Using Chebyshev's Theorem, we are guaranteed to find at least 75% of the people earning hourly wages between $4.15 and $23.23.
What does Chebyshev’s Theorem state?When the distribution is not normal, Chebyshev's Theorem is used. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.At least 89% of the measures are within 3 standard deviations of the mean.An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]100(1 - \frac{1}{k^{2}})[/tex].In this problem, we want the values within 2 standard deviations of the mean, hence the values are:
13.69 - 2 x 4.77 = $4.15.13.69 + 2 x 4.77 = $23.23.More can be learned about Chebyshev's Theorem at https://brainly.com/question/25303620
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Use the distributive property to simplify the expression.
-6(2²+3)-2(1²-2)
A. 4² +22
B. 4:² +14
C. -8²-22
D. -8:²-14
[tex] \huge\mathbb{ \underline{SOLUTION :}}[/tex]
Given:[tex]\bold{-6(2^2+3)-2(1^2-2)}[/tex][tex]\\[/tex]
The [tex]\mathrm{distributive \: property}[/tex] states that an expression that is given in the form of [tex]\small\sf{ A(B + C)}[/tex] can be solved as [tex]\small\sf{A \times (B + C) = AB + AC}[/tex] . So:
[tex]\small\longrightarrow\sf{-24-18-2+4}[/tex]
[tex]\small\longrightarrow\sf{-42+2}[/tex]
▪ [tex]\large\tt{All \: \: options \: \: are \: \: wrong}[/tex]
[tex]\\[/tex]
[tex]\huge \mathbb{ \underline{ANSWER:}}[/tex]
[tex]\small\longrightarrow\sf{−6 (2^2+3) − 2 (1^2 - 2) = \underline{-6(4+3)}}[/tex]
A 400 L tank is filled with pure water. A copper sulfate solution with a concentration of 20 g/L flows into the tank at a rate of 4 L/min. The thoroughly mixed solution is drained from the tank at a rate of 4 L/min. a. Write a differential equation (initial value problem) for the mass of the copper sulfate. b. Solve the differential equation
(a) Let [tex]C(t)[/tex] denote the amount (in grams) of copper (II) sulfate (CuSO₄) in the tank at time [tex]t[/tex] minutes. The tank contains only pure water at the start, so we have initial value [tex]\boxed{C(0)=0}[/tex].
CuSO₄ flows into the tank at a rate
[tex]\left(20\dfrac{\rm g}{\rm L}\right) \left(4\dfrac{\rm L}{\rm min}\right) = 80 \dfrac{\rm g}{\rm min}[/tex]
and flows out at a rate
[tex]\left(\dfrac{C(t)\,\rm g}{400\,\mathrm L + \left(4\frac{\rm L}{\rm min} - 4\frac{\rm L}{\rm min}\right) t}\right) \left(4\dfrac{\rm L}{\rm min}\right) = \dfrac{C(t)}{100} \dfrac{\rm g}{\rm min}[/tex]
and hence the net rate of change in the amount of CuSO₄ in the tank is governed by the differential equation
[tex]\boxed{\dfrac{dC}{dt} = 80 - \dfrac C{100}}[/tex]
(b) This ODE is linear with constant coefficients and separable, so we have a few choices in how we can solve it. I'll use the typical integrating factor method for solving linear ODEs.
[tex]\dfrac{dC}{dt} + \dfrac C{100} = 80[/tex]
The integrating factor is
[tex]\mu = \exp\left(\displaystyle \int \frac{dt}{100}\right) = e^{t/100}[/tex]
Distributing [tex]\mu[/tex] on both sides gives
[tex]e^{t/100} \dfrac{dC}{dt} + \dfrac1{100} e^{t/100} C = 80 e^{t/100}[/tex]
and the left side is now the derivative of a product,
[tex]\dfrac d{dt} \left[e^{t/100} C\right] = 80 e^{t/100}[/tex]
Integrate both sides. By the fundamental theorem of calculus,
[tex]e^{t/100} C = e^{t/100}C\bigg|_{t=0} + \displaystyle \int_0^t 80 e^{u/100}\, du[/tex]
The first term on the right vanishes since [tex]C(0)=0[/tex]. Then
[tex]e^{t/100} C = 8000 \left(e^{t/100} - 1\right)[/tex]
[tex]\implies \boxed{C(t) = 8000 - 8000 e^{-t/100}}[/tex]
In a scale drawing of a painting, 2 centimeters represents 7 inches.
