List 4 major types of inhibition modes and clearly indicate the effect on vmax and km for each mode?

Answers

Answer 1

The 4 major types of inhibition are  Competitive Inhibition, Non-competitive Reversible Inhibition,  Non-competitive Irreversible Inhibition, and  Uncompetitive Inhibition.

Types of inhibition modes:

1. Competitive Inhibition: Competing inhibitors are substances that resemble an enzyme's natural substrate so closely that they vie for the active site. In order to stop additional reactions, the inhibitor binds to the active site and stays there.

The inhibitor and substrate fight for the enzyme's active site because the enzyme may react with the inhibitor and release the products as it normally would with its substrate

2. Non-competitive Inhibition:

Reversible: There is no competition in this instance because the inhibitor and substrate are not related. The substrate and the inhibitor may mix at various places of the complexes of the enzymes [E-I], [E-S], and [E-I-S].

And in the Michaelis equation, this kind of inhibition lowers V max but has no impact on Km.The rate at which the enzyme is fully saturated is given by V = V max [S] / Km + [S] (V max).

(Km): The substrate is the Michaelis constant, at which the reaction rate is halved, or at V maximum.

Irreversible: These kinds of inhibitors impact the chemical alteration of an amino acid residue in the enzyme that plays a function in catalysis when they join with the enzyme nearby or at the active site.

       Additionally, this kind of inhibition lowers Vmax but has no impact on Km.

3. Uncompetitive Inhibition: is the last type, where the inhibitor attaches to the [E-S] complex to create [E-S-I] even if it has no affinity for the enzyme.

However, this kind of inhibition lowers both Vmax and Km.

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Related Questions

In Birkeland and Eyde's process, ____ is prepared from atmospheric oxygen and nitrogen.

Answers

Synthetic fertilizer

What is  Birkeland and Eyde's process?

It is a process developed by two scientists - Kristian Birkeland and  Sam Eyde - to fix atmospheric nitrogen for the production of fertilizer.

The nitrogen oxide produced is then used in the production of nitric acid and eventually, the production of synthetic fertilizer.

First, nitrogen is fixed into nitrogen oxide:

[tex]N_2 + O_2 --- > 2NO[/tex]

Then, the NO is oxidized:

[tex]2NO + O_2 -- > 2NO_2[/tex]

The nitrous oxide produced is then dissolved in water to form nitric acid:

[tex]3NO_2 + H_2O --- > 2HNO_3 + NO[/tex]

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Calculate how many moles of nh3 form when each quantity of reactant completely reacts?

Answers

3.6 moles [tex]NH_{3}[/tex] required when each quantity of reactant completely reacts.

The ratio of the mole quantities of any two compounds present in a balanced chemical reaction is known as the mole ratio. A reaction's product yield can be predicted using mole ratios, as can the amount of reactant required to produce a specific amount of result.

The balanced chemical equation is :

[tex]3N_{2} H_{4}[/tex](l) → [tex]4NH_{3}[/tex](g) + [tex]N_{2}[/tex](g)

Given is = 2.6 mol [tex]N_{2} H_{4}[/tex]

As we see, 3 moles of [tex]N_{2} H_{4}[/tex] reacts with  4 moles of [tex]NH_{3}[/tex].

Therefore,

n( [tex]NH_{3}[/tex]) = n(  [tex]N_{2} H_{4}[/tex] ) × [tex]\frac{4}{3}[/tex]

n( [tex]NH_{3}[/tex]) = [tex]2.6mol^{*} \frac{4mol}{3mol}[/tex]

n( [tex]NH_{3}[/tex]) = 3.6 moles.

Therefores, 3.6 moles [tex]NH_{3}[/tex] required when each quantity of reactant completely reacts.

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All simple metal with acid reactions are ____ displacement reactions.

