In a survey of 2035 workers, 73% reported working out 3 or more days a week. What is the margin of error? What is the interval that is likely to contain the exact percent of all people who work out 3 or more days a week? Show all work.

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In A Survey Of 2035 Workers, 73% Reported Working Out 3 Or More Days A Week. What Is The Margin Of Error?

Answers

Answer 1

The margin of error is 1.9%. and the interval that likely contains the true percent of all people who work out 3 or more days a week is: (71.1%, 74.9%)

What is the Margin of Error?

Margin of error is the critical value (t score or z score) multiplied by the standard error (standard deviation of the sample). Thus;

ME = Critical value × S.E

Since n > 30, we can use the z-score as the critical value.

Assuming 95% confidence level, then z = 1.96

The standard error for a proportion is given by the formula:

s = √(p (1 − p) / n)

We are given;

p = 0.73

n = 2035:

Thus;

s = √(0.73 (1 − 0.73) / 2035)

s = 0.0098

Thus, the margin of error is:

ME = 1.96 × 0.0098

ME = 0.019

The margin of error is 1.9%.  

The interval that likely contains the true percent of all people who work out 3 or more days a week is:

73% ± 1.9% = (71.1%, 74.9%)

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Related Questions

2. The product of two consecutive even numbers is 168. What are the numbers? ​

Answers

Answer:

12 and 14

Step-by-step explanation:

12 * 14 = 168

Answer:

12 & 14

Step-by-step explanation:

the work: x = first even number, (x+2) = second even number

The equation

[tex]x(x+2)=168[/tex]

[tex]x^{2} +2x=168[/tex]

[tex]x^{2} +2x-168=0[/tex]

Factoring

[tex](x-12)(x+14)=0[/tex]

first factor

[tex]x-12=0\\x=12[/tex]

Second factor

[tex]x+14=0\\x=-14[/tex]

The solution is the positive number

x = 12     is the first even number

x + 2 = 12 + 2 = 14    is the second even number

Hope this helps

HELPPPP PLSSSSSSSSS!!!!!!!!??!

Answers

Answer:

(3+3) x (3+1)

Step-by-step explanation:

nice

Given :

We have give 4 numbers that are 1,3,3,3. we have to apply operations on it to make it 24.

Solution :

» (1 + 3) × (3 + 3)

» (4) × (6)

» 24

Here's our answer..!!

In the diagram, is parallel to. Also, is drawn such that the length of is half the length of. If sin A = 0.5, then what is sin E?

Answers

sinE is 0.5

What are similar triangles?

Two triangles will be similar if the angles are equal (corresponding angles), and sides are in the same ratio or proportion (corresponding sides). Similar triangles may have different individual lengths of the sides of triangles, but their angles must be equal and their corresponding ratio of the length of the sides must be the same.

Clearly, given triangle AFB and triangle DFE are similar.

We know that Similar Triangles have the same corresponding angle

We can find sinE as show below:

From diagram clearly

∠A=∠E

and ∠B=∠D

Since, ∠A=∠E

Taking sin on both sides

sinA=sinE

Give, sinA=0.5

sinA=sinE=0.5

⇒ sinE=0.5

Hence, sinE is 0.5

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what is the area of the figure bellow?

Answers

Answer:

The area of the figure is C. 48.5 cm²

Which of the following options have the same value as 5\%5%5, percent of 353535?

Answers

Answer:

[tex]\frac{5}{100}\times35[/tex]

[tex]0.05\times35[/tex]

Step-by-step explanation:

Given:

Which of the following options have the same value as 5% 35, percent of 35?

Following Options:

[tex]5 \times 35[/tex]

[tex]\frac{5}{100}\times35[/tex]

[tex]0.5\times0.35[/tex]

[tex]0.05\times35[/tex]

[tex]\frac{5}{10}\times35[/tex]

Solve:

[tex]5[/tex] % [tex]= 0.05=\frac{5}{100}[/tex]

Thus the following options:

[tex]5 \times 35[/tex]           [ False x ]

5 does not equal 5%

[tex]\frac{5}{100}\times35[/tex]         [True √ ]

[tex]5[/tex]% [tex]=\frac{5}{100}[/tex]

[tex]0.5\times0.35[/tex]      [ False x ]

[tex]0.5 = 0.50[/tex]

[tex]0.05\times35[/tex]       [True √ ]

[tex]5[/tex]% [tex]= 0.05=\frac{5}{100}[/tex]

[tex]\frac{5}{10}\times35[/tex]          [ False x ]

[tex]\frac{5}{10}=0.50[/tex]

Therefore, the options [B] [tex]\frac{5}{100}\times35[/tex] and [D] [tex]0.05\times35[/tex] is True.

