Three lorries each making five trips per day transport 2500 crates from a factory to a distributor in two days .how many lorries each making 6 trips a day are needed to transport 10000 such crates in a day

Answer: x =   -1

Step-by-step explanation:

To remove the radical on the left side of the equation, square both sides of the equation.

√1−3x2=(x+3)2

Simplify each side of the equation.

1−3x=x2+6x+9

Solve for x

x=−1−8

Exclude the solutions that do not make true

√1−3x=x+3

x=−1

The height of the taller building is 18.6 meters

A right triangle has one of its angles as 90 degrees. The side of a right angle triangle can be found using trigonometric ratios.

Therefore, the height of the taller building is the sum of the height of the smaller building and upper part of the taller building.

tan 53 = opposite / adjacent

tan 53 = x / 10

cross multiply

x = 10 tan 53

x = 10 × 1.32704482162

x = 13.2704482162

x = 13.3 m

tan 28 = y / 10

y = 10 tan 28

y = 5.31709431661

y = 5.3

Therefore, the height of the taller building is 13.3 + 5.3 = 18.6 meters.

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Answer:

y=(1/-4)(x+4)^2 +4

Step-by-step explanation:

Don't ask

The overall algebraic  expression will be:   [tex]\frac{5(x+11)}{3(x+8)}[/tex]

Definition of algebraic expression -

An expression obtained by a finite number of the fundamental operations of algebra upon symbols representing numbers.

Five times the sum of a number and eleven, divided by three times the sum of the number and eight.

Let the number be x.

Five times the sum of a number and eleven means 5 multiplied to the sum of x and 11. In expression this will be written as:

5(x + 11)

Three times the sum of the number and eight means 3 multiplied to the sum of x and 8. In expression this will be written as:

3(x + 8)

So, the overall algebraic expression will be:    [tex]\frac{5(x+11)}{3(x+8)}[/tex]

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Using the Fundamental Counting Theorem, it is found that there are 1024 ways of delivering the letters.

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

In this problem, each house has a correct letter, however the letter cannot be used for the house, hence the parameters are given as follows:

n1 = n2 = n3 = n4 = n5 = 5 - 1 = 4.

Thus the number of ways is:

N = 4 x 4 x 4 x 4 x 4 = 4^5 = 1024.

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720 cubic inches of soil will be in the flower box.

Cuboid Definition: Cuboid shaped objects surround us in our day-to-day life. From television sets, books, carton boxes to bricks, mattresses, and shoeboxes, cuboid objects are all around us. In Geometry, a cuboid is a three-dimensional figure with six rectangular faces, twelve edges, and eight vertices.

Volume of Cuboid = Length x Width x Height

∴ The volume of the soil box = 15 x 8 x 8 = 960 inch³

Since 3/4 is occupied by the soil, the volume of the soil becomes

= 3/4 x 960

= 720 inch³

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Answer: [tex]\Large\boxed{a_n=6n-4}[/tex]

Step-by-step explanation:

Given sequence

2, 8, 14, 20, 26

Determine the pattern

2 + 6 = 8

8 + 6 = 14

14 + 6 =20

20 + 6 = 26

For each term, add 6 to get the next term

Determine the type of sequence

Since it continuously adds 6, the common difference is 6, which means it is an arithmetic sequence

Given the arithmetic sequence formula

aₙ = a₁ + d (n - 1)

Substitute values into the formula

aₙ = (2) + (6) (n - 1)

aₙ = 2 + 6 (n - 1)

aₙ = 2 + 6n - 6

aₙ = 2 - 6 + 6n

[tex]\Large\boxed{a_n=6n-4}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Given sequence :-

Solution :-

We need to calculate the nth term of the given sequence.

We know that,

Applying the values here.

>> tn = 2 + (n - 1) 6

>> tn = 2 + (n - 1) × 6

>> tn = 2 + 6n - 6

>> tn = 6n - 4

Therefore, nth term of the sequence is (6n - 4).

3 /10 foot³ packing material is required to fill the box.

