Jocelyn has a ladder that is 15 ft long. She wants to lean the ladder against a vertical wall so that the top of the ladder is 13.5 ft above the ground. For safety reasons, she wants the angle the ladder makes with the ground to be less than 75°. Will the ladder be safe at this height? Show your work and equation to support your answer

Answers

Answer 1

By using trigonometric relations, we will see that the angle that the ladder makes with the ground is 64.2°, so we conclude that the ladder is safe.

Will the ladder be safe at this height?

Notice that the ladder makes a right triangle with the wall.

Such that the hypotenuse (the ladder itself) measures 15 ft, and one of the catheti (distance between the ground and top of the ladder) measures 13.5ft

If we considerate the angle that the ladder makes with the ground, the known cathetus is the opposite cathetus.

Then we can use the relation:

sin(x) = (opposite cathetus)/(hypotenuse)

Then:

sin(x) = (13.5ft)/(15ft)

If we use the inverse sine function on both sides, we get:

Asin(sin(x)) = Asin( 13.5ft/15ft)

x = Asin(13.5/15) = 64.2°

So the angle is less than 75°, which means that in fact, the ladder is safe.

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Related Questions

Find the solution of the differential equation that satisfies the given initial condition. dy/dx=x/y , y(0)=-1

Answers

Separating variables, we have

[tex]\dfrac{dy}{dx} = \dfrac xy \implies y\,dy = x\,dx[/tex]

Integrate both sides.

[tex]\displaystyle \int y\,dy = \int x\,dx[/tex]

[tex]\dfrac12 y^2 = \dfrac12 x^2 + C[/tex]

Given that [tex]y(0)=-1[/tex], we find

[tex]\dfrac12 (-1)^2 = \dfrac12 0^2 + C \implies C = \dfrac12[/tex]

Then the particular solution is

[tex]\dfrac12 y^2 = \dfrac12 x^2 + \dfrac12[/tex]

[tex]y^2 = x^2 + 1[/tex]

[tex]y = \pm\sqrt{x^2 + 1}[/tex]

and because [tex]y(0)=-1[/tex], we take the negative solution to accommodate this initial value.

[tex]\boxed{y(x) = -\sqrt{x^2+1}}[/tex]

ASAP HELP ME WITH THIS QUESTIONN

Answers

Answer:

inductive reasoning

Step-by-step explanation:

i need help w this pls

Answers

Answer: C

Step-by-step explanation: The y-intercept is 1/5 since the point on the y-axis is (0, 1/5). The slope is 2/3 because the other coordinate is up 2 and right 3 from (0, 1/5) *remember rise over run*. The shading means that the answer (y) must be less than or equal to 2/3x + 1/5, hence it being underneath the line.

Complete the equivalent fraction 3/5 = ?/10

Answers

Answer:

Step-by-step explanation:

3/5 = x/10

5x = 30

x = 6

6/10

Hey there!

Original equation:

3/5 = ?/10

Convert to:

3/5 = x/10

Cross multiply the numbers:

3 * 10 = 5 * x

Simplify it:

3 * 10 = 5 * x

30 = 5x

5x = 30


Divide 5 to both sides:

5x/5 = 30/5


Simplify it:

x = 30/5

x = 6


Therefore, your mystery number should be: 6


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

Prove that :-
(sinA + secA)² + (cosA + cosecA)² = 1 + secAcosecA​

Answers

May this answers be helps you to solve

In 5-card poker, the number of outcomes favorable to an event E is given in the table. Find the
probability of being dealt four of a kind or a a straight.
The probability of being dealt four of a kind or a straight is
(Round to 6 decimal places.)
Event E
Royal flush
Straight flush
Four of a kind
Full house
Flush
Straight
Three of a kind
Two pairs
One pair
No pair
Total
# of Outcomes Favorable to E
4
36
624
3744
5108
10,200
54,912
123,552
1,098,240
1,302,540
2,598,960

Answers

The probability of being dealt four of a kind or a straight is 0.00416 or 0.416%.

What is probability?

It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

It is given that:

In 5-card poker, find the probability of being dealt the following hand. Refer to the table.

From the table:

Total number of outcomes = 2598960

Total number of favorable outcomes = 624 + 10200 = 10824

The probability of being dealt four of a kind or a straight

P = 10824/2598960

P = 0.00416

In percentage:

P = 0.416%

Thus, the probability of being dealt four of a kind or a straight is 0.00416 or 0.416%.

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Someone please help me with this question

Answers

Answer: Neither

Step-by-step explanation:

It is not an angle of the quadrilateral, so it is not an interior angle.

