Answer:
Dynamics is just a nice word used in physics denoting a branch of physics, related to the study of forces. Usually these forces are not in mechanical equilibrium, else the branch would be statics.
1. The diagram shows a satellite traveling in uniform circular motion around the Earth.
(a) Give the relation between radius of the orbit and the velocity of the satellite.
(b ) The satellite is kept in orbit by a force. On the diagram draw an arrow to show the
direction of this force.
Answer:
M V R = constant angular momentum is constant because no forces act in the direction of V
Since M (mass) = constant
V R = constant
The force is directed along the gravitational force vector (towards the center of rotation)
An ultracentrifuge is spinning at a speed of 80,000 rpm. The rotor that spins with
the sample can be roughly approximated as a uniform cylinder of 10 cm radius
and 8 kg mass, spinning about its symmetry axis). In order to stop the rotor in
under 30 s from when the motor is turned off, find the minimum braking torque
that must be applied.
O-19.2 Nm
-17.2 Nm
O -15.2 Nm
O-11.2 Nm
O None of the above
D. The minimum braking torque that must be applied is -11.2 Nm.
Moment of inertia of the uniform cylinderThe moment of inertia of the uniform cylinder is calculated as follows;
I = ¹/₂MR²
where;
M is mass of the cylinderR is radius of the cylinderI = (0.5)(8)(0.1²)
I = 0.04 kgm²
Minimum braking torqueτ = -Iα
where;
α is angular accelerationα = ω/t
α = (80,000 x 2π/rev x 1 min/60s) / (30 s)
α = (80,000 x 2π)/(60 x 30)
α = 279.25 rad/s²
τ = - ( 0.04 kgm²) x (279.25)
τ = -11.2 Nm
Thus, the minimum braking torque that must be applied is -11.2 Nm.
Learn more about minimum braking torque here: https://brainly.com/question/6845979
#SPJ1
Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 1026 kg, and use an orbital radius of 3.00 x 105 km. (G = 6.67 × 10-11 N ∙ m2/kg2)
The required orbital speed of the ice cube is 355,358m/s
What is gravitational law?The force of gravitation is directly proportional to the product of the masses and inversely proportional to the distance between them. This can be expressed mathematically as;
Fr = GMm/r²
The distance is calculated as;
s = Gm/r²
Solving both equation, we will have:
v²/r = Gm/r²
v² = Gm/r
Take the square root of both sides
v = √Gm/r
Solve the required orbital speed
V = √6.67×10^-11 * 5.68 x 10^26 / 3.00 x 10^5
V = 355358.97m/s
Hence the required orbital speed of the ice cube is 355,358m/s
Learn more on orbital speed here: https://brainly.com/question/22247460
#SPJ1
An internal explosion breaks an object, initially at rest, into two pieces: A and B. Piece A has 1.9 times the mass of piece B. The energy of 7900 J is released in the explosion.
a)Determine the kinetic energy of piece A after the explosion.
Express your answer to two significant figures and include the appropriate units.
b)Determine the kinetic energy of piece B after the explosion.
Express your answer to two significant figures and include the appropriate units.
Kinetic energy of pieces A and B are 2724 Joule and 5176 Joule respectively.
What is the relation between the masses of A and B?Let mass of piece A = MaMass of piece B = Mb
Velocities of pieces A and B are Va and Vb respectively.As per conservation of momentum,Ma×Va = Mb×Vb
Here, Ma=1.9MbSo, 1.9Mb × Va = Mb×Vb
=> 1.9Va = Vb
What are the kinetic energy of piece A and B?Expression of kinetic energy of piece A = 1/2 × Ma × Va²Kinetic energy of piece B = 1/2 × Mb × Vb²Total kinetic energy= 7900J=>1/2 × Ma × Va² + 1/2 × Mb × Vb² = 7900
=> 1/2 × Ma × Va² + 1/2 × (Ma/1.9) × (1.9Va)² = 7900
=> 1/2 × Ma × Va² ×(1+1.9) = 7900 j
=> 1/2 × Ma × Va² = 7900/2.9 = 2724 Joule
Kinetic energy of piece B = 7900 - 2724 = 5176 JouleThus, we can conclude that the kinetic energy of piece A and B are 2724 Joule and 5176 Joule respectively.
