mo is 95.96 g/mole)
The edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.
What is cubic unit cell?The cubic unit cell is the smallest repeating unit when all angles are 90 degrees and all lengths are equal.
Volume of molybdenumThe volume of the molybdenum is calculated from mass and density of the molybdenum as shown below;
V = (zm/ρN)
where;
z is 2 for cubic unit cellm is mass of the molybdenumρ is density of the molybdenumV = (2 x 95.96) / (10.28 x 6.02 x 10²³)
V = 3.10 x 10⁻²³ cm³
Edge length of the unit cella³ = V
a = (V)^¹/₃
a = ( 3.10 x 10⁻²³)^¹/₃
a = 3.142 x 10⁻⁸ cm
a = 3.142 x 10⁻¹⁰ m
a = 314.2 x 10⁻¹² m
a = 314.2 pm
Thus, the edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.
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What is a catalyst?
Group of answer choices
A. A substance that speeds up the reaction by increasing the activiation energy.
B. A substance added to the reaction that lowers the activation energy by providing an alternate pathway for the reactions to go to completion.
C. A substance that slows down the reaction by lowering the activation energy.
D. A substance added to the reaction that raises the activation energy by providing an alternate pathway for the reactions to go to completion.
A catalyst is a substance added to the reaction that lowers the activation energy by providing an alternate pathway for the reactions to go to completion.
A catalyst is a substance that accelerates a chemical response, or lowers the temperature or strain needed to begin one, with out itself being ate up at some stage in the response. Catalysis is the procedure of adding a catalyst to facilitate a response.
Catalysts may be categorized as homogeneous, heterogeneous, or enzymatic. Homogeneous catalysts exist inside the identical phase as the reactants, whereas heterogeneous catalysts exist in a exclusive section than the reactants.
Catalysts are basically categorised into 4 kinds.Homogeneous, Heterogeneous, Heterogenized homogeneous catalyst and Biocatalysts. Homogeneous catalyst: In homogeneous catalysis, reaction mixture and catalyst both are gift inside the equal segment.
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Assuming ideal solution behavior, what is the boiling point of a solution of 115.0 g of nonvolatile sucrose (table sugar), C₁₂H₂₂O₁₁ (342.300 g/mol), in 350.0 g of water (Kb = 0.512 °C m⁻¹; boiling point = 100.0 °C)?
The boiling point of the solution will be 100.97 ° C.
[tex]T_f[/tex], pure water = 0.00 ° Celsius.
[tex]T_b[/tex] , pure water = 100° Celcius
[tex]K_b[/tex] = 0.512 C kg/mol
[tex]K_f[/tex] = -1.86 C kg/mol.
Given,
[tex]K_b = \frac{0.512 C kg}{mol}[/tex]
[tex]m = \frac{115g \frac{mol }{342.300g} }{0.35 kg}[/tex]
m = 0.95
i = 2 ( assuming no ion pairing)
Now, recall,
Δ[tex]T_b[/tex] =[tex]iK_bm[/tex]
Hence,
Δ[tex]T_b[/tex] = [tex]iK_bm[/tex]
= 2 × 0.512 × 0.95
= 0.97 °C
Therefore, the boiling point of the solution will be 100.97 °C.
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