QUESTION IS DOW BELOW 15 POINTS EACH PLEASE HELP PLEASE HELP PLEASE HELP

Mary added [tex]$24 \frac{1}{2}[/tex] cups of sugar.

The ratio of flour to sugar exists at 9 cups: 2 4/7 cups

Utilizing equivalent ratios, given that 7 cups of sugar was utilized,

Let cups of flour needed = x such that our equation becomes

flour/sugar[tex]$ =\frac{9}{2\frac{4}{7} }=\frac{x}{7}[/tex]  

[tex]$ \frac{9}{2\frac{4}{7} }=\frac{x}{7}[/tex]

Convert mixed numbers into improper fractions

[tex]$2 \frac{4}{7}= \frac{18}{7}[/tex]

simplifying the above equation, we get

[tex]$\frac{9}{\frac{18}{7} } = \frac{x}{7}[/tex]

= [tex]$24 \frac{1}{2}[/tex]

x = 24.5

The value of x = 24.5.

Therefore, [tex]$24 \frac{1}{2}[/tex] cups of sugar exist required.

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Answer

here

A={a,b,c,d}

B={c,d,e,f}

C={x,y,z}

A-B={e,f}

Answer: 2

Step-by-step explanation:

When a^b = c, loga(c) = b

So b^5 = 32 and b is 2

Using proportions, the estimate of the population percentage of seniors that will say they are going to the graduation party is of 62.5%.

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

The estimate of a population proportion is the sample proportion. In this problem, the sample proportion is of 75 out of 120 students, hence:

p = 75/120 = 0.625 = 62.5%.

The estimate of the population percentage of seniors that will say they are going to the graduation party is of 62.5%.

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The mean, median, and mode are;

median=77

Mean=73.33

Mode= 78, 67

This is further explained below.

Generally, The middle number in a list that is arranged from smallest to greatest is referred to as the median. On the list, the value that occurs most often is known as the mode. Therefore

median=77

Generally, In mathematics, particularly statistics, the term "mean" may refer to a number of different concepts. The purpose of each mean is to summarize a certain collection of data, often for the purpose of gaining a better understanding of the overall value of a specific data set.

A dataset's mean (also known as the arithmetic mean, which is distinct from the geometric mean) is calculated by dividing the sum of all of the values in the dataset by the total number of values in the dataset. It is the measure of central tendency that is used the most often, and it is sometimes referred to as the "average."

[tex]mean=\frac{\sum x}{n}\\\\Mean=\frac{78+67+98+50+67+78+67+77+78}{9}[/tex]

Mean=73.33

Mean=73.3 in one dp

In conclusion, The mode is the number that appears the most often, or the number that stands out as having the most occurrences overall. The number 2 is the mode of the sequence 4, 2, 4, 3, 2, 2 because it appears three times, which is more than any other number in the sequence.

The mode of 78, 67, 98, 50, 67, 78, 67, 77, 78  is

Mode= 78, 67

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The pounds of alloy that contains 26% copper that would be used is  23.42 pounds.

The pounds of alloy that contains 69% copper that would be used is 29.58 pounds.

0.26a + 0.69b = (53 x 0.5)

0.26a + 0.69b = 26.50 equation 1

a + b = 53 equation 2

Where:

Multiply equation 2 by 0.26

0.26a + 0.26b = 13.78 equation 3

Subtract equation 3 from equation 2

12.72 = 0.43b

b = 12.72 / 0.43

b = 29.58 pounds

a = 53 - 29.58 = 23.42 pounds

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Under the straight-line depreciation method, the depreciation expenses for the years ended December 31, Year 1, Year 2, Year 3, and Year 4, for Perdue Company, are as follows:

Year Amount

Year 1 $2,858.33 ($11,4333.33 x 3/12)

Year 2 $11,433.33

Year 3 $11,433.33

Year 4 $8,575.01 ($11,433.34 - $2,858.33)

The straight-line method is one of the depreciation methods in use by companies to allocate the cost of plants and equipment over their useful lives.

Under the straight-line method, the depreciable amount (cost less residual value) is divided by the estimated useful life.

