They are both 6.9 miles apart after one hour if they both hike 4 miles/hour
The correct option is (B)
What is the triangle?In terms of geometry, the triangle is a three-sided polygon with three edges and three vertices. The triangle's interior angles add up to 180°.
According to the given information:Miranda and Cyndi start hiking from the same point. Miranda hikes at a heading of 270° or due west, and Cyndi hikes at a heading of 30°
From the isosceles triangle:h = 4sin30
h = 4(1/2)
h = 2 miles
From Pythagoras theorem:x² = 4² - h² = 4² - 2²
x = √12
x = 3.46 miles
Total distance = 2×3.46 = 6.9 miles
Thus, they are both 6.9 miles apart after one hour if they both hike 4 miles/hour option (B) 6.9 miles is correct.
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I understand that the question you are looking for :
Miranda and Cyndi start hiking from the same point. Miranda hikes at a heading of , or due west, and Cyndi hikes at a heading of , or n e. if they both hike 4 miles/hour, approximately how far apart are they after one hour?
A) 4.3 miles. .
B) 6.9 miles
C) 8.0 miles
D) 5.7 miles
How is a circumference related to an arc
Answer:
An arc of a circumference or of a circle mostly is a portion of the circumference. The length of an arc for all intents and purposes is simply the length of this portion of the circumference in a definitely major way. The circumference itself can particularly be considered an arc that goes around the circle in a fairly major way.
find the length of MN
Answer:
The length of MN is 5 cm
Step-by-step explanation:
Add the segment LX, parallel to QP.
Recall the properties of midsegment:
Midsegment is parallel to side,Midsegment is half the length of the parallel side.We have:
Since QL = LR, the point L is midpoint of Q,Since PN = NL, the point N is midpoint of PL,Since LX is parallel to QP, LX is midsegment of ΔPRQ.Find the length of LX:
LX = QP/2 = 20/2 = 10 cmSince QP ║ LX ║ NM, the segment NM is the midsegment of ΔPLX.
Find the length of NM:
NM = LX/2 = 10/2 = 5 cmHELP ASAP!!! 40 POINTS
Identify each x-value at which the slope of the tangent line to the function f(x) = 0.2x2 + 5x − 12 belongs to the interval (-1, 1).
Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:
(-15,-10).
What is the slope of the tangent line to a function f(x) at point x = x0?It is given by the derivative at x = x0, that is:
[tex]m = f^{\prime}(x_0)[/tex].
In this problem, the function is:
[tex]f(x) = 0.2x^2 + 5x - 12[/tex]
Hence the derivative is:
[tex]f^{\prime}(x) = 0.4x + 5[/tex]
For a slope of -1, we have that:
0.4x + 5 = -1
0.4x = -6
x = -15.
For a slope of 1, we have that:
0.4x + 5 = 1.
0.4x = -4
x = -10
Hence the interval is:
(-15,-10).
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How many ways are there to get from (0, 0) to (7, 7) in the coordinate plane
with movements of only one unit right or one unit up? How many ways are there to do so that do not go above the line y = x?
The number of ways there are to move from (0, 0) to (7, 7) in the coordinate plane with movements of only one unit right or one unit up accordingly is; 49 while that such that y =x is; 7.
How many ways are there to get from (0, 0) to (7, 7) in the coordinate plane with pmovements of only one unit right or one unit up?It follows from the task content that the movement intended on the coordinate plane is; from (0, 0) to (7, 7).
The number of ways to move such that movements of only one unit right or one unit up is; 7 × 7 = 49.
The number of ways for which y= x is therefore is; 7 as the movement is diagonal.
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OA=
Please help asap!! Thanks so much :))
In the given diagram, the value of the dashed side of rhombus OABC is 5
Distance between two pointsFrom the question, we are to determine the length of the dashed line (OA), in rhombus OABC
In the diagram, we can observe that the length of OA is the distance between point A and the origin (O).
