The motion of an object was recorded by measuring the velocity of the object in meters per second at various times, as shown in the table. The scatterplot below was graphed from the data in the table, where t represents the time, and v represents the velocity.
Based on the scatterplot, which equation BEST represents the relationship between velocity and time?

The Motion Of An Object Was Recorded By Measuring The Velocity Of The Object In Meters Per Second At

Answers

Answer 1

The regression equation that represents the relationship between velocity and time is:

How to find the equation of linear regression using a calculator?

To find the equation, we need to insert the points (x,y) in the calculator.

For this problem, the points (t,v), that is, time and velocity, are given as follows:

(0, 6.1), (2.1, 12.2), (5.3, 17.4), (8.2, 26.4), (10, 28.1), (12.1, 32.8).

Hence, inserting these points into a calculator, the equation is given by:

v = 2.19t + 6.7.

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Related Questions

How many fruits did Anna get?

Answers

Answer: Anna got 30

Step-by-step explanation: 2x+3y=25

15+10=25

Quick algebra 1 question for 25 points!

Only answer if you know the answer, Tysm!

Answers

Using a quadratic regression equation, it is found that the prediction of volunteers in year 10 is of:

A. 47.

How to find the equation of quadratic regression using a calculator?

To find the equation, we need to insert the points (x,y) in the calculator.

In this problem, we have that the function initially increases, then it decreases, which means that it is a quadratic function. The points (x,y) to  be inserted into the calculator are given as follows:

(1, 20), (2,17), (3, 16), (4,16), (5,18), (6,21), (7,25), (8,31)

Inserting these points into the calculator, the prediction of y for a value of x is given as follows:

y = 0.702x^2 - 4.726x + 23.857

Hence, when x = 10, the prediction is:

y = 0.702 x 10² - 4.726 x 10 + 23.857

y = 47.

Hence option A is correct.

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17. In a spelling competition, school X had 12 more participants than school Y and 18 fewer participants than school Z. The ratio of the number of boys to the number of girls in school X, Y and Z were 1:2, 1:5 and 2: 1 respectively. There were 50 more girls than boys in total from the 3 schools. How many participants from the 3 school were there in all?​

Answers

There were 204 participants from the three schools

How to determine the number of participants?

The given parameters are:

X = 12 + Y

X = Z - 18

Girls = Boys + 50

The ratios of the number of boys to girls in the schools are:

1 : 2

1 : 5

2 : 1

This means that:

School X: Boys = 1/3 and Girls = 2/3School Y: Boys = 1/6 and Girls = 5/6School Z: Boys = 2/3 and Girls = 1/3

So, we have:

Boys = 1/3X + 1/6Y + 2/3Z

Girls = 2/3X + 5/6Y + 1/3Z

Substitute the above equations in Girls = Boys + 50

2/3X + 5/6Y + 1/3Z = 1/3X + 1/6Y + 2/3Z + 50

Evaluate the like terms

1/3X + 2/3Y - 1/3Z = 50

Multiply through by 3

X + 2Y - Z = 150

So, we have:

X = 12 + Y

X = Z - 18

X + 2Y - Z = 150

Substitute X = 12 + Y in X = Z - 18 and X + 2Y - Z = 150

12 + Y = Z - 18 ⇒ Y - Z = 30

12 + Y + 2Y - Z = 150 ⇒ 3Y - Z = 138

Subtract Y - Z = 30 from the equation 3Y - Z = 138 to eliminate Z

2Y = 108

Divide by 2

Y = 54

Substitute Y = 54 in X = 12 + Y

X = 12 + 54

X = 66

Substitute X = 66 in X = Z - 18

66 = Z - 18

Solve for Z

Z = 66 + 18

Z = 84

So, the total number of participants from the 3 schools is

Total = X + Y + Z

This gives

Total = 66 + 54 + 84

Evaluate the sum

Total = 204

Hence, there were 204 participants from the three schools

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What is the solution of square root 1-3x = x+3?
O x = -8 or x = -1
O x=-8
O x=-1
O no solution

Answers

Answer: x =   -1

Step-by-step explanation:

To remove the radical on the left side of the equation, square both sides of the equation.

√1−3x2=(x+3)2

Simplify each side of the equation.

1−3x=x2+6x+9

Solve for x

x=−1−8

Exclude the solutions that do not make true

√1−3x=x+3

x=−1

Explain the similarities and differences between the two relationships in this situation.

