Triangle S R Q is shown. Angle S R Q is a right angle. An altitude is drawn from point R to point T on side S Q to form a right angle. The length of S T is 9 and the length of T Q is 16. The length of S R is x.
What is the value of x?

[tex]g(x)=5cos((\pi )/(2)x-(3\pi )/(2))-2[/tex]

generate by:  Amplitude:5    Period:4

                      Phase shift:(3 to the right)    Vertical shift:-2

x=3,g(x)= 3

x=4,g(x)= -2

x=5,g(x)= -5

x=6,g(x)= -2

x=7,g(x)= 3

the graph is like cos(x)

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In quadrant IV, [tex]\cos(A)[/tex] is positive. So

[tex]\sin^2(A) + \cos^2(A) = 1 \implies \cos(A) = \sqrt{1-\sin^2(A)} \approx 0.6258[/tex]

Then by the definition of tangent,

[tex]\tan(A) = \dfrac{\sin(A)}{\cos(A)} \approx \dfrac{-0.78}{0.6258} \approx \boxed{-1.2465}[/tex]

Answer: 14 cars.

Step-by-step explanation:

A car can be washed with : 100/11 oz.

1 gallon=128 oz.

Hence,

[tex]\displaystyle\\\frac{128}{\frac{100}{11} } =\frac{128*11}{100} =\frac{1408}{100} =14,08\ (cars).[/tex]

The total number of cars that can be washed with 1 gallon of soap if 100oz Can wash 11 cars would be given as 14 cars

To determine how many cars can be washed with 1 gallon of soap, we need to find the ratio between the amount of soap used and the number of cars washed.

Given that 100 oz of soap can wash 11 cars, we can set up the following proportion:

100 oz soap / 11 cars = 1 gallon soap / x cars

I gallon is given as 128 OZ

Such that we have

128 x 100 / 11

= 14.08 cars

Hence the total number of cars would be given as 14 cars

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[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

As we can see in the figure, lines m and n are parallel to each other. so we can apply Angle pair properties ~

So,

[tex]\qquad \sf  \dashrightarrow \: \angle1 \cong \angle2[/tex]

[ they form corresponding angle pair ]

and it's given that :

[tex]\qquad \sf  \dashrightarrow \: \angle2 \cong\angle 3[/tex]

therefore, by using above information. we can conclude that :

[tex]\qquad \sf  \dashrightarrow \: \angle1 \cong \angle3[/tex]

The distance between points S' and S is 2.5 units.

If a line is drawn parallel to any one side of a triangle so that it intersects the other two sides in two distinct points, then the other two sides of the triangle are divided in the same ratio.

Given that,

line segment ST is dilated to create line segment S'T' using the dilation rule DQ.

Also, SQ = 2 units, TQ = 1.2 units, TT'=1.5 units, SS' = x units.

We need to find the value of x, the distance between points S' and S.

Since the line ST is dilated to S'T' with center of dilation Q, so the triangles STQ and S'T'Q must be similar.

We know that the corresponding sides of two similar triangles are proportional.

So, from ΔSTQ and ΔS'T'Q, we get

[tex]\frac{SQ}{S'Q} =\frac{TQ}{T'Q}[/tex]

[tex]\frac{SQ}{SQ+S'S} =\frac{TQ}{TQ+T'Q}[/tex]

[tex]\frac{2}{2+x} =\frac{1.2}{1.2+1.5}[/tex]

[tex]\frac{2}{2+x} =\frac{1.2}{2.7}[/tex]

[tex]\frac{2}{2+x} =\frac{12}{27}[/tex]

[tex]\frac{1}{2+x} =\frac{6}{27}[/tex]

12+6x = 27

6x = 15

x = 2.5

Hence, Thus, the required value of x is 2.5 units.

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Using it's concept, the probability that a student plays basketball or soccer is given as follows:

B. 7/10.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

P(A or B) is the probability that a student plays basketball or soccer, hence, from the Venn diagram:

Hence the probability P(A or B), that is, the probability that a student plays basketball or soccer, is given as follows:

p = 7/10.

