The list below shows the height, in meters, of an ocean's first high tide for each of 6 days.
1.72 1.8 1.86 1.88 1.74 1.86
What is the mean height of the ocean's first high tide for the 6 days?
1.81 meters
1.83 meters
1.86 meters
1.87 meters

Answer: 3 loops

Step-by-step explanation: The loop is 1.2 miles, and the total walk is 3.6 miles. You want to find out how many laps are in the 3.6 miles. This can be found using division. 3.6/1.2= the number of 1.2 mile laps inside the 3.6 mile walk, which is 3 laps. hope this helped!

See attachment for the graph of the cosine function f(x) = 5 cos(π/2x) - 1

From the question, the given parameters are:

Amplitude, A = 5

Vertical shift, D = -1

Period, T = 4

A cosine function is represented as:

f(x) = A cos(B(x + C)) + D

Where

Amplitude = A

Period = T

Horizontal shift = C

Vertical shift = D

Since the horizontal shift is not stated in the question, we can assume that the horizontal shift is 0

i.e. C = 0

So, the equation of the cosine function becomes

f(x) = A cos(Bx) + D

Calculate the value of B using

B = 2π/T

So, we have:

B = 2π/4

Evaluate

B = π/2

So, we have:

f(x) = A cos(π/2x) + D

Substitute the known values of A and D in the above equation

f(x) = 5 cos(π/2x) - 1

Next, we plot the graph of the cosine function on a graphing tool

See attachment for the graph of the cosine function f(x) = 5 cos(π/2x) - 1

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**Disclaimer** Hi there! I assumed the question is to represent W in terms of all other variables (P, L). The following answer corresponds to this understanding. If it is incorrect, please let me know and I will modify my answer.

Answer: W = (P/2) - L

Step-by-step explanation:

Given equation

P = 2L + 2W

Factorize 2 out

P = 2 (L + W)

Divide 2 on both sides

P / 2 = 2 (L + W) / 2

P / 2 = L + W

Subtract L on both sides

(P / 2) - L = L + W - L

[tex]\Large\boxed{W=\frac{P}{2} -L}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

[tex]\displaystyle{W = \dfrac{P}{2} - L}[/tex]

Step-by-step explanation:

To solve for W, we have to isolate the W-variable. First, we can factor the expression 2L + 2W to 2(L+W):

[tex]\displaystyle{P = 2(L+W)}[/tex]

Next, we'll be dividing both sides by 2:

[tex]\displaystyle{\dfrac{P}{2} = \dfrac{2(L+W)}{2}}\\\\\displaystyle{\dfrac{P}{2} = L+W}[/tex]

Then subtract both sides by L:

[tex]\displaystyle{\dfrac{P}{2} - L= L+W-L}\\\\\displaystyle{\dfrac{P}{2} - L= W}[/tex]

Therefore, we'll obtain W = P/2 - L.

Note that the given formula is perimeter formula of a rectangle where Perimeter = 2 * Length + 2 * Width.

So if we solve for W (Width) then we'll get Width = Perimeter / 2 - Length which can be useful to find width with given perimeter and length.

Answer:

one of several possible solutions :

18, 75, 105

Step-by-step explanation:

prime factors of 3150 :

3150 ÷ 2 = 1575

1575 ÷ 2 no

1575 ÷ 3 = 525

525 ÷ 3 = 175

175 ÷ 3 no

175 ÷ 5 = 35

35 ÷ 5 = 7

7 ÷ 5 no

7 ÷ 7 = 1

3150 = 2¹ × 3² × 5² × 7¹

these are the product of the longest streaks of prime factors in x, y and z.

the GCF(y, z) = 15.

the prime factors of 15 are simply 3¹×5¹.

so, y and z share only the factors 3 and 5.

the GCF(x, y, z) = 3.

since x is an even number, the elimination of 5 in the GCF is not surprising.

let's try the following :

x = 2¹ × 3² = 2×9 = 18

y = 3¹ × 5² = 3×25 = 75

z = 3¹ × 5¹ × 7¹ = 3×5×7 = 105

that uses all the factors of 3150, and their LCM is as the product of the longest streaks of their prime factors is

2¹ × 3² × 5² × 7¹.

fits.

the GCF(75, 105) is the product of the prime factors they have in common : 3¹ × 5¹ = 15.

fits.

the GCF(18, 75, 105) is the product of the prime factors ask 3 numbers have in common, which is only 3¹ = 3.

fits.

