Need help with my math please. 31-41. Read the directions carefully please.

Magnitude of the momentum of this system just after the collision = 19.2Kgm/s

Law of conservation of momentum states that the total momentum after the collision must be equal to the total momentum before the collision.

The momentum of each ball is given by:

p = mv

where m is the mass of the ball and v its velocity.

The momentum of ball 1 is:

p = mv

= (3.0 kg)(4.0 m/s)

= 12.0 kg m/s in the eastward direction

The momentum of ball 2 is:

p = mv

= (5.0 kg)(3.0 m/s)

= 15.0 kg m/s in the northward direction

The two momenta are in perpendicular directions, so the magnitude of the total momentum can be found as:

[tex]p = \sqrt{p1^{2} +p2^{2} }[/tex]

[tex]p = \sqrt{12^{2} +15^{2} }\\p = \sqrt{144 + 225} \\p = \sqrt{369}\\ p = 19.2 kgm/s[/tex]

and due to the law of conservation of the momentum, this is also equal to the total momentum after the collision.

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The size of the largest angle of the pentagon will be 150°.

A pentagon is the polygon that has five sides. It should be noted that the interior angle of a regular pentagon is 540°.

The given ratio is 2:3:4:4:5. Therefore, the size of the largest angle of the pentagon will be:

= 5/(2+3+4+4+5) × 540

= 5/18 × 540

= 150°

In this case, the size of the largest angle of the pentagon will be 150°.

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Answer:

he didn't mistake step 2

The become in the inequality form is -3≥x≥4.

According to the statement

we have given that the statement and we have to write this condition in the form of the inequality.

So, we know that the

Inequality, a statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

It is represented with the grater than or less than or equal to signs.

so, the given statement is

x is less than or equal to negative 3 or greater than or equal to 4

and we have to write in the inequality condition so,

we have to write it but before this break the statement like

x is less than or equal to negative 3

And

x is greater than or equal to 4.

So,

-3≥x≥4.

So, The become in the inequality form is -3≥x≥4.

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let's keep in mind that i² = -1, and let's use the conjugate of the denominator.

[tex]\cfrac{2+5i}{3-2i}\cdot \cfrac{3+2i}{3+2i}\implies \cfrac{(2+5i)(3+2i)}{\underset{\textit{difference of squares}}{(3-2i)(3+2i)}}\implies \cfrac{6+4i+15i+10i^2}{(3)^2~~ - ~~(2i)^2} \\\\\\ \cfrac{6+19i+10(\stackrel{i^2}{-1})}{9~~ - ~~(2^2 i^2)}\implies \cfrac{6+19i-10}{9~~ - ~~4(\underset{i^2}{-1})}\implies \cfrac{-4+19i}{9+4}\implies -\cfrac{4}{13}+\cfrac{19i}{13}[/tex]

Answer:

65°

Step-by-step explanation:

JM = JK (all sides of a rhombus are equal)

Angle JKM = 25° (isosceles triangle)

Angle JKL = 50° (consecutive angles of rhombus)

Angle MKL = 25° (angle subtraction)

Angle MLK = 130° (opposite angles of a rhombus)

Angle KLN = 50° (angles on a straight line)

Angle LKN = 40° (angle sum of triangle)

Angle MKN = 65° (angle addition)

Answer: x>8.

Step-by-step explanation:

[tex]14-2*(x+1) < -4\\ 14-2x-2 < -4\\12-2x < -4\\12-2x+4 < 0\\16-2x < 0\\16-2x+2x < 0+2x\\16 < 2x\\Divide \ both\ sides\ of \ the\ equation \ by \ 2:\\8 < x.[/tex]

I assume [tex]C[/tex] is oriented counterclockwise. If [tex]C[/tex] is the closed rectangle, then by Green's theorem we have

[tex]\displaystyle \int_C F\cdot dr = \int_0^3 \int_0^9 \frac{\partial (x-y)}{\partial x} - \frac{\partial (x^2+y^2)}{\partial y} \, dy \, dx \\\\ ~~~~~~~~~~~~ = \int_0^3 \int_0^9 (1 - 2y) \, dy \, dx = 3 \int_0^9 (1-2y)\, dy = \boxed{-216}[/tex]