What is meant by volume of prism?

Volume =  base area × height

             = 9/10 × 1/3

             =  3 /10  foot³

Therefore, 3/10  foot³ packing material is required to fill the box.

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The complete question is-

An empty box is shaped like a rectangular prism. The box has a base area of 9/10 square foot and a height of 1/3 foot. How much packing material is required to fill the box?

Answer: Midpoint=(−6 ,3.5)

Step-by-step explanation:

=(1+22,1+22)M=(x1+x22,y1+y22)=(−1+−112,−3+102)M=(−1+−112,−3+102)=(−122,72)M=(−122,72)=(−6,312)

Answer:

(-6,3.5)

Step-by-step explanation:

x = [tex]\frac{-1-11}{2}[/tex] = [tex]\frac{-12}{2}[/tex] = -6

y = [tex]\frac{-3+10}{2}[/tex] = [tex]\frac{7}{2}[/tex] = 3.5

Answer:

300

Step-by-step explanation:

375 divided by 5=75

Each “1”=75

4x75=300

There are 300 boys.

Hope this makes sense

Answer:

300 boys

Step-by-step explanation:

Let the number of boys = x

Girls: 375

boys : girls = 4 : 5

total in the ratio is 9

girls are 5/9 of total, and are 375

boys are 4/9 of total

5/9 x = 375

x = 375 × 9/5

x = 675

Boys are 4/9 of total.

4/9 × 675 = 300

Answer:

615.7536

Step-by-step explanation:

Remember the equation for finding the area of a circle is:

A=π[tex]r^2[/tex]

Just substitute in your radius for r and solve:

A=3.1416*[tex]14^2[/tex]

A=3.1416*196

A=615.7536

Answer:

Okay, so:

sinA = 22.5/25.5

<A = 62* (correct)

cos C = 22.5/25.5 (correct)

tanA = 22.5/12.0 = 1.875 (correct)

sinC = 12.0/25.5

tan C = 12.0/22.5 = 0.53 (correct)

Step-by-step explanation:

I'll explain the wrong ones in the comments hold on-

If a photo below is being enlarged you a 24 negative by 30 inches current. The scale factor being used to enlarge it is: 6.

Given:

Enlarged size=24 negative by 30 inches

Original size=4 in, 5 in

Using this formula

Let k represent the (ratio) scale factor being used to enlarge it

Scale factor/Enlarged size/Original size

Let plug in the formula

K=24/4

K=6

K=30/5

K=6

Therefore if a photo below is being enlarged you a 24 negative by 30 inches current. The scale factor being used to enlarge it is: 6.

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Answer: Anna got 30

Step-by-step explanation: 2x+3y=25

15+10=25

[tex](-7+9, 1-3)=\boxed{(2, -2)}[/tex]

The answer is (2,-2).

Find the image of the given point under the given translation:

The rule of translation is (x+9, y - 3), P (-7, 1).

Here we need to add 9 from

x value is -7+9=2

y We need to subtract -3 from

y value is (1-3)=-2

So, P’=( 2,-2)

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The identity for addition for rational numbers is zero which is the option b.

Given addition of rational numbers.

We are required to find the identity for the addition of rational numbers.

Rational numbers are those numbers which can be written in the form of p/q and q cannot be equal to zero because if q is equal to zero the whole fraction will become infinity. The numbers whih cannot be written as p/q are known as irrational numbers.

From the all option zero is the identity for addition for rational numbers. This  means if a is a rational number. Then a+0=0+a=a.

Hence the identity for addition for rational numbers is zero which is the option b.

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The statement that the equation has no solutions because the constant is the same is true

The equation is given as:

3x - 8 = 7x- 8

Add 8 to both sides

3x - 8 + 8= 7x-  8 + 8

Evaluate the like terms

3x = 7x

Divide both sides by x

3 = 7

The above equation is false, because 3 and 7 are not equal

This means that the statement that the equation has no solutions because the constant is the same is true

Hence, I agree with Kiran

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Each element in the range of g(x) is 3 less than the corresponding element in the range of f(x).