Other depreciation methods include the unit-of-production, double-declining-balance, and the sum-of-the-years-digit methods.

Equipment cost = $36,100

Residual value = $1,800

Depreciable amount = $34,300 ($36,100 - $1,800)

Estimated useful life = 3 years

Annual depreciation = $11,433.33 ($34,300/3)

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Determine the amount of depreciation expense for the years ended December 31, Year 1, Year 2, Year 3, and Year 4, by the straight-line method.

The x- and y- coordinates of point E, which partitions the directed line segment from J to K into a ratio of 1:4 is (17, 11)

The midpoint of a line is the point that bisects or divides the line into two equal parts

If the line JK is partitioned into the ratio 1:4 with the following coordinates

J(-15, -5) and K(25, 15)

Using the expression below;

M(x, y) =[mx1+nx2/m+n, my1+ny2/m+n]

Substitute the ratio and the coordinates

M(x, y) =[1(-15)+4(25)/4+1, 1(-5)+4(15)/1+4]

M(x, y) = [(85)/5, 55/5]

M(x, y) = (17, 11)

Hence the x- and y- coordinates of point E, which partitions the directed line segment from J to K into a ratio of 1:4 is ((17, 11)

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The interpretation based on the confidence interval given is that the population mean will fall within the interval.

Number of observations = 10

Sample mean = 2.60

Standard deviation = 1.07

The degree of freedom will be:

= n - 1

= 10 - 1 = 9

Confidence level = 95% = 0.95

Level of significance = 1 - 0.95 = 0.05

The value of the t critical from the t table will be 2.262.

The margin of error will be:

= 2.262 × 1.07/✓10

= 0.765

We get the 95% confidence interval for the population mean. This will be:

(2.60 - 0.765( <= U =(2.60 + 0.765)

1.83 <= 3.37

Therefore, the interpretation is that the population mean will fall within the interval.

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[tex]x ^{3} + 5x {}^{2} - 8 r - 20 = 0 \\ x { }^{3} + 5x {}^{2} - 8r - 20(x {}^{3} + 5x {}^{2} ) = 0 - (x {}^{3} + 5x {}^{2} ) \\ - 8r - 20 = - (x {}^{3} + 5x {}^{2} ) \\ \\ - 8r - 20 + 20 = - (x {}^{3 } + 5x {}^{2} ) + 20 \\ \\ - 8r = x {}^{3} - 5x {}^{2} + 20 \\ \\ [/tex]

hope it is helpful

Answer:

I don't know what are you saying bro

Answer:

[tex]a_{n} = -3n + 10[/tex]

Step-by-step explanation:

The arithmentic function formula is:

[tex]a_{n} = a_{1} + d(n-1)[/tex]

Let's plug in what we know. [tex]a_{1}[/tex] (the first term in our sequence) is 7. d (the common difference) is -3. This means we are subtracting 3 every time.

Plugging that in to the formula, we get

[tex]a_{n} = 7 -3(n-1)[/tex]

Now we distribute and combine like terms.

[tex]a_{n} = 7 - 3n +3[/tex]

[tex]a_{n} = 10 - 3n[/tex]

Change the order to fit the format and you get

[tex]a_{n} = -3n + 10[/tex]

Using it's concept, the probability that the first coin is a nickel and the second coin is a quarter is:

2/39.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

Hence the probability will be given as follows:

p = 4/13 x 2/12 = 4/13 x 1/6 = 2/13 x 1/3 = 2/39.

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Answer:-2,0 & 1,0

Step-by-step explanation:

Substitute them in with zero product property

[tex]~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$132.90\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 5.5\%\to \frac{5.5}{100}\dotfill &0.055\\ t=years \end{cases} \\\\\\ 132.90 = (6000)(0.055)(t)\implies \cfrac{132.90}{(6000)(0.055)}=t\implies \cfrac{443}{1100}=t \\\\\\ \stackrel{\textit{converting that to days}}{\cfrac{443}{1100}\cdot 365} ~~ \approx ~~ 147~days[/tex]

now, if we move back from August 14th by 147 days backwards, that'd put us on March 20th.