It seems unlikely, but if you actually are omitting the integral along the line segment joining (0, 9) and (0, 0), let [tex]x=0[/tex] and [tex]y=9-t[/tex] with [tex]0\le t\le9[/tex]. Then the integral along this line segment would be

[tex]\displaystyle \int_{(0,9)\to(0,0)} F\cdot dr = \int_0^9 \bigg((0^2 + (9-t)^2) i + (0 - (9-t)) j\bigg) \cdot (0i - j) \, dt \\\\ ~~~~~~~~  = \int_0^9 (9-t) \, dt = \frac{81}2[/tex]

so that the overall integral would instead have -216 - 81/2 = -513/2.

Answer Section 1. <3
Heyy, I'm sunny and I'm here to help you :)
(P.S: answer in explanation)

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Explanation Section:

It is false

If f(x) is a function , then for each value of x there should be  a single y values

For input 0 there is a output 0

for input 10, the output is 2

for input 15, output is 3

For input 5, we have two output 1 and 3

for single input 5, the function cannot have two outputs 1  and 3

So this f(x) is not a function

Bye! - SunnyBunny <3

45 candidates are expected to be rejected.

What is a percentage in math?

Here, we want to calculate the number of candidates to be rejected

The number of candidates to be rejected can be calculated from;

100% - (28% + 12%) = 60%

So 60% of the 75 interviewed are to be rejected

Thus, we have

60/100 * 75

= 45

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Answer: 1223.07

Step-by-step explanation: you don't round up

Answer:

Ascending Order: 0.432 < 0.5734 < 0.76373

Descending Order: 0.76373 < 0.5734 < 0.432

Step-by-step explanation:

Check the tenths place of the decimal number and order them accordingly. If the tenths place is the same for two decimal numbers, go on to the next corresponding place to compare their values.

Answer:

Step-by-step explanation:

x=8,-8

y=-4-4

Answer:

  a.  1080

  b.  405

Step-by-step explanation:

Function evaluation is often conveniently done using a calculator. Many calculators know about the order of operations, so can be used without fear of an incorrect evaluation.

Put the value where the variable is and do the arithmetic.

  f(x) = 40(3^x)

  f(3) = 40(3^3) = 40(27) = 1080

  g(x) = 5(3^(x+1))

  g(3) = 5(3^(3+1)) = 5(3^4) = 5(81) = 405

The probability that it also rained that day is to be considered as the 0.30 and the same is to be considered.

The extent to which an event is likely to occur, measured by the ratio of the favorable cases to the whole number of cases possible.

The probability that the temperature is lower than 80°F and it rained can be measured by determining the number at the intersection of a temperature that less than 80°F and rain.

So, This number is 0.30.

Hence, we can say that it was less than 80°F on a given day, the probability that it also rained that day is 0.30.

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The above question is incomplete.

The conditional relative frequency table was generated using data that compared the outside temperature each day to whether it rained that day. A 4-column table with 3 rows titled weather. The first column has no label with entries 80 degrees F, less than 80 degrees F, total. The second column is labeled rain with entries 0.35, 0.3, nearly equal to 0.33. The third column is labeled no rain with entries 0.65, 0.7, nearly equal to 0.67. The fourth column is labeled total with entries 1.0, 1.0, 1.0. Given that it was less than 80 degrees F on a given day, what is the probability that it also rained that day?

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Answer: Its 0.3 so the first one

Step-by-step explanation:

Im 101% sure

Answer:

Step-by-step explanation:

The standard form equation for a circle is

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where h and k are the coordinates of the center. Our center is given as (-6,7)  and the radius is given as 9, so that information fits into our standard form like this:

[tex](x-(-6))^2+(y-7)^2=9^2[/tex] and simplified, it looks like this:

[tex](x+6)^2+(y-7)^2=81[/tex]

That's choice C

Answer:

1. Given.

2. Triangle Exterior Angle Theorem.

3. Definition of Equilateral Triangles.

4. Substitution Property of Equality.

5. Addition Property of Equality.

answers :

a.

coordinates of A are (2,4)

b.

coordinates of B are (6,0)

i.