Answers

Answer:

single displacement

Explanation:

the metal replaces the hydrogen of the acid to for a salt and hydrogen gas

How many electrons are transferred in the given redox reaction? zn 2agno3⟶2ag zn(no3)2

Answers

The electrons are transferred in the given redox reaction are 2 electrons.

what is redox reaction?

When oxidation and reduction that is gaining of electron and loosing of electrons takes place simultaneously in a chemical reaction then it would be known as redox reaction.

In terms of oxygen the gaining of oxygen is oxidation and loosing of oxygen is reduction.

In the given chemical reaction the transfer of two electrons will be as follows

Zn₂ (2e) + AgNo₃ → 2Ag (2e) + Zn(NO₃)₂

It is clear from the reaction their is transfer of two electrons zinc is loosing 2 electrons undergoes to oxidation while silver gets reduced.

Therefore, transfer of only two electrons.

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A 200. 0-ng sample of sodium-24 was stored in a lead-lined cabinet for 45 hours. The half-life of sodium-24 is 15 hours. How much sodium-24 remains?

Answers

Answer:

25 gm would be left

Explanation:

45 hours is 3 half lives

200 gm  * 1/2 * 1/2 * 1/2 = 25 gm

According to the concept of half life , as 45 hours are equal to three half- lives after 3 half-lives 25 g of sodium-24 remains.

What is half-life?

Half -life of a substance is defined as the time which is required for half of the quantity of a radioactive substance to get decayed.It is a term which is used in nuclear chemistry for describing how quickly unstable atoms undergo radioactive decay into other nuclear species by emitting particles or the time which is required for number of disintegrations per second of radioactive material to decrease by one half of its initial value.

In the given problem time is=45 hours and as 1 half  life=15 hours , for 45 hours=45/15=3 half lives .

Amount of sodium-24 after 3 half lives= 200×1/2×1/2×1/2=25 grams.

Therefore, after 45 hours 25 g of sodium-24 remains.

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What is the molality of a solution containing 3. 0 moles of nacl and 100. 0 moles of water?

Answers

The molality of a solution containing 3. 0 moles of NaCl and 100. 0 moles of water is 30 mol/kg.

The number of moles of solute in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality. Mole per kilogram of solvent is the SI unit for molality.

Given:

3.0 moles of NaCl in 100 moles of water.

To find:

The molality of the solution

The moles of solute (NaCl) = 3.0 moles

The mass of solvent (water) = 100 moles (0.1 kg/mol)

Molality of a solution = Number of Moles of solute/ Mass of solvent(kg)

                                 = 3.0 moles/0.1 kg/mol

                                 = 30 mol/kg

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CaCO3(s) CaO(s) + CO₂(g)
3.25 mol CaCO3 decomposes according to the reaction above. What volume of CO2 gas is produced once the gas cools to STP?

Answers

Taking into account the reaction stoichiometry and the definition of STP, 72.8 L of CO₂ gas is produced once the gas cools to STP.

Reaction stoichiometry

In first place, the balanced reaction is:

CaCO₃  → CaO + CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CaCO₃: 1 moleCaO: 1 moleCO₂: 1 mole

STP  conditions

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

Moles of CO₂ formed

The following rule of three can be applied: if by reaction stoichiometry 1 mole of CaCO₃ form 1 mole of CO₂, 3.25 moles of CaCO₃ form how many moles of CO₂?

[tex]moles of CO_{2} =\frac{3.25 moles of CaCO_{3}x 1 mole of CO_{2}}{1 moleof CaCO_{3}}[/tex]

moles of CO₂= 3.25 moles

Then, 3.25 moles of CO₂ are formed when 3.25 moles of CaCO₃ decomposes.

Now, you can apply the following rule of three: if by definition of STP conditions 1 mole of CO₂ occupies a volume of 22.4 liters, 3.25 moles occupies how much volume?

[tex]volume= \frac{3.25 molesx22.4 L}{1 mole}[/tex]

volume= 72.8 L

Finally, 72.8 L of CO₂ gas is produced once the gas cools to STP.

