Answer:
40 ml
Explanation:
boyles law
Pi Vi = PƒVƒ
4 * 20 = 2 * Vƒ
40 ml = Vƒ
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Consider the following reaction at 298K.
I2 (s) + H2 (g) 2 I- (aq) + 2 H+ (aq)
Which of the following statements are correct?
From the forgoing, we can conclude that the the correct statements are;
n = 2 mol of electronsK < 1What are the redox reaction?The redox reaction is one in which one specie is oxidized and the other is reduced. We can obtain the equilibrium constant from the relation;
E°cell = 0.0592/n log K
E°cell = cell potential
n = number of electrons
K = equilibrium constant
E°cell = -0.403 - 0.535 = -0.938 V
n = 2 electrons
Thus;
-0.938 = 0.0592/2 logK
-0.938 * 2/ 0.0592 = log K
K = 2 * 10^-31
Also;
ΔG = - nFE°cell
ΔG = - (2 * 96500 * -0.938)
ΔG = 181kJ/mol
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What would the hydroxide ion concentration be if the hydrogen ion concentration was 1.5 x 10-10 M?
Taking into account the definition of pH and pOH, the hydroxide ion concentration will be 6.61×10⁻⁵ M.
Definition of pHpH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:
pH= - log [H⁺]= - log [H₃O⁺]
Definition of pOHSimilarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
Relationship between pH and pOHThe following relationship can be established between pH and pOH:
pOH + pH= 14
Hydroxide ion concentrationIn this case you know that the hydrogen ion concentration is 1.5×10⁻¹⁰ M, this is, [H⁺]= 1.5×10⁻¹⁰ M.
Replacing in the definition of pH:
pH= - log (1.5×10⁻¹⁰ M)
Solving:
pH= 9.82
Replacing in the relationship established between pH and pOH, the pOH can be calculated as:
pOH + 9.82= 14
Solving:
pOH= 14 - 9.82
pOH= 4.18
Replacing in the definition of pOH, the concentration of hydroxide ion is obtained:
- log [OH⁻]= 4.18
Solving:
[OH⁻]= 10⁻⁴ ¹⁸
[OH⁻]= 6.61×10⁻⁵ M
In summary, the hydroxide ion concentration will be 6.61×10⁻⁵ M.
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Assuming the substance is one of those listed in the table presented in this lesson, what is the identity of the substance?
iron
copper
lead
aluminum
Answer: Iron
Explanation: IRON : Iron is an element with symbol Fe and atomic number 26 2) it is the fourth most common element in earth's crust 3) It is a heavy silvery grey metal belongs to the first transition series. 4) High ductility and malleability 5) It is a good conductor.
The identity of the substance is Iron.
Properties of IronChemical propertiesThe element iron has the atomic number 26 and the symbol FeElectronic configuration of Fe is [AR] 3d6 4s2The atomic weight of Iron is 55.847The element iron belong to the group VIII of the periodic tableIt is the fourth most prevalent element in the crust of the worldIt is a highly reactive element as it gets rusted readily in the moisture of airPhysical propertiesIt is a heavy metal in the first transition series The color of iron is silvery greyHigh malleability and ductilityIt has a strong electrical conductivity.Learn more about periodic table on
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1. A cell must continuously sort useful materials from its waste products and then remove or recycle the waste. One way a cell does this is to first put tiny tags on proteins that are no longer needed. These tags, which are small polypeptide chains 76 amino acids long, are called ubiquitin.
2. Ubiquitin tags direct proteins to compartments of the cell called proteasomes. Within each proteasome, ubiquitin-tagged proteins are deconstructed into their component amino acids. These pieces can be repurposed to build new proteins.
3. Sometimes organs stop processing waste effectively, allowing the waste to pile up and contributing to many diseases. Alzheimer's disease, for example, includes piles of waste proteins in the brain called tangles, while Parkinson's disease involves the accumulation of recyclable material into Lewy bodies. Mallory bodies are piles of waste proteins common in liver disease. These piles, known generically as inclusions, can be identified under the microscope because they are covered in tiny ubiquitin tags.
