The elements of group IA have been termed alkali metals because of their ___ alkaline.

400 BTU of wasted heat energy is present in the form of electricity.

So, when efficiency is 60%, energy is used 60% of the time and lost 40% of the time. Thus, according to question, the energy that is wasted is:

1000 BTUx (40/100) = 400 BTU

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Answer:  

It won't let me type this for some reason but here it is.

448 K is the final temperature of the water.

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Given,

the mass of Na is 23 g

The volume of water = 293 cm3

Mass of water = 293 g

Total solution mass = 23 g + 293 g = 316 g

Specific heat capacity of water = 4.18 J/Kg

The equation relating mass, heat, specific heat capacity and temperature change is:

q = mcΔT

197 kJ = 316 g x 4.18 J/Kg x ([tex]T_{finals} - T_ {initial}[/tex])

197 kJ = 316 g x 4.18 J/Kg x ( [tex]T_{finals}[/tex]-298 K)

0.1491429956 x 1000 =  [tex]T_{finals}[/tex]-298 K

149.1429956 + 298 = [tex]T_{finals}[/tex]

447.1429956 = [tex]T_{finals}[/tex]

448 K = [tex]T_{finals}[/tex]

Hence, 448 K is the final temperature of the water.

A high specific heat capacity means that it can store a large amount of thermal energy for a small change in mass or temperature.

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Using the gas laws, the volume of nitrogen produced is 6.6 L.

We know that the product of a reaction is obtained from the balanced reaction equation. The reactants combine together to yield the products hence we have; N2 + 3H2 ----> 2NH3

We know that 1 mole of hydrogen occupies 22.4 L

x moles of hydrogen occupies 25500 L

x = 1 mole * 25500 L/ 22.4 L

x = 1138.4 moles

If 3 mole of hydrogen reacts with 1 mole of nitrogen

1138.4 moles  reacts with 1138.4 moles * 1 mole/ 3 moles = 379.5 moles

Mass of nitrogen = 379.5 moles * 28 g/mol = 10626 g

Now 3 moles of hydrogen produces 44.8 L of NH3

1138.4 moles  produces 1138.4 moles * 44.8 L/ 3 moles = 17000 L

Now;

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 1 * 17000 * 848/5.5 * 273

V2 =9601 L

2) 2NH4NNO3(s) ---> 4H2O(g) + 2N2(g) + O2(g)

Number of moles = 12g/ 80 g/mol = 0.15 moles

Now;

2 moles of NH4NNO3 produced 2 moles of nitrogen hence 0.15 moles of N2 was produced.

1 mole of N2 occupies 22.4 L

0.15 moles of N2 occupies 0.15 moles  *  22.4 L/1 mole = 3.36 L

P1 = 760 torr

V1 = 3.36 L

T1 = 273 K

P2 = 745 torr

T2 = 527 degrees or 800 K

V2 = ?

V2 =  P1V1T2/P2T1

V2 =  760 *  3.36 * 527/745 * 273

V2 = 6.6 L

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The major alkene  product that results when n,n-dimethylhexan-2-amine undergoes cope elimination is hexene or hex-1-ene.

The reaction in which an amine is oxidize to an intermediate called an N-oxide which , when heated , acts as base in an intramolecular elimination reaction. The oxidation of tertiary amine into N-oxide is called cope reaction.

This elimination gives the less substituted alkene along with more substituted alkene which is Zaitsev product.

Example: Cope elimination of  n,n-dimethylhexan-2-amine form hexene.

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Answer:

Below I have listed a write up that helped me!

Explanation:

Here are some general rules regarding significant figures (or sigfigs!)

1) any number that is not a 0 is always a sigfig. In your example, the significant figures would be 4, 6, 7,3,5 and *0. (*there are special rules regarding the number 0)

2) If a 0 is between two non-zero digits (sigfigs), it will be a significant figure. For example, in the number 305, the 0 between the 3 and 5 would be considered a significant figure.

3) 0's that "lead", or are to the left of significant figures are NOT significant figures. For example, in the number 0.002, there would be only one significant figure, which is the 2.

