In the figure, what is the ratio of the area of square KLMN to the area of LOK?

The area of the trapezoid in the given image is: 49 cm².

A trapezoid can be described as a quadrilateral that has four sides, whereby one pair of opposite sides are parallel to each other.

The area of a trapezoid is calculated using the formula, Area = 1/2 × (a + b) × h, where:

a and b represents lengths of the parallel sides of the trapezoid

h = height of the trapezoid.

Given the parameters for the trapezoid as:

a = 6 cm

b = 8 cm

h = 7 cm

Plug in the values into Area = 1/2 × (a + b) × h:

Area of trapezoid = 1/2 × (6 + 8) × 7

Area of trapezoid = 1/2 × (14) × 7

Area of trapezoid = 7 × 7

Area of trapezoid = 49 cm²

Thus, the area of the trapezoid in the given image is: 49 cm².

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Answer:

Step-by-step explanation:

3. A line of best fit can be roughly determined using an eyeball method by drawing a straight line on a scatter plot so that the number of points above the line and below the line is about equal (and the line passes through as many points as possible). This will help me to see weather or not it is positive or negative.3

The slope of the line is 1/3and the y-intercept is at the (0, 2) as shown in the graph below.

A linear function is a function that has a leading degree of 1. The standard equation for a linear function is expressed as:

y = mx + b

where

m is the slope which is equal to the rate of change of y coordinate to x-coordinates.

b is the y-intercept

Given the following equation

y= 1/3x + 2

The slope of the line is 1/3 and the y-intercept is at the(0,2) as shown in the graph below.

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Answer:

See picture.

C is the point that does not move because it is on the line of reflection
Yes, a reflection is a rigid motion.  It does not change size.  A dilation changes the size.

Step-by-step explanation:

In the picture, you will see that I traced the triangle on tracing paper and then folded (flipped) the drawing over the line of reflection.

Rounded to the nearest square units, the surface area of the cone, is: 524 square units.

The surface area of a cone = πr(r + l), where:

r is the radius of the cone

l is the length of the cone.

Given the following:

Radius of the cone (r) = 12/2 = 6 units

Slant height of the cone (l) = √(21² + 6²) [Pythagorean theorem]

Slant height of the cone (l) = 21.8 units.

Plug in the values into πr(r + l):

Surface area of the cone = π × 6(6 + 21.8)

Surface area of the cone = 3.14 × 6(27.8)

Surface area of the cone ≈ 525 square units

The surface area of the cone, approximated to the nearest square units, we have: 524 square units.

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The first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608

For given question,

We have been given the recursive formula of a sequence.

[tex]a_{k+1}=\frac{1}{3}{a_k}^2[/tex]

Also, the first term of the sequence is,

a1 = 6

Substitute k = 1 in given recursive formula.

⇒ [tex]a_{1+1}=\frac{1}{3}{a_1}^2[/tex]

⇒ a2 = 1/3 (6)²

⇒ a2 = (1/3) × 36

⇒ a2 = 12

Substitute k = 2 in given recursive formula.

⇒ [tex]a_{2+1}=\frac{1}{3}{a_2}^2[/tex]

⇒ a3 = (1/3) × (12)²

⇒ a3 = (1/3) × 144

⇒ a3 = 48

Substitute k = 3 in given recursive formula.

⇒ [tex]a_{3+1}=\frac{1}{3}{a_3}^2[/tex]

⇒ a4 = (1/3) × (48)²

⇒ a4 = (1/3) × 2304

⇒ a4 = 768

Substitute k = 4 in given recursive formula.

⇒ [tex]a_{4+1}=\frac{1}{3}{a_4}^2[/tex]

⇒ a5 = (1/3) × (768)²

⇒ a5 = (1/3) × 589824

⇒ a5 = 196608

Therefore, the first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608

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The total volume of silo is  = 116.5[tex]{~m}^{3}[/tex]

The correct option is C

Any arrangement of points, lines, or planes constitutes a geometric figure. Depending on their dimensions, geometric figures can be categorized as either a space figure, a plane figure, a line, a line segment, a ray, or a point.

Any object's surface area is the space that the object's surface takes up on a specific area or region. Volume, however, refers to how much room a thing has.

