if you rolled two dice what is the probability that you would roll a 4 or a 5

Answers

Answer 1
Hello there! Given that normal dice are numbered 1-6, individually rolling a 4 or a 5 would give a 1/6 probability. That converts to about 17% as a percentage because we can multiply 1 by 100 to get 100/6, then divide 100 by 6 to get 16.6666. When rounding, that gives approximately 17%. However, if we combined probabilities, we would find that rolling a 4 or a 5 collectively gives a 2/6 probability, which is approximately 33% as a decimal.

In terms of individual probabilities, you would be 17% likely to roll one of them. In terms of collectiveness, the likelihood of rolling a 4 or 5 would render 33% on each die. If you need additional help, let me know and I will gladly assist you.

Related Questions

Define the geometric sequence as a recursive function, if the first term is 1/5 and the common ratio is 5 .

Answers

The geometric sequence when the first term is 1/5 and the common ratio is 5 is; f(n) = f(n-1) . 5.

What is the geometric sequence described?

The geometric sequence described in the task content is one whose first term is; f(1) = 1/5.

Additionally, it follows from convention that the recursive function for a geometric sequence is; a product of a previous term and the common ratio.

Hence, we have; f(n) = f(n-1) . 5.

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What is the equation of the line that is parallel to the line y = -1/3x + 4 and passes through the point (6, 5)?

Answers

Answer:

[tex]y=-\frac{1}{3}x+7[/tex]

Step-by-step explanation:

Parallel lines have the same slope, so the slope of the line we need to find is -1/3.

Substituting into point-slope form and converting to slope-intercept form,

[tex]y-5=-\frac{1}{3}(x-6) \\ \\ y-5=-\frac{1}{3}x+2 \\ \\ y=-\frac{1}{3}x+7[/tex]

In △ABC, AB = 13, AC = 20, BC = 21. Find the length of the altitude AD

Answers

The length of the altitude AD is 12 units.

How to find the height of a triangle?

The height of the triangle can be found as follows:

We have to find an angle using cosine law before  we can find the height.

Therefore,

20² = 13² + 21² - 2 × 21 × 13 cos B

400 = 169 + 441  - 546 cos B

400 - 610 = - 546 cos B

-210 = - 546 cos B

cos B = -210 / -546

cos B = 0.38461538461

B = cos⁻¹ 0.38461538461

B = 67.3810899783

B = 67.38°

Hence,

sin 67.38° = opposite / hypotenuse

sin 67.38° = AD / 13

cross multiply

AD = 13 sin 67.38°

AD = 11.9999882145

AD = 12 units

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When you send out a resume, the probability of being called for an interview is 0. 40. what is the probability that the first interview occurs on the fifth resume that you send out?

Answers

The probability that the first interview occurs on the fifth resume that you sent is 0.2592.

According to the given question.

The probability of being called for an interview, p = 0.40.

So, the probability of not being called for an interview, q = 1 - 0.40 = 0.60

As we know that binomial distribution summarizes the number of trials, or observations when each trial has the same probability of attaining one particular value. The binomial distribution determines the probability of observing a specified number of successful outcomes in a specified number of trials.

Therefore, the probability that the first interview occurs on the fifth resume that you send out

= [tex]^{5} C_{1} (0.40)^{1} (0.60)^{4}[/tex]

= 5(0.40)(0.1296)

= 0.2592

Hence, the probability that the first interview occurs on the fifth resume that you sent is 0.2592.

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Is there any number in base 10 (positive or negative) that can be written in multiple
ways in base −4? Can you prove it? If yes, provide the number and the base −4
representations, and if no, show why.

Answers

The true statement is that no number in base 10 can be written in multiple ways in base 4

How to determine the true statement?

The base of the numbers are given as:

Base 10 and base 4

Base 10 numbers are also referred to as decimal numbers, while base 4 numbers are quaternary numbers

There is only one equivalent of each number in each base.

This means that (for instance)

357 in base 10 is 11211 in base 4

The above number does not have any other representation in base 4 and it can not be written in another way.