Kavinsky

8v(v+3)(v+3) rewrite the expression factoring out (v+3)

Answers

If we rewrite the expression 8v(v+3)(v+3) then we will get [tex]v^{3}+6v^{2} +9v[/tex]

Given an expression 8v(v+3)(v+3).

We are required to rewrite the given expression.

Expression is a combination of numbers, symbols, fraction , determinants,indeterminants, coefficients. They are not mostly found in equal to form. It expresses a relationship of a line or something else.

The expression is 8v(v+3)(v+3). There are three terms in which variable is v.

To rewrite the expression we have to multiply all the three terms with each other which can be done as under:

=8v(v+3)(v+3)

=[tex](8v^{2}+24v)(v+3)[/tex]

=[tex]8v^{3}+24v^{2}+24v^{2}+72v[/tex]

=[tex]8v^{3}+48v^{2} +72v[/tex]

Now divide it by 8.

=[tex]v^{3}+6v^{2} +9v[/tex]

Hence if we rewrite the expression 8v(v+3)(v+3) then we will get [tex]v^{3}+6v^{2} +9v[/tex] .

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Find the surface area of a sphere with radius 15 in

Answers

radius -15

Surface Area of a sphere =4πr^2

=4x22/7x15x15

=19800/7

=2828.57

i. 749x98+749 x2 ii. 62 x 999 +4795 iii. 736 x 97 iv. 258 x 1008

solve these using distributive property
pls help if u know​

Answers

Step-by-step explanation:

I= 74810

II=66733

III=71392

iv=239904

Solve for y.......
[tex]6 = 2(y + 2)[/tex]

Answers

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

y = 1

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

[tex] \qquad❖ \: \sf \:6 = 2(y + 2)[/tex]

[tex] \qquad❖ \: \sf \:(y + 2) = \cfrac{6}{2} [/tex]

[tex] \qquad❖ \: \sf \:y + 2 = 3[/tex]

[tex] \qquad❖ \: \sf \:y = 3 - 2[/tex]

[tex] \qquad❖ \: \sf \:y = 1[/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

Value of y = 1
Rewrite the equation as 2(y+2)=6

Divide each term in 2 (y+2)=6 by 2 and simplify

2(y+2)/2=6/2

Simplify the left side

Cancel the common factor of 2

x(y+3)x=6/2

Divide y+2 by 1

y+2=6/2

Simplify the right side

Divide 6 by 2

y+2=3

Move all terms not containing y to the right side of the equation

y=1

HOW MANY DIFFERENT ARRANGEMENTS CAN BE MADE WITH THE NUMBERS
28535852

Answers

Answer:

1,680

Step-by-step explanation:

8 positions with basically 8 choices.

that is 8! arrangements.

but 2 is there 2 times.

8 is there 2 times.

5 is there 3 times.

only 3 is a single digit.

so, we need to eliminate every arrangement, where the 2s trade places, where the 5s trade places, and where the 8s trade places, because they are the same numbers.

that means we have to divide the 8! by 2!, then again by 2!, and again by 3!.

8! / (2! × 2! × 3!) = 8! / 24 = 1,680

Throughout this course, you have examined how real-world scenarios can be modelled using quadratic functions, exponential functions, trigonometric ratios sinusoidal functions, and sequences and series. Part A:- In this task, you will be creating unique real-world problems that can be modelled using the functions that we have learned. You may use real-world scenarios that we have examined throughout the course, but your problem should be created by you and have a unique description. Choose three (3) of the five (5) topics below and create a real-world scenario related to each of the three. 1. Exploring Quadratic Functions to Find Zeros or the Vertex; 2. Exponential Growth or Decay; 3. Using Trigonometric Ratios to Solve Three Dimensional Problems; 4. Representing Periodic Behaviour with Sinusoidal Functions: 5. Solving Financial Problems using Sequences & Series.