(4,2) is the midpoint

ii.

y = -3x + 18 is the parallel line

Step-by-step explanation:

a.

if two things are equal to the same thing then they are equal to each other

y = 4

2x + y = 8 is y = -2x +8 so

-2x +8 = 4

-2x = -4

x = 2

coordinates of A are (2,4)

b.

if two things are equal to the same thing then they are equal to each other

y=0

3x+y=18 is y = -3x+18 so

-3x+18=0

x = 6

coordinates of B are (6,0)

midpoint formula is

(X1+X2)/2 , (Y1+Y2)/2

(2,4) (6,0)

(X1+X2)/2 , (Y1+Y2)/2

(2+6)/2 , (4+0)/2

(4,2) is the midpoint

parallel line has the same x value

so for a line parallel to 3x+y=18 or y = -3x+18

the parallel line would be

y = -3x

point slope formula

point slope formulay - y1 = m (x - x1)

3x+y=18 or y = -3x+18 was 6,0 at y = 0

y - y1 = m (x - x1)

y - 0 = m (x - x1)

since it's a parallel line the m has to be the same

(6,0)

y - 0 = -3 (x - 6)

y = -3x + 18 is the parallel line

Answer: 5 cm

Step-by-step explanation:

B = [tex]\sqrt{13^{2} -12^{2} } = 5[/tex]

Answer:

OPTION C, 5

Step-by-step explanation:

Using the formula, substitute the hypotenuse and the other leg of the right triangle.

13²=12²+b²

Rearrange appropriately.

13²-12²=c²

Convert.

13²=169

12²=144

Apply and work out.

169-144= 25

c²=25

c=√25

c=5

OPTION C is therefore the answer.

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EachEach value of time elapsed (in seconds) corresponding instantaneous velocity (in feet/second) are:2s= 96, 3s = 64, 4s= 32, 5s = 0, 6s = -32, 7s = -64. 8s= -96, 9s= -128.

Given equation:

f(t) = -16t² +160t

Velocity (v)=df(t)/dt

=-2×16t²+ 160t

=-32t+160

Hence:

-32t+160

1.     -32×(1) + 160 =    128ft/s

2.    -32×(2) + 160 =    96ft/s

3.    -32×(3) + 160 =    64ft/s

4.    -32×(4) + 160 =     32m/s

5.    -32×(5) + 160 =     0m/s

6.   -32×(6) + 160 =   -32m/s

7.    -32×(7) + 160 =    -64m/s

8.   -32×(8) + 160 =    -96m/s

9.    -32×(9) + 160 =   -128m/s

The pairs are;

2s= 96

3s = 64

4s= 32

5s = 0

6s = -32

7s = -64

8s= -96

9s= -128

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Solución de problemas

6x 2x3xx

Answer:

is there a picture I can look at?

Answer: Line

Step-by-step explanation:

3%

Answer:

Selling price with VAT {15%} = Rs 41400

S.P +15% of S.P =Rs 41400

S.P(1+15%)=Rs 41400

S.P=Rs 41400/1.15

Selling price without VAT =Rs 36000

Again

Discount = 10%

M.P =S.P+ Discount % of M.P

M.P-Discount% of M.P= S.P

M.P(1-Discount%)=Rs 36000

M.P(1-10%)=Rs 36000

M.P=Rs 36000/0.9

Marked Price = Rs 40,000

again

Discount =Discount % of M.P

=10% of 40000

=Rs 4,000

Again

Profit=20%

For 20% profit

Cost price = (S.P*100)/(100+profit%)

=(36000*100)/(100+20)

= Rs 30000

For 24% profit

selling price = (100+profit%)*C.P/100

=(100+24)*30000/100

=Rs 37200

Again

Discount = 40000–37200 = Rs2800

Discount % = discount/M.P*100%

=2,800/40,000* 100 = 7%

Finally

Discount percent to be reduced =10%–7%= 3%

If a salesperson has 7 customers in denver and 13 customers in reno then there are 20 different ways in which he can make calls.

