The dashed triangle is the image of the solid triangle. The center of dilation is (6, 6).



What is the scale factor used to create the dilation?

Enter your answer as an integer or decimal in the box.



The two right triangles are graphed on a coordinate plane. The horizontal x-axis ranges from negative 10 to 10 in increments of 1. The vertical y-axis ranges from negative 10 to 10 in increments of 1. A dashed triangle has vertices at begin ordered pair 6 comma 6 end ordered pair, begin ordered pair 6 comma 9 end ordered pair, and begin ordered pair 9 comma 6 end ordered pair. A solid triangle has vertices at begin ordered pair 6 comma 6 end ordered pair, begin ordered pair 6 comma negative 9 end ordered pair, and begin ordered pair negative 9 comma 6 end ordered pair.

2461,8

hope this helps!! just use the formulas and substitute

The value of the missing length in the image shown using the Pythagoras theorem is x = 1500

An equation is an expression that shows the relationship between two or more variables and numbers.

Let h represent the missing red line. Using Pythagoras:

x² = h² + 900²

h² = x² - 900²

Also:

r² = h² + 1600²

r² = x² - 900² + 1600²

And:

(1600 + 900)² = r² + x²

(1600 + 900)² = (x² - 900² + 1600²) + x²

x = 1500

The value of the missing length in the image shown using the Pythagoras theorem is x = 1500

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Answer:

B

Step-by-step explanation:

5x - 625[tex]x^{4}[/tex] ← factor out 5x from each term

= 5x(1 - 125x³) ← this factor is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b²) , then

1 - 125x³

= 1³ - (5x)³

= (1 - 5x) (1² + 5x(1) + (5x)² )

= (1 - 5x) (1 + 5x + 25x²)

Then

5x - 625[tex]x^{4}[/tex] = 5x(1 + 5x + 25x²)

Given

[tex]7 - px - x^2 = 16 - (q + x)^2[/tex]

expanding the right side gives

[tex]7 - px - x^2 = 16 - (q^2 + 2qx + x^2)[/tex]

[tex]7 - px - x^2 = 16 - q^2 - 2qx - x^2[/tex]

Two polynomials of equal degree are the same if their coefficients are identical. This means

[tex]\begin{cases}16 - q^2 = 7 \\ -2q = -p\end{cases}[/tex]

[tex]16 - q^2 = 7 \implies q^2 = 9 \implies q=\pm3[/tex]

[tex]-2q = -p \implies p = 2q = \pm6[/tex]

Both [tex]p[/tex] and [tex]q[/tex] are positive, so [tex]\boxed{p=6}[/tex] and [tex]\boxed{q=3}[/tex].

Answer:

1. (2,2)

2. (-20, -1)

3. (4,3)

Step-by-step explanation:

See attached images

Answer:

The solutions to the sets of equations may be found by either a substitution process or by graphing and looking for the point that the two lines formed by the quations intersect.  Both approaches are described.

The "solution" to these sets of equations is the point at which the two lines intersect each other.

Step-by-step explanation:

1. 3x-y=4 and x+2y=6

x+2y=6

6x-2y=8     We can simply add these two equations since y will            disappear, leaving just x.

7x = 14  [result of addition]

x = 2    [Solve]

Since x = 2,  [Then use the solution for x to find y]

x+2y=6

(2)+2y=6

2y = 4

y = 2

(2,2) is the solution (where the lines intersect).  See attached graph.

2. 2x-y= -39 and x+y= -21

2x-y= -39

x+y= -21               Add the two equations (since the y will be eliminated)

3x = -60

x = -20

Find y:  

x+y= -21

(-20)+y= -21

y = -1

Solution is (-20,-1)

3. 2x+y =11 and 6x-5y =9

2x+y =11

-6x+-3y = -33    [Multiply by -3 and then add to other equation.  This allows us to eliminate x]

6x - 5y =   9

 -8y = - 24

y = 3

2x+y =11

2x+(3) =11

2x = 8

x = 4

Solution is (4,3)

==================

See attached graph for all the graphed solutions.