Using the formula for calculating distance between two points,
d =√[(x₂-x₁)² + (y₂-y₁)²]
In the diagram,
The coordinate of the origin is (0, 0)
The coordinate of point A is (3, 4)
Thus,
x₁ = 0
x₂ = 3
y₁ = 0
y₂ = 4
Putting the parameters into the formula, we get
OA =√[(3-0)² + (4-0)²]
OA =√(3² + 4²)
OA =√(9+16)
∴ OA =√25
OA = 5
Hence, in the given diagram, the value of the dashed side of rhombus OABC is 5
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What are the solutions to the system of equations? {−x+y=4y+12=x2+x
Answer: (-4, 0) and (4, 8)
Step-by-step explanation:
Looking at the graph, we can see where the line passes the parabola and can tell the solutions are (-4, 0) and (4, 8)
Which of the following is a monomial? O A. 11x-9 OB. 20x9 OC. 20x⁹ - 7x O D.9/x
Answer:
B. 20x⁹
Step-by-step explanation:
A monomial is a polynomial with just one term.
Example: 3x²
A. 11x - 9
INCORRECT, this has two terms 11x and 9
B. 20x⁹
CORRECT, this only has one term!
C. 20x⁹ - 7x
INCORRECT, this has two terms 20x⁹ and 7x
D.9/x
INCORRECT, this is not a polynomial
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Russell has $38 and is saving $2 per day. cornelius has $64 and is spending $2 per day. after how many days will russell have more money than cornelius?
The equation be 38 + 2x - (64 - 2x) = 0 then the value of x = 6.5.
How to find the value of x?To estimate the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to estimate the result.
Let the day be x
38 + 2x - (64 - 2x) = 0
Subtract 38 from both sides
38 + 2x - (64 - 2x) - 38 = 0 - 38
Simplifying the above equation, we get
2x - (64 - 2 x) = -38
Expanding the above equation, 2x - (64 - 2x) = 4x - 64
4x - 64 = -38
Add 64 to both sides
4x - 64 + 64 = -38 + 64
Simplify
4x = 26
Divide both sides by 4
[tex]$\frac{4 x}{4}=\frac{26}{4}[/tex]
Simplifying the equation
[tex]$x=\frac{13}{2}[/tex]
The value of x = 6.5.
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What must be true in order to find a sum for an infinite geometric series?
Answer:
0 < r < 1
Step-by-step explanation:
That every sequence gets multiplied by a number less than 1 but more than 0
The law is
Common ratio or r must lies in between 0 and 1
It means
r is in (0,1)
r is greater than 0 but less than 1The formula is
[tex]\boxed{\sf S_{\infty}=\dfrac{a}{1-r}}[/tex]
What is the value of the expression when n = 3?
StartFraction 6 (n squared plus 2) Over n EndFraction
16
22
30
66
Answer:
B) 22
Step-by-step explanation:
The expression is:
[tex]\cfrac{6(n^2+2)}{n}[/tex]Find its value when n = 3, substitute n with 3 in the expression:
[tex]\cfrac{6(3^2+2)}{3} =\cfrac{6(9+2)}{3} =\cfrac{6(11)}{3}=2(11) = 22[/tex]The matching answer choice is B.
11/6 + -2/5 +-13/10?
Answer:
2/15Step-by-step explanation:
11/6 + -2/5 +-13/10?
11/6 + (-2/5) + (-13/10)
43/30 - 13/10
2/15
The diagonal is a of a rectangular field is 169m. If the ratio of the length to the width is 12:5 find the dimensions
Based on the calculations, the dimensions of the rectangle are
Length, L = 156 meters.Width, w = 65 meters.What is a diagonal?The diagonal of a rectangle can be defined as a line segment that connects any two (2) of its non-adjacent vertices together while dividing the rectangle into two (2) equal parts.
