pls help me!!! #18-19

Pls Help Me!!! #18-19

Answers

Answer 1

Answer:

18. Sqrt40 goes between 6 and 7.

19. Sqrt83 ~= 9

Step-by-step explanation:

For both of these problems, it's really useful to be very familiar with the perfect squares on the times table. 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225...



On #18, we're looking at the sqrt40. This will be between sqrt36 and sqrt49, because 40 is between 36 and 49. But sqrt36 is 6 and sqrt49 is 7. So sqrt40 is between 6 and 7.

For #19, the sqrt83 is far closer to sqrt81 than it is to sqrt100. Sqrt81 = 9. So sqrt83 is very close to 9, it would round to 9 and not 10.


Related Questions

If Lonnie has 40 plants and half of his plants die...how many plants does that
equal?
A 20
B 15
C 25

Answers

Answer:

20

Step-by-step explanation:

We know that she initially had 40 plants. The half of 40 is 20. That is also the number of plants that died.

Answer: A. 20

Step-by-step explanation:

Given Information:

Original = 40 Plants

New = Half Died

Find the number of plants that died:

40 × (1 / 2) = 40 / 2 = 20 Plants

or

40 ÷ 2 = 20 Plants

Therefore, it equals to [tex]\boxed{20 \:Plants}[/tex]

Hope this help!! :)

Please let me know if you have any questions

5. If 15 men can finish a work in 16 days in how many days will 8 men can finish the same work? a. 15 b. 20 c. 30 d. 42​

Answers

Answer:

C. 30

Step-by-step explanation:

15 men do work in 16 days

This means that 7.5 men (15/2) would do that same work in 32 days (16x2).

If the number of men increase, the amount of days decrease.

8 men would do that work in 30 days

8 men > 7.5 men

30 days < 32 days

Answer:

Option c.

Step-by-step explanation:

It is an inverse proportion, fewer workers more days to finish the job.

15 -----16

8 ----- x

x = (16)(15)/8 = 240/8 = 30 days

Hope this helps

5=logb(32) what does b equal

Answers

Answer: 2

Step-by-step explanation:

When a^b = c, loga(c) = b

So b^5 = 32 and b is 2

The answer is b equals 2

what is 23,995 rounded to the nearest ten​

Answers

Answer: 24,000

Step-by-step explanation:

24,000
you round up since it’s closer

USH financial is a small bank that is examining its customers use of its website.the number of online transactions made per day during the past 9 days are as follows

Answers

The mean, median, and mode are;

median=77

Mean=73.33

Mode= 78, 67

This is further explained below.

What is median?

Generally, The middle number in a list that is arranged from smallest to greatest is referred to as the median. On the list, the value that occurs most often is known as the mode. Therefore

median=77

Generally, In mathematics, particularly statistics, the term "mean" may refer to a number of different concepts. The purpose of each mean is to summarize a certain collection of data, often for the purpose of gaining a better understanding of the overall value of a specific data set.

A dataset's mean (also known as the arithmetic mean, which is distinct from the geometric mean) is calculated by dividing the sum of all of the values in the dataset by the total number of values in the dataset. It is the measure of central tendency that is used the most often, and it is sometimes referred to as the "average."

[tex]mean=\frac{\sum x}{n}\\\\Mean=\frac{78+67+98+50+67+78+67+77+78}{9}[/tex]

Mean=73.33

Mean=73.3 in one dp

What exactly is the mode in math?

In conclusion, The mode is the number that appears the most often, or the number that stands out as having the most occurrences overall. The number 2 is the mode of the sequence 4, 2, 4, 3, 2, 2 because it appears three times, which is more than any other number in the sequence.

The mode of 78, 67, 98, 50, 67, 78, 67, 77, 78  is

Mode= 78, 67

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1) The following scatterplot shows the percentage of the vote a candidate received in the 2016 senatorial elections

according to the voter's income level based on an exit poll of voters conducted by a news agency. The income

levels 1-8 correspond to the following income classes:

1 = Under $15,000; 2 = $15-30,000; 3 = $30-50,000; 4 = $50-75,000; 5 = $75-100,000;

6 = $100-150,000; 7 = $150-200,000; 8 = $200,000 or more.