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Match the following vocabulary words with their correct definitions.
1. single displacement
2. reactant
3. double displacement
4. product
One of the starting substances
involved in a chemical reaction.
lons in aqueous compounds
exchange cations and anions
respectively.
A substance formed as a result of a
chemical reaction.
One element replaces another in a
compound.

Answers

Single displacement

One element replaces another in a compound.

Reactant

One of the starting substances involved in a chemical reaction.

Double displacement

Ions in aqueous compounds exchange cations and anions respectively.

Product

A substance formed as a result of a chemical reaction.

The chemical breakdown of starch that occurs in the mouth is due to the enzyme action of:_______.

Answers

Because of the enzyme action of Amylase, the chemical breakdown of starch happens in the mouth.

It is an enzyme, simply a type of protein that aids in breaking down the carbohydrates in your body. The main two glands as the pancreas and salivary glands help in making amylase in your mouth.

A small amount of amylase is also present in your urine and blood. If the levels present in your body are high then it causes health problems.

The amylase test performs to know the amount of amylase present in your body. This test is called as "amy test".

The normal range of Amylase in the human body is 40 to 140 U/L or 0.38 to 1.42 microkat/L.

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Identify the classification of milk a aerosol b solid emulsion c solid aerosol d foam e emulsion

Answers

option (c) emulsion is the right answer

Emulsion is a classification of milk.

Describe an emulsion.

In physical chemistry, an emulsion is a combination of two or more liquids in which one of the liquids is present as microscopic or ultramicroscopic droplets dispersed throughout the other.

How is emulsion used?

Emulsions form as a result of the cleansing action of soaps.

(ii) The emulsification process is how lipids are broken down in the intestines.

(iii) Disinfectants and antiseptics combine with water to generate emulsions.

(iv) The emulsification technique is utilized to create medications.

How is an emulsion created?

When two immiscible liquids, such as oil and water, are stirred together with an emulsifier—which might be a protein, phospholipid, or even a nanoparticleemulsion is created.

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As a gaseous element condenses, the atoms become ________ and they have ________ attraction for one another.

Answers

As a gaseous element condenses, the atoms become close together and they have more attraction for one another.

What is condensation?

Condensation is the transformation of water from its gaseous or vaporous state into its liquid state. It typically occurs when warm airborne vapor comes into contact with a cold surface. When gas molecules transfer their energy to a cooler surface, they begin to slow down and attract one another, forming a liquid.

Examples:

Dew in the morning occurs when moisture in the air condenses on grass that has been chilled over night.Droplets on the soda can. Moisture from the warm outer air condenses on the outside of the can due to its cool surface.A foggy windscreen. The moisture in the air in your automobile is increased by the breath and body heat of the passengers. The moisture condenses as droplets that fog your window when there is enough moisture present and a chilly enough windscreen.

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A toy truck has a speed of 10 m/s and kinetic energy of 50 J. What is its mass?

A. 5 kg
B. 4 kg
C. 1 kg
D. 3 kg

Answers

Answer: 5kg

Explanation: formula K=1/2mv^2

50=10m

Answer:

C

Explanation:

KE = 1/2 m v^2

KE *2 / v^2   = m

50 (2)/ 10^2   = m =  1 kg

URGENT 80 POINTS AND BRAINLIEST FOR ANSWER
this wuestion or photo is on my chemistry DBA laster today, what is it? please explain possible questions and responses and answers to what may be asked.
i think it involves things like the reaction moving forward and what would do that or somehing but i am unsure. something online said stuff that raise pressure was the answer to something but why?
sorry if this is confusing i havent been given an actual question for this yet but need to know ahead of time.

