PLEASE HELP IM STUCK PLS

We can rewrite the given time as:

First, remember that:

60s = 1 min

Then to write that amount in minutes, we just need to divide by 60, so we get:

(4.22x10^17)/60  mins=  7.03x10^15 mins

Now, remember that:

1 hour = 3600s

Then to get the time in hours, we need to divide by 3600:

(4.22x10^17)/3600 h = 1.17x10^14 hours.

Similarly, you can change to any time unit that you want, for example:

1 day = 24*3600 s

Then the time in days is:

(4.22x10^17)/(24*3600) days = 4.88x10^12 days.

And so on.

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Answer:

7/5

Step-by-step explanation:

The area around the given curve according to the green theorem is [tex]F. dr = 0[/tex].

According to the statement

we have to find the area enclosed by the simple closed curve that encloses the origin.

So, We know that the

The given equation is

[tex]f(x,y) = \frac{2xyi + (y^{2} - x^{2} ) j}{(x^{2} + y^{2} )^{2} }[/tex]

and

If function is in form of,

[tex]F = Pi + Qj[/tex]

and C is any positively oriented simple closed curve that encloses the origin.

Then,by use of Green's theorem

Do the partial differentiation of the given function

Then

[tex]\frac{dQ}{dx} = \frac{2x^{3} - 6xy^{2}}{(x^{2} + y^{2} )^{3}}[/tex]

and

[tex]\frac{dP}{dy} = \frac{2x^{3} - 6xy^{2}}{(x^{2} + y^{2} )^{3}}[/tex]

On substitution in Green's theorem,

We get the value

[tex]F. dr = 0[/tex]

From this it is clear that the area around the given curve is zero.

So, The area around the given curve according to the green theorem is [tex]F. dr = 0[/tex].

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In step 2, the property of equality applied was addition property of equality.

In step 4, the property of equality applied was multiplication property of equality.

The addition property of equality states that, to move a negative number over to the other side of an equation, add the number to both sides of the equation. For example, given the equation: a - c = b, to move c over to the other side of the equation, add c to both sides of the equation. we will have:

a - c + c = b + c

a = b + c.

According to the multiplication property of equality, if we have, a/c = b, to isolate a, we would multiply both sides of the equation by c. Thus:

a/c × c = b × c

a = bc

In the table given, in step 2, 6 was added to both sides of the equation. This means the property of equality that was applied was: addition property of equality.

In step 4, both sides of the equation was multiplied by -2. Thus, the property of equality that was applied was: multiplication property of equality.

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Answer: step 2 - addition property

              step 4 - multiplication property

Step-by-step explanation:

Based on the given data; the table represent an inverse variation and the equation that model the data in the table is y = 8/x

y = k × x

4 = k × 2

4 = 2k

k = 4/2

k = 2

when y = 2 and x = 4

y = k × x

= 2 × 4

y = 8

y = k/x

4 = k / 2

8 = k

when y = 2 and x = 4

y = k/x

2 = k/4

2 × 4 = k

k = 8

So,

y = k/x

y = 8/x

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Given

[tex]f(x) = \begin{cases} -x^2 - 1 & \text{if }x \neq 5 \\ -3 & \text{if }x=5 \end{cases}[/tex]

we have

[tex]\displaystyle \lim_{x\to5} f(x) = \lim_{x\to5} (-x^2-1) = -5^2-1 = \boxed{-26}[/tex]

since we are approaching [tex]x=5[/tex], so effectively [tex]x\neq 5[/tex] and we use the definition of [tex]f(x)[/tex] under that condition.

Answer:

D

Step-by-step explanation:

When you reflect the point it goes to point (-2,5).  From that point, go 4 left and 8 down.  That gets you to (-2,-3)

The value of [tex](102)^3[/tex] exists 1061208.

Let us rewrite [tex](102)^3[/tex] as [tex](100+2)^3[/tex]

Now utilizing the identity [tex](a+b)^3=a^3+b^3+3ab(a+b)[/tex], we get

a = 100 and b = 2 then substitute the values of a and b then

[tex](100+2)^3=100^3+2^3+[(3\times100\times2)(100+2)][/tex]

= 1000000 + 8 + (600 × 102)

= 1000000 + 8 + 61200

= 1061208

Hence, [tex](102)^3=1061208[/tex]

Therefore, the value of [tex](102)^3[/tex] exists 1061208.

