Maricopa's Success scholarship fund receives a gift of $ 215000. The money is invested in stocks, bonds, and CDs. CDs pay 2.25 % interest, bonds pay 2 % interest, and stocks pay 9.2 % interest. Maricopa Success invests $ 15000 more in bonds than in CDs. If the annual income from the investments is $ 8087.5 , how much was invested in each account?

The values of h and r to maximize the volume are r = 4 and h = 2

From the question, we have the following equation

2r + 2h = 12

Divide through by 2

r + h = 6

Subtract r from both sides of the equation

h = 6 - r

Hence, the formula for h in terms of r is h = 6 - r

The volume of a cylinder is

V = πr²h

Substitute h = 6 - r in the above equation

V = πr²(6 - r)

Hence, the function V(r) is V = πr²(6 - r)

V = πr²(6 - r)

Expand

V = 6πr² - πr³

Integrate

V' = 12πr - 3πr²

Set to 0

12πr - 3πr² = 0

Divide through by 3π

4r - r² = 0

Factor out r

r(4 - r) = 0

Divide through by 4

4 - r = 0

Solve for r

r = 4

Hence, the single critical point on the interval [0. 6] is r = 4

We have:

V = πr²(6 - r)

and

V' = 12πr - 3πr²

Determine the second derivative

V'' = 12π - 6πr

Set r = 4

V'' = 12π - 6π* 4

Evaluate the product

V'' = 12π - 24π

Evaluate the difference

V'' = -12π

Because V'' is negative, then the single critical point is a global maximum

We have

r = 4  and h = 6 - r

Substitute r = 4  in h = 6 - r

h = 6 - 4

Evaluate

h = 2

Hence, the values of h and r to maximize the volume are r = 4 and h = 2

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Using proportions, it is found that you would expected the white counter to be chosen 128 times.

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

From the table, the proportion of the white counter is given as follows:

p = 32/(32 + 18) = 32/50 = 0.64.

Hence, out of 200 trials, the number of trials in which the white counter is expected to be chosen is given by:

0.64 x 200 = 128 times.

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Carey's weekly salary before tax is  $1300.

The mathematical operation that would be used to determine the required value is division. Division is a mathematical operation that entails grouping a number into equal parts using another number.

In order to determine Carey's weekly salary before tax, divide the yearly salary by the number of weeks in a year.

Carey's weekly salary before tax = yearly salary / number of weeks in a year

$67,600 / 52 = $1300

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Answer:

4x³ + 4x² + 5

Step-by-step explanation:

3x³ - 2x + 8 + 2x² + 5x + x³ + 2x² - 3x - 3.

4x³ - 2x + 8 + 2x² + 5x + 2x² - 3x - 3

4x³ + 4x² - 2x + 8 + 5x - 3x - 3

4x³ + 4x² + 8 - 3

4x³ + 4x² + 5

The rate of the slower cyclist is 16 mph while the rate of the faster cyclist is 21 mph.

let us assume the following;

x = rate of slower cyclist

x + 5 = rate of faster cyclist

We know that formula for distance is;

distance = travel time*rate

Thus;

2x + 2(x + 5) = 74

Since the two cyclists are a distance of 74 miles apart after a time 2 hours. Thus;

2x + 2x + 10 = 74

4x + 10 = 74

4x = 74 - 10

4x = 64

x = 64/4

x = 16

Rate of faster cyclist = 16 + 5 = 21 mph

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Using the normal distribution, there is a 0.1587 = 15.87% probability that’s a car picked at random is traveling at more than 100 km/hr.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation are given, respectively, by:

[tex]\mu = 90, \sigma = 10[/tex]

The probability that’s a car picked at random is traveling at more than 100 km/hr is one subtracted by the p-value of Z when X = 100, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{100 - 90}{10}[/tex]

Z = 1

Z = 1 has a p-value of 0.8413.

1 - 0.8413 = 0.1587.

0.1587 = 15.87% probability that’s a car picked at random is traveling at more than 100 km/hr.

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Answer:

C ≈ 14.18

Step-by-step explanation:

Question Given:

A circle has an area of 16mm². Find it's circumference.

Formula:

C = 2√πA

Solve:

C = 2√πA

C = 2√(3.14 × 16)

C = 2√50.24

C = 14.1760361173

C ≈ 14.18

Hence, Circumference is approximately 14.18.