This is the same for other numbers in base 10

Hence, the true statement is that no number in base 10 can be written in multiple ways in base 4

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Amelia has a job baby-sitting for a neighbor. she is paid $20 plus $2.50 for each hour on the job. if amelia wants to earn $40 to buy a new sweater, how many hours would she need to work? a. 16 hours b. 9 hours c. 10 hours d. 8 hours please select the best answer from the choices provided a b c d

Answers

The correct option is option (d) 8 hours.

Amelia need to work for 8 hours to buy new sweater $40.

What is an equation and its solution?

When two expressions are connected with the equals sign (=) in a math equation, it expresses the equality of the two expressions. A number that may be entered for the variable to produce a true number statement is the solution to an equation.

Let the hours Amelia need to work=h

Amalia paid=$20

Payment of each hour=$2.50

So, we can make an equation with given problem

40=20+2.50h

40-20=2.5h

20=2.5h

[tex]h=\frac{20}{2.5}[/tex]

h= 8

So, Amelia need to work for 8 hours to get $40.

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PLEASE ITS MY LAST QUESTION

Answers

Answer:

[tex]y = - \frac{1}{4} x - 10[/tex]

Step-by-step explanation:

The negative reciprocal of 4 is -1/4.

Let's substitute in our values, to find the y-intercept:

[tex]y = - \frac{1}{4} x + c[/tex]

[tex] - 11 = - 1 + c[/tex]

[tex]c = - 10[/tex]

Finally, our full equation is:

[tex]y = - \frac{1}{4} x - 10[/tex]

Jarred sells DVDs. His inventory shows that he has a total of 3,500 DVDs. He has 2,342 more contemporary titles than classic titles. Let x represent the number of contemporary titles and y represent the number of classic titles. The system of equations models the given information for both types of DVDs.

x + y = 3,500

x – y = 2,342

Solve the system of equations. How many contemporary titles does Jarred have?

Answers

The number of contemporary titles and classic titles in Jarred DVDs collection is 2,921 and 579 respectively.

Simultaneous equation

Simultaneous equation is an equation which involves the solving for two unknown values at the same time.

number of contemporary titles = xnumber of classic titles = y

x + y = 3,500

x – y = 2,342

Add both be equation

x + x = 3,500 + 2,342

2x = 5,842

x = 5,842 ÷ 2

x = 2,921

Substitute x = 2,921 into

x – y = 2,342

2,921 - y = 2, 342

-y = 2,342 - 2,921

-y = -579

y = 579

Therefore, the number of contemporary titles and classic titles in Jarred DVDs collection is 2,921 and 579 respectively.

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How to answer this problem

Answers

Answer:

m<C = 12.0 °

Step-by-step explanation:

Since we know that this is a non-right triangle, we must use either the law of sines or law of cosines to find m<C.  

The information we now have only allows us to use the law of sines, which focuses on proportions:

[tex]\frac{SinA}{a}=\frac{SinB}{b}=\frac{SinC}{c}[/tex]

Thus, we can use:

[tex]\frac{sin(98)}{19}=\frac{sinC}{4}\\ 4*sin(98)=19*sinC\\ \frac{4*sin(98)}{19}=sinC\\ sin^-1\frac{4*sin98}{19}=12.033=12.0[/tex]

The sin^-1 represents the sin inverse, which you must use to find angle measures.

Solve For x :
[tex] \color{purple}{ \pmb{ \frak{2x \: = 100 \red { \: ?}}}}[/tex]
[tex] \\ \\ \\ \\ \\ [/tex]

[tex] { \color{yellow}\bigstar}\underline{ \pmb{ \frak{Thank \: uh }} \color{purple}{ \hearts} !!\: }[/tex]

Answers

[tex]\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}[/tex]

Given ,

[tex]2x = 100[/tex]

To find ,

value of x

Now ,

[tex]\longrightarrow{2x = 20}[/tex]

Dividing both sides by 2 , we get

[tex] \frac{2x}{2} = \frac{100}{2} \\ \\ \longrightarrow\boxed{ \: x = 50} [/tex]

nikal -,- xD

Answer:

[tex]\bf x=50[/tex]

Step-by-step explanation:

[tex]\bf 2x=100[/tex]

