In c 11 you cannot use a range-based for loop to modify the contents of an array unless you declare the range variable as a reference variable. true false

The real statement is that the closer you get to the center of the vortex, the closer the current speed approaches infinity. option C is correct.

Given the speed s of the flow in a given vortex is modeled by x=300/d, where d is the distance to the center of the vortex.

speed is defined as the rate of change of an object's position in any direction. Speed ​​is measured as the ratio of distance traveled to time traveled.

As d approaches 0, you are approaching the center of the vortex.

[tex]\begin{aligned}S&=\lim_{d\rightarrow 0}\frac{300}{d}\\ &=\frac{300}{0}\\ &=\infty\end[/tex]

Thus, if the flow in a given vortex is modeled by x = 300/d, as one approaches the center of the vortex, the speed of the flow tends to infinity.

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Answer: C- As you move closer to the center of the whirlpool, the speed of the current approaches infinity.

The margin of sampling error for a 95% confidence interval is 9.7%

The formula for margin of error here is;

E = z√(p(1 - p)/N)

where;

n is sample size

z is the z score

p is the sample proportion

z-score for a 95% confidence interval from tables is 1.96.

We are given;

p = 43% = 0.43

n = 100

Thus;

E = 1.96√(0.43(1 - 0.43)/100)

E =  0.097 = 9.7%

Thus, we can conclude that  the margin of sampling error for a 95% confidence interval is 9.7%

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a) The coordinates for T and H such that quadrillateral MATH is a rectangle are T(x, y) = (2, - 2) and H(x, y) = (5, - 4).

b) The quadrilateral MATH is a rectangle.

Quadrilaterals are figures with four sides and whose internal angles sums a total of 360 degrees. A quadrilateral is a rectangle when each pair of opposite sides are parallel and have the same length to each others, each of the four angles are right angles and each pair of perpendicular sides.

a) Vectorially speaking, we can construct a rectangle by using the following definitions:

M(x, y) = (a, b), A(x, y) = (c, d), T(x, y) = (a, d), H(x, y) = (c, b)

If we know that a = 2, b = - 4, c = 5, d = - 2, then the points T and H are described below:

T(x, y) = (2, - 2), H(x, y) = (5, - 4)

The coordinates for T and H such that quadrillateral MATH is a rectangle are T(x, y) = (2, - 2) and H(x, y) = (5, - 4).

b) To prove that quadrilateral MATH, we need to prove that:

MT = HA      

(2, - 2) - (2, - 4) = (5, - 2) - (5, - 4)

(0, 2) = (0, 2)

TA = MH

(5, - 2) - (2, - 2) = (5, - 4) - (2, - 4)

(3, 0) = (3, 0)

MT • TA = 0

(0, 2) • (3, 0) = 0 · 3 + 2 · 0 = 0

MH • HA = 0

(3, 0) • (0, 2) = 3 · 0 + 0 · 2 = 0

Therefore, the quadrilateral MATH is a rectangle.

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Answer:

B. -1/3

Step-by-step explanation:

Choose 2 points. From the lower points count up until it is in line with the other point. Then count left until you reach the second point.

Rise/Run

Rise=1

Run=-3

[tex]-\frac{1}{3}[/tex]

Hope this helps!

Answer: -1/3 is the answer

Step-by-step explanation:

The y-intercept represents the average cost, in dollars per pint, of all the raspberries Ethan bought. Therefore, option B is the correct answer.

Given that, Ethan bought 3 pints of raspberries for $5 per pint and x pints of blueberries for $3 per pint.

The average is (15 + 3x)/(3+x) per pint.

We need to find what quantity will be represented by the y-intercept of the graph.

Since the y-intercept always has a corresponding x-value of 0, replace x with 0 in the equation and solve for y. On a graph, the y-intercept can be found by finding the value of y when x=0. This is the point at which the graph crosses through the y-axis.

Now, the graph of y=(15 + 3x)/(3+x)is given below.

To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.

x-intercept(s): (−5,0)

y-intercept(s): (0,5)

So, the y-intercept represents the average cost, in dollars per pint, of all the raspberries Ethan bought.

Therefore, option B is the correct answer.