Learn more about the kinetic energy here:
brainly.com/question/25959744
#SPJ1
The resistivity of a 1.0 m long wire is 1.72 × 10-8 ωm and its cross sectional area is 2.0 × 10-6 m2. if the wire carries a current of 0.20 a, what is the voltage across the wire?
The voltage across the wire is 1.72 x [tex]10^{-3}[/tex] V
What does the Resistance of a wire depend on ?The resistance of a wire is the opposition to the flow of current. It depends on the following;
TemperatureLength of the wireCross sectional areaResistivity of the wireGiven that the resistivity of a 1.0 m long wire is 1.72 × 10-8 ωm and its cross sectional area is 2.0 × 10-6 m2. if the wire carries a current of 0.20A
The given parameters are;
Resistivity ρ = 1.72 × 10-8 ωm Length L = 1.0 mCross sectional area A = 2.0 × [tex]10^{-6}[/tex] m²Current I = 0.2 AResistance R = ?Voltage V = ?The formula to use to get R will be
R = ρL / A
Substitute all the necessary parameters into the formula
R = 1.72 x [tex]10^{-8}[/tex] x 1 / 2 x [tex]10^{-6}[/tex]
R = 8.6 x [tex]10^{-3}[/tex] Ω
From Ohm's law, V = IR
Substitute all the necessary parameters into the formula
V = 0.2 x 8.6 × [tex]10^{-3}[/tex]
V = 1.72 x [tex]10^{-3}[/tex] V
Therefore, the voltage across the wire is 1.72 x [tex]10^{-3}[/tex] V
Learn more about Resistance here: https://brainly.com/question/17563681
#SPJ1
3 A rocket of mass 1200 kg is travelling at 2000 m/s. It fires its engine for 1 minute. The forward thrust provided by the rocket engines is 10 kN (10 000 N).
(i) Use increase in momentum = F x t to calculate the increase in momentum of the rocket.
(ii) Use your answer to a to calculate the increase in velocity of the rocket and its new velocity after firing the engines.
The impulse shared by the object equals the difference in momentum of the object. In equation form,
F • t = m • Δ v. In a collision, objects experience an impulse; the impulse causes and is equal to the difference in momentum.
How to calculate thrust provided by the rocket engines is 10 kN (10 000 N).?
a)There is this impulse-momentum change equation.
[tex]where m$ is the mass of a body, $F$ is a force acting to the body, $t$ is time and $D E L A T A N\}=V_{2}-V_{1}$ is the change of velocity.We consider everything is happen along a straight line, and gravitation does not participate.So, the increase of momentum is $\mathrm{F}^{*} \mathrm{t}=10000 \mathrm{~N} * 60$ seconds $=600000 \mathrm{~N}^{*} \mathrm{~s}=600000\left(\mathrm{~kg}^{*} \mathrm{~m}\right)^{*} \mathrm{~s} / \mathrm{s}^{\wedge} 2=600000 \mathrm{~kg}{ }^{*} \mathrm{~m} / \mathrm{s}$.[/tex]
We consider everything exits happen along a straight line, and gravitation does not participate.
So, the increase of momentum is F×t = 10000 N × 60 seconds = 600000 N*s = 600000 (kg*m)*s/s^2 = 600000 kg*m/s.
[tex]$$\Delta(\mathrm{V})=\frac{\mathrm{F.t}}{\mathrm{m}}=\frac{600000}{1200}=500 \mathrm{~m} / \mathrm{s} .$$[/tex]
New velocity after engine was firing during 60 seconds is 2000 + 500 = 2500 m/s.