Answer:

20

Step-by-step explanation:

We know that she initially had 40 plants. The half of 40 is 20. That is also the number of plants that died.

Answer: A. 20

Step-by-step explanation:

Given Information:

Original = 40 Plants

New = Half Died

Find the number of plants that died:

40 × (1 / 2) = 40 / 2 = 20 Plants

or

40 ÷ 2 = 20 Plants

Therefore, it equals to [tex]\boxed{20 \:Plants}[/tex]

Hope this help!! :)

Please let me know if you have any questions

It's easy to show that [tex]7\tan(4x)[/tex] is strictly increasing on [tex]x\in\left[0,\frac\pi8\right][/tex]. This means

[tex]M = \max \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/12} = 7\sqrt3[/tex]

and

[tex]m = \min \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/16} = 7[/tex]

Then the integral is bounded by

[tex]\displaystyle 7\left(\frac\pi{12} - \frac\pi{16}\right) \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le 7\sqrt3 \left(\frac\pi{12} - \frac\pi{16}\right)[/tex]

[tex]\implies \displaystyle \boxed{\frac{7\pi}{48}} \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le \boxed{\frac{7\sqrt3\,\pi}{48}}[/tex]

Answer:  y = -3x-3 (Choose values for x)

Step-by-step explanation:

1st change the equation to y = mx+b form

In order to change the equation to y = mx+b form subtract the 3x to both sides.
The equation now becomes y = -3x-3

2nd we can either choose values for x such has (-2,-1,0,1,2) and plug in those values into our equation y = -3x-3
For example, if we plug in x= -2 we get y= -3(-2)-3 which becomes y =3. We then plot the point (-2,3) because -2 is our x coordinate and 3 is our y coordinate.
Or we can plug the equation into a calculator that will graph the equation for you.

Answer:   so there would be 1

23                                                

3   21

2   20

Step-by-step explanation:

The value of the expression (a - b)² from the given equations is; 16

We are given the two equations as;

a + b = 10   -----(eq 1)

ab = 21    ------(eq 2)

From eq 1, square both sides;

(a + b)² = 10²

a² + 2ab + b² = 100

a² + b² = 100 - 2ab

We are given ab = 21. Thus;

a² + b² = 100 - 2(21)

a² + b² = 58

Now, we know that (a - b)² = a² - 2ab + b²

Thus;

(a - b)² = 58 - 2(21)

(a - b)² = 16

Complete question is;

If a + b = 10 and ab = 21, then the value of (a - b)² is?

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Answer:

DO not working in you

Step-by-step explanation:

PLEASE help me in answering

Answer:

Step-by-step explanation:

The population at various days is as follows since population triples every 3 days

Day     Population

0          10

3          30

6          90

9          270

....         ......

This can be modeled by the general equation

[tex]n_{t} = n_{0}(r)^{t/k}[/tex]

where

[tex]n_{t}[/tex] is the population after t days

[tex]n_{0}[/tex] is the population at start (10)

[tex]r[/tex] is the rate at which population changes ie 3

[tex]t[/tex] is the number days from start

[tex]k[/tex] is the number of days at which the population triples(here k =3 days)

We can check this by plugging in values for each of the variables

At day 0, population = 10(3)⁰ = 10. 1 = 10

Similarly populations for days 3, 6, 9 are:

[tex]\\\\10.3^{3/3} = 10. 3^1 = 10.3 = 30\\10.3^{6/3} = 10. 3^2 = 10.9 = 90\\\\10.3^{9/3} = 10. 3^3 = 10.27 = 270[/tex]

[tex]30 \: percent \: alcohol \: in \: 260 \: ml \\ alcohol = 0.3 \times 26 0= 78 \: ml[/tex]

[tex]c( \gamma ) = \frac{78 + 0.95\gamma }{260 + \gamma } \times 100[/tex]

[tex]c( \gamma ) = 75[/tex]

[tex] \frac{78 + 0.95\gamma }{260 + \gamma } = 0.75[/tex]

[tex]78 + 0.95\gamma = 0.75 \gamma + 195 \\ 0.2 \gamma = 117 \\ \gamma = 585[/tex]

[tex]we \: need \: 585 \: ml \: of \: 95% \: alcohol[/tex]

Answer:

You will need 585 mL of the 95% solution.