Answer:

See below.

In short, by having vertical shift will affect range from -1 ≤ y ≤ 1 to -1 + a ≤ y ≤ 1 + a

Step-by-step explanation:

Generally, a cosine function without vertical shift will always have range equal to -1 ≤ y ≤ 1

If there is given vertical shift, our range will change to -1 + a ≤ y ≤ 1 + a

An example is if we are given the function of cos(x), this always has range of -1 ≤ y ≤ 1 because there is no vertical shift.

But if we have cos(x) + 1, we have vertical shift which is 1. Then the range will be -1+1 ≤ y ≤ 1+1 which equals to 0 ≤ y ≤ 2.

Hence, the function of -5cos(2x) has only range of -1 ≤ y ≤ 1 but the function of -5cos(2x) - 3 will have range of -1-3 ≤ y ≤ 1-3 which equals to -4 ≤ y ≤ -2

The value of x is 11 1/2 OR 11.5

From the question, we are to determine the value of x

In the given diagram, we have two isosceles triangles

Since base angles of isosceles triangles are equal,

Then, each of the base angles of the isosceles triangle is 68°

Then, we can write that

m ∠2 + 68° + 68° = 180° (Sum of angles in a triangle)

From the given information,

m ∠2 = 4x - 2

Then,

4x -2 + 68° + 68° = 180°

4x = 180 - 68 - 68 +2

4x = 46

x = 46/4

x = 11 1/2 OR 11.5

Hence, the value of x is 11 1/2 OR 11.5

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m1 x m2 = - 1

Rearrange 4x + 2y = 8.

4x + 2y = 8

-4x, then ÷ 2

y = - 4x + 8 / 2

y = - 2x + 4

m1 = - 2, find reciprocal of - 2, by placing 1 over the 2

So, - 2 will become - 1/2, but multiplying this gives us a positive 1. Thus, m2 = 1/2

m1 x m2 = - 1

-2 x 1/2 = - 1

That means slope perpendicular to the line

4x + 2y = 8 is y = 1/2x, where a half is the gradient/slope.

Ans: 1/2

Hope this helps!

The answer is y = -5.5x - 52.

First, let's find the slope of the line.

m = Δy/Δx

Now, substitute the slope and one of the given points in the point slope equation.

y - y₁ = m (x - x₁)

Answer: y=-5,5x-52.

Step-by-step explanation:

                        Equation of a straight line

                               [tex]\displaystyle\\\boxed {\frac{x-x_1}{x_2-x_1}=\frac{y-y_1}{y_2-y_1} }[/tex]

[tex](-10;3)\ \ \ \ \ (-8;-8).\\\displaystyle\frac{x-(-10)}{-8-(-10)} =\frac{y-3}{-8-3}\\ \frac{x+10}{-8+10}=\frac{y-3}{-11} \\ \frac{x+10}{2}=\frac{y-3}{-11} \\-11*(x+10)=2*(y-3)\\-11x-110=2y-6\\2y=-11x-104\ |:2\\y=-5,5x-52.[/tex]

Answer:

8

Step-by-step explanation:

I belive what they mean is how many dots thier are i am not complety sure though but just by counting them up i came up with 8.

hope this helped

Answer:

m∠DBC = 51°

Step-by-step explanation:

Circle Theorem vocabulary

Inscribed Angle Theorem

The measure of an inscribed angle is half the measure of the intercepted arc.