PLEASE SOLVE WITHOUT USING RADINAS

Answers

The exponential function is illustrated below.

How to illustrate the example?

An exponential function has a growth factor or 3.76. What is the percentage growth rate?

The growth factor (b) is given as:

b = 3.76

So, the percentage growth rate (r) is calculated as:

r = b - 1

Substitute known values

r = 3.76 - 1

Evaluate the difference

r = 276%

The way to solve Financial Problems using Sequences & Series will be:

The first salary that Mr James earn is 10000 and there is a yearly increase of 2000. Find his salary in the 5th year. This will be:

= a + (n - 1)d

= 1000 + (5 - 1)2000

= 10000 + (4 × 2000)

= 10000 + 8000.

= 18000

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please help!!
maths functions

Answers

Answer:

The Co-ordinate of C is (4/3, -1/2)

Step-by-step explanation:

We have two equation one is of straight line equation which is:

                                              y=2x-3           (i)

Other equation is of quadratic function which is:

                                         y=-3x^2+5         (ii)

Put the value of y from equation (i) in equation (ii)

So, we have:

                                     2x-3=-3x^2+5

                                      3x^2+2x-8=0

By factorization:

                                    3x^2+6x-4x-8=0

                                   3x(x+2)-4x(x+2)=0

                                        (x+2)(3x-4)=0

              x+2=0                             ;                      3x-4=0

              x=-2                                ;                       x=4/3

Put first x=-2 in equation (i)

                                                y=2(-2)-3

                                                  y=-4-3

                                                    y=-7

Now Put x=4/3 in equation (i)

                                             y=2(4/3)-3

                                                 y=8/3-3

                                                   y=-1/2

So, we have two Order pair One is (-2 , -7) and Second one is (4/3 , -1/2)

Hence the Co-ordinate of C is:

                                               C=(4/3 , -1/2)

Answer:

Point C:  (3, 3)

Point D:  (3, -22)

Step-by-step explanation:

If the distance between points C and D is 25 units, the y-value of point D will be 25 less than the y-value of point C.  The x-values of the two points are the same.

Therefore:

[tex]\textsf{Equation 1}: \quad y=2x-3[/tex]

[tex]\textsf{Equation 2}: \quad y-25=-3x^2+5[/tex]

As the x-values are the same, substitute the first equation into the second equation and solve for x to find the x-value of points C and D:

[tex]\implies 2x-3-25=-3x^2+5[/tex]

[tex]\implies 3x^2+2x-33=0[/tex]

[tex]\implies 3x^2-9x+11x-33=0[/tex]

[tex]\implies 3x(x-3)+11(x-3)=0[/tex]

[tex]\implies (x-3)(3x+11)=0[/tex]

[tex]\implies x=3, -\dfrac{11}{3}[/tex]

From inspection of the given graph, the x-value of points C and D is positive, therefore x = 3.

To find the y-value of points C and D, substitute the found value of x into the two original equations of the lines:

[tex]\begin{aligned} \textsf{Point C}: \quad 2x-3 & =y\\2(3)-3 & =3\\ \implies & (3, 3)\end{aligned}[/tex]

[tex]\begin{aligned} \textsf{Point D}: \quad -3x^2+5 & = y \\ -3(3)^2+5 & =-22\\ \implies & (3, -22)\end{aligned}[/tex]

Therefore, point C is (3, 3) and point D is (3, -22).

There are 48 people coming to a family reunion. One fourth of them live out of state. How many live in-state?

Answers

Step-by-step explanation:

1/4×48

=12

So if 12people are out of state

48-12=36,is the number of people living in the state

13. A data set has a mean of x=3905 and a standard deviation of 110. Find the z-score for each of the following.

14. A random sample of 80 tires showed that the mean mileage per tire was 41,400mi, with a standard deviation of 4700mi.

Answers

Question 13

Part (a)

[tex]\frac{3840-3905}{110}=\boxed{0.5\overline{90}}[/tex]

By similar logic, the other answers are

(b) 2.6818181....

(c) 3.5909090...

(d) 1.1363636...

Question 14

Part (a)

[tex]\frac{46800-41400}{4700} \approx \boxed{1.15}[/tex]

Part (b)

[tex]-2.57=\frac{x-41400}{4700} \\ \\ -2.57(4700)=x-41400 \\ \\ x=41400-2.57(4700) \\ \\ x \approx \boxed{29300}[/tex]

PLEASE HELP ASAP !!!!