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In four days,the total change in value -$12.60.

According to the statement

we have given that the value of an investment changed at a rate of -$3.15 each day. And we have to find that the after how many days the change in value reaches at the -$12.60.

So, here we use division rule to find the solution.

The given change value is :

-$3.15 each day.

The desired change value is :

-$12.60.

Number of days required = -12.60 / -3.15

Number of days required = 12.60 / 3.15

Number of days required = 4 days.

So, in four days the change in value reaches at the desired value of change.

So, In four days,the total change in value -$12.60.

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Answer:

The function is increasing from x = 0 to x = 1.

Step-by-step explanation:

A function is increasing when the y-value increases as the x-value increases.

A function is decreasing when the y-value decreases as the x-value increases.

From x = -2 to x = -1 the function is decreasing as the y-value decreases as the x-value increases:  

From x = -1 to x = 0 the function is increasing as the y-value increases as the x-value increase:  

From x = 0 to x = 1 the function is increasing as the y-value increases as the x-value increase:  

P(A and B) expressed in the simplest form is (B) 2/21.

To express P(A and B) in the simplest form:

Therefore, P(A and B) expressed in the simplest form is (B) 2/21.

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The complete question is given below:

A bag contains 4 black tiles, 5 white tiles, and 6 blue tiles. Event A is defined as drawing a black tile from the bag on the first draw, and event B is defined as drawing a white tile on the second draw.

If two tiles are drawn from the bag, one after the other without replacement, what is P(A and B) expressed in the simplest form?

A. 4/45

B. 2/21

C. 4/15

D. 5/14

[tex]\boldsymbol{\sf{Therefore \to \ 5.75\not{h}*\dfrac{60 \ min}{1\not{h}} =345 \ min }}[/tex]

5.75 hours is equal to 345 minutes.

Correct answer is C. the number of times blue ball appears is 56

Given,

probability of picking a green ball is 0.5,

the probability of picking a blue ball is 0.4,

the probability of picking a red ball is 0.1.

a ball is picked and replaced = 140

Probability = (the number of ways of achieving success) / (the total number of possible outcomes)

Probability provides information about the likelihood that something will happen. Meteorologists, for instance, use weather patterns to predict the probability of rain. In epidemiology, probability theory is used to understand the relationship between exposures and the risk of health effects.

For this item, the number of times that we should expect that a blue ball is picked should be the product of the number of times  and the probability of picking a blue ball (which is equal to 0.4)

                            = (140)(0.4) = 56

Therefore, we should expect that the blue ball will be picked 56 times.

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Answer:

2, x - 2, x + 4

Step-by-step explanation:

The factors of the given quadratic expression, 2x² - 4x - 16, are 2, (x +2), and (x -4)

From the question, we are to determine the each of the factors of the given quadratic expression

The given quadratic expression is

2x² - 4x - 16

Factoring

2x² - 4x - 16

First, factor out 2

That is,

2(x² - 2x - 8)

Now, we will factor x² - 2x - 8
x² - 2x - 8

x² - 4x + 2x - 8

x(x - 4) +2(x -4)

(x +2)(x -4)

Thus,

2x² - 4x - 16  = 2(x +2)(x -4)

Hence, the factors of the given quadratic expression, 2x² - 4x - 16, are 2, (x +2), and (x -4)

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The focus of a parabola can be found by adding p to the y-coordinate k if the parabola opens up or down. (h, k + p) exist (2, 0).

Given: [tex]$y=\frac{1}{8} (x^{2} -4x-12)[/tex]

[tex]$y=\frac{x^{2}}{8}-\frac{x}{2}-\frac{3}{2}$$[/tex]

Use the form [tex]$a x^{2}+b x+c$[/tex] to find the values of a, b, and c.

[tex]$a=\frac{1}{8}$[/tex], [tex]$b=-\frac{1}{2}$[/tex] and [tex]$c=-\frac{3}{2}$[/tex]

Consider the vertex form of a parabola [tex]$a(x+d)^{2}+e$[/tex]

To estimate the value of d using the formula [tex]$d=\frac{b}{2 a}$[/tex].

Substitute the values of a and b into the formula

[tex]$d=\frac{-\frac{1}{2}}{2\left(\frac{1}{8}\right)}$$[/tex]

[tex]$d=-\frac{1}{2} \cdot \frac{1}{\frac{2}{8}}$$[/tex]

Cancel the common factor 2 and 8.