Mathematically, the length of diagonals of a rectangle can be calculated by using this formula:
d = √(l² + w²)
Where:
d is the diagonal of a rectangle.l is the length of a rectangle.w is the width of a rectangle.Since the ratio of the length to the width is 12:5, we have:
Width, w = 5l/12
Substituting the given parameters into the formula, we have;
169 = √(l² + (5l/12)²)
169² = l² + (5l/12)²
169² = l² + (25l²/144)
Length, L = 156 meters.
For the width, we have:
Width, w = 5l/12
Width, w = 5(156)/12
Width, w = 65 meters.
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if you rolled two dice what is the probability that you would roll a 4 or a 5
Question 9 of 25 a bookstore costs $105 a day to keep open, and it spends $12 for each book that it sells. if each book sells for $15, what is the break-even point for this bookstore?
The store will break even after selling 35 books.
What is the break-even point?The break-even point is the moment at which total cost and total revenue are equal, implying that your small firm has no loss or benefit. In other words, you've reached the point where the costs of production equal the revenues for a product.To find what is the break-even point for this bookstore:
Given:
The cost required per day to keep the store open = $105Amount spent on each book = $12Let, n be the number of books.
Total costs = 12n + 105
The selling price of each book = $15
Total revenue = 15n
For breaking even, costs = revenue.
12n + 105 = 15n105 = 15n - 12n105 = 3n3n = 105Dividing both sides by 3:3n/3 = 105/3n = 35Therefore, the store will break even after selling 35 books.
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Factorise 10xy-12+15x-8y
Answer: 10xy-12+15x-8y=(5x-4)*(2y+3).
Step-by-step explanation:
[tex]10xy-12+15x-8y=(10xy-8y)+(15x-12)=\\=2y*(5x-4)+3*(5x-4)=(5x-4)*(2y+3).[/tex]
Jack and Serena can write a lab report together in 12 hours. If all people work at the same rate, how many hours would it take to write a lab report if Kay joins Jack and Serena?
One positive integer is 2 times another positive integer and their product is 50. what are the positive integers?
The first integer is 5.
The second integer is 10.
What is Positive integer ?If an integer is higher than zero, it is positive; if it is lower than zero, it is negative. Zero can be either positive or negative. Since a b and c d, then a + c b + d, the ordering of integers is consistent with algebraic operations.
According to the information:One integer is twice the other
so,
If one integer is x then
The other will be 2x.
Their product :
2x * x = 50
2x² = 50
x² = 50/2
x² = 25
x = √25
x = 5
the first integer is 5.
the second integer is 2x = 2 x 5
= 10.
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Find the terms through degree four of the maclaurin series for f(x) = sin(x) 1−x.
The terms through degree four of the Maclaurin series is [tex]f(x)=x+x^{2} +\frac{5x^{3} }{6} +\frac{5x^{4} }{6} +.....[/tex].
In this question,
The function is f(x) = [tex]\frac{sin(x)}{1-x}[/tex]
The general form of Maclaurin series is
[tex]\sum \limits^\infty_{k:0} \frac{f^{k}(0) }{k!}(x-0)^{k} = f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} +\frac{f'''(0)}{3!}x^{3}+......[/tex]
To find the Maclaurin series, let us split the terms as
[tex]f(x)=sin(x)(\frac{1}{1-x} )[/tex] ------- (1)
Now, consider f(x) = sin(x)
Then, the derivatives of f(x) with respect to x, we get
f'(x) = cos(x), f'(0) = 1
f''(x) = -sin(x), f'(0) = 0
f'''(x) = -cos(x), f'(0) = -1
[tex]f^{iv}(x)[/tex] = cos(x), f'(0) = 0
Maclaurin series for sin(x) becomes,