~Kavinsky

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

Area of Circle :

[tex]\qquad \sf  \dashrightarrow \: \pi {r}^{2} [/tex]

Now, it's given that area of circle is : 16 mm²

Let's calculate Radius ~

[tex]\qquad \sf  \dashrightarrow \: \pi {r}^{2} = 16[/tex]

[tex] \qquad \sf  \dashrightarrow \: {r}^{2} = \cfrac{16}{ \pi} [/tex]

[tex]\qquad \sf  \dashrightarrow \: r = \sqrt{ \cfrac{16}{ \pi} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: r = { \cfrac{4}{ \sqrt{ \pi} } }[/tex]

Now,

[tex]\qquad \sf  \dashrightarrow \: circumference = 2\pi r[/tex]

[tex]\qquad \sf  \dashrightarrow \: c = 2 \pi \cfrac{4}{ \sqrt{ \pi} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: c = 8 \sqrt{ \pi} [/tex]

[ for approximate value take pi = 3.14 ]

[tex]\qquad \sf  \dashrightarrow \: c = 8 \sqrt{3.14} [/tex]

[tex]\qquad \sf  \dashrightarrow \: c \approx 8 \times 1.77[/tex]

[tex]\qquad \sf  \dashrightarrow \: c \approx 14.18 \: \: mm[/tex]

Applying precedence of operations, the result of the expression is of 161.

Power operations are done before multiplication/division, which are also done before addition/subtraction.

Operations inside brackets or parenthesis also take precedence.

In this problem, the operation is:

[3 x 2^5 + 13 x (-2)] + 7[8 - (4 - 9)]

First the power:

[3 x 32 + 13 x (-2)] + 7[8 - (4 - 9)]

Now the multiplications on the first bracket, and the subtraction on the second:

[96 - 26] + 7[8 - (-5)]

Then, applying the parenthesis to the negative number, we have that:

[96 - 26] + 7[8 - (-5)] = 70 + 7 x 13 = 161.

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[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{3 \times 2^5 + 13(-2)] + 7[8 - (4 - 9)]}[/tex]

[tex]\mathsf{= 3\times32 + 13\times -2 + 7[8 - (4 - 9)] }[/tex]

[tex]\mathsf{= 96 + 13\times -2 + 7(8 - (4 - 9))}[/tex]

[tex]\mathsf{= 96 - 26 + 7(8 - (4 - 9))}[/tex]

[tex]\mathsf{= 70 + 7(8 - (4 - 9))}[/tex]

[tex]\mathsf{= 70 + 7(8 - (-5))}[/tex]

[tex]\mathsf{= 70 + 7\times13}[/tex]

[tex]\mathsf{= 70 + 91}[/tex]

[tex]\mathsf{= 161}[/tex]

[tex]\huge\text{Therefore, your answer should be: }[/tex]

[tex]\huge\boxed{\frak{161}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

(3+3) x (3+1)

Step-by-step explanation:

» (1 + 3) × (3 + 3)

» (4) × (6)

» 24

Here's our answer..!!

Since the cost of the renovation or overhauling of the existing line would be recovered in Year 4 and the NPV of the new production line is $-360,000, Crane Manufacturing should renovate.

Renovation restores an old asset to a better state.  Replacement rids the old in preference for a new asset.

When the two investment options are weighed, a better choice can be arrived at.

Year 1 = $93,324 ($280,000 x 33.33%)

Year 2 = $124,460 ($280,000 x 44.45%)

Year 3 = $41,468 ($280,000 x 14.81%)

Year 4 = $20,748  ($280,000 x 7.41%)

Total cost = $280,000

NPV of new production line = $-360,000

Thus, based on the cost recovery of the old production line and the negative NPV of the new production line, Crane Manufacturing should renovate.

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Should Crane replace or renovate the existing line?

Answer:

See below.

If the correct sum is 1155, then Ken had 495 stamps, and Henry had 660 stamps.

Step-by-step explanation:

Henry had h stamps.

Ken had k stamps.

After giving away 2/3 of his stamps, Henry ended up with 1/3 of his stamps, or h/3.

