is it possible to see the answer without paying?

Answer:

10b/y^2

Step-by-step explanation:

Hope this helps! :)

Answer:

5%.

Step-by-step explanation:

That is

(24/480 * 100    

 Now 480 / 24 = 20 so we have

(1/20) * 100

= 100/20

= 5%.

Answer:

24 is 5% of 480

Step-by-step explanation:

24 / 480 = 0.05

Percent is "for each 100"

Then:

0.05 * 100 = 5%

Answer:

the perpendicular bisector

Explanation:

The perpendicular bisector will intersect the segment at its midpoint.

Step-by-step explanation:

Notice that the main vertices (-15,4) and (5,4) both have the same y coordinate. This means that the focal axis is horizontal so we have a horizontal ellispe.

Equation of a horizontal ellipse is

[tex] \frac{(x - h) {}^{2} }{ {a}^{2} } + \frac{(y - k) {}^{2} }{ {b}^{2} } = 1[/tex]

I'll explain the variables.

Step 1: Find the center.

The center (h,k) is the midpoint of either the main or co vertices. It doesn't matter because of the definition of an ellipse.

So using the midpoint formula, let find the midpoint of the main vertices.

[tex]( \frac{ - 15 + 5}{2} ) = - 5[/tex]

[tex] \frac{4 + 4}{2} = 4[/tex]

So our center is (-5,4) so as of right now we have

[tex] \frac{(x + 5) {}^{2} }{ {a}^{2} } + \frac{(y - 4) {}^{2} }{ {b}^{2} } = 1[/tex]

Step 2: The variable a represents the semi major axis. This

basically means what is the distance from the center to either main vertex.

Here, let use (5,4). Using (5,4), our main vertex and (-5,4), our center.

Use the distance formula

[tex]a= \sqrt{(5 - ( - 5) {}^{2} + (4 - 4) {}^{2} } [/tex]

[tex]a = \sqrt{100} [/tex]

[tex]a= 10[/tex]

So our distance is 10, this means a=10

Step 3: The variable b represent the semi minor axis. This basically the distance from the center to either co vertex.

Using the distance formula,

[tex]b = \sqrt{ (- 5 - ( - 5) {}^{2} + (4 - 11) {}^{2} } [/tex]

[tex]b = \sqrt{49} [/tex]

[tex]b = 7[/tex]

So b=7, so finally we plug a=10, b=7

[tex] \frac{(x + 5) {}^{2} }{100} + \frac{(y - 4) {}^{2} }{49} = 1[/tex]

The number of $1, $5 and $10 are 49, 44 and 22 respectively.

There are 3 denominations of bills in a wallet: $1, $5, and $10.

There are 5 fewer $5-bills than $1-bills.

let

x = number of $1 bills

Hence,

number of $5 bills = x - 5

There are half as many $10-bills as $5-bills.

number of $10 bills = 1 / 2 (x - 5)

Therefore,

x + x - 5 + 1 / 2 (x - 5) = 115

2x - 5  + 1 / 2 x - 5 / 2 = 115

2x + 1 / 2 x - 5 - 5 / 2 = 115

5 / 2 x  - 7.5 = 115

2.5x  = 115 + 7.5

x = 122.5 / 2.5

x = 49

Number of $1 bills = 49

Number of $5 bills = 49 - 5 = 44

Number of $10 bills = 1 / 2 (49 - 5) = 22

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The expected value for the drilling company, using a discrete distribution, is of -$9,125, that is, a loss of $9,125.

The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.

Considering the cost that it takes to sink a test well, and the probabilities of each outcome, the discrete distribution is given by:

Hence the expected value is given as follows:

E(X) = 300000 x 0.025 + 130000 x 0 .05 - 25000 x 0.925 = -$9,125.

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Answer:

42km/h

Step-by-step explanation:

70km=100 minutes

7km= 10min

42km=60min

42km/h

Answer:

Step-by-step explanation:

....

Using Hinton's method;

A four-dimensional shape (4D) is a mathematical extension of a three-dimensional or 3D space.