Answers

enter then equation?

Complete the equation of the line through
(-10, 3) and (-8, -8).

Answers

The answer is y = -5.5x - 52.

First, let's find the slope of the line.

m = Δy/Δx

m = -8 - 3 / -8 - (-10)m = -11 / -8 + 10m = -11/2m = -5.5

Now, substitute the slope and one of the given points in the point slope equation.

y - y₁ = m (x - x₁)

y - 3 = -5.5 (x - (-10))y - 3 = -5.5 (x + 10)y - 3 = -5.5x - 55y = -5.5x - 52

Answer: y=-5,5x-52.

Step-by-step explanation:

                        Equation of a straight line

                               [tex]\displaystyle\\\boxed {\frac{x-x_1}{x_2-x_1}=\frac{y-y_1}{y_2-y_1} }[/tex]

[tex](-10;3)\ \ \ \ \ (-8;-8).\\\displaystyle\frac{x-(-10)}{-8-(-10)} =\frac{y-3}{-8-3}\\ \frac{x+10}{-8+10}=\frac{y-3}{-11} \\ \frac{x+10}{2}=\frac{y-3}{-11} \\-11*(x+10)=2*(y-3)\\-11x-110=2y-6\\2y=-11x-104\ |:2\\y=-5,5x-52.[/tex]

The area of a painting is 4081 c m squared.

If the width of the painting is 53 cm, what is its length, in centimeters?

Type your numerical answer below (without units). If necessary, round to the nearest integer.

Answers

The length of the rectangle is 77cm.

According to the statement

we have given that the area of a painting is 4081 c m squared. and width of the painting is 53 cm.

And we have to find the Length of the painting.

So, For this purpose

Area of rectangle is the region occupied by a rectangle within its sides. It depends on its sides.

So, the formula to find the area of rectangle is

Area = Length*Breadth

4081 = L*53

L = 4081/53

L = 77 cm.

So, The length of the rectangle is 77cm.

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8 out of 10 people saw the show

Answers

Answer: 80% of the 10 people saw the show.

Step-by-step explanation:

8/10 = 0.8, which is 80%.

I hope this helped!

According to USA Today, the average cost of a private university is $50,000 with a population standard deviation of $2,500. 100 universities are randomly selected and the average income of those 100 universities was $49,450. Using the 5 step hypothesis testing process, can you support the claim that the average cost of private universities are decreasing? Use a .01 significance level. (Use the z or t value of -2.2) What is your conclusion based on p-value?

Answers

Using the z-distribution, it is found that since the p-value is less than 0.05, there is evidence to support the claim that the average cost of private universities are decreasing.

What are the hypothesis tested?

At the null hypothesis, it is tested if the average cost is still of $50,000, that is:

[tex]H_0: \mu = 50000[/tex]

At the alternative hypothesis, it is tested if the average cost is decreasing, that is:

[tex]H_1: \mu < 50000[/tex]

What is the test statistic?

The test statistic is:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which:

[tex]\overline{x}[/tex] is the sample mean.[tex]\mu[/tex] is the value tested at the null hypothesis.[tex]\sigma[/tex] is the standard deviation of the population.n is the sample size.

The parameters for this problem are:

[tex]\overline{x} = 49450, \mu = 50000, \sigma = 2500, n = 100[/tex]

Hence:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{49450 - 50000}{\frac{2500}{\sqrt{100}}}[/tex]

z = -2.2.

What is the p-value and the conclusion?

Using a z-distribution calculator, for a left-tailed test, as we are testing if the mean is less than a value, with z = -2.2, the p-value is of 0.0139.

Since the p-value is less than 0.05, there is evidence to support the claim that the average cost of private universities are decreasing.

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How does changing the function from f(x) = -5 cos 2x to g(x) = -5 cos 2x-3 affect the range of the function?

Answers

Each element in the range of g(x) is 3 less than the corresponding element in the range of f(x).

Answer:

See below.

In short, by having vertical shift will affect range from -1 ≤ y ≤ 1 to -1 + a ≤ y ≤ 1 + a

Step-by-step explanation:

Generally, a cosine function without vertical shift will always have range equal to -1 ≤ y ≤ 1

If there is given vertical shift, our range will change to -1 + a ≤ y ≤ 1 + a

An example is if we are given the function of cos(x), this always has range of -1 ≤ y ≤ 1 because there is no vertical shift.