4. A problem in the breakdown of ubiquitin-tagged proteins may be one cause of spinocerebellar ataxia type 1. In this disease, a protein called ataxin-1 has an abnormal genetic mutation, and ubiquitin is able to attach to the mutant protein. Scientists believe that the mutated protein cannot be chopped up by the proteasome because of its shape, so ubiquitin-tagged ataxin-1 starts to accumulate, which leads to cell death. The cells most affected by this genetic mutation are neurons in a part of the brain associated with motor control and the spinal cord. So, a person with mutant ataxin-1 progressively loses muscle control as these cells die.
Which phrase describes the purpose of ubiguitin
A. to tag waste proteins for recycling in the proteasomes
B. to create small polypeptide chains that are 76 amino acids long
C. to create inclusions that can be identified under the microscope
D. to attach to mutant proteins so that they can accumulate In the cell
If proteins contain mutations, the proteins often do not maintain the proper shape and are unable to perform their functions. Properly functioning proteins are essential to maintaining healthy organisms.
Which statement describes the overall consequence of proteins containing mutations like those described in the passage?
A. Wastes will build up and will be reassembled to build new proteins.
B. Wastes will build up, and Mallory bodies will accumulate in the liver.
C. Wastes will build up in cells and will eventually be excreted from each cell.
D. Wastes will build up in vital organs, and the organism will experience disease.
Why do individuals with spinocerebellar ataxia experience loss of muscle control, even though the ataxin-1 protein builds up only In the brain and spinal cord?
A. Inclusions can build up in all body systems and can cause debilitating effects.
B. Genetic mutations in the ataxin-1 protein cause muscular proteins to change shape.
C. When the ubiquitin tagging system does not work effectively, cellular waste can build up in the muscles.
D. The neurons affected by the ataxin-1 protein buildup are in a region of the brain that manages muscle control.
Based on the role of ubiquitin in protein deconstruction as stated in the passage, the correct options are as follows:
to tag waste proteins for recycling in the proteasomes; option A.Wastes will build up in vital organs, and the organism will experience disease; option Dthe neurons affected by the ataxin-1 protein buildup are in a region of the brain that manages muscle control; option D.What are phrases?
Phrases refers to a group of words which contains a verb but which on their own do not make complete sense.
In the description of the role of Ubiquitin, it is described as a small polypeptide chain containing 76 amino acids. The main tole of ubiquitin is to tag proteins for deconstruction in the proteasomes.
Therefore, the phrase describes the purpose of ubiquitin is to tag waste proteins for recycling in the proteasomes; option A.
Based on the passage, the statement that describes the overall consequence of proteins containing mutations is: Wastes will build up in vital organs, and the organism will experience disease; option D
Individuals with spinocerebellar ataxia experience loss of muscle control, even though the ataxin-1 protein builds up only in the brain and spinal cord because the neurons affected by the ataxin-1 protein buildup are in a region of the brain that manages muscle control; option D.
In conclusion, mutations in ubiquitin-tagged proteins will result in accumulation in the body since they cannot be deconstructed in the proteasomes.
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silver
nitrate
solution
A current was passed through the circuit shown in figure above. In the
experiment, 5.4 g of silver metal was discharged at the cathode in electrolysis cell
B. What mass of copper was discharged at the cathode in cell A?
[Molar mass: Ag = 108 gmol¹; Cu= 63.5 gmol ¹]
Answer:
Silver
Explanation:
What mass of copper was discharge at the cathode in a cell
Determine the osmotic pressure (atm) of an aqueous sugar solution with a
concentration of 2.5 M at 25 °C?
Answer:
61 atm
Explanation:
You can calculate osmotic pressure using the following equation:
π = i MRT
In this equation,
-----> π = osmotic pressure (atm)
-----> i = van't Hoff's factor
-----> M = molarity (M)
-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)
-----> T = temperature (K)
The van't Hoff's factor is the amount of ions the substance dissociates into. Since sugar does not dissociate, this value is 1. After converting Celsius to Kelvin, you can plug the values into the equation and simplify.
i = 1 R = 0.08206 atm*L/mol*K
M = 2.5 M T = 25 °C + 273.15 = 298.15 K
π = i MRT
π = (1)(2.5 M)(0.08206 atm*L/mol*K)(298.15 K)
π = 61 atm
What volume did a helium-filled balloon have at 22.5 c and 1.95 atm if it’s new volume was 56.4 mL at 3.69 atm and 11.9c
This is an exercise in the general or combined gas law.