It does not form a linear pair with any interior angle of the quadrilateral, so it is not an exterior angle.

ill give you brainliest :)

Answers

Following the instructions for the inequalities gives the following results:

1. 4<7, both sides multiplied by 7

= 28<49, both sides multiplied by 6

= 168<294, both sides multiplied by 3

= 504<882, both sides multiplied by 10

= 5,040<8,820

2. 11>2, add 5 to both sides

= 16>3, add 3 to both sides

= 19>9, add -4

= 15>5

3. -4<-2, subtract 6

= -10<-8, subtract 8

= -18<-16, subtract 2

= -20<-18

4. -8<8, divide by -4

= 2>-2, divide by -2

= -1<1

5. The inequalities remain correct at the end because the same mathematical operations are performed on both sides simultaneously.

What are inequalities?

Inequality is a relationship of a non-equal comparison between two numbers or algebraic expressions.

Inequality can be represented as greater than, greater than or equal to, less than, or less than or equal to.

Thus, the rules for inequalities show that if one adds to, subtracts from, multiplies by, or divides by the same number on both sides of an inequality, the inequality remains true.

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What is the equation of the circle that has its center at -26,120 and passed through the origin

Answers

well, first off let's check those two points, we know it's centerd at (-26 , 120) and we also know it passes through (0 , 0), so the distance between those two points is its radius

[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{-26}~,~\stackrel{y_2}{120})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{(~~-26 - 0~~)^2 + (~~120 - 0~~)^2} \implies r=\sqrt{(-26)^2 + (120 )^2} \\\\\\ r=\sqrt{( -26 )^2 + ( 120 )^2} \implies r=\sqrt{ 676 + 14400 } \implies r=\sqrt{ 15076 } \\\\[-0.35em] ~\dotfill[/tex]

[tex]\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{-26}{h}~~,~~\underset{120}{k})}\qquad \stackrel{radius}{\underset{\sqrt{15076}}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - (-26) ~~ )^2 ~~ + ~~ ( ~~ y-120 ~~ )^2~~ = ~~(\sqrt{15076})^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (x+26)^2+(y-120)^2 = 15076~\hfill[/tex]

Given: m space measured angle space C space equals space 76, a = 20, and b = 13. What is the length of c to the nearest tenth?

Answers

Based on the given parameters, the length of c is 8.0 units

How to determine the side length of c?

The given parameters are

Angle c = 76 degrees

Side a = 20

Side b = 13

The length of c is then calculated using the following law of sines

c^2 = a^2 + b^2 - 2absin(C)

Substitute the known values in the above equation

So, we have

c^2 = 20^2 + 13^2 - 2 * 20 * 13 * sin(76)

Express 20^2 as 400

c^2 = 400 + 13^2 - 2 * 20 * 13 * sin(76)

Express 13^2 as 169

c^2 = 400 + 169 - 2 * 20 * 13 * sin(76)

Evaluate the product and sin(76)

c^2 = 400 + 169 - 520 * 0.9703

Evaluate the product

c^2 = 400 + 169 - 504.55

Evaluate the exponents

c^2 = 400 + 169 - 504.55

So, we have

c^2 = 64.45

Evaluate the square root

c = 8.0

Hence, the length of c is 8.0 units

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Which pair of words describe this system of equations
3y=9x-6
2y-6x=4

Answers

The pair of words that describe the given system of equations is: consistent and dependent.

A mathematical statement that has a "equal to" symbol between two expressions with equal values is called an equation.

It demonstrates the equality of the relationship between the expressions written on the left and the right.

Given equations:

3y=9x-6

2y-6x=4

The first equation can be simplified and written as: y=3x-2

Similarly, the second equation can be written as: y-3x=2

It can be seen that the two equations are the same. Thus, the given system of equations is consistent and dependent.

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Evaluate the function f(x) = –2x2 – 3x + 5 for the input value –3.

−22
–4
2
32

Answers

Hi there,

please see below for solution steps :

‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗

Evaluate by substituting :

[tex]\begin{gathered} \boldsymbol{f(x)=-2x^2-3x+5; \ evaluate \ when \ x=-3} \\\boldsymbol{Write \ -3 \ everywhere \ you \ see \ and \ x :}\\\boldsymbol{f(-3)=-2(-3)^2-3(-3)+5}\\\boldsymbol{Evaluate \ using \ Order \ of \ Operations :}\\\boldsymbol{f(-3)=-2(9)+9+5= > -18+9+5= > -18+14= > -4}\end{gathered}[/tex]

Therefore, the answer is [tex]\LARGE\textbf{-4}[/tex].