[tex]f(x) = 0 +\frac{1}{1!}x +0+(-\frac{1}{3!} )x^{3} +....[/tex]
⇒ [tex]f(x)=x-\frac{x^{3} }{3!} +\frac{x^{5} }{5!}+.....[/tex]
Now, consider [tex]f(x) = (1-x)^{-1}[/tex]
Then, the derivatives of f(x) with respect to x, we get
[tex]f'(x) = (1-x)^{-2}, f'(0) = 1[/tex]
[tex]f''(x) = 2(1-x)^{-3}, f''(0) = 2[/tex]
[tex]f'''(x) = 6(1-x)^{-4}, f'''(0) = 6[/tex]
[tex]f^{iv} (x) = 24(1-x)^{-5}, f^{iv}(0) = 24[/tex]
Maclaurin series for (1-x)^-1 becomes,
[tex]f(x) = 1 +\frac{1}{1!}x +\frac{2}{2!}x^{2} +(\frac{6}{3!} )x^{3} +....[/tex]
⇒ [tex]f(x)=1+x+x^{2} +x^{3} +......[/tex]
Thus the Maclaurin series for [tex]f(x)=sin(x)(\frac{1}{1-x} )[/tex] is
⇒ [tex]f(x)=(x-\frac{x^{3} }{3!} +\frac{x^{5} }{5!}+..... )(1+x+x^{2} +x^{3} +......)[/tex]
⇒ [tex]f(x)=x+x^{2} +x^{3} - \frac{x^{3} }{6} +x^{4}-\frac{x^{4} }{6} +.....[/tex]
⇒ [tex]f(x)=x+x^{2} +\frac{5x^{3} }{6} +\frac{5x^{4} }{6} +.....[/tex]
Hence we can conclude that the terms through degree four of the Maclaurin series is [tex]f(x)=x+x^{2} +\frac{5x^{3} }{6} +\frac{5x^{4} }{6} +.....[/tex].
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Determine the seating capacity of an auditorium with 15 rows of seats if there are 25 seats in the first row, 29 seats in the second row, 33 seats in the third row, 37 seats in the forth row, and so on
Answer:
Step-by-step explanation:
15 rows adding 4 additional seats to each. Once at end add all seats in rows together for the final answer.
1-25
2-29
3-33
4-37
5-41
6-45
7-49
8-53
9-57
10-61
11-65
12-69
13-73
14-77
15-81
Add all togther. 25+29+33+37+41+45+49+53+57+61+65+69+73+77+81=795
So there are 795 seating capacity.
The marked price of a mobile set is Rs 9,600 and 40% discount is allowed to make 20% profit. By what percent is the discount to be reduced to increase the profit by 10%?
Answer:
5%
Step-by-step explanation:
price after discount :
9 600 - 9 600×40%
= 5760
Original price (price without profit) :
let x be the original price of the device.
x + x × 20% = 5760
Then
x = (5 760×100)÷120
= 4 800
Original price increased by 30% :
4 800 + 4 800×30%
= 6 240
the discount needed to increase the profit by 10% :
[(9 600-6 240)÷9 600]×100
= 35%
Then
to increase the profit by 10% ,we have to reduce
the percent of discount to :
40% - 35%
= 5%
If p(x,3) Q(7,1) and pQ(15) unit find the possible value of x
Answer:
Step-by-step explanation: P(x 3), Q(7, -1) and PQ= 5 .
To Find :
The possible value of x.
Solution :
We know, distance between two points in coordinate plane is given by :
Therefore, the possible value of x are 10 and 4.
For a pair of sample x- and y-values, the ______________ is the difference between the observed sample value of y and the y-value that is predicted by using the regression equation.
For a pair of sample x and y values, the residual exists as the distinction between the observed sample value of y and the y value that exists indicated by utilizing the regression equation.
What is the difference between the observed sample value of Y and the Y value that exists as predicted by utilizing the regression equation?In regression analysis, the distinction between the observed value of the dependent variable and the predicted value exists named the residual.
A regression equation exists utilized in stats to estimate what relationship if any, exists between sets of data.
For a pair of sample x and y values, the residual exists as the distinction between the observed sample value of y and the y value that exists indicated by utilizing the regression equation.
Residual = observed y - predicted y.
