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Help me please thank u so much

Answer: 170 marbles

Step-by-step explanation: Rani had 20 more marbles than Seema and Seema had 150. 150+20 is 170.

Answer:

The total number of feet travelled by the motorcycle is 396 feet

Step-by-step explanation:

Using the constant speed relationship with the distance:

           v = s/t

From the above equation the distance travelled will be:

          s = v * t              (i)

We are given with the v, that is:

          v = 45 miles per hour

Converting in to feet per second.

          v = (45 * 5280)/3600 feet / s

          v = 66 feet per second

Now, put that v and t in equation (i)

          s = 66 * 6

          s = 396 feet

The side lengths of the isosceles triangle are:

AO = 16 units

AB = 16 units

OB = 6 units.

An isosceles triangle is a type of triangles that has two sides that are congruent to each other, and two base angles that are opposite these two sides that are also congruent to each other.

Referring to the isosceles triangle in the image attached below, we have the following:

One of the congruent sides = AO = 3x + 4 units

The other congruent side = AB = x + 12 units

The third side = OB = 4x - 10 units

Applying the definition of an isosceles triangle, we can create an equation as shown below to find x:

AO = AB [congruent sides]

Substitute

3x + 4 = x + 12

3x - x = - 4 + 12

2x = 8

2x/2 = 8/2

x = 4

Find the side lengths of the isosceles triangle by plugging in the value of x:

One of the congruent sides = AO = 3x + 4 = 3(4) + 4 = 16 units

The other congruent side = AB = x + 12 = 4 + 12 = 16 units

The third side = OB = 4x - 10 = 4(4) - 10 = 6 units.

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Answer:

ur answer is B

Step-by-step explanation:

Answer:

B

As root over 72 is 8.48 and after we round off we get 8.5 so no B is correct

Answer:

y = [tex]\frac{1}{2}[/tex] x + 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 1) ← 2 points on the line

m = [tex]\frac{1-0}{0-(-2)}[/tex] = [tex]\frac{1}{0+2}[/tex] = [tex]\frac{1}{2}[/tex]

the line crosses the y- axis at (0, 1 ) ⇒ c = 1

y = [tex]\frac{1}{2}[/tex] x + 1 ← equation of line

The straight line equation is :

[tex]\boxed {y = mx + c}[/tex]

Here, c = 1 as it intersects (0, 1) on the y-axis.

The slope is :

Hence, the equation will be :

y = 0.5x + 1

I hope it helped you solve the problem.

Good luck in your studies!

Answer:

Width is 11 inches

Step-by-step explanation:

I am not sure what the question is.  I think you might be looking for the width length.  The perimeter is the distance around a rectangle.  If the whole distance around is 48.  We have 2 lengths and 2 widths.  They tell us that the length is 13.  We have two lengths so the lengths add up to 26.  We can subtract that from 48 and that leaves us with 22 (48-26)  This is the total for the 2 widths.  Since the 2 widths are the same length we divide that number by 2 to get 11.

11 + 11+ 13 + 13 = 48

The radius of the table can be either 13 inches or 73 inches.

Let the radius of the table be r inches and the corner be the origin.

The coordinates of the center of the table exist (r, r).

The equation for the circumference of the table exists (x−r)²+(y−r)²=r².

The mark at the edge of the table exists 18 inches from one wall and 25 inches from the other wall. Therefore, the coordinates of this point exist (18, 25). It could also be (25, 18) but it does not make any difference to our estimations.

As the mark exists on the edge, it meets the requirements of the equation of the circumference of the table.

(18−r)² + (25−r)² = r²

324−36r+r²+625−50r+r² = r²

r²−86r+949 = 0

(r − 13)(r − 73) = 0

r = 13 inches and r = 73 inches

Therefore, the radius of the table can be either 13 inches or 73 inches.

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[tex]4r {}^{3} s - rs + 7r {}^{3} s + 8rs - 3 + 8rs + 6 \\ add \: \: terms \: \: of \: \: same \: \: variables \\ 11r {}^{3} s + 15rs + 3[/tex]

Step-by-step explanation:

I just answered this. how often did you post that question ?

she added 54-48 = 6g.

how many % of 48g are these 6g ?

100% = 48

1% = 100%/100 = 48/100 = 0.48g

how many % are 6g ?

as many as how often 1% (0.48g) fits into 6g :

6 / 0.48 = 12.5%

If the speed of the ball after kicking is 48 feet per second then the ball will return on the ground after 3 seconds.

Given that the speed of the ball after kicking is 48 feet per second and the function that represents the height of the ball is [tex]-16t^{2} +48t[/tex].