I hope the answer - and steps - made sense to you !!

Happy Learning !!

‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗

Simplify the expression cos (tan-1(x/2)).

Answers

\cos (\tan \left( -1\right) (\frac{x}{2}))

c

o

s

(

t

a

n

(

1

)

(

2

)

)

Simplify

1

Combine multiplied terms into a single fraction

\cos (\tan \left( -1\right) \cdot \frac{x}{2})

c

o

s

(

t

a

n

(

1

)

2

)

\cos (\frac{\tan \left( -1\right) x}{2})

c

o

s

(

t

a

n

(

1

)

2

)

Solution

\cos \left( \frac{\tan \left( -1\right) x}{2}\right)

c

o

s

(

t

a

n

(

1

)

2

)

Answer:

Step-by-step explanation:

[tex]cos(tan^{-1}(\frac{x}{2} ))\\put~tan^{-1}(\frac{x}{2} )=t\\\frac{x}{2} =tan~t\\sec^2t-tan^2t=1\\sec^2t=1+tan^2t=1+(\frac{x}{2} )^2=\frac{x^2+4}{4} \\sec~t=\pm\frac{\sqrt{x^2+4}}{2} \\cos ~t=\pm\frac{2}{\sqrt{x^2+4}} \\hence~cos(tan^{-1}(\frac{x}{2} ))=cos~t=\pm\frac{2}{\sqrt{x^2+4}}[/tex]

A poster is 15 inches wide by 24 inches tall. A smaller version of the same poster is created using a scale factor of 2/3. What is the area of the smaller poster

Answers

The area of the small poster is 160 inches square

How to determine the area

From the information given, we have the poster to take the form of a rectangle

The formula for area of a rectangle is;

Area = length × width

For the smaller poster created using a scale of factor 2/3

Length = 2/ 3 × 24

Length = 16 inches

Width = 2/ 3 × 15

Width = 10 inches

Substitute into the formula

Area = 16 × 10

Area = 160 inches square

Thus, the area of the small poster is 160 inches square

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The perimeter of a rectangular field is 282 yards. If the width of the field is 52 yards, what is its length? ​

Answers

Answer:  89 yards

Step-by-step explanation: The perimeter is all the sides added up together. Since the width of the field is 52, the two sides are 52 yards which in total is 104 yards. 282- 104 = 178 yards. The length is 178/2 yards which is 89 yards.

Answer:

75

Step-by-step explanation:

math

If P(A)=12, P(A B)=16, and P(A B)=23, what is P(B)?
1/4
2/3
1/2
1/3

Answers

Answer:

P(B) 7

Step-by-step explanation:

The answer is P (B)

What is the sum of ∞Σn=1 2(1/5)^n-1? s=1/5 s=2/5 s=5/3 s=5/2

Answers

The sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2

How to determine the sum of the notation?

The sum notation is given as:

∞Σn=1 2(1/5)^n-1

The above notation is a geometric sequence with the following parameters

Initial value, a = 2Common ratio, r = 1/5

The sum is then calculated as

S = a/(1 - r)

The equation becomes

S = 2/(1 - 1/5)

Evaluate the difference

S = 2/(4/5)

Express the equation as products

S = 2 * 5/4

Solve the expression

S= 5/2

Hence, the sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2

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Answer:

S = 5/2

Thank me later

How do I graph the following set {x is an even number, -1≤x<12}

Answers

Step-by-step explanation:

Use this sort of layout, but where x will be an odd number, do not shade it. there should be a pattern of shaded segments followed by unshaded segments repeating

NO LINKS!! Please help me with this problem​

Answers

Information : The given hyperbola is a horizontal hylerbola with its centre (3 , -5) and one of its focus at (9 , -5) and vertex at (7 , -5) and as we can see that the focus and vertex have same y - coordinates, it must have its Transverse axis on line y = - 5.