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The expression [tex]\sqrt[4]{\frac{24x^6y}{128x^4y^5} }[/tex] is equivalent to the expression [tex]\frac{\sqrt[4]{3x^2}}{2y}[/tex]

An equation is an expression that shows the relationship between two numbers and variables.

An independent variable is a variable that does not depend on any other variable for its value whereas a dependent variable is a variable that depend on any other variable for its value.

Given the expression:

[tex]\sqrt[4]{\frac{24x^6y}{128x^4y^5} }\\ \\Simplifying:\\\\=\frac{\sqrt[4]{3x^2}}{2y}[/tex]

The expression [tex]\sqrt[4]{\frac{24x^6y}{128x^4y^5} }[/tex] is equivalent to the expression [tex]\frac{\sqrt[4]{3x^2}}{2y}[/tex]

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Answer:

The answer is D

Step-by-step explanation:

Answer:

○ 1 hour 41 minutes or more

Step-by-step explanation:

We can make two equations that represent the total amount each plumber charges.

If [tex]x[/tex] represents the number of hours they work, then:

•Total charged by Plumber A = [tex]35 + 15x[/tex]

• Total charged by Plumber B = [tex]40+12x[/tex]

Now, if Plumber A is more expensive than Plumber B, then:

Total charged by Plumber A > Total charged by Plumber B

∴ [tex]35 + 15x[/tex] > [tex]40+12x[/tex]

Now all we have to do is solve for [tex]x[/tex]:

[tex]35 + 15x[/tex] > [tex]40+12x[/tex]

⇒ [tex]35 + 15x -12x > 40[/tex]

⇒ [tex]35 + 3x > 40[/tex]

⇒ [tex]3x > 5[/tex]

⇒ [tex]x > \bf \frac{5}{3} \space\ \mathrm{h}[/tex]

[tex]\frac{5}{3} \space\ \mathrm h[/tex]  is equivalent to  [tex]\frac{5}{3} \times 60 \space\ \mathrm {min}[/tex] = 100 minutes, which is the same as 1h 40min.

This means if Plumber A works more than 1h 40min, they become more expensive than Plumber B.

More than 1h 40min is equivalent to '1 hour 41 minutes or more', therefore the first option is correct.

The surface area of the shape is 117.8 km²

From the question, we are to determine the surface area of the figure

The given figure is a cone.

Total surface area of a cone  = Area of circular part + Curved surface area

Total surface area of a cone = πr² + πrl = πr(r + l)

Where r is the radius

and l is the slant height

From the given information,

r = 3 km

l = 9.5 km

The total surface area of the cone = π×3(3+9.5)

The total surface area of the cone = 3π(12.5)

The total surface area of the cone = 117.8 km²

Hence, the surface area of the shape is 117.8 km²

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The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.

The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;

Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.

Consequently, we can evaluate the distance travelled after 4 minutes as;

Distance = 200 × 4 = 800mi.

Ultimately, the distance travelled per minute by the spaceship is; 800mi.

Remarks:

600 miles

520 miles

800 miles

1,080 miles

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Answer: [tex]\Large\boxed{C.~21}[/tex]

Step-by-step explanation:

The goal of the question

Find the value of 2abcosC

Given information

a = 4

b = 3

c = 2

Given formula (Law of Cosine)

[tex]c^2=a^2+b^2-2abcosC[/tex]

Substitute values into the formula (Leave 2abcosC as it is)

[tex](2)^2=(4)^2+(3)^2-2abcosC[/tex]

Simplify the exponents

[tex]4=16+9-2abcosC[/tex]

Simplify by addition

[tex]4=25-2abcosC[/tex]

Add 2abcosC on both sides

[tex]4+2abcosC=25-2abcosC+2abcosC[/tex]

[tex]4+2abcosC=25[/tex]

Subtract 4 on both sides

[tex]4 + 2abcosC-4=25-4[/tex]

[tex]\Large\boxed{2abcosC=21}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

C

Step-by-step explanation:

a² + b² - 2abcosC = c² ( subtract a² + b² from both sides )

- 2abcosC = c² - a² - b² ( multiply through by - 1 )

2abcosC = a² + b² - c²

a, b, c are the sides opposite vertices A, B, C

here a = 4 , b = 3 , c = 2 , then

a² + b² - c²

= 4² + 3² - 2²

= 16 + 9 - 4

= 25 - 4

= 21

The function to model the water used by the car wash on a shorter day is (C) [tex]4x^{3} +7x^{2} -14x-6[/tex].