Divide both sides by 2:-

[tex]\bf \cfrac{2x}{2}=\cfrac{100}{2}[/tex]

Simplify:-

[tex]\bf x=50[/tex]

___________________

neeed help more more please uwu

Answers

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

Let's calculate its discriminant ~

[tex]\qquad \sf  \dashrightarrow \: {t}^{2} + \cfrac{17}{2} t - 5 = 0[/tex]

[ Multiply both sides by 2 ]

[tex]\qquad \sf  \dashrightarrow \: 2 {t}^{2} + 17t - 10[/tex]

a = 2

b = 17

c = 10

[tex]\qquad \sf  \dashrightarrow \: discriminant = {b}^{2} - 4ac[/tex]

[tex]\qquad \sf  \dashrightarrow \: d = (17) {}^{2} - (4 \times 2 \times - 10)[/tex]

[tex]\qquad \sf  \dashrightarrow \: d = 289 - ( - 80)[/tex]

[tex]\qquad \sf  \dashrightarrow \: d = 369[/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt {d }= 3 \sqrt{41} \approx19.209 [/tex]

So, by quadratic formula :

[tex]\qquad \sf  \dashrightarrow \: t = \dfrac{ - {b}^{} \pm \sqrt{d} }{2a} [/tex]

[tex]\qquad \sf  \dashrightarrow \: t = \dfrac{ - {17}^{} \pm \sqrt{369} }{2 \times 2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \:t = \cfrac{ - 17 - 19.209}{4} \: \: and \: \: t = \dfrac{-17+19.209}{4} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \:t = \cfrac{ - 36.209}{4} \: \: and \: \: t = \dfrac{2.209}{4} [/tex]

[tex]\qquad \sf  \therefore \: t = - 9.052 \: \: \: or \: \: \: t = 0.552[/tex]

properties of intersection of sets

Answers

The intersection of the sets has the following properties: Commutative law – A ∩ B = B∩ A. Associative law – (A ∩ B)∩ C = A ∩ (B∩ C) φ ∩ A = φ

do mark brainliest

Find the missing length.
= √ [?]
C =
C
6
2
Pythagorean Theorem: a² + b² = c²

Answers

[tex]\huge\text{Hey there!}[/tex]


[tex]\mathsf{Formula: a^2 + b^2 = c^2}[/tex]


[tex]\textsf{Solving:}[/tex]

[tex]\mathsf{2^2 + 6^2 = c^2}[/tex]

[tex]\mathsf{2 \times 2 + 6 \times6 = c^2}[/tex]

[tex]\mathsf{4 + 36 = c^2}[/tex]

[tex]\mathsf{40 = c^2}[/tex]


[tex]\large\textsf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\frak{\sqrt{40}}}\huge\checkmark[/tex]


[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]


~[tex]\frak{Amphitrite1040:)}[/tex]

Humood's house is (-5,7)
The school is (3,1)
If each unit in the graph is 50m, find the distance from Humood's house to the school.

Answers

The distance from Humood's house to the school is 500m

How to determine the distance from Humood's house to the school?

The given parameters are:

Humood's house is (-5,7)

The school is (3,1)

The distance between both points is calculated using

[tex]d = \sqrt{(x_2- x_1)^2 + (y_2 - y_1)^2[/tex]

Substitute the known values in the above equation

[tex]d = \sqrt{(-5 - 3)^2 + (7 - 1)^2[/tex]

Evaluate

d = 10

Each unit in the graph is 50m.

So, we have

Distance =10 * 50m

Evaluate the product

Distance = 500m

Hence, the distance from Humood's house to the school is 500m

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PQRS is a cyclic quadrilateral.Chord RS is produced to T.K is a point on RS and W is a point on the circle such that QRKW is a parallelogram. PS and QW intersect at U. PST = 136° and Q₁ =100° Determine, with reasons, the size of: 8.1.1.R 8.1.2.P 8.1.3.PQW 8.1.4.U2​

Answers

Answer:

Step-by-step explanation:

PS and QW intersect at U. PST = 136° and Q₁ =100°

PLS HELP!What is the difference of

Answers

Answer:

Option 3

Step-by-step explanation:

Since the denominators are the same, you can just subtract the numerators.