==================

The substitution process also works if we isolate one of the 2 variables in one equation and then use the resulting value in the second eqaution.  For example, in problem 1:

3x-y=4

x+2y=6

Pick either equation and isolate the x or y.  I'll pick the second equation and isolate for x:

x = 6-2y

Now use this value of x (6-2y) in the other equation:

3x-y=4

3(6-2y)-y=4

18 - 6y - y = 4

-7y = -14

y = 2

Then use y=2 to fiond x, using either equation:

x+2y=6

x+2(2)=6

x = 2

The solution is (2,2).

This same approach can be used on all these problems.  It avoids trying to visualize what can be done to an entire equation to eliminate one of the variables, but it takes a bit more paper.

All solutions are graphed in the attachment.

The square root of the quantity x plus 7 end quantity minus 1 equals x=2.

To find the square root:

Check for extraneous solutions:

Therefore, the square root of the quantity x plus 7 end quantity minus 1 equals x = 2.

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The correct question is given below:
The square root of the quantity x plus 7 end quantity minus 1 equals x

The question requires that we have to state the hypothesis:

null hypothesis;H0: u1 < u2, the alternate hypothesis;H1: u1 > u2. The one tail test is what is to be used.

H0: u1 < u2

H1: u1 > u2

The one tail test statistic is what is to be used here

[tex]\sqrt{\frac{30.8}{17} +\frac{6.1}{15} }[/tex]

= 1.49

The df = 17 + 15 - 2

= 30

test statistic = 18.9 - 17.4 / 1.49

= 1.007

We have the critical value on excel as T.INV(0.9,30)

=  1.310

E. At 0.1, we can conclude that  t-value (1.007) does not lies in the rejection area. We fail to reject the null hypothesis. Hence we conclude that the mean vacation with the unlimited plan is greater.

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The correct option is: (b)

                                =432.

By employing multiple processes, simplification refers to reducing the expression to a simpler form. Approximation is the process of making something less complicated and hence easier to accomplish or understand, or the object that arises from this process. The mathematical formula is simplified to its nearest value but is not exactly correct.

Therefore, we must follow the order listed above when simplifying expressions. In the example before, we divide 8 by 4 and then add the result to 12 because, according to BODMAS, division (D) comes before multiples (M).

[tex]$3 \cdot 2^{3} \cdot 2 \cdot 3^{2}Calculate exponents $2^{3}: 8$$$=3 \cdot 8 \cdot 2 \cdot 3^{2}$$Calculate exponents $3^{2}: 9$$$=3 \cdot 8 \cdot 2 \cdot 9$$ $3 \cdot 8 \cdot 2 \cdot 9= 432$$$=432$$[/tex]

So. the value will be = 432

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I understand that the question you are looking for is :

Simplify the expression to a single numerical value.

3*2^3*2*3^2

(a)144

(b)432

(c)900

(d)5,184

Answer:

y does not depend on x - it is not a function

That leaves (2) or (4)

Since one does not need y in the equation (4) is eliminated

(2) is the only possible result

For example:        x = 5

Answer:

3 sqrt 5

Step-by-step explanation:

diameter talks about the center of the circle..and the middle of the circle lies between 3 and 5

If Connie spent $26 on 8 books, The number of hard covers she buy is 5 hard cover.

Let h represent hard cover

Let p represent paperbacks

Formulate an equation

h + p= 8.......(1)

4h + 2p= 26......(2)

Multiply equation (1) by -2

-2h + -2p = -16

4h  +  2p   = 26

2h  +   0p =10

2h = 10

Divide both side by 2h

h=10/2

h =5 hard covers

Paper backs

P=5-2

P=3 paper backs

Therefore If Connie spent $26 on 8 books, The number of hard covers she buy is 5 hard cover.