Now,

it's vertex is given, I.e (7 , -5)

so, length of semi transverse axis will be equal to distance of vertex from centre, i.e

a = 7 - 3 = 4 units

Now, it's focus can be represented as ;

[tex]\qquad \sf  \dashrightarrow \: (3 + ae, - 5 )[/tex]

so,

ae + 3 = 9

and we know, a = 4

[tex]\qquad \sf  \dashrightarrow \: 4e + 3 = 9[/tex]

[tex]\qquad \sf  \dashrightarrow \: 4e = 6[/tex]

[tex]\qquad \sf  \dashrightarrow \: e = \cfrac{3}{2} [/tex]

Now, let's find the measure of semi - conjugate axis (b)

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = {a}^{2} ( {e}^{2} - 1)[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 16( \frac{9}{4} - 1)[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 16( \frac{9 - 4}{4} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 16( \frac{5}{4} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 20[/tex]

[tex]\qquad \sf  \dashrightarrow \: b = \sqrt{20} [/tex]

So, it's time to write the equation of hyperbola, as we already have the values of a and b ~

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {(x - h)}^{2} }{ {a}^{2} } - \cfrac{( {y - k)}^{2} }{ {b}^{2} } = 1[/tex]

[ plug in the values, and h = x - coordinate of centre, and k = y - coordinate of centre ]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ ({x-3)}^{2} }{ {16}^{} } - \dfrac{ {(y+5)}^{2} }{ { {20} }^{} } = 1[/tex]

Hello and Good Morning/Afternoon:

Let's solve this problem step-by-step:

Let's find the format of the standard form of hyperbole:

 [tex]\hookrightarrow \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2} =1[/tex]

(h,k): hyperbole center ⇒(3,-5)

Let's find the value of a, b:

value of a: distance between vertex (7, -5) and center (3, -5)

             [tex]a = \sqrt{(7-3)^2+(-5--5)^2} =\sqrt{16} =4[/tex]

value of b: [tex]\sqrt{c^2-a^2}[/tex]

           ⇒value of c: distance between focus (9, -5) and center (3, -5)

                  [tex]c = \sqrt{(3-9)^2+(-5--5)^2}=\sqrt{36} =6[/tex]

            ⇒ therefore:

                  [tex]b = \sqrt{c^2-a^2} =\sqrt{6^2-4^2}=\sqrt{20}[/tex]

Let's plug everything into our standard form of the equation:

   [tex]\frac{(x-3)^2}{4^2} -\frac{(y--5)^2}{(\sqrt{20})^2 } =1\\\frac{(x-3)^2}{16} -\frac{(y+5)^2}{20 } =1[/tex] <== Answer

Hope that helps!

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The volume of a rectangular prism is given by the following function:
V(x) = 2x³ + x² - 16 - 15
The length of the rectangular prism is (x − 3) and the width is (2x + 5). What is the height?

Answers

[tex]v(x) = wlh \\ 2x {}^{3} + {x}^{2} - 16 x- 15 =(2x + 5)(x - 3)h \\ h = \frac{2x {}^{3} + x {}^{2} - 16x - 15 }{2x {}^{2} - x - 15 } \\ using \: long \: divison \\ h = x + 1[/tex]

find the slope of the line that passes through each pair of points a. (-4, 5), (1, 1)

Answers

The slope would be -4/5

1+1-1(2)+1=?
A,0
B,1
C,2
D,3​

Answers

Answer:

B. 1

Step-by-step explanation:

-1*2 = -2

-2+1 = -1

-1+1 = 0

0+1 = 1

About 5% of the population has a particular genetic mutation. 300 people are randomly selected.

Find the standard deviation for the number of people with the genetic mutation in such groups of 300. Round your answer to two decimal places.

Answers

The standard deviation for the number of people with the genetic mutation is 3.77

How to determine the standard deviation?

The given parameters are:

Sample size, n = 300

Proportion that has the particular genetic mutation, p = 5%

The standard deviation for the number of people with the genetic mutation is calculated as:

Standard deviation = √np(1 - p)

Substitute the known values in the above equation

Standard deviation = √300 * 5% * (1 - 5%)

Evaluate the product

Standard deviation = √14.25

Evaluate the exponent

Standard deviation = 3.77

Hence, the standard deviation for the number of people with the genetic mutation is 3.77

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The sum of three numbers is 100. The second number is 2 times the third. The third number is 8 less than the first. What are the numbers?

Answers

Answer:

Step-by-step explanation:x+y+z=100(let x ,y,z represent the first second and third numbers respectively)

Therefore,y=2z

z=x-8

y=2x-16

substituting the values of x,y and z into the question,we have

x+(2x-16)+(x-8)=100

Simplifying,we have

4x-24=100

adding 24 to both sides of the equation,

4x=100+24

4x=124

dividing both sides of the equation by the co-efficient of x,we have

4x/4=124/4

4.31=124

therefore,x=31.

three varieties of coffee -coffee A coffee B and coffee C are combined and roasted yield a 54 lb batch of coffee beans. twice as many pounds of coffee C which is retails for $10.39 per pound are needed as coffee a which sells for $15.21 per pound coffee b retails for $13.21 per pound. how many pounds of each coffee should be used in a blend that sells for $12.61 per pound?