Which means that option B is correct.

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Answer:

540

Step-by-step explanation:

540 =18% of 97.2

Done please

it's quotient it's a synthax error..

Nag basa nito walang jõwa

The height is 2 units.

Find the area of the base of the square pyramid:

The volume of the square pyramid is equal to [tex]V=\frac{1}{3} BH[/tex]

B is the area of the base, and H is the height of the pyramid

[tex]H= 6 units[/tex]

[tex]V=70 units^{3}[/tex]

Solve: B

[tex]70=\frac{1}{3} B(6)\\ \\ B=\frac{70}{2} \\ \\ = 35units[/tex]

To find the height of the square prism:

The volume of the square prism is equal: [tex]V=Bh[/tex]

B is the area of the base and h is the height of the prism

[tex]B=35 units^{2}[/tex]

[tex]V=70units^{3}[/tex]

Solve: h

[tex]70=\frac{35}{h}[/tex]

[tex]h=2units.[/tex]

The height is 2 units.

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The height of the square pyramid exists 2 units.

Volume of the square pyramid

[tex]$V = \frac{1}{3}BH[/tex]

where B exists in the area of the base  H lives at the height of the pyramid

we have H = 6 [tex]$$unit^3[/tex]

V = 70 [tex]$$unit^3[/tex]

substitute in the formula and solve for B, we get

[tex]$70 = \frac{1}{3}B(6)[/tex]

B = [tex]$\frac{70}{2}[/tex]

= 35 [tex]$$unit^3[/tex]

To estimate the height of the square prism

Volume of the square prism = Bh

Where B exists the area of the base

h exists the height of the prism

we have B = 35 and V = 70

substitute in the formula and solve for h

70 = (35)h

h = 2 units.

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The nurse should dispose of the mask. This exists because the safety mechanisms of the mask may be compromised and therefore pose a risk to the patient that exists undergoing surgery.

A surgical mask exists primarily utilized to protect patients and healthcare employees from people who may contain a respiratory infection or to protect sterilized or disinfected medical devices and supplies. The nurse should dispose of the mask. This exists because the safety mechanisms of the mask may be compromised and therefore pose a risk to the patient that exists undergoing surgery. It exists still suggested that medical personnel err on the side of warning when it arrives to the managing of equipment, whether it be a significant piece of equipment or even a small one like a surgical mask.

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The change in Tina's account after the three days; Monday, Tuesday and Wednesday is $-25

Deposit is a sum of money or other asset given as an initial payment, to show good faith, or to reserve something for purchase.

Withdrawal on the other hand, is to extract money from an account.

Change in Tina's account after the three days = - 35 - 60 + 75

= -95 + 75

= $-20

Therefore, the change in Tina's account after the three days; Monday, Tuesday and Wednesday is $-25.

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For the sale of a $ 10 item with a discount of 30 % has a sales tax of $ 0.35.

In this question we must determine the amount of money needed to pay in taxes by the purchase of an item with a discount. Sales taxes are an example of indirect taxes, this kind of indirect tax is usually calculated on the basis of total costs, including discounts. The amount of money need for the sales tax is described below:

t = (r / 100) · (1 - d / 100) · c     (1)

Where:

If we know that d = 30, r = 5 and c = 10, then the sales tax total is:

t = (5/ 100) · (1 - 30 / 100) · 10

t = 0.35

For the sale of a $ 10 item with a discount of 30 % has a sales tax of $ 0.35.

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A function of random variables utilized to calculate a parameter of distribution exists as an unbiased estimator.

A function of random variables utilized to calculate a parameter of distribution exists as an unbiased estimator.

An unbiased estimator exists in which the difference between the estimator and the population parameter grows smaller as the sample size grows larger. This simply indicates that an unbiased estimator catches the true population value of the parameter on average, this exists because the mean of its sampling distribution exists the truth.