4) 0's that "trail", or are to the right of a significant figure behind a decimal place, are significant figures. For example, in the number 3.1250, the 0 at the end would be considered significant. There are five sigfigs total in this number. The trailing 0 in your example would be significant!

5) However, regarding the rule above, if the number DOES NOT have a decimal place and has trailing 0's, those 0's will not be considered significant figures. For example, in the number 5,320, the 0 at the end would not be significant and there would be three sigfigs in this number.

The statement is False.

No, whole cloves are not broken up to help release the eugenol during distillation.

Steam distillation:

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When 0.34 of HNO₃ is titrated to equivalence using 0.14 l of 0.1 m NaOH then the concentration of HNO₃ is 0.041 M

The reaction of neutralization of HNO₃ with NaOH is

HNO₃ + NaOH → H₂O + NaNo₃

When 1 mole of HNO₃ react with 1 mole of NaOH, based on chemical rection the moles of NaOH at equivalence point are equal to moles of HNO₃ present in solution: -

With the mole and volumes, we can find molarity as follows:

            Moles of NaOH = moles HNO₃

            ⁼ 0.14 L X (0.1 mol NaOH/L) = 0.014 mole NaOH

            =0.014 mol HNO₃

Molarity: -

              [tex]\frac{(Mole of HNO₃)}{(volume of HNO₃)}= \frac{0.014}{0.34}[/tex]

               = 0.041 M

Thus, from above solution we concluded that the concentration of HNO₃ solution is 0.041 M.

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The percent yield of a reaction that produces 12.5 g of the gas freon cf2cl2 from 32.9g of ccl4 and excess HF is 48.33%

CCl4 + 2HF  → CCl2F2 + 2HCl  

Mass of CCl4 = 32.9 g

Mass of CCl2F2 (practical yield)  = 12.5 g

Molecular mass of CCl4 = 153.82 g / mol

Number of moles of CCl4 = Mass of CCl4 / Molecular mass of CCl4

                                           = 32.9 / 153.82

                                           = 0.2139 mol

Number of moles of CCl4 = Number of moles of CF2Cl2 = 0.2139 mol

Molecular mass of CF2Cl2 = 120.91 g / mol

Mass of CCl2F2 = Number of moles of CF2Cl2 * Molecular mass of CF2Cl2

                           = 0.2139 * 120.91

Mass of CCl2F2 ( Theoretical yield ) = 25.8626 g

Percentage yield = Practical yield / Theoretical yield  * 100

                             = 12.5 / 25.8626 * 100

Percentage yield = 48.33%

Hence, the percentage yield of CF2Cl2 is 48.33%

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The percent yield of a reaction that produces 12.5 g of the gas from CF2Cl2 from 32.9 g of CCl4 and excess HF is 48.33%.

CCl4 + 2HF --- CCl2F2 + 2HCl

Mass of CCl4 = 32.9g

Mass of CCl2F2(practical yield) = 12.5g

Molar mass of CCl4 = 153.82 g/mil

Number of moles of CCl4= given mass / molar mass

= 32.9/153.82

= 0.2139mol

As we know

Number of moles of CCl4 = Number of moles of CF2Cl2 = 0.2139 mol

Molecular mass of CF2Cl2 = 120.91 g/ mol

Mass of CCl2F2= number of moles of CF2Cl2 × molar mass of CF2Cl2= 0.2139× 120.91

Mass of CF2Cl2 (Theoretical yield) = (12.5/25.8626) × 100

Percentage yield= 48.33%

Thus, we concluded that the percentage yield of CF2Cl2 is 48.33%.

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Based on the half-life of the radioactive sample and the properties of nuclear reactions, the correct options are:

Half-life is the time taken for half the amount of atoms in an a radioactive element to decay.