Which functions have a range of {y e R-00 < y < ∞0}?
O f(x) = -4x + 11
Of(x) = x - 8
O
f(x) = 2x+3
O f(x) = -(x + 1)² - 4
O
f(x)
f(x) = x²
x² + 7x9

Answers

Answer:

Options 1 and 2

Step-by-step explanation:

Correct. The range of all linear functions without a restricted domain is the set of all real numbers.Correct. The range of all linear functions without a restricted domain is the set of all real numbers.Wrong. The exponential cannot take negative values.Wrong. Quadratics do not have a range that is the set of real numbers.Wrong. Quadratics do not have a range that is the set of real numbers.

A normal population has a mean u = 31 and standard deviation = 10. What proportion of the population is less than 30?​

Answers

The proportion of the population exists less than 30 then

(x< 30) = 0.986.

How to estimate the proportion of the population that exists less than 30?​

To estimate the z-score using the formula, z = (x - µ)/σ

Where, x be the randomly chosen values = 30

µ be the mean = 31

σ be the standard deviation = 10

Proportion of the population that exists less than 18 = P(x < 30)

Plug in the values into z = (x - µ)/σ, to get z-score.

Substitute the values in the above equation, we get

z = (30 - 31)/10

z = -1/10 = -0.1

Therefore, the value of z = - 0.1.

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Write down the answer for Q 7 and 8

Answers

The answers to the given addition operations are

7) 6 Hundredths add to 4 tenths add to 6 ones is equal to 6.46

8) 82 Hundredths add to 9 tenths add to 4 tens is equal to 41.72

Addition operation

From the question, we are to add the given numbers

7. 6 Hundredths add to 4 tenths add to 6 ones is equal to

6 Hundredths = 0.06

4 tenths = 0.4

6 ones = 6

Thus, we get

0.06 + 0.4 + 6 = 6.46

8. 82 Hundredths add to 9 tenths add to 4 tens is equal to

82 Hundredths = 0.82

9 tenths = 0.9

4 tens = 40

Thus, we get

0.82 + 0.9 + 40 = 41.72

Hence, the answers to the given addition operations are

7) 6 Hundredths add to 4 tenths add to 6 ones is equal to 6.46

8) 82 Hundredths add to 9 tenths add to 4 tens is equal to 41.72

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What is the volume of a cylinder with a radius of 3 inches and a height of 5 inches? Round to the nearest tenth if necessary.

Answers

The volume of the cylinder in discuss in which case, the radius of the cylinder is 3 inches and the height is inches is; V = 141.3in³.

What is the volume of the the described cylinder?

The cylinder in discuss according to the task content has radius, 3 inches and height, 5 inches.

Since the volume of a cylinder by convention is given as; V = πr²h

Therefore, the volume of the cylinder in discuss is;

V = π (3²)×5

V = 3.14 × 45

V = 141.3in³

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find the value of x,y in the given figure with reasons.​

Answers

Answer:

answer

x= 40°

Step-by-step explanation:

x= 40° [ base angle of isocles triangle]

The volume of a sphere is 144π. What is its Surface Area to the nearest whole number?

Answers

Volume = pi (radius ^2)
144 PI = PI (r^2)
Divide both sides by pi
144 =radius ^2
Square root
Radius is 12
Surface area=4PI(radius^2)
4(144)
576

Question 8 of 10
Factor the polynomial: -5x³ - 10x² - 15x
OA. 5x(x²+2x-3)
OB. -5x(-x2 - 2x - 3)
C. -5x(x2 + 2x - 15)
OD. -5x(x2+2x+3)

Answers

Letter D

All terms are negative, so A won’t work
-5x^3/-5x = x^2, so B won’t work
-15x/-5x = 3, so C won’t work

The base of the following pyramid is a square. If the volume of the pyramid is 400 feet³, what is the missing length? Round the answer to the nearest hundredth. The S=11ft​

Answers

The length of the missing side is 9.92 ft given that the base of the following pyramid is a square, base side length(s) is 11 ft and the volume of the square pyramid is 400 ft³. This can be obtained using the formula of finding the volume of the pyramid with base as square.

