Rhett is solving the quadratic equation 0= x2 – 2x – 3 using the quadratic formula. which shows the correct substitution of the values a, b, and c into the quadratic formula? quadratic formula: x = startfraction negative b plus or minus startroot b squared minus 4 a c endroot over 2 a endfraction

The amount of money that Miguel would save when he earns $120 is  $96.

Ratio expresses the relationship between two or more numbers. It shows the frequency of the number of times that one value is contained within other value(s).

A ratio table can be described as table that shows equivalent values between two or more numbers and helps us to understand the relationship between the numbers.

The first step is to determine the ratio between the money earned and the money saved.

Ratio = money saved / money earned

8/10 = 0.8

Now, multiply the ratio gotten in the previous step by the amount earned to determine the amount saved.

Amount saved = amount earned x ratio

0.8 x 120 = $96

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Answer:

96

Step-by-step explanation:

I took the quiz edge 2022

Answer: Answer is B, Mark me brainliest please

Step-by-step explanation:

The numbers are arrange in order of consecutive numbering, terminal-digit numbering, and middle-digit numbering to give a value.

Methods of arranging numbers:

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Answer: c = 520

Step-by-step explanation:

     f(2) = 578 means that when x = 2, the value is equal to 578. We will plug these knowns in and then solve for c.

Given:

    f(x) = 4x³ + 7x² - x + c

Substitute:

    578 = 4(2)³ + 7(2)² - (2) + c

Distribute:

    578 = 4 * 2³ + 7 * 2² - 2 + c

Raise to the power of 3 and 2:

    578 = 4 * 8 + 7 * 4 - 2 + c

Multiply:

    578 = 32 + 28 - 2 + c

Add:

    578 = 60 - 2 + c

Subtract:

    578 = 58 + c

Subtract 58 from both sides:

    520 = c

Reflexive property:

   c = 520

[tex] \huge\mathbb{ \underline{SOLUTION :}}[/tex]

Given:

[tex]\longrightarrow\bold{f(x) = 4x^3 + 7x2 −x + c}[/tex]

[tex]\longrightarrow\sf{578= 32+28 −2+ c}[/tex]

[tex]\longrightarrow\sf{578 =58+ c}[/tex]

[tex]\longrightarrow\sf{c = 578-58}[/tex]

[tex]\huge \mathbb{ \underline{ANSWER:}}[/tex]

[tex]\longrightarrow\sf{c= 520}[/tex]

Answer:

someone please help me check my page

someone please help me check my pageStep-by-step explanation:

The number of solutions of a+b+c+d+e+f = 2006 is 9.12 * 10^16

The equation is given as:

a+b+c+d+e+f = 2006

In the above equation, we have:

Result = 2006

Variables = 6

This means that

n = 2006

r = 6

The number of solutions is then calculated as:

(n + r - 1)Cr

This gives

(2006 + 6 - 1)C6

Evaluate the sum and difference

2011C6

Apply the combination formula:

2011C6 = 2011!/((2011-6)! * 6!)

Evaluate the difference

2011C6 = 2011!/(2005! * 6!)

Expand the expression

2011C6 = 2011 * 2010 * 2009 * 2008 * 2007 * 2006 * 2005!/(2005! * 6!)

Cancel out the common factors

2011C6 = 2011 * 2010 * 2009 * 2008 * 2007 * 2006/6!

Expand the denominator

2011C6 = 2011 * 2010 * 2009 * 2008 * 2007 * 2006/720

Evaluate the quotient

2011C6 = 9.12 * 10^16

Hence, the number of solutions of a+b+c+d+e+f = 2006 is 9.12 * 10^16

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Answer:

210 = 6!/1!•1!•1!•1!•1!•1!

Step-by-step explanation:

We can use the stars and bars method to solve this problem. Imagine we have 2006 stars and we want to distribute them among 6 bins (a, b, c, d, e, and f). We can represent the stars as follows:

... * (a stars)

| * * * ... * (b stars)

| | * * * ... * (c stars)

| | | * * * ... * (d stars)

| | | | * * * ... * (e stars)

| | | | | * * * ... * (f stars)

The bars divide the stars into 6 bins, and the number of stars in each bin represents the value of the corresponding variable (a, b, c, d, e, or f).