But if we have cos(x) + 1, we have vertical shift which is 1. Then the range will be -1+1 ≤ y ≤ 1+1 which equals to 0 ≤ y ≤ 2.

Hence, the function of -5cos(2x) has only range of -1 ≤ y ≤ 1 but the function of -5cos(2x) - 3 will have range of -1-3 ≤ y ≤ 1-3 which equals to -4 ≤ y ≤ -2

On Wednesday, 1/3 of the students in Mr. Short's homeroom had drama practice, and 1/4 of his other homeroom students had band practice. If 6 students had band practice, how many students are in Mr. Short's homeroom?

Answers

Answer:

36

Step-by-step explanation:

Honestly, I'd work this out visually (see image) by drawing a rectangle and dividing it up. But if you need to show the math, here's how to do it:

Let x = the number of students in the homeroom

1/3 x have drama

1/4 (x - 1/3x) have band, and we are told 6 students have band, so

1/4 (x - 1/3 x) = 6

1/4 (2/3 x) = 6    

2/12 x = 6          

1/6 x = 6            

6 × 1/6 x = 6 × 6

1 x = 6 × 6            

x = 36

Answer:

36

Step-by-step explanation:

Let n be the total number of students in Mr. Short's homeroom. Then, working backward, we see that 

6 = 1/4(1 - 1/3)n = 1/4(2/3)n = 1/6n,$

so n = 6 x 6 = 36 students.

Pls help
Write the equation for a parabola with a focus at (-4,3) and a directrix at y=5

Answers

Answer:

y=(1/-4)(x+4)^2 +4

Step-by-step explanation:

Don't ask

Find the number of ways of delivering five letters to five houses so that no house gets
a correct letter.

Answers

Using the Fundamental Counting Theorem, it is found that there are 1024 ways of delivering the letters.

What is the Fundamental Counting Theorem?

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

In this problem, each house has a correct letter, however the letter cannot be used for the house, hence the parameters are given as follows:

n1 = n2 = n3 = n4 = n5 = 5 - 1 = 4.

Thus the number of ways is:

N = 4 x 4 x 4 x 4 x 4 = 4^5 = 1024.

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A retailer allowed 4% discount on his goods to make 20% profit and sold a refrigerator for Rs 10,848 with 13% VAT. By how much is the discount to be increased so that he can gain only 15%?​

Answers

The discount to be increased so that he can gain only 15% is 8%.

What is a discount? Discounts are given when a reduction in the price is permitted to promote more purchases or timely payments. Discounts are divided into Trade reduction: The discount granted when substantial purchases are made is referred to as a trade discount.Discounts are given when a reduction in the price is permitted to promote more purchases or timely payments. Discounts are divided into Trade reduction: The discount granted when substantial purchases are made is referred to as a trade discount.Since sales discounts lower the cost of a product, they are not considered costs. These monetary discounts provided to consumers do, however, have an impact on a company's financial statements. Thus they must be reported as a decrease in revenue under the accounts receivable line item.

How much is the discount to be increased so that he can gain only 15%:

The cost price of the goods - y.

The selling price of the goods - x.

The selling price is

1.2y (100% + 20% = 120%).

The refrigerator was sold at 13% VAT at Rs. 10848:

=> 1.2y + 13%(1.2y) = 10848

=> 1.2y + 0.156y = 10848

=> 1.356y = 10848

=> y = 8000

Thus, the cp is Rs 8000.

The selling price is:

=> 0.96x = 1.2y

=> 0.96x = 1.2(8000)

=> x = 10000

The selling price is Rs. 10000

For a profit of 15%, that is 1.15(8000) = 9200, the discount is:

(1 - discount)10000 = 9200

1 - discount = 0.92

Discount = 1 - 0.92 = 0.08 or 8%

How much is the discount to be increased so that he can gain only 15%: Discount=8%

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Help please! What is the correct answer and how do I solve for R?

Answers

the correct answer is d, to solve for r divide both sides by 2piH

is the identity for addition for rational number a) 1 b) 0 c) -1 d) 1/2​

Answers

The identity for addition for rational numbers is zero which is the option b.

Given addition of rational numbers.

We are required to find the identity for the addition of rational numbers.

Rational numbers are those numbers which can be written in the form of p/q and q cannot be equal to zero because if q is equal to zero the whole fraction will become infinity. The numbers whih cannot be written as p/q are known as irrational numbers.