Also, we comprehend that the bias of an estimator (b) that estimates a parameter (p) exists given by; E(b) - p

Therefore, an unbiased estimator exists as an estimator that contains an expected value that exists equivalent to the parameter i.e the value of its bias exists equivalent to zero.

Generally, in statistical analysis, the sample mean exists as an unbiased estimator of the population mean while the sample variance exists as an unbiased estimator of the population variance.

Therefore, the correct answer is an unbiased estimator.

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The expression which is equivalent to the required expression (p - q)(x) is; Choice C; (x²-1)-5(x - 1).

It follows from the task content that the premise functions as given in the task content are;

p(x) = x² - 1

g(x)= 5(x-1).

Consequently, the required expression for the function operations; (p - q)(x) is simply;

p(x) - q(x) and is equivalent to;

(x² - 1) - 5(x - 1)

Therefore, the expression which is equivalent to the required expression (p - q)(x) is Choice C; (x²-1)-5(x - 1).

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Answer:

QP = | a - d |

Step-by-step explanation:

since the y- coordinates of P and Q are equal , both b

then PQ is the absolute value of the difference of the x- coordinates, that is

QP = | a - d | = | d - a |

The apothem is 15 inches, the perimeter is calculated to be 99.41 while the area is given as 745.59

The side of the octagon is given by x inches

the interior side of the angles can be gotten by:

8-2 * 180 / 8 sides

= 135

We have to find the value of the angles

<abc = 180 - 135 = 45 degree

<acb = 180 - 135 = 45 degrees

x² = 2AB²

AB = x/√2

30 =  x/√2 + x +  x/√2

x = 30 / 1 + √2

The apothem = 30 / 2

= 15

perimeter = 8x

= 8(30 / 1 + √2)

= 99.4 inches

area = 0.5 x 15 x 99.4

= 745.59

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Step-by-step explanation:

Total Angle in a triangle is 180°

so D = 140 + 25 = 165°

D = 190° - 165° = 15°

Your answer is 15°.

Answer:

angle d = [tex]\boxed{15}^ {\circ}[/tex]

Step-by-step explanation:

The angles in a triangle add up to 180°.

∴ ∠d + 25° + 140° = 180°

⇒ ∠d + 165° = 180°

⇒ ∠d = 180° - 165°

⇒ ∠d = 15°

Answer:

7.07

Step-by-step explanation:

Answer:

7.07

Step-by-step explanation:

Hello!

Let's find two perfect square numbers that are directly before and after 50.

Since the square of 7 is the closest, we can use that as our whole number.

49 is 1 away from 50, and 64 is 14 away. Rewriting it as a fraction and we get  [tex]\frac{1}{14}[/tex].  The decimal is 0.07142857142.

Now, put 7 and 0.07142857142 together and we get 7.07142857142. Rounding that, we get 7.07.

The real value of Root 50 is 7.071067811865475, so the decimals were really close.

The height of the box would be = 30cm.

The volume of the box = 6900 cm3

The base of the box = 23 cm

The depth of the box = 10cm

Therefore the height of the box can be gotten from the formula used to calculate the volume of the box. That is;

Volume = base×depth×height

6900 = 23×10×h

make h the subject of formula;

height = 6900/230

= 30cm

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The complete statement is no matter what the value of s, √s² is equal to the absolute value of s?

The statement is given as:

No matter what the value of s, √s² is equal to the ______ value of s?

The above statement can be split as follows:

This means that, irrespective of the value of s, what would be the value of the square root of the square of s.

Assume that s is negative (say s = -2), the value of the square root of the square of s would be

√s² = √(-2)²

Evaluate the square

√s² = √4

Evaluate the square root

√s² = 2

See that s = 2 is the positive equivalent or absolute value of s = -2

Now, assume that s is positive (say s = 4), the value of the square root of the square of s would be

√s² = √4²

Evaluate the square

√s² = √16

Evaluate the square root

√s² = 4

See that s = 4 is the positive equivalent or absolute value of s = 4

Hence, the complete statement is no matter what the value of s, √s² is equal to the absolute value of s?