To learn more about Impulse-momentum, refer
https://brainly.com/question/20586658
#SPJ9
(refer to photos attached. Example of previous question with wrong/correct answers example, and current question needing to be solved)
Determine the electric field strength at a point 1.00 cm to the left of the middle charge shown in the figure below. (Enter the magnitude of the electric field only.) _____N/C
If a charge of −3.94 µC is placed at this point, what are the magnitude and direction of the force on it?
Magnitude _______N
Direction?
- toward the left
- upward
-downward
- toward the right
(a) The electric field strength at a point 1.00 cm to the left of the middle is 2.0 x 10⁷ N/C.
(b) The magnitude of the force is 94.4 N and direction of the force on it towards the left.
Electric field strengthThe electric field strength at a point 1.00 cm to the left of the middle is calculated as follows;
E = kq/r²
Electric field due to first chargeE1 = (9 x 10⁹ x 6 x 10⁻⁶)/(0.02)²
E1 = 1.35 x 10⁸ N/C
Electric field due to second chargeE2 = -(9 x 10⁹ x 1.5 x 10⁻⁶)/(0.01)²
E2 = - 1.35 x 10⁸ N/C
Electric field due to third chargeE3 = - (9 x 10⁹ x 2 x 10⁻⁶)/(0.03)²
E3 = -2.0 x 10⁷ N/C
Net electric fieldE = E1 + E2 + E3
E = +1.35 x 10⁸ N/C - 1.35 x 10⁸ N/C - (-2.0 x 10⁷ N/C)
E = +2.0 x 10⁷ N/C
Force on the charge −4.72 µCF = Eq
F = 2.0 x 10⁷ x -4.72 x 10⁻⁶
F = -94.4 N
Thus, the direction of the force will be towards the left.
Learn more about force on charge here: brainly.com/question/25923373
#SPJ1
If the velocity of an object is -8 m/s and its momentum is -32 kgm/s, what is its mass?
The revolution of the earth around the sun demonstrate what motion?
Answer:
Anticlockwise directions
Please mark me Brainliest to help me
Pilots can be tested for the stresses of flying high-speed jets in a whirling "human centrifuge," which takes 1.3 min to turn through 22 complete revolutions before reaching its final speed.
a)What was its angular acceleration (assumed constant)?
Express your answer using two significant figures.
b)What was its final angular speed in rpm ?
Express your answer using two significant figures
(a) The angular acceleration will be 26.035 rev/[tex]min^{2}[/tex].
(b) The final angular velocity is expected to be 33.846 rev/min.
Given.
t=1.3 min, Θ=22 rev, [tex]ω_{i}[/tex]=0
We know, Θ= [tex]ω_{i}[/tex]t+[tex]\frac{1}{2}[/tex][tex]\alpha[/tex][tex]t^{2}[/tex]
22=0+[tex]\frac{1}{2}[/tex][tex]\alpha[/tex][tex]1.3^{2}[/tex]
[tex]\alpha[/tex]=26.035 rev/[tex]min^{2}[/tex]
[tex]ω_{f} =ω_{i}+\alpha t[/tex]=0+26.035*1.3=33.846 rev/min
Angular velocityAn object's rate of change in angular position or orientation over time is depicted by its angular velocity, rotational velocity, or both ( or ), also known as the angular frequency vector (i.e. how quickly an object rotates or revolves relative to a point or axis). The direction of the pseudovector is normal to the instantaneous plane of rotation or angular displacement, and its magnitude denotes the angular speed, or the rate at which the item rotates or revolves. It is customary to use the right-hand rule to specify the direction of angular motion. A general definition of angular velocity is "angle per unit time" (angle replacing distance from linear velocity with time in common). Radians per second is how angles are measured in the SI.
Learn more about Angular velocity here:
https://brainly.com/question/13649539
#SPJ1
Three ropes A, B and C are tied together in one single knot K. (See figure.)