Three-dimensional space is the simplest possible abstraction of the observation that one only needs three numbers, called dimensions, to describe the sizes or locations of objects.

Using Hinton's method;

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For the given coordinates of A, B, C, and D as (-8, 1), (-2, 4), (-3,-1), and (-6, 5), respectively, OD, AB and CD are intersecting lines but are not perpendicular (third option) is the correct assertion.

Reasons for the Choice

Therefore, the lines OD, AB, and CD are intersecting lines but are not perpendicular.

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Quadrilaterals are plane shapes that are bounded by four straight sides. Thus, the required answers to the questions are:

46. True. Other examples include kites, rhombus, etc.

47. False.

46. When a plane shape is bounded by four straight sides of equal or different lengths, it is called a  quadrilateral. Examples include trapezium, kite, rhombus, rectangle, square, etc. Each of these examples has individual properties.

Thus the required answer to question 46 is; True. It can be observed that with respect to their individual properties, other quadrilaterals which have a pair of opposite angles to be equal include: kite, rectangle, rhombus, etc.

47. A ray segment is a given line that points or heads in a specific direction. So that the direction in which the ray moves is very important.

Thus in the given question, the required answer is; False. This is because the two given rays are moving in opposite directions. Though the two rays may have the same length of the segment.

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The piecewise defined function is

f(t) = 800 * 1.5^t for 0 - 2

f(t) = 2700 * 1.05^t-3 for 3 to 9

On the domain of t = 0 to 2, we have:

f(0) = 800

f(1) = 1200

f(2) = 1800

The above function is a piecewise function with the following definition

f(0) = 800 --- initial value

r = 1200/800 = 1.5 --- rate

The function is then represented as:

f(t) = f(0) * r^t

This gives

f(t) = 800 * 1.5^t

On the domain of t = 3 to 9, we have:

f(3) = 2700

f(4) = 2835

The above function is a piecewise function with the following definition

f(3) = 800 --- initial value

r = 2835/2700 = 1.05 --- rate

The function is then represented as:

f(t) = f(3) * r^t-3

This gives

f(t) = 2700 * 1.05^t-3

Hence, the piecewise defined function is

f(t) = 800 * 1.5^t for 0 - 2

f(t) = 2700 * 1.05^t-3 for 3 to 9

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Answer:

9:50 am

Step-by-step explanation:

because 10 x 60 is equal to 1 hour, so you get 600 seconds subtracted from 10am. 600 seconds is equal to 10 minutes. so 10 am - 10 minutes = 9:50am

The system of inequalities having the given feasible regions and points at (-5, 0), and (0, 5), and (-2, -9), (-5, 0), and (1, 0) is the option;

y > x² + 4•x - 5

y > x + 5

The coordinates of the given points on the linear inequality are;

(-5, 0), and (0, 5)

Slope, m, of the linear inequality is therefore;

m = (5 - 0)/(0 - (-5)) = 1

The equation of the inequality is therefore;

y - 0 > 1•(x - (-5)) = x + 5

Which gives;

Quadratic Inequality;

The coordinates of the points on the quadratic inequality are;

Vertex point = (-2, -9)

x-intercept = (-5, 0), and (1, 0)

Therefore, we have;

y > (x + 5)•(x - 1) = x² + 4•x - 5

The correct option is therefore;

y > x² + 4•x - 5

y > x + 5

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Answer:

y > x2 + 4x – 5

y > x + 5

Step-by-step explanation:

If you put this system into desmos you will see that it matches the photo shown in the question, and it would need to be both greater than symbols because the dotted lines indicate that it is not included in the solution.

According to the graph, the ships’ paths do not meet at any point.

Linear equations are equations that have constant average rates of change, slope or gradient

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

2x = 5y - 40

-4x + 10y = 20

Make y the subject in the second equation, by adding 4x to both sides of the equation

4x -4x + 10y = 20 + 4x

This gives

10y = 20 + 4x

Divide both sides by 10

y = 2 + 0.4x

Substitute y = 2 + 0.4x in 2x = 5y - 40

2x = 5(2 + 0.4x) - 40

Expand

2x = 10 + 2x - 40

Subtract 2x from both sides of the equation.

