Una química tiene 3 soluciones acidas de varias concentraciones. La primera es 10% acida; la segunda 20% y la tercera 40%. ¿Cuántos mililitros de cada una debe ella usar para hacer 100ml de una solución al 18%, si tiene que usar cuatro veces mas de la solución al 10% que de la solución al 40%?

The total cost to run Val’s AC costs for a summer month of 30 days is $94.5.

Quantity of electricity used in kilowatts

1000 watts = 1 kilowatts

2,500 watts = 2.5 kilowatts

Cost of Val’s AC to run for a summer month of 30 days = Quantity of electricity used × Number of hours Val runs AC per day × Number of days × Cost of electricity

= 2.5 × 7 × 30 × 0.18

= $94.5

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Following the instructions for the inequalities gives the following results:

1. 4<7, both sides multiplied by 7

= 28<49, both sides multiplied by 6

= 168<294, both sides multiplied by 3

= 504<882, both sides multiplied by 10

= 5,040<8,820

2. 11>2, add 5 to both sides

= 16>3, add 3 to both sides

= 19>9, add -4

= 15>5

3. -4<-2, subtract 6

= -10<-8, subtract 8

= -18<-16, subtract 2

= -20<-18

4. -8<8, divide by -4

= 2>-2, divide by -2

= -1<1

5. The inequalities remain correct at the end because the same mathematical operations are performed on both sides simultaneously.

Inequality is a relationship of a non-equal comparison between two numbers or algebraic expressions.

Inequality can be represented as greater than, greater than or equal to, less than, or less than or equal to.

Thus, the rules for inequalities show that if one adds to, subtracts from, multiplies by, or divides by the same number on both sides of an inequality, the inequality remains true.

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Answer:

a=–2, 3

Step-by-step explanation:

r(a)=20

a²–a+14=20===> a²–a–6=0===> (a–3)(a+2)

Answer: Neither

Step-by-step explanation:

It is not an angle of the quadrilateral, so it is not an interior angle.

It does not form a linear pair with any interior angle of the quadrilateral, so it is not an exterior angle.

[tex]v(x) = wlh \\ 2x {}^{3} + {x}^{2} - 16 x- 15 =(2x + 5)(x - 3)h \\ h = \frac{2x {}^{3} + x {}^{2} - 16x - 15 }{2x {}^{2} - x - 15 } \\ using \: long \: divison \\ h = x + 1[/tex]

Answer:

17

Step-by-step explanation:

i think its the right answer

May this answers be helps you to solve

Answer:

1575

Step-by-step explanation:

105

× 15

  525             ( First multiply 105 by 5 )

+1050             ( Then multiply 105 by 1.  Remember to place a 0 below 5 )

                      ( It is very important to write each and every number in a

                                                         straight line)

   1575             ( Now add them )  

∴ 105 × 15 = 1575

The pair of words that describe the given system of equations is: consistent and dependent.

A mathematical statement that has a "equal to" symbol between two expressions with equal values is called an equation.

It demonstrates the equality of the relationship between the expressions written on the left and the right.

Given equations:

3y=9x-6

2y-6x=4

The first equation can be simplified and written as: y=3x-2

Similarly, the second equation can be written as: y-3x=2

It can be seen that the two equations are the same. Thus, the given system of equations is consistent and dependent.

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8.9 pounds of coffee A, 27.3 pounds of coffee B and 17.8 pounds of coffee C are need to make a blend that sells for $12.61 per pound.

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent coffee A, y represent coffee B and z represent coffee C, hence:

x + y + z = 54   (1)

Also:

2x = z        (2)

And:

15.21x + 13.21y + 10.39z = 12.61(54)   (3)

x = 8.9, y = 27.3 and z = 17.8

8.9 pounds of coffee A, 27.3 pounds of coffee B and 17.8 pounds of coffee C are need to make a blend that sells for $12.61 per pound.]

