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Answer:

∠ 3 = 65°

Step-by-step explanation:

∠ 2 and 115° are a linear pair and sum to 180° , that is

∠ 2 + 115° = 180° ( subtract 115° from both sides )

∠ 2 = 65°

∠ 2 and ∠ 3 are corresponding angles and and are congruent , then

∠ 3 = 65°

Answer:

(10,10)

Step-by-step explanation:

y = .5x + 5

If you put in 10 for x, we get 10 for y.

y = .5(10) + 5

y =5 + 5

y = 10

When x is 10, y is 10 (10,10)

The value of x is 70°. The correct option is A. 70

From the question, we are to determine the value of the measure of arc x

From one of the circle theorems, we have that

The angle subtended by an arc at the center is twice the angle subtended by it at any point on the circumference.

First, we will determine the value of the third angle in the triangle formed.

Let the angle be y

y + 15° + 20° = 180°

∴ y = 180° - 15° - 20°

y = 145°

Now, the angle supplementary to this is the angle the arc subtends at the circumference.

Thus,

The angle at the circumference = 180° - 145°

The angle at the circumference = 35°

From the above theorem, we can conclude that the angle subtended by the arc at the center of the circle is 2 × 35° = 70°

∴ The measure of the arc is 70°

This is the value of x

Hence, the value of x is 70°. The correct option is A. 70

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Answer:

1.46m or 14600cm are left over

Step-by-step explanation:

Assuming you mean that there were 4m of string and 254cm were used/removed.

Answer: x = 9

Step-by-Step Solution:

Hypotenuse = 15 units

Base = 12 units

Altitude = x units

Using Pythagoras Theorem,

=> Hypotenuse^2 = Base^2 + Altitude^2

(15)^2 = (12)^2 + x^2

225 = 144 + x^2

225 - 144 = x^2

81 = x^2

x^2 = 81

x = √81

=> x = 9

Therefore, Altitude = 9 units

Step-by-step explanation:

x =130.......................

Using translation concepts, it is found that:

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

The rule applied for each vertex of the rectangle is given as follows:

(x,y) -> (x + 7, y - 2).

The new coordinates of A' are given as follows:

(-2 + 7, 2 - 2) = (5,0).

The new coordinates of B' are given as follows:

(-2 + 7, 4 - 2) = (5,2).

The new coordinates of C' are given as follows:

(2 + 7, 4 - 2) = (9,2).

The new coordinates of D' are given as follows:

(2 + 7, 2 - 2) = (9,0).

Since there are only two values for the x-coordinates and two values for the y-coordinates, if the corresponding vertices were connected with line segments, a rectangle would be formed.

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Answer:

[tex]12.3 - 33.9 = 21.6 \div 10 = 2.16[/tex]

The dy/dx of equation  [tex]x^{3} -3x^{2} y+2xy^{2} =12[/tex] is [tex](6xy-3x^{2} -2y^{2} )/(4xy-3x^{2})[/tex].

Given an equation [tex]x^{3} -3x^{2} y+2xy^{2} =12[/tex].

We are required to find dy/dx of the equation.

Equation is like a relationship between two or more variables that are expressed in equal to form. Equations of two variables look like ax+by=c.

Differentiation is basically finding the change in variables.

It may be linear equation, quadratic equation,cubic equation or many more depending on the power of the variable present in the equation.

Equation:[tex]x^{3} -3x^{2} y+2xy^{2} =12[/tex]

Differentiating with respect to x.

3[tex]x^{2}[/tex]-3([tex]x^{2}[/tex]*dy/dx+y*2x)+2(x*2y*dy/dx+[tex]y^{2}[/tex])=0

3[tex]x^{2} -3x^{2} dy/dx-6xy+4xy dy/dx+2y^{2}[/tex]=0

Taking dy/dx at one side and take the other part to other end.