Use the election scatterplot to determine whether there is a correlation between percentage of vote and income

level at the 0.01 significance level with a null hypothesis of ρs = 0.

A) The test statistic is between the critical values, so we fail to reject the null hypothesis. There is no

evidence to support a claim of correlation between percentage of vote and income level.

B) The test statistic is not between the critical values, so we fail to reject the null hypothesis. There is no

evidence to support a claim of correlation between percentage of vote and income level.

C) The test statistic is between the critical values, so we reject the null hypothesis. There is sufficient

evidence to support a claim of correlation between percentage of vote and income level.

D) The test statistic is not between the critical values, so we reject the null hypothesis. There is sufficient

evidence to support a claim of correlation between percentage of vote and income level

Answers

Option C is correct. The test statistic is not between the critical values, so we reject the null hypothesis. There is sufficient evidence to support a claim of correlation between percentage of vote and income level.

How to find the correlation

The scatter plot is the plot that is used to show the correlation that is known to exist between the given data sets that is of interests. It helps by showing the existing relationship between the x values and the y values in the question.

When we look at the graph properly, if we are to rule a line we would find out that most of the data points in the equation fall under the line in the data set. This shows that there is high correlation between these two variables.

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Directions: Factor the following trinomials containing negative numbers. Follow the rules for operations with signed numbers to identify the correct binomial factors.

1. x2 + 6x - 7

2. x2 - 5x + 6

3. x2 - 6x - 7

4. x2 + 5x - 6

5. x2 + x - 12

6. x2 - 2x - 8

7. x2 - 4x - 5

8. x2 + 2x - 3

9. x2 - 16

10. x2 - x - 12

11. x2 -9x + 18

12. x2 -5x - 14

13. x2 - 7x + 10

14. x2 -11x + 24

15. x2 - x - 30

Answers

The factored form of the given quadratic expressions are

1. (x -1)(x +7)

2. (x -2)(x -3)

3. (x +1)(x -7)

4. (x -1)(x +6)

5. (x -3)(x +4)

6. (x +2)(x -4)

7. (x +1)(x -5)

8. (x -1)(x +3)

9. (x +4)(x -4)

10. (x +3)(x -4)

11. (x -3)(x -6)

12. (x +2)(x -7)

13. (x -2)(x -5)

14. (x -3)(x -8)

15. (x +5)(x -6)

Factoring quadratic expressions

From the question we are to factor the given quadratic expressions

1. x² + 6x - 7

x² +7x -x - 7

x(x +7) -1(x +7)

(x -1)(x +7)

2. x² -5x +6

x² -3x -2x +6

x(x -3) -2(x -3)

(x -2)(x -3)

3. x² -6x -7

x² -7x +x -7

x(x -7) +1(x -7)

(x +1)(x -7)

4. x² +5x -6

x² -x +6x -6

x(x -1) +6(x -1)

(x -1)(x +6)

5. x² + x - 12

x² +4x -3x -12

x(x +4) -3(x +4)

(x -3)(x +4)

6. x² -2x -8

x² -4x +2x -8

x(x -4) +2(x -4)

(x +2)(x -4)

7. x² -4x -5

x² -5x +x -5

x(x -5) +1(x -5)

(x +1)(x -5)

8. x² + 2x - 3

x² +3x -x -3

x(x +3) -1(x +3)

(x -1)(x +3)

9. x² - 16

(x +4)(x -4)

10. x² -x -12

x² -4x +3x -12

x(x -4) +3(x -4)

(x +3)(x -4)

11. x² -9x +18

x² -6x -3x +18

x(x -6) -3(x -6)

(x -3)(x -6)

12. x² -5x -14

x² -7x +2x -14

x(x -7) +2(x -7)

(x +2)(x -7)

13. x² -7x +10

x² -5x -2x +18

x(x -5) -2(x -9)

(x -2)(x -5)

14. x² -11x +24

x² -8x -3x +24

x(x -8) -3(x -8)