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Answer:  89 yards

Step-by-step explanation: The perimeter is all the sides added up together. Since the width of the field is 52, the two sides are 52 yards which in total is 104 yards. 282- 104 = 178 yards. The length is 178/2 yards which is 89 yards.

Answer:

75

Step-by-step explanation:

math

Answer: an improper fraction

Step-by-step explanation:  An improper fraction is a fraction that is larger than 1 7/3 is larger than one because 7, the numerator is larger than the denominator so 7/3 is an improper fraction

The sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2

The sum notation is given as:

∞Σn=1 2(1/5)^n-1

The above notation is a geometric sequence with the following parameters

The sum is then calculated as

S = a/(1 - r)

The equation becomes

S = 2/(1 - 1/5)

Evaluate the difference

S = 2/(4/5)

Express the equation as products

S = 2 * 5/4

Solve the expression

S= 5/2

Hence, the sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2

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Answer:

S = 5/2

Thank me later

Essentially just count the tick marks between the two letters.

JL= 5

JK= 3

KP= 9

NP= 2

JP= 12

LN= 5

The asked lengths are from the number line:

JK = 3, JL = 5, KP = 9, NP = 2, JP = 12 and LN = 5.

Given that is a number line we need to find the asked values,

1. JK =

K = -4 and J = -7

So, JK = -4-(-7)

JK = -4+7

JK = 3

2. JL =

J = -7 and L = -2

So, JL = -2-(-7)

JL = -2+7

JL = 5

3. KP =

K = -4 and P = 5
So, KP = 5-(-4)

KP = 9

4. NP =

N = 3 and P = 5

So, NP = 5-3

NP = 2

5. JP =

J = -7 and P = 5

So, JP = 5-(-7)

JP = 12

6. LN =

L = -2 and N = 3

So, LN = 3-(-2)

LN = 5

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The probability that the instructor asks one of Sam and John whose probabilities of being asked are as indicated in the task content is; 0.12.

It follows from the task content that the probability that Sam is being asked is; 0.05 while that for John being asked is; 0.07.

Consequently, we may conclude that the probability of either of the two classmates being asked the question in discuss is; the sum of the probabilities and hence, we have;

P(Sam or John) = 0.05 + 0.07

= 0.12.

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The number of cases after two years is 221.

As a result of the disease, the population of the village would decrease by 95% per year. The number of cases at the village is function of the rate of infection, the number of years and the beginning number of cases.

The exponential function that can be used to represent this situation is:

FV = P( 1 + r)^t

FV = 200 (1.05)^2 = 221

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Answer:

Step-by-step explanation:

3/5 = x/10

5x = 30

x = 6

6/10

Hey there!

Original equation:

3/5 = ?/10

Convert to:

3/5 = x/10

Cross multiply the numbers:

3 * 10 = 5 * x

Simplify it:

3 * 10 = 5 * x

30 = 5x

5x = 30

Divide 5 to both sides:

5x/5 = 30/5

Simplify it:

x = 30/5

x = 6

Therefore, your mystery number should be: 6

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

P(B) 7

Step-by-step explanation:

The answer is P (B)

Trabajando con porcentajes, concluimos que la pérdida es de $4800.

Sabemos que la inversión inicial es de $60000, y de esta cantidad, se pierde un 8%.

Entonces la pérdida va a ser el 8% de $60000.

Podemos escribir las relaciones:

$60000 = 100%

x = 8%

Queremos resolver esto para x, tomando el cociente entre esas relaciones y resolviendo para x obtenemos:

x = $60000*(8%/100%) = $60000*0.08 = $4800

Así, concluimos que la pérdida es de $4800.