To start solving this exercise, we obtain the following data:
Data:T₁ = 22.5 °C + 273 = 295.5 KP₁ = 1.95 atmV₁ = ¿?P₂ = 3.69 atmT₂ = 11.9 °C + 273 = 284.9 kV₂= 56.4 mlWe use the following formula:
P₁V₁T₂ = P₂V₂T₁ ⇒ General formula
Where
P₁ = Initial pressureV₁ = Initial volumeT₂ = Initial temperatureP₂ = Final pressureV₂ = final volumeT₁ = Initial temperatureWe clear the formula for the initial volume:
[tex]\boldsymbol{\sf{V_{1}=\dfrac{P_{2}V_{2}T_{1}}{P_{1}T_{2}} } }[/tex]
We substitute our data into the formula to solve:
[tex]\boldsymbol{\sf{V_{1}=\dfrac{(3.69 \not{atm})(56.4 \ ml)(295.5 \not{k})}{(1.95 \not{atm})(284.9\not{k})} }}[/tex]
[tex]\boldsymbol{\sf{V_{1}=\dfrac{61498.278}{555.555} \ lm }}[/tex]
[tex]\boxed{\boldsymbol{\sf{V_{1}=110.697 \ lm }}}[/tex]
The helium-filled balloon has a volume of 110.697 ml.
Answer:
111 ml
Explanation:
Use the general rule for gases:
P1 V1 / T1 = P2 V2 / T2 Looking for V1 T must be in Kelvin
re-arrange to :
V1 = P2 V 2 * T1 / (T2 * P1) <==== now sub in the values
V1 = 3.69 * 56.4 * (22.5 + 273.15) / [(11.9 + 273.15) * 1.95]
V1 = 110.6949 ml
for correctness, the answer should only have THREE significant digits as all of the factors have three SD
V1 = 111 ml
What volume, in liters, of 0.023 M NH4NO3 solution can be made using 25 g NH4NO3
The molar mass of NH4NO3 is 80.043 g/mol
Answer:
14 L
Explanation:
To find the volume, you need to (1) convert grams to moles (via molar mass) and then (2) calculate the volume (via molarity equation). The final answer should have 2 sig figs to match the sig figs of the given values.
(Step 1)
Molar Mass (NH₄NO₃): 80.043 g/mol
25 grams NH₄NO₃ 1 mole
------------------------------- x ------------------------- = 0.312 moles NH₄NO₃
80.043 grams
(Step 2)
Molarity = moles / volume
0.023 M = 0.312 moles / volume <----- Insert values
(0.023 M) x volume = 0.312 moles <----- Multiply both sides by volume
volume = 14 L <----- Divide both sides by 0.023
Volume, in liters, of 0.023 M NH₄NO₃ solution can be made using 25 g NH₄NO₃ are 13.47L.
What is Molarity?Molarity of a given solution is known as the total number of moles of solute per litre of the solution. A solution that is 1.00 molar (written 1.00 M) contains 1.00 mole of solute for every liter of solution.
Molarity = (No. of moles of solute ÷ Volume of solution in liters)
The unit of molarity is mol L⁻¹.
Molarity is temperature dependent because as temperature changes, volume of the solution also changes.
No. of moles of solute = Mass / Molar mass
No. of moles of solute = 0.31
Hence,
Volume of solution in liters = No. of moles of solute ÷ molarity
= 13.47 litres
Therefore, Volume, in liters, of 0.023 M NH₄NO₃ solution can be made using 25 g NH₄NO₃ are 13.47L.
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Which Inorganic Substance has a melting point of -101°C and a boiling point of -35°C?
Group of answer choices
A. Chlorine
B. Hydrogen
C. Hydrogen Sulfide
D. Hydrogen Chloride
The inorganic substance that has a melting point of -101°C and a boiling point of -35°C is chlorine (option A).
What is melting and boiling point?Melting point is the temperature at which the solid and liquid phases of a substance are in equilibrium.