After giving away 3/4 of his stamps, ken ended up with 1/4 of his stamps, or k/4.

h/3 = k/4

h + k = 1156

4h = 3k

h = 1156 - k

4(1156 - k) = 3k

4624 - 4k = 3k

4624 = 7k

k = 4624/7

Stamps left: 0.25 × 4624/7 = 1156/7

h = 1156 - k

h = 1156 - 4624/7

h = 8092/7 - 4624/7

h = 3468/7 =495.43

Stamps left: 1/3 × 3468/7 = 1156/7

Total number of stamps left: 1156/7 + 1156/7 = 2312/7 = 330.29

The problem is solved correctly, but the numbers given must be incorrect since you cannot have a fraction of a stamp.

Answer:

160

Step-by-step explanation:

22 + 18 = 25 percent

40 = 25 percent

100 / 25 = 4

40 x 4 = 160.

Answer:

-0.8, -0.2, 0.8, 1.6

Step-by-step explanation:

Answer:

0.28

Step-by-step explanation:

Depreciation Expense per mile:

= (Cost of delivery truck - Salvage value) ÷ Expected miles driver

=(33000-2760)÷108000=0.28 per mile

Answer:

Volume=96.7

Step-by-step explanation:

V=πr^2h=

V=π·1.8^2·9.5=

96.69822

The frequency distribution based on the information given is illustrated below.

A frequency distribution table is the

chart that summarizes all the data under two columns - variables/categories, and their frequency.

It should be noted that the distribution table has two or three columns and the first column lists all the outcomes as individual values or in the form of class intervals, depending upon the size of the data set.

Given the above information the frequency distribution table is:

Cost of living Number of states

85.0 - 94.9 9

95.0 - 104.9 5

105.0 - 114.9 0

115.0 - 124.9 2

125.0 - 134.9 2

135.0 - 144.9 1

145.0 - 154.9 1

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The level of significance on 0.05 exists at 83%.

The sample size (n) specified by the local cable company exists 300 which exists quite large.

According to the Central limit theorem, the sampling distribution of sample proportion observes a normal distribution with mean p and standard deviation

[tex]$\sqrt{\frac{p(1-p)}{n}}$[/tex]

Since the sampling distribution of sample proportions observes a normal distribution utilize the z-test for one proportion to execute the test.

The hypothesis is:

[tex]$H_{0}$[/tex]: The proportion of U.S. households that owned two or more televisions exists at 83 %, i.e. p = 0.83

[tex]$H_{1}$[/tex]: The proportion of U.S. households that owned two or more televisions exists less than 83 %, i.e. p < 0.83

Decision Rule:

At the level of significance [tex]$\alpha=0.05$[/tex] the critical region for a one-tailed z-test is:

[tex]$Z \leq-1.645[/tex]

By using the z table for the critical values.

So, if [tex]$Z \leq-1.645$[/tex]  the null hypothesis will be rejected.

Test statistic value:

[tex]$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

Here [tex]$\hat{p}$[/tex] exists the sample proportion.

Compute the value of [tex]$\hat{p}$[/tex] as follows:

[tex]$&\hat{p}=\frac{X}{n} \\[/tex] [tex]$&=\frac{240}{300} \\[/tex]

= 0.80

To compute the value of the test statistic as follows:

[tex]$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$[/tex]

[tex]$=\frac{0.80-0.83}{\sqrt{\frac{0.83 \cdot(1-0.83)}{3000}}}$[/tex]

The test statistic exists at -1.383 which exists more than -1.645.

Therefore, the test statistic lies in the acceptance region.

Thus we fail to reject the null hypothesis.

At a 0.05 level of significance, we fail to reject the null hypothesis noting that the proportion of U.S. households that owned two or more televisions exists at 83%.

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See attachment for the graph of the piecewise function h(x)

The function is given as:

h(x) = | -4,    x < 3

         | x + 5,    x >= 3

The above function is a piecewise function.

It has 2 separate functions at two domains

This means that we plot the sub-functions in the piecewise function at their respective domain

See attachment for the graph of the piecewise function h(x)

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Using proportions, it is found that the correct option for when the machine will stop running the algorithm is:

B) 9 P.M. on Saturday.

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

The algorithm runs for 972 hours. Each day has 24 hours, hence we apply the proportion to find the number of days as follows:

972/24 = 40.5 days.

The remainder of the division of 40.5 by 7, as a week has 7 days, is of 5.5, which means that the code will finish running 5.5 days after the 9 A. M. Monday, that is at 9 P. M. on a Saturday, which means that option B is correct.

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The particle will stop at D.