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Based on the scale, the actual length of the Golden Gate Bridge is  68,600 inches.

A scale drawing is a reduced form in terms of dimensions of an original image / building / object. The scale drawing is usually reduced at a constant dimension. An example of a scale drawing is a map.

The scale of a drawing is usually written in this format -  length in the drawing, a colon (:), then the matching length on the original image. An example of a scale is 1 : 19,600. This scale means that 1 inch of the postcard represents 19.600 of the original Golden Gate Bridge.

Actual length of the Bridge = scale x length of the bridge in the postcard

19,600 x 3.5 = 68,600 inches

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The slope-intercept form of given equation is y = 1/2x + 5/2.

According to the statement

we have given that the equation y-3 = 1/2(x-1) and the passing points are (–9, –2) and (1, 3).

And we have to find the slope-intercept form of the equation

slope-intercept form is the equation of a straight line in the form y = mx + b where m is the slope of the line and b is its y-intercept.

So, According to this

y-3 = 1/2(x-1)

convert this into y = mx +b form then

y-3 = 1/2x -1/2

here m is 1/2 and b is -1/2.

Then

y-3 = 1/2x -1/2

Add three on both sides then

y = 1/2x + 5/2

So, The slope-intercept form of given equation is y = 1/2x + 5/2.

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Answer:

its cccccccc

Step-by-step explanation:

Answer:

x = 10.7

Step-by-step explanation:

Answer:

Number = 12

Step-by-step explanation:

2n-7=n+5 (+7 to both sides)

2n=n+12 (-n to both sides)

n=12

Answer:

  32.4 inches

Step-by-step explanation:

Sam wants the increase to be 8% of 30 inches.

The amount of increase Sam wants in his waist size is ...

  8% × 30 in = 0.08×30 in = 2.4 in

Adding the wanted increase to his present size would make Sam's waist size be ...

  30 in + 2.4 in = 32.4 in

Sam wants his waist size to be 32.4 inches.

__

Additional comment

The larger size can also be computed from ...

  30 +8%×30 = (1 +8%)×30 = 1.08×30 = 32.4 . . . inches

Answer: D

Step-by-step explanation:

If the leading coefficient is negative, then as [tex]x \to \infty[/tex], [tex]f(x) \to -\infty[/tex].

If the leading coefficient is negative, then as [tex]x \to -\infty[/tex], [tex]f(x) \to \infty[/tex].

This leaves D as the correct answer.

[tex]f(x) = y \: \: \ \: \: \: \: \: \: \: \: \: {normal \: function} \\ f(x) = y - 1 \: \: \: \: \: \: \: func\: shifted \: down[/tex]

[tex]f(x) = \frac{ - 1}{3} x {}^{2} \\ f(x) = \frac{ - 1}{3} x {}^{2} - 1[/tex]

Answer: F(x)= -1/3x2-1

Step-by-step explanation:

He worked 43 hours to earn Rs. 23250

His basic pay is Rs. 18000 for a basic 36 hours a week. His salary is

Rs. 23250. This proves that he has worked extra time. So the amount earned in the extra hours equals Rs. 23250 - Rs. 18000 = Rs.5250.

Amount per hour earned in basic pay = 18000/36 = Rs.500 a hour.

∴ Amount per hour earned in extra hours = 1.5 x 500 = 750  per hour.

So number of hours he worked in extra time =  Rs.5250/750 = 7 hours.

Thus total number of hours = 36 + 7 = 43 hours.

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Compounded continuously the balance grows at a continuous rate of 1.7%.

What is compound interest ?

The model used for continuous compounding is

 f(t) = Pe^(rt)

where P is the principal amount, and r is the interest rate being compounded. Assuming a typo in your given equation, you have

 f(t) = 1000·e^(0.017t)

Matching the various parts of the equation, we see that P = 1000 and r = 0.017 = 1.7%.

Therefore, the balance grows at a continuous rate of 1.7%.

