The wall, shown above in Figure 105.1401, has an overall length that is 37’ and 8 1/4" . Three receptacle outlets are to be installed in this wall. L2 is twice as long as L1 . L1 should be _____' _____''.

The value of tan 0 as given in question is 0

Trigonometric identities are equations involving the trigonometric functions that are true for every value of the variables involved. They are written in terms of sine, cosine and tangent.

According to the question, we are to find the value of tan0. This is as shown below;

tan 0 = 0

Note that the tangent angle is positive in the first and third quadrant. Hence the result of the given tangent expression will also be positive.

Hence the value of tan 0 as given in question is 0

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Using proportions, it is found that due to the smaller division of the exchange rate by the cost, the souvenir would be less expensive in Egypt.

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

The souvenir would be less expensive in the country in which the division of the exchange rate by the cost is smaller.

In Britain, the cost is of 17, with an exchange rate of 0.83, hence the cost in US dollars is:

c = 17/0.83 = $20.48.

In Egypt, the cost is of 288, with an exchange rate of 18, hence the cost in US dollars is:

c = 288/18 = $16.

16 < 20.48, hence the souvenir would be less expensive in Egypt.

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Answer:

c

Step-by-step explanation:

consider points (0,2) and (-4,0)

slope=(0-2)/(-4-0)=-2/-4=1/2

y-intercept=2

y=mx+c

y=1/2 x+2

Answer:

y=1/2x+2

Step-by-step explanation:

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

Transverse axis

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

Where

a = 3 and b = 6

The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

y = ±6/3x

Evaluate the quotient

y = ±2x

This means that the transverse axes are y = 2x and y =-2x

The vertices

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

The co-vertices

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

And

a = 3 and b = 6

The co-vertices are

(h - a, k) and (h + a, k)

So, we have:

(0 - 3, 0) and (0 + 3, 0)

Evaluate

(-3,0) and (3, 0)

See attachment for the graph of the hyperbola

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Answer:

76 sodas

Step-by-step explanation:

152 divided by 2

Answer: 76 sodas

Step-by-step explanation:

To find the sodas, use the data you see. Bottles of water are twice the sodas. So divided water by 2 to get the sodas.
152 ÷ 2 = 76 ( sodas ) . Hope it helps !

a. Central angle in the circle is: Angle BAC

b. A major arc is: Arc BEC

c. A minor arc is: Arc BC

d. measure of arc BEC is: 260°

e. m(BC) = 100°

A central angle has two of its sides as radii of the circle, forming an angle at the center of the circle, where the vertex is at the center of the circle.

A major arc has a measure that is greater than 180 degrees. That is, it is more than half a circle (semicircle). Thus, measure of major arc > 180 degrees.

A minor arc has a measure that is less than 180 degrees. That is, it is not more than half a circle (semicircle). Thus, measure of minor arc < 180 degrees.

a. Central angle in the circle is: Angle BAC

b. A major arc in circle A is: Arc BEC

c. A major arc in circle A is: Arc BC.

d. Measure of arc BEC = 360 - 100 [according to the central angle theorem]

Measure of arc BEC = 260°.

e. Measure of angle BAC = 100°  [given]

Measure of arc BC = angle BAC [according to the central angle theorem]

Measure of arc BC = 100°

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Answer:

[1 , +∞)

Step-by-step explanation:

Solving the inequality 6x ≥ 6

6x ≥ 6

⇔ x ≥ 1   (Divide both sides by 6)

⇔ x ∈ [1 , +∞)

Answer:

The fraction of his farm which isn’t ruined is 11/18

Fractions are written as a ratio of two integers. The given question will be solved using the method of proportion.

If Uncle Bill has planted fruits in the farm and 7/12 is watermelon, and 2/3 of the watermelon section is ruined from the storm, the fraction ruined from the storm is;

Fraction ruined from the storm = 2/3* (7/12)

Simplify to its lowest term to have:

Fraction ruined from the storm = 7/18

Determine the fraction of the firm that is not ruined

Fraction not ruined = 1 - 7/18

Fraction not ruined = 11/18

Hence the fraction of his farm which isn’t ruined is 11/18 if uncle Bill has planted fruits in the farm and 7/12 is watermelon.

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Answer:

2 1/8

Step-by-step explanation:

I counted from 29 to 31 and then saw that for 29 it was 3/8 and for 31 it was 2/8 so i knew that the answer would be 2 1/8

Answer: 5/11

Solution: x = 5/11

Step-by-step explanation:

Question: -(x+3)=-8+10x

Result -x-3=10x-8

Hope this help :)

Please give brainless

-(×+3)=-8+10× is a math equation with the solution of 5/11

Answer:

angle G

Step-by-step explanation:

the quadrilateral did not change position or ration, it only shrank, so all the angles are in the same place and angle C = angle G

Answer:

2

Step-by-step explanation:

Answer:

five-hundredths

Step-by-step explanation:

The graphs of the equations are:

In fig. 1:

a) y = x (red line)

b) y = -x (blue line)

c) y = x + 5 (green line)

In Fig. 2:

a. y = 3x + 2 (red line)

b. y = 3x - 2 (blue line)

A linear equation can be expressed in slope-intercept form as, y = mx + b, where m is the slope of the line and b is the y-intercept where the line cuts across the vertical axis (y-axis).