PLEASE HELP IM STUCK

Answers

Answer:

23

Step-by-step explanation:

The question gives the first equation:

0.05N + 0.10D = 2.20

It can be rewritten as:

0.05$ times the number of nickels plus 0.10$ times the number of dimes is equivalent to $2.20.

Notice that 0.05$ or 5 cents is equivalent to one nickel and 0.10$ or 10 cents is equivalent to one dime.

The question asks for N+D. We know that N stands for the number of nickels Daniel has and D stands for the number of dimes Daniel has. We also know that Daniel only has dimes and nickels in his pocket. Therefore N+D most be equivalent to the total number of coins, which is given in the question to be equal to 23 coins.

Therefore...

N+D = 23

Find the extremum of f(x,y) subject to the given constraint, and state whether it is a maximum or a minimum. f(x,y)=xy; 6x y=10

Answers

There is a maximum value of 7/6 located at (x, y) = (5/6, 7).

The function given to us is f(x, y) = xy.

The constraint given to us is 6x + y = 10.

Rearranging the constraint, we get:

6x + y = 10,

or, y = 10 - 6x.

Substituting this in the function, we get:

f(x, y) = xy,

or, f(x) = x(10 - 6x) = 10x - 6x².

To find the extremum, we differentiate this, with respect to x, and equate that to 0.

f'(x) = 10 - 12x ... (i)

Equating to 0, we get:

10 - 12x = 0,

or, 12x = 10,

or, x = 5/6.

Differentiating (i), with respect to x again, we get:

f''(x) = -12, which is less than 0, showing f(x) is maximum at x = 5/6.

The value of y, when x = 5/6 is,

y = 12 - 6x,

or, y = 12 - 6*(5/6) = 7.

The value of f(x, y) when (x, y) = (5/6, 7) is,

f(x, y) = xy,

or, f(x, y) = (5/6)*7 = 7/6.

Thus, there is a maximum value of 7/6 located at (x, y) = (5/6, 7).

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Verify that the intermediate value theorem applies to the indicated interval and find the value of c guaranteed by the theorem. f(x) = x2 7x 1, [0, 9], f(c) = 19 c =

Answers

we verified the intermidiate value theorem applies to the function f(x) = x^2 + 7x  + 1 . And the value of c is 2.

According to the given question.

We have a function.

f(x) = x^2 + 7x  + 1

As, we know that "the Intermediate Value Theorem (IVT) states that if f is a continuous function on [a,b] and f(a)<M<f(b), there exists some c∈[a,b] such that f(c)=M".

Now, we will apply the theorem for the given function f(x).

So,

f(0) = 0^2 +7(0) + 1 = 1

And,

f(9)=9² + 7(9) + 1 = 81 + 63 + 1 = 145

Here,  f(0) = 1< 19< 145 = f(9).

So, f is continous since it is a polynomial. Then the IVT applies, and such c exists.

To find, c,

We have to solve the quadratic equation f(c) =19.

This equation is

c² + 7c + 1 = 19.

Rearranging, c²+ 7c - 18=0.

Factor the expression to get

c² + 9c - 2c -18 = 0

⇒ c(c + 9) - 2( c + 9) = 0

⇒ (c - 2)(c + 9) = 0

⇒ c = 2 or -9

c = -9 is not possible beacuse it is not in the interval [0, 9].

So, the value of c is 2.

⇒ f(2) = 2^2 + 7(2) + 1 = 4 + 14 + 1 = 19

Hence, we verified the intermidiate value theorem applies to the function f(x) = x^2 + 7x  + 1 . And the value of c is 2.

