Solve using the distributive property -5(-3u-3x+4)

The number which represents the difference between the numbers given -3 and -2 as in the task content is; 1.

It follows from the task content that the difference between the given numbers -3 and -2 is to be determined by means of the number line.

On this note, since, it follows that the difference between two numbers in the number line is given by the absolute value of their arithmetic difference.

It follows that the number which is required in this scenario is; |-3-(-2)| = |-1| = 1.

This follows from the fact that the absolute value big any number is that number with a positive polarity.

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For a probability distribution to be represented, it is needed that P(X = 0) + P(X = 1) = 0.44. Hence one possible example is:

The sum of all the probabilities must be of 1, hence:

P(X = 0) + P(X = 1) + P(X = 3) + P(X = 4) + P(X = 5) = 1.

Then, considering the table:

P(X = 0) + P(X = 1) + 0.15 + 0.17 + 0.24 = 1

P(X = 0) + P(X = 1) + 0.56 = 1

P(X = 0) + P(X = 1) = 0.44.

Hence one possible example is:

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well, the regular price is really "x", which oddly enough is 100%, but we also know that $358 is really the discounted price by 20%, namely 100% - 20% = 80%, so we know that 358 is really just 80% of "x", so

[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} x & 100\\ 358& 80 \end{array} \implies \cfrac{x}{358}~~=~~\cfrac{100}{80} \\\\\\ \cfrac{x}{358}=\cfrac{5}{4}\implies 4x=1790\implies x=\cfrac{1790}{4}\implies x\approx 448[/tex]

Answer:

250.

Step-by-step explanation:

if one coin covers 1.14 cm, then the required number can be calculated according the equality:

required_number=(given_length/given_diameter);

Then:

[tex]number=\frac{2.85*100}{1.14} =\frac{285}{1.14} =250[coins].[/tex]

P.S. note, the given length is in [meter], the diameter is in [cm].

The number of tickets sold are:

From the question, we have the following parameters:

Represent the children tickets with x and adults ticket with y.

So, we have the following system of equations

x + y = 63

6x + 8y = 444

Express the equations as a matrix

x      y

1       1       63

6      8       444

Apply the following transformation

R2 = R2 - 6R1

This gives

x      y

1       1       63

0      2       66

Apply the following transformation

R2 = 1/2R2

x      y

1       1       63

0      1       33

From the above matrix, we have the following system of equations

x + y = 63

y = 33

Substitute y = 33 in x + y = 63

x + 33 = 63

Subtract 33 from both sides of the above equation

x = 30

Hence, 30 children tickets were sold and 33 adult tickets were sold

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[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textbf{Equation: }[/tex]

[tex]\large\textsf{(3x)(4x)}[/tex]

[tex]\large\textbf{Solving:}[/tex]

[tex]\large\textsf{(3x)(4x)}[/tex]

[tex]\large\textsf{= 3x} * \large\textsf{4x}[/tex]

[tex]\large\textbf{Combine the like terms:}[/tex]

[tex]\large\textsf{(3x * 4x)}[/tex]

[tex]\large\textsf{= 3x * 4x}[/tex]

[tex]\large\textsf{= 12x}^2[/tex]

[tex]\large\textbf{Therefore, your answer should be: }[/tex]

[tex]\huge\boxed{\frak{Option\ D. 12\mathsf{x}^2}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Discrete data exists as a numerical kind of data that contains total, concrete numbers with clear and fixed data values specified by counting.

Therefore, the correct answer is option B. the number of dogs you take for a walk each day.

Discrete data exists as a numerical kind of data that contains total, concrete numbers with clear and fixed data values specified by counting. Discrete data exists a count that involves integers only a limited number of values exists possible. This kind of data cannot be subdivided into distinct parts. Discrete data contains discrete variables that exist in finite, numeric, countable, and non-negative integers.

Therefore, the correct answer is option B. the number of dogs you take for a walk each day.

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In conducting a​ goodness of fit test, a requirement is that​ the expected frequency must be at least ten for each category.

In relation to the statistical model, the test tells how well it fits a set of observations.

The measures of the goodness of fit summarize the discrepancy between observed values and the values expected under the model in question.

Also, when conducting a​ goodness of fit test, a requirement is that​ the expected frequency must be at least ten for each category.

Therefore, the Option B is correct,

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! is shorthand for the factorial function. If [tex]n[/tex] is a non-negative integer, then

[tex]n! = n\times(n-1)\times(n-2)\times\cdots3\times2\times1[/tex]

with [tex]0! = 1[/tex].

So how to compute [tex]n![/tex] ?

Multiply each number in sequence from that number to 1.

Answer: -1

Step-by-step explanation:

Here, we are subtracting two fractions; therefore, we must make the denominators the same by finding the least common multiple. Since we have x - 3 for one denominator and x + 2 for the other, we don't have any common factors. Hence, the least common multiple would be their product.