On the other hand, the boiling point is the temperature at which a liquid boils, with the vapor pressure equal to the given external pressure.
Chemical elements and compounds have specific boiling and melting points that distinguishes them chemically.
The following are the melting and boiling point of the given compound and elements respectively;
Chlorine - -101°C and -35°CHydrogen: -259.2°C and -252.9 °CHydrogen sulfide: -85.5 °C and -60°CHydrogen chloride: -114.2 °C and - 85°CTherefore, the inorganic substance that has a melting point of -101°C and a boiling point of -35°C is chlorine.
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What is meant by the term hydrocarbon?
[tex] \quad \quad\quad\huge \tt{ANSWER}[/tex]
Hydrocarbons are organic compounds which made up of only carbon and hydrogen.
[tex] \pink{ \star}[/tex]Carbon - ( C )
[tex] \pink{ \star}[/tex]Hydrogen - ( H )
━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
[tex] \red{✿}[/tex] Type of Hydrocarbon :
AlkanesAlkenesAlkynes[tex] \purple{\mathfrak{llXecretll}}[/tex]
Which of the following transformations represent an increase in the entropy of the system.
Choose all that apply
26 g C5H12 (liquid, 156K)------>26 g C5H12 (liquid, 297K)
3 mol O2 (1.14 atm, 408K) ------>3 mol O2 (1.14 atm, 204K)
32 g Pb (liquid, 601.0K) ------>32 g Pb (solid, 601.0K)
26 g C5H12 (liquid, 309K) ------->26 g C5H12 (gas, 309K)
3 mol CH4 (8.17 L, 240K) ------->3 mol CH4 (16.3 L, 240K)
The transformations that result in increase in entropy are those that result in increased disorderliness and they are:
26 g C5H12 (liquid, 156K)------>26 g C5H12 (liquid, 297K) 26 g C5H12 (liquid, 309K) ------->26 g C5H12 (gas, 309K) 3 mol CH4 (8.17 L, 240K) ------->3 mol CH4 (16.3 L, 240K) What is entropy of a system?The entropy of a system is a measure of the degree of randomness or disorderliness of a system.
When a system changes from a more ordered state to a more disordered state, there is an increase in the entropy of the system.
Increase in temperature or volume also results in increase in entropy.
For example, when solid melts to form liquid, entropy increases. Also, when liquid changes to gas, entropy of the system increases.
Based on the above transformations:
26 g C5H12 (liquid, 156K)------>26 g C5H12 (liquid, 297K) - entropy increases3 mol O2 (1.14 atm, 408K) ------>3 mol O2 (1.14 atm, 204K) - entropy decreases32 g Pb (liquid, 601.0K) ------>32 g Pb (solid, 601.0K) - entropy decreases 26 g C5H12 (liquid, 309K) ------->26 g C5H12 (gas, 309K) - entropy increases3 mol CH4 (8.17 L, 240K) ------->3 mol CH4 (16.3 L, 240K) - entropy increasesIn conclusion, an increase in disorderliness of a system results in entropy increase.
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If you dilute a solution what is the only thing about the solution that does NOT change?
Group of answer choices
A. Concentration
B. Kilograms of Solvent
C. Moles of Solute
D. Liters of Solution
Taking into account the definition of dilution, moles of solute (option C) is the only thing about the solution that does NOT change.
DilutionWhen it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.
Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.
In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
A dilution is mathematically expressed as:
Ci×Vi = Cf×Vf
where
Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volumeSummaryIn summary, moles of solute (option C) is the only thing about the solution that does NOT change.
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Your first post will be about one of the following topics: how stoichiometry is used
in formulating airbags, producing contrails, or formulating rocket engines .It must
be a minimum of 1 paragraph (at least 6-8 complete sentences), use lesson
specific vocabulary, and be classroom appropriate.
Stoichiometry is used in formulating airbags that shows relationship between product and reactants.
How stoichiometry is used in formulating airbags?
The quick chemical decomposition of solid sodium azide (NaN3) that allows the air bag to inflate fast at any time when the car hit anything. The decomposition reaction is initiated in a car by a small ignition that occurs due to collision sensing mechanism. The nitrogen gas produced during the reaction inflates the air bag which protect the person in the car.