18 < 75 < 105

fits.

18 is an even number greater than 10.

fits.

there are more than 1 solutions.

e.g.

z = 2¹ × 3¹ × 5¹ × 7¹ = 210

is also possible.

The direct variation function is y = 0.3x

The direct variation from y to x is represented as:

y = kx

When y = 1.5 and x = 5, we have

1.5 = 5k

Divide by 5

k = 0.3

Substitute k = 0.3 in y = kx

y = 0.3x

Hence, the direct variation function is y = 0.3x

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The size of the second application given the size of the first application and the expression ( x - 3.45 mb) for the size of the second application is 293.55 MB.

Let

For instance,

if the size of the first application is 297 MB

Size of the second application= x - 3.45 mb

= 297 MB - 3.45 MB

= 293.55 MB

Therefore, the size of the second application given the size of the first application and the expression for the size of the second application is 293.55 MB

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Area equals Length times Width.

since the width of this equation is 5 units Longer then its Length

W = L + 5

To put this area in a equation we could say

L(L+5)=A
Simplify the equation, L^2 + 5L = A.

The cost to rent each chair is $1.5 and cost to rent each table is $6.5

From the question, we are to determine the cost to rent each chair and each table

Let c represent chair

and

t represent table

From the given information,

The total cost to rent 5 chairs and 3 tables is $27

That is,

5c + 3t = 27 ------------ (1)

Also,

The total cost to rent 2 chairs and 12 tables is $81

That is,

2c + 12t = 81 ---------- (2)

Now, solve the equations simultaneously

5c + 3t = 27 ------------ (1)

2c + 12t = 81 ---------- (2)

Multiply equation (1) by 2 and multiply equation (2) by 5

2 × [5c + 3t = 27 ]

5 × [2c + 12t = 81 ]

10c + 6t = 54        ------------- (3)

10c + 60t = 405   ------------- (4)

Subtract equation (4) from equation (3)

10c + 6t = 54        

10c + 60t = 405

---------------------------

-54t = -351

t = -351/-54

t = 6.5

Substitute the value of t into equation (2)
2c + 12t = 81

2c + 12(6.5) = 81

2c + 78 = 81

2c = 81 - 78

2c = 3

c = 3/2

c = 1.5

∴ The cost of chair is $1.5 and cost of table is $6.5

Hence, the cost to rent each chair is $1.5 and cost to rent each table is $6.5

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The price elasticity of demand of the pen will be -0.2.

The demand and supply schedule will be:

Price Qd. Qs

$10. 250. 100

$20. 200. 90

$30. 180. 80

The price elasticity of demand from $1 to $2 will be:

= Percentage change in quantity demanded/percentage change in price

Percentage change in quantity demanded will be:

= (200 - 250)/250 × 100

= -20%

Percentage change in price will be:

= (20 - 10)/10 × 100

= 100%

Therefore, the elasticity of demand will be:

= -20/100

= - 0.2

The value gotten illustrates an inelastic demand.

In order to increase the total revenue, the price can be reduced as it will lead to more sales.

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Complete question:

Choose any product or service. Create the demand and supply schedule.

Calculate just one PED.

Is the demand elastic or inelastic?

What price change would you recommend to increase TR?

Proportionately, if they do half and half of 50% and 80% of the two bags, Bob is correct.

A proportion is a mathematical measure that compares two variables or numbers.

Proportions can be stated in percentages or ratios, as decimals or fractions.

Content of 16-ounce bag of nuts = 60% chocolate-covered nuts

Content of first bag = 50/50 plain and chocolate-covered nuts

Content of second bag = 80% chocolate-covered nuts

A mixture of half of 50% bag with half of 80% bag will result in 65% (50% + 80%)/2.