[tex](x-3)(x+2)\\x(x-3)+2(x-3)\\x^2-3x+2x-6\\x^2-x-6[/tex]

The question is looking for the coefficient of the second term. Since there is just a negative sign in front of the x, the "?" can be filled with either a negative sign or a -1.

The probability that at least 11 of them graduated is 0.7739 if graduation rate is 92.5%.

Given that graduation rate is 95.2%.

We are required to find the probability that out of 12 selected candidates atleast 11 should be graduated.

Probability is basically the chance of happening an event among all the events possible. It cannot be negative. It lies between 0 and 1.

Probability=Number of items/ Total items.

Probability that atleast 11 will be graduated out of 12 selected candidates is as under:

It will be a binomial distribution.

So,

P(X>=11)=[tex]12C_{11}(0.925)^{11} (0.075)^{1} +12C_{12}(0.925)^{12} (0.075)^{0}[/tex]

=12*0.4241*0.075+1*0.3923

=0.3816+0.3923

=0.7739

Hence the probability that at least 11 of them graduated is 0.7739 if graduation rate is 92.5%.

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Solve the second equation for [tex]t[/tex], then substitute it into the first equation.

[tex]y = t + 2 \implies t = y-2[/tex]

[tex]x = t^2 - 3 \implies \boxed{x = (y-2)^2 - 3}[/tex]

0.03607

Absolute value is the distance of a number from zero. Since distance is always positive, the absolute value is the same number but positive.

Please note, for this problem I have rounded to 5 decimal points because the answer is irrational.

Subtracting

There are 2 different ways to approach this problem. You can either estimate the square root of 5 or plug this question straight into a calculator.

First, we can estimate [tex]\sqrt{5}[/tex] and round to 5 decimal places.

Then, take this value and subtract.

Absolute Value

Now that we have solved the subtraction problem we have to find the absolute value. As stated above, the easiest way to find absolute value is to simply make the number positive. Since the answer is already positive, this is the final answer.

Yes, the mean is 26.4 and the standard deviation is 3

We are given;

n = 40, p = 66% = 0.66, and  q = 1 – 0.66 = 0.34

If np ≥ 5 and np ≥ 5, then the binomial random variable, x is approximately normally distributed, then;

Mean; µ = np

Standard deviation; σ = √npq

where;

n is the sample size.

p is the population proportion.

q = 1 – p.

Calculating np and nq gives;

np = (40)(0.66) = 26.4

nq = (40)(0.34) = 13.6

Both np and nq are greater than 5, the normal distribution can be used to approximate the binomial distribution.

Thus, µ = np

µ = 40(0.66) = 26.4

Standard deviation;

σ = √(40 * 0.66 * 0.34)

σ = 3

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Answer:

42

Step-by-step explanation:

similar triangles

24/x = (24+8)/x+14

that looks complicated so we do

8/24 = 14/x

or

24/8 = x/14

3 = x/14

x = 3*14

x = 42

we test it with the first equation

24/42 = 32/56

simplify

4/7 = 4/7

true so 42 is correct

Answer:

approximately 2 lb

Step-by-step explanation:

Juan: 31/7

Ari: 19/3

Juan's fraction is close to 32/8 = 4

Ari's fraction is close to 18/3 = 6

6 - 4 = 2

Answer: approximately 2 lb

The pair of functions that are inverses of each other is (a) f(x) = 5x - 11 and g(x) = (x + 11)/5

The complete question is added as an attachment

Function 1

f(x) = 5x - 11 and g(x) = (x + 11)/5

Represent 5x - 11 with y in f(x) = 5x - 11

y = 5x - 11

Swap x and y

x = 5y - 11

Add 11 to both sides

x + 11 = 5y

Divide by 5

y = (x + 11)/5

Express as a function

g(x) = (x + 11)/5

From the question, we have:

f(x) = 5x - 11 and g(x) = (x + 11)/5

This means that the function g(x) is an inverse of the function f(x)

Hence, the pair of functions that are inverses of each other is (a) f(x) = 5x - 11 and g(x) = (x + 11)/5

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Answer:

x = 159; y = 140

Step-by-step explanation:

a = 40

a + y = 180

y = 180 - 40

y = 140

b = 61

b = (180 - x) + a

61 = 180 - x + 40

x = 159

Answer:

m∠x = 159°

m∠y = 140°

Step-by-step explanation:

Given information

∠a = 40°

Given formula

∠a + ∠y = 180° (Supplementary angles)

Substitute values into the formula

40 + ∠y = 180

∠y = 180 - 40

[tex]\Large\boxed{\angle y=140^\circ}[/tex]