Answers

8.9 pounds of coffee A, 27.3 pounds of coffee B and 17.8 pounds of coffee C are need to make a blend that sells for $12.61 per pound.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent coffee A, y represent coffee B and z represent coffee C, hence:

x + y + z = 54   (1)

Also:

2x = z        (2)

And:

15.21x + 13.21y + 10.39z = 12.61(54)   (3)

x = 8.9, y = 27.3 and z = 17.8

8.9 pounds of coffee A, 27.3 pounds of coffee B and 17.8 pounds of coffee C are need to make a blend that sells for $12.61 per pound.]

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Find the distance between each pair of points. Round your answer to the nearest tenth if necessary

(IMAGE)

Answers

Answer is 5.4 units

Step by step.
I used Pythagorean theorem to find the diagonal (hypotenuse) of the triangle.
We know the height (y) is 5 and the other leg (x) is 2.

a^2 + b^2 = c^2 is the formula.
Substitute the two legs in for a and b.

5^2 + 2^2 = c^2
29 = c^2

Now take the square root of both sides
5.385 = c

Round to nearest tenth = 5.4 units

Si al invertir $60.000 se pierde un 8% ¿A cuánto asciende la pérdida?

Answers

Trabajando con porcentajes, concluimos que la pérdida es de $4800.

¿A cuánto asciende la pérdida?

Sabemos que la inversión inicial es de $60000, y de esta cantidad, se pierde un 8%.

Entonces la pérdida va a ser el 8% de $60000.

Podemos escribir las relaciones:

$60000 = 100%

x = 8%

Queremos resolver esto para x, tomando el cociente entre esas relaciones y resolviendo para x obtenemos:

x = $60000*(8%/100%) = $60000*0.08 = $4800

Así, concluimos que la pérdida es de $4800.

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In a football tournament, each team played exactly 19 games. Teams get three points for everyone and one point for every time. At the end of the tournament, team Olympus got a total of 28 points. How many could team Olympus have tied?

Answers

We can actually deduce here that when the tournament ended, team Olympus have tied for 13, 10, 7, 4, 1 times.

What is inequality?

In Mathematics, inequality is used to express or show quantities that are less than, greater than, greater than or equal to,  less than or equal to.

The following can be seen in inequality expressions:

≤≥ ><≠

Looking at the question, we can see that each team plays exactly 19 games.

Every win (w) = 3

Every tie (t)= 1

Every loose = 0

But Olympus got a total of 28 points

Thus: 3w + t = 28 ---------(1)

Note that each team plays  19 games

Thus, T + W  ≤  19 --------------(2)

and T , W ≥ 0

Looking at equation (1) and (2)

=> 2W  ≥  9

=> W ≥ 4.5  

( match can be won in integers only )

=> W  ≥  5  

W - 5, 6, 7, 8, 9    

T - 13, 10, 7, 4, 1  

Loose - 1, 3, 5, 7, 9

Thus, team Olympus have tied for 13, 10, 7, 4, 1 times.

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QUESTION IS DOW BELOW 5 POINTS EACH PLEASE HELP PLEASE HELP PLEASE HELP
WILL GIVE BRAINLIEST FOR ACCURATE ANWSER

Answers

The length of segment XY is 52 units and the length of segment HD is 26 units

How to determine the lengths?

Secant lines (a)

To do this, we make use of the following intersecting secant theorem

VZ * VW = VY * VX

Substitute the known values in the above equation

12 * 40 = VY * 8

Divide by 8

12 * 5 = VY

Evaluate the product

VY = 60

The length VX is

XY = VY - VX

Substitute the known values in the above equation

XY = 60 - 8

Evaluate

XY = 52

Hence, the length of segment XY is 52 units

Secant lines (b)

To do this, we make use of the following intersecting secant theorem

GH^2 = HC * HD

Substitute the known values in the above equation

13^2 = 6.5 * HD

Divide by 6.5

13^2/6.5 = HD

Evaluate the quotient

26 = HD

The length HD is

HD = 26

Hence, the length of segment HD is 26 units

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Let r(x)=x^2 - x + 14. Find all values of a such that r(a) = 20.

Answers

Answer:

a=–2, 3

Step-by-step explanation:

r(a)=20

a²–a+14=20===> a²–a–6=0===> (a–3)(a+2)

Other Questions
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