Calculate the length of the missing side:

The formula of finding the volume of the pyramid with base as square is,

⇒ V = s²h/3

where V is the volume of the square pyramid, s is the side length of the base and h is the height of the square pyramid.

Here in the question it is given that,

it is a pyramid with base as squarethe side length of the base is 11 ftvolume of the square pyramid is 400 ft³

that is, s = 11 ft, V = 400 ft³

By using the formula of finding the volume of the pyramid with base as square we get,

V = s²h/3

400 = (11)²h/3

By rearranging the equation we get,

h = 400 × 3/11²

h = 9.92 ft

Hence the length of the missing side is 9.92 ft given that the base of the following pyramid is a square, base side length(s) is 11 ft and the volume of the square pyramid is 400 ft³.

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Rewrite the quadratic function in vertex form (which is also called a standard form) and give the vertex.

f(x)=x^2-3x

f(x)=

Enter your answer as a point (a,b)
Vertex:

Please explain how you arrived at that answer.

Answers

The vertex form of the equation f(x) = x^2 - 3x, is f(x) = (x - 3/2)^2 - 9/5

How to rewrite the quadratic function?

The quadratic function is given as:

f(x) = x^2 - 3x

Differentiate the function

f'(x) = 2x - 3

Set the function to 0

2x - 3 = 0

Add 3 to both sides

2x = 3

Divide by 2

x = 3/2

Set x = 3/2 in f(x) = x^2 - 3x

f(x) = 3/2^2 - 3 * 3/2

Evaluate

f(x) = -9/5

So, we have:

(x, f(x)) = (3/2, -9/5)

The above represents the vertex of the quadratic function.

This is properly written as:

(h, k) = (3/2, -9/5)

The vertex form of a quadratic function is

f(x) = a(x - h)^2 + k

So, we have:

f(x) = a(x - 3/2)^2 - 9/5

In f(x) = x^2 - 3x,

a = 1

So, we have:

f(x) = (x - 3/2)^2 - 9/5

Hence, the vertex form of the equation f(x) = x^2 - 3x, is f(x) = (x - 3/2)^2 - 9/5

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(5.01 LC) A square is shown below. which expression can be used to find the area, in square units, of the Shaded triangle in the Square?

(answer options are in picture)​

Answers

The expression can be used to find the area, in square units, of the Shaded triangle in the Square is  1/2 ( 4 · 4 ) .

What is the area of a square?

The area of a square can be calculated as the square of the sides of a given figure.

The area of a square = side x side

where s = side length.

If a diagonal is drawn to create 2 halves, then area of each half is 8.

So, The area of a square = 1/2 ( 4 · 4 ) = 16.

If a square has a side length of 4, then the area of the square is 16.

The expression can be used to find the area, in square units, of the Shaded triangle in the Square is  1/2 ( 4 · 4 ) .

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Can someone help me with a step by step process of how to solve this? Calculus 2

Answers

If you fix a point on the curve in the given interval, and revolve that point about the [tex]x[/tex]-axis, it will trace out a circle with radius given by the function value [tex]y[/tex] for that point [tex]x[/tex]. The perimeter of this circle is then [tex]2\pi(8\sqrt x) = 16\pi \sqrt x[/tex].

The surface in question is essentially what you get by joining infinitely many of these circles at every point in the interval [0, 9].

So, the surface area is given by the definite integral

[tex]\displaystyle \int_0^9 16\pi \sqrt x \, dx = 16\pi\times\frac23 x^{3/2}\bigg|_{x=0}^{x=9} = \frac{32\pi}3 \left(9^{3/2} - 0^{3/2}\right) = \boxed{288\pi}[/tex]

Cos3A ×cos2A =cos A ×cos 2A -sin4A×sin A=prove it

Answers

Answer:

Step-by-step explanation:

cosA×cos 2A-sin4A×sinA

=cosAcos2A-2sin2Acos2A sin A

=cos 2A(cosA-2sin2AsinA)

=cos 2A(cosA-2×2sinAcosAsin A)

=cos2A×cosA(1-4sin²A)

=cos 2AcosA(1-4(1-cos²A))

=cos2A×cosA(1-4+4cos²A)

=cos 2A(-3cosA+4cos³A)

=cos 2A(4cos³A-3cosA)

=cos 2A×cos3A

a dust mite is 400 pm long under a microscope, it looks 100,000 pm long. what magnification scale was used​

Answers

Answer: 250:1

Step-by-step explanation:

Divide the measurement of appearance by the actual measurement.