Thus, since the promise for each 16-ounce bag is for at least 60% chocolate-covered nuts, Bob is correct.

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Is Bob correct?

The conclusion that can be made based on the hypothesis is:

1. It's a valid conclusion.

2. It is a valid conclusion.

3. It is a valid conclusion.

According to the law of detachment, when the conditional and the hypothesis are true, the conclusion will be true.

Therefore, if 6x < 42, the value of x will also be less than 6. This is valid.

When an angle is more than 90°, it's an obtuse angle and since A is 103°, it's valid.

Also, the statement about the violin being a string instrument is logically valid.

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Check the picture below.

The odds in favor of them winning is 20%

From the information given, we have that the probability of them winning the next game is 80%

P( winning) = 80% = 0. 8

The odds against them winning is given as;

1 - probability of winning

We have;

= 1 - 0. 8

= 0. 2

The odds in favor of them winning is simply the probability of them losing;

= 0. 2 × 100

= 20%

Thus, the odds in favor of them winning is 20%

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[tex]y = 5x \\ switch \: y \: and \: x \\ x = 5y \\ solve \: for \:y \\ y = \frac{x}{5} [/tex]

Answer:

yes dear u need not to pay before viewing answer

You should at least answer 1 question to view the answers.

Answer:20.00

Step-by-step explanation: next time include the table but i managed to find it anyway

Step-by-step explanation:

this just means that the first function with input value x = 0 is calculated. that result becomes the input value x for the second function. and that result becomes the input value x for the 3rd function. and that result is then our result.

to answer a and b we only need to look at the main operation of each function :

the first one uses only basic multiplication and subtraction.

the second one uses squaring.

the third one is a 1/x operation.

a.

since the final result is a negative number (-31), the second function with the square operation cannot be last.

because a square operation always delivers a positive result.

+a × +a = +a²

-a × -a = +a²

remember, for a square operation we multiply the same number by itself. therefore we cannot mix signs like -a × +a, because then they would not be the same numbers anymore.

b.

since the initial input value is 0, the third function (1/x) cannot be the first, because 1/0 is not defined.

c.

because of the "large" -32 term in the first function I guess that this will be the last one to create such a low negative result of -31.

since 1/x cannot be first, (x - 2)² is then first. that makes 1/x second, and (4x - 32) third, as mentioned.

let's try :

x = 0

(x - 2)² = (0 - 2)² = (-2)² = 4

x = 4

1/x = 1/4

x = 1/4

4x - 32 = 4×1/4 - 32 = 1 - 32 = -31

hurrah ! we are correct !

Using the normal distribution, there is a 0.2076 = 20.76% probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3%.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The proportion estimate and the sample size are given as follows:

p = 0.45, n = 437.

Hence the mean and the standard error are:

The probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3% is 2 multiplied by the p-value of Z when X = 0.45 - 0.03 = 0.42.

Hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem:

[tex]Z = \frac{X - \mu}{s}[/tex]

Z = (0.42 - 0.45)/0.0238

Z = -1.26

Z = -1.26 has a p-value of 0.1038.

2 x 0.1038 = 0.2076.

0.2076 = 20.76% probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3%.

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The most suitable measurements for a box with a square base are 5cm (width) x 5cm (length) x 640cm (height). This box would be worth $4875

To find the minimum value of a box that must have a square base and 16000 cm³, we must try different measurements to find the variable that represents the least value.

In this case, the variable that represents less value is a base of 5cm x 5cm and a height of 640cm. This means that the box would be worth $4875 as shown below.

Base

Sides

Additionally, we can check that the volume of the box is the required 16000cm³, as shown below:

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Answer: 1

Step-by-step explanation:  It's subtraction and add ion look at the right side

Answer:

x+(x+5)=28

Step-by-step explanation:

girls(g)should be equal to x

boys(b) will therefore be x+5

x+(x+5)=28

Solving a system of equations, we can see that:

Let's define the variables:

With the given information, we can write:

P*8h = D

C*7h = D

C = 2*P - 144mi/h

So we have a system of 3 equations, where D is the distance in the problem.