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HElp meee mwa mwa mwa

Answers

Answer:

[tex]a = 1, \ - 3[/tex]

Explanation:

[tex](a-6)(a+8) = -45[/tex]

distribute

[tex]a^2 + 8a - 6a - 48 = -45[/tex]

collect terms

[tex]a^2 + 8a - 6a - 48 + 45=0[/tex]

simplify

[tex]a^2 + 2a - 3=0[/tex]

factor

[tex](a - 1)(a + 3)= 0[/tex]

set to zero

[tex]a = 1, \ - 3[/tex]

Answer:

a = 1,  -3

Step-by-step explanation:

Given equation:

[tex](a-6)(a+8)=-45[/tex]

Expand the brackets:

[tex]\implies a^2+8a-6a-48=-45[/tex]

[tex]\implies a^2+2a-48=-45[/tex]

Add 45 to both sides:

[tex]\implies a^2+2a-48+45=-45+45[/tex]

[tex]\implies a^2+2a-3=0[/tex]

To factor a quadratic in the form [tex]ax^2+bx+c[/tex], find two numbers that multiply to [tex]ac[/tex] and sum to [tex]b[/tex].  

Two numbers that multiply to -3 and sum to 2 are: 3 and -1.  

Rewrite the middle term as the sum of these two numbers:

[tex]\implies a^2+3a-a-3=0[/tex]

Factorize the first two terms and the last two terms separately:

[tex]\implies a(a+3)-1(a+3)=0[/tex]

Factor out the common term (a + 3):

[tex]\implies (a-1)(a+3)=0[/tex]

Apply the zero product property:

[tex]\implies (a-1)=0 \implies a=1[/tex]

[tex]\implies (a+3)=0 \implies a=-3[/tex]

Verify the solutions by inputting the found values of a into the original equation:

[tex]a=1 \implies (1-6)(1+8) & =-5 \cdot 9 = -45[/tex]

[tex]a=-3 \implies (-3-6)(-3+8) & =-9 \cdot 5 = -45[/tex]

Hence both found values of a are solutions of the given equation.

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Quick algebra 1 question for 10 points!

Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!

Answers

Answer:

○ [tex]x = -7[/tex]

Step-by-step explanation:

Given the equation:

[tex]10(x + 10) - 4 = 11 - 5(2x + 11)[/tex],

to solve for [tex]x[/tex], we have to rearrange the equation to make [tex]x[/tex] its subject.

[tex]10(x + 10) - 4 = 11 - 5(2x + 11)[/tex]

⇒ [tex]10x + 100 - 4 = 11 - 10x -55[/tex]      [expand brackets]

⇒ [tex]10x + 96 = -44 - 10x[/tex]

⇒ [tex]10x + 10x + 96 = -44[/tex]                   [add [tex]10x[/tex] to both sides]

⇒ [tex]20x + 96 = -44[/tex]

⇒ [tex]20x = -44 - 96[/tex]                             [subtract 96 from both sides]

⇒ [tex]20x = -140[/tex]

⇒ [tex]x = \frac{-140}{20}[/tex]                                        [divide both sides by 20]

⇒ [tex]x = \bf-7[/tex]

Answer:

B) x = -7

Step-by-step explanation:

Given equation: [tex]10(x+10)-4=11-5(2x+11)[/tex]

Step 1: Distribute [tex]10[/tex] and [tex]-5[/tex] through the parentheses.

[tex]\implies 10(x)+10(10)-4=11-5(2x)-5(11)[/tex]

[tex]\implies 10x+100-4=11-10x-55[/tex]

Step 2: Simplify (combine like terms).

[tex]\implies 10x+100-4=11-10x-55[/tex]

[tex]\implies 10x+96=-44-10x[/tex]

Step 3: Add [tex]10x[/tex] to both sides.

[tex]\implies 10x+10x+96=-44-10x+10x[/tex]

[tex]\implies 20x+96=-44[/tex]

Step 4: Subtract [tex]96[/tex] from both sides.

[tex]\implies 20x+96-96=-44-96[/tex]

[tex]\implies 20x=-140[/tex]

Step 5: Divide both sides by [tex]20[/tex] to isolate [tex]x[/tex].

[tex]\implies \dfrac{20x}{20}=\dfrac{-140}{20}[/tex]

[tex]\implies \boxed{x=-7}[/tex]

A test consists of section A and section B. Section A has 15 questions and section B has 10 questions. The number of questions in section A is ____% if the questions in the test.