The height of the real painting is 35 inches. What is the height of the painting in the scale drawing?
The height of the painting in the scale drawing is 10 centimeters if the height of the real painting is 35 inches given that in a scale drawing of a painting, 2 centimeters represents 7 inches. This can be obtained by using the ratio of scale drawing to the real drawing.
Find the height of the painting in the scale drawing:Here in the question it is given that,
In a scale drawing of a painting, 2 centimeters represents 7 inchesThe height of the real painting is 35 inchesThus we can say that, scale of the painting is 2 cm : 7 in
Ratio of scale drawing and real painting is 2 : 7
⇒ Similarly here height of the painting in the scale drawing to the height of the painting in the real drawing will be in the ratio 2 : 7.
We can say that,
2 cm/7 in = x cm/35 in
where x is the height of the painting in the scale drawing
2 cm × 35 in /7 in = x cm
x = 2 × 5 cm
x = 10 cm
Hence the height of the painting in the scale drawing is 10 centimeters if the height of the real painting is 35 inches given that in a scale drawing of a painting, 2 centimeters represents 7 inches.
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Please help and explain!!!
Answer:
Option A
Step-by-step explanation:
The solution is in the image
a homeowner has budgeted $10,000 for some home remodeling. a contractor has told him the labor and the cost of materials will be about the same amount. the homeowner wants to have about $3,000 left over for furnishings. how much will the homeowner be able to spend on labor and on materials?
Answer:
$3,500 labor and $3,500 materials
Step-by-step explanation:
furnishings + labor + materials = 10,000
furnishings = 3000
3000 + labor + materials = 10,000
labor = materials
3000 + labor + labor = 10,000
2(labor) = 7,000
labor = 7,000/2
labor = 3,500
labor = materials = 3,500
What is the scale factor of the dilation shown ?
Work Shown:
k = scale factor
k = (A'B')/(AB)
k = 8/12
k = (4*2)/(4*3)
k = 2/3
Triangle A'B'C' (image) has side lengths that are 2/3 as long compared to the side lengths of triangle ABC (preimage).
What type of construction is illustrated in the figure?
A
The bisection of ∠D
B
A line segment congruent to segment AB
C
An angle congruent to ∠D
D
The bisection of segment BD
Option A is correct. The type of construction that we have here is the bisection of the <D.
What is the bisection of an angle?The bisection of angle can be defined to be the construction of a ray that would help to divide a particular angle into two equal halves.
In this diagram we can see that the angle here is at D. Hence the construction is aimed at dividing this particular angle into 2. Therefore the answer to the question is The bisection of ∠D.
The bisector does the job of creating an equal measure. The given bisector is known to have the midpoint of the segment. It cuts through this angle and creates two different angles that are of the same size.
If we draw the line in that shape, we will be having the division of that angle. From the explanation here, we can see the answer is the first option
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Pls help me answer this question3 x 2 2/5
Answer:
7 1/5
Step-by-step explanation:
ANSWER ASAP!
what is the value of a₁₇ if a₁₃=26 and the recursive form of a geometric sequence is aₙ=1/2aₙ₋₁
please answer with atleast some detail
The 17th term of the geometric sequence given in the problem is:
[tex]a_{17} = \frac{13}{8}[/tex]
What is a geometric sequence?A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.
The nth term of a geometric sequence is given by:
[tex]a_n = a_1q^{n-1}[/tex]
In which [tex]a_1[/tex] is the first term.
As a function of the mth term, the nth term can also be given as follows:
[tex]a_n = a_mq^{n - m}[/tex]
In this problem, we have that:
[tex]a_{13} = 26, q = \frac{1}{2}[/tex]
Hence the 17th term is:
[tex]a_{17} = a_{13}q^{4}[/tex]
[tex]a_{17} = 26 \times \frac{1}{16}[/tex]
[tex]a_{17} = \frac{13}{8}[/tex]
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Find the area of a circle with a diameter of 16.
