The rate of inflation in the fictional land of sardonia is such that the price of a car costing 24000 dollars in u.s. currency will double in eleven years. what is the annual rate of inflation? what will be the price of this car in five years?

Answer: [tex]x=-5, -3[/tex]

Step-by-step explanation:

[tex]x^2 +8x+15=0\\\\(x+5)(x+3)=0\\\\x=-5, -3[/tex]

The cost of new product on the website is $309.375.

Given that, the cost of product = $412.50 and discount percentage = 25%.

A discount is the reduction of either the monetary amount or a percentage of the normal selling price of a product or service.

Discount = 25% of 412.50

= 25/100 × 412.50

= 0.25 × 412.50

= 103.125

So, cost = 412.50-103.125

= $309.375

Therefore, the cost of new product on the website is $309.375.

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Answer:

B

Step-by-step explanation:

- 6x + 3 ≥ 21 ( subtract 3 from both sides )

- 6x ≥ 18

divide both sides by - 6, reversing the symbol as a result of dividing by a negative quantity.

x ≤ - 3

Solution of integral  [tex]\int \frac{ds}{s^{2}(s-1)^{2} }[/tex] is  [tex]2ln|\frac{s}{s-1}|-\frac{1}{s}-\frac{1}{s-1}+c[/tex].

We have to evaluate [tex]\int \frac{ds}{s^{2}(s-1)^{2} }[/tex]

By using partial fractions, evaluate the integral

Let [tex]\frac{1}{s^{2}(s-1)^{2} } =\frac{A}{s} +\frac{B}{s^{2}} +\frac{c}{s-1} +\frac{D}{(s-1)^{2} }[/tex]

[tex]1=As(s-1)^{2} +B(s-1)^{2} +Cs^{2}(s-1)+Ds^{2}[/tex]

Put s = 0, 1 = B.1 ⇒ B = 1

Put s= 1, 1 = D ⇒ D = 1

Put s = -1, [tex]1=A(-1)(-2)^{2} +B(-2)^{2} +C(-1)^{2} (-2)+D(-1)^{2}[/tex]

1 = -4A + 4B -2C + D

1 = -4A + 4 -2C + 1

-4 = -4A -2C

2 = 2A + C----------------(1)

Put s = 2, 1 = A(2) + B +C(4) +D(4)

1 = 2A + 1 + 4C +4

-4 = 2A + 4C

-2 = A + 2C---------------(2)

From(1),

C = 2 -2A ---------------(3)

From (2),

⇒ -2 = A + 4 -4A

⇒ -6 = -3A ⇒ A = 2

From (3)

C = 2 - 2(2)

⇒ C = -2

Thus [tex]\int \frac{ds}{s^{2}(s-1)^{2} }= \int (\frac{2}{s} +\frac{1}{s^{2} }- \frac{2}{s-1} +\frac{1}{(s-1)^{2} } )ds[/tex]

= [tex]2 ln|s|-\frac{1}{s} -2ln|s-1|-\frac{1}{s-1}+c[/tex]

= [tex]2ln|\frac{s}{s-1}|-\frac{1}{s}-\frac{1}{s-1}+c[/tex]

Thus,

Solution of integral  [tex]\int \frac{ds}{s^{2}(s-1)^{2} }[/tex] is  [tex]2ln|\frac{s}{s-1}|-\frac{1}{s}-\frac{1}{s-1}+c[/tex].

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The number of people who must be included in the survey, that is, the sample size should be 340.

We assume the sample size to be n.

The confidence interval required is 99%.

The Z-score corresponding to the 99% confidence interval is (Z) 2.58.

The true proportion (p) of the sample is not given, so we assume it to be 50% or 0.5.

The margin of error for the sample (E) is given to be 7% or 0.07.

By the formula of margin of error, we know that:

E = Z√[{p(1 - p)}/n].

Putting in the values, we have, we get:

0.07 = 2.58√[{0.5*0.5}/n],

or, (0.07/2.58)² = 0.25/n,

or, n = 0.25/{(0.07/2.58)²} = 339.6122449 ≈ 340.