(x -3)(x -8)

12. x² -x -30

x² -6x +5x -30

x(x -6) +5(x -6)

(x +5)(x -6)

Hence, the factored form of the given quadratic expressions are

(x -1)(x +7)

(x -2)(x -3)

(x +1)(x -7)

(x -1)(x +6)

(x -3)(x +4)

(x +2)(x -4)

(x +1)(x -5)

(x -1)(x +3)

(x +4)(x -4)

(x +3)(x -4)

(x -3)(x -6)

(x +2)(x -7)

(x -2)(x -5)

(x -3)(x -8)

(x +5)(x -6)

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You need a 75 % alcohol solution. On hand, you have a 260 mL of a 30% alcohol mixture. You also have 95 % alcohol mixture . How much of the 95% mixture will you need to add to obtain the desired solution? You will need mL of the 95% solution

Answers

[tex]30 \: percent \: alcohol \: in \: 260 \: ml \\ alcohol = 0.3 \times 26 0= 78 \: ml[/tex]

[tex]c( \gamma ) = \frac{78 + 0.95\gamma }{260 + \gamma } \times 100[/tex]

[tex]c( \gamma ) = 75[/tex]

[tex] \frac{78 + 0.95\gamma }{260 + \gamma } = 0.75[/tex]

[tex]78 + 0.95\gamma = 0.75 \gamma + 195 \\ 0.2 \gamma = 117 \\ \gamma = 585[/tex]

[tex]we \: need \: 585 \: ml \: of \: 95% \: alcohol[/tex]

Answer:

You will need 585 mL of the 95% solution.

Step-by-step explanation:

The Black Pearl is following a course that is represented by the equation. + ? = 14. . The interception course of the Flying Dutchman is represented by the equation
Use the graphing method to determine the coordinate point where the two ships’ paths meet.

Answers

According to the graph, the ships’ paths do not meet at any point.

What are linear equations?

Linear equations are equations that have constant average rates of change, slope or gradient

How to determine the point where the two ships' path meet?

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

2x = 5y - 40

-4x + 10y = 20

Make y the subject in the second equation, by adding 4x to both sides of the equation

4x -4x + 10y = 20 + 4x

This gives

10y = 20 + 4x

Divide both sides by 10

y = 2 + 0.4x

Substitute y = 2 + 0.4x in 2x = 5y - 40

2x = 5(2 + 0.4x) - 40

Expand

2x = 10 + 2x - 40

Subtract 2x from both sides of the equation.

2x - 2x = 10 + 2x - 2x - 40

Evaluate the like terms

0 = 10 - 40

Evaluate the like terms

0 = -30

The above equation is not true.

This means that the ships’ paths do not meet at any point.

This can be confirmed using the attached graph.

From the graph, we can see that the lines of 2x = 5y - 40 and -4x + 10y = 20 do not intersect

Hence, we can conclude that the ships’ paths do not meet at any point.

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Use the following information collected in a town of fast food restaurants. 13 served hamburgers, 8 served roast beef sandwiches, 10 served pizza, 5 served hamburgers and roast beef sandwiches 3 served hamburgers and pizza, 2 served roast beef sandwiches and pizza, 1 served hamburgers, roast beef sandwiches and pizza, 5 served none of the three foods
a) Construct a Venn Diagram and put the correct numbers in the Venn diagram.
b) Find the Probabilities. P(pizza)= ___________
c) P (roast beef and pizza)=___________
d) P ( hamburgers, but not roast beef) =______________
e) P (only hamburgers) = ____________

Answers

Answer:

I don't know what are you saying bro


In 5-card poker, find the probability of being dealt the following hand. Refer to the table. Note that
a standard deck of playing cards has 52 cards-4 suits (clubs, diamonds, hearts, spades), where
each suit has 13 cards (Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King).
no pair
The probability of being dealt no pair is
(Type an integer or decimal rounded to eight decimal places as needed.)
Event E
Royal flush
Straight flush
Four of a kind
Full house
Flush
Straight
Three of a kind
Two pairs
One pair
No pair
Total
Number of
Outcomes
Favorable to E
4
36
624
3744
5108
10,200
54,912
123,552
1,098,240
1,302,540
2,598,960

Answers

The probability of being dealt no pair is 0.5011 or 50.11% if the tandard deck of playing cards has 52 cards-4 suits.