If the tension in rope A is 50.5 N, then what is the tension in rope B?
Assuming point K is held in equilibrium, by Newton's second law we have
• net horizontal force
[tex]F_C \cos\left(\tan^{-1}\left(\dfrac57\right)\right) - F_A = 0[/tex]
• net vertical force
[tex]F_C \sin\left(\tan^{-1}\left(\dfrac57\right)\right) - F_B = 0[/tex]
where the angle [tex]\theta[/tex] that rope C makes with the horizontal axis satisfies
[tex]\tan(\theta) = \dfrac{9-4}{11-4} = \dfrac57[/tex]
Solve the first equation for [tex]F_C[/tex].
[tex]F_C = F_A \sec\left(\tan^{-1}\left(\dfrac57\right)\right)[/tex]
(Recall that [tex]\sec(x)=\frac1{\cos(x)}[/tex].)
Substitute this into the second equation and solve for [tex]F_B[/tex].
[tex]F_B = F_C \sin\left(\tan^{-1}\left(\dfrac57\right)\right)[/tex]
[tex]F_B = F_A \sec\left(\tan^{-1}\left(\dfrac57\right)\right) \sin\left(\tan^{-1}\left(\dfrac57\right)\right)[/tex]
[tex]F_B = F_A \tan\left(\tan^{-1}\left(\dfrac57\right)\right)[/tex]
(Recall that [tex]\tan(x)=\frac{\sin(x)}{\cos(x)}[/tex].)
[tex]F_B = \dfrac57 F_A[/tex]
[tex]\boxed{F_B \approx 36.1\,\rm N}[/tex]
How much energy is needed to move an electron in a hydrogen atom from the ground state (n = 1) to n = 3?
The energy needed to move an electron in a hydrogenatome from the ground state (n=1) to n=3 will be 1.93 *10^-18J and 12.09 eV.
How to compute the value?The following can be deduced:
Energy of electron in hydrogen atom is
En = -13.6 /n2 eV
where n is principal quantum number of orbit.
Energy of electron in first orbit = E1 = -13.6 / 12 = - 13.6eV
Energy of electron in third orbit = E3 = -13.6 /32 = -1.51 eV
Energy required to move an electron fromfirst to thirdorbit ΔE = E3- E1
ΔE = -1.51 - ( 13.6) = 12.09 eV
Energy in Joule = 12.09 *l/× 1.6 × 10^-19 = 1.93 × 10^-18 J.
Learn more about energy on:
https://brainly.com/question/13881533
#SPJ1
Complete question:
How much energy is needed to move an electron in a hydrogenatome from the ground state (n=1) to n=3? Give theanswer (a) in joules and (b) in eV.
A stone of weight 10N falls from the top of a 250m high cliff. a) Calculate how much work is done by the force of gravity in pulling the stone to the foot of the cliff. b) How much energy is transferred to the stone?
Answer:
work done = ( force × displacement)
(a)The force acting on the block is it's self weight and displacement is equal to height of the tower.
work done by gravity = (250 × 10) = 2500 joule
(b) The work done by gravity 2500 joule is transferred to the object in the form of it's kinetic energy.
figue 1 shows a piece of elastic being stretched between 2 pieces of wood
When a piece of elastic material between two pieces of wood is being stretched beyond its limit, the elastic material or the object does not return to its original length when the force is removed
However, in physics, the type of stress applied when an elastic material is stretched is tensile stress.
Recall:
Stess is defined as force per unit area
Mathematically; Stress = F/A
What is elasticity?Elasticity can be defined as the ability of a deformed elastic material or body to return to its original size and shape when the forces causing the deformation are removed.
So therefore, when a piece of elastic material between two pieces of wood is being stretched beyond its limit, the elastic material or the object does not return to its original length when the force is removed
Complete question:
What happens when a piece of elastic material between two pieces of wood is being stretched beyond its limit?