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Li Juan solves the equation below by first squaring both sides of the equation. [tex]\sqrt{3-2w}=w+6[/tex]
What extraneous solution does Li Juan obtain?
Answer:
w = -11
Step-by-step explanation:
[tex]\sqrt{3 - 2w} = w + 6[/tex]
[tex](\sqrt{3 - 2w})^2 = (w + 6)^2[/tex]
[tex] 3 - 2w = w^2 + 12w + 36 [/tex]
[tex] w^2 + 14w + 33 = 0 [/tex]
[tex] (w + 11)(w + 3) = 0 [/tex]
[tex] w + 11 = 0 [/tex] or [tex] w + 3 = 0 [/tex]
[tex] w = -11 [/tex] or [tex] w = -3 [/tex]
When you square both sides of an equation, you must check all solutions for extraneous solutions.
Check w = -11.
[tex]\sqrt{3 - 2w} = w + 6[/tex]
[tex] \sqrt{3 - 2(-11)} = -11 + 6 [/tex]
[tex] \sqrt{3 + 22} = -5 [/tex]
[tex] \sqrt{25} = -5 [/tex]
[tex] 5 = -5 [/tex]
This is a false statement, so the solution w = -11 is extraneous since it does not satisfy the original equation.
Check w = -3.
[tex]\sqrt{3 - 2w} = w + 6[/tex]
[tex] \sqrt{3 - 2(-3)} = -3 + 6 [/tex]
[tex] \sqrt{3 + 6} = 3 [/tex]
[tex] \sqrt{9} = 3 [/tex]
[tex] 3 = 3 [/tex]
This is a true statement, so the solution w = -3 is valid.
Answer: w = -11
What is the solution to 3/2b + 5 < 17? Explain How.
(1) b < 8
(2) b > 8
(3) b < 18
(3) b > 18
We subtract 5 from both sides of the inequality.
3/2b + 5 - 5 < 17 - 53/2 b < 12Multiply both sides by 2/3.
( 2/3) * (3/2b) < (2/3) * 12b < 8Therefore, the correct option is alternative "A".
We would think that it is option B, but the only difference is that it changes the direction of the sign.
Answer: [A]: " b < 8 " .
_____
Step-by-step explanation:
Given:
Find the solution to: " 3/2b + 5 < 17 " ; and choose from the answer choices.
So; we have:
(3/2)b + 5 < 17 ;
Now, subtract "5" from each side of this inequality:
(3/2)b + 5 − 5 < 17 − 5 ;
To get:
(3/2)b < 12 ;
Now, let's multiply Each Side of this inequality by "2" ;
to get rid of the fraction:
" 2*(3/2)b < 12*2 " ;
{Note: " [tex]2 *\frac{3}{2}=\frac{2}{1}*\frac{3}{2}[/tex] " } ;
Note: To simplify: " [tex]\frac{2}{1} * \frac{3}{2}[/tex] " ;
Note the "2" in the denominator in the "first term" ;
And: The "2" in the denominator in the "second term" ;
Both "cancel out" to "1" ; since: "[ 2 / 2 = 2÷2 = 1 ]" ;
And: we have: " [tex]\frac{1}{1}*\frac{3}{1}= 1 *3 = 3[/tex] " };
_____
and rewrite:
" 3b < 24 " ;
Now, divide Each side of the inequality by "3" ;
to isolate "b" on one side of the inequality;
and to solve for "x" ;
_____
" 3b/3 < 24/3 " ;
to get:
_____
" b < 8 " ; which corresponds to the correct answer:
Answer choice: [A]: " b < 8 " .
_____
Hope this is helpful to you! Best wishes!
_____
O Yes
O No
2. (02.01 LC)
Is the following relation a function? (1 point)
{(3,-2), (1, 2), (-1,-4), (-1, 2)}
Answer:
no
Step-by-step explanation:
In a function, each "x" value [input] must have only one corresponding "y" value.