Step-by-step explanation:

Answer:

0.75, 0.675, 0.475, 0.253, -0.123

Step-by-step explanation:

Positive Numbers will always be greater than negative numbers, so you know -0.123 comes at the end.

Example

0.ABC

The tenth's place (A in the number above) holds the most weight. 0The hundreth's place (B in the number above) holds the second most weight. The thousandth's place (C in the number above) holds the third most weight.

Comparing 0.75 and 0.675 is the same as comparing 75 and 67.5. When in doubt, you can multiply the decimals by 100 to determine their order of value.

Answer:

The answer is 3

Step-by-step explanation:

List all prime factors

15:1,3,5,

27:1,3,

Biggest one is 3

Answer:

the answer is 3

Step-by-step explanation:

cuz the prime factors of 27 is 1,3,and 27

while 15 is 1, 3 ,5 and 15

I hope this helps

Answer: 24,000

Step-by-step explanation:

The graph of the function, f(x) = (1/4)ˣ, can be seen in the attached graph, following the given steps.

In the question, we are given the function, f(x) = (1/4)ˣ.

Step 1, has asked us to find the initial value of the graph, f(0).

This can be calculated by substituting x = 0, in the given function, which gives us:

f(0) = (1/4)⁰ = 1.

Step 2, has asked us to plot the initial value of the function at (0, 1). This is plotted using the graphing tools.

Step 3, has asked us to evaluate f(1) and f(-1). By substituting x = 1, and x = -1, we get:

f(-1) = (1/4)⁻¹ = 4,

f(1) = (1/4)¹ = 1/4.

Step 4, has asked us to plot the points (1, 1/4), and (-1, 4). This is plotted using the graphing tools.

Step 5, has made us identify the asymptote y = 0.

Step 6, gives us the final curve for the function, f(x) = (1/4)ˣ.

The provided question is incomplete. The complete question is:

"Graph: f(x) = (1/4)ˣ

Step 1: Calculate the initial value of the function. f(0) =

Step 2: Plot the initial value of the function at (0, 1).

Step 3: Evaluate the function at two more points. f(1) = 1/4, f(-1) = 4

Step 4: Plot the points (1, 1/4) and (-1, 4)

Step 5: Identify the horizontal asymptote of the function. The asymptote is the line y = 0

Step 6: The smooth curve that includes these points and approaches to the asymptote shows the graph of the function"

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If we compare the given values then we can find that the database B is more likely to have smaller standard deviation.

Given that the values in database A are 0 from 100 and has mean of 50 and Database B has entries from 49 to 51 and also has mean of 50.

We are required to find the database whose standard deviation is lower.

Standard deviation measures the variation of values. It is calculated after finding mean. The square of a standard deviation is known as variance.

Database A has values from 0 to 100 and has mean of 50. Because the values are somewhat very larger than 50 and in database B has values from 49 to 51,there are more chances that the standard deviation of database B will have smaller value than from standard deviation of database A.

Hence if we compare the given values then we can find that the database B is more likely to have smaller standard deviation.

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The amount of the mortgage on this house is given as $300000, while the 1.5 points on the house is given as 3000 dollars

The data from the questions says that the cost of the house = $245000

The down payment amount amount is 45000

Given that they already paid 45000 from the cost of the house, the mortgage would be 245000 - 45000

= $200000

The cost of 1.5 points is the same as the cost of 1.5% of the mortgage of this house.

This is calculated as 0.015 x 200000

= $3000

The conclusion is that the amount of the mortgage on this house is given as $300000, while the 1.5 points on the house is given as 3000 dollars

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Using it's concept, the integer numbers in the data-set are given as follows:

6/1, -14, 56/7.

The other numbers, -74.48 and 3/17, are not integers.

Integer numbers are numbers that have no decimal part. They can be represented by pure numbers, either negative or positive, or also fractions that result in an exact division.

In this problem, we have that:

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