Either enter an exact answer in terms T or use 3.14 for TT and enter your answer as a decimal
Answer:
Step-by-step explanation:
Area of circle:
area = π · r · r
Radius= [tex]\frac{16}{2}[/tex]= 8
[tex]3.14\times { 8 }^{ 2 }[/tex] = 200.96 [tex]cm^2\\[/tex]
Test the claim that the proportion of people who own cats is larger than 60 t the 0. 10 significance level?
The null hypothesis to test the claim that the proportion of people who owns cats is larger than 60% of the significance level is [tex]H_{0}[/tex]:μ<0.06.
Given that the significance level is 0.10.
We are required to form the null hypothesis to test the claim that the proportion of people who owns cats is larger than 60% the significance level.
Hypothesis is a statement which is tested for its validity. Null hypothesis is the statement which is accepted or not by z test,t test,f test ,chi-square test or any other test.
We have to take opposite of the statement to form a null hypothesis. Since we have to check whether the proportion of people who owns cats is larger than 60% of the significance level, we have to assume that it is smaller than 60% of the significance level.
60% of the significance level=0.60*0.10=0.06.
Null hypothesis is [tex]H_{0}[/tex]:μ<0.06
Hence the null hypothesis to test the claim that the proportion of people who owns cats is larger than 60% of the significance level is [tex]H_{0}[/tex]:μ<0.06.
Question is incomplete.The question should include the following:
Find the null hypothesis for the testing.
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Which describes the combined variation shown in the equation F = kxy/z?
1) F varies directly with x, and inversely with y
and z.
2)F varies directly with z, and inversely with x
and y.
3)F varies directly with y, and inversely with x and z.
4) F varies directly with x and y, and inversely
with z.
Answer:
option 4
Step-by-step explanation:
F = [tex]\frac{kxy}{z}[/tex]
k is the constant of variation
• if the variables are on the numerator they vary directly
• if the variables are on the denominator they vary inversely
In this case F varies directly with x and y ( variables on numerator ) and inversely with z ( variable on denominator )
S is a geometric sequence.
a) (√x + 1), 1 and (√x-1) are the first three terms of S.
Find the value of x.
You must show all your working.
How much money do I need now if I am going to recieve $5000 every 6 months (starting in 6 months) for 10 years if the interest rates are 4%/a compounded semi-annually?
By using the compound interest model, the initial deposit required to receive $ 5 000 every 6 months is $ 125 000.
How many money should be deposited in the beginning to receive a certain amount periodically
In this problem we must apply the compound interest model, which represent a periodic accumulation of interest according to the following formula:
C' = C · (1 + r/100)ˣ (1)
Where:
C - Initial depositr - Interest rateC' - Resulting moneyx - Period indexIf we know that x = 1, r = 4, C = x and C' = x + 5 000, then the initial deposit is:
x + 5 000 = x · (1 + 4/100)
x + 5 000 = 1.04 · x
0.04 · x = 5 000
x = 125 000
By using the compound interest model, the initial deposit required to receive $ 5 000 every 6 months is $ 125 000.
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The average of 15,19,23,41,and Z is 20. What is the value of x
The value of x from the given data is 2
Calculating the average of numbersMean is the ratio of sum of numbers to the total samples. Given the following data
15,19,23,41, and Z
The mean is calculated as
Mean = 15+19+23+41+z/5
Since the mean the of the data is given as 20. Substitute
20 = 15+19+23+41+z/5
Cross multiply
20*5 = 15+19+23+41+z
100 = 15+19+23+41+z
100 = 98 + z
z = 100- 98
z = 2
Hence the value of x from the given data is 2
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Evaluate the integral.
√
S-
5
√x (4+5√x)²
2
dx
Substitute [tex]y=4+5\sqrt x[/tex] and [tex]dy=\frac5{2\sqrt x}\,dx[/tex]. Then the integral is
[tex]\displaystyle \int \frac5{\sqrt x (4+5\sqrt x)^2} \, dx = 2 \int \frac{1}{(4+5\sqrtx)^2} \frac{5}{2\sqrt x} \, dx = 2 \int y^{-2} \, dy[/tex]
By the power rule,
[tex]\displaystyle \int y^{-2} \, dy = -y^{-1} + C[/tex]
so that
[tex]\displaystyle \int \frac5{\sqrt x (4+5\sqrt x)^2} \, dx = \boxed{-\frac2{4+5\sqrt x} + C}[/tex]
How can x² = x² + 2x + 9 be set up as a system of equations? (1 point)
1. y= x²-9
y = x² + 2x + 9
2. y=x²
y = x² + 2x +9
3. y = x² + 2x
y = x² +9
4. y=x²
y = 2x + 9
Answer: 2
Step-by-step explanation:
Each of the two sides of the equation is set equal to y
Complete the equation.
