Tritium, or 3h, has a half-life of 12. 32 years. imagine a sample of tritium is prepared. (a) what fraction of the sample will remain 3. 80 yr after its preparation?

Answer:

3.0 moles Al₂O₃

Explanation:

We do not know which of the reactants is the limiting reactant. Therefore, you need to convert both of the given mole values into the product. This can be done using the mole-to-mole ratio made up of the balanced equation coefficients.

4 Al + 3 O₂ -----> 2 Al₂O₃

6.0 moles Al            2 moles Al₂O₃
----------------------  x  -------------------------  =  3.0 moles Al₂O₃
                                    4 moles Al

4.0 moles O₂           2 moles Al₂O₃
----------------------  x  -------------------------  =  2.7 moles Al₂O₃
                                    3 moles O₂

As you can see, O₂ produces the smaller amount of product. This means O₂ is the limiting reactant. Remember, the limiting reactant is the reactant which runs out before the other reactant(s) are completely reacted. As such, the actual amount of Al₂O₃ produced is 2.7 moles.

However, since this problem is directly addressing how much Al₂O₃ is produced from Al, the answer you most likely are looking for is 3.0 moles Al₂O₃.

Answer:

pKb = 5

Explanation:

To find the pKb, you need to (1) calculate the pka (using the pKa equation) and then (2) calculate the pKb (using the relationship between the pKa and pKb).

(Step 1)

pKa = -log (Ka)

pKa = -log (1 x 10⁻⁹)

pKa = 9

(Step 2)

pKa + pKb = 14

9 + pKb = 14

pKb = 5

Answer:

80 m/hr

Explanation:

Changes from 20 to 100 meters in ONE Hour

    changes  80 meters in one hour    = 80 m/hr

The way to find the moles of CO2 in a pop are:

A mole is a measure of molecules that is equal to approximately 6.022x10^23 molecules. Using the ideal gas formula, one can find the number of moles of carbon dioxide in a container if you know the other needed parameters and conditions.

Based on the above, it should be noted that P is the pressure, V is the volume from, T is the temperature and R is a proportionality constant that is equal to 0.0821 L atm / K mol.

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The mass percent composition of C in glycine is 31.66%.

The formula mass of a substance is defined as the sum of the atomic masses of constituent atoms in an ionic compound. This is generally used for ionic compounds which do not contain discrete molecules, but ions as their constituent units.

Given,

Formula mass of C2H5NO2 = Molar mass of C2H5NO2

Molar mass of C2H5NO2 = 75.08 g

Futher we know that the 75.08g of glycine contain 24 g of carbon,

then mass percent composition of C in glycine can be given as,

% C = (mass of carbon/ molar mass of glycine) ×100

%C = (24/ 75.8) × 100

= 31.66%

Thus, we find that the mass percent composition of C in glycine is 31.66%.

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2mol of Hydrogen peroxide releases 196.6KJ heat

1mol releases

5mol releases

Answer: 491.5

Explanation:

Hope this helps :)

3rd statement about this acidic reaction is not true

In acidic reactions,  Litmus paper is available in red and blue varieties and is typically more trustworthy. To determine whether a solution is normal or acidic, use litmus paper. The acid or basic strength is not precisely outlined in Litmus's paper. Thus, Base causes red litmus to turn blue.

The pH scale has numbers 0 through 14. Seven is the neutral pH. Over 7 is a base, and anything below 7 is acidic.

H+ ions are present in all acidic reactions. As a result, whether mineral or organic, all acid solutions transmit electricity. They allow an electric current to flow through them.

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Answer:

mass number = 18

Explanation:

The mass number is the total amount of protons and neutrons in an atom. Therefore, if there are 8 protons and 10 neutrons, the mass number is 18 (8 + 10 = 18).

The treatment of tetrahydrofuran with excess HBr results in the formation of 1,4-dibromobutane as a major organic product .

THF which is  tetrahydrofuran is reated with excess of HBr at 373 K .The product is 1,4-dibromobutane as a major organic product .

In the mechanism proton having positive charge is attack on electron rich oxygen and protonated it then bromine anion attack at adjacent carbon and break carbon - protonated  oxygen bond and in he final step the hydroxyl group is protonated and remove as a water with attack at bromine anion .

Therefore , on treatment of tetrahydrofuran with excess HBr results in the formation of 1,4-dibromobutane as a major organic product .

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A molecular size affects the rate of evaporation when the larger the intermolecular forces in a compound, the slower the evaporation rate and this correlates with temperature change.