[tex]-3x^{2} dy/dx+4xy dy/dx[/tex]=[tex]6xy-3x^{2} -2y^{2}[/tex]

dy/dx=[tex](6xy-3x^{2} -2y^{2})/(4xy-3x^{2} )[/tex]

Hence the dy/dx of equation  [tex]x^{3} -3x^{2} y+2xy^{2} =12[/tex] is [tex](6xy-3x^{2} -2y^{2} )/(4xy-3x^{2})[/tex].

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Answer:

9060$ is the final amount because 7060 is the interest

The amount of money after 45 years will be $64,060.

Compound interest is the interest on a loan or deposit calculated based on the initial principal and the accumulated interest from the previous period.

We know that the compound interest is given as

A = P(1 + r)ⁿ

Where A is the amount, P is the initial amount, r is the rate of interest, and n is the number of years.

Investments increase exponentially by about 26% every 3 years.

If you made a $2,000 investment.

Then the equation will be

[tex]\rm A = 2000 \times \left (1.26 \right )^{\frac{t}{3}}[/tex]

Where t is the number of years.

Then the amount of money after 45 years will be

[tex]\rm A = 2000 \times \left (1.26 \right )^{\frac{45}{3}}[/tex]

Simplify the equation, then we have

A = 2000 × (1.26)¹⁵

A = 2000 × 32.03

A = $64,060

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Splitting up [0, 3] into [tex]n[/tex] equally-spaced subintervals of length [tex]\Delta x=\frac{3-0}n = \frac3n[/tex] gives the partition

[tex]\left[0, \dfrac3n\right] \cup \left[\dfrac3n, \dfrac6n\right] \cup \left[\dfrac6n, \dfrac9n\right] \cup \cdots \cup \left[\dfrac{3(n-1)}n, 3\right][/tex]

where the right endpoint of the [tex]i[/tex]-th subinterval is given by the sequence

[tex]r_i = \dfrac{3i}n[/tex]

for [tex]i\in\{1,2,3,\ldots,n\}[/tex].

Then the definite integral is given by the infinite Riemann sum

[tex]\displaystyle \int_0^3 2x^2 \, dx = \lim_{n\to\infty} \sum_{i=1}^n 2{r_i}^2 \Delta x \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac6n \sum_{i=1}^n \left(\frac{3i}n\right)^2 \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac{54}{n^3} \sum_{i=1}^n i^2 \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac{54}{n^3}\cdot\frac{n(n+1)(2n+1)}6 = \boxed{18}[/tex]

Answer:

y = 1/3x - 3

Step-by-step explanation:

We can find the equation of the line, by finding the slope and combine with our y-intercept (-3).

We need to use the slope formula to find the slope.

Thus, we have (-3 - (-2)) / 0 - 3 = -1/-3 = 1/3

So our equation is y = -1/3x - 3

Answer:

ummm the answer is very simple

The answer is 0/6

Step-by-step explanation:

[tex] \frac{1}{2 \times 3} - \frac{1}{6} [/tex]

[tex] \frac{1}{6} - \frac{1}{6} [/tex]

[tex]1 - 1 = \frac{0}{6} [/tex]

Answer:15

Step-by-step explanation: 20 divided by 8=2.5 x 6=15

Applying the initial conditions, the specific solution is:

[tex]y = e^{-2x}(-3\sin{3x} + 4\cos{3x})[/tex]

The general solution is given by:

[tex]y = e^{-2x}(C_1\sin{3x} + C_2\cos{3x})[/tex]

We apply the initial conditions to find the specific solution.

First, we have that y(0) = 4, then:

[tex]4 = e^{-2(0)}(C_1\sin{3(0)} + C_2\cos{3(0)})[/tex]

Since cos(0) = 1, we have that:

[tex]C_2 = 4[/tex]

Then:

[tex]y = e^{-2x}(C_1\sin{3x} + 4\cos{3x})[/tex]

The derivative is:

[tex]y^\prime(x) = -2e^{-2x}(C_1\sin{3x} + 4\cos{3x}) + e^{-2x}(3C_1\cos{3x} - 4\sin{3x})[/tex]

Since y'(0) = -17, then:

[tex]-17 = -8 + 3C_1[/tex]

[tex]3C_1 = -9[/tex]

[tex]C_1 = -3[/tex]

Then the specific solution is:

[tex]y = e^{-2x}(-3\sin{3x} + 4\cos{3x})[/tex]

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The marked price of the ring given the cost as 8740 inclusive of 15% tax and discount of 5% is $7,283.3.