1. After three half-lives, (1/2)³ of the original amount will remain = 1/8

1/8 of 16 = 2 ; option A

2. The balanced nuclear equation is given below:

action below:

/64 → /62 + 4He 2 ; option C

3. The trend of proton-to-neutron ratio as elements become heavier is that heavier elements have a greater amount of neutrons per proton; option C

4. The loss in mass of a compound composed of multiple atom types than those of the individual atoms they are made of is due to energy stored in the bonds in the nucleus known as the binding energy; option D

5. Initially, 12 g of carbon-14 was present

After one half-life, 6 g of carbon-14 remained, and 6 g of carbon-12 was present.

After two half-lives, 3 g of carbon-14 remained, and 9 grams of carbon-12 was present.

Age of the carbon sample = 5730 * 2 = 11460 years; option B

6.  A major argument against nuclear power plants is that they produce radioactive waste materials; option A.

7.  A common source of radiation that humans are exposed to come from outer space in the form of ultraviolet rays; option C.

8. The  balanced nuclear reaction is:

/92+/0 → /36+ 1/0 + 143Ba 56 ; option C

In conclusion, nuclear reaction results in changes in the nucleus of atoms.

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The mass of this ion is 1.16*10^-26kg.

To find the answer, we have to know about the force acting on a particle circulating in a uniform magnetic field.

                                  [tex]F_c=F_B\\\frac{mv^2}{r} =qvB\\[/tex]

                   [tex]m=\frac{qBr}{v} =\frac{2*1.67*10^{-19}*0.8*30*10^{-2}}{6.9*10^6} \\m=1.16*10^{-26}kg[/tex]

Thus, we can conclude that, the mass of this ion is 1.16*10^-26kg.

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There are 5 alpha and 5 beta particle  emit emission of thorium-232 nucleus into astatine-212.

A beta ray would be released from such an atomic nucleus during a radioactive decay process known as beta decay. The proton in the nucleus changes from a proton to a neutron throughout beta decay, and vice versa.

It is given that, The atomic mass of Th = 232

Atomic mass of astatine = 212

Atomic number of Th = 90.

Atomic number of  astatine = 85

Number of alpha particle = difference between atomic mass / 4

Number of alpha particle = 232-212 /4

Number of alpha particle = 20/4

Number of alpha particle = 5

Thus, the number of alpha particle will be 5.

Number of beta particle = difference between atomic number

Number of beta particle = 90-85

Number of beta particle = 5

Thus, the number of beta particle will be 5

Therefore, the number of alpha and beta particle will be 5 and 5.

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Tert-butyl alcohol's 13C-NMR spectrum will only display two signals.

(I) Signal at about 31 ppm: This signal is for the more shielded and electron-rich carbon atoms and is upfield. The height of the peak on the y-axis indicates the relative quantity of carbon atoms to other peaks. Since it is three times as tall as the second signal in this instance, it is clear that this peak represents three carbon atoms.

(ii) Signal at about 70 ppm: This signal is directed downfield and pertains to the carbon atom, which is more exposed and has an environment poor in electrons. The height of these peaks is only one carbon higher than the second signal. Furthermore, the exposed environment demonstrates this carbon.

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The oxidation state of a pure element is always zero.

The oxidation state for a pure ion is equivalent to its ionic charge.

What is oxidation state?

The oxidation state or oxidation number, is the hypothetical charge of an atom if all of its bonds to different atoms were fully ionic. The oxidation state may be positive, negative or zero.

What are the rules to write the oxidation number?

1. The atoms in pure elements have oxidation number of ZERO.

2. The more-electronegative element in a binary molecular compound is assigned the number equal to the negative charge it would have as an anion. The less-electronegative element is assigned the number equal to the positive charge it would have as a cation.

3. Fluorine always has an oxidation number of -1 in compounds because it is the most electronegative element.

4. Oxygen is usually -2 unless in peroxides (then it is -1) or with fluorine.

5. Hydrogen has +1 in all compounds containing elements that are more electronegative than it, and is -1 in compounds with metals.

6. The algebraic sum of the oxidation numbers of all atoms in a neutral compound is zero.

7. The algebraic sum of the oxidation numbers of all atoms in a polyatomic ion is equal to the charge of the ion.

8. Although rules 1-7 apply to covalently bonded atoms, oxidation numbers can also be assigned to atoms in ionic compound. Monoatomic ions have oxidation numbers equal to their ionic charge.