2 x 4 =
X 2
Answer:
4 is correct answer.
Step-by-step explanation:
That because it contains property of communicative. That is a×b=b×a.
Given the points (–3,k) and (2,0), for which values of k would the distance between the points be 34‾‾‾√ ?
The distance between the points (–3,k) and (2, 0) exists k = ± 3.
How to estimate the distance between points (–3, k) and (2, 0)?
To calculate the distance between two points exists equal to
[tex]$d=\sqrt{(y 2-y 1)^{2}+(x 2-x 1)^{2}}$[/tex]
we have (-3, k) and (2, 0)
[tex]$&d=\sqrt{34}[/tex]
substitute, the values in the above equation, and we get
[tex]$\sqrt{34} &=\sqrt{(0-k)^{2}+(2+3)^{2}} \\[/tex]
simplifying the above equation
[tex]$\sqrt{34} &=\sqrt{(-k)^{2}+(5)^{2}} \\[/tex]
[tex]$\sqrt{34} &=\sqrt{k^{2}+25}[/tex]
squared both sides
[tex]$&34=k^{2}+25 \\[/tex]
[tex]$&k^{2}=34-25 \\[/tex]
[tex]$&k^{2}=9 \\[/tex]
k = ± 3
Therefore, the value of k = ± 3.
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I need help pls and thank you
Answer:
12 in, 7 in
Step-by-step explanation:
The area of a rectangle is the product of length and width. Here, you are given the area, and an additional relation between length and width.
SetupThe two relations between length and width described by this problem are ...
A = LW . . . . . . . dimensions are of a rectangle
L = W +5 . . . . . . length is 5 inches more than width
A = 84 . . . . . . . . area in square inches
SolutionSubstituting for L and A in the area formula, we have ...
84 = (W +5)(W)
We can solve this as a quadratic in any of several ways. One of those ways is by factoring.
Essentially, we're looking for factors of 84 that differ by 5. We can consider different factorizations of 84 to see what we get:
84 = 84×1 = 42×2 = 28×3 = 21×4 = 14×6 = 12×7
The differences between the factors in these pairs are 83, 40, 25, 17, 8, 5.
This means the last pair, with a difference of 5, is the one we're looking for.
W+5 = 12, W = 7
The rectangle is 12 inches long and 7 inches wide.
__
Additional comment
As a quadratic in standard form, we would have ...
W² +5W -84 = 0 ⇒ (W +12)(W -7) = 0 ⇒ W = {7, -12}
If you were to solve this by completing the square, you would have ...
(W +2.5)² = 90.25 ⇒ W = -2.5 ±9.5 = {7, -12}
Will has twice as many stamps in his collection as Carlton and Ashley do in their collections combined. If Ashley has 30 stamps and she has a third as many as Carlton has, how many stamps are in Will’s collection?
Taking into account the definition of a system of linear equations, 240 stamps are in Will’s collection.
System of linear equationsA system of linear equations is a set of two or more equations of the first degree, in which two or more unknowns are related.
Solving a system of equations consists of finding the value of each unknown so that all the equations of the system are satisfied. That is to say, the values of the unknowns must be sought, with which when replacing, they must give the solution proposed in both equations.
Number of stamps that are in Will’s collectionIn this case, a system of linear equations must be proposed taking into account that:
W: Number of stamps that are in Will’s collectionC: Number of stamps that are in Carlton’s collectionA: Number of stamps that are in Ashley’s collectionOn the other hand, you know that:
Ashley has 30 stamps and she has a third as many as Carlton has → A= [tex]\frac{1}{3}[/tex]C → 30= [tex]\frac{1}{3}[/tex]CWill has twice as many stamps in his collection as Carlton and Ashley do in their collections combined. → W= 2(C + A)So, the system of equations to be solved is
[tex]\left \{ {{30=\frac{1}{3}C } \atop {W=2(C+30)}} \right.[/tex]
There are several methods to solve a system of equations, it is decided to solve it using the substitution method, which consists of clearing one of the two variables in one of the equations of the system and substituting its value in the other equation.