Thus, the number of people who must be included in the survey, that is, the sample size should be 340.

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Answer:

There is no answer

Step-by-step explanation:

82 can not equal $14.00, however if you mean 82x=14.00, the answer will be 0.17 (7/41), and if you mean 82=14x, the answer will be 5.86 (41/7)

The approximate number of text messages sent in 2011 is 2 x 10^1.

Scientific notation is used in expressing large numbers in smaller numbers. To write a number in scientific notation, the number is written as a decimal number, between 1 and 10 and multiplied by a power of 10.

118, 000, 000, 000 in scientific notation is 1,18 x 10^11

2,357, 000, 000, 000 in scientific notation is 2.357 x 10^12

Difference in messages sent in 2011 compared to 2005 : (2.357 / 1.18) x 10^(12 - 11)

2 x 10^1

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Answer: x-6, x+3, x-3

Step-by-step explanation;

Split the equation into two.

x2(x-6)-9(x-6)

(x-6) is seen as one of the tiles. Now work on x2-9

x2-9 is a difference of squares meaning the last two are (x+3) and (x-3).

Answer:

Hey there!

Step-by-step explanation:

This is ur answer...

Hope it helps!

Brainliest pls!

Have a good day!^^

Using the combination formula, it is found that he can make 4 different stacks.

The order in which the balls are selected is not important, as stated in the problem. hence the combination formula is used to solve this question. If the order was important, then the permutation formula would be used.

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this problem, he has four flavors, and will choose three of them for the stacks, hence the number of different stacks is given as follows:

[tex]C_{4,3} = \frac{4!}{3!1!} = 4[/tex]

He can make 4 different stacks.

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The mean of the sample from number of patients treated at Dr. Frank's dentist office each day for ten days is 8.2

Given data:

13, 9, 7, 8, 2, 4, 22, 12, 5, 0.

Mean of the sample = Total number of patients treated / number of days

= (13 + 9 + 7 + 8 + 2 + 4 + 22 + 12 + 5 + 0) / 10

= 82/10

= 8.2

Therefore, the mean of the sample is 8.2

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What this has to signify would be the fact that there is a the spread of a stimulus through the ventricles.

This is used to refer to the term that has to do with the combination of the different types of waves. These are the Q wave, the R wave as well as the S wave. This is used in ECG measurement. It has to do with the measurement of the chambers of a person heart to check its normal function.

When the ECG are in this category, it can be regarded as a high. This may put a person to have the more likelihood of having a death that is caused by coronary diseases.

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Rotating 90 degrees counterclockwise: [tex](x,y) \longrightarrow (-y,x)[/tex]

[tex]A(-4,4) \longrightarrow A'(-4, -4)\\\\B(-3, 4) \longrightarrow B'(-4, -3)\\\\C(-3, 1) \longrightarrow C'(-1, -3)\\\\D(-4, 1) \longrightarrow D'(-1, -4)[/tex]

Translate along [tex]\langle 3, 4 \rangle[/tex]: [tex](x,y) \longrightarrow (x+3, y+4)[/tex]

[tex]A'(-4, -4) \longrightarrow A''(-1, 0)\\\\B'(-4, -3) \longrightarrow B''(-1, 1)\\\\C'(-1, -3) \longrightarrow C''(2, 1)\\\\D'(-1, -4) \longrightarrow D''(2, 0)[/tex]

Answer: [tex]\Large\boxed{First~Choice.~-28}[/tex]

Step-by-step explanation:

Given function expression

f(x) = -5x² - x + 20

Requirement of the question

Find the value of f(3)

Substitute the values into the function

f(x) = -5x² - x + 20

f(3) = -5(3)² - (3) + 20

Simplify the exponents

f(3) = -5(9) - 3 + 20

Simplify by multiplication

f(3) = -45 - 3 + 20

Simplify by subtraction and addition

f(3) = -48 + 20

[tex]\Large\boxed{f(3)=-28}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

The equivalent expression of 21√(3)(15) - 9√(3)(15) is 36√5

The expression is given as:

21√(3)(15) - 9√(3)(15)