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Serotonin acts as a weak base and has a pkb = 3. 84. The ph of a solution made by adding 0. 025 m of serotonin in water is 2.4.

A molecule called serotonin delivers information between nerve cells in the brain and other parts of the body. Body processes like mood, sleep, digestion, nausea, wound healing, bone health, blood clotting, and sexual desire are all significantly influenced by serotonin.

Tryptophan, an important amino acid, is used to make serotonin. This amino acid, which must be ingested by food, is frequently present in foods including nuts, cheese, and red meat. Lower amounts of serotonin can result from tryptophan insufficiency. Anxiety or depression may come from this, among other mood disorders. The chemical serotonin is essential for elevating mood and lowering anxiety.

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The set of reaction conditions would favor a sn2 reaction on 2-bromo-3-methylbutane is a strong nucleophile in an aprotic solvent. The correct option is D.

It is a type of nucleophilic substitution reaction. This mechanism is common in organic chemistry. In these reactions, one bond is break and one bond is formed simultaneously.

The sn2 is a nucleophile reaction, and it is a strong nucleophile. This type of reaction, will occur in the compounds in which there is one alkyl halide group and a good leaving group.

In 2-bromo-3-methylbutane, there is a bromine and methyl group both, so the favor would be a strong nucleophile in an aprotic solvent.

Thus, the correct option is D) strong nucleophile in an aprotic solvent.

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The question is incomplete. Your complete question is given below:

A) weak nucleophile in a protic solvent

B) weak nucleophile in an aprotic solvent

C) strong nucleophile in a protic solvent

D) strong nucleophile in an aprotic solvent

E) none of the above

Answer: Calcium Hydroxide

Explanation:

CaOH will as it is the only base, the rest is acid

When a nonmetal bonds with a nonmetal, a covalent bond is involved. Details about non-metals can be found below.

A nonmetal is an element, such as phosphorus or chlorine, that does not have the chemical or physical properties of a metal.

A metal is known to lose or donate electrons when it goes into a reaction, hence, an electrovalent bond is usually formed.

However, a nonmetal is known to accept or gain electrons when it goes into reactions. This means that when two nonmetals bonds in a chemical reaction, a covalent bond is formed between them.

Covalent bond is a type of chemical bond where two atoms are connected to each other by the sharing of two or more electrons.

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Dsm-5 includes gambling disorder as an addictive disorder, along with substance use disorders. This change is considered important because it suggest that people may become addicted to behavior net just substance.

Gambling disorder which involve repeated, problem gambling behavior. The behavior leads to problem for the individual families, and society.

The emotional and physical sign of gambling disorder are:

Gambling disorder make another kind of addiction that an individual uses to be able to deal with the situation. Start using the drugs alcohol to reduce the feeling of anxiety.

Thus from the above conclusion we can say that Dsm-5 includes gambling disorder as an addictive disorder, along with substance use disorders. This change is considered important because it suggest that people may become addicted to behavior net just substance.

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The volume of methanol necessary to prepare the antifreeze good for antifreeze solution is 3.2 L

M₁V₁ = M₂V₂

Where

The volume of the methanol necessary to prepare the solution can be obtained as illustrated below:

M₁V₁ = M₂V₂

24.7 × V₁ = 10 × 8

24.7 × V₁= 80

Divide both side by 24.7

V₁ = 80 / 24.7

V₁ = 3.2 L

Thus, the volume of methanol necessary to prepare the antifreeze good for antifreeze solution is 3.2 L

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The concentration of ClO₂⁻ at equilibrium if the initial concentration of  HClO₂ is 0.0654.

The concentration of any substance is the quantity of that substance in per square of the space or container.