To find the function to model the water used by the car wash on a shorter day:

Given that the amount of water used on normal days is given by the equation:

The amount of decrease in water used is modeled by the equation:

To get the function [tex]C(x)[/tex] that models the water used by the car wash on a shorter day you subtract equation (2) from equation (1).

Therefore, the function to model the water used by the car wash on a shorter day is (C) [tex]4x^{3} +7x^{2} -14x-6[/tex].

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The correct question is shown below:

The water usage at a car wash is modeled by the equation w(x) = 5x3 9x2 − 14x 9, where w is the amount of water in cubic feet and x is the number of hours the car wash is open. the owners of the car wash want to cut back their water usage during a drought and decide to close the car wash early two days a week. the amount of decrease in water used is modeled by d(x) = x3 2x2 15, where d is the amount of water in cubic feet and x is time in hours. write a function, c(x), to model the water used by the car wash on a shorter day.

(A) c(x) = 5x3 7x2 − 14x − 6

(B) c(x) = 4x3 7x2 − 14x 6

(C) c(x) = 4x3 7x2 − 14x − 6

(D) c(x) = 5x3 7x2 − 14x 6

Answer:

"Unary Association" I believe

The total surface area of the figure is 92 m².

The surface area of a figure is the sum of the whole sides of the figure.

Therefore,

surface area = 4 × 4 + 4 × 4 + 6 × 4 + 2 × 4 + 1 / 2 (2 + 6)3.5 +  1 / 2 (2 + 6)3.5

Hence,

surface area = 16 + 16 + 24 + 8 + 14 + 14

Therefore,

surface area = 32 + 24 + 8 + 28

surface area = 56 + 8 + 28

surface area = 92 m²

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The number of hours it will take both the surveyor and apprentice to complete the same job is 15/56 hours.

If the two work together;

Time taken for both to complete the task = Surveyors rate of work + Apprentice rate of work

= 1/8 + 1/7

= (7+8) / 56

= 15/56 hours

Therefore, the number of hours it will take both the surveyor and apprentice to complete the same job is 15/56 hours.

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Answer:

tanya 22

leah12

Step-by-step explanation:

i hope it

help ...

Answer:

14m

Step-by-step explanation:

Please refer to the attached figure
B is the position where John is standing, His eyes are at point A, 2 meters from the ground

D is the base of the cliff and E is the top of the cliff

∠EAC is the angle at which John looks up to the cliff and is given as 45°

BD is the distance from the cliff given as 12m

So AC is also 12m

∠ACE is 90°

Therefore ∠AEC is 180-(45+90) = 45° since AEC forms a triangle and sum of angles in a triangle = 180°

In the ΔAEC, by the law of sines
12/sin(45) = EC/sin(45) . This means EC = 12 since the denominators cancel out

Since point C is 2 meters above ground(the base of the cliff) add 2 and we get the height of the cliff as 12+2 = 14m

The points in a scatter plot cluster closely around the regression line, the correlation can be said to be the proportion of variance in Y that is determined or explained by X.

It is critical to understand that a correlation coefficient of zero indicates that there is no linear courting, but there can also nonetheless be a strong relationship among the 2 variables.

If one point of a scatter diagram is farther from the regression line than a few other factor, then the scatter diagram has as a minimum one outlier. If two or extra points are the identical farthest distance from the regression line not a commonplace prevalence), then every of those points is an outlier.

When the y variable has a tendency to increase because the x variable increases, we say there may be a high-quality correlation between the variables. when the y variable has a tendency to lower as the x variable increases, we are saying there's a bad correlation between the variables.