Given information

∠b = 61°

∠c = Supplementary angle of ∠b

Given formula

∠b + ∠c = 180°

Substitute values into the formula

61 + ∠c = 180

∠c = 180 - 61

∠c = 119°

Determine the value of ∠x

∠x = ∠a + ∠c (Exterior angle theorem)

∠x = (40) + (119)

[tex]\Large\boxed{\angle x=159^\circ}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

Domain: All Real Numbers

Range: All Real Numbers

Step-by-step explanation:

So the domain of a function can be defined as an interval of x-values, which you can input into the function and get real numbers as an output. Since we have a cube root here, or more specifically an odd nth root, the domain is all real numbers, since cbrt(negative number) will just be a negative number since (negative number * negative number * negative number) = negative number, so there does exist a solution, unlike even nth roots like square root, which is restricted to only positive values inside the radical, otherwise you get non-real solutions.

Now let's look at the range of the function, which can be defined as an interval of y-values which can possibly be outputted by the function.

Since as mentioned before, the cube root isn't limited to a certain interval, and rather all real numbers, the range is also similar, since whenever you have a negative number in the radical, the output will be a negative number, so the range is all real numbers

The answer is A.

As any number can be inputted in place of x and the result, y, will be directly proportional to the inputting value, the domain and range of the function is All Real Numbers.

Answer:

Step-by-step explanation:

speed = 50 km / hr.

distance = 20 km

time = distance / speed.

time = ( / 50) hr.

speed =  2 km/hrs

The equation for the tangent plane is 12x - y + 4z - 56 = 0 and the equation for normal line is (x - 6)/12 = (32 - y) = (z - 2)/4

Finding the Equations for Tangent Plane and Normal Line:

The given function is,

f(x, y, z) = x² - y - z² = 0

∂f/ ∂x = 2x

∂f/ ∂y = -1

∂f/ ∂z = 2z

At given point (6, 32, 2),

∂f/ ∂x = 12

∂f/ ∂y = -1

∂f/ ∂z = 4

(a) The equation of tangent plane is given as follows,

(∂f/ ∂x)(x-x₁) + (∂f/ ∂y)(y-y₁) + (∂f/ ∂z)(z-z₁) = 0

12(x - 6) - 1(y - 32) + 4(z - 4) = 0

12x - 72 - y + 32 + 4z - 16 = 0

The required tangent plane is,

12x - y + 4z - 56 = 0

(b) The equation for normal line is given as,

(x-x₁) / (∂f/ ∂x) = (y-y₁) / (y-y₁) = (z-z₁) / (∂f/ ∂z)

(x - 6)/12 = (y - 32)/(-1) = (z - 2)/4

Thus, the required equation of normal line is,

(x - 6)/12 = (32 - y) = (z - 2)/4

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Applying the definition of the median of a triangle: x = 9; CD = 28; DB = 28.

The median of a triangle can be defined as a line segment in a triangle that joins the vertex of a triangle to the midpoint of the side of the triangle that is opposite the vertex.

Given triangle ABC, where AD is the median and D is the midpoint of side AB, therefore:

Side CD equals side DB.

Side CD = 5x - 17

Side DB = 3x + 1

Make both segments equal to each other. Therefore, we would have the equation:

5x - 17 = 3x + 1

Solve for x

Add both sides by 17

5x - 17 + 17 = 3x + 1 + 17

5x = 3x + 18

Subtract 3x from both sides

5x - 3x = 3x + 18 - 3x

2x = 18

Divide both sides by 2

2x/2 = 18/2

x = 9

CD = 5x - 17

Plug in the value of x

CD = 5(9) - 17

CD = 45 - 17

CD = 28 units.

DB = 3x + 1

Plug in the value of x

DB = 3(9) + 1

DB = 27 + 1

DB = 28 units.

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Answer:

-1

Step-by-step explanation:

0.35 - 0.8 = -0.45

-0.1 - 0.35 = -0.45

-0.55 - 0.45 = -1

Answer:

5

Step-by-step explanation:

where there is the decimal point,you count the numbers after the decimal point

The exponential model for the data is: [tex]y = 693(1.5)^x[/tex]

When the cost is of $6000, the weight is of approximately 5.3 carats.

An exponential function is modeled by:

[tex]y = ab^x[/tex]

In which:

From the table, the rate of change is given by:

b = 4980/3210 = 3210/2140 = 2140/1430 = 1.5.

When x = 1, y = 1040, hence the initial value is found as follows:

1.5a = 1040.

a = 1040/1.5

a = 693.

So the model is:

[tex]y = 693(1.5)^x[/tex]

When the cost is of $6000, the weight is found as follows:

[tex]693(1.5)^x = 6000[/tex]

[tex](1.5)^x = \frac{6000}{693}[/tex]

[tex]1.5^x = 8.658[/tex]

[tex]\log{1.5^x} = \log{8.658}[/tex]

x log(1.5) = log(8.658)

x = log(8.658)/log(1.5)

x = 5.3

When the cost is of $6000, the weight is of approximately 5.3 carats.

