the graph of y=-3x+ 2 is:

I've done it on the attached pages.

I hope this helps you...

There are some ways by which move the steps from sequence and series method like

Move the medium desk to the left peg. Move the small desk to the left peg. Move the large desk to the right peg. With the small disc to the middle peg. Move the middle desk to the right peg. With the small desk to the right peg.

According to the statement

we have to explain the moving steps to change the position of the given three disk from one peg to another.

So, for the solution of this problem

Firstly we know that the sequence and series

An itemized collection of elements in which repetitions of any sort are allowed is known as a sequence, whereas series is the sum of all elements.

we have to use the sequence and series method.

So, according to this method

Move the medium desk to the left peg. Move the small desk to the left peg. Move the large desk to the right peg. With the small disc to the middle peg. Move the middle desk to the right peg. With the small desk to the right peg.

So, there are some ways by which move the steps from sequence and series method like

Move the medium desk to the left peg. Move the small desk to the left peg. Move the large desk to the right peg. With the small disc to the middle peg. Move the middle desk to the right peg. With the small desk to the right peg.

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Charles' weight = Edith's weight + 20% of Edith's weight

We'll use a variable to represent Edith's weight, x.

The decimal form of 20% is 0.2.

60 = x + 0.2x

60 = 1.2x

x = 50

Edith's weight is 50kg.

Hope this helps!

Answer:

  8

Step-by-step explanation:

The four angles formed at each intersection of lines are all 90°.

The total number of 90° angles at the two intersections is 2×4 = 8 90° angles.

You can use the well-known binomial series,

[tex]\displaystyle (1+x)^\alpha = \sum_{k=0}^\infty \binom \alpha k x^k[/tex]

where

[tex]\dbinom \alpha k = \dfrac{\alpha(\alpha-1)(\alpha-2)\cdots(\alpha-(k-1))}{k!} \text{ and } \dbinom \alpha0 = 1[/tex]

Let [tex]\alpha=\frac12[/tex] and replace [tex]x[/tex] with [tex]3x[/tex]; then the series expansion is

[tex]\displaystyle (1+3x)^{1/2} = \sum_{k=0}^\infty \binom{\frac12}k (3x)^k[/tex]

and the first 4 terms in the expansion are

[tex]\sqrt{1+3x} \approx 1 + \dfrac{\frac12}{1!}(3x) + \dfrac{\frac12\cdot\left(-\frac12\right)}{2!}(3x)^2 + \dfrac{\frac12\cdot\left(-\frac12\right)\cdot\left(-\frac32\right)}{3!}(3x)^3[/tex]

which simplify to

[tex]\sqrt{1+3x} \approx \boxed{1 + \dfrac32 x - \dfrac98 x^2 + \dfrac{27}{16} x^3}[/tex]

You can also use the standard Maclaurin coefficient derivation by differentiating [tex]f[/tex] a few times.

[tex]f(x) = (1+3x)^{1/2} \implies f(0) = 1[/tex]

[tex]f'(x) = \dfrac32 (1+3x)^{-1/2} \implies f'(0) = \dfrac32[/tex]

[tex]f''(x) = -\dfrac94 (1+3x)^{-3/2} \implies f''(0) = -\dfrac94[/tex]

[tex]f'''(x) = \dfrac{81}8 (1+3x)^{-5/2} \implies f'''(0) = \dfrac{81}8[/tex]

Then the 3rd order Maclaurin polynomial is the same as before,

[tex]\sqrt{1+3x} \approx f(0) + \dfrac{f'(0)}{1!} x + \dfrac{f''(0)}{2!} x^2 + \dfrac{f'''(0)}{3!} x^3 = 1 + \dfrac32 x - \dfrac98 x^2 + \dfrac{27}{16} x^3[/tex]

Now,

[tex]\sqrt{1.3} = \sqrt{1+3x} \bigg|_{x=\frac1{10}} \\\\ ~~~~~~~~ \approx 1 + \dfrac32 \left(\dfrac1{10}\right) - \dfrac98 \left(\dfrac1{10}\right)^2 + \dfrac{27}{16} \left(\dfrac1{10}\right)^3 \\\\ ~~~~~~~~ = \dfrac{18,247}{16,000} \approx \boxed{1.14044}[/tex]

Compare to the actual value which is closer to 1.14018.