Answers

I suggest researching if you still don’t understand but here’s the general idea

Reaction rate is increased by an increase in kinetic energy
of the reacting particles when their
is _____________
increased


A . Collision theory
B . Surface Area
C . Temperature
D. Concentration

Answers

Answer:

Reaction rate is increased by an increase in kinetic energy

of the reacting particles when their

is _temperature_

increased

A . Collision theory

B . Surface Area

C . Temperature

D. Concentration

In the cathode ray tube experiment, j. j. thomson passed an electric current through different gases inside a cathode ray tube in the presence of an electric field. in which two ways did this experiment change scientists’ understanding of the atom?

Answers

The two ways were,

It showed that atoms can be divided into smaller parts. It showed that all atoms contain electrons.

What is Cathode ray tube experiment ?

A cathode-ray tube, often known as a CRT, is a vacuum tube that houses one or more electron cannons that produce electron beams that are then bent to produce pictures on a phosphorescent screen. The visuals might be pictures (from a television or computer display), electrical waveforms (from an oscilloscope), radar targets, or other occurrences.

Tomson came to the conclusion that atoms can be divided into their constituent corpuscles (atoms are made up of smaller particles).

The electron was discovered in 1897 by J. J. Thomson.

His "plum pudding" concept from 1904 postulated that the positive charge contains embedded electrons.

With this model, he disproved his first theory (the atom was composed of immaterial vortices).

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Calculate the molar solubility of silver(i) bromate with ksp = 5. 5×10-5. also, convert the molar solubility to the solubility. the molar solubility is ___________ and the solubility is ____________

Answers

The molar solubility is 7.4×[tex]10^{-3}[/tex] M and the solubility is  7.4×[tex]10^{-3}[/tex] g/L .

Calculation ,

The dissociation of silver bromide is given as ,

[tex]AgBr[/tex] → [tex]Ag ^{+}[/tex] + [tex]Br^{-}[/tex]

S  

 -          S        S        

Ksp =  [[tex]Ag ^{+}[/tex] ] [ [tex]Br^{-}[/tex] ]  =  [S] [ S ] = [tex]S^{2}[/tex]

S = √ Ksp = √ 5. 5×[tex]10^{-5}[/tex] = 7.4×[tex]10^{-3}[/tex]

The solubility =7.4×[tex]10^{-3}[/tex] g/L

The molar solubility is the solubility of one mole of the substance.

Since ,  one mole of [tex]AgBr[/tex] is dissociates and form one mole of each  [tex]Ag ^{+}[/tex] and [tex]Br^{-}[/tex] ion . So, solubility is equal to molar solubility but unit is different.

Molar solubility = 7.4×[tex]10^{-3}[/tex] mol/L = 7.4×[tex]10^{-3}[/tex] M

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A 5.00 g sample of hydrated sodium tetraborate, Na2B4O7 x nH2O is heated to drive off the water. After heating, 2.64 g of anhydrous Na2B4O7 reasons. What is the value of "n" in the hydrate formula

Answers

The value of ''n" in the hydrate formula is 10

Moles of anhydrous sodium tetraborate:

Mass of anhydrous NA2B4O7 = 2.64g

Molar mass of NA2B4O7 = 201.224 g/mol

Number of Moles of anhydrous NA2B4O7 = Mass of NA2B4O7 / Molar mass of NA2B4O7

                                                     = 2.64 / 201.224

                                                     = 0.0131 mol

Mass of water in 5.00g of NA2B4O7 = 5.00 - 2.64

                                                              = 2.36 g

Moles of water = 2.36 / 18.015

                          = 0.1307 mol

The whole number ratio = moles of water / moles of anhydrous sodium tetra borate

                                           = 0.1307 / 0.0131

The whole number ratio = 10

Hence the value of n in the hydrate formula is 10.

NA2B4O7. 10H2O

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During transpeptidation, nucleophilic attack occurs between the α-amine group in the ____ site and the esterified carbon in the ____ site.

Answers

During transpeptidation, nucleophilic attack occurs between the α-amine group in the A site and the esterified carbon in the P site

What is transpeptidation ?