We know that points are written as (x, y)
Our points: {(3,-2), (1, 2), (-1,-4), (-1, 2)}
We can see that the x-input of -1 has two y-outputs, so this is therefore not a function
hope this helps! have a lovely day :)
Lori was paid a 15 percent commission for the home audio system that she sold. The electronics store had marked up the price of the system by 60 percent over the wholesale price of $264. How much did Lori earn for the sale of the home audio system? $15.84 $23.76 $39.60 $63.36
Answer:
$63.36
Step-by-step explanation:
The home audio system costs $264 wholesale.
The system's price had been increased by 60 percent at the electronics retailer.
Consequently, the increased cost is 60/100x264=$158.40.
The audio system's total cost is now $422.40 (264 + 158.40).
Given that Lori received a commission of = 15% on $422.40, her commission is now (15/100) x 422.40
= $63.36
Make a list of 4 different numbers whose average works up to 50
(a) if x is the sample mean young's modulus for a random sample of n = 64 sheets, where is the sampling distribution of x centered, and what is the standard deviation of the x distribution?
The standard deviation of the x distribution is 0.2.
According to the statement
we have given that the the sample n is 64 and we have to find the standard deviation of the given sample.
So, For this purpose, we know that the
The standard deviation of the sample is the standard deviation of population divided by the square root of the length of the sample.
In this problem, we have that the value of alpha is
[tex]\alpha = 1.6[/tex]
Suppose that for aluminum alloy sheets of a particular type,
If X is the sample mean Young's modulus for a random sample of n = 64 sheets, and the standard deviation of the X distribution is given by
[tex]s = \frac{\alpha}{\sqrt{64} }[/tex]
then solve it then the standard deviation
s = {1.6} / {8 }
s = 0.2
So, The standard deviation of the x distribution is 0.2.
Disclaimer: This question was incomplete. Please find the full content below.
Question:
Given that Young's modulus is a quantitative measure of stiffness of an elastic material. Suppose that for aluminum alloy sheets of a particular type, its mean value and standard deviation are 70 GPa and 1.6 GPa, respectively.
a. If X is the sample mean Young's modulus for a random sample of n = 64 sheets, the sampling distribution of X centered at 70 GPa, and the standard deviation of the X distribution is given by
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q=sqrt (c+d)/(c-d) solve for c
The equation for the variable 'c' is c = d(q² + 1)/(q² - 1). By using simple arithmetic operations on the original equation, the required equation can be obtained.
What is an equation?An equation is a relationship between two expressions given by a mathematical statement.
There are different types of equations. They are linear equations, quadratic, polynomial, etc.
Solving for c in the given equation:The given equation is
q = √((c + d)/(c - d))
Squaring on both, root gets canceled out
⇒ q² = (c + d)/(c - d)
⇒ q²(c - d) = (c + d)
⇒ cq² - dq² = c + d
Separating like terms aside,
cq² - c = d + dq²
⇒ c(q² - 1) = d(q² + 1)
⇒ c = d(q² + 1)/(q² - 1)
Therefore, the required equation is c = d(q² + 1)/(q² - 1).
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Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ?
Step-by-step explanation:
log 6 = log (2×3) = log 2 + log 3 = 0.3010+0.4771
=0.7781
Answer:
[tex]\sf \log_{10}6=0.7781[/tex]
Step-by-step explanation:
Given:
[tex]\sf \log_{10} 2 = 0.3010[/tex]
[tex]\sf \log_{10} 3 = 0.4771[/tex]
To find log₁₀ 6, first rewrite 6 as 3 · 2:
[tex]\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)[/tex]
[tex]\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay[/tex]
[tex]\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2[/tex]
Substituting the given values for log₁₀ 3 and log₁₀ 2:
[tex]\begin{aligned} \sf \implies \log_{10}3+\log_{10}2 & = \sf 0.4771+0.3010\\ & = \sf 0.7781 \end{aligned}[/tex]
Therefore:
[tex]\sf \log_{10}6=0.7781[/tex]
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