Molecular size seems to have an effect on evaporation rates in that the larger a molecule gets or grows from a base chemical formula, its evaporation rate will get slower.

This is a measure of the area a molecule occupies in three-dimensional space as this relates to the physical size of an individual molecule.

Hence, we can see that a molecular size affects the rate of evaporation the larger the forces, the lower the rate.

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12.28 L volume at 6.98atm in sample gas occupies 10. 28 l at 8. 34atm. Hence, option A is correct.

Ideal gas is a hypothetical gas whose molecules occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.

In the limit of low pressures and high temperatures, where the molecules of the gas move almost independently of one another, all gases obey an equation of state known as the ideal gas law:

PV = nRT,

When Temperature is constant so, it follow Boyle's law:

P1 V1 = P2 V2

P1 = 8.34atm, V1 = 10.28 L, P2 = 6.98atm

V2 = P1 V1 / P2

V2 = 8.34atm x 10.28 / 6.98atm

V2 = 12.28 L

12.28 L volume at 6.98atm in sample gas occupies 10. 28 l at 8. 34atm. Hence, option A is correct.

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Answer:

NH₄CN,  NH₄IO₃,  Fe(CN)₃,  Fe(IO₃)₃

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) NH₄CN

-----> NH₄⁺ and CN⁻

-----> +1 + (-1) = 0

2.) NH₄IO₃

-----> NH₄⁺ and IO₃⁻

-----> +1 + (-1) = 0

3.) Fe(CN)₃

-----> Fe³⁺ and CN⁻

-----> +3 + (-1) + (-1) + (-1) = 0

4.) Fe(IO₃)₃

-----> Fe³⁺ and IO₃⁻

-----> +3 + (-1) + (-1) + (-1) = 0

The percentage of the original sample which would remain after 17.5 days according to the given half-life of the isotope is; 22.06%.

The given sample in discuss has a half life of; 8.02 days, this therefore indicates that after 17.5 days, the number of half-life periods completed is; 17.5/8.02 = 2.18 half-lifes.

Hence, the percentage of the original sample remaining after 17.5 days can be evaluated as follows;

N = 100% × (0.5)^2.18

N = 100 × 0.22

N = 22.06%.

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Liquid acetaminophen for children is labeled 180 mg 3 ml. The strength expressed as grams per ml is 0.060.

Acetaminophen is a medicine that is used to treat all kind of pains. Headache, menstrual pain, stomach ache, etc. It also used to reduce fever and cold/cough.

Liquid acetaminophen for children is labeled as 180 mg/ 3ml

The 180 mg will be divided by 3 ml

180 mg/ 3ml = 60 mg/ml

The amount will be multiplied by 1 /1000 to get the quantity equal.

60 mg/ml x 1g / 1000 g

60 x 1/ 1000 mg/ml = 0.060

Thus, the strength expressed as grams per ml is 0.060.

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pH of the solution after 24. 00 ml of the hcl has been added is 12.87

millimoles NaOH = mL x M = 24.00 mL x 0.25 M = 6.00

millimoles HCl = 24.00 mL x 0.10 M = 2.40

total volume = 48.00 mL

.................................NaOH + HCl ==>NaCl + H2O

initial.........................6.00.........0............0.........0

added.....................................2.40............................

change.................... -2.40......-2.40.........+2.40.... +2.40

equilibrium.................3.60.........0..............2.40.......2.40

The NaCl contributes nothing to the pH of the final solution. The pH is determined by the excess of NaOH present. (NaOH) = millimoles/mL = 3.60/48.00 = 0.075 M = (OH^-)

pOH = -log (OH^-). Then

pOH = -log (0.075)

pOH =1.1249

As we know,

pH + pOH = pKw = 14.00

pH=14-pOH

pH=14-1.1249

pH=12.87

pH is a logarithmic measure of an aqueous solution's hydrogen ion concentration. pH = -log[H+], where log is the base 10 logarithm and [H+] is the concentration of hydrogen ions in moles per liter.

The pH of an aqueous solution describes how acidic or basic it is, with a pH less than 7 being acidic and a pH greater than 7 being basic. A pH of 7 is regarded as neutral (e.g., pure water). pH values typically range from 0 to 14, though very strong acids may have a negative pH and very strong bases may have a pH greater than 14.

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Answer:

Al₂O₃ + 6 NaOH -----> 2 Al(OH)₃ + 3 Na₂O

Explanation:

This is a double-displacement reaction. In these reactions, the cation of one compound is swapped with the cation of another.