Learn more about elasticity:
https://brainly.com/question/7694106
#SPJ1
You are designing a delivery ramp for crates containing exercise equipment. The 1390 N crates will move at 1.8 m/s at the top of a ramp that slopes downward at 22.0∘. The ramp exerts a 515 N kinetic friction force on each crate, and the maximum static friction force also has this value. Each crate will compress a spring at the bottom of the ramp and will come to rest after traveling a total distance of 5.0 m along the ramp. Once stopped, a crate must not rebound back up the ramp.
The maximum force constant of the spring Kmax is 2337.9 N/m.
What is force constant of a spring?The force constant or spring constant is defined as the force required to stretch or compress a spring such that the displacement in the spring is 1 meter.
Force constant is denoted by K and its unit is N/m.
Force = K * xWhere;
K = spring constant
x = displacement
The work done by the spring is given below as follows:
Work done = Fx/2
Kinetic Energy = mv²/2
Force on an inclined plane = mgsinθ
Total force, F = mgsinθ + frictional force
F = 1390 * sin 22° + 515
F = 1035.7 N
Work done = change in KE
Fx/2 = mv²/2
Fx = mv²
m = 1390/9.81 = 141.692
Solving for x;
x = mv²/F
x = 141.692 * 1.8²/1035.7
x = 0.443 m
The maximum force constant of the spring Kmax = 1035.7/0.443
Kmax = 2337.9 N/m
In conclusion, the maximum force constant of the spring is the ratio of the total force and displacement.
Learn more about force constant of a spring at: https://brainly.com/question/12253978
#SPJ1
Note that the complete question is given below:
You are designing a delivery ramp for crates containing exercise equipment. The crates of weight 1490 N will move with speed 2.0 m/s at the top of a ramp that slopes downward at an angle 21.0 ∘. The ramp will exert a 533 N force of kinetic friction on each crate, and the maximum force of static friction also has this value. At the bottom of the ramp, each crate will come to rest after compressing a spring a distance x. Each crate will move a total distance of 8.0 m along the ramp; this distance includes x. Once stopped, a crate must not rebound back up the ramp. Calculate the maximum force constant of the spring Kmax that can be used in order to meet the design criteria
ASAP NEED HELP !! :(
Why are temperatures more moderate around the fall and spring equinoxes?
C The angle at which Earth's axis tilts changes.
Neither end of Earth's axis is tilted toward the Sun.
The north end of Earth's axis is tilted toward the Sun.
C
The Earth briefly wobbles on its axis.
Answer:C is the answer
Explanation:
It is the most reasonable and the answer that makes most sense
Answer:
The angle at which Earth's axis tilts changes.
An Airbus A380-800 passenger airplane is cruising at constant altitude on a straight line with a constant speed. The total surface area of the two wings is 395 m^2. The average speed of the air just below the wings is 259 m/s, and it is 288 m/s just above the surface of the wings.
What is the mass of the airplane? (The average density of the air around the airplane is ρair = 1.21 kg/m^3.)
The mass of an airplane with two wings that are 395m2 in size and average wing surface speeds of 259 and 288 m/s is 387x 10^3 kg.
We need to be aware of the Bernoulli principle in order to determine the solution.
How can I determine an airplane's mass?According to the Bernoulli's principle, the total amount of pressure energy, kinetic energy, and potential energy in a streamlined flow of an incompressible, non-viscous fluid is constant.It can be stated as follows:[tex]P+\frac{1}{2}dv^2+ dgh = constant.[/tex] We substitute d for to represent density.