What is probability?

It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

It is given that:

In 5-card poker, find the probability of being dealt the following hand. Refer to the table.

From the table:

Total number of outcomes = 2598960

Total number of favourable outcomes = 1302540

The probability of being dealt no pair:

P(no pair) = 1302540/2598960

P(no pair) = 0.5011

In percentage:

P(no pair) = 50.11%

Thus, the probability of being dealt no pair is 0.5011 or 50.11% if the tandard deck of playing cards has 52 cards-4 suits.

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Please help! I am trying to do my homework but I am have trouble with these problems

Answers

The interpretation based on the confidence interval given is that the population mean will fall within the interval.

How to illustrate the information?

Number of observations = 10

Sample mean = 2.60

Standard deviation = 1.07

The degree of freedom will be:

= n - 1

= 10 - 1 = 9

Confidence level = 95% = 0.95

Level of significance = 1 - 0.95 = 0.05

The value of the t critical from the t table will be 2.262.

The margin of error will be:

= 2.262 × 1.07/✓10

= 0.765

We get the 95% confidence interval for the population mean. This will be:

(2.60 - 0.765( <= U =(2.60 + 0.765)

1.83 <= 3.37

Therefore, the interpretation is that the population mean will fall within the interval.

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Graph the line y+3x=-3​

Answers

Answer:  y = -3x-3 (Choose values for x)

Step-by-step explanation:

1st change the equation to y = mx+b form

In order to change the equation to y = mx+b form subtract the 3x to both sides.
The equation now becomes y = -3x-3

2nd we can either choose values for x such has (-2,-1,0,1,2) and plug in those values into our equation y = -3x-3
For example, if we plug in x= -2 we get y= -3(-2)-3 which becomes y =3. We then plot the point (-2,3) because -2 is our x coordinate and 3 is our y coordinate.
Or we can plug the equation into a calculator that will graph the equation for you.

What are the x- and y- coordinates of point E, which partitions the directed line segment from J to K into a ratio of 1:4?

Answers

The x- and y- coordinates of point E, which partitions the directed line segment from J to K into a ratio of 1:4 is (17, 11)

Midpoint of coordinate points

The midpoint of a line is the point that bisects or divides the line into two equal parts

If the line JK is partitioned into the ratio 1:4 with the following coordinates

J(-15, -5) and K(25, 15)

Using the expression below;

M(x, y) =[mx1+nx2/m+n, my1+ny2/m+n]

Substitute the ratio and the coordinates

M(x, y) =[1(-15)+4(25)/4+1, 1(-5)+4(15)/1+4]

M(x, y) = [(85)/5, 55/5]

M(x, y) = (17, 11)

Hence the x- and y- coordinates of point E, which partitions the directed line segment from J to K into a ratio of 1:4 is ((17, 11)

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There are 3
denominations of bills in a wallet: $1, $5, and $10.
There are 5 fewer $5-bills than $1-bills. There are half as many
$10-bills as $5-bills. If there is $115 altogether, find the number of
each type of bill in the wallet.

Answers

The number of $1, $5 and $10 are 49, 44 and 22 respectively.

How to use equation to find the number of bills?

There are 3 denominations of bills in a wallet: $1, $5, and $10.

There are 5 fewer $5-bills than $1-bills.

let

x = number of $1 bills

Hence,

number of $5 bills = x - 5

There are half as many $10-bills as $5-bills.

number of $10 bills = 1 / 2 (x - 5)

Therefore,

x + x - 5 + 1 / 2 (x - 5) = 115

2x - 5  + 1 / 2 x - 5 / 2 = 115

2x + 1 / 2 x - 5 - 5 / 2 = 115

5 / 2 x  - 7.5 = 115

2.5x  = 115 + 7.5

x = 122.5 / 2.5

x = 49

Number of $1 bills = 49

Number of $5 bills = 49 - 5 = 44

Number of $10 bills = 1 / 2 (49 - 5) = 22

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If $6,000 principal plus $132.90 of simple interest was withdrawn on August 14, 2011, from an investment earning 5.5% interest, on what day was the money invested?