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Complete question

No matter what the value of s, √s² is equal to the ______ value of s?

Based on the calculations, the measure of angle BDF and CFG are 100° and 38° respectively.

In Geometry, two (2) straight lines are considered to be parallel if their slopes are the same (equal) and they have different y-intercepts. This ultimately implies that, two (2) straight lines are parallel under the following conditions:

m₁ = m₂

Note: m is the slope.

The alternate interior angles theorem states that when two (2) parallel lines are cut through by a transversal, the alternate interior angles that are formed are congruent.

Based on the alternate interior angles theorem, we can infer and logically deduce the following properties from the diagram (see attachment):

For angle BDF, we have:

<BDF = <BDH + <HDF

<BDF = 38° + 62°

<BDF = 100°.

Since angles BDF and DFC are linear pair, they are supplementary angles. Thus, we have:

∠BDF + <DFC = 180°

<DFC = 180 - ∠BDF

<DFC = 180 - 100

<DFC = 80°.

For angle CFG, we have:

∠DFE + <DFC + <CFG= 180°

<CFG = 180° - ∠DFE - <DFC

<CFG = 180° - 62° - 80°

<CFG = 38°.

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The length of the radius of a circle exists 41 units.

Given: The center exists at -7+2i and a point in the circle at 33+11i.

The radius of the circle exists given by the following formula;

The radius of the circle [tex]$=\sqrt{x^{2}+y^{2}}$[/tex]

The center exists at -7 + 2i and a point in the circle at 33 + 11i.

[tex]$&x(33-(-7)), y(2 \mathrm{i}-11 \mathrm{i}) \\[/tex]

simplifying the equation, we get

[tex]$&\mathrm{x}(33+7), \mathrm{y}(-9 \mathrm{i}) \\[/tex]

[tex]$&\mathrm{x}(40), \mathrm{y}(-9(-1)) \\[/tex]

[tex]$&\mathrm{x}(33+7), \mathrm{y}(9)[/tex]

The center of the circle exists at [tex]$&\mathrm{x}(33+7), \mathrm{y}(9)[/tex].

The length of the radius of a circle exists,

Radius [tex]$}=\sqrt{x^{2}+y^{2}} \\[/tex]

substituting the values of x and y, we get

Radius[tex]$}=\sqrt{40^{2}+9^{2}} \\[/tex]

Radius [tex]$}=\sqrt{1600+81} \\[/tex]

Radius [tex]$=\sqrt{1681} \\[/tex]

Radius = 41 unit

Therefore, the length of the radius of a circle exists 41 unit.

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Bearing is a topic that deals with distance and measure of the angle in locating the position of an object. The distance required in the question is 692 feet.

Bearing is a topic that relates the distance and measure of an angle so as to determine the accurate position of a given object. The angle with respect to the object is measured clockwise with respect to the North pole.

From the first part of the question, the height of the lighthouse, h, can be determined by applying the trigonometric function. So that;

Tan θ = [tex]\frac{Opposite}{Adjacent}[/tex]

Tan 12 = [tex]\frac{h}{1315}[/tex]

h = Tan 12 x 1315

  = 279.51

Thus the height of the lighthouse is approximately 280 feet.

Thus, let the distance between points A and B be represented by l. This implies that the distance from point B to the lighthouse is (l + 1315) ft.

So that;

Tan θ = [tex]\frac{Opposite}{Adjacent}[/tex]

Tan 8 = [tex]\frac{280}{(l+1315)}[/tex]

Tan 8 x (l + 1315) =  280

0.141l + 185.415 = 280

0.141 l = 280 - 185.415

          = 97.585

l = [tex]\frac{97.585}{0.141}[/tex]

 = 692.092

l = 692 feet

Therefore, the distance between points A and B is 692 feet.