We've done that,[tex]V_1=259m/s\\V_2=288m/s\\A=395m^2\\d=1.21kg/m^3[/tex]
We compare the governing idea for the wing's bottom and upper surfaces to:[tex]P_1+\frac{1}{2}dV_1^2+dgh=P_2+ \frac{1}{2}dV_2^2+dgh\\P_1-P_2=\frac{1}{2}d(V_2^2-V_1^2)\\\frac{F}{A}= \frac{1}{2}d(V_2^2-V_1^2)\\[/tex]
Consequently, using the aforementioned equation, the airplane's mass will be,[tex]m=\frac{\frac{1}{2}d(V_2^2-V_1^2)A\\}{g} \\m=387*10^3kg.[/tex]
Consequently, we can say that the mass of an airplane with two wings that are 395m2 in size and average wing surface speeds of 259 and 288 m/s is 387 x 10^3 kg.
Learn more about the Bernoulli's principle here:
https://brainly.com/question/13098748
#SPJ1
How far would you push a car if you did 28,000J of work, exerting a force of 825N?
We push a car to the distance of 33.939m if we do 28000J work , exerting a force of 825N.
What is work done and force ?work done: The amount of energy transferred to a body .Force : force is an influence that can change the velocity of an object .How to calculate distance moved from work done and force ?we know ; work done =Force ×distance moved in the direction of force Mathematically, W=F.Swhere W= work doneF = applied force
S = distance moved
So S=W/F=28000J/825N
=33.939meter
Thus, we can conclude that the distance moved by the car is 33.939m.
Learn more about relation between work done and force applied here:
brainly.com/question/25573309
#SPJ1
Two uncharged spheres are separated by 1.70 m. If 2.40 ✕ 10¹² electrons are removed from one sphere and placed on the other, determine the magnitude of the Coulomb force (in N) on one of the spheres, treating the spheres as point charges.
_______N
**Hint** Find the net charge on each sphere and substitute values into Coulomb's law.
The magnitude of the Coulomb force (in N) on one of the spheres, given the data is 4.59×10⁻⁴ N
How to determine the charge on each spheresSphere 1 losses 2.40×10¹² electrons
But
1 electron = 1.6x10¯¹⁹ C
Thus,
Charge on sphere 1 = +1.6x10¯¹⁹ × 2.40×10¹² = +3.84×10¯⁷ C
Sphere 2 gains 2.40×10¹² electrons
But
1 electron = 1.6x10¯¹⁹ C
Thus,
Charge on sphere 2 = -1.6x10¯¹⁹ × 2.40×10¹² = -3.84×10¯⁷ C
How to determine the coulomb forceCharge on sphere 1 (q₁) = +3.84×10¯⁷ CCharge on sphere 2 (q₂) = 3.60 mC = -3.84×10¯⁷ CElectric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 1.7 mForce (F) =?
Using the Coulomb's law equation, the force can be obtained as illustrated below:
F = Kq₁q₂ / r²
F = (9×10⁹ × 3.84×10¯⁷ × 3.84×10¯⁷) / (1.7)²
F = 4.59×10⁻⁴ N
Thus, the magnitude of the Coulomb's force is 4.59×10⁻⁴ N
Learn more about Coulomb's law:
https://brainly.com/question/506926
#SPJ1
a man carries a hand bag by hanging on his hand moves horizantaly wher the bag does not up or down what is the work done on the bag
Since the displacement is completely perpendicular to the direction of the applied force, the work done on the bag is zero.
When is the Work done on an object ?The work is done on an object when the force applied is multiply by the distance moved by the object in the direction of the force applied.
Given that a man carries a hand bag by hanging on his hand moves horizontally where the bag does not up or down.
What is work if the displacement is not in the direction of force ?
The work done can only be zero if the displacement is perpendicular to the direction of force. otherwise, it will not be equal to zero.
Also, the work done will be zero, if the displacement is zero.
In the question above, the displacement is completely perpendicular to the direction of the applied force.
Therefore, the work done on the bag is zero.
Learn more about Work Done here: https://brainly.com/question/8119756
#SPJ1
a 30kg crate is pulled up a ramp 15m long and 2m high by a constant force of 100n. the crate starts from resta nd has a velocity of 2m/s when it reaches the ramp. what is the frictional force between the crate and the ramp. use the principal of conservation energy.