Answers

60%
15+10=25 questions
Multiply 25 X 4 to get 100, what a percentage is
15X4 = 60

Bryan's Boutique sells shirts, skirts, shoes and hats. If Bryan sells 3 types of shirts, 6 types of skirts, 8 types of bracelets and 2 types of hats, how many different outfits can a customer put together if an outfit must include one shirt, one skirt, one bracelet and one hat?

Answers

Using the Fundamental Counting Theorem, it is found that the customer can put together 288 different outfits.

What is the Fundamental Counting Theorem?

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

Bryan sells 3 types of shirts, 6 types of skirts, 8 types of bracelets and 2 types of hats, hence the parameters are given as follows:

[tex]n_1 = 3, n_2 = 6, n_3 = 8, n_4 = 2[/tex]

Hence the number of different outfits is given as follows:

N = 3 x 6 x 8 x 2 = 288

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Enter the correct answer in the box. jackson needs to determine the value of x in this equation. rewrite the expression as a logarithmic quotient that he could enter in his calculator.

Answers

A logarithmic equation exists as an equation that uses the logarithm of an expression containing a variable. The value of the logarithmic equation x = log 2.97/log 1.13.

What is a logarithmic equation?

A logarithmic equation exists as an equation that applies the logarithm of an expression having a variable. To estimate exponential equations, first, see whether you can note both sides of the equation as powers of the same number.

Given: [tex]$1.13^x = 2.97[/tex]

Taking log on both sides, we get

log [tex]$1.13^x[/tex] = log 2.97

x log 1.13 = log 2.97

x = log 2.97/log 1.13

Therefore, the value of logarithmic equation x = log 2.97/log 1.13.

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Michael and Sondra are mixing lemonade. In Michael’s lemonade, the ratio of lemons to water is 1:4. In Sondra’s lemonade, the ratio of lemons to water is 2:6. Several equivalent ratios for each mixture are shown in the ratio tables.

Michael
Lemons
Cups of Water
1
4
3
12
4
16

Sondra
Lemons
Cups of Water
2
6
4
12
6
18

Imagine that you want to compare Michael’s ratio to Sondra’s ratio. Which two ratios in the tables shown have a common denominator you could use to compare?
Three-fourths and StartFraction 6 Over 4 EndFraction
StartFraction 3 Over 12 EndFraction and StartFraction 4 Over 12 EndFraction
StartFraction 16 Over 4 EndFraction and StartFraction 18 Over 6 EndFraction
StartFraction 1 Over 12 EndFraction and StartFraction 4 Over 18 EndFraction

Answers

The two ratios in the tables shown which have a common denominator you could use to compare is; 3/12 and 4/12

Ratio

Machael's ratio:

lemons to water = 1:4

Equivalent ratio

= 3 : 12

= 4 : 16

Sondra's ratio:

lemons to water = 2 : 6

Equivalent ratio

= 4 : 12

= 6 : 18

Therefore, the two ratios in the tables shown which have a common denominator you could use to compare is; StartFraction 3 Over 12 EndFraction and StartFraction 4 Over 12 EndFraction

Complete question

Michael and Sondra are mixing lemonade. In Michael’s lemonade, the ratio of lemons to water is 1:4. In Sondra’s lemonade, the ratio of lemons to water is 2:6. Several equivalent ratios for each mixture are shown in the ratio tables. Imagine that you want to compare Michael’s ratio to Sondra’s ratio. Which two ratios in the tables shown have a common denominator you could use to compare?

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A bowl holds Fraction 3 over 10 cups of oil when it is Fraction 2 over 5 full. Which statement best describes the quotient of 3 over 10 division sign2 over 5?

1. The maximum amount of oil the bowl can hold is Fraction 3 over 4 cup.
2. The amount of oil that can be still poured in the bowl is Fraction 3 over 4 cup.

Answers

The statement that describes the quotient of 3 over 10 division sign2 over 5 is A. The maximum amount of oil the bowl can hold is Fraction 3 over 4 cup.

How to illustrate the fraction?

From the information given, we are told that a bowl holds fraction 3 over 10 cups of oil when it is Fraction 2 over 5 full.