It is important that the new products have an overall charge of 0. To do this, some compounds must have more than 1 atom of each ion.

1.) Al(OH)₃

-----> Al³⁺ and OH⁻

-----> +3 + (-1) + (-1) + (-1) = 0

2.) Na₂O

-----> Na⁺ and O²⁻

-----> +1 + 1 + (-2) = 0

An equation is balanced when there is an equal amount of each element on both sides of the reaction. If these values are unequal, you can add coefficients to modify the amounts of particular compounds.

The unbalanced equation:

Al₂O₃ + NaOH -----> Al(OH)₃ + Na₂O

Reactants: 2 aluminum, 4 oxygen, 1 sodium, 1 hydrogen

Products: 1 aluminum, 4 oxygen, 2 sodium, 3 hydrogen

The balanced equation:

Al₂O₃ + 6 NaOH -----> 2 Al(OH)₃ + 3 Na₂O

Reactants: 2 aluminum, 9 oxygen, 6 sodium, 6 hydrogen

Products: 2 aluminum, 9 oxygen, 6 sodium, 6 hydrogen

If the freezing point depression for a solution is 2.5°c and kf = 4.5°c/m, the molality of the solution is

m= 0.56m

While molecular weight (MW) and molecular weight (MW) may be used to measure concentration, molecular weight (MW) and molecular weight (MW) is used to measure molecular weight and concentration, respectively.

Generally, the equation for  of freezing point of depression with molality is  mathematically given as

[tex]\Delta T_{f} = k_{f} *m[/tex]

Therefore

m = 2.5/4.5

m= 0.56m

In conclusion,  the molality of the solution  is 0.56m

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Formic acid (ch2o2)  on reaction with water undergoes dissociation reaction.

Formic acid  is the acid released by ant when it bites which causes us irritation.

It's formula is CH2O2 or HCOOH. and pH is 3.75.

In the case of dehydration, one hydrogen atom in the water molecule joins the hydroxyl group in the trans formic acid to form a new water molecule, while the hydrogen bonded to carbon in the acid breaks off to regenerate a water molecule.

Formic acid dissociates in water according to the equation:

HCOOH (aq) + H2O (l) = H3O + (aq) + HCOO- (aq)

Formic acid is the simplest carboxylic acid, containing a single carbon. Occurs naturally in various sources including the venom of bee and ant stings, and is a useful organic synthetic reagent. Principally used as a preservative and antibacterial agent in livestock feed.

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Answer:

decreased by a factor of 10

Explanation:

pH is defined in such a way that;

pH= −log10(H)

Where H represents the concentration of Hydronium or Hydrogen ions

Given that pH is changed from 1 to 2,

By rearranging the above formula , we get 10−pH = H

Therefore,  0.1/0.01 = 10 and 0.1 > 0.01

Hence, the concentration of hydronium ions in the solution is decreased by a factor of 10

Answer:

I think it involves the use of extractive distillation but I'm not sure.

Still hope it helps:-)

The physical property is used to separate cyclohexanone from any unreacted cyclohexanol is distillation.

The process for separating cyclohexanone from cyclohexanol comprises the following steps

1. reacting a mixture of ketone and alcohol with an organometallic compound M(X)n to form compound HX, wherein M is chosen from aluminium, titanium and boron, where n is the valance of a M, X denotes equal or different organic group chosen from alkyl group and electric group having up to 10 carbon atom

2. liberating the newly formed compound HS from the reaction mixture by distillation

3. separating the ketone from the organometallic compound formed by reaction between M(X)n and the alcohol in the mixture.

Thus, we concluded that above compound is seprated by forming organometallic compound.

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Styrene is an organic chemical used to make rubber, latex, resins, etc. It can be best converted using the anti-Markovnikov rule by (1) BH₃ - THF and (2) H₂O₂, NaOH. Thus, option B is correct.

The anti-Markovnikov rule defines the attachment of the substituent group to the least substituted carbon than the more substituted groups. This is due to the induction and hyperconjugation effect.

To convert styrene, the alcohol group from sodium hydroxide must be added to the least substituted carbon of the compound using other reagents like BH₃ - THF and hydrogen peroxide.

Therefore, option B. (1) BH₃ - THF and (2) H₂O₂, NaOH can be used to convert styrene.

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Your question is incomplete, but most probably your full question was, What is the best method to convert styrene, C₆H₅CH=CH₂, to 2-phenyl ethanol with minimal side product formation?