With the first and second equations we can write:

P*8h = D = C*7h

Isolating P, we get:

P = C*(7/8)

Now we can replace that in the last equation:

C = 2*P - 144mi/h

C = 2*C*(7/8) - 144mi/h

And now we can solve that for C.

C - 2*(7/8)*C = - 144mi/h

C*(1 - 14/8) = -144mi/h

C*(8/8 - 14/8) = - 144mi/h

C*(6/8) = 144mi/h

C = (8/6)*144mi/h = 192mi/h

Now that we know the speed of the commercial jet, we can find the speed of the private jet.

P = C*(7/8) = 192mi/h*(7/8) = 168 mi/h

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answer

is true statement w= 4

The possible values of X for this game are 0, 1, 2, 3, 4.......n, where n ≥ 1

From the complete question, we understand that Mr. A wants to plays the game until he wins

This means that

He might win at the first game and he might win after n attempts

So, the values of X are

X = 0, 1, 2, 3, 4.......n

Hence, the possible values of X for this game are 0, 1, 2, 3, 4.......n, where n ≥ 1

The probability of x is represented as:

P(x) = nCx * p^x * (1 - p)^(n-x)

So, the probability that X = n is:

P(n) = nCn * p^n * (1 - p)^(n - n)

Evaluate the exponent

P(n) = nCn * p^n * 1

Evaluate the combination expression

P(n) = 1 * p^n * 1

This gives

P(n) = p^n

Hence, the probability that X = n is p^n

The distribution satisfies PMF conditions because

The expected value E(x) is calculated using

E(x) = n * p

So, we have:

E(x) = np

Hence, the value of E(x) is np

The variance V(x) is calculated using

V(x) = √n * p * (1 - p)

So, we have:

V(x) = √np(1 - p)

Hence, the value of V(x) is √np(1 - p)

The memoryless property of X is that each probability of X is independent

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Answer:

Step-by-step explanation:

slope-- 1/2

y intercept-- -4

Answer:

26 units^2

Step-by-step explanation:

the area of a kite is (d1 * d2)/2

d1 = 2 + 2 = 4

d2 = 6 + 7 = 13

4 * 13 = 52

52 / 6 = 26

26 units^2 is your answer

Answer: 26

Step-by-step explanation:

Angle HEJ measures 15 degrees.

If the height of ball is shown by h(t)=52t-16[tex]t^{2}[/tex] then the ball will reach after 1.625 seconds.

Given that height in t seconds is shown by h(t)=52t-16[tex]t^{2}[/tex].

We are required to find the time after which the ball will attain its maximum height.

The maximum height is the y coordinate of vertex of the parabola. Then we can use the following value of t.

h(t)=52t-16[tex]t^{2}[/tex]

Differentiate with respect to t.

dh/dt=52-32t

Again differentiate with respect to t.

[tex]d^{2}h/dt^{2}[/tex]=-32t

Because tim cannot be negative means the height is maximum.

Put dh/dt=0

52-32t=0

-32t=-52

t=52/32

t=1.625

Hence if the height of ball is shown by h(t)=52t-16[tex]t^{2}[/tex] then the ball will reach after 1.625 seconds.

Question is incomplete as the right and complete equation is

h(t)=52t-16[tex]t^{2}[/tex] .

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Hi :)

I'd start by adding 5 to both sides of the equation. That would make the equation easier.

[tex]\boldsymbol{\sqrt{2x}-5=3}}[/tex]

[tex]\boldsymbol{\sqrt{2x}=2}[/tex]

The next step is to get rid of the radical sign.

Which operation will undo the square root? Squaring.

So that's why we square both sides:

[tex]\boldsymbol{2x=4}[/tex]

And Now we just divide both sides by 2

[tex]\boldsymbol{x=2}[/tex]

~[tex]\textit{\textbf{Learn More; Work Harder}}[/tex]~

:)