To ensure that each variable is a positive integer, we can add 1 to each variable and distribute the remaining stars. For example, if we add 1 to a, b, c, d, e, and f, the equation becomes:

(a+1) + (b+1) + (c+1) + (d+1) + (e+1) + (f+1) = 2012

Now we have 6 stars and 5 bars, and we can use the stars and bars formula to find the number of solutions:

Number of solutions = (6+5-1) choose (5-1) = 10 choose 4 = 210

Therefore, the equation a+b+c+d+e+f=2006 has 210 positive integer solutions.

Expressing the answer in the form x!/x!•x!, we have:

210 = 6!/1!•1!•1!•1!•1!•1!

The stars and bars formula is a combinatorial formula that allows us to count the number of ways to distribute identical objects into distinct groups.

Suppose we have n identical objects and k distinct groups. We can represent the objects as stars and the groups as bars. For example, if we have 7 objects and 3 groups, we can represent them as:

| | |

The bars divide the 7 stars into 3 groups, and the number of stars in each group represents the number of objects in that group.

The stars and bars formula tells us that the number of ways to distribute n identical objects into k distinct groups is:

(n+k-1) choose (k-1)

where "choose" is the binomial coefficient. This formula can be derived using a technique called "balls in urns" or by using generating functions.

In the example above, we have n = 7 objects and k = 3 groups, so the number of ways to distribute the objects is:

(7+3-1) choose (3-1) = 9 choose 2 = 36/2 = 18

Therefore, there are 18 ways to distribute 7 identical objects into 3 distinct groups.

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Using the volume for rectangular prisms, the volume of the chimney is: 216 in.³.

The volume of a rectangular prism = (length)(width)(height).

The Chimney in Emily's house is a composite solid consisting of two rectangular prism. To find the volume, we have to decompose the figure into two rectangular prisms. Then solve for the volume of each before finding the total volume.

Volume of the bigger rectangular prism = (length)(width)(height) = (4)(4)(12)

Volume of the bigger rectangular prism = 192 in.³

Volume of the smaller rectangular prism = (length)(width)(height) = (4)(2)(3)

Volume of the smaller rectangular prism = 24 in.³

The volume of the chimney = volume of the two rectangular prism

The volume of the chimney = 192 + 24

The volume of the chimney = 216 in.³

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More than 50% of Americans rely upon television broadcasts for their news.

News, current occasions and ancient programming can help make younger humans extra aware of other cultures and those. Documentaries can help increase vital thinking about society and the arena. television can help introduce teens to classic Hollywood movies and overseas movies that they might not otherwise see.

It broadens the know-how of various cultures, and promotes tolerance and international information of worldwide issues. Through contemporary affairs, discovery, lifestyle, cooking indicates and children's programs, television encourages medical and cultural interest.

Agree with and effect: television is the most relied on a form of marketing and stays maximumly probable to make consumers chortle, circulate them to tears or cause feelings. For example, television is with the aid of a long way the maximum relied on shape of video advertising in Canada. 70% of 18-34-year-olds named tv the most truthful compared to 12% for online video.

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Answer:

76

Step-by-step explanation:

Formula

[tex]\sf Average=\dfrac{\textsf{sum of all the numbers}}{\textsf{amount of numbers}}[/tex]

Given values:

Let x be the score of the fourth test.

To find the score of the fourth test, substitute the given values into the formula and solve for x:

[tex]\begin{aligned} \sf Average & =\dfrac{\textsf{sum of all the numbers}}{\textsf{amount of numbers}}\\\\\implies \sf 80 & = \sf \dfrac{84+78+82+x}{4}\\\sf 80 & = \sf \dfrac{244+x}{4}\\\sf 80 \cdot 4 & = \sf 244 + x \\\sf 320 & = \sf 244 + x\\\implies \sf x & = \sf 320 - 244\\& = \sf 76\end{aligned}[/tex]

Therefore, John scored 76 on his fourth test.