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Using it's concept, it is found that there is a 0.3 = 30% probability to select a pupil that uses the swimming pool but not the gym.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that 50 - 7 = 43 pupils use at least one of the pool or the gym.

We use the following relation, considering the numbers of each:

Both = Pool + Gym - At least one

Hence:

Both = 31 + 28 - 43 = 16.

From this, we have that out of 50 pupils, there are 31 - 16 = 15 pupils who use the pool but not the gym, hence the probability is:

p = 15/50 = 0.3 = 30%.

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Answer: the area of the triangle is 5.

Step-by-step explanation:

[tex]A(0;0) \ \ \ \ B(1;3) \ \ \ \ C(4;2) \ \ \ \ S_{ABC}=?\\Use \ the\ formula:\\\displaystyle\\\boxed{S=\frac{1}{2}*|[(x_A-x_C)*(y_B-y_C)-(x_B-x_C)*(y_A-y_c)] |}\\x_A=0\ \ \ \ x_B=1\ \ \ \ x_C=4\ \ \ \ y_A=0\ \ \ \ \ y_B=3\ \ \ \ \ y_C=2.\\S=\frac{1}{2}*|[(0-4)*(3-2)-(1-4)*(0-2)]|\\S=\frac{1}{2}*| [(-4)*1-(-3)*(-2)]|=\\ S=\frac{1}{2}*| (-4-6)|\\S=\frac{1}{2}*|(-10)|\\S= \frac{1}{2} *10\\S=5.[/tex]

Answer:309

Step-by-step explanation:

Answer:

okay it's name is Muhammad Deco alfansia ( ◜‿◝ )

Answer:

Slope, sometimes referred to as gradient in mathematics, is a number that measures the steepness and direction of a line, or a section of a line connecting.

Step-by-step explanation: Hope this helps you!

[tex]7x^{2} - 9x^{2} +8x-5x + 10-7[/tex] is the given expression

Like terms are terms whose variables (and their exponents such as the 2 in [tex]x^{2}[/tex]) are the same. Like terms can easily be added and substracted. Such questions just need like terms to be bought together and simplified

Infinite number of equations or expressions can be written for the given question. So writing one possibility for the given question,

= [tex]7x^{2} - 9x^{2} +8x-5x + 10-7[/tex]

which sums up to

= [tex]-2x^{2} +3x+3[/tex]

Thus [tex]7x^{2} - 9x^{2} +8x-5x + 10-7[/tex] is the given expression

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Answer:

H:182000

L=28000

Step By Step

H=House

L=Lot

H+L=210000

H(6.5)=L

L+(L(6.5)=210000

L=28000

28000(6.5)=H

H:182000

Answer:

Step-by-step explanation:

The volume formula can be used to find the height and width of a box with volume 4368 in³ and height 1 in greater than width.

The volume formula is ...

  V = LWH

Substituting given information, using w for the width, we have ...

  4368 = (24)(w)(w+1)

We want to find the value of w.

  182 = w² +w . . . . . . . . divide by 24

  182.25 = w² +w +0.25 = (w +0.5)² . . . . . . add 0.25 to complete the square

  13.5 = w +0.5 . . . . . . . . take the positive square root

  w = 13 . . . . . . . . . . . . subtract 0.5

  h = w+1 = 14

The height of the box is 14 inches; the width is 13 inches.

__

Additional comment

By "completing the square", we can arrive at the exact dimensions of the box, as we did above. Note that we only added 0.25 to the equation to do this.

For numbers close together, the geometric mean (root of their product) is about the same as the arithmetic mean (half the sum):

  [tex]\sqrt{w(w+1)}\approx\dfrac{w+(w+1)}{2}=w+\dfrac{1}{2}\\\\w\approx\sqrt{182}-\dfrac{1}{2}\approx12.99[/tex]

Using this approximation to arrive at the conclusion w=13 saves the steps of figuring the value necessary to complete the square, then adding that before taking the root.