We are required to find the time that the ball took to travel before returning the ground.

We know that speed is the distance a thing covers in a particular time period.

The height of the ball after t seconds is as follows:

h(t)=[tex]-16t^{2} +48t[/tex]

It is at ground at the instants of t.

Hence,

[tex]-16t^{2} +48t[/tex]=0

-16t(t-3)=0

We want value of t different of 0, hence :

t-3=0

t=3.

Hence if the speed of the ball after kicking is 48 feet per second then the ball will return on the ground after 3 seconds.

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Answer:

B. t=3

Step-by-step explanation:

i took the test and got it right

Answer:

not sure but I think it is this

Answer:

10

Step-by-step explanation:

By the alternate interior angles theorem,

[tex]4x=2x+20 \\ \\ 2x=20 \\ \\ x=10[/tex]

The standard deviation exists as the positive square root of the variance.

So, the standard deviation = 4.47.

Given data set: 13 17  9 21

To calculate the mean of the data.

We know that mean exists as the average of the data values and exists estimated as:

Mean [tex]$=\frac{13+17+9+21}{4} \\[/tex]

Mean [tex]$=\frac{60}{4} \\[/tex]

Mean = 15

To find the difference of each data point from the mean as:

Deviation:

13 - 15 = -2

17 - 15 = 2

9 - 15 = -6

21 - 15 = 6

Now we have to square the above deviations we obtain:

4, 4, 36, 36

To estimate the variance of the above sets:

variance [tex]$=\frac{4+4+36+36}{4}$[/tex]

Variance [tex]$=\frac{80}{4}$[/tex]

Variance = 20

The standard deviation exists as the positive square root of the variance. so, the standard deviation [tex]$=\sqrt{20 }=4.47$[/tex].

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Answer:

4.4

Step-by-step explanation:

The answer above is correct.

The answer is B.

If the terminal point of θ is at (0, -1), then tanθ is equal to :

The tangent of the given angle is undefined, so the correct option is B.

The tangent function is one of the main six trigonometric functions and is generally written as tan x. It is the ratio of the opposite side and the adjacent side of the angle in consideration in a right-angled triangle.

Given that on a unit circle, the terminal point of θ is (0, - 1) we need to determine tan θ,

We know that the terminal point of θ is (0, -1).

Now, the tangent of an angle is equal to the quotient between the y-component and the x-component of the terminal point, then we have:

tan(θ) = =1/0

And we can't divide by zero, so it is undefined, then the correct option is B.

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By evaluating the function, we conclude that f(10) = -7

Here we know that:

g(x) = 2x - 8

And f(x) = 5 - g(x).

Then we can write:

f(x) = 5 - (2x - 8) = 5 - 2x + 8 = -2x + 13

Now we want ot evaluate it in x = 10, this means replace the variable by the number 10.

f(10) = -2*10 + 13 = -20 + 13 = -7

Then, we conclude that f(10) = 7

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Answer:

a = 97° , b = c = 146°

Step-by-step explanation:

a and 83° are same- side interior angles and sum to 180°

a + 83° = 180° ( subtract 83° from both sides )

a = 97°

34° and b are same- side interior angles and sum to 180°

b + 34° = 180° ( subtract 34° from both sides )

b = 146°

b and c are corresponding angles and are congruent , so

c = b = 146°

Answer:

< a = 97 degrees.

< b = 146 degrees.

< c = 146 degrees.

Step-by-step explanation:

We have 2 lines crossing 2 parallel lines.

Internal angles between the 2 parallel lines add up to 180 degrees, so

34 + <b = 180

<b = 180 - 34 = 146 degrees

Also

<a + 83 = 180 degrees (also internal angles)

---> <a = 97 degrees

< c and < b are corresponding angles so are congruent, therefore

<c = < b = 146 degrees.

Solving a system of equations we can see that:

Let's define:

When the airplane travels against the wind, the total speed is:

(A - W)

In this way, we know that the airplane travels 1350 miles in 5 hours, then:

(A - W) = 1350mi/5h

When the airplane travels with the wind, it takes 3.75 hours to travel the same distance, then:

(A + W) = 1350mi/3.75h

We have now a system of equations:

(A - W) = 1350mi/5h

(A + W) = 1350mi/3.75h

If we isolate A on the first equation, we get:

A = 270mi/h + W

Replacing that in the other equation we get:

270mi/h + W + W = 360 mi/h

Solving for W we get:

2*W = 360mi/h - 270mi/h = 90mi/h

W = 90mi/h = 45mi/h

And the airplane rate is:

A =  270mi/h + W = 270mi/h + 45mi/h = 315 mi/h

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Answer:

  0.33 ⋅ 10^−15

Step-by-step explanation:

Scientific notation requires exactly one non-zero digit to the left of the decimal point.