From the all option zero is the identity for addition for rational numbers. This  means if a is a rational number. Then a+0=0+a=a.

Hence the identity for addition for rational numbers is zero which is the option b.

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Evaluate the surface integral. s y ds s is the surface z = 2 3 x3/2 y3/2 , 0 ≤ x ≤ 4, 0 ≤ y ≤ 1

Answers

The surface integral of the given surface [tex]z=\frac{2}{3}(x^\frac{3}{2}+y^\frac{3}{2})[/tex] in the intervals 0 ≤ x ≤ 4, 0 ≤ y ≤ 1 is 7.36615.

How to evaluate the surface integral?

To evaluate the surface integral, the formula applied is

[tex]S=\int\limits^b_a\int\limits^d_c {f(x,y)} \ dy\ dx[/tex]

⇒ S = [tex]\int\limits^b_a \int\limits^d_c {\sqrt{1+(\frac{dz}{dx})^2+(\frac{dz}{dy})^2 } } \, dy \, dx[/tex]

Where the differentiation is partial differentiation and f(x, y) = z.

Calculation:

The given function is

f(x, y) = [tex]z=\frac{2}{3}(x^\frac{3}{2}+y^\frac{3}{2})[/tex]

Then, applying the partial differentiation w.r.t x and y respectively,

dz/dx = [tex]\frac{2}{3}(\frac{3}{2})x^{1/2}[/tex] = [tex]x^{1/2}[/tex]

dz/dy = [tex]\frac{2}{3}(\frac{3}{2})y^{1/2}[/tex] = [tex]y^{1/2}[/tex]

Then,

we have surface integral  formula as

S = [tex]\int\limits^b_a \int\limits^d_c {\sqrt{1+(\frac{dz}{dx})^2+(\frac{dz}{dy})^2 } } \, dy \, dx[/tex]

On substituting,

⇒ S = [tex]\int\limits^4_0 {\int\limits^1_0 {\sqrt{1+(x^{1/2})^2+(y^{1/2})^2} \, dy } \, dx[/tex]

⇒ S = [tex]\int\limits^4_0 {\int\limits^1_0 {\sqrt{1+x+y} \, dy } \, dx[/tex]

On integrating w.r.t y

⇒ S = [tex]\int\limits^4_0 {\frac{2}{3}(1+x+y)^{3/2}} \,|_0^1 dx[/tex]

Applying limits,

⇒ S = [tex]\int\limits^4_0 {\frac{2}{3}[(1+x+1)^{3/2}-(1+x+0)^{3/2} } \, dx[/tex]

⇒ S = [tex]\frac{2}{3} \int\limits^4_0 {[(x+2)^{3/2}-(x+1)^{3/2}}] \, dx[/tex]

Again applying the integration w.r.t x

⇒ S = [tex]\frac{2}{3}[\frac{2}{5}(x+2)^{5/2}-\frac{2}{5}(x+1)^{5/2}]|_0^4[/tex]

Applying the limits and simplifying,

⇒ S = [tex]\frac{4}{15}[(4+2)^{5/2}-(4+1)^{5/2}-(0+2)^{5/2}+(0+1)^{5/2}][/tex]

⇒ S = [tex]\frac{4}{15}[1+36\sqrt{6}-25\sqrt{5}-4\sqrt{2}][/tex]

∴ S = 7.36615

Therefore, the surface integral of the given function is 7.36615.

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The first 5 terms of a sequence are 2 8 14 20 26 Find the nth term ​

Answers

Answer: [tex]\Large\boxed{a_n=6n-4}[/tex]

Step-by-step explanation:

Given sequence

2, 8, 14, 20, 26

Determine the pattern

2 + 6 = 8

8 + 6 = 14

14 + 6 =20

20 + 6 = 26

For each term, add 6 to get the next term

Determine the type of sequence

Since it continuously adds 6, the common difference is 6, which means it is an arithmetic sequence

Given the arithmetic sequence formula

aₙ = a₁ + d (n - 1)

a₁ = 1st term of a sequenceaₙ = nth term of a sequencen = nth positiond = Common difference

Substitute values into the formula

aₙ = (2) + (6) (n - 1)

aₙ = 2 + 6 (n - 1)

aₙ = 2 + 6n - 6

aₙ = 2 - 6 + 6n

[tex]\Large\boxed{a_n=6n-4}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Given sequence :-

2 , 8 , 14 , 20 , 26...