[tex]$d=-\frac{1}{2} \cdot \frac{1}{\frac{1}{4}}$$[/tex]

[tex]$d=-\frac{1}{2}(1 \cdot 4)$$[/tex]

Multiply the numerator by the reciprocal of the denominator.

[tex]$d=-\frac{1}{2} \cdot \frac{1}{2\left(\frac{1}{8}\right)}$$[/tex]

[tex]$d=-\frac{1}{2} \cdot \frac{1}{\frac{2}{8}}$$[/tex]

equating, we get

[tex]$d=-\frac{1}{2}(1 \cdot 4)$$[/tex]

[tex]$d=-\frac{1}{2} \cdot 4$$[/tex]

The value of [tex]$d=-2$[/tex]

Find the value of e using the formula [tex]$e=c-\frac{b^{2}}{4 a}$[/tex].

Substitute the values of c, b and a into the above formula, and we get

[tex]$e=-\frac{3}{2}-\frac{\left(-\frac{1}{2}\right)^{2}}{4\left(\frac{1}{8}\right)}$$[/tex]

simplifying the equation, we get

[tex]$e=-\frac{3}{2}-\frac{(-1)^{2}\left(\frac{1}{2}\right)^{2}}{4\left(\frac{1}{8}\right)}$[/tex]

Apply the product rule to [tex]$\frac{1}{2}$[/tex].

[tex]$e=-\frac{3}{2}-\frac{1\left(\frac{1}{4}\right)}{4\left(\frac{1}{8}\right)}$$[/tex]

[tex]$e=-\frac{3}{2}-\frac{\frac{1}{4}}{4\left(\frac{1}{8}\right)}$$[/tex]

[tex]$e=-\frac{3}{2}-\frac{\frac{1}{4}}{\frac{4(1)}{8}}$$[/tex]

simplifying the above equation, we get

[tex]$e=-\frac{3}{2}-\frac{\frac{1}{4}}{\frac{4 \cdot 1}{4 \cdot 2}}$$[/tex]

[tex]$e=-\frac{3}{2}-\frac{\frac{1}{4}}{\frac{4 \cdot 1}{4 / 2}}$$[/tex]

[tex]$e=-\frac{3}{2}-\frac{\frac{1}{4}}{\frac{1}{2}}$$[/tex]

Multiply the numerator by the reciprocal of the denominator.

[tex]$e=-\frac{3}{2}-\left(\frac{1}{4} \cdot 2\right)$$[/tex]

[tex]$e=\frac{-3-1}{2}$$[/tex]

[tex]$e=\frac{-4}{2}=2$[/tex]

Substitute the values of [tex]$a, d_{t}$[/tex] and e into the vertex form [tex]$\frac{1}{8}(x-2)^{2}-2$[/tex].

Set y equal to the new right side.

[tex]$y=\frac{1}{8} \cdot(x-2)^{2}-2$[/tex]

Use the vertex form, [tex]$y=a(x-h)^{2}+k$[/tex], to determine the values of a, h, and k.

[tex]$a=\frac{1}{8}$[/tex]

[tex]$h=2$[/tex]

[tex]$k=-2$[/tex]

Find the vertex [tex]$(h, k)$[/tex]

[tex]$(2,-2)$[/tex]

Find [tex]$\boldsymbol{p}$[/tex], the distance from the vertex to the focus.

To estimate the distance from the vertex to a focus of the parabola [tex]$\frac{1}{4 a}$[/tex]

Substitute the value of a into the formula

[tex]$\frac{1}{4 \cdot \frac{1}{8}}=\frac{1}{\frac{4(1)}{8}}$[/tex]

[tex]$\frac{1}{\frac{4 \cdot 1}{4-2}}=\frac{1}{\frac{4 \cdot 1}{4 \cdot 2}}$[/tex]

[tex]$\frac{1}{\frac{1}{2}}=2$[/tex]

The focus of a parabola can be found by adding p to the y-coordinate k if the parabola opens up or down. (h, k + p)

Substitute the known values of h, p, and k into the formula, we get

(2,0).

Therefore, the correct answer is (2,0).