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Answer:

  f(x) = x³ -4x² +9x +164

Step-by-step explanation:

When a function has a zero at x=p, it has a factor (x-p). When a polynomial function with real coefficients has a complex zero, its conjugate is also a zero.

Given the two zeros and the one we can infer, we can factor our 3rd-degree polynomial function as ...

  f(x) = a(x -(-4))·(x -(4+5i))·(x -(4-5i))

Using the factoring of the difference of squares, we can combine the complex factors to make a real factor.

  f(x) = a(x +4)((x -4)² -(5i)²) = a(x +4)(x² -8x +16 +25)

The value of this at x=1 is ...

  f(1) = a(1 +4)(1 -8 +41) = 170a

We want f(1) = 170, so ...

  170 = 170a   ⇒   a=1

The factored polynomial function is ...

  f(x) = (x +4)(x² -8x +41)

Expanding this expression, we have ...

  f(x) = x(x² -8x +41) +4(x² -8x +41) = x³ -8x² +41x +4x² -32x +164

  f(x) = x³ -4x² +9x +164

The attached graph verifies the real zero (x=-4) and the value at x=1. It also shows that the factor with complex roots has vertex form (x -4)² +25, exactly as it should be.

Answer:

[tex]f(x) = (x+4)(x^2-8x+41)[/tex]

Step-by-step explanation:

Ok, so there are a couple of things to note here. The first thing is that there is a complex solution

Complex Conjugate Root Theorem:

    if [tex]a-bi[/tex] is a solution then [tex]a+bi[/tex] is a solution and vice versa

Fundamental Theorem Of Algebra:

   Any polynomial with a degree "n", will have "n" solutions. Those solutions can be real and imaginary numbers

So since we're given the root: [tex]4+5i[/tex], we can use the Complex Conjugate Root Theorem to assert that: [tex]4-5i[/tex] is also a solution.

So now we know 3 solutions/zeroes, and since n=3 (the degree), we can know for a fact that we have all the solutions due to the Fundamental Theorem of Algebra.

So using these roots, we can express the polynomial as it's factors. When you express a polynomial as factors it'll look something like so: [tex]f(x) = a(x-b)(x-c)(x-d)...[/tex] where a, b, and d are zeroes of the polynomial. Also notice the "a" value? This will affect the stretch/compression of the polynomial.

So let's express the polynomial in factored form:

[tex]f(x) = a(x-(-4))(x-(4+5i))(x-(4-5i))[/tex]

Simplify the x-(-4)

[tex]f(x) = a(x+4)(x-(4+5i))(x-(4-5i))[/tex]

Now let's distribute the negative sign to the complex roots

[tex]f(x) = a(x+4)(x-4-5i)(x-4+5i))[/tex]

Now let's rewrite the two factors (x-4-5i) and (x-4+5i) so the (x-4) is grouped together

[tex]f(x) = a(x+4)((x-4)-5i)((x-4)+5i))[/tex]

If you look at the two complex factors, this looks very similar to the difference of squares: [tex](a-b)(a+b) = a^2-b^2[/tex]

In this case a=(x-4) and b=5i. So let's use this identity to rewrite the two factors

[tex]f(x) = a(x+4)((x-4)^2-(5i)^2)[/tex]

Let's expand out the (x-4)^2

[tex]f(x) = a(x+4)(x^2+2(-4)(x)+(-4)^2-(5i)^2)[/tex]

Simplify

[tex]f(x) = a(x+4)(x^2-8x+16-(5i)^2)[/tex]

Now simplify the (5i)^2 = 5^2 * i^2

[tex]f(x) = a(x+4)(x^2-8x+16-(-25))[/tex]

Simplify the subtraction (cancels out to addition)

[tex]f(x) = a(x+4)(x^2-8x+41)[/tex]

So just to check for the value of "a", we can substitute 1 as x, and set the equation equal to 170

[tex]170 = a(1+4)(1^2-8(1)+41)\\170 = a(5)(1-8+41)\\170 = a(5)(34)\\170 = 170a\\a=1[/tex]

In this case it's just 1, so the polynomial can just be expressed as:
[tex]f(x) = (x+4)(x^2-8x+41)[/tex]

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

The two triangles are right angled Triangles and they have one common angle. so the two triangles are similar to each other.

By using similarity, ratio of their corresponding sides must be equal as well~

[tex]\qquad \sf  \dashrightarrow \: \cfrac{1}{2 + 1} = \cfrac{3}{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{1}{3} = \cfrac{3}{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 3 \times 3[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 9 \: \: units[/tex]