The frictional force between the crate and the ramp is determined as 35.2 N.
Energy lost to frictional forceApply the principle of conservation energy to calculate the change in the energy of the crate.
Change in energy of the crate = energy loss to friction
P.Ei - K.Ef = E
mgh - ¹/₂mv² = E
where;
m is mass of the crateh is vertical height traveled by the cratev is the final velocity of the crate(30)(9.8)(2) - (0.5)(30)(2²) = E
528 J = E
Frictional force between the crate and the rampE = Fd
where;
F is the frictional forced is the distance traveled by the crateF = E/d
F = (528)/(15)
F = 35.2 N
Thus, the frictional force between the crate and the ramp is determined as 35.2 N.
Learn more about frictional force here: https://brainly.com/question/4618599
#SPJ1
Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 1026 kg, and use an orbital radius of 3.00 x 105 km. (G = 6.67 × 10-11 N ∙ m2/kg2)
The orbital speed of an ice cube in the rings of saturn is approximately 3.56 * 10^6 m/s
What is law of gravitation?The law of gravitation states that the force of gravitation is directly proportional to the product of the masses and inversely proportional to the distance between the masses. Mathematically;
F = GMm/r²
where
M and m are the mass of ice cube and
Recall that;
s = Gm1/r^2
Also;
F = sm²
Substitute to have;
s = m²/F
For the centripetal acceleration
a = v²/r
Such that;
v²/r = Gm/r²
v² = Gm/r
v = √Gm/r
Substitute the given parameters into the formula to have:
V = √6.67×10^-11 * 5.68 x 10^26 / 3.00 x 10^5
V = 355358.97m/s = 3.56 * 10^6 m/s
Therefore the orbital speed of an ice cube in the rings of saturn is approximately 3.56 * 10^6 m/s
Learn more on orbital speed here: https://brainly.com/question/7260440
#SPJ1
why is the bulb of hydrometer is made heavier give two reasons
The reason behind the heavier hydrometer bulb is the sinking of hydrometer is inversely proportional to the density of hydrometer, hence hydrometers is made heavier.
We all know that hydrometers float in liquid hence to maintain the centre of gravity while floating the hydrometer is made heavier using lead shots.
Question 5 & 6 plissssssss
Question: 5
The length of the pendulum is 7.6 m.
What is the expression of length of a pendulum in term of time period?Time period of the pendulum (T) = 2π×√(L/g)L= length of pendulum, g = acceleration due to gravity on earthSo, L = T²g/4π²
What is the length of the pendulum, if the time period is 3.20 s and acceleration due to gravity becomes 3×g?T= 3.20 sL = (3.2²×3×9.8)/4π²= 7.6 m
Thus, we can conclude that the length of the pendulum is 7.6 m i.e option C is correct.
Learn more about the pendulum motion here:
brainly.com/question/15261645
#SPJ1
Question: 6
The object takes 2.55 seconds to reach the ground.
What is the expression of time taken to reach the earth surface by an object?From the conversation of energy, (1/2)mv²=mghSo, v=√(2gh)From Newtown's equation of motion, v=u+atHere, a= acceleration due to gravity which is gSo, √(2gh)=gtt= √(2h/g)
What is the time taken by an object dropped from 31 m to reach the ground?t= √(2×31/9.8)
= 2.55s
Thus, we can conclude that the option A is correct.
Learn more about the conversation of energy here:
brainly.com/question/24772394
#SPJ1
Which of the following statements are true about gravity? Check all that
apply.
A. Gravity exists between two objects that have mass.
B. Gravity exists in the whole universe.
C. Gravity doesn't exist between Earth and the sun.
D. Gravity is a force that pulls two objects together.
E. Gravity exists only on Earth.
SUBMIT
Answer:
Gravity exist between two objects that have mass
a trolley and a sandbag have a combined mass of 4 kg. a bullet with a mass of 150 gram is fired towards the trolley and is lodged in the sand bag immediately after the Collision, on the trolley and sandbag in combination with the bullet, move backwards at 53 metre per second calculate the kinetic energy of the trolley , with the sandbag and bullet ,directly after the Collision
The correct answer is 5828.675 J.