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The height of the flagpole is 12.4 meters and the altitude of the balloon is 29.1 meters

See attachment for the diagram, when redrawn

Start by calculating the length AB using the following tangent function

tan(22) = BC/AB

This gives

tan(22) = 9/AB

Make AB the subject

AB = 9/tan(22)

Evaluate the quotient

AB = 22.3

The length DB is then calculated using:

tan(9) = DB/AB

This gives

tan(9) = DB/22.3

Make DB the subject

DB = 22.3 * tan(9)

Evaluate

DB = 3.35

The height of the flagpole is then calculated as:

Height = DB + BC

This gives

Height = 3.35 + 9

Evaluate

Height = 12.35

Approximate

Height = 12.4

Hence, the height of the flagpole is 12.4 meters

The diagram that illustrates the scenario is added as an attachment

Calculate the value of y using the following tangent functions

tan(57) = x/y and tan(72) = (15 + x)/y

Make y the subject in tan(57) = x/y and tan(72) = (15 + x)/y

y = x/tan(57) and y = (15 + x)/tan(72)

Substitute y = x/tan(57) in y = (15 + x)/tan(72)

x/tan(57) = (15 + x)/tan(72)

Evaluate the tangent ratios

x/1.5 = (15 + x)/3.1

Cross multiply

3.1x = 22.5 + 1.5x

Evaluate the like terms

1.6x = 22.5

Divide by 1.6

x = 14.1

The altitude of the balloon is then calculated as:

Altitude = 14.1 + 15

Altitude = 29.1

Hence, the altitude of the balloon is 29.1 meters

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Answer:

C.) [tex]log_2(\frac{x^3z^2}{y^4})[/tex]

Step-by-step explanation:

To find the answer, you need to simplify the expression. To do so, you must combine the logs. You can combine the logs because they all have the same subscript (2).

[tex]3 log_2x - 4log_2y + 2log_2z[/tex]                           <----- Given expression

[tex]log_2x^3-log_2y^4+log_2z^2[/tex]                            <----- Raise coefficients to variables

[tex]log_2x^3+log_2z^2-log_2y^4[/tex]                            <----- Rearrange

[tex]log_2(x^3z^2)-log_2y^4[/tex]                                    <----- Multiply added logs

[tex]log_2(\frac{x^3z^2}{y^4})[/tex]                                                  <------ Divide subtracted log

Express the multiplication of a logarithm number of an expression as the logarithm of the power of the expression.

Take the product of the arguments

                         [tex]\red{\boxed{\boldsymbol{\sf{\blue{Answer \ \ \longmapsto \ \ Log_{2} \frac{x^{3}z^{2} }{y^{4} } } }}}}[/tex]

Therefore, the correct option is alternative "C".

The volume of box B is (A) 864 cubic meters.

To find the volume of box B:

= 864 cubic meters.

Therefore, the volume of box B is (A) 864 cubic meters.

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The complete question is given below:

Box A has a volume of 32 cubic meters. Box B is similar to box A. To create box B, box A's dimensions were tripled. What is the volume of box B?

a. 864 m3.

b. 288 m3.

c. 96 m3.

d. 32 m3

The factoring the equation (a + 1)² - 4b² we get (a+1+2b)(a+1-2b).

Given:  (a + 1)² - 4b²

Apply Perfect Square Formula, and we get

(a + b)² = a² + 2 a b + b²

(a + 1)² = a² + 2a1+1²

= a² + 2a1 + 1² - 4 b²

simplifying the equation, we get

a² + 2a1 + 1² = a² + 2a + 1

= a² + 2a + 1 - 4b²

Factor, a² + 2a + 1 = (a + 1)²

= (a + 1)² - 4 b²

Simplify 4 b² = (2 b)²

= (a + 1)² - (2b)²

Apply the Difference of Two Squares Formula, and we get

x² - y² = (x + y)(x - y)

(a + 1)² - (2b)² = ((a + 1) + 2b)((a + 1) - 2 b)

simplifying the equation, we get

= ((a + 1) + 2b)(a + 1) - 2 b)

= (a + 1 + 2b)(a + 1 - 2b)

Therefore, the correct answer is (a+1+2b)(a+1-2b).

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Yes, the correlation coefficient is statistically significance

The precise metric used in a correlation analysis to quantify the strength of the linear relationship between two variables is the correlation coefficient. In a correlation report, the r stands for the coefficient.

Given,

Sample size, n = 11

Where ρ is the population correlation.