Therefore, the statement that best describes the quotient of 3 over 10 division sign2 over 5 will be that the maximum amount of oil the bowl can hold is fraction 3 over 4 cup.

In conclusion, the correct option is A.

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Find the value of x.
OA. 66
OB. 122
OC. 98
O D. 76
SUBMIT

Answers

Answer:

C) 98

Step-by-step explanation:

Hope this helps! sry  if I'm wrong

The value of x in the given equation 15x + 120 = 5x + 1100 is 98. Option C is correct.

An equation is a combination of numbers, variables, mathematical operations, and functions. It is basically a statement emphasising that the two or more expressions are equal to each other.

The given equation is

15x + 120 = 5x + 1100

Take the like terms together,

15x - 5x = 1100 - 120

10x = 980

x = [tex]\frac{980}{10}[/tex]

x = 98.

Thus, the option C is correct stating that the value of x in the given equation is 98.

Learn more about Equation here:

https://brainly.com/question/28953876

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The complete question is as follows:

Find the value of x in the equation:

15x + 120 = 5x + 1100.

A. 66

B. 122

C. 98

D. 76

SUBMIT.

Approximate the area under the
function between a and b using a
left-hand sum with the given
number of intervals.
f(x) = x² + 2

a = 0
b= 6
6 intervals

Answers

Answer:

  67 square units

Step-by-step explanation:

The area using the left-hand sum is the sum of products of the function value at the left side of the interval and the width of the interval.

Area

The attachment shows a table of the x-value at the left side of each interval, and the corresponding function value there. The interval width is 1 unit in every case, so the desired area is simply the sum of the function values.

The approximate area is 67 square units.

Split up the interval [0, 6] into 6 equally spaced subintervals of length [tex]\Delta x = \frac{6-0}6 = 1[/tex]. So we have the partition

[0, 1] U [1, 2] U [2, 3] U [3, 4] U [4, 5] U [5, 6]

where the left endpoint of the [tex]i[/tex]-th interval is

[tex]\ell_i = i - 1[/tex]

with [tex]i\in\{1,2,3,4,5,6\}[/tex].

The area under [tex]f(x)=x^2+2[/tex] on the interval [0, 6] is then given by the definite integral and approximated by the Riemann sum,

[tex]\displaystyle \int_0^6 f(x) \, dx \approx \sum_{i=1}^6 f(\ell_i) \Delta x \\\\ ~~~~~~~~ = \sum_{i=1}^6 \bigg((i-1)^2 + 2\bigg) \\\\ ~~~~~~~~ = \sum_{i=1}^6 \bigg(i^2 - 2i + 3\bigg) \\\\ ~~~~~~~~ = \frac{6\cdot7\cdot13}6 - 6\cdot7 + 3\cdot6 = \boxed{67}[/tex]

where we use the well-known sums,

[tex]\displaystyle \sum_{i=1}^n 1 = \underbrace{1 + 1 + \cdots + 1}_{n\,\rm times} = n[/tex]

[tex]\displaystyle \sum_{i=1}^n i = 1 + 2 + \cdots + n = \frac{n(n+1)}2[/tex]

[tex]\displaystyle \sum_{i=1}^n i^2 = 1 + 4 + \cdots + n^2 = \frac{n(n+1)(2n+1)}6[/tex]

THE FIRST PERSON TO ANSWER GETS BRAINLIEST!!! A student traveled to a foreign country on an airplane. It took 18 hours to arrive at his destination, and the plane was traveling 900 kilometers per hour. When returning home, the same trip took only 15 hours going at a speed of 1,080 kilometers per hour. If t represents time and s represents the speed of the plane, which statement is true about this relationship?

(answer choices are below)

Answers

Answer:

4

Step-by-step explanation:

the time it takes for a plane to travel a distance varies directly as the speed of the plane because ts=16,200

The number of views on a viral video can be modeled by the function p(t)=590(5)^3t . Write an equivalent function of the form p(t)=ab^t

Answers

Answer:

p(t) = 2950^3t

Step-by-step explanation:

I’m not sure if this is exactly what you wanted or not. Please let me know more info and I’ll write any more answers for this question in the comments. Have a great day!!

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