Solution :-

We need to calculate the nth term of the given sequence.

Common difference (d) = 8 - 2 => 6First term of sequence (a) = 2

We know that,

tn = a + (n - 1) d

Applying the values here.

>> tn = 2 + (n - 1) 6

>> tn = 2 + (n - 1) × 6

>> tn = 2 + 6n - 6

>> tn = 6n - 4

Therefore, nth term of the sequence is (6n - 4).

An amusement park sells adults' and
children's passes. An adult's pass is $25,
and a child's pass is $15. A group spent
$440 on 20 passes. How many children's
passes did the group purchase?
A

Answers

Answer:

6 children passes

Step-by-step explanation:

a = adult and c = children

25a + 15c = 440           and          a + c = 20

                                                     c = 20 - a

25a + 15(20-a) = 440

25a + 300 - 15a = 440

25a - 15a = 440 - 300

10a = 140

a = 140/10

a = 14 and this is 14 adult tickets

Now we plug the a value into the equation to find the c value

14 + c = 20

c = 20 - 14

c = 6

Verify answer:

25(14) = 15(6) = 440

350 + 90 = 440

440 = 440

ASAP NOW
below is the question

Answers

The mean of the data set A is 4.58 while the mean of data set B is 5.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

The mean of a set of numbers is the average of that group of number. It is the ratio of the sum of the data to the total number of data.

Mean of data set A = [(3 * 1) + (4 * 3) + (5 * 2) + (6 * 2) + (7 * 3) + (8 * 1)] / (1 + 3 + 2 + 2 + 3 + 1) = 4.58

Mean of data set B = [(4 * 2) + (5 * 2) + (6 * 2)] / ( 2 + 2 + 2) = 5

The mean of the data set A is 4.58 while the mean of data set B is 5.

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Find the value of x if m2 = 4x - 2.
68⁰
2

Answers

The value of x is 11 1/2 OR 11.5

Calculating the measure of angles

From the question, we are to determine the value of x

In the given diagram, we have two isosceles triangles

Since base angles of isosceles triangles are equal,

Then, each of the base angles of the isosceles triangle is 68°

Then, we can write that

m ∠2 + 68° + 68° = 180° (Sum of angles in a triangle)

From the given information,

m ∠2 = 4x - 2

Then,

4x -2 + 68° + 68° = 180°

4x = 180 - 68 - 68 +2

4x = 46

x = 46/4

x = 11 1/2 OR 11.5

Hence, the value of x is 11 1/2 OR 11.5

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divide the polynomials:
x^2-3x+9/x-2

Answers

The value of dividing x^2-3x+9 by x-2 is x + 3

Ways of dividing polynomials

There are several ways to divide polynomial functions; some of these ways include

By factorizationBy long divisionBy synthetic divisionBy using technology such as graph

How to divide the polynomials?

The expression for the polynomial division is given as:

x^2-3x+9/x-2

To divide polynomial functions, we make use of the division by factorization method

Start by expanding the numerator of the polynomial division

x^2-3x+9/x-2 = x^2 + 3x - 6x + 9/x-2

Factorize the equation

x^2-3x+9/x-2 = x(x + 3) - 2(x + 3)/x - 2

Factor out x + 3 from the numerator

x^2-3x+9/x-2 = (x- 2)(x + 3)/x - 2

Cancel out the common factors

x^2-3x+9/x-2 = x + 3

Hence, the value of dividing x^2-3x+9 by x-2 is x + 3

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Evaluate the following integral (Calculus 2) Please show step by step explanation!

Answers

Answer:

[tex]4\ln \left| \dfrac{1}{3}\sqrt{9+(\ln x)^2} + \dfrac{1}{3}\ln x \right|+\text{C}[/tex]

Step-by-step explanation:

Fundamental Theorem of Calculus

[tex]\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))[/tex]

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

[tex]\displaystyle \int \dfrac{4}{x\sqrt{9+(\ln(x))^2}}\:\:\text{d}x[/tex]

Rewrite 9 as 3²:

[tex]\implies \displaystyle \int \dfrac{4}{x\sqrt{3^2+(\ln(x))^2}}\:\:\text{d}x[/tex]

Integration by substitution

[tex]\boxed{\textsf{For }\sqrt{a^2+x^2} \textsf{ use the substitution }x=a \tan\theta}[/tex]