Given the equations:

a) y = x, the slope is 1, while the y-intercept is 0. This means the line of the graph passes through the point of origin (0, 0). (It is the red line on the graph plotted).

b) y= -x, the slope is -1 (declining slope), while the y-intercept is 0. This means the line of the graph passes through the point of origin (0, 0). (It is the blue line on the graph plotted).

c) y = x + 5, the slope is 1 (rising slope), while the y-intercept is 5. This means the line of the graph passes the y-axis at 5. (It is the green line on the graph plotted).

In Figure 2, we have the second graph with the following equations:

a. y = 3x + 2, the slope is 3 (rising slope), while the y-intercept is 2. This means the line of the graph passes the y-axis at 2. (It is the red line on the graph plotted).

b. y = 3x - 2, the slope is 3 (rising slope), while the y-intercept is -2. This means the line of the graph passes the y-axis at -2. (It is the blue line on the graph plotted).

In summary, the graphs of the equations are:

In fig. 1:

a) y = x (red line)

b) y = -x (blue line)

c) y = x + 5 (green line)

In Fig. 2:

a. y = 3x + 2 (red line)

b. y = 3x - 2 (blue line)

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Answer:

7.88 x 10^5 is 788,000 is scientific notation

The inequality that compares the number of videos Sarita uploaded, v, to the number of videos Tyson uploaded is v - 500 < y

Inequality for number of videos Sarita uploaded:

v - 500 < y

Therefore, the inequality that compares the number of videos Sarita uploaded, v, to the number of videos Tyson uploaded is v - 500 < y

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Answer:

- v < 500

Step-by-step explanation:

The major requirements for a group of individuals and organisations to be a market as evident from the definition big a market is that; there must be an exchange of goods or services in which case, there are sellers and buyers.

The occurrence of the exchange of goods and services represents the qualifying requirement for a market.

The distinctive property between a consumer market and a business-to-business market is the that former, involves the end user of the good or service while the latter involves the use of the good or service exchanged to facilitate the production of other goods.

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The points would be matched with their polar coordinates as follows:

A polar coordinate can be defined as a two-dimensional coordinate system, wherein each point on a plane is typically determined by a distance (r) from the pole (origin) and an angle (θ) from a reference direction (polar axis).

In geometry, the relationship between a polar coordinate (r, θ) and a rectangular coordinate (x, y) based on the conversion rules is given by the following polar functions:

a = rcos(θ)    ....equation 1.

b = rsin(θ)     ....equation 2.

Where:

In Mathematics, a negative vector for a given vector has the same magnitude but acts in an opposite direction while an antiparallel vector for a given vector refers to any vector that acts in an opposite direction.

This ultimately implies that, a negative vector equals to an antiparallel vector, but an antiparallel vector isn't always a negative vector.

In this context, we can infer and logically deduce that the points would be matched with their polar coordinates as follows:

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Answer:

84

Step-by-step explanation:

Since we are given line OP perpendicular to line DR, then angles PDR and ODR are right angles.

Angles PDA and ADR are complementary.

Angles ODU and UDR are complementary.

Angles ADR and UDR are given as congruent.

We can conclude that angles PDA and ODU are congruent.

By AA Similarity, triangles APD and UMD are similar.

DP/DM = PA/MU

3.75/10 = 4.5/MU

3.75MU = 10 × 4.5

MU = 12 (altitude of triangle DUO)

OD = OM + MD =  4 + 10 = 14 (base of triangle DUO)

area = base × height / 2

area = 14 × 12 / 2

area = 84

Answer:

84

Step-by-step explanation:

correct me if im wrong

Answer:

no habla espanol

Step-by-step explanation:

Answer:

[tex]\left(a-b\right)\sqrt{\frac{2}{a^2-b^2}}[/tex]

=

[tex]\frac{ \sqrt{2} }{a + b} [/tex]

Step-by-step explanation:

[tex]\left(a-b\right)\sqrt{\frac{2}{a^2-b^2}}[/tex]

[tex](a - b)( \frac{ {2}^{ \frac{1}{2} } }{(a + b)(a - b)} )[/tex]

[tex] \frac{(a - b)( {2}^{ \frac{1}{2} }) }{(a - b)(a + b)} = \frac{ \sqrt{2} }{a + b} [/tex]

By the definition and properties of absolute value, there are two possible resulting functions: (i) g(x) = 5 · |x|, (ii) g(x) = |5 · x|. (Correct choices: B, D)

Herein we must modify a parent function to get a resulting function by the use of rigid transformations, defined as those transformations applied on geometric loci, including functions, such that Euclidean distance is conserved.