The number ...

  0.33 ⋅ 10^−15

has no non-zero digits to the left of the decimal point. It is not in "scientific notation."

__

Additional comment

Expressed in scientific notation, it would be ...

     3.3 ⋅ 10^−16

Answer:

  140 cm

Step-by-step explanation:

The distance of the foot of the ladder from the building can be found using the Pythagorean theorem (or your knowledge of Pythagorean triples). Once the two distances are found, their difference can be found.

The 650 cm ladder reaches 520 cm up the side of the building. The ratio of these side lengths is 650/520 = 5/4, suggesting these are the sides of a 3-4-5 right triangle. The distance from the building is ...

  (3/5)×650 cm = 390 cm.

Alternatively, the distance (a) from the building can be found using the Pythagorean relation ...

  a² +b² = c²

  a² +520² = 650²

  a = √(422500 -270400) = √152100 = 390 . . . cm

The 650 cm ladder reaches 520 +80 = 600 cm up the side of the building. The ratio of these side lengths is 650/600 = 13/12, suggesting these are the sides of a 5-12-13 right triangle. The distance from the building is ...

  (5/13)×650 cm = 250 cm

Again, the Pythagorean theorem can be used to obtain the same result:

  a = √(422500 -360000) = √62500 = 250 . . . cm

The difference between the two distances is ...

  390 cm -250 cm = 140 cm

The foot of the ladder will be 140 cm closer to the building.

Answer:

Your answer is 7^2.

Step-by-step explanation:

-------------------------

Have a great day,

Nish

The equivalent expression is [tex]7^{2}[/tex].

We have the following expression -

[tex]\frac{7^{-3} }{7^{-5} }[/tex]

We have to find its equivalent value.

[tex]f(x, y) =\frac{A^{x} }{A^{y} }[/tex]

In order to divide two exponents with same base, we use the 'Quotient property of exponents.

The equivalent expression can be written as -

f(x, y) = [tex]A^{x} A^{-y} = A^{x-y}[/tex]

In the question given we have -

[tex]\frac{7^{-3} }{7^{-5} }[/tex]

Using the property discussed above -

[tex]7^{-3}\;7^{5}[/tex] = [tex]7^{-3+5}[/tex] = [tex]7^{2}[/tex]

Hence, the equivalent expression is [tex]7^{2}[/tex].

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Using the Pythagorean Theorem, it is found that the unknown side length of the triangle is of 7.9 cm.

The Pythagorean Theorem relates the length of the legs [tex]l_1[/tex] and [tex]l_2[/tex] of a right triangle with the length of the hypotenuse h, according to the following equation:

[tex]h^2 = l_1^2 + l_2^2[/tex]

Researching this problem on the internet, we have that:

Hence:

x² + 9² = 12²

x = sqrt(12² - 9²)

x = 7.9 cm.

The unknown side length of the triangle is of 7.9 cm.

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Answer:

16 square units

Step-by-step explanation:

You find the area by multiplying the base times the height.  The base or horizonal length is 4.  You get this from the ordered point x (4,0).  The x coordinate 4, tells us that the point x is 4 spaces to the right of zero, so the length or base is 4.

The height is also 4.  You get this from the point S (2,4)  The y coordinate of 4 tells you how high up the point is.

4 x 4 = 16

The equation of the vertical asymptote of the function [tex]g(x)=4log_{2} (x-2)+5[/tex] is x=2.

Vertical asymptotes are vertical lines that represent the zeros of a rational function's denominator. Asymptotes can also occur in other situations, such as logarithms. It occurs at the x-value that is outside the domain of the function, therefore the graph can never cross it.

There may be a vertical asymptote along the vertical line if a portion of the graph is about to turn vertical. At the point of x along which you discovered the vertical asymptote, the function's value changes to either ∞ or -∞. A vertical asymptote, however, must never touch the graph.

Graph the function [tex]g(x)=4log_{2} (x-2)+5[/tex]

(x,y)= (3,5), (4,9), (6,13)

From graph we can see that the graph is turning to be vertical from x=2. So, the equation of vertical asymptote of the function is x=2.

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The complete question is:

“What is the equation of the vertical asymptote of [tex]g(x)=4log_{2} (x-2)+5[/tex]? enter your answer in the box.”