[tex]\textsf{Let } \ln x=3 \tan \theta[/tex]

[tex]\begin{aligned}\implies \sqrt{3^2+(\ln x)^2} & =\sqrt{3^2+(3 \tan\theta)^2}\\ & = \sqrt{9+9\tan^2 \theta}\\ & = \sqrt{9(1+\tan^2 \theta)}\\ & = \sqrt{9\sec^2 \theta}\\ & = 3 \sec\theta\end{aligned}[/tex]

Find the derivative of ln x and rewrite it so that dx is on its own:

[tex]\implies \ln x=3 \tan \theta[/tex]

[tex]\implies \dfrac{1}{x}\dfrac{\text{d}x}{\text{d}\theta}=3 \sec^2\theta[/tex]

[tex]\implies \text{d}x=3x \sec^2\theta\:\:\text{d}\theta[/tex]

Substitute everything into the original integral:

[tex]\begin{aligned} \implies \displaystyle \int \dfrac{4}{x\sqrt{9+(\ln(x))^2}}\:\:\text{d}x & = \int \dfrac{4}{3x \sec \theta} \cdot 3x \sec^2\theta\:\:\text{d}\theta\\\\ & = \int 4 \sec \theta \:\: \text{d}\theta\end{aligned}[/tex]

Take out the constant:

[tex]\implies \displaystyle 4 \int \sec \theta\:\:\text{d}\theta[/tex]

[tex]\boxed{\begin{minipage}{7 cm}\underline{Integrating $\sec kx$}\\\\$\displaystyle \int \sec kx\:\text{d}x=\dfrac{1}{k} \ln \left| \sec kx + \tan kx \right|\:\:(+\text{C})$\end{minipage}}[/tex]

[tex]\implies 4\ln \left| \sec \theta + \tan \theta \right|+\text{C}[/tex]

[tex]\textsf{Substitute back in } \tan\theta=\dfrac{1}{3}\ln x :[/tex]

[tex]\implies 4\ln \left| \sec \theta + \dfrac{1}{3}\ln x \right|+\text{C}[/tex]

[tex]\textsf{Substitute back in } \sec\theta=\dfrac{1}{3}\sqrt{9+(\ln x)^2}:[/tex]

[tex]\implies 4\ln \left| \dfrac{1}{3}\sqrt{9+(\ln x)^2} + \dfrac{1}{3}\ln x \right|+\text{C}[/tex]

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Quick algebra 1 question for 10 points!

Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!

Answers

Answer:

See image

Step-by-step explanation:

Using a graphing calculator, first press the Y= button at the top left.

Then enter the equation given in the question.

Next, press 2nd then graph, and you will get the table. Put in whatever values for x to get y.

So your answer is 48, 18, 0, -6, 0, -18, 0, 48

Given the angles inscribed in the circle, find m ∠ DBC.

Answers

Answer:

m∠DBC = 51°

Step-by-step explanation:

Circle Theorem vocabulary

Chord: A straight line joining two points on the circle.Inscribed angle: The angle formed when two chords meet at one point on a circle.Intercepted arc: The arc that is between the endpoints of the chords that form the inscribed angle.

Inscribed Angle Theorem

The measure of an inscribed angle is half the measure of the intercepted arc.

Therefore:

[tex]\sf \implies \angle DBC=\dfrac{1}{2}\:\overset{\frown}{BC}[/tex]

[tex]\sf \implies \angle DBC=\dfrac{1}{2}\:(102^{\circ})[/tex]

[tex]\sf \implies \angle DBC=51^{\circ}[/tex]

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[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]

To determine ∠DBC, we will apply the theorem relating the inscribed angle to the intercepted arc:

[tex]\longrightarrow \sf{Intercepted \: arc= (inscribe \: angle)}[/tex]

[tex]\longrightarrow \sf{Intercept \: arc= 102^\circ}[/tex]

[tex]\longrightarrow \sf{Inscribed \: angle= \angle DBC }[/tex]

[tex]\longrightarrow \sf{102=2( \angle DBC)}[/tex]

[tex]\longrightarrow \sf{\angle DBC= \dfrac{102}{2} }[/tex]

▪ [tex]\longrightarrow \sf{\angle DBC = 51^\circ}[/tex]

[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]

[tex]\boxed{\bf{\large m \: \angle DBC= 51^\circ}}[/tex]

A study of college freshmen found that students who watched tv for more than one hour each night gained 15 pounds in the first semester, compared to those who watched less than one hour. they concluded that there is an association between watching tv and weight gain in college freshmen. which study design did they most likely use?