Based on the statement seen in the picture, the enlargement of the parent function can be done by a rigid transformation known as dilation, whose definition is shown below:

g(x) = k · f(x), where k is the stretch factor and is greater than 1.     (1)

If we know that f(x) = |x| and k = 5, then the resulting function is:

g(x) = 5 · |x|     (1)

This expression is also equivalent to the expression g(x) = |5 · x| by definition of absolute value.

By the definition and properties of absolute value, there are two possible resulting functions: (i) g(x) = 5 · |x|, (ii) g(x) = |5 · x|. (Correct choices: B, D)

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Answer:

69500

Step-by-step explanation:

695 x 100 = 69500

to check answer divided 69500 by 100

which is equals to 695

695 is a hundred times smaller than 69500

multiplication is a method of finding the product of two or more numbers.

We need to find the number which 695 is a hundred times smaller than

Six hundred ninety five times smaller than

Let us consider the number to be x.

Let us multiply 695 with 100 to  get the value or answer of the above question.

Six hundred ninety five into hundred is sixty nine thousand five hundred

695 x 100 = 69500

To verify the answer is correct or not , divide 69500 by 100. if we get 695 out answer is correct

69500/100=695

Hence 695 is a hundred times smaller than 69500

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The cosine equation of the attached graph is; y = 5 cos [( π/40)(x - (π/2))] + 3

The given parameters are:

Diameter = 10 m

Thus;

Radius; r = 5 m

Time; t = 80 s

Height above the ground, h = 2 m

The above means that:

Amplitude; A = 5 m

Period, T = 80 s

Minimum = 2 m

The cosine function is represented as:

y = a cos [k(x - d)] + c.

where;

A is amplitude

B is cycles from 0 to 2π

period = 2π/k

d is horizontal shift

c is vertical shift (displacement)

Thus;

2π/k = 80

k = 2π/80 = π/40

Where

c = Amplitude - Minimum

c = 5 - 2

c = 3

Shift to the left by π/2 gives;

d = π/2

Thus, the equation of the cosine graph is;

y = 5 cos [( π/40)(x - (π/2))] + 3

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Answer: Same

Step-by-step explanation:

Given formula

[tex]Percent~of~change~=~\Large\frac{New~-~Original}{Original}*100\%[/tex]

Given information

Troop A:

Troop B:

Substitute values into the formula (Troop A)

[tex]Percent~of~change~=~\Large\frac{New~-~Original}{Original}*100\%[/tex]

[tex]Percent~of~change~=~\Large\frac{(16)~-~(14)}{(14)}*100\%[/tex]

Simplify the fraction

[tex]Percent~of~change~=~\Large\frac{2}{14}*100\%[/tex]

[tex]Percent~of~change~=~\Large\frac{1}{7}*100\%[/tex]

[tex]Percent~of~change~\approx~14.29\%[/tex]

Substitute values into the formula (Troop B)

[tex]Percent~of~change~=~\Large\frac{New~-~Original}{Original}*100\%[/tex]

[tex]Percent~of~change~=~\Large\frac{(24)~-~(21)}{(21)}*100\%[/tex]

Simplify the fraction

[tex]Percent~of~change~=~\Large\frac{3}{21}*100\%[/tex]

[tex]Percent~of~change~=~\Large\frac{1}{7}*100\%[/tex]

[tex]Percent~of~change~\approx~14.29\%[/tex]

Compare the two percent of change

[tex]Troop~A~v.s.~Troop~B[/tex]

[tex]14.29\%~=~14.29\%[/tex]

Therefore, they are [tex]\Large\boxed{Same}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

The answer is same.

Finding the percentage of change for Troop A :

New - Original / Original × 100%

Finding the percentage of change for Troop B :

Both the troops have the same percent change in membership.

Answer:

True

Step-by-step explanation:

Plotting the point of any linear equation on a graph gives a straight line

Answer:

[tex]\sqrt[3]{192} x^{\frac{3}{5} }y^{\frac{3}{8} }[/tex]

Step-by-step explanation:

You have to simplify all of the terms individually

[tex]\sqrt[3]{192} = 5.769[/tex]

Since that isn't a whole number, it doesn't simplify

Use the root to exponent rule for the variables

[tex]\sqrt[3]{x^{5} } =x^{\frac{3}{5} }[/tex]

[tex]\sqrt[3]{y^{8} } =y^{\frac{3}{8} }[/tex]

Then put them all together to get

[tex]\sqrt[3]{192} x^{\frac{3}{5} }y^{\frac{3}{8} }[/tex]

Make sure the variables aren't under the root when you give your answer

I hope this helps!

pls mark brainliest