2x - 2x = 10 + 2x - 2x - 40

Evaluate the like terms

0 = 10 - 40

Evaluate the like terms

0 = -30

The above equation is not true.

This means that the ships’ paths do not meet at any point.

This can be confirmed using the attached graph.

From the graph, we can see that the lines of 2x = 5y - 40 and -4x + 10y = 20 do not intersect

Hence, we can conclude that the ships’ paths do not meet at any point.

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Answer:i am not sure

Step-by-step explanation:

This question is very hard to answer

Answer: I think your brain needs cheese but..............................................

Step-by-step explanation:

Don't know

The addition of the polynomials x⁴ - 3x + 1, 4x² - 2x + 8, x³ - 9 in descending powers of x is x⁴ + x³ + 4x² - 5x.

Adding the polynomial

(x⁴ - 3x + 1) + (4x² - 2x + 8) + (x³ - 9)

= x⁴ - 3x + 1 + 4x² - 2x + 8 + x³ - 9

= x⁴ + x³ + 4x² - 3x - 2x + 1 + 8 - 9

= x⁴ + x³ + 4x² - 5x

Therefore, the addition of the polynomials x⁴ - 3x + 1, 4x² - 2x + 8, x³ - 9 in descending powers of x is x⁴ + x³ + 4x² - 5x.

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y=x²+(3+1)x-3

y=x²+3x+1x-3

y=x(x+3)-1(x+3)

y=(x-1)(x+3)

a) The slope of the secant lines are: q = 5, f(q) = 2,076: m = - 131.1, q = 10, f(q) = 1,299: m = - 106.8, q = 20, f(q) = 357: m = - 81.6, q = 25, f(q) = 84: m = - 68.1, q = 30, f(q) = 0: m = - 51.

b) The estimated slope of the line tangent to the curve at the point (x, y) = (15, 765) is - 94.2 gallons per minute.

In this problem we must determine the slope of several lines based on the information given by the table and using the secant line formula:

m = [f(q) - f(p)] / (q - p)     (1)

If we know that a = 15 and p = 765, then the slope of the secant lines are:

q = 5, f(q) = 2,076

m = [2,076 - 765] / (5 - 15)

m = - 131.1

q = 10, f(q) = 1,299

m = [1,299 - 765] / (10 - 15)

m = - 106.8

q = 20, f(q) = 357

m = [357 - 765] / (20 - 15)

m = - 81.6

q = 25, f(q) = 84

m = [84 - 765] / (25 - 15)

m = - 68.1

q = 30, f(q) = 0

m = [0 - 765] / (30 - 15)

m = - 51

The slope of the line tangent to the curve at the point (x, y) = (15, 765) can be estimated by averaging the slopes of the closest secant lines:

m' = [(- 106.8) + (- 81.6)] / 2

m' = - 94.2

The estimated slope of the line tangent to the curve at the point (x, y) = (15, 765) is - 94.2 gallons per minute.

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The derivative of y= sin x sin 3x​ is [tex]$=3 \cos x-3 \cos 3 x$[/tex]

To find the derivative of y= sin x sin 3x​:

[tex]$y=3 \sin (x)-\sin (3 x)$[/tex]

[tex]$y^{\prime}=3 \cos x-[\cos (3 x) \cdot 3]$[/tex]

[tex]$y^{\prime}=3(\cos x-\cos 3 x)$[/tex]

[tex]\frac{dx}{dy} =3 cosx - 3 cos x[/tex]

Differentiate [tex]sin 3x[/tex] using the chain rule

Given [tex]y=f^{'} (g(x))*g^{'}[/tex]←chain rule

y=[tex]y=3 sin x-sin 3x[/tex]

[tex]\frac{dx}{dy} =3 cos x - cos 3x*\frac{d}{dx} (3x)[/tex]

[tex]=3cosx-3cos3x[/tex]

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Answer:

Each Cat video gets 750 comments

Each dog video gets 450 comments

Hope this helps you!