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Answer: 18

Step-by-step explanation: 18=1+8=9

its complicated but when you check something like

23= 2+3 =5

 10 = 1+0=1

the individual digits of 18 are 1 and 8

Sum = 1+8=9

multiply 9 by 2 we get 18

18 is also a multiple of 9.

I hope this helps

Answer:

[tex]\Large\boxed{a)~4\sqrt{3} }[/tex]

[tex]\Large\boxed{b)~10\sqrt{10} }[/tex]

Step-by-step explanation:

Given term

[tex]\sqrt{48}[/tex]

Factorize 48 inside the radical sign

[tex]\sqrt{2\times2\times2\times2\times3}[/tex]

Combine terms to form squares

[tex]\sqrt{2^2\times2^2\times3}[/tex]

Simplify the radical sign

[tex](2\times2)\sqrt{3}[/tex]

[tex]\Large\boxed{4\sqrt{3} }[/tex]

Given term

[tex]\sqrt{1000}[/tex]

Factorize 1000 inside the radical sign

[tex]\sqrt{2\times2\times2\times5\times5\times5}[/tex]

Combine terms to form squares

[tex]\sqrt{2^2\times5^2\times2\times5 }[/tex]

Simplify the radical sign

[tex](2\times5)\sqrt{2\times5}[/tex]

[tex]\Large\boxed{10\sqrt{10} }[/tex]

Hope this helps!! :)

Please let me know if you have any questions

The steps to solve the inverse variation will be:

The example will be y varies inversely with x and y = 2 when x = 5. Find y when x = 30

Step 1: Write the variation equation: y = k/x or k = xy:

k = xy

Step 2: Substitute in for the given values of x and y:

k = (2)(5) = 10

Step 3: Rewrite the variation equation: y = k/x with the known value of k (10):

y = 10/x

Step 4: Substitute the remaining values and find the unknown:

y = 10/30

y = 1/3

Therefore, y is 1/3 when x is 30.

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It is true that the graph represents a function

For a graph to represent a function, the following must be true

Each x value on the graph must point to exactly one

The above means that the function must pass the vertical line test

The given graph would pass the vertical line test

This is so because:

Each x value on the graph points to exactly one

Hence, the graph represents a function

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Considering the piecewise function, it is found that f(5) is given by:

f(5) = -1.

A piecewise function is a function that has different definitions, depending on the input.

To find the value of f(5) looking at the graph, we have to find y when x = 5. Researching this graph on the internet, we have that, when x = 5:

The definition is at the closed circle, hence f(5) is given by:

f(5) = -1.

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The correct unscrambling of whyrot is worthy.

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Answer:

a = 3.14

b = 6.28

Step-by-step explanation:

The interval where the function is decreasing is where increasing x values result in decreasing y values. The y values peak at the point (3.14, 2) and decrease until the point (6.28, 0) where the function starts increasing again.

Using the fundamental theorem of calculas the derivative of function g(x)=[tex]xt^{3}+t^{5}[/tex] at x=0 is [tex]t^{3}[/tex].

Given a function g(x)=[tex]xt^{3}+t^{5}[/tex].

We are required to find the derivative of the function g(x) at x=0.

Function is relationship between two or more variables expressed in equal to form. The values entered in a function are part of domain and the values which we get from the function after entering of values are part of codomain of function. Differentiation is the sensitivity to change of the function value with respect to a change in its variables.

g(x)=[tex]xt^{3}+t^{5}[/tex]

Differentiating with respect to x.

d g(x)/dx=[tex]t^{3}[/tex]+0  [Differentiation of x is 1 and differentiation of constant is 0]

=[tex]t^{3}[/tex]

Hence using the fundamental theorem of calculas the derivative of function g(x)= [tex]xt^{3}+t^{5}[/tex] at x=0 is [tex]t^{3}[/tex].

The function given in the question is incomplete. The right function will be g(x)=[tex]xt^{3}+t^{5}[/tex].

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