A chemical process in which an amino acid residue or peptide residue is transferred from one amino compound to another. This process occurs when a protease reversibly converts one peptide to another.

a process where one or more amino acids are transferred from one peptide chain to another, as in the case of a transpeptidase activity, or where a peptide chain itself is produced, as in the case of the production of a bacterial cell wall.Peptidoglycan glyco-syltransferases create the glycan strands (PGTs). The most popular class of antibiotics' fatal targets are enzymes termed transpeptidases (TPs), which produce the peptide crosslinks: using beta-lactams

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A gas has a volume of 27. 5 L at 302 k and 1. 40 atm. How many moles are in the sample of gas?

Answers

There are  1.554 moles are in the sample of gas when a  gas has a volume of 27. 5 L at 302 K and 1. 40 atm.

Calculation,

The given question is solved by the using of ideal gas equation which is shown below.

PV = nRT                               .... ( i )

where , P is he pressure of the gas = 1. 40 atm

V is the volume occupied by the gas = 27.5 L

R is the universal gas constant = 0.082 L atm/K mol

T is the temperature =  302 K

n is he number of moles of the gas = ?

By putting the value of pressure  P , volume V , Universal gas constant and temperature T in the equation ( i ) we get the number of moles.

1. 40 atm × 27.5 L = n × 0.082 L atm/K mol×  302 K

n = 1. 40 atm × 27.5 L/0.082 L atm/K mol×  302 K = 1.554 mole

There are  1.554 moles are in the sample of gas

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Select true or false: the work done on the surroundings by the expansion of a gas is w = –pdv

Answers

The work done on the surroundings by the expansion of a gas is w = –pdv .The statement is true.

The work is the energy required to move a system or body or anything against a force is called work. The word done = force×distance

Work done in an isobaric process is given by

W = PΔV

Where W = Work done

P =pressure

ΔV = change in volume

In a free expansion , the gas is allowed to expand into a vacuum.

This happens so quickly , so there is no heat transferred . No work is done , because the gas does not display anything.

W = PΔV

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The molar volume of copper (63.5 g.mol^–1 ) at 25°C is 7.09 cm^3.mol^–1. What is the density of copper at 25°C in g.cm^3?

Answers

Considering the definition of molar volume and density,the density of copper at 25°C is 8.96 [tex]\frac{g}{cm^{3} }[/tex].

Molar volume

Molar volume is an intensive property that indicates how much space one mole of a certain substance or compound occupies. In other words, the molar volume is the space occupied by one mole of a substance.

The expression to calculate the molar volume is:

Vm= V÷ n

where:

V is the occupied volume.n is the molar amount of the substance.

Density

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density= mass÷ volume

Relationship between molar volume and density

The relationship between molar volume and density is reflected in the following expression, where the molar volume is calculated by dividing the molar mass (M) by the mass density (ρ):

Vm= M÷ρ

Density of copper

In this case, you know:

Vm= 7.09 [tex]\frac{cm^{3} }{mol}[/tex]M= 63.5 [tex]\frac{g}{mol}[/tex]ρ= ?

Replacing in the relationship between molar volume and density:

7.09 [tex]\frac{cm^{3} }{mol}[/tex]= 63.5 [tex]\frac{g}{mol}[/tex]÷ρ

Solving:

7.09 [tex]\frac{cm^{3} }{mol}[/tex]×ρ= 63.5 [tex]\frac{g}{mol}[/tex]

ρ= 63.5 [tex]\frac{g}{mol}[/tex]÷7.09 [tex]\frac{cm^{3} }{mol}[/tex]

ρ= 8.96 [tex]\frac{g}{cm^{3} }[/tex]

Finally, the density of copper at 25°C is 8.96 [tex]\frac{g}{cm^{3} }[/tex].