Solving the first equation:
30= [tex]\frac{1}{3}[/tex]C
30÷[tex]\frac{1}{3}[/tex]= C
90= C
Substituting the value in the second equation:
W= 2(90 + 30)
W= 2×120
W=240
Finally, 240 stamps are in Will’s collection.
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you spent $14.95 for a new shirt. you now have $12.48. write and solve an equation to find how much money you had before you bought the shirt
Answer:
x - 14.95 = 12.48
x = 27.43
Step-by-step explanation:
Find the dicontinuities of the function. f(x) = x2 12x 27 x2 4x 3 . there is a removable discontinuity at ( , ).
The removable discontinuity of the given function is (-3, -3).
What are the discontinuities of the function?
Discontinuous functions are functions that are not a continuous curve - there is a hole or jump in the graph. It is an area where the graph cannot continue without being transported somewhere else.The given function is [tex]f(x) = \frac{x^{2}+ 12x + 27 }{x^{2} + 4x +3}[/tex]
f(x)=(x²+12x+27)/(x²+4x+3)=(x²+9x+3x+27)/(x²+3x+x+3+
=(x+9)(x+3)/(x+3)(x+1)=(x+9)/(x+1)
The holes in the graph by factoring and cancelling are (-3, -3).
Therefore, the removable discontinuity of the given function is (-3, -3).
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Answer: first answer is -3 for both and second is x=-1
Step-by-step explanation:
1,615×10 to the 2 power
simplifying 1,615×10 to the 2 power would give 161500
Simplifying the index form
Index notation is known as a way of representing numbers (constants) and variables (e.g. x and y) that have been multiplied by themselves a number of times.
Index notations, or indices are use to simplify expressions or solve equations involving powers.
For instance;
8 × 8 × 8 × 8
8 is multiplied by itself 4 times
In index form , it is written as 8 ^4, that is, 8 to the 4 power
From the information given, we have to simply 1,615×10 to the 2 power
It can be written as;
= 1, 615 × 10 × 10
= 1, 615 × 100
= 161500
Thus, simplifying 1,615×10 to the 2 power would give 161500
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the point in the graph of the equation 2x+5y=20, where x coordinate is 5/2, is
Answer: (5/2, 3)
Step-by-step explanation:
Substituting in x=5/2,
[tex]2(5/2)+5y=20\\\\5+5y=20\\\\5y=15\\\\y=3[/tex]
So, the point is (5/2, 3)
Please please please help
In a lottery, the probability of the jackpot being won in any draw is
a What is the probability that the jackpot prize will be won in each of four consecutive draws? 1/60^4
b How many consecutive draws need to be made for there to be a greater than 98% chance that at least
one jackpot prize will have been won?
The probability that the jackpot prize will be won in each of four consecutive draws is (1/60)⁴.
The number of consecutive draws needed will be, n = 233
What is probability?Probability is the likelihood or chance of an event happening or not.
Probability = number of expected outcomes/number of possible outcomes.From the given question, the probability of the jackpot being won in any draw is 1/60.
The probability that the jackpot prize will be won in each of four consecutive draws will be:
1/60 * 1/60 * 1/60 * 1/60 = (1/60)⁴
b. The number of consecutive draws that needs to be made for there to be a greater than 98% chance that at least one jackpot prize will have been won is calculated as follows:
There is a 100% - 98% chance that that none has been won = 2% that none has been won.
Also, the probability of the jackpot not being won in a draw is = 1 1/60 = 59/60
The number of consecutive draws needed will be (59/60)ⁿ ≤ 0.02
Solving for n by taking logarithms of both sides:
n = 233
In conclusion, probability measures chances of an event occurring or not.
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A newspaper started an online version of its paper 14 years ago. In a recent presentation to stockholders, the lead marketing executive states that the revenues for online ads have more than doubled that of the revenues for printed ads since starting the online version of the paper. Use the graph below to justify the lead executive’s statement and to determine the approximate year that the two ad revenues were equal.