So we can conclude that Stoichiometry is used in formulating airbags that shows relationship between product and reactants.
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Stoichiometry is important in formulating airbags, producing contrails, or formulating rocket engines so as to ensure the required amount of products are formed.
What is stoichiometry?Stoichiometry is the molar relationship between the reactants and products of a reaction.
It is the ratio in which moles of reactants of a reaction combine to form moles of products.
Stoichiometry is important in determining the amount of reactants required to produce a given amount of products.
For example, stoichiometry is important in formulating airbags, producing contrails, or formulating rocket engines in order to ensure the mass of reactants used is enough to produce the required products.
In conclusion, stoichiometry of a reaction provides the knowledge about the amount of reactants required to form products.
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Which of the following will increase entropy in a reaction?
Group of answer choices
A. Using a larger particle
B. heating up the reaction
C. cooling down the reaction
D. Making less moles of products than there were reactants.
The condition that will increase the entropy in a reaction is heating up the reaction (option B).
What is entropy?Entropy in chemistry is the measure or degree of the disorder or randomness present in a chemical system.
In a chemical reaction, reacting substances called reactants collide with one another to form products.
However, the degree at which the reactants collide with one another is referred to as the entropy of the reaction.
Therefore, the condition that will increase the entropy in a reaction is heating up the reaction i.e. increase in temperature.
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what is the correct iupac name for the following structure:CH2=CH-CH2-CH3
The correct IUPAC name of the following structure CH2=CH2-CH-CH3 is But - 1 - ene
IUPAC rules for alkene nomenclatureThe parent alkene is picked because it has the longest carbon chain with the double bond between carbon atoms.The suffix "ane" of the alkane is transformed to "ene."Depending on whether a double bond appears twice or three times in the parent chain, an alkene is referred to as a diene or triene.the positions of double bonds or side chains, indicated by the numerals 1, 2, 3, etc.Because it is the longest chain and is numbered from that end, the carbon atom in the double bond, which is written just before the suffix "ene," has the lowest number.The carbon chain is numbered so that the substituent receives the lowest number if both sides of a double bond receive the same number.Hence the structure CH2=CH-CH2-CH3 is named on the basis of the above rule as but - 1 - ene.
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perform the following operation and express the answer in scientific notation 6x10^2 / 8x10^12
Answer:
7.5 x 10 ^-11
Explanation:
6/8 = .75
10^2 / 10^12 = 10^ (2-12) = 10^(-10)
so far .75 x 10^-10
which is 7.5 x 10^-11
1. State the three factors that increase the rate of dissolving a solid substance in solution.
2. An oven-cleaning solution is 40.0% (by mass) NaOH.
If one jar of this product contains 458 g of solution, how much NaOH (by mass) does it contain?
Answer:
The rate of dissolving is influenced by several factors, including stirring, temperature of solvent, and size of solute particles.
What is the [OH-] if the [H3O+] is 1 x 10 -6?
The answer is [OH⁻] = 1 x 10⁻⁸.
To find OH⁻, divide the ionic product of water by [H₃O⁺] as :
OH⁻ + H₃O⁺ = H₂O
[OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻⁶[OH⁻] = 1 x 10⁻⁸HELP NOW pls will give points due soon
Sorry for the sloppy writing I tried my best.
If you can't read the words in my photo it says
Evaporation
condensation precipitation and runoff
definition of these words
evaporation: The process of turning liquid into vapor
Condensation:water which collects as droplets on a cold surface when humid air is in contact with
Precipitation: the action or process of precipitating a substance from a solution
runoff: liquid, especially water or rainwater, that flows off or drains away
I hope this is helpful
Sincerely- Your Brainly Bestfriend
How do scientists believe that chloroplasts got into photosynthetic cells?
Let's see what I can come up with here. So chloroplasts are made up of several separate sections. They have the stroma (the liquid in which everything is contained) and the grana (plural of granum and is a stack of thylakoids). Chlorophyll is found in thylakoids.