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The order of magnitude for total attended for a high school football team is 3

The given parameters are:

Average number of fan = 1000

Number of home games = 5

The total number of fans in the 5 games is:

Total number of fans = Average number of fan * Number of home games

Substitute known values in the above equation

Total number of fans = 1000 * 5

Express 1000 as 10^3

Total number of fans = 10^3 * 5

Rewrite the equation as:

Total number of fans = 5 * 10^3

The power of 10 represents the order of magnitude

Since the power of 10 is 3, the order of magnitude is 3

Hence, the order of magnitude for total attended for a high school football team that averages 1,000 fans for each of its 5 home games is 3

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Answer:

6.75

Step-by-step explanation:

         Distance in Miles

MPH -------------------------

         Time in Hours

27/2 = 13.5. That is 1 hour. Half that and you get 6.75 MP1/2H

Natasha got the power right. The power is 295 hp.

t = 5.825∛w / p

where,

Therefore,

t = 13.4 s

p = 3590

13.4 = 5.825∛ 3590 / p

cube both sides

13.4³ = 5.825³ × 3590 / p

2406.104 = 197.645890625 × 3590 / p

cross multiply

2406.104 p = 709548.747344

p = 709548.747344 / 2406.104

p = 294.895294361

p = 295 hp

Therefore, Natasha got the power right

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Answer: 6328723894

Step-by-step explanation:

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{Formula \rightarrow \dfrac{1}{2} \times \bold{b}ase\times\bold{h}eight\times \bold{l}ength}[/tex]

[tex]\mathsf{Your\ equation\ should\ look\ like\rightarrow \dfrac{1}{2}\times12\times8\times27}[/tex]

[tex]\mathsf{Solving\rightarrow \dfrac{1}{2}\times12\times8\times27}[/tex]

[tex]\mathsf{ \dfrac{1}{2}\times12\times8\times27}[/tex]

[tex]\mathsf{= \dfrac{1}{2}\times\dfrac{12}{1}\times\dfrac{8}{1}\times\dfrac{27}{1}}[/tex]

[tex]\mathsf{= \dfrac{1\times12\times8\times27}{2\times1\times1\times1}}[/tex]

[tex]\mathsf{= \dfrac{12\times8\times27}{2\times1\times1}}[/tex]

[tex]\mathsf{= \dfrac{96\times27}{2\times1}}[/tex]

[tex]\mathsf{= \dfrac{2,592}{2}}[/tex]

[tex]\mathsf{= 2.592\div2}[/tex]

[tex]\mathsf{= 1,296}[/tex]

[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{Option\ C.\ }\frak{1,296\ cm^3}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer:

51   74

Step-by-step explanation:

x = smaller

x +23 = larger

added together   (x   + x+23)    equal to 28 less than 3x      = 3x-28

x    + x+23  = 3x-28      subtract 2x from both sides of the equation

   23 = x -28      add 28 to both sides

 51 = x      then the larger   =  51 + 23 = 74

Answer:

51 and 74

Step-by-step explanation:

Let the smaller of the two numbers be represented by x. The larger of the two numbers is 23 greater than the smaller, and therefore can be written as x + 23.

First, we can write the sum of the two numbers in terms of the smaller number. "three times the smaller" is 3x, and "28 less" is 3x-28.

Therefore our equation is:

[tex]x+x+23=3x-28[/tex]

Start by adding like terms

[tex]2x+23=3x-28[/tex]

Subtract 23 from both sides

[tex]2x=3x-51[/tex]

Subtract 3x from both sides

[tex]-x=-51[/tex]

Divide both sides by -1

[tex]x=51[/tex]

The larger term is: [tex]x+23\Rightarrow51+23\Rightarrow74[/tex]

[tex]51+74=125[/tex]

[tex]3(51)-28=153-28=125[/tex]

[tex]125=125[/tex]

The smaller number is 51 and the larger number is 74

Recall the binomial theorem.

[tex](a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k[/tex]

1. The binomial expansion of [tex]\left(1+\frac x3\right)^7[/tex] is

[tex]\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}[/tex]

Observe that

[tex]k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x[/tex]

[tex]k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2[/tex]

When we multiply these by [tex]8-9x[/tex],

• [tex]8[/tex] and [tex]\frac73 x^2[/tex] combine to make [tex]\frac{56}3 x^2[/tex]

• [tex]-9x[/tex] and [tex]\frac73 x[/tex] combine to make [tex]-\frac{63}3 x^2 = -21x^2[/tex]

and the sum of these terms is

[tex]\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}[/tex]

2. The binomial expansion is

[tex]\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k[/tex]

We get the [tex]a^6b^2[/tex] term when [tex]k=2[/tex] :

[tex]k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2[/tex]

Using it's definitions, the five-number summary and the interquartile range for the data-set is given as follows:

This data-set has 12 elements, which is an even number, hence the median is the mean of the 6th and 7th elements, as follows:

Me = (19 + 23)/2 = 21.