Answers

[tex]~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$132.90\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 5.5\%\to \frac{5.5}{100}\dotfill &0.055\\ t=years \end{cases} \\\\\\ 132.90 = (6000)(0.055)(t)\implies \cfrac{132.90}{(6000)(0.055)}=t\implies \cfrac{443}{1100}=t \\\\\\ \stackrel{\textit{converting that to days}}{\cfrac{443}{1100}\cdot 365} ~~ \approx ~~ 147~days[/tex]

now, if we move back from August 14th by 147 days backwards, that'd put us on March 20th.

The population of a rabbit colony triples every 3 days. The population starts at 10 rabbits. Write an exponential function that will model the population of the colony after, t, days have passed.

Answers

Answer:

DO not working in you

Step-by-step explanation:

PLEASE help me in answering

Answer:

Step-by-step explanation:

The population at various days is as follows since population triples every 3 days

Day     Population

0          10

3          30

6          90

9          270

....         ......

This can be modeled by the general equation

[tex]n_{t} = n_{0}(r)^{t/k}[/tex]

where

[tex]n_{t}[/tex] is the population after t days

[tex]n_{0}[/tex] is the population at start (10)

[tex]r[/tex] is the rate at which population changes ie 3

[tex]t[/tex] is the number days from start

[tex]k[/tex] is the number of days at which the population triples(here k =3 days)

We can check this by plugging in values for each of the variables

At day 0, population = 10(3)⁰ = 10. 1 = 10

Similarly populations for days 3, 6, 9 are:

[tex]\\\\10.3^{3/3} = 10. 3^1 = 10.3 = 30\\10.3^{6/3} = 10. 3^2 = 10.9 = 90\\\\10.3^{9/3} = 10. 3^3 = 10.27 = 270[/tex]

THE NICHOLS ARE BUYING A HOUSE SELLING FOR $245,000. THEY PAY A DOWN
PAYMENT OF $45,000 FROM THE SALE OF THEIR CURRENT HOUSE. TO OBTAIN A 15-
YEAR MORTGAGE AT 4.5% INTEREST, THEY MUST PAY 1.5 POINTS AT THE TIME OF
CLOSING. WHAT IS THE AMOUNT OF THE MORTGAGE, AND WHAT IS THE COST OF
THE 1.5 POINTS

Answers

The amount of the mortgage on this house is given as $300000, while the 1.5 points on the house is given as 3000 dollars

How to solve for the mortgage that is on this house

The data from the questions says that the cost of the house = $245000

The down payment amount amount is 45000

Given that they already paid 45000 from the cost of the house, the mortgage would be 245000 - 45000

= $200000

The cost of 1.5 points is the same as the cost of 1.5% of the mortgage of this house.

This is calculated as 0.015 x 200000

= $3000

The conclusion is that the amount of the mortgage on this house is given as $300000, while the 1.5 points on the house is given as 3000 dollars

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120 high school seniors were asked,
"Are you going to the graduation
party?" Of those 120 students, 75 said yes. Estimate the population mean
that a senior will say they are going to the graduation party.

Answers

Using proportions, the estimate of the population percentage of seniors that will say they are going to the graduation party is of 62.5%.

What is a proportion?

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

The estimate of a population proportion is the sample proportion. In this problem, the sample proportion is of 75 out of 120 students, hence:

p = 75/120 = 0.625 = 62.5%.

The estimate of the population percentage of seniors that will say they are going to the graduation party is of 62.5%.

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Decimals from greatest to least
.750
.475
-0.123
.675
.253

Answers

Answer:

0.75, 0.675, 0.475, 0.253, -0.123

Step-by-step explanation:

Positive Numbers will always be greater than negative numbers, so you know -0.123 comes at the end.