The chlorophyll absorbs light (not green light since that is what is reflected to our eyes). Light energy is utilized to split water into hydrogen ions, electrons, and oxygen gas. With these ions and electrons, the electron transport chain, with the assistance of enzymes, produces ATP and NADPH. In all living cells, ATP is the primary source of energy. Because light is required to split water, this step of photosynthesis is known as the "light reaction."
The ATP and NADPH are transported into the stroma, where the "dark reaction" can take place. And, despite the name, it does not occur at night since our energy source does not store well. You've probably heard of the Calvin Cycle. The Calvin Cycle basically uses water, CO2, and the energy from earlier to generate carbohydrates, which are then stored in various ways. Glucose is the most well-known monosaccharide, although there are others, as well as countless polysaccharides such as cellulose and starch.
Thank you,
Eddie
Consider this reaction: 6 CO2 + 6 H2O + light equation C6H12O6 + 6 O2 If there were 2.38 x 102 g of H2O, 18.6 moles of CO2, and plenty of light, which reactant would be the limiting reactant?
H₂O would be the limiting reactant.
Balanced chemical equation:
6CO₂ + 6H₂O + light equation → C₆H₁₂O₆ + 6O₂
The amount of product that can be created is constrained by the reactant that is consumed first in a chemical reaction, commonly referred to as the limiting reactant (or limiting reagent).
Given
No. of moles of CO₂ = 18.6
Mass of H₂O = 2.38 × 10² g = 238g
No. of moles of H₂O = Given mass/ Molar mass
= 238 / 18 = 13.22 moles
Moles of H₂O = 13.22
According to the balanced chemical equation
6 moles of CO₂ react with 6 moles of H₂O
So the reactant that has less number of moles will be consumed first.
As the No. of moles of H₂O < No. of moles of CO₂
So, H₂O is the limiting reactant with 13.22 moles.
Hence, H₂O would be the limiting reactant.
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How many moles of solute particles are present in 1 mL (exact) of aqueous 0.0040 M Ba(OH)2?
Answer:
4.0 x 10^-6 moles
Explanation:
0.0040 M Ba(OH)2 means there is .0040 moles per liter
you want 1 ml which is 1/1000 liter so you get 1/1000 of the moles
= .0000040 moles
Aluminum has a face-centered cubic lattice with all atoms at lattice points. Its atomic mass is 26.982 amu. (4 r = 1(2)^1/2 ; Avogadro's # is 6.022 x 10^23)
a) If each aluminum atom has a radius of 143 pm, what is the edge length of the unit cell?
b) Calculate the density of aluminum metal.
(a) The edge length of the unit cell is 286 pm.
(b) The the density of aluminum metal is 1.27 x 10⁻²³ g/cm³.
What is edge length of the aluminum atom?
The edge length of the aluminum atom is calculated as follows;
a = 2r
where;
r is the radius of the atoma is edge lengtha = 2 x 143 pm = 286 pm
Volume of the aluminum atomV = a³
V = (286 x 10⁻¹²)³
V = 2.34 x 10⁻²⁹ m³
Density of the aluminum metalρ = ZM/VN
where;
Z is 4 for face-centered cubicM is mass of aluminum atom (g/mol), 26.982 amu = (1.66 x 10⁻²⁴ x 26.982) = 4.479 x 10⁻²³ g/molV is volumeN is Avogadro's numberρ = (4 x 4.479 x 10⁻²³) / ( 2.34 x 10⁻²⁹ x 6.023 x 10²³)
ρ = 1.27 x 10⁻¹⁷ g/m³
ρ = 1.27 x 10⁻¹⁷ g/m³ x (1 m³ / 10⁶ cm³)
ρ = 1.27 x 10⁻²³ g/cm³
Thus, the edge length of the unit cell is 286 pm and the the density of aluminum metal is 1.27 x 10⁻²³ g/cm³.
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If you mix 20.0 mL of a 3.00 M sugar solution with 30.0 mL of a 6.38 M sugar solution, you will end up with a sugar solution of ______ M
Taking into account the definition of molarity, the final sugar solution has a concentration of 5.028 M.
Definition of molarityMolar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
molarity= number of moles÷ volume
Molarity is expressed in units [tex]\frac{moles}{L}[/tex].