Express 15 as 3 * 5

21√(3)(15) - 9√(3)(15) = 21√(3)(3 * 5) - 9√(3)(3 * 5)

Evaluate the product of 3 and 3

21√(3)(15) - 9√(3)(15) = 21√(9 * 5) - 9√(9 * 5)

Take the square root of 9

21√(3)(15) - 9√(3)(15) = 21*3√(5) - 9*3√5)

Evaluate the product

21√(3)(15) - 9√(3)(15) = 63√(5) - 27√5)

Evaluate the difference

21√(3)(15) - 9√(3)(15) = 36√5

Hence, the equivalent expression of 21√(3)(15) - 9√(3)(15) is 36√5

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The inequality will not have a shared solution set with the graphed linear inequality is y > five-thirds x + 2.

Linear inequalities are inequalities that involves at least one linear algebraic expression, that is, a polynomial of degree 1.Linear inequalities are the expressions where any two values are compared by the inequality symbols such as, '<', '>', '≤' or '≥'. These values could be numerical or algebraic or a combination of both.

Hence, the inequality will not have a shared solution set with the graphed linear inequality is y > five-thirds x + 2.

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Answer:

C

Step-by-step explanation:

answer is C

[tex](\stackrel{x_1}{-10}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{-9}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-9}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{-5}-\underset{x_1}{(-10)}}} \implies \cfrac{-9 +7}{-5 +10} \implies \cfrac{ -2 }{ 5 }\implies -\cfrac{2}{5}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{-\cfrac{2}{5}}(x-\stackrel{x_1}{(-10)}) \\\\\\ y+7=-\cfrac{2}{5}(x+10)\implies y+7=-\cfrac{2}{5}x-4\implies y=-\cfrac{2}{5}x-11[/tex]

Considering the situation described, the classification of the elections is given as follows:

We take the situation that is described, and build the classification from it. The classification has the following format:

P1 - P2 - P3 - P4 - P5

With P1 being the first placed candidate, P2 being the second placed candidate, and so on until P5 which is the fifth placed candidate.

From the text given in this problem, we have that:

Hence the places of each candidate are given as follows:

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What is an algebraic expression?

An expression that is made up of variables and constants, along with algebraic operations like addition, subtraction, etc.

What is the substitution method?

The substitution method is generally used to solve the system of equations. In this method, first, solve the equation for one variable, and substitute the value of the variable in the other equation

5th question :

⇒ x(2y-x)²+2x²(x-2y)

let (x-2y) = A

⇒we can also write (2y-x)² as (x-2y)² as both have the same value

x(x-2y)²+2x²(x-2y)

x(A)²+2x²(A)

By taking xA common

⇒ xA(A+2x)

On putting the value of A=(x-2y)

⇒ x(x-2y) (x-2y+2x)

⇒x(x-2y) (3x-2y)

6th question :

2(x-y)-(y-x)²

let (x-y) = B

⇒we can also write (y-x)² as (x-y)² as both have the same value

2(x-y)-(x-y)²

2B-(B)²

By taking B common

⇒ B(2-B)

On putting the value of B=(x-y)

⇒(x-y) (2-{x-y})

⇒(x-y) (2-x+y)

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The bucket number 2 will contain 45 after sorting the data.

According to the statement

we have given that the a data list which is sorted into 4 buckets then we have to find he in which the umber 45 is sorted.

So, For this purpose,

The given data list is:

76, 56, 93, 24, 45, 88, 13, 7, 37

And the data is sorted into the buckets so,it is sorted in 4 buckets. and the data contain numbers from 0 to 100.

So, let the sorting.

We know that the 100 numbers are sorted in 4 buckets then it means each bucket contain 25 numbers.

So, let us consider a

BUCKET 1 : 0 to 25

it contains the data number 7, 13,24.

Now,

BUCKET 2 : 25 to 50

it contains the data number 37,45.

Now,

BUCKET 3 : 50 to 75

it contains the data number 56.

Now,

BUCKET 4 : 75 to 100

it contains the data number 76, 88, 93.

From sorting the 45 number sort in the bucket 2.