Answer:

Situation 2 (B)

Step-by-step explanation:

I think it would be B since the power of the gear increases proportionally with the radius.

Answer:

The answer is 314

Step-by-step explanation:

You need to do

3.14(pie) times the radius times the height divided by 3

Answer:

C. 314 [tex]in^{3}[/tex]

Step-by-step explanation:

The volume of a cone is: 1/3[tex]\pi[/tex][tex]r^{2}[/tex]h'

1/3 x 3.14 x [tex]5^{2}[/tex] x 12

1/3 x 3.14 x 25 x 12

1/3 x 3.14 x 300

100 x 3.14

V = 314

Answer:$6

Step-by-step explanation:

If only 3 got the children's price, that means there were 4 adult tickets.
4*11=44

62-44=18

18/3=6

$6 per child ticket

Answer:

The rope is worth 13.

The shoe is worth 5.

The clock is worth 3.

Step-by-step explanation:

We know that the weights are 8 so we will use 8 for the weights.

Let s = show

Let r = rope

Let c = clock

We have three unknowns so we need three equations.

8 + s = r                      c + s = 8                                 s= c +2

There are a number of ways that we can approach this.  Let's substitute

c + 2 for s in the first 2 equations.

8 + s = r

8 + c + 2 = r

10 + c = r

c + s = 8

c + c + 2 = 8

2c + 2 = 8  

2c = 6

c = 3  we found the value of the clock.

Now, let's substitute 3 in for 3 in the bold equation above.

10 + c = r

10 + 3 = r

13 = r we found the value of the rope.

We can use any of the equations to find the shoe.

s= c + 2

s = 3 + 2

s = 5

This is tricky.  It takes a lot of practice.  Don't give up!

Shoe= 5

Rope= 13

Clock= 3

We can start by giving each item a variable. Shoe= s, rope= r, clock= c. The weight is 8, so we don't need to give it a variable. Our equations are now:

8+s= r

c+s= 8

s= c+2

Now, we can isolate a variable to solve for it using the substitution method. Let's start with s.

c+s=8

-c    -c

s= 8-c

Now, we'll take another equation and plug s in.

8-c=c+2

 +c +c

8= 2c+2

-2      -2

6=2c

c=3

Now we know that the clock is 3. Put 3 into the last equation, and add 3+2 to get 5 for the shoe. 5 in the first equation for the shoe plus 8 as the weight means the rope is 13.

hope this helped!

Recall that for [tex]|x|<1[/tex], we have the convergent geometric series

[tex]\displaystyle \sum_{n=0}^\infty x^n = \frac1{1-x}[/tex]

Now, for [tex]\left|\frac x5\right| < 1[/tex], we have

[tex]\dfrac1{5 - x} = \dfrac15 \cdot \dfrac1{1 - \frac x5} = \dfrac15 \displaystyle \sum_{n=0}^\infty \left(\frac x5\right)^n = \sum_{n=0}^\infty \frac{x^n}{5^{n+1}}[/tex]

Integrating both sides gives

[tex]\displaystyle \int \frac{dx}{5-x} = C + \int \sum_{n=0}^\infty \frac{x^n}{5^{n+1}} \, dx[/tex]

[tex]\displaystyle -\ln(5-x) = C + \sum_{n=0}^\infty \frac{x^{n+1}}{5^{n+1}(n+1)}[/tex]

If we let [tex]x=0[/tex], the sum on the right side drops out and we're left with [tex]C=-\ln(5)[/tex].

It follows that

[tex]\displaystyle \ln(5-x) = \ln(5) - \sum_{n=0}^\infty \frac{x^{n+1}}{5^{n+1}(n+1)}[/tex]

or

[tex]\displaystyle \ln(5-x) = \boxed{\ln(5) - \sum_{n=1}^\infty \frac{x^n}{5^n n}}[/tex]

The total price paid by Mr. Thapa as per the new rating will be equal to Rs 180.

The four basic operations of arithmetic can be used to add, subtract, multiply, or divide two or even more quantities.

They cover topics like the study of integers and the order of operations, which are relevant to all other areas of mathematics including algebra, data processing, and geometry.

As per the given information in the question,

Total distance traveled by Mr. Thapa = 5 km = 5000 meters.

The initial price paid for the taxi = Rs 14

Then, the meter was flagged down, then the fare went to rs 7.20 per 200 m.

Let the price paid after 5 km is x.

So, the ratio will be,

200 m = Rs 7.20

5000 m = x

Perform cross-multiplication,

200x = 5000 × 7.20

200x = 36000

x = 36000/200

x = Rs 180

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