[tex]\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}[/tex] is the maclaurin polynomial and estimate value of [tex]\sqrt{1.3}[/tex] is 1.14. This can be obtained by using the formula to find the maclaurin polynomial.

Given the polynomial,

[tex]f(x)=\sqrt{1+3x}=(1+3x)^{\frac{1}{2} }[/tex]

The formula to find the maclaurin polynomial,

[tex]f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}[/tex]

Next we have to find f'(x), f''(x) and f'''(x),

By putting x = 0 , we get,

Therefore the maclaurin polynomial by using the formula will be,

[tex]\sqrt{1+3x}=f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}[/tex]

[tex]\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}[/tex]

To find the value of [tex]\sqrt{1.3}[/tex]  we can use the maclaurin polynomial,

[tex]\sqrt{1.3}[/tex] is  [tex]\sqrt{1+3x}[/tex] with x = 1/10,

[tex]\sqrt{1+3(1/10)}=1+\frac{3}{2} (1/10)-\frac{9}{8} (1/10)^{2} + \frac{81}{8}(1/10)^{3}[/tex]

[tex]\sqrt{1+3(1/10)}=\frac{18247}{16000} = 1.14[/tex]

Hence [tex]\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}[/tex] is the maclaurin polynomial and estimate value of [tex]\sqrt{1.3}[/tex] is 1.14.

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In triangle XYZ, angle X Z Y is a right angle. The length of Z X is b, the length of Z Y is a, and the length of hypotenuse X Y is c. Then, the side XZ which is the perpendicular, is opposite to ∠Y. Side XZ is adjacent to the ∠Y, and side ZY, which is the base, is also adjacent to ∠Y. We can say that ∠Y has been formed by the sides XZ and ZY.

It is given that,

In triangle X Y Z, angle X Z Y is a right angle or 90°.

The length of the hypotenuse XY is c.

⇒ The side with length c is adjacent to ∠Y.

The sides XZ and ZY form the right angle, thus one is base and the other is perpendicular.

Now, in relation to ∠Y, side ZY of length a is the base (adjacent to angle Y)

Similarly, side XZ of length b forms the perpendicular and is opposite to ∠Y.

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The number of people that have watched the video is 858 people

A function is a mathematic rule. We know that a function shows the rule that is to  be carried out and is often written in the form of an equation.

Now we have the function shown as; f(x) = 33(1.3)x. Since we know that the term x is referred as the number of days the video has been online.

Thus,  f(x) = 33(1.3)(20) thus we can now say that the number of people who have vied the video in twenty days is 858 people.

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Answer: the answer is B or 858

Step-by-step explanation: The answer is B or 858

Answer:

2/6

Step-by-step explanation:

Count up and over going from one point to the next and you get slope intercept. This one is up 2 over 6

Answer:

y = 1/3x - 3

Step-by-step explanation:

Slope-intercept form follows the format y = mx + b, where m is the slope of the line, and b is the y-intercept.

First let's find the slope. The slope is the amount the graph rises/runs. From point (0,-3), it rises by 1, and runs to the right by 3 where it meets the next point on the graph, meaning that the slope is 1/3.

Now, let's find the y-intercept. The y-intercept is the point on the graph where the line touches the y-axis. In this line, we can clearly see that the line touches (0,-3), therefore, the y-intercept is -3.

Using this information, we can construct the equation y = 1/3x - 3

His average rate of speed for the entire trip is 12.8 miles per hour.

Marty's speed is =V

[tex]\frac{3}{4} V+\frac{1}{2} V=8*2[/tex]

         [tex]\frac{5}{4} V=16[/tex]

           [tex]V=12.8[/tex]

The average rate of speed for the entire trip is 12.8 miles per hour.