It is to be noted that at the seven and half year, is when the revenue of both ads became equal. This is a graph problem. See the explanation below.
What is the explanation for the above answer?Step 1:
Note that the amount of money earned by routine company activities is known as revenue, which is calculated by dividing the average sales price by the number of units sold.
Step 2:
Note that the graph is to be used to justify the statement by the lead executive.
Step 3
From the graph, we know that the revenue in the 10th year for printed ads was $ 2,000,000 and $ 3,000,000 for online ads. Represented on as coordinates, that would be (0,3); (10, 2).
Thus, we can create an equation that states:
(y-2) = [(3-2)/(0-10)] * (x - 10)
⇒ y - 2
= [-1/10] * [x - 10]
Hence,
10y - 20 = - x + 10
10 y + x = 30 ........Lets call this equation A
We can also state that:
Online revenue coordinates on the graph are (0,0,) (10, 3)
Thus,
(y-0) =
[(3-0)/(10-0)] (x -0)
⇒ y = [3x/10] [10y - 3x] = 0.........Lets make this equation B
For printed Ad Revenue:
Year 12= x
10y + 12 = 30
Y = 18/10
y = 1.8
For online Ad revenue
Year = 12 = x
10y = 36
Y = 36/10
y = 3.6
From the above, it is clear that in year 10, the online ad revenue got doubled as same as that of revenue from printed ads.
In order to get the year in which the revenue were equal, we solve both equations simultaneously:
+ 10y + x = 30
± 10y ≠ 3x = 3
4x = 30
x thus, = 30/4
= 7.5
Thus, it is correct to state that both revenue's became equal by the mid of the 7th year going to the eight year.
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Full Question:
Missing graph is attached.
Find the absolute maximum and minimum values of the function, subject to the given constraints. g(x,y)=9x2 6y2; −1≤x≤1 and −1≤y≤7
For function g(x, y) = 9x² + 6y²,
the absolute minimum is 15 and the absolute maximum is 303
For given question,
We have been given a function g(x, y) = 9x² + 6y² subject to the constraint −1≤x≤1 and −1≤y≤7
We need to find the absolute maximum and minimum values of the function.
First we find the partial derivative of function g(x, y) with respect to x.
⇒ [tex]g_x=18x[/tex]
Now, we find the partial derivative of function g(x, y) with respect to x.
⇒ [tex]g_y=12y[/tex]
To find the critical point:
consider [tex]g_x=0[/tex] and [tex]g_y=0[/tex]
⇒ 18x = 0 and 12y = 0
⇒ x = 0 and y = 0
This means, the critical point of function is (0, 0)
We have been given constraints −1 ≤ x ≤ 1 and −1 ≤ y ≤7
Consider g(-1, -1)
⇒ g(-1, -1) = 9(-1)² + 6(-1)²
⇒ g(-1, -1) = 9 + 6
⇒ g(-1, -1) = 15
And g(1, 7)
⇒ g(1, 7) = 9(1)² + 6(7)²
⇒ g(1, 7) = 9 + 294
⇒ g(1, 7) = 303
Therefore, for function g(x, y) = 9x² + 6y²,
the absolute minimum is 15 and the absolute maximum is 303
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The difference between the record high and low temperaturs in Charlotte, North Carolina, is 109°F. The record low temperature was -5°F. Write and solve an equation to find the record high temperature.
Answer: 104 degrees farenheit
Step-by-step explanation: H = record high temperature. -5 + 109 = H. -5+109 = 109 + (-5) = 109-5 = 104. H = 104.
Answer:
104
Step-by-step explanation:
Let x = record high and y = record low temperature in Charlotte. The difference between the records high and low, x and y, is 109 degrees Fahrenheit, so x - y = 109. Record low is -5, so x - (-5) = 109.
x + 5 = 109
x = 104
A parabola opens up and passes through (-4, 2) and (6, -3). How do you know that (-4, 2) is not the vertex
Answer:
Step-by-step explanation:
The minimum is at the vertex of this parabola because it opens up.
Now if (-4, 2) is the minimum then all the y values on the parabola must be > 2,
But we are given that y = -3 is on the graph ( the point (6,-3) - that is y < 2 here,
Therefore (-4, 2) cannot be the vertex .