Given that the salesperson has 7 customers in denver and 13 customers in reno.

We are required to find the number of ways in which he can make use of telephone.

Number of customers in denver=7

Number of customers in reno=13

Total customers=20

Since he can talk to one customer at one time and he can either choose customer from denver or reno, the number of ways by using combinations will be [tex]7C_{1}[/tex]+[tex]13C_{1}[/tex]

=7+13

=20 ways.

Hence if a salesperson has 7 customers in denver and 13 customers in reno then there are 20 different ways in which he can make calls.

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Answer: Total = $200

Step-by-step explanation:

Given information

Money spent on shoes = $20.00

Percent of Money spent on shoes = 10%

Given formula

The total amount of money spent × Percent = Money spent on shoes

                                                      ⇵    

The total amount of money spent = Money spent on shoes / Percent

Substitute values into the given formula

The total amount of money spent = Money spent on shoes / Percent

Total = (20.00) / (10%)

Convert percentage into decimal

Total = 20.00 / 0.1

Simplify the fraction

[tex]\Large\boxed{Total~=~200~Dollars}[/tex]

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Answer:

484 Students

Step-by-step explanation:

This is simple probability. Assuming 22/80 students walk to school within a small population, and there are 1760 students at the school, there should be (22/80)*1760 students that walk to school in total. (This is just theoretical). This is 484 students.

Answer:

A

Step-by-step explanation:

First, we should put this equation in slope-intercept form by isolating y.

Thus, we have:

[tex]2x-\frac{4}{3}y=4\\ -\frac{4}{3}y=4-2x\\ y=\frac{3}{2}x-3[/tex]

The slope-intercept equation shows that the y-intercept is -3 and the slope is 3/2.

Only answer A meets these requirements.

This statement is true that the In c 11 you cannot use a range-based for loop to modify the contents of an array unless you declare the range variable as a reference variable.

According to the statement

we have given that the one statement and we have to tell that the those statement is true or false after analyzing it.

So,

In C++ 11 is  a programming language which is used to write the coding. And in this language you cannot use a range-based for loop to modify the contents of an array unless you declare the range variable as a reference variable.

Because in the coding it is not possible that the you can make loop without declare the random variable in the loop.

Due to this reasons without declare the variable it is not possible.

So, This statement is true that the In c 11 you cannot use a range-based for loop to modify the contents of an array unless you declare the range variable as a reference variable.

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Answer:

Step-by-step explanation:

The domain is an x thing. We are being asked to determine what x values to function takes on. We see that the blue dot on the left is at the x-value of 2. It doesn't go any farther to the left of 2. Since the dot is closed, the inequality symbol will have the "equal to" line underneath.

The function then continues along the x axis and stops at 5, closed hole. This means that the function does not go past the x value of 5 but it is included in our domain.

2 ≤ x ≤ 5. That is choice B.

Answer:

a) √80 ≈ 9

b) √27 ≈ 5

c) √110 ≈ 10

d) √0.03 ≈ 0.2

e) √0.12 ≈ 0.3

Step-by-step explanation:

80 is close to 81

Therefore, √80 can be estimated as √81

√81 = 9

[tex]\Large\boxed{\sqrt{80}\approx9 }[/tex]

27 is close to 25

Therefore, √27 can be estimated as √25

√25 = 5

[tex]\Large\boxed{\sqrt{27}\approx5 }[/tex]

110 is close to 100

Therefore, √110 can be estimated as √100

√100 = 10

[tex]\Large\boxed{\sqrt{110}\approx10 }[/tex]

0.03 is close to 0.04

Therefore, √0.03 can be estimated as √0.04

√0.04 = 0.2

[tex]\Large\boxed{\sqrt{0.03}\approx0.2 }[/tex]

0.12 is close to 0.09

Therefore, √0.12 can be estimated as √0.09

√0.09 = 0.3

[tex]\Large\boxed{\sqrt{0.12}\approx0.3 }[/tex]

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