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Answer:

D

Step-by-step explanation:

the figure is composed of a rectangle and a right triangle ( top )

calculate the hypotenuse h of the right triangle using Pythagoras' identity

h² = 6² + 8² = 36 + 64 = 100 ( take square root of both sides )

h = [tex]\sqrt{100}[/tex] = 10

the base of the rectangle is equal to h , then perimeter (P) of pentagon is

P = 10 + 4 + 6 + 8 + 4 = 32 cm

Hello and Good Morning/Afternoon:

Let's take this problem step-by-step:

What does the problem want:

 ⇒ the dimensions or the perimeter of the pentagon

What information do we need to find the perimeter:

 ⇒ the unknown side length

Let's find the unknown side length:    

[tex]\hookrightarrow \text{split the pentagon into two shapes as shown in the image below}\\\hookrightarrow \text{the hypotenuse of the right triangle is equal to the length of the unknown side}\\\hookrightarrow\text{hypotenuse}=\sqrt{6^2+8^2}= \sqrt{36+64}=\sqrt{100}=10\\[/tex][tex]\hookrightarrow \text{the unknown side length is 10}[/tex]

Perimeter = 6 + 8 + 4 + 4 + 10 = 32

Answer: 32 or (D)

Hope that helps!

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Answer:

[tex]x=6[/tex]
[tex]y=\frac{3}{4}[/tex]

Step-by-step explanation:

Given the following question:

[tex]x+4y=9[/tex]
[tex]2x-4y=9[/tex]

To solve using the elimination method we will add the two equations together to find the two individual values.

[tex]x+2x=3x[/tex]
[tex]4y-4y=0[/tex]
[tex]9+9=18[/tex]
[tex]3x=18[/tex]
[tex]\frac{3x}{3} =x[/tex]
[tex]18\div3=6[/tex]
[tex]x=6[/tex]

[tex]x+4y=9[/tex]
Substitute six in for x:
[tex]x=6[/tex]
[tex]6+4y=9[/tex]
Solve for y:
[tex]6-6=0[/tex]
[tex]9-6=3[/tex]
[tex]\frac{4y}{4} =y[/tex]
[tex]3=\frac{3}{4}[/tex]
[tex]y=\frac{3}{4}[/tex]

x is equal to 6, and y is equal to 3/4.

Hope this helps.

The simplified expression of 2√8x³(3√10x⁴ - x√5x²) is 24x³√5x  - 4x³√10x

The complete question is added as an attachment

From the attached figure, the product expression is:

2√8x³(3√10x⁴ - x√5x²)

Evaluate the exponents

2√8x³(3√10x⁴ - x√5x²) =  2 *2x√2x(3x²√10 - x²√5)

Evaluate the products

2√8x³(3√10x⁴ - x√5x²) =  4x√2x(3x²√10 - x²√5)

Open the bracket

2√8x³(3√10x⁴ - x√5x²) =  12x³√20x  - 4x³√10x

Evaluate the exponents

2√8x³(3√10x⁴ - x√5x²) = 24x³√5x  - 4x³√10x

Hence, the simplified expression of 2√8x³(3√10x⁴ - x√5x²) is 24x³√5x  - 4x³√10x

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Answer:

Second option

Step-by-step explanation:

edge

Answer:

d - 18

Step-by-step explanation:

The question said to use d as the variable. We do not know the number of dollars Paul owes. So we put d for that amount.

Then "minus" means to subtract 18.

Writing the expression is all that is being asked for. Translating the words into algebra. We aren't solving anything. Not even writing an entire equation, just an expression, so it has no equals sign.

The probability that the squad will have exactly two male members is; 0.0816

We are given;

Total number of people in cheerleading squad = 13

Number of Men = 8

Number of Women = 5

We are told that a 6 member squad is selected and now we want to find the probability that the squad will have exactly two male members.

Thus;

P(exactly 2 male members) = (8C2 * 5C4)/(13C6)

P(exactly 2 male members) = 140/1716

P(exactly 2 male members) = 0.0816

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The point which is indicated in the task content; (1, 2) represents; parking costs $2 per hour for the entire day.

What is the interpretation of the point given in the task content; (1,2)?

It follows from convention that the coordinate systems are structured such that the independent variable, x be placed 1st and the dependent variable, y be placed second.

Consequently, since the cost of parking is dependent on the time for which the car is parked, then, it represents parking costs 2 per hour for the entire day.