So,The bucket number 2 will contain 45 after sorting the data.

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Answer: Line D

Step-by-step explanation:

The points in the scatterplot are closest to line D.

Answer:

a

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (4, - 1 ) and (x₂, y₂ ) = (- 2, 3 )

m = [tex]\frac{3-(-1)}{-2-4}[/tex] = [tex]\frac{3+1}{-6}[/tex] = [tex]\frac{4}{-6}[/tex] = - [tex]\frac{2}{3}[/tex] , then

y = - [tex]\frac{2}{3}[/tex] x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (- 2, 3 ) , then

3 = [tex]\frac{4}{3}[/tex] + c ⇒ c = 3 - [tex]\frac{4}{3}[/tex] = [tex]\frac{5}{3}[/tex]

y = - [tex]\frac{2}{3}[/tex] x + [tex]\frac{5}{3}[/tex] ← in slope- intercept form

multiply through by 3 to clear the fractions

3y = - 2x + 5 ( subtract - 2x + 5 from both sides )

2x + 3y - 5 = 0 ← in general form

60 ÷ 30 = 2

and

90 ÷ 30 = 3

---> 60/90 = 2/3

❄ Hi there,

the way 60/90 becomes 2/3 is this:

[tex]\sf{\dfrac{60\div30}{90\div30}=\dfrac{2}{3}}[/tex]

That's it!

❄

She walks 540 yards for 3 full laps around the park per day.

From the information given;

The longest part of the triangular park = 75 yards

The shortest part = 45 yards

Let's find the other part, using Pythagorean theorem;

a² = b² + c²

75² = 45² + c²

c² = 75² - 45²

Find the squares

c² = 5625 - 2025

c² = 3600

Make 'c' the subject

c = √3600

c = 60 yards

If she walks

75 + 60 + 45 yards per lap

180 yards per lap

For three laps, she walks

= 3 × 180

= 540 yards

Thus, she walks 540 yards for 3 full laps around the park per day.

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Condition (A) P(B/A) = y is true.

To find the true condition:

If two events are independent, then:

Use formulas for conditional probabilities:

For independent events these formulas will be:

Now in your case, Pr(A) = x and Pr(B) = y.

Therefore, condition (A) P(B/A) = y is true.

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The complete question is given below:

The probability of event A is x, and the probability of event B is y. If the two events are independent, which of these conditions must be true?

a. P(B|A) = y

b. P(A|B) = y

c. P(B|A) = x

d. P(A and B) = x + y

e. P(A and B) = x/y

Answer:

52º, 128º

Step-by-step explanation:

8. Because ∠6 is an opposite angle to ∠5, ∠6=∠5=52º;

9. Because line a//line b, ∠6=∠4=52º, so ∠7=180º–52º=128º

Hello and Good Morning/Afternoon

Let's take this problem step-by-step:

What does this problem give us:

What does this problem want us to find:

Let's solve:

           ⇒ by the vertical angle theorem is equal in measure to ∠5

               ⇒ ∠6 = 52°

           ⇒ lines a and b are parallel

               ⇒ the corresponding angles on both lines formed by the

                    transversal are equal

                         i.e. m∠2 = m∠3, m∠7 = m∠8

           ⇒ ∠8 is on a straight line with ∠6

                      [tex]\hookrightarrow angle8 +angle6 = 180\\\hookrightarrow angle8 + 52 = 180\\\hookrightarrow angle8 =128[/tex]

           ⇒ since m∠8 is equal to m∠7

              ⇒ m∠7 = 128

Definitions

Answer:

Hope that helps!

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Answer: [tex]g(x)=2^{x-3}[/tex]

Step-by-step explanation:

The graph of y=g(x) is the graph of y=f(x) shifted 3 units right.

The perimeter of quadrilateral ABCD will be 26 units.

It should be noted that we want to measure the length of each side of ABC, and use those lengths to calculate the perimeter of ABC.

This will be 10, 5, 5, and 6. Therefore the perimeter will be the addition. This will be:

= 10 + 5 + 5 + 6

= 26 units.

This also was identical to the result gotten. This is attached below.

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