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Based on the given parameters, the length of c is 8.0 units

The given parameters are

Angle c = 76 degrees

Side a = 20

Side b = 13

The length of c is then calculated using the following law of sines

c^2 = a^2 + b^2 - 2absin(C)

Substitute the known values in the above equation

So, we have

c^2 = 20^2 + 13^2 - 2 * 20 * 13 * sin(76)

Express 20^2 as 400

c^2 = 400 + 13^2 - 2 * 20 * 13 * sin(76)

Express 13^2 as 169

c^2 = 400 + 169 - 2 * 20 * 13 * sin(76)

Evaluate the product and sin(76)

c^2 = 400 + 169 - 520 * 0.9703

Evaluate the product

c^2 = 400 + 169 - 504.55

Evaluate the exponents

c^2 = 400 + 169 - 504.55

So, we have

c^2 = 64.45

Evaluate the square root

c = 8.0

Hence, the length of c is 8.0 units

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Information : The given hyperbola is a horizontal hylerbola with its centre (3 , -5) and one of its focus at (9 , -5) and vertex at (7 , -5) and as we can see that the focus and vertex have same y - coordinates, it must have its Transverse axis on line y = - 5.

Now,

it's vertex is given, I.e (7 , -5)

so, length of semi transverse axis will be equal to distance of vertex from centre, i.e

Now, it's focus can be represented as ;

[tex]\qquad \sf  \dashrightarrow \: (3 + ae, - 5 )[/tex]

so,

and we know, a = 4

[tex]\qquad \sf  \dashrightarrow \: 4e + 3 = 9[/tex]

[tex]\qquad \sf  \dashrightarrow \: 4e = 6[/tex]

[tex]\qquad \sf  \dashrightarrow \: e = \cfrac{3}{2} [/tex]

Now, let's find the measure of semi - conjugate axis (b)

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = {a}^{2} ( {e}^{2} - 1)[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 16( \frac{9}{4} - 1)[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 16( \frac{9 - 4}{4} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 16( \frac{5}{4} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 20[/tex]

[tex]\qquad \sf  \dashrightarrow \: b = \sqrt{20} [/tex]

So, it's time to write the equation of hyperbola, as we already have the values of a and b ~

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {(x - h)}^{2} }{ {a}^{2} } - \cfrac{( {y - k)}^{2} }{ {b}^{2} } = 1[/tex]

[ plug in the values, and h = x - coordinate of centre, and k = y - coordinate of centre ]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ ({x-3)}^{2} }{ {16}^{} } - \dfrac{ {(y+5)}^{2} }{ { {20} }^{} } = 1[/tex]

Hello and Good Morning/Afternoon:

Let's solve this problem step-by-step:

Let's find the format of the standard form of hyperbole:

 [tex]\hookrightarrow \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2} =1[/tex]

Let's find the value of a, b:

             [tex]a = \sqrt{(7-3)^2+(-5--5)^2} =\sqrt{16} =4[/tex]

           ⇒value of c: distance between focus (9, -5) and center (3, -5)

                  [tex]c = \sqrt{(3-9)^2+(-5--5)^2}=\sqrt{36} =6[/tex]

            ⇒ therefore:

                  [tex]b = \sqrt{c^2-a^2} =\sqrt{6^2-4^2}=\sqrt{20}[/tex]

Let's plug everything into our standard form of the equation:

   [tex]\frac{(x-3)^2}{4^2} -\frac{(y--5)^2}{(\sqrt{20})^2 } =1\\\frac{(x-3)^2}{16} -\frac{(y+5)^2}{20 } =1[/tex] <== Answer

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well, first off let's check those two points, we know it's centerd at (-26 , 120) and we also know it passes through (0 , 0), so the distance between those two points is its radius

[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{-26}~,~\stackrel{y_2}{120})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{(~~-26 - 0~~)^2 + (~~120 - 0~~)^2} \implies r=\sqrt{(-26)^2 + (120 )^2} \\\\\\ r=\sqrt{( -26 )^2 + ( 120 )^2} \implies r=\sqrt{ 676 + 14400 } \implies r=\sqrt{ 15076 } \\\\[-0.35em] ~\dotfill[/tex]

[tex]\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{-26}{h}~~,~~\underset{120}{k})}\qquad \stackrel{radius}{\underset{\sqrt{15076}}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - (-26) ~~ )^2 ~~ + ~~ ( ~~ y-120 ~~ )^2~~ = ~~(\sqrt{15076})^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (x+26)^2+(y-120)^2 = 15076~\hfill[/tex]

We can actually deduce here that when the tournament ended, team Olympus have tied for 13, 10, 7, 4, 1 times.