Given data:

Radius =4.4/2

                   =2.2

height of cylinder = 6.2

to find :

total volume of silo =  volume of cylinder + volume of hemisphere

                                  [tex]\begin{aligned}&=\pi r^{2} h+\frac{2}{3} \pi r^{3} \\&=\pi r^{2}\left(h+\frac{2}{3} r\right) \\&=\frac{22}{7} \times(2.2)^{2}\left[6.2+\frac{2 \times 2.2}{3}\right]\end{aligned}[/tex]

                                   = 116.5[tex]m^2[/tex]

The total volume of silo is = 116.5[tex]m^2[/tex]

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I understand that the question you are looking for is:

A grain silo is composed of a cylinder and a What is the approximate total volume of the silo? Use hemisphere. The diameter is 4.4 meters. The height of  3.41 for [tex]\pi[/tex] and round the answer to the nearest tenth of its cylindrical portion is  6.2 meters. a cubic meter.

a. 37.1[tex]m^2[/tex]

b. 71.9 [tex]m^2[/tex]

c.116.5 [tex]m^2[/tex]

d. 130.8[tex]m^2[/tex]

3435 were children visited the India gate.

What is a linear equation in math?

Given,

             men = 1265

            women = 1150

Total women and men -

        men + women = 2415

         = 5450-2415  ⇒ 3435

Therefore,  3435 were children visited the India gate.

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The sum of each of the 4 polynomials and their answers are respectively;

12x² + 3x + 6 + (-7x²) – 4x – 2  = 5x² - x + 4

(2x² - x) + (-x – 2x² – 2) = -2x - 2

(x³ + x² + 2) + (x² – 2 - x³) = 2x²

(x² + x) + (x² + 8x - 2) = 2x²+ 9x - 2

1) We want to find the sum of the polynomials (12x² + 3x + 6) and (-7x² – 4x – 2). Thus, we have;

12x² + 3x + 6 + (-7x²) – 4x – 2

= 5x² - x + 4

2)  We want to find the sum of the polynomials (2x² - x) and (-x – 2x² – 2). Thus, we have;

(2x² - x) + (-x – 2x² – 2)

= -2x - 2

3) We want to find the sum of the polynomials (x³ + x² + 2) and (x² – 2 - x³). Thus, we have;

(x³ + x² + 2) + (x² – 2 - x³)

= 2x²

4) We want to find the sum of the polynomials (x² + x) and (x² + 8x - 2). Thus, we have;

(x² + x) + (x² + 8x - 2) = 2x²+ 9x - 2

The sum of each of the 4 polynomials and their answers are respectively;

12x² + 3x + 6 + (-7x²) – 4x – 2  = 5x² - x + 4

(2x² - x) + (-x – 2x² – 2) = -2x - 2

(x³ + x² + 2) + (x² – 2 - x³) = 2x²

(x² + x) + (x² + 8x - 2) = 2x²+ 9x - 2

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Answer:

D 0.0353

Step-by-step explanation:

a= 0.05. p= 0.65. n=700

S N P = 700 × 065 = 45575

1 n ( 1 - p ) = 700× ( 1 - 0.65 ) = 24575

get the sample is big ,. p~ N ( π. √ π ( 1-π ) p - π

-----------. ------- ~ ( o. 1

n Ñ 1 ~ñ

the margin of error ∆ = Z a

-----. =. √ π ( 1 - π )

2 --------

n

according to the standard normal distribution,

Z d

---. = zo.o25 = 1.96

2

∆=1.96×√p ( 1 - p ). =. 1.96 × √ 0.65× ( 1 - 65)

---------. ---------

π. 700

= 0.0353

Step-by-step explanation:

-3(x+8)=-21

open the bracket

-3x-24=-21

-3x=-21+24

-3x=3

x=-3/3

x=-1

Answer:

-1/2

Step-by-step explanation:

The cosine is equal to the x coordinate of the point where the terminal side of the angle intersects the unit circle.