Each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure and diffusion occurs until equilibrium is reached.

The gas exchange refers to the process by which oxygen is absorbed by red blood cells and carbon dioxide is removed through the respiratory system.

The process of gas exchange is carried out due to the differential diffusion rates of gases in the bloodstream (O2 and CO2), which facilitates the transference of these gases.

In conclusion, each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure and diffusion occurs until equilibrium is reached.

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The column count property can be used to create multiple columns of text within a single element.

The process of evaporation by which liquid water changes to vapor is shown by a chemical formulae as follows:

Three separation methods that can be used to reverse a physical change include:

Evaporation is the process by which liquids changes to vapor or gas spontaneously.

The rate of evaporation of a liquid increases with increase in temperature of the liquid. The rate of evaporation also increases with increase in surface area of the liquid exposed as well as with increase in wind speed.

The process by which liquid water changes to vapor can be represented by chemical formulae as follows:

H₂O (l) → H₂O (g)

In the equation above, the liquid phase of water, l, is undergoing change to gaseous phase, g.

b. Separation techniques are techniques which are used to separate mixtures of substances.

Three separation methods that can be used to reverse a physical change include:

In conclusion, physical changes are those changes that are easily reversible and which no new products are formed.

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The pH after 10. 0 ml of 0. 40 M NaOH is added to 20. 0 ml of 0. 50 M HCl is 13.3 .

Calculation ,

[ [tex]OH^{-}[/tex] ] = [tex]M_{1} V_{1} -M_{2} V_{2} /V_{1} +V_{2}[/tex]

where M is molarity and V is the volume .

[ [tex]OH^{-}[/tex] ] = 0. 50 M × 20. 0 ml - 0. 40 M × 10. 0 ml / 10. 0 ml +20. 0 ml

[ [tex]OH^{-}[/tex] ] = 6/30 = 0.2

pOH = -㏒[ [tex]OH^{-}[/tex] ]  =  -㏒ 0.2 = 0.7

pH = 14 - pOH =  14 - 0.7 = 13.3

Therefore , the pH after 10. 0 ml of 0. 40 M NaOH is added to 20. 0 ml of 0. 50 M HCl is 13.3 .

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Which atomic model that shows the atomic structure is missing from this set?

Dalton’s model

In 1898, J. J. Thomson proposed the first of many atomic models to come as he made the proposition that the shape of an atom was like a sphere.

This refers to the way and manner an atom is arranged and the things that are contained in it.

Hence, we can see that an atom contains:

Therefore, the atomic model that shows the atomic structure is missing from this set is Dalton's model.

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The complete question is:

The model of the atom has changed as scientists have gathered new evidence. Four models of the atom are shown below, but one important model is missing.

An image at left with overlapping red and blue balls in the center with a circular fuzzy green cloud outside them. An image at center left with a purple ball in the center surrounded by overlapping concentric black ovals, each with a small green ball on each of the 6 ovals. An image at center right with a large black cross in a purple circle with a black line around the purple, with 10 small green balls dispersed within the purple circle.

Which atomic model is missing from this set?

Bohr’s model

Dalton’s model

Rutherford’s model

Thomson’s model

Answer: B.  schrodingers model

Explanation:

correct on edge

Answer:

Explanation:

B

Three complete orders on each side of the m=0 order can be produced in addition to the m = 0 order.

The ruling separation is

d=1 / (470mm −1) = 2.1×10⁻³ mm

Diffraction lines occur at angles θ such that dsinθ=mλ, where λ is the wavelength and m is an integer.

Notice that for a given order, the line associated with a long wavelength is produced at a greater angle than the line associated with a shorter wavelength.

We take λ to be the longest wavelength in the visible spectrum (538nm) and find the greatest integer value of m such that θ is less than 90°.

That is, find the greatest integer value of m for which mλ<d.

since  d / λ = 538×10⁻⁹m / 2.1×10 −6 m ≈ 3

that value is m=3.

There are three complete orders on each side of the m=0 order.

The second and third orders overlap.

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the greatest amount of work is required if the process is adiabatic.The correct option is adiabatic.

The process in  which heat is constant is called adiabatic process.

The The process in  which temperature is constant is called isothermal process.

The process in  which pressure is constant is called isobaric process.

The P-V diagram for adiabatic , isothermal and isobaric process is given below.

Work done in process = area encloses by P-V diagram axis . Since area under the curve is maximum for adiabatic process which is shown in the above diagram. So, work done by the gas will be maximum for adiabatic process.

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