The first quartile is the median of 6, 7, 8, 8, 16, which is the third element of 8.

The third quartile is the median of 23, 24, 26, 27, 34, 35, which is of 27. Hence the interquartile range is of 27 - 8 = 19.

The minimum is the lowest value in the data-set, which is of 6, while the maximum is of 35, which is the largest value in the data-set.

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Answer:

  x = 3√3

  y = 6

Step-by-step explanation:

The geometric mean relations between segments intersecting the long hypotenuse and its parts can be used to find the values of interest.

  x = √(9·3) = 3√3

  y = √((9+3)·3) = 6

__

Additional comment

These right triangles are all similar, so corresponding sides are proportional. When the proportions are solved for a missing side, a geometric mean relation results. (The geometric mean of 'a' and 'b' is √(ab).)

Identify the segments above the horizontal line as w, x, y. (x and y are already identified in this figure.)

The ratio of short side to long side is ...

  x/9 = 3/x   ⇒   x² = 9·3   ⇒   x = √(9·3)

The ratio of short side to hypotenuse is ...

  y/(9+3) = 3/y    ⇒   y² = (9+3)·3   ⇒   y = √((9+3)·3)

Likewise, the ratio of long side to hypotenuse is ...

  w/(9+3) = 9/w   ⇒   w² = (9+3)·9   w = √((9+3)·9) = 6√3

The number of boys wear glasses are 156 boys.

In this question,

Total number of pupils in the school = 910

Ratio of boys = 3/7

Then, number of boys = 910 × 3/7

⇒ 130 × 3

⇒ 390

Ratio of boys wear glasses = 2/5

Then, number of boys wear glasses = 390 × 2/5

⇒ 78 × 2

⇒ 156

Hence we can conclude that the number of boys wear glasses are 156 boys.

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The sum of the given expression expressed as a quadratic equation is 10x^2 + 13x + 11

Expressions are equations separated by mathematical signs. This expressions are known to contains certain unknowns

Given the following expression

10x^2 +7x+6 and 6x + 5

We are to take the sum of both expression to have:

f(x) = 10x^2 +7x+6 + 6x + 5

Collect the like terms

f(x) = 10x^2 + 7x + 6x + 6 + 5

f(x) = 10x^2 + 13x + 11

Hence the sum of the given expression expressed as a quadratic equation is 10x^2 + 13x + 11

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Answer: Choice D

[tex]\frac{-19}{\text{x}-5}[/tex]

=================================================

Work Shown:

[tex]\frac{\text{x}^2+10\text{x}+25}{\text{x}+5} - \frac{\text{x}^2-6}{\text{x}-5}\\\\\\\frac{(\text{x}+5)(\text{x}+5)}{\text{x}+5} - \frac{\text{x}^2-6}{\text{x}-5}\\\\\\\frac{\text{x}+5}{1} - \frac{\text{x}^2-6}{\text{x}-5}\\\\\\\frac{(\text{x}+5)(\text{x}-5)}{1(\text{x}-5)} - \frac{\text{x}^2-6}{\text{x}-5}\\\\\\[/tex]

[tex]\frac{\text{x}^2-25}{\text{x}-5} - \frac{\text{x}^2-6}{\text{x}-5}\\\\\\\frac{\text{x}^2-25-(\text{x}^2-6)}{\text{x}-5}\\\\\\\frac{\text{x}^2-25-\text{x}^2+6}{\text{x}-5}\\\\\\\frac{-19}{\text{x}-5}\\\\\\[/tex]

This matches with choice D as the final answer.

Keep in mind that we can only subtract fractions when the denominator is the same. The rule is [tex]\frac{a}{c}-\frac{b}{c} = \frac{a-b}{c}[/tex]

2r + t + r

3r + t

The correct answer is C - None of the Above.

When we combine like terms, we combine terms that have the same variables but different coefficients. We cannot add 2r and t because r and t are not the same variables.

Hope this helps!

Answer:

None of the above

Step-by-step explanation:

Because the answer is 3r + t