Answers

Answer:

C.  They most likely used an observational study asking students to keep track of their TV habits and weight.

A.  This is an experiment because a treatment was applied to a group.

Step-by-step explanation:

According to our question:

1. The study concluded that there is a relation between watching TV and the weight gain in college freshmen.

Now, this is possible when a group of college students were asked to participate to watch TV for more than 1 hour for a specific amount of time and have a record of their weights.

So, the study is an observational study where the habits and weights of college students were observed.

Hence, option C is correct.

2. The students were divided onto two groups where one group used the computer program and the other did not to check the improvement in the reading levels.

This means that the students were given a procedure to follow during the study in order to see the results..

So, the study is an experiment where a treatment is applied to the group of students.

Hence, option A is correct.

Answer: C

For the people who want only one answer and not 2 for the question if you can only submit one answer :)

3x+5<6x+8
4x+3 is <7x+5

Answers

The solution to the inequalities 3x + 5 < 6x + 8 and 4x + 3 < 7x + 5 is x > -1 and x > -2/3 respectively

Inequality

Inequality signs are;

Greater than >Less than <Equal to =Less than equal to ≤Greater than equal to ≥

3x + 5 < 6x + 8

collect like terms

3x - 6x < 8 - 5

-3x < 3

divide both sides by -3

x > 3/-3

The inequality sign is flipped from < to greater than because of the division with negative value.

x > -1

2. 4x + 3 < 7x + 5

collect like terms

4x - 7x < 5 - 3

-3x < 2

divide both sides by -3

The inequality sign is flipped from < to greater than because of the division with negative value.

x > -2/3

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April was asked to determine whether f(x)=x^3 -1 is even, odd, or neither. Here is her work:

Answers

April's work in checking for the function, [tex]f(x) = x^3 - 1[/tex], to be even, odd, or neither, is incorrect. She did a mistake in step 2, where she took [tex]f(-x) = - f(x)[/tex], which was not true, since [tex]f(-x) = -x^3 - 1[/tex], whereas [tex]- f(x) = -x^3 + 1[/tex].

A function f(x) is said to be odd or even when it completes the condition:

f(-x) = -f(x), for f(x) to be an odd function, andf(-x) = f(x), for f(x) to be an even function.

In the question, we are given that April was asked to determine whether  [tex]f(x) = x^3 - 1[/tex], is even, odd, or neither, and are shown her work.

We are asked whether April's work is correct, and if not, what is the first step where April made a mistake.

To check for a function is even or odd, we first calculate f(-x).

April's first step was also finding f(-x), which she found accurately as  [tex]f(-x) = -x^3 - 1[/tex].

Next, we need to check whether f(-x) is equal to f(x), -f(x), or neither, to check if the function is even, odd, or neither, respectively.

April, also choose the right step of checking, but did a mistake in checking, since f(-x) ≠ f(x), and also, f(-x) ≠ - f(x), since, [tex]- f(x) = -(x^3 - 1)[/tex] = [tex]-x^3 + 1[/tex], which is not equal to f(-x).

Thus, April's work in checking for the function, [tex]f(x) = x^3 - 1[/tex], to be even, odd, or neither, is incorrect. She did a mistake in step 2, where she took f(-x) = - f(x), which was not true, since [tex]f(-x) = -x^3 - 1[/tex], whereas [tex]- f(x) = -x^3 + 1[/tex].

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I need help asap please help me

Answers

Answer:

8

Step-by-step explanation:

I belive what they mean is how many dots thier are i am not complety sure though but just by counting them up i came up with 8.

hope this helped

Area=
Help me please asap.
Thanks so much :)

Answers

The area of the given parallelogram is 8 square units

Area of a parallelogram

A parallelogram is a 2 dimensional figure with 4 sides and angles. From the given diagram, the opposite sides are equal and the sum of the adjacent angles are supplementary

The formula for calculating the area of a parallelogram is expressed as:

A = base * height

From the given diagram

Base = (4, 0) = 4 units

Height. = (2, 0) = 2 units

Substitute the given values into the formula to have:

A = 4 units * 2 units

A = 8 square units

Hence the area of the given parallelogram is 8 square units

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