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The amount spent by Seedevi is $66

From the question, the given parameters are:

Seedevi = half as much money as Georgia,

Seedevi = $6 more than Amy

The three of them = $258

To solve this question, we use the following representations

x = Seedevi

y = Georgia

z = Amy

So, we have the following equations

x = 0.5y

x = 6 + z

x + y + z = 258

Make y and z the subjects

y = 2x

z = x - 6

Substitute y = 2x and z = x - 6 in x + y + z = 258

x + 2x + x - 6 = 258

Evaluate the like terms

4x = 264

Divide by 4

x = 66

Hence, the amount spent by Seedevi is $66

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[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textsf{Equation:}[/tex]

[tex]\mathsf{2[(8 \div 4)-(-5)] + 6}[/tex]

[tex]\huge\textsf{Solving:}[/tex]

[tex]\mathsf{2[(8 \div 4)-(-5)] + 6}[/tex]

[tex]\mathsf{= 2[((2 - (-5)] + 6}[/tex]

[tex]\mathsf{= 2(7) + 6}[/tex]

[tex]\mathsf{= 2 \times 7 + 6}[/tex]

[tex]\mathsf{= 14 + 6}[/tex]

[tex]\mathsf{= 20}[/tex]

[tex]\huge\textbf{Therefore, your answer should be: }[/tex]

[tex]\huge\boxed{\frak{20}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]

▪ [tex] \sf{2[(8 ÷ 4)-(-5)] + 6}[/tex]

First, we will start with the division:

[tex]\longrightarrow \sf{2[(2) − (−5)] +6}[/tex]

Now we will resolve what is inside the bracket:

[tex]\longrightarrow \sf{2[2+5] +6}[/tex]

[tex]\longrightarrow \sf{2 \times 7 +6}[/tex]

Now we will solve the multiplication:

[tex]\longrightarrow \sf{14 +6= 20}[/tex]

[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]

[tex] \bm{2[(8 ÷ 4)-(-5)] + 6 = \boxed{\bm {20}}}[/tex]

Answer:

47/100

Step-by-step explanation:

First you have to make the denominators equal.

4/10 * 10/10 = 40/100

40/100 + 7/100 = 47/100

Answer:

-3

Step-by-step explanation:

(-3, -1), (-5, 5)

Each point is (x, y).

slope = (difference in y)/(difference in x)

slope = (-1 - 5)/(-3 - (-5)) = -6/(-3 + 5) = -6/2 = -3

The slope is -3

Apply the exponent rule (x^a)^b= x^ab.

(b^9)^3= b^9*3= b^27

The length of the sides,MD, DK, and KM gives the measure of the angle m<D as c) 76°

In triangle ∆MDK, we have;

m = 16.4

d = 22

k = 19

Using cosine rule, we get;

d² = m² + k² - 2•m•k•cos(D)

Therefore;

2•m•k•cos(D) = m² + k² - d²

[tex]D = arccos \left( \frac{ {m}^{2} + {k}^{2} - {d}^{2} }{2 \cdot m \cdot k} \right)[/tex]

Which gives;

[tex]D = arccos \left( \frac{ {16.4}^{2} + {19}^{2} - {22}^{2} }{2 \times 16.4 \times 19} \right) \approx {76}^{ \circ} [/tex]

The correct option is therefore;

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Answer:

76

Step-by-step explanation:

Use the Law of Cosines to find m∠D

.The figure shows the same triangle as in the beginning of the task. Angle M D K is highlighted in red.

Set up the equation for the Law of Cosines.

d2=k2+m2−2kmcosD

Substitute the given values and solve for m∠D

.222=192+16.42−2(19)(16.4)cosD

Simplify.

484=629.96−623.2cosD

Subtract 629.96

.−145.96=−623.2cosD

Divide by −623.2

0.234=cosD

Use the inverse cosine function to find m∠D

and round to the nearest degree.

The figure shows a screen of a graphical calculator. The inverse cosine of 0 point 2 3 4 is calculated. The result is 76 point 4 6 7 3 1 6 4 6.

m∠D=cos−1(0.234)≈76∘

Therefore, m∠D≈76∘

hope it helps you!

.