Answer:

He gets 750 comments on the cat videos and 450 on the dog videos the answer to the second question is yes

Step-by-step explanation:

khan :)

Answer:

(f º g) = [tex]-x^4+1[/tex]

Step-by-step explanation:

So it's important to note that the notation: "(f º g)" isn't f(x) * g(x), it's a composite function, where you essentially have two functions, with one of the functions being the argument of one of the functions.

This means we can plug in the function g(x) as x into the function f. So let's do that

Original Function:

f(x) = -1x + 1

Plug in x^4 (this is the value of g(x)) as x into the function

f(g(x)) = [tex]-(x^4)+1[/tex]

Distribute the negative sign

f(g(x)) = [tex]-x^4+1[/tex]

The amount that was invested are at 3% = 400000, at 4% = 500000 and at 2% = 100000

We have x + y + z = 1000000

((1+0.03)x - x)+ ((1+0.04)y - y) + ((1 + 0.02)z-z) = 34000

4z + x + z = 1000000

((1+0.03)4z - 4z)+ ((1+0.04)y - y) + ((1 + 0.02)z-z) = 34000

((1+0.03)4z - 1)+ ((1+0.04)y - 1) + ((1 + 0.02)z-1) = 34000

12/100z + 4/100y +2/100z = 34000

2y + 7z = 1700000

-2y - 10z = -2000000

2y + 7z = 1700000

Solve through the use of the simultaneous linear equation

z = 100000

y = 500000

x = 400000

The amount that was invested are at 3% = 400000, at 4% = 500000 and at 2% = 100000

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The forecasted capital expenditure related to the information below exists at 4,900.

Therefore, the correct answer is option b) 4,900.

Capital exists directed as the lifeblood of any business. It exists the group of assets of the business that contains their financial value to create the production of goods and services.

For calculating the forecasted capital-

Net PP&E beginning of period = 15,000

Net PP&E end of period = 17,500

Depreciation expenses = 2,400

Forecasted capital expenditure = Net PP&E end of period + Depreciation expenses - Net PP&E beginning of the period

= 17500 + 2400 - 15,000

Forecasted capital expenditure = 4,900

Therefore, the correct answer is option b) 4,900.

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The complete question is:

What’s the forecasted capital expenditure based on the information below?

Net PP&E beginning of period: 15,000

Net PP&E end of period: 17,500

Depreciation expenses: 2,400

Review Later

a) 2,500

b) 4,900

c) 100

d) -100

Answer:

1 (3.66)

2(3.5)

3(5.25)

The function in terms of the time (t) is t=d/r and the value of the time (t) for the given values is 5.

An equation can be represented by a linear function. The standard form for the linear equation is: ax+b , for example, y=2x+7. Where:

a= the slope

b=constant term that represents the y-intercept.

For the given example: a=2 and b=7.

In the exercise is asked the equation for the time (t) in the function of the distance (d) and the rate (r).

Thus, if d=rt, we will have t= d/r

Replacing the variables for the given values for finding t. The question gives:

distance (d) =40

rate (r) = 8

Thus, you will have t= 40/8. Then, t=5

Therefore, the answer is the fourth option.

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Answer:

C (third figure from left)

Step-by-step explanation:

The spirals in the first, second, and fourth figures are all clockwise from the outer end, i.e., if you trace these three spirals with your finger from the outside to the inside, your finger will move clockwise.

However, if you did the same with the third figure, you would see that the spiral is anti-clockwise from the outside moving in.

Therefore, the third figure doesn't belong.

Answer:

So this is all you need to do!

Hope it helped you:)

The y-intercept of the graph of y = x2 is shifted up 3 units.

The standard exponential equation is expressed as y = ab^x. Exponential equation is inverse of logarithmic equation.

Translations is a transformation technique that changes the position of an object from one point on the plane to another.

Given the parent function f(x) = x^2

If the function is shifted 3 units up, the function g(x) is derived by adding 3 to the function f(x). The resulting function is given as;

g(x) = f(x) + 3

g(x) = x^2 + 3

Hence the equation of the new graph g(x) is expressed as g(x) = x^2 + 3

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Answer:

Step-by-step explanation:

1.733707699

could you brainlyest me?