The reaction is

HClO₂ + H₂O <=> H₃O⁺ + ClO₂⁻

The pH is 0.454 M

Ka = [H₃O⁺][ClO₂⁻ ] / [HClO₂]

2. 25 × 10⁻² m = [x][x] / 0.454-x]

2 + 0.011 - 0.004994 = 0

solve the quadratic equation

x = 0.0654 = [H3O+] = [ClO2-]

pH = -log (H3O+)

pH = -log(0.0654)

pH = 1.2

equilibrium concentrations of

[HClO2] = 0.454 -x = 0.454 -0.0654 = 0.3886 M

[ClO2- ] = x = 0.0654

Thus, the equilibrium concentrations  is 0.0654.

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Answer:

5.80 M

Explanation:

In this problem, the solute is NaCl and the solvent is water. To find the molality, you need to (1) convert grams NaCl to moles NaCl (via molar mass), then (2) convert grams H₂O to kilograms H₂O, and then (3) calculate the molality (via molality equation). The final answer should have 3 sig figs to match the sig figs of the given values.

(Step 1)

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

14.3 grams NaCl                1 mole
--------------------------  x  ------------------------  =  0.245 moles NaCl
                                     58.443 grams

(Step 2)

1,000 g = 1 kg

42.2 grams H₂O                 1 kg
--------------------------  x  -----------------------  =  0.0422 kg H₂O
                                      1,000 grams

(Step 3)

Molality = moles solute / mass solvent (kg)

Molality = 0.245 moles NaCl / 0.0422 kg H₂O

Molality = 5.80 M

To convert oxygen gas to solid, we need to continuous withdrawal of heat from the gas by cooling.

Matter is composed of particles and these particles that compose matter are always in constant motion. This is the main thrust of the so called Kinetic Theory of Matter.

Now we know that the particles that compose a solid are held in a fixed position thus they spread out or expand when heated. The particles of a liquid tend not to be held in fixed positions thus they can be poured.

Given that oxygen has a boiling point of -219°C and a freezing point of -183°C, it follows that at 0°C is a gas and at -200°C, oxygen is a liquid.

To convert oxygen gas to solid, we need to continuous withdrawal of heat from the gas by cooling.

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The correct answer is Carbon Dioxide.

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A chemist reacted 0. 2 moles sodium benzoate with 0. 25 moles of hydrochloric acid. if she generated 22 g benzoic acid, the percent yield is 90%.

Reactant + HCl ------ Product

0.2 mol 0.25 22g

mol

Number of moles of reactant = 0.2mol

Molar mass of product = 122.12g

Number of moles of product = given mass/ molar mass

= 22g/ 122.12 g

= 0.180mol

Percent yield = (number of moles of product/ number of moles of reactant) × 100

= (0.180/0.2) × 100

= 90%

Thus we concluded that the percent yield of the given solution is 90%.

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The freezing point of benzene is 14.08°C.

The temperature at which the liquid and solid states of the substance are in equilibrium at atmospheric pressure.

Calculation

The equation which give relation between freezing point depletion and molality is,

[tex]\Delta T_{f} = K_{f} \times m[/tex]

where,

[tex]\Delta T_{f}[/tex] = change in the freezing point of the solvent.

[tex]K_{f}[/tex] of benzene = 5.12°C/m (given)

M is molality of the solution = 2.75 M

Now, after putting the value in above formula we get

[tex]\Delta T_{f} = K_{f} \times m[/tex]

[tex]\Delta T_{f} = 5.12 \times 2.75[/tex]

       = 14.08°C

Thus from the above conclusion we can say that The freezing point of benzene is 14.08°C.

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Answer:

-8.58

Okay, im having trouble with the question too and the answer i types was wrong, so i went to omnicalculator instead and got this answer which was right. :')

Acetic acid activates the bromine and makes it a better electrophile.

When a substance undergoes bromination, bromine is added to the compound as a result of the chemical reaction. After bromination, the result will have different properties from the initial reactant.

DCM (dichloromethane) requires more time. Acetic acid has protons that can give one of the Br (bromine) a positive charge and activate it. There is a brief loss of aromaticity that calls for high energy activation.

Refer to the attached image for bromination reaction.

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The bromine is activated by acetic acid, which improves its electrophilic properties.

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