In Mathematics, inequality is used to express or show quantities that are less than, greater than, greater than or equal to,  less than or equal to.

The following can be seen in inequality expressions:

Looking at the question, we can see that each team plays exactly 19 games.

Every win (w) = 3

Every tie (t)= 1

Every loose = 0

But Olympus got a total of 28 points

Thus: 3w + t = 28 ---------(1)

Note that each team plays  19 games

Thus, T + W  ≤  19 --------------(2)

and T , W ≥ 0

Looking at equation (1) and (2)

=> 2W  ≥  9

=> W ≥ 4.5  

( match can be won in integers only )

=> W  ≥  5  

W - 5, 6, 7, 8, 9    

T - 13, 10, 7, 4, 1  

Loose - 1, 3, 5, 7, 9

Thus, team Olympus have tied for 13, 10, 7, 4, 1 times.

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The length of segment XY is 52 units and the length of segment HD is 26 units

Secant lines (a)

To do this, we make use of the following intersecting secant theorem

VZ * VW = VY * VX

Substitute the known values in the above equation

12 * 40 = VY * 8

Divide by 8

12 * 5 = VY

Evaluate the product

VY = 60

The length VX is

XY = VY - VX

Substitute the known values in the above equation

XY = 60 - 8

Evaluate

XY = 52

Hence, the length of segment XY is 52 units

Secant lines (b)

To do this, we make use of the following intersecting secant theorem

GH^2 = HC * HD

Substitute the known values in the above equation

13^2 = 6.5 * HD

Divide by 6.5

13^2/6.5 = HD

Evaluate the quotient

26 = HD

The length HD is

HD = 26

Hence, the length of segment HD is 26 units

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Sarah requires the purchase of additional 12 tickets to ensure her participation in the seven activities at the fair.

The additional tickets required by Sarah can be determined as follows:

Number of tickets purchased initially = 15

Number of tickets for playing a game = 3

Number of tickets for riding a ride = 6

Sarah can play five (5) games with 15 tickets (15/3).

Sarah can then purchase 12 additional tickets (6 x 2).

The later action enables Sarah to participate in 5 games and 2 rides, making it a total of 7 activities.

Thus, by purchasing additional 12 tickets, Sarah can participate in 5 games and 2 rides, making it a total of 7 activities.

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How many more tickets does Sarah require to ensure her participation in the seven activities at the fair?

Answer:

Step-by-step explanation:x+y+z=100(let x ,y,z represent the first second and third numbers respectively)

Therefore,y=2z

z=x-8

y=2x-16

substituting the values of x,y and z into the question,we have

x+(2x-16)+(x-8)=100

Simplifying,we have

4x-24=100

adding 24 to both sides of the equation,

4x=100+24

4x=124

dividing both sides of the equation by the co-efficient of x,we have

4x/4=124/4

4.31=124

therefore,x=31.

Answer: The slope is -2 and the y-intercept is (0,1)

Step-by-step explanation:

The area of the small poster is 160 inches square

From the information given, we have the poster to take the form of a rectangle

The formula for area of a rectangle is;

Area = length × width

For the smaller poster created using a scale of factor 2/3

Length = 2/ 3 × 24

Length = 16 inches

Width = 2/ 3 × 15

Width = 10 inches

Substitute into the formula

Area = 16 × 10

Area = 160 inches square

Thus, the area of the small poster is 160 inches square

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