8740 = x + (15% of x) + (5% of x)

8740 = x + (0.15x) + (0.05x)

8740 = x + 0.15x + 0.05x

8740 = 1.20x

x = 8740 / 1.20

x = 7283.33333333333

Approximately,

x = $7,283.3

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Answer:

  1∠22.5°, 1∠112.5°, 1∠202.5°, 1∠292.5°

Step-by-step explanation:

A root of a complex number can be found using Euler's identity.

For some z = a·e^(ix), the n-th root is ...

  z = (a^(1/n))·e^(i(x/n))

Here, we have z = i, so a = 1 and z = π/2 +2kπ.

Using r∠θ notation, this is ...

  i = 1∠(90° +k·360°)

and

  i^(1/4) = (1^(1/4))∠((90° +k·360°)/4)

  i^(1/4) = 1∠(22.5° +k·90°)

For k = 0 to 3, we have ...

 for k = 0, first root = 1∠22.5°

  for k = 1, second root = 1∠112.5°

  for k = 2, third root = 1∠202.5°

  for k = 3, fourth root = 1∠292.5°

The true statements are:

The median number of pages of the sixth graders is 76.

One-fourth of the students have read less than 72 pages.

One-half of the students have read between 72 and 86 pages.

A box plot is used to study the distribution and level of a set of scores. The box plot consists of two lines and a box. the two lines are known as whiskers.

The end of the first line represents the minimum number and the end of the second line represents the maximum number. The difference between the minimum number and the maximum number is the range.

Range = 92 - 61 = 31

On the box, the first line to the left represents the lower (first) quartile. 1/4 of the score represents the lower quartile. The next line on the box represents the median. 1/2 of the score represents the median. The third line on the box represents the upper (third) quartile. 3/4 of the scores represents the upper quartile.

First quartile = 72

Third quartile = 86

Median = 76

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The value of the probability P(A) is 0.40

The given parameters about the probability are

P(A or B) = 0.6

P(B) = 0.3

P(A and B) = 0.1

To calculate the probability P(A), we use the following formula

P(A and B) = P(A) + P(B) - P(A or B)

Substitute the known values in the above equation

0.1 = 0.3 + P(A) - 0.6

Collect the like terms

P(A)= 0.1 - 0.3 + 0.6

Evaluate the expression

P(A)= 0.4

Hence, the value of the probability P(A) is 0.40

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Based on the information, it is expected Fareed can be assigned to live on any of the floors.

The only condition that limits the floor Fareed can be assigned to is that he cannot be immediately below Damaris. This means that as long as Damaris is not immediately above him, he can be assigned to all floors. Here are two possible arrangements:

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Answer:

○ [tex]y = 6 + 5x + x^2[/tex]

Explanation:

A quadratic equation is an algebraic equation where the highest power of [tex]x[/tex] is 2. The general form of a quadratic equation is as follows:

[tex]\boxed{ax^2 + bx + c = 0}[/tex],

where a, b, and c represent known constants, and [tex]x[/tex] is the unknown.

In this question, if you take a look at the second option, you will see that it is possible to rearrange the equation to make it look the general form:

[tex]y = 6 + 5x + x^2[/tex]

⇒ [tex]y = x^2 + 5x + 6[/tex]

Therefore, this equation is quadratic.

The other three options are not quadratic equations because none of them have an [tex]x^2[/tex]  term in them.