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What would the potential of a standard hydrogen electrode (s. h. e. ) be under the given conditions? [h ]=0. 84 mh2=2. 2 atm=298 k

Answers

The potential of a standard hydrogen electrode (s. h. e. ) be under the given conditions is - 0.029 V

Calculation ,

Formula used :

[tex]E_{cell}[/tex] = [tex]E_{cell}[/tex] ° - 0.059/n ㏒[tex]H_{2}[/tex]/ [tex][H^{+}]^{2}[/tex]

As we know that ,

[[tex]H^{+}[/tex]] = 0. 84 M

[tex]P_{H_{2}[/tex] = 2. 2 atm

Temperature ( T ) = 298  K

From reaction at electrode number of electrons involve ( n ) = 1

Standard electrode potential of  standard hydrogen electrode [tex]E_{cell}[/tex] ° = 0

Putting the value of all data in equation ( i ) , we get

[tex]E_{cell}[/tex] = 0  - 0.059/1 ㏒2. 2 / [tex](0. 84)^{2}[/tex] =  - 0.059 ㏒3.14 =  - 0.059×0.497

[tex]E_{cell}[/tex] = - 0.029 V

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What can be said about this reaction when the concentration of 2-phosphoglycerate is 0.490 mm and the concentration of 3-phosphoglycerate is 2.90 mm at 25°c?

Answers

The reaction is at equilibrium. Option C

What is the equilibrium constant?

The term equilibrium constant refers to a value that shows the extent to which reactants are converted into products in the reaction.

We know that;

∆G =∆G'° + RT In Keq

∆G'°  = −4.40 kJ/mol

R = 8.314 J/K/mol

T = 25 + 273 = 298 K

Thus;

∆G = −4.40 * 10^3 + (8.314 *  298  * ln[2.90 * 10^-3/0.490  * 10^-3]

∆G =  −4.40 * 10^3 + 4.40 * 10^3

∆G = 0

Hence, the reaction is at equilibrium.

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1) Consider the following metabolic reaction:

2-Phosphoglycerate ® 3-Phosphoglycerate DG°' = −4.40 kJ/mol

What can be said about this reaction when the concentration of 2-phosphoglycerate is 0.490 mM and the concentration of 3-phosphoglycerate is 2.90 mM at 25°C?

I. This reaction is endergonic under these conditions.

II. This reaction is exergonic under these conditions.

III. This reaction is at equilibrium under these conditions.

IV. This reaction is not favorable under standard conditions.

A) I, IV

B) II only

C) III only

D) IV only

E) None of the above

2) Consider the following metabolic reaction:

What is the "average atomic mass" of this set of pennies.

(can you guys also include a formula on how i can solve future problems like this, please.)

Answers

Answer:

A. 2.74g is the correct answer

Explanation:

Greetings!

[tex]average \: mass = \frac{(mass \: pre - 1982 \times abundance) + (mass \: post - 1982 \times abundance}{100 } \\ ave = \frac{ (3.1g \times 40.0) + (2.5g \times 60.0)}{100} \\ ave = \frac{124 + 150}{100} \\ ave = \frac{274}{10} = 2.74g[/tex]

where, the sum of abundance always have to be 100%

Thus, 40.0 +60.0= 100.0

2C6H6(g) + 15O2(g) = 12CO2(g) + 6H2O(g)


2.0 moles C6H6 reacts with oxygen according to the reaction above. What volume of water vapor forms at STP?

Answers

At STP, the volume of water that is produced is 134.4 L.

What is the volume?

Now we know that the equation of the reaction is;

2C6H6(g) + 15O2(g) = 12CO2(g) + 6H2O(g)

We can use the stoichiometry of the reaction to determine the volume of the water produced as follows;

2 mole of C6H6 produced 6 moles of water. If 1 mole of water occupies 22.4 L then 6 moles of water will occupy 6 * 22.4 L = 134.4 L

Thus, we can see that at STP, the volume of water that is produced is 134.4 L.

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It takes 11. 2 kj of energy to raise the temperature of 145 g of benzene from 23. 0°c to 68. 0°c. what is the specific heat of benzene?