Example

0.ABC

The tenth's place (A in the number above) holds the most weight. 0The hundreth's place (B in the number above) holds the second most weight. The thousandth's place (C in the number above) holds the third most weight.

Comparing 0.75 and 0.675 is the same as comparing 75 and 67.5. When in doubt, you can multiply the decimals by 100 to determine their order of value.

Classify each number below as an integer or not.

Answers

Using it's concept, the integer numbers in the data-set are given as follows:

6/1, -14, 56/7.

The other numbers, -74.48 and 3/17, are not integers.

What are integer numbers?

Integer numbers are numbers that have no decimal part. They can be represented by pure numbers, either negative or positive, or also fractions that result in an exact division.

In this problem, we have that:

The division of 6 by 1 has a exact result of 6, hence 6/1 is an integer.The division of 56 by 7 has a exact result of 8, hence 56/7 is an integer.-14 is a pure number with no decimal part, hence it is an integer.-74.48 has a decimal part, hence it is not an integer.3/17 is not an exact division, hence it is not an integer.

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What are the rational roots for the polynomial shown below?
x³ + 5x²-8r-20=0

Answers

[tex]x ^{3} + 5x {}^{2} - 8 r - 20 = 0 \\ x { }^{3} + 5x {}^{2} - 8r - 20(x {}^{3} + 5x {}^{2} ) = 0 - (x {}^{3} + 5x {}^{2} ) \\ - 8r - 20 = - (x {}^{3} + 5x {}^{2} ) \\ \\ - 8r - 20 + 20 = - (x {}^{3 } + 5x {}^{2} ) + 20 \\ \\ - 8r = x {}^{3} - 5x {}^{2} + 20 \\ \\ [/tex]

hope it is helpful

The graph shows a system of inequalities.

Graph of two inequalities. One is a dashed line increasing from left to right passing through negative 5 comma 0 and 0 comma 5, and it has shading above the line. The second is a dashed upward opening parabola with a vertex at negative 2 comma negative 9 and x-intercepts at negative 5 comma 0 and 1 comma 0. This parabola is shaded on the inside.

Which system is represented in the graph?

y > x2 + 4x – 5
y > x + 5
y < x2 + 4x – 5
y < x + 5
y ≥ x2 + 4x – 5
y ≤ x + 5
y > x2 + 4x – 5
y < x + 5

Answers

The system of inequalities having the given feasible regions and points at (-5, 0), and (0, 5), and (-2, -9), (-5, 0), and (1, 0) is the option;

y > x² + 4•x - 5

y > x + 5

How can the required system of inequalities be found?

The coordinates of the given points on the linear inequality are;

(-5, 0), and (0, 5)

Slope, m, of the linear inequality is therefore;

m = (5 - 0)/(0 - (-5)) = 1

The equation of the inequality is therefore;

y - 0 > 1•(x - (-5)) = x + 5

Which gives;

y > x + 5

Quadratic Inequality;

The coordinates of the points on the quadratic inequality are;

Vertex point = (-2, -9)

x-intercept = (-5, 0), and (1, 0)

Therefore, we have;

y > (x + 5)•(x - 1) = x² + 4•x - 5

y > x² + 4•x - 5

The correct option is therefore;

y > x² + 4•x - 5

y > x + 5

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Answer:

y > x2 + 4x – 5

y > x + 5

Step-by-step explanation:

If you put this system into desmos you will see that it matches the photo shown in the question, and it would need to be both greater than symbols because the dotted lines indicate that it is not included in the solution.

Database A contains 40 data items and is made up with an equal number of the values of 0 and 100 and has a mean of 50. Database B also has 40 entries made up equally of the values 49 and51 and also has a mean of 50. Which database will have the smaller value for its standard deviation?



Set A: 1 2 3 23 24 25

Set B: 9 10 11 14 16 18

Answers

If we compare the given values then we can find that the database B is more likely to have smaller standard deviation.

Given that the values in database A are 0 from 100 and has mean of 50 and Database B has entries from 49 to 51 and also has mean of 50.

We are required to find the database whose standard deviation is lower.

Standard deviation measures the variation of values. It is calculated after finding mean. The square of a standard deviation is known as variance.