This caseIn this case, you mix 20.0 mL (0.02 L) of a 3.00 M sugar solution with 30.0 mL (0.03 L) of a 6.38 M sugar solution. To know the concentration of the sugar solution, you need to find the total moles of sugar solution from the mixtures as follow:
0.02 L× 3 M= 0.06 moles of sugar.0.03 L× 6.38 M= 0.1914 moles of sugar.total moles of sugar solution= 0.06 moles + 0.1914 moles= 0.2514 moles.Now, the total volume of the solution is calculated adding the volume of the two solutions:
total volume= 20 mL + 30 mL= 50 mL= 0.05 L
Replacing the values inf the definition of molarity:
molarity= 0.2514 moles÷ 0.05 L
Solving:
molarity= 5.028 M
Finally, the final sugar solution has a concentration of 5.028 M.
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The volume of a gas at 0 degrees Celsius is 100 L. If the volume of the gas is increased to 200 L at a constant temperature, what is the new temperature of the gas in Kelvin?
The new temperature of the gas in Kelvin, given the data from the question is 273 °C
Data obtained from the questionFrom the question given above, the following data were obtained:
Initial volume (V₁) = 100 LInitial temperature (T₁) = 0 °C = 0 + 273 = 273 KPressure = ConstantNew volume (V₂) = 200 LNew temperature (T₂) =? How to determine the new temperatureThe new temperature of the gas can be obtained by using the Charles' law equation as illustrated below:
V₁ / T₁ = V₂ / T₂
100 / 273 = 200 / T₂
Cross multiply
100 × T₂ = 273 × 200
Divide both side by 100
T₂ = (273 × 200) / 100
T₂ = 546 K
Subtract 273 to obtain answer in °C
T₂ = 546 – 273 K
T₂ = 273 °C
Thus, new temperature of the gas is 273 °C
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What answer should be reported, with the correct number of significant figures, for the following calculation? (433.621 - 333.9) × 11.900
Answer:
1187 ( four S.D. )
Explanation:
(433.621 - 333.9) × 11.900 333.9 has only 4 S.D. answer should only have 4 S.D
= 1186.6799 = ~ 1187 with 4 Significant Digits
Calculate the pOH of a 0.0143 M NaOH solution at 25 ⁰C.
1.845
6.993 x 10⁻¹³
12.155
-1.845
Answer:
A.) 1.845
Explanation:
You can find the pOH using the following equation:
pOH = -log[OH⁻]
Since NaOH dissociates into 1 Na⁺ and 1 OH⁻, the concentration of both ions is 0.0143 M.
pOH = -log[OH⁻]
pOH = -log[0.0143]
pOH = 1.845
Suppose you have 4.0 moles of aqueous barium chloride, and you mix this with aluminum sulfate solution. How many moles of aluminum chloride can you produce?
Answer:
2.7
Explanation:
The equation of the reaction is
3 BaCl2 + Al2(SO4)3 = 3 BaSO4 + 2 AlCl3
So, frok the coefficients of the equation, the answer is 2.7
2.67 moles of aluminum chloride can be produce if we have 4.0 moles of aqueous barium chloride, and we mix this with aluminum sulfate solution.
The balanced chemical reaction is :
3BaCl₂ + Al₂(SO₄)₃ ---> 3BaSO₄ + 2AlCl₃
When aqueous barium chloride is mixed with aluminum sulfate solution, a double displacement reaction occurs. The barium ions from barium chloride react with the sulfate ions from aluminum sulfate to form insoluble barium sulfate precipitate. At the same time, the aluminum ions from aluminum sulfate react with the chloride ions from barium chloride to form aluminum chloride.
Given :
Number of Moles of BaCl₂ = 4.0 moles
From the balanced chemical reaction,moles of AlCl₃:
= (4.0 moles BaCl₂) (2 moles AlCl₃/3 moles BaCl₂)
= 2.67 moles AlCl₃
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The empirical formula for a compound is C3H3O the molecular mass is 110 what is its molecular formula
Answer:
emiprical formula is 55
Explanation:
(-^〇^-)
Anyone know this please and thank you
Answer:
The correct answer is a hypothesis.