The value of f(3) is 147.3306

The function is given as:

[tex]f(x)=147+2e^{-0.6x[/tex]

Substitute 3 for x

[tex]f(3)=147+2e^{-0.6*3[/tex]

Evaluate the product

[tex]f(3)=147+2e^{-1.8[/tex]

Evaluate the exponent

f(3)=147 + 2* 0.1653

Evaluate the sum

f(3) = 147.3306

Hence, the value of f(3) is 147.3306

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Answer:

182000

Step-by-step explanation:

4.82 x 10^5

1.

10^5 is equal to 10 being multiplied 5 times. So this can be expressed as:

10 x 10 x 10 x 10 x 10.

When you multiply 10s, you just add the number of zeros next to one.

==> 100000 (5 zeros total)

2.

We multiply 100000 to 4.82.

100000 x 4.82 = 182000

So our final answer will be 182000.

Answer:

482,000.

Step-by-step explanation:

The 5 tells us this number is 6 digits long.

The answer is

482,000

Answer:  1.51

Step-by-step explanation:

        [tex]\frac{w + 7.1}{3} =2.87[/tex]

   [tex]3(\frac{w+7.1}{3})=3(2.87)[/tex]

      w + 7.1 = 8.61

w + 7.1 - 7.1 = 8.61 - 7.1

               w = 1.51

Answer: its C

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

  (b)  2.175 miles to 2.185 miles

Step-by-step explanation:

When a value is rounded, the original "exact" value is presumed to be within 1/2 of the value of one least-significant unit of the rounded number.

A rounded value of 2.18 has a least-significant digit with a place value of 0.01 units. Half that value is the "margin of error". That is, the range of numbers that would be rounded to 2.18 is ...

  2.18-0.005 ≤ x < 2.18+0.005

  2.175 ≤ x < 2.185 . . . . miles

Answer:

227.02

Step-by-step explanation:

[tex]400.00-172.98 \\ \\ =300 - 72.98 \\ \\ =230-2.98 \\ \\ =228-0.98 \\ \\ =227.02[/tex]

Answer:

227.02

Step-by-step explanation:

[tex]400.00\\-172.98[/tex]

To solve: First subtract 172 from 400, resulting in 228, then you may subtract the 0.98, leaving 227.02.

By the integral test, the series is convergent.

The sequence [tex]k^3/e^{k^4}[/tex] is clearly positive and decreasing for [tex]k\in\Bbb N[/tex]; then by the integral test,

[tex]\displaystyle \int_1^\infty \frac{x^3}{e^{x^4}} \, dx \le \sum_{k=1}^\infty \frac{k^3}{e^{k^4}}[/tex]

and

[tex]\displaystyle \int_1^\infty \frac{x^3}{e^{x^4}} \, dx = \frac14 \int_1^\infty e^{-u}\, du = \frac1{4e} < \infty[/tex]

By using the integral test, series converges

What is an integral test for convergence and divergence?

⇒ It is used to prove the divergence or convergence of series. This test is called the integral test, which compares an infinite sum to an improper integral. It is important to note that this test can only be applied when we are considering a series whose terms are all positive.

How to know if a series is converging or diverging?

If the limit exists and is a finite number (a number less than infinity), we say the integral converges. If the limit is ±∞ or does not exist, we say the integral diverges.

let aₓ= f (x) is any function

⇒ In order for the integral test to work The function must be positive it has to be continuous and it has to be decreasing when x≥1

If the integral converges it means the series is also converging

If the integral diverges it means the series is also diverging

The sequence [tex]k^{3} /{e^{k^{4} }[/tex] is clearly positive and decreases for k∈N then by the integral test,

[tex]\int\limits^\infty_1 {x^{3} /e^{x^4} dx[/tex] [tex]\leq\displaystyle \sum^{\infty}_{k = 1} {x^{3} /e^{x^{4}[/tex]

and

[tex]\int\limits^\infty_1 {x^{3} /e^{x^4} dx[/tex][tex]=1/4\int\limits^\infty_1 {x^{3} /e^{-u} du[/tex]

⇒ [tex]1/4 < \infty[/tex]

So it comes with a finite value hence the series converges

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Answer:

C

Step-by-step explanation:

the sum of the exterior angles of a polygon = 360°

sum the 4 exterior angles and equate to 360

8x + 9x + 5 + 5x + 4 + 9x + 3 = 360 , that is

31x + 12 = 360 ( subtract 12 from both sides )

31x = 148 ( divide both sides by 31 )

x ≈ 11.23 ( to 2 dec. places )

then exterior angle at B is

9x + 3 = 9(11.23) + 3 ≈ 104° → C

The approximate measure of exterior angle B in the polygon is 104° option (C) is correct.