Therefore:

[tex]\sf \implies \angle DBC=\dfrac{1}{2}\:\overset{\frown}{BC}[/tex]

[tex]\sf \implies \angle DBC=\dfrac{1}{2}\:(102^{\circ})[/tex]

[tex]\sf \implies \angle DBC=51^{\circ}[/tex]

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[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]

To determine ∠DBC, we will apply the theorem relating the inscribed angle to the intercepted arc:

[tex]\longrightarrow \sf{Intercepted \: arc= (inscribe \: angle)}[/tex]

[tex]\longrightarrow \sf{Intercept \: arc= 102^\circ}[/tex]

[tex]\longrightarrow \sf{Inscribed \: angle= \angle DBC }[/tex]

[tex]\longrightarrow \sf{102=2( \angle DBC)}[/tex]

[tex]\longrightarrow \sf{\angle DBC= \dfrac{102}{2} }[/tex]

▪ [tex]\longrightarrow \sf{\angle DBC = 51^\circ}[/tex]

[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]

[tex]\boxed{\bf{\large m \: \angle DBC= 51^\circ}}[/tex]

Answer:

[tex]4\ln \left| \dfrac{1}{3}\sqrt{9+(\ln x)^2} + \dfrac{1}{3}\ln x \right|+\text{C}[/tex]

Step-by-step explanation:

Fundamental Theorem of Calculus

[tex]\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))[/tex]

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

[tex]\displaystyle \int \dfrac{4}{x\sqrt{9+(\ln(x))^2}}\:\:\text{d}x[/tex]

Rewrite 9 as 3²:

[tex]\implies \displaystyle \int \dfrac{4}{x\sqrt{3^2+(\ln(x))^2}}\:\:\text{d}x[/tex]

Integration by substitution

[tex]\boxed{\textsf{For }\sqrt{a^2+x^2} \textsf{ use the substitution }x=a \tan\theta}[/tex]

[tex]\textsf{Let } \ln x=3 \tan \theta[/tex]

[tex]\begin{aligned}\implies \sqrt{3^2+(\ln x)^2} & =\sqrt{3^2+(3 \tan\theta)^2}\\ & = \sqrt{9+9\tan^2 \theta}\\ & = \sqrt{9(1+\tan^2 \theta)}\\ & = \sqrt{9\sec^2 \theta}\\ & = 3 \sec\theta\end{aligned}[/tex]

Find the derivative of ln x and rewrite it so that dx is on its own:

[tex]\implies \ln x=3 \tan \theta[/tex]

[tex]\implies \dfrac{1}{x}\dfrac{\text{d}x}{\text{d}\theta}=3 \sec^2\theta[/tex]

[tex]\implies \text{d}x=3x \sec^2\theta\:\:\text{d}\theta[/tex]

Substitute everything into the original integral:

[tex]\begin{aligned} \implies \displaystyle \int \dfrac{4}{x\sqrt{9+(\ln(x))^2}}\:\:\text{d}x & = \int \dfrac{4}{3x \sec \theta} \cdot 3x \sec^2\theta\:\:\text{d}\theta\\\\ & = \int 4 \sec \theta \:\: \text{d}\theta\end{aligned}[/tex]

Take out the constant:

[tex]\implies \displaystyle 4 \int \sec \theta\:\:\text{d}\theta[/tex]

[tex]\boxed{\begin{minipage}{7 cm}\underline{Integrating $\sec kx$}\\\\$\displaystyle \int \sec kx\:\text{d}x=\dfrac{1}{k} \ln \left| \sec kx + \tan kx \right|\:\:(+\text{C})$\end{minipage}}[/tex]

[tex]\implies 4\ln \left| \sec \theta + \tan \theta \right|+\text{C}[/tex]

[tex]\textsf{Substitute back in } \tan\theta=\dfrac{1}{3}\ln x :[/tex]

[tex]\implies 4\ln \left| \sec \theta + \dfrac{1}{3}\ln x \right|+\text{C}[/tex]

[tex]\textsf{Substitute back in } \sec\theta=\dfrac{1}{3}\sqrt{9+(\ln x)^2}:[/tex]

[tex]\implies 4\ln \left| \dfrac{1}{3}\sqrt{9+(\ln x)^2} + \dfrac{1}{3}\ln x \right|+\text{C}[/tex]

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Answer: 80% of the 10 people saw the show.

Step-by-step explanation:

8/10 = 0.8, which is 80%.

I hope this helped!