Answers

If we takes 11. 2 kj of energy to raise the temperature of 145 g of benzene from 23. 0°c to 68. 0°c, then the specific heat of benzene is

1716.475 J/kg.°C.

Specific Heat capacity is given as

Q = cm(t₂-t₁) ................[tex]equation 1[/tex]

Where Q = quantity of heat, c = specific heat of benzene, m = mass of benzene, t₁  = initial temperature, t₂ = final temperature.

[tex]C[/tex] = [tex]\frac{Q}{m_{(t2-t1)} } ...........equation 2[/tex]

Given:

[tex]Q = 11.2 kJ = 11200 J \\\\m= 145\\\\g = 0.145 kg\\\\t_{2} = 68.0 °C\\\\t_{1} = 23.0 °C[/tex]

Substitute into equation 2.

[tex]C = \frac{11200}{[0.145(68-23)]}\\\\ C= \frac{11200}{6.525}\\\\ C= 1716.475 J/kg °C[/tex]

Hence the specific heat of benzene = [tex]1716.475 J/kg °C[/tex]

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In a chemical hot pack, iron powder and oxygen react to form iron oxide in the presence of a catalyst. This reaction causes the temperature of the hot pack to increase. This process is

Answers

Answer:

exothermic

Explanation:

exothermic reactions give off heat.....or the temp of the substances increases

A sample 0. 100 moles of a gas is collected at at stp. What is the volume of the gas in liters?

Answers

A sample 0. 100 moles of a gas is collected at at STP . 2.24 is the volume of the gas in liters.

The STP means standard temperature and pressure.

At STP,

Temperature = 0 °C =273 K

Pressure = 1 atm

We get value of volume by using ideal gas equation,

PV = nRT

P is the pressure of the gas = 1 atmV is the volume occupied by the gas = ?n is the number of the moles = 1 moleT is the temperature of the gas = 273 K or  0 °CR universal gas constant = 8.31 J/ mole × K

Calculation,

Since, one mole of a gas occupy 22.4 L volume at STP

So, for 0.1 mole volume occupy = 22.4L × 0.1 mole/1 mole =  2.24L

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When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. what is the net ionic equation for this reaction?

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When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).

What is Balanced Chemical Equation ?

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now first write the balanced chemical equation

CuSO₄ (aq) + Na₂S (aq)  → CuS(s) + Na₂SO₄ (aq)

Now write the net ionic equation

Cu⁺² (aq) + SO₄⁻² (aq) + 2Na⁺ (aq) + S⁻² (aq) → CuS (s) + 2Na⁺ + SO₄⁻² (aq)

So the net ionic equation is

Cu⁺² (aq) + S⁻² (aq) → CuS (s)

Thus from the above conclusion we can say that When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).

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You are asked to weigh approximately 0. 4g of acetylsalicylic acid to the nearest mg. When you enter the data in grams in your lab notebook, how many significant figures will you record ?.

Answers

Number of significant figures will be 1.

Given:

weight of acetylsalicylic acid = 0. 4g

Significant figures are the digits of value which carry meaning towards the resolution of the measurement. They are also called significant figures in chemistry. All the experimental measurements have some kind of uncertainty associated with them.

When we convert 0.4g acetylsalicylic acid to mg we get value 400mg

when we convert 400mg to gram we get value of 0.4 gram

Since 0 before a decimal is not significant so there is only one significant figure that is 4.

How do you determine the number of significant figures?The zero to the left of a decimal value less than one is meaningless.All trailing zeros that are placeholders are meaningless.The presence of zeros between non-zero numbers is significant.Non-zero numbers are all significant.If a number contains more digits than the desired number of significant digits, it is rounded.Why 'Hidden Figures' is so important?

It's an important story for a variety of reasons, and it comes at a time when people are looking to Hollywood more than ever to tell stories that represent them. Hidden Figures is that movie for many, and it's critical that everyone sees these women in action. This is why. This film tells a story that you've probably never heard before.

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