A polygon is a geometric figure with a finite number of sides in two dimensions. On the sides or edges of a polygon, straight-line segments are joined end to end to form a closed shape. The vertices, also known as corners, are the points where two line segments meet and form an angle.

[tex]\rm Area = |\dfrac{(x_1y_2-y_1x_2)+(x_2y_3-y_2x_3)....+(x_ny_1-y_nx_1)}{2}|[/tex]

It is given that:

A polygon is given in the picture with angle measures.

As we know,

The sum of the exterior angles of a polygon = 360°

8x + 9x + 5 + 5x + 4 + 9x + 3 = 360

31x + 12 = 360

31x = 148

x ≈ 11.23

= 9x + 3 = 9(11.23) + 3

≈ 104°

Thus, the approximate measure of exterior angle B in the polygon is 104° option (C) is correct.

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Answer:

The solution is x < 3. To represent that on a number line, you'd have an open (not filled in) circle on 3 and shading to the left.

Step-by-step explanation:

You would only have a closed (solid/filled in) circle if the inequality had a ≤

Answer:

12.5%

Step-by-step explanation:

27-24=3

3/24=1/8

1/8=0.125

0.125 in percent is 12.5%

13.1 = 13.10

---> 13.1 > 13.01

---> 13.01 < 13.1

The correct answer is <

The statement that best describes the relationship between triangles ABD and CBD is 'Triangles ABD and CBD are congruent by the SSS Congruence postulate'. Option A

It is important to note the following;

"Two triangles are similar when their corresponding angles are equal and corresponding sides are in equal proportion."

The SSS congruence states that ; "Two triangles are congruent if all three sides of a triangle are congruent to corresponding three sides of other triangle."

SSS similarity postulates that;  "Two triangles are similar if all the three sides of a triangle are in proportion to the three sides of another triangle."

SAS similarity postulates that ; "Two triangles are similar if the two sides of a triangle are in the same proportion of the two sides of another triangle, and the angle between the two sides in both the triangle are equal."

SAS congruence postulates that ; "Two triangles are congruent if two sides and the angle between these two sides of one triangle are congruent to the corresponding two sides and the included angle of a second triangle."

For given question,

We have been given triangles ABD and CBD.

B is the midpoint of line AC

⇒ AB = BC

For triangles ABD and CBD,

side AB = side CB; since, B is the midpoint of line AC

side BD = side BD ; they have common sides

side AD = side CD = 15 units each

So, by SSS postulates of triangle congruence triangles ABD and CBD are congruent triangles.

Therefore, the statement that best describes the relationship between triangles ABD and CBD is 'Triangles ABD and CBD are congruent by the SSS Congruence postulate'. Option A

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The expression that represents the volume of the cone is 6aπ.

What is called cone?

Given the data in the question;

Radius r = 3

Height h = 2a

Volume of the cone V = ?

We substitute our given values into the expression above.

V = (1/3) × π × r² × h

V = (1/3) × π × (3)² × 2a

V = (1/3) × π × 9 × 2a

V = 18aπ / 3

V = 6aπ

Therefore, the expression that represents the volume of the cone is 6aπ.

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The answer is 114.5%.

Let the original population be denoted by x.

Now, let's go through the percentage increase per year.

Year 1

Year 2

Year 3

Year 4

Overall increase : 214.5% - 100% = 114.5%

Hence, the overall percentage increase in these 4 years is 114.5%.

Step-by-step explanation:

the general slope-intercept form is

y = ax + b

a is the slope, b is the y-intercept.

we need to transform x + 2y = 6, so that we end up with y being all alone on one side, and the rest on the other side.

x + 2y = 6

2y = -x + 6

y = -x/2 + 6

Using binomial distribution, the probability of

a. 5 will still be with the company after 1 year is 28%.

b. at most 6 will still be with the company after 1 year is 89%.