[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]

[tex]\leadsto[/tex] A quadratic equation is an algebraic equation of the second degree. The formula is:

▪ [tex]\longrightarrow \sf{y = ax^2 + bx + c}[/tex]

This can also be written as:

▪ [tex]\longrightarrow \sf{y = c + bx+ax^2}[/tex]

Comparing the equation above with each of the options, the equation that represents a quadratic function is:

[tex]\longrightarrow \sf{y=6+5 + x^2}[/tex]

[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]

◉ [tex] \large\bm{b. \: y=6+5x + x^2}[/tex]

Answer:

w = 15 cm

Step-by-step explanation:

We want to find the width, as the area of a rectangle is length (l) * width (w).

Since we know the area and the length, we have 480 = 32w

Isolating w by dividing both sides by 32 gives us w = 15 cm

Answer:

7×10³+3×10²+4×10¹+2×10 or 7.342×10³

the inequality gives the 'y' value as -4

An inequality is a mathematical tool that compares two values, expressing when one is less than, greater than, or not equal to the other value.

For instance,

a ≠ b says that a is not equal to b

a < b says that a is less than b

a > b says that a is greater than b

From the information given, that 3y+1 is less than -11 . It can be expressed as;

3y + 1 ∠ -11

Let's collect like terms

3y ∠ -11 - 1

add like terms

3y ∠ -12

make 'y' the subject of formula

y ∠ -12/3

y ∠ -4

The inequality gives the 'y' value as -4

Thus, the inequality gives the 'y' value as -4

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The surface area of the balloon is 249 in².

A balloon has the shape of a sphere. The distance round the sphere is equal to the circumference of the sphere.

Circumference of the sphere = 2πr

Where:

Radius - circumference / 2π

28 / ( 2 x 22/7) = 4.45 inches

Surface area of a sphere = 4πr²

4 x 22/7 x 4.45² = 249 in²

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Answer:

x=a-d/c+b

Step-by-step explanation:

a-bx =cx+d

collect like terms

a-d=cx+bx

a-d=x(c+b)

x=a-d/c+b

Answer:

plane HNA, HMB, ANG ...

Step-by-step explanation:

Any combination of three points on plane K will work unless all three are on the same line.

The probability of 11 voters out of 15 voting candidate A is 0.9770

According to the statement

we have given that the percentage of voters is 81% and poll conducts are 15 and we have to find the probability that 11 of the 15 voters will prefer Candidate

So, For this purpose,  

the question in based on binomial probability which means the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes p and q and p+q=1

let probability of choosing candidate A be p

and probability of choosing candidate B be q

In question p=0.81 and q=0.16

n be total number of voters=15

x be number of successes

then P(x=x)= [tex]\frac{n}{x} p^{x} q^{n-x}[/tex]

P(x=11)= [tex]\frac{11}{15} 0.81^{11} 0.16^{4}[/tex]

= 0.9770

So, the probability of 11 voters out of 15 voting candidate A is 0.9770

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The computation shows that the number of weeks that it take to repair this stretch of road will be 4 weeks.

From the information given, we are told that a thirteen kilometers stretch of road needs repairs and that the workers can repair three and half kilometers of road per week.

The question is simply for us to calculate the number or weeks that it will take to be able to repair the stretch of road.

Therefore, based on the information given, it should be noted that to get the number of weeks that will be used to repair the road, we simply have to divide the total distance or the road by the distance that is repaired every week.

Therefore, the number of weeks that it will take to be able to repair this stretch of road will be:

= 13/3.5

= 3.7

= 4 weeks approximately

Therefore, based on the information given, the number of weeks that's required is 4 weeks.

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The number of moles of hydrogen is 185 moles.

We know that the mole refers to the number of elementary entities that make up a substance. According to Avogadro, one mole of a substance contains 6.02 * 10^23 elementary entities which includes atoms, molecules and ions.

Now, we know the number of moles is obtained as the ratio of the mass to the molar mass of the substance.

Thus;

Mass of hydrogen = 370.g

Molar mass of hydrogen = 2 g/mol

Number of moles of hydrogen = 370.g/2 g/mol = 185 moles

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