Given combined mass 4kg and mass of bullet 150gm=0.150kg.
Total mass= 4+0.150=4.150kg
Velocity=53 m/s
Kinetic energy = [tex]\frac{1}{2} *m*v^{2}[/tex] =0.5*4.150*[tex]53^{2}[/tex] =5828.675 J
Kinetic energyKinetic energy is a type of power that an item or particle possesses as a result of motion. When an item undergoes work—the transfer of energy—by being subjected to a net force, it accelerates and consequently obtains kinetic energy. A moving object or particle's kinetic energy, which depends on both mass and speed, is one of its characteristics. Any combination of motions, including translation (or travel along a path from one location to another), rotation about an axis, and vibration, may be used as the type of motion.
A body's translational kinetic energy is equal to [tex]\frac{1}{2} *m*v^{2}[/tex] , or one-half of the product of its mass, m, and square of its velocity, v.
a trolley and a sandbag have a combined mass of 4 kg. a bullet with a mass of 150 gram is fired towards the trolley and is lodged in the sand bag immediately after the Collision, on the trolley and sandbag in combination with the bullet, move backwards at 53 metre per second calculate the kinetic energy of the trolley , with the sandbag and bullet ,directly after the Collision
Learn more about kinetic energy here:
https://brainly.com/question/12669551
#SPJ1
"The acceleration due to gravity on the surface of the earth is 9.8 m/s ²." What does it mean?
Answer: It simply means that a freely falling object would increase its velocity by 9.8 m/s per second
Answer:
Hello!
"The acceleration due to gravity on the surface of the earth is 9.8 m/s ²." What does it means that
That every second an object is in free fall, gravity will cause the velocity of the object to increase 9.8 m/s. So, after one second, the object is traveling at 9.8 m/s.
What is an example of total internal reflection at work?
A.
A ray of light has the same intensity both entering and exiting a fiber optic cable.
B.
A ray of light entering a glass cube gets refracted.
C.
A ray of light in air hits a shiny surface and bounces off.
D.
A ray of light entering a ruby gets refracted.
Answer:
A i think...
Explanation:
Sorry if its wrong
The velocity of a body is given by the equation v= a + bx, where 'x' is displacement. The unit of b is .......
Answer:
s^ -1 ( or 1/sec)
Explanation:
Velocity is given in units of displacement / sec
like feet /sec or m/sec
so b would have units of s^-1
(or perhaps a more general term would be time^-1)
Which of the following is correct concerning the uncontrolled burn phase?
Group of answer choices
The uncontrolled burn phase is characterized by uncontrolled combustion in a cylinder until fuel accumulated during ignition delay is burned.
This is also called the flame propagation phase.
Many points in the combustion chamber will simultaneously reach the threshold values required for ignition, and multiple flame fronts will move through the air-fuel mixture.
(All three statements are correct.)
The option that is the correct one concerning the uncontrolled burn phase is:
The uncontrolled burn phase is characterized by uncontrolled combustion in a cylinder until fuel accumulated during ignition delay is burned.What is uncontrolled combustion?
Uncontrolled Combustion is known to be the the time and place in which a kind of an ignition will stop and it is said to be never fixed by anything in regards to the compression ignition engine as seen in SI engines.
Note that the four Stages of combustion are:
1. Pre-flame combustion
2. Uncontrolled combustion
3. Controlled combustion and
4. After burning
Hence, The uncontrolled burn phase is characterized by uncontrolled combustion in a cylinder until fuel accumulated during ignition delay is burned as all the fuel need to burn out.
Learn more about burn phase from
https://brainly.com/question/14414049
#SPJ1