Answer:

382.19cm²

Step-by-step explanation:

a / sin(A) = b / sin(B)

a / sin(68) = 53 / sin(95)

a = (53 x sin(68)) / sin(95)

a = 49.33

area = ½absin(C)

C = 180 - (95 + 68)

C = 180 - 163

C = 17°

area = ½(53)(49.33)sin(17)

area = 382.19cm²

Based on the density and the given parameters, the density of the sheet of glass in kg per m cubed is 2500 kg/m cubed

The density of the sheet of glass  is given as

Density = 2.5g/cm cubed

Start by converting grams (g) to kilogram (kg)

This is done by dividing 2.5 by 1000

So, we have:

Density = 2.5/1000 kg/cm cubed

Evaluate the quotient

Density = 0.0025 kg/cm cubed

Next, we then convert cm cubed (cm^3) to meter cubed (m^3)

This is done by dividing the volume by 1000000

So, we have:

Density = 0.0025 kg/(1/1000000) m cubed

Express as product

Density = 1000000 * 0.0025 kg/m cubed

Evaluate the product

Density = 2500 kg/m cubed

Based on the density and the given parameters, the density of the sheet of glass in kg per m cubed is 2500 kg/m cubed

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Answer:

See below

Step-by-step explanation:

Are you wanting to convert density of   gm/ cm^3   to    kg/m^3 ??

    there are 100 x 100 x 100  cm^3 =  1,000,000  cm^3/ m^3

2.5 gm / cm^3   *  1 000 000 cm^3 / m^3   =  2, 500 000 gm / m^3

   now 1 kg is   1000 gm

2, 500 000 gm / m^3   *  1 kg / 1000 gm  = 2500 kg / m^3

The box and whisker plot for the data-set is given at the end of the question.

It is a plot that focuses the interquartile range of the population, which is the difference between the third and the first quartile, but gives a five number summary of the population, composed by these following measures.

For this problem, we have that:

The graph at the end gives a vertical version of the box plot.

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Answer:

First number = 33, Second number = -19

Step-by-step explanation:

We can use F to represent the first number and S to represent the second number.

Our two equations then are F + S = 14 and 2F + 3S = 9

We can use substitution:

[tex]F+S = 14\\2F+3S=9\\F=14-S\\2(14-S)+3S=9\\28-2S+3S=9\\28+S=9\\S=-19\\\\F-19=14\\F=33[/tex]

B is the answer

i simplified the theorem, but i hope this makes sense!

Answer:

B

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

Let n = the number.

2n - 7 = n + 5

n = 12

Let’s check if we got the right answer by substituting 12 for n into the original equation.

2*12 - 7 = 12 + 5

24 - 7 = 17

17 = 17

Answer:

I am not 100% confident, but I think that she is 11.

Step-by-step explanation:

Answer:

14 years old

Step-by-step explanation:

Define the variable

Let x be the actual age of Zeba (in years).

Create an equation using the give information and the variable x:

[tex](x - 5)^2=5x+11[/tex]

To find Zeba's age now, solve the equation for x.

Expand the brackets:

[tex]\implies x^2-10x+25=5x+11[/tex]

Subtract 5x from both sides:

[tex]\implies x^2-10x+25-5x=5x+11-5x[/tex]

[tex]\implies x^2-15x+25=11[/tex]

Subtract 11 from both sides:

[tex]\implies x^2-15x+25-11=11-11[/tex]

[tex]\implies x^2-15x+14=0[/tex]

Factor the found quadratic

To factor a quadratic in the form [tex]ax^2+bx+c[/tex], find two numbers that multiply to [tex]ac[/tex] and sum to [tex]b[/tex], then rewrite [tex]b[/tex] as the sum of these two numbers:

[tex]\implies x^2-14x-x+14=0[/tex]

Factor the first two terms and the last two terms separately:

[tex]\implies x(x-14)-1(x-14)=0[/tex]

Factor out the common term (x - 14):

[tex]\implies (x-1)(x-14)=0[/tex]

Apply the zero product property:

[tex]\implies (x-1)=0 \implies x=1[/tex]

[tex]\implies (x-14)=0 \implies x=14[/tex]

Therefore, Zeba's age now is either 1 or 14 years.

As the question states "If Zeba were younger by 5 years" then 1 must be an extraneous solution since 1 - 5 = -4 and Zeba cannot be -4 years old.

Therefore, Zeba's age now is 14 years old.