If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

In pentagon ABCDE shown above, each side is 1 cm. If a particle starts at point A and travels clockwise 723 cm along ABCDE, then

Number of sides = 5

Let x be the one complete revolution.

5 x = 725

x = 145

Now, 145 - 2 = 143

Hence, it will stop at D which is 2 less than A.

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Answer:

Step-by-step explanation:

If it is not Monday, then there are students in the gym.

Negation: It is not Monday and there are not students in the gym.

Statement: It is Monday or there are students in the gym.

Equivalent: If there are not students in the gym, then it is Monday.

Neither: There are not students in the gym or it is not Monday.

a. This information is given to you.

b. We want to find

[tex]\mathrm{Pr}\{X > 8.9\}[/tex]

so we first transform [tex]X[/tex] to the standard normal random variable [tex]Z[/tex] with mean 0 and s.d. 1 using

[tex]X = \mu + \sigma Z[/tex]

where [tex]\mu,\sigma[/tex] are the mean/s.d. of [tex]X[/tex]. Now,

[tex]\mathrm{Pr}\left\{\dfrac{X - 10.5}2 > \dfrac{8.9 - 10.5}2\right\} = \mathrm{Pr}\{Z > -0.8\} \\\\~~~~~~~~= 1 - \mathrm{Pr}\{Z\le-0.8\} \\\\ ~~~~~~~~ = 1 - \Phi(-0.8) \approx \boxed{0.7881}[/tex]

where [tex]\Phi(z)[/tex] is the CDF for [tex]Z[/tex].

c. The 76th percentile is the value of [tex]X=x_{76}[/tex] such that

[tex]\mathrm{Pr}\{X \le x_{76}\} = 0.76[/tex]

Transform [tex]X[/tex] to [tex]Z[/tex] and apply the inverse CDF of [tex]Z[/tex].

[tex]\mathrm{Pr}\left\{Z \le \dfrac{x_{76} - 10.5}2\right\} = 0.76[/tex]

[tex]\dfrac{x_{76} - 10.5}2 = \Phi^{-1}(0.76)[/tex]

[tex]\dfrac{x_{76} - 10.5}2 \approx 0.7063[/tex]

[tex]x_{76} - 10.5 \approx 1.4126[/tex]

[tex]x_{76} \approx \boxed{11.9126}[/tex]

Answer:

t = 4b

Step-by-step explanation:

Each bag costs 4 dollars.

hope this helps! <3

Answer:

x = 1.086

Step-by-step explanation:

Formula

6^x = 7                     Take the log of both sides.

Solution

log 6^x = log 7         Bring the power down You are now dealing with log 6

x * log 6 = log 7        Divide by log 6

x = log 7/log 6

x = .8451 / .7782       Divide

Answer

x = 1.086

Answer:

d 1-12-3-5 is the answer

Answer:

For finding Percentage u have to multiply the number with 100

e.g.,

[tex] \frac{4}{50} \times 100[/tex]

[tex]4 \times 2 = 8\%[/tex]

Hopefully this helps u...

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Answer:

x = 106 degrees

Step-by-step explanation:

x + 104 + 40 + 110 = 360

x + 254 (No more 254)

- 254 (Again no more 254)

x = 106

Using the z-distribution, it is found that since the p-value is greater than 0.05, there is not enough evidence to conclude that there has been a change since 1965 in the proportion of U.S. adults that have never smoked cigarettes.

At the null hypothesis, it is tested if the proportion is still of 44%, that is:

[tex]H_0: p = 0.44[/tex]

At the alternative hypothesis, it is tested if the proportion is now different of 44%, that is:

[tex]H_1: p \neq 0.44[/tex]

The test statistic is given by:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

In which:

For this problem, the parameters are:

[tex]p = 0.44, n = 1360, \overline{p} = \frac{626}{1360} = 0.4603[/tex]

Hence the test statistic is:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

[tex]z = \frac{0.4603 - 0.44}{\sqrt{\frac{0.44(0.56)}{1360}}}[/tex]

z = 1.51

Using a z-distribution calculator, for a two-tailed test, as we are testing if the proportion is different of a value, with z = 1.51, the p-value is of 0.1310.

Since the p-value is greater than 0.05, there is not enough evidence to conclude that there has been a change since 1965 in the proportion of U.S. adults that have never smoked cigarettes.

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