Database A has values from 0 to 100 and has mean of 50. Because the values are somewhat very larger than 50 and in database B has values from 49 to 51,there are more chances that the standard deviation of database B will have smaller value than from standard deviation of database A.

Hence if we compare the given values then we can find that the database B is more likely to have smaller standard deviation.

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The GCF of 15 and 27 is _____.

Answers

Answer:

The answer is 3

Step-by-step explanation:

List all prime factors

15:1,3,5,

27:1,3,

Biggest one is 3

Answer:

the answer is 3

Step-by-step explanation:

cuz the prime factors of 27 is 1,3,and 27

while 15 is 1, 3 ,5 and 15

I hope this helps

find the x-intercept of the graph of the equation y=(x+2)(x-1)

Answers

Answer:-2,0 & 1,0

Step-by-step explanation:

Substitute them in with zero product property

A metallurgist has one alloy containing 26% copper and another containing 69% copper. How many pounds of each alloy must he use to make 53 pounds of a third alloy containing 50% copper?

Answers

The pounds of alloy that contains 26% copper that would be used is  23.42 pounds.

The pounds of alloy that contains 69% copper that would be used is 29.58 pounds.

What are the linear equations that represent the question

0.26a + 0.69b = (53 x 0.5)

0.26a + 0.69b = 26.50 equation 1

a + b = 53 equation 2

Where:

a =pounds of alloy that contains 26% copperb = pounds of alloy that contains 69% copper

How many pounds of each alloy should be in the third alloy?

Multiply equation 2 by 0.26

0.26a + 0.26b = 13.78 equation 3

Subtract equation 3 from equation 2

12.72 = 0.43b

b = 12.72 / 0.43

b = 29.58 pounds

a = 53 - 29.58 = 23.42 pounds

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Find a formula for the nth term in this
arithmetic sequence:
a₁ = 7, a2 = 4, a3 = 1, a4 = -2, ...
an
=
[?]n +

Answers

The formula for the nth term in this arithmetic sequence is:

-3n + 10

Answer:

[tex]a_{n} = -3n + 10[/tex]

Step-by-step explanation:

The arithmentic function formula is:

[tex]a_{n} = a_{1} + d(n-1)[/tex]

Let's plug in what we know. [tex]a_{1}[/tex] (the first term in our sequence) is 7. d (the common difference) is -3. This means we are subtracting 3 every time.

Plugging that in to the formula, we get

[tex]a_{n} = 7 -3(n-1)[/tex]

Now we distribute and combine like terms.

[tex]a_{n} = 7 - 3n +3[/tex]

[tex]a_{n} = 10 - 3n[/tex]

Change the order to fit the format and you get

[tex]a_{n} = -3n + 10[/tex]

What's the forecasted capital expenditure based on the information below? • Net PP&E beginning of period: 15,000 • Net PP&E end of period: 17,500 Depreciation expenses: 2,400​

Answers

The forecasted capital expenditure related to the information below exists at 4,900.

Therefore, the correct answer is option b) 4,900.

What is Capital?

Capital exists directed as the lifeblood of any business. It exists the group of assets of the business that contains their financial value to create the production of goods and services.

For calculating the forecasted capital-

Net PP&E beginning of period = 15,000

Net PP&E end of period = 17,500

Depreciation expenses = 2,400

Forecasted capital expenditure = Net PP&E end of period + Depreciation expenses - Net PP&E beginning of the period

= 17500 + 2400 - 15,000

Forecasted capital expenditure = 4,900

Therefore, the correct answer is option b) 4,900.

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The complete question is:

What’s the forecasted capital expenditure based on the information below?

Net PP&E beginning of period: 15,000

Net PP&E end of period: 17,500

Depreciation expenses: 2,400

Review Later

a) 2,500

b) 4,900

c) 100

d) -100

1. If A = {a, b, c, d}, B={c, d, e, f}, C={x, y, z} find (A-B)​

Answers

Answer

here

A={a,b,c,d}

B={c,d,e,f}

C={x,y,z}

A-B={e,f}

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