[tex]100,000/400=250[/tex]

The magnification scale is 250:1. The scale is used by a 250X magnifying lense.

What is the solution of the inequality shown
below?
c+3>8

Answers

Answer:

  c > 5

Step-by-step explanation:

The properties of equality can be used to solve inequalities. Attention needs to be paid to ordering.

Application

We can subtract 3 from both sides to solve this.

  c +3 > 8 . . . . . . given

  c +3 -3 > 8 -3 . . . . subtract 3 from both sides

  c > 5 . . . . . . . . . simplify

The solution is c > 5.

__

Additional comment

Adding or subtracting a value to a number on a number line is equivalent to shifting it right or left. It does not change ordering.

Multiplying or dividing by a positive number is equivalent to expanding or compressing the distance from zero. It does not change ordering.

Multiplying or dividing by a negative number reflects the value across the origin, in addition to expanding or compressing the distance from zero. This reflection reverses the left-right ordering. For example, -2 < -1, but 2 > 1. (Both numbers multiplied by -1.)

As long as you're aware of the effect on ordering, you can use any of the properties of equality to solve inequalities.

An insurance provider states that their customers save at least, on average, 300 dollars per year by switching to them, with a standard deviation of 150 dollars. Before we decide to switch to the new company and go through all of the hassle, we want to test the claim. So, we go out and sample 64 individuals who switched to the new insurance company and found them to have saved an average of 255 dollars per year. Do we have enough evidence at the α = 0.05 level to state that the insurance provider is false in their claim? Discussion Prompts Answer the following questions in your initial post: What are the hypotheses based on the words given in the problem? Should we use a Z or T distribution in this case? What is our Z or T statistic? What is the P-value? Based on your p-value and alpha, what conclusion will we make? Based on your results, would you switch to this company? Explain why or why not (Note: this can go beyond the use of statistics, but statistical analysis can help our decisions)

Answers

The solution to the question is mathematically given as

1)

H0: M [tex]\geqslant[/tex] 300

H0: M [tex]\geqslant[/tex] 300

2)

Z distribution.

3)

z=-2.4

4)

P=0.0082

5)

"H0" is rejected as a hypothesis with a level of significance of 0.05.

What is the hypothesis ?

Generally, the equation for is mathematically given as

Solutions

we have, [tex]$u=300$$$\begin{aligned}& \sigma=150 \text { dollars } \\N &=64 \text { individuals } \\\bar{x} &=255 \text { dollare. } \\a=& 0.05 .\end{aligned}[/tex]

(1):

H0: M [tex]\geqslant[/tex] 300 dollars;  customers save at least 300 dollars per year by switching to them.

H0: M [tex]\geqslant[/tex] 300 dollars:

(This is a left-tailed test)

(2):

when [tex]\sigma[/tex] is known, we use the Z test. we use Z distribution.

(3):

[tex]\begin{gathered}z=\frac{\bar{x}-\mu}{6 / \sqrt{n}}=\frac{255-300}{150 / \sqrt{64}}=\frac{-45}{18.75}=-2.4 \\z=-2.4\end{gathered}[/tex]

(4):

[tex]Pvalue $=P(z < -2 \cdot 4)$ $=0.0082 \quad\{$ wing $z$ tables $\}$ \\\\\text { Pvalue }=0.0082[/tex]

(5):

In conclusion, Since p-value = 0·0082 <0.05

This is statistically significant at the 0.05 level.

We thus "Refect H0" using a threshold of significance of 0.05.

"H0" is rejected as a hypothesis with a level of significance of 0.05.

There is not enough data to support the assertion that consumers may save at least $300 annually by switching insurance providers.

Therefore, we would not consider making the transition to this firm.

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P=2(L+W) Solve for W

Answers

W=p/2 -1
That should be the answer

Answer:

W = (P -2L)/2

Step-by-step explanation:

P = 2(L + W)  Distribute the 2

P = 2L + 2W   Subtract 2L from both sides

P - 2L = 2W  Divide both sides by 2

(P-2L)/2 = W  

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