The probability of a new employee in a fast-food chain still being with the company at the end of the year is given to be 0.6, which can be taken as the success of the experiment, p.

We are finding probability for people, thus, our sample size, n = 8.

Thus, we can show the given experiment a binomial distribution, with n = 8, and p = 0.6.

(i) We are asked for the probability that 5 will still be with the company.

Thus, we take x = 5.

P(X = 5) = (8C5)(0.6⁵)((1 - 0.6)⁸⁻⁵),

or, P(X = 5) = (56)(0.07776)(0.064),

or, P(X = 5) = 0.27869184 ≈ 0.28 or 28%.

(ii) We are asked for the probability that at most 6 will still be with the company.

Thus, our x = 6, and we need to take all values below it also.

P(X ≤ 6)

= 1 - P(X > 6)

= 1 - P(X = 7) - P(X = 8)

= 1 - (8C7)(0.6)⁷((1 - 0.6)⁸⁻⁷) - (8C8)(0.6)⁸((1 - 0.6)⁸⁻⁸)

= 1 - 8*0.0279936*0.4 - 1*0.01679616*1

= 1 - 0.08957952 - 0.01679616

= 0.89362432 ≈ 0.89 or 89%.

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The provided question is incomplete. The complete question is:

If the probability of new employee in a fast-food chain still being with the company at the end of 1 year is 0.6, what is the probability that out of 8 newly hired people,

a. 5 will still be with the company after 1 year?

b. at most 6 will still be with the company after 1 year?

The solution to the equation is x = 1.62

The equation is given as:

[tex]x =\sqrt{x\ -\ \frac{1}{x}}+\sqrt{1-\ \frac{1}{x}}[/tex]

Next, we split the equations as follows:

y = x

[tex]y =\sqrt{x\ -\ \frac{1}{x}}+\sqrt{1-\ \frac{1}{x}}[/tex]

Next, we graph the equations (see attachment)

From the attached graph, the equations intersect at

(x, y)= (1.62, 1.62)

Remove the y value

x = 1.62

Hence, the solution to the equation is x = 1.62

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Rationalize the right side first. Expand and simplify.

[tex]x = \sqrt{x - \dfrac1x} + \sqrt{1 - \dfrac1x}[/tex]

[tex]x \left(\sqrt{x - \dfrac1x} - \sqrt{1 - \dfrac1x}\right) = \left(\sqrt{x - \dfrac1x} + \sqrt{1 - \dfrac1x}\right) \left(\sqrt{x - \dfrac1x} - \sqrt{1 - \dfrac1x}\right)[/tex]

[tex]x \left(\sqrt{x - \dfrac1x} - \sqrt{1 - \dfrac1x}\right) = \left(\sqrt{x - \dfrac1x}\right)^2 - \left(\sqrt{1 - \dfrac1x}\right)^2[/tex]

[tex]x \left(\sqrt{x - \dfrac1x} - \sqrt{1 - \dfrac1x}\right) = \left(x - \dfrac1x\right) - \left(1 - \dfrac1x\right)[/tex]

[tex]x \left(\sqrt{x - \dfrac1x} - \sqrt{1 - \dfrac1x}\right) = x - 1[/tex]

Rearrange terms as

[tex]\dfrac{x - 1}x = \sqrt{x - \dfrac1x} - \sqrt{1 - \dfrac1x}[/tex]

[tex]\dfrac{x - 1}x + \sqrt{\dfrac{x - 1}x} = \sqrt{x - \dfrac1x}[/tex]

Substitute

[tex]y = \sqrt{\dfrac{x-1}x} = \sqrt{1 - \dfrac1x} \\\\ \implies y^2 = 1 - \dfrac1x \implies x = \dfrac1{1-y^2}[/tex]

(noting that [tex]y>0[/tex]) so that

[tex]x - \dfrac1x = \dfrac1{1-y^2} - (1-y^2) = \dfrac{2y^2 - y^4}{1-y^2}[/tex]

and the equation transforms to

[tex]y^2 + y = \sqrt{\dfrac{2y^2 - y^4}{1-y^2}}[/tex]

[tex]y + 1 = \sqrt{\dfrac{2 - y^2}{1-y^2}}[/tex]

Solve for [tex]y[/tex].

