The reaction equations for the steps involved in the decay of U-238 to Ra-226 are;
[tex]^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He[/tex]
[tex]^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He[/tex]
[tex]^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He[/tex]
What is the radioactive equation for the decay of U-238?The radioactive equation for the decay of U-238 to Ra-226 is calculated as follows;
First the uranium atom (U-238) will decay thorium by emitting alpha particle as shown in the equation below;
[tex]^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He[/tex]
The second stage is, the thorium will decay to radium by emitting alpha particles again as shown below;
[tex]^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He[/tex]
The third, and final stage, the radium will decay to an isotope of radium again, by emitting alpha particle as shown below;
[tex]^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He[/tex]
Thus, the reaction equations for the steps involved in the decay of U-238 to Ra-226 are;
[tex]^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He[/tex]
[tex]^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He[/tex]
[tex]^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He[/tex]
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Part C
Increase the value of the Applied Force to 150 N. Pause the simulation and observe the magnitudes and directions of the applied force, the friction
force, and the sum of forces. Why do you think the crate moves this time?
The crate moves this time because the applied force of 150 N is greater than the maximum static friction force that opposes the motion of the crate. Static friction is a force that opposes the relative motion between two objects in contact. The maximum static friction force is determined by the normal force and the coefficient of static friction between the two surfaces in contact. The harder the surfaces are pushed together, the more force is needed to move them. When the applied force exceeds the maximum static friction force, the crate will start to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force.
What is the reactive force when a fish swims through water
The reactive force when a fish swims through water is the force of the water on the fish. This is an example of Newton’s third law of motion which states that for every action, there is an equal and opposite reaction. The active force is the fish pushing against the water, so the reactive force would be the reverse, the equal force of the water pushing back on the fish.
How can graphs help demonstrate the qualitative relationship that may exist in a set of data to readers?
Graphs can help to demonstrate the qualitative relationship between a set of data by identifying patterns among these data.
What other information can the data show?Comparison between groups.Proportional relationships.Variation and dispersion.Graphs can allow readers to identify a lot of information among a set of data. The most common information to be evaluated through the graphs is the existence of patterns between the data.
For example, a line graph can show the change in a variable over time, allowing readers to see if there is a consistent increase or decrease.
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A boy slides a book across the floor, using a force of 5 N over a distance of 2
m. What is the kinetic energy of the book after he slides it? Assume there is
no friction.
A. 5 J
B. 10 J
C. 20 J
D. 2.5 J
SUBMIT
The kinetic energy of the book after it is slids a distance of 2 meters will be 10 Joules.
How to determine the kinetic energy of an object?The work-energy theorem states that "the work done on an object is the change in its kinetic energy".
Hence;
Kinetic energy = work done
Note that: work-done is expressed as:
Work done = f × d
Where f is force applied and d is distance traveled.
Given that:
Force applied f = 5 newton
Distance d = 2 meters
Work done = ?
Plug these values into the above formula and solve for the workdone.
Work done = f × d
Work done = 5N × 2m
Work done = 10Nm
Work done = 10 Joules
Therefore, the kinetic energy is 10 Joules.
Option B) 10 J is the correct answer.
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how many seconds makes 20 years (show all workings)
There are 630,720,000 seconds in 20 years.
To calculate the number of seconds in 20 years, we need to consider the number of seconds in a minute, minutes in an hour, hours in a day, and days in a year.
1 minute consists of 60 seconds.
1 hour contains 60 minutes (60 minutes × 60 seconds = 3600 seconds).
1 day consists of 24 hours (24 hours × 3600 seconds = 86,400 seconds).
1 year typically consists of 365 days (365 days × 86,400 seconds = 31,536,000 seconds).
To find the number of seconds in 20 years, we multiply the number of seconds in one year by 20:
20 years × 31,536,000 seconds = 630,720,000 seconds.
Therefore, there are 630,720,000 seconds in 20 years.
This calculation assumes a non-leap year with 365 days.
If the 20 years span a leap year, the total number of seconds would be slightly higher, accounting for the extra day in the leap year.
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