Then the number of degrees of freedom is, df = n-2 = 11-2 = 9

The corresponding critical correlation value re for a significance level of a 0.01, for a two-tailed test is た= 0.254

Here,

The null hypothesis,  = ρ - 0 is rejected

Suppose lr> re 0.254

Because on the sample correlation provided, we know that lrl = 0.599>=0.254.

Here, it is clear that the null hypothesis is rejected.

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If the length of whice is shorter than the length of the train but longer than the length of one train car then the train can pass one car at a time.

Given that two trains are moving towards each other on the same railroad track. From this track there's an offshot peice of railroad- the length of whice is shorter than the length of the train but longer than the length of one train car.

We are required to find how the trains pass each other.

Two cases are there:

For each car in the shorter train

We assume that cars can be decoupled at any point in the train,so that any required order of cars can be preserved.We further assume that train can move any one of the A's car in addition to all of them.

The total number of cars lengths that must pass the off shoot is the product of the number of cars in both the trains.So,it does not seems to matter which train makes use of the offshoot.

Hence if the length of whice is shorter than the length of the train but longer than the length of one train car then the train can pass one car at a time.

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The Surface area of the triangular prism is: 318 km³.

A triangular prism is a solid that has two triangular bases and three rectangular faces.

The surface area of a triangular prism is the sum of the areas of its two triangular bases and three rectangular faces.

The formula for the surface area of a triangular prism = (S1 +S2 + S3)L + bh, where:

Perimeter of the base  = S1 + S2 + S3

Length of the prism = L

2 × Base Area = bh

Given the following:

s1 + s2 + s3 = 7 + 9 + 8 = 24 km

L = 11 km

bh = (9)(6) = 54 km²

Plug in the values

Surface area of the triangular prism = (24)11 + 54

Surface area of the triangular prism = 264 + 54

Surface area of the triangular prism = 318 km³

Thus, the Surface area of the given triangular prism in the diagram above is: 318 km³.

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The length of the diagonal of the canvas = 27 inches.

The correct option is D.

A fundamental relationship in Euclidean geometry between a right triangle's three sides is known as the Pythagorean theorem, or Pythagoras' theorem. The area of the square whose side is the hypotenuse is said to be equal to the total of the areas of the squares on the other two sides.

the Hight of the rectangle = 18 inches

the angle it form sinθ = H/P

H = 18

P =

cosθ = 48

cosθ = H/P

cosθ =18/P

P = 18/cosθ

 = 29.60

= 27

The length of the diagonal of the canvas = 27 inches.

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Answer:

.....................................

To know if the classmate’s family is actually wealthy, one will need to know their assets and their debt.

In financial accounting, an asset means a resource that is owned or controlled by a business or an economic entity. An asset is anything that can be used to produce positive economic value.

Assets represent the value of ownership that can be converted into cash and the examples of personal financial assets include cash and bank accounts, real estate, personal property like furniture and vehicles, and investments such as stocks, mutual funds, and retirement plans.

In this case, through the assets, one will be able to know that they're wealthy. The debt is an obligation that requires one party, the debtor, to pay money or other agreed-upon value to another party, the creditor. This is the money that they owe.

The asset should more than the debt.

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Based on the amount of oranges bought, those sold at a profit and those sold at a loss, the overall profit is 14.2%

Assume that the buying price was $1 each.

The amount earned from 60% of them is:

= 60% x 100,000 x 1

= $60,000

The profit from selling 50% of the remaining is:

= (50% x 40,000) x 1.60

= $32,000

The loss from selling the other 50%:

= (50% x 40,000) x 0.90

= $22,222.22

Total selling price:

= 60,000 + 32,000 + 22,222.22

= $114,222.22

Total profit:

= (114,222.22 - 100,000) / 100,000

= 14.2%

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Answer:

-2.25

Step-by-step explanation:

Answer:

B. 183

Step-by-step explanation:

m<L = (1/2)[m(arc)KN - m(arc)KM)]

35 = (1/2)(177x - 107x)

70 = 70x

x = 1

m(arc)KN = 177x = 177

m(arc)NMK = 360 - m(arc)KN

m(arc)MNK = 360 - 177

m(arc)MNK = 183