The value of dividing x^2-3x+9 by x-2 is x + 3

There are several ways to divide polynomial functions; some of these ways include

The expression for the polynomial division is given as:

x^2-3x+9/x-2

To divide polynomial functions, we make use of the division by factorization method

Start by expanding the numerator of the polynomial division

x^2-3x+9/x-2 = x^2 + 3x - 6x + 9/x-2

Factorize the equation

x^2-3x+9/x-2 = x(x + 3) - 2(x + 3)/x - 2

Factor out x + 3 from the numerator

x^2-3x+9/x-2 = (x- 2)(x + 3)/x - 2

Cancel out the common factors

x^2-3x+9/x-2 = x + 3

Hence, the value of dividing x^2-3x+9 by x-2 is x + 3

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Answer:

See image

Step-by-step explanation:

Using a graphing calculator, first press the Y= button at the top left.

Then enter the equation given in the question.

Next, press 2nd then graph, and you will get the table. Put in whatever values for x to get y.

So your answer is 48, 18, 0, -6, 0, -18, 0, 48

The surface integral of the given surface [tex]z=\frac{2}{3}(x^\frac{3}{2}+y^\frac{3}{2})[/tex] in the intervals 0 ≤ x ≤ 4, 0 ≤ y ≤ 1 is 7.36615.

To evaluate the surface integral, the formula applied is

[tex]S=\int\limits^b_a\int\limits^d_c {f(x,y)} \ dy\ dx[/tex]

⇒ S = [tex]\int\limits^b_a \int\limits^d_c {\sqrt{1+(\frac{dz}{dx})^2+(\frac{dz}{dy})^2 } } \, dy \, dx[/tex]

Where the differentiation is partial differentiation and f(x, y) = z.

The given function is

f(x, y) = [tex]z=\frac{2}{3}(x^\frac{3}{2}+y^\frac{3}{2})[/tex]

Then, applying the partial differentiation w.r.t x and y respectively,

dz/dx = [tex]\frac{2}{3}(\frac{3}{2})x^{1/2}[/tex] = [tex]x^{1/2}[/tex]

dz/dy = [tex]\frac{2}{3}(\frac{3}{2})y^{1/2}[/tex] = [tex]y^{1/2}[/tex]

Then,

we have surface integral  formula as

S = [tex]\int\limits^b_a \int\limits^d_c {\sqrt{1+(\frac{dz}{dx})^2+(\frac{dz}{dy})^2 } } \, dy \, dx[/tex]

On substituting,

⇒ S = [tex]\int\limits^4_0 {\int\limits^1_0 {\sqrt{1+(x^{1/2})^2+(y^{1/2})^2} \, dy } \, dx[/tex]

⇒ S = [tex]\int\limits^4_0 {\int\limits^1_0 {\sqrt{1+x+y} \, dy } \, dx[/tex]

On integrating w.r.t y

⇒ S = [tex]\int\limits^4_0 {\frac{2}{3}(1+x+y)^{3/2}} \,|_0^1 dx[/tex]

Applying limits,

⇒ S = [tex]\int\limits^4_0 {\frac{2}{3}[(1+x+1)^{3/2}-(1+x+0)^{3/2} } \, dx[/tex]

⇒ S = [tex]\frac{2}{3} \int\limits^4_0 {[(x+2)^{3/2}-(x+1)^{3/2}}] \, dx[/tex]

Again applying the integration w.r.t x

⇒ S = [tex]\frac{2}{3}[\frac{2}{5}(x+2)^{5/2}-\frac{2}{5}(x+1)^{5/2}]|_0^4[/tex]

Applying the limits and simplifying,

⇒ S = [tex]\frac{4}{15}[(4+2)^{5/2}-(4+1)^{5/2}-(0+2)^{5/2}+(0+1)^{5/2}][/tex]

⇒ S = [tex]\frac{4}{15}[1+36\sqrt{6}-25\sqrt{5}-4\sqrt{2}][/tex]

∴ S = 7.36615

Therefore, the surface integral of the given function is 7.36615.

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