Answer: C = 97.34 inches

Step-by-step explanation:

C = πd

= 3.14(31)

= 97.34

Answer:

Step-by-step explanation:

The first three terms of the arithmetic sequence for the number of words written are 10010, 9760, 9510. These have a common difference of 9760-10010 = -250. The first term and common difference can be used to make the explicit equation for the words written on the n-th day.

The explicit formula for the n-th term of an arithmetic sequence with first term a₁ and common difference d is ...

  [tex]a_n=a_1+d(n-1)[/tex]

For first term a₁ = 10010 and common difference d = -250, the explicit rule is ...

  [tex]a_n=10010-250(n-1)[/tex]

On day 14, n=14, and the number of words written is ...

  [tex]a_{14}=10010-250(14-1)\\\\a_{14}=10010-250(13)=10010-3250\\\\a_{14}=6760[/tex]

The writer would write 6760 words on the 14th day.

Answer:

Area = 113.04 in^2

Step-by-step explanation:

you have the diameter which is twice the radius, the formula is in the question:

Area = πr^2

so

12: 2 = 6 (RADIUS)  

Area = π6 ^ 2 =

Area = π 36 in^2

Area = 3.14 * 36

Area = 113.04 in^2

Answer:

3/4 or 75%

Step-by-step explanation:

Falcons scored 3 and Hawks scored 1, so in total 4 points were scored during the game. Falcons scored 3 out of 4 points, so they scored 3/4 of the points scored in the game.

To convert 3/4 to percentage, divide 3 by 4, multiply the quotient (result after division calculation) by 100, and add % sign after the number.

3/4 = 0.75

Therefore 3/4 is equivalent to 75%.

Answer:

[tex] \frac{3}{4} [/tex]

[tex]75\%[/tex]

Step-by-step explanation:

From the information given from the question, we can deduce:

Total goals scored by both teams = 3 + 1 = 4

Fraction of Goals Scored by Falcons =

[tex] \frac{goals \: scored \: by \: falcons}{total \: goals \: scored \: by \: both \: teams} \\ = \frac{3}{4} [/tex]

To get the percentage, we have to make sure the denominator is 100.

[tex] \frac{3}{4} \\ = \frac{3 \times 25}{4 \times 25} \\ = \frac{75}{100} \\ = 75\%[/tex]

Answer:

[tex]a.(fog)(x) = 7x + 7 \\ b.(gof)(x) = 7x + 1 \\ c.(fog)(4) = 35 \\ d.(gof)(4) = 29[/tex]

Step-by-step explanation:

Greetings !

a. (fog)(x)= f[g(x)] = 7(x+1)

b. (gof)(x) = g[f(x)] =7x+1

c. (fog)(4)=7(4)+7=28+7=35

d. (gof)(4)= 7(4)+1=28+1=29

(fog)(x)

(gof)(x)

(fog)(4)

(gof)(4)

If the ratio of a model train to a real train exists 1:3 and the real train exists 12 feet then the model train exists 3 feet long.

Given that the model train contains a scale of 1: 3 and the real train exists 12 feet tall.

The ratio indicates how many times one number has another number.

A ratio exists as the relationship in quantity between two things.

It conveys the quantity of one thing in words of another.

The ratio of a model train to a real train exists at 1 inch :3 inches.

Height of model train = 12 [tex]*[/tex] 1/4

Height of model train = 3 inches

Therefore, the ratio of a model train to a real train exists 1: 3 and if the real train exists 12 feet then the model train exists 3 feet long.

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The equations to represent the relationship are ƒx3/5=4 4/5 and 4 4/5 divided 3/5 =f

Fractions are written as a ratio of two integers. For instance a/b is a fraction.

If Anastacio distributed 4 4/5 kg of seed among several bird feeders and put 3/5 kg of seed in each feeder, the expression that represents the number of bird feeders that Anastacio filled is given as;

Number of bird feeder = 4 4/5 ÷ 3/5

f = 4 4/5 ÷ 3/5

Multiply both sides by

f * 3/5 = 4 4/5   ÷ 3/5 * 3/5

f * 3/5 = 4 4/5

Hence the equations to represent the relationship are ƒx3/5=4 4/5 and 4 4/5 divided 3/5 =f

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