[tex](y+1)^2 = \left(\sqrt{\dfrac{2-y^2}{1-y^2}}\right)^2[/tex]

[tex]y^2 + 2y + 1 = \dfrac{2 - y^2}{1 - y^2}[/tex]

[tex]-y^4 - 2y^3 + 2y + 1 = 2 - y^2[/tex]

[tex]y^4 + 2y^3 - y^2 - 2y + 1 = 0[/tex]

[tex]\left(y^4 + 2y^3 + y^2\right) - 2y^2 - 2y + 1 = 0[/tex]

[tex](y^2 + y)^2 - 2(y^2 + y) + 1 = 0[/tex]

[tex]\left(y^2 + y - 1\right)^2 = 0[/tex]

[tex]y^2 + y - 1 = 0[/tex]

[tex]y = \dfrac{-1 \pm \sqrt5}2[/tex]

Since [tex]y>0[/tex], we take the positive root. Then

[tex]y = \sqrt{\dfrac{x-1}x} = \dfrac{-1 + \sqrt5}2[/tex]

Solve for [tex]x[/tex].

[tex]\left(\sqrt{\dfrac{x-1}x}\right)^2 = \left(\dfrac{-1 + \sqrt5}2\right)^2[/tex]

[tex]\dfrac{x-1}x = \dfrac{6 - 2\sqrt5}4 = \dfrac{3 - \sqrt5}2[/tex]

[tex]x - 1 = \dfrac{3-\sqrt5}2x[/tex]

[tex]\dfrac{-1+\sqrt5}2 x = 1[/tex]

[tex]x = \dfrac2{-1+\sqrt5}[/tex]

Rationalize to clean up the answer.

[tex]x = \dfrac2{-1+\sqrt5}\cdot\dfrac{-1-\sqrt5}{-1-\sqrt5} = \boxed{\dfrac{1+\sqrt5}2} \approx 1.6108[/tex]

i.e. the golden ratio constant.

Truth statement exists statements or assertions that exist true yet of whether the constituent premises exist true or false.

There exist five Euclidean Postulates or axioms.

1. Any two ends can be bound by a straight line segment.

2. In a straight line, any straight line segment can be extended indefinitely.

3. A circle can be created utilizing any straight line segment as the radius and one endpoint as the center.

4. Right angles exist all the exact.

5. If two lines meet a third in a manner that the totality of the inner angles on one side exists smaller than two Right Angles, the two lines will inevitably collide on that side if they exist extended far enough.

1. The right angle on the first page of the book offered and the right angles on the last page of the book shown exist all the exact. (Axiom 4)

2. If the string from the Yoyo dangling from the hand in the picture exists circled for 360° such that the length of the string stays equivalent to all thought, and the point from where it exists attached stays fixed, it will trace a circular trajectory. (Axiom 3)

3. The swords held by the fighters can be extended into infinity because they exist in in straight lines. (Axiom 5)

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The value of the given expression is 9/10. The properties of real numbers, such as commutative and distributive are used for solving this expression.

The properties are:

The given expression is

(-3/7) × 6/5 + (3/2) - (6/5) × 1/14

applying commutative law (a + b = b + c)

⇒ (-3/7) × 6/5 - (6/5) × 1/14 + (3/2)

again applying commutative law (a × b = b × a)

⇒ (-3/7) × 6/5 - 1/14 × (6/5)+ (3/2)

applying distributive law (a × (b + c) = a × b + b × c) in reverse order

⇒ (-3/7 - 1/14) × (6/5)+ (3/2)

⇒ (-7/14) × (6/5)+ (3/2)

⇒ (-1/2) × (6/5)+ (3/2)

⇒ (-6/10) + (3/2)

⇒ (-6 + 15)/10

⇒ 9/10

Thus, the required value is 9/10 and the suitable properties are commutative and distributive.

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