Check

Given the actual age of Zeba is 14 years old.

Therefore, If Zeba were younger by 5 years, she would be 9 years old as:  14 - 5 = 9

The square of 9 is:  9² = 81.

5 times her actual age:  5 × 14 = 70

81 is 11 more than 70, hence verifying that her actual age is 14 years old.

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3x-2y=  7

Slope intercept form y= mx+b

   3x- 2y=  7

-   3x           -3x

-2y/-2=  3x/-2 - 7/2  

y=   3x/-2 -7/2

Answer:

3x/2 and the second 7/-2y

Step-by-step explanation:

thats how is what i got

Answer:

There are 7 two bed bedroom apartments.

Step-by-step explanation:

Solution Given:

let the one bedroom apartment be x and two bedroom apartment be y.

By the question we can make an equation as

x+y=12

or y=12-x............................[1]

Again:

$360x+$450y=$4,950

Now substituting value of y, we get

$360x+$450(12-x)=$4,950

Opening Bracket

$360x+$5400-$450x=$,4,950

solving equation

-90x=-450

dividing both side by -90,we get

x=5

again,

substituting value of x in equation 1,we get

y=12-5=7 two bed bedroom apartments.

Let, x represents the number of one bedrooms and 12 - x represents the number of two bedrooms.

According to the question,

[tex]360x + 450(12 - x) = 4950[/tex]

[tex]360x + 5400 - 450x = 4950[/tex]

[tex]5400 - 4950 = 450x - 360x[/tex]

[tex]450 = 90x[/tex]

[tex] \frac{450}{90} = x[/tex]

[tex]5 = x[/tex]

Therefore, one bedrooms = x = 5

For number of two bedrooms which is equal to 12 - x

= 12 - 5

= 7

So your required answer is 7

The winning probability is 1/3.

To find the winning probability:

Therefore, the winning probability is 1/3.

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Step-by-step explanation:

You got your fraction messed up

It should be -3/2 or -1.5

The Area of the composite figure as shown in the image below is: 105.57 km².

Referring to the diagram given below, the shape can be decomposed into one rectangle, one square, and one quarter circle.

The area of the composite figure = area of rectangle + area of square + area of quarter circle.

Area of the Rectangle = length × width

Length = 12 km

Width = 7 km

Area of the Rectangle = 12 × 7

Area of the Rectangle = 84 km²

Area of the square = (s)²

s = 3 km

Area of the square = 3²

Area of the Rectangle = 9 km²

Area of the quarter circle = 1/4(πr²)

r = 4 km

Area of the quarter circle = 1/4(π × 4²)

Area of the quarter circle = 12.57 km²

Area of the composite figure = 84 + 9 + 12.57

Area of the composite figure = 105.57 km².

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The range of the quadratic function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.

In this case we have a quadratic equation whose domain is stated. The domain of a function is the set of x-values associated to only an element of the range of the function, that is, the set of y-values of the function. We proceed to evaluate the function at each element of the domain and check if the results are in the choices available.

x = - 9

y = (2 / 3) · (- 9)² - 6

y = 48

x = - 6

y = (2 / 3) · (- 6)² - 6

y = 18

x = - 3

y = (2 / 3) · (- 3)² - 6

y = 0

x = 0

y = (2 / 3) · 0² - 6

y = - 6

x = 3

y = (2 / 3) · 3² - 6

y = 0

x = 6

y = (2 / 3) · 6² - 6

y = 18

x = 9

y = (2 / 3) · 9² - 6

y = 48

The range of the quadratic function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.

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Answer:

Domain is 1 and 7 and range is -5and -4

Step-by-step explanation:

because domain is a first group element and range is a second element of a set

The time in seconds that it took the ball to travel would be = 0.25 seconds.

Speed can be defined as the distance covered by an object per unit time.

The speed used to kick the soccer off the ground = 56 feet per second.

The height equation= −16t² + 56t

The time= ?

The formula for speed = distance/time

56= −16t² + 56t/t

56t = −16t² + 56t/t

−16t² = -56t + 56t

−16t² = 0

Make t the subject formula,

t = √1/16

t = 0.25 seconds.

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Step-by-step explanation:

2a -1.28b +2.8 for simplification.