Your hand feels colder when it transitions from warm to "colder" (room temperature) water.
What happens when you put your hand from warm water to cold water?Your hand feels colder when you move it from the warm water to the "colder" (room temperature) water. Skin surface temperature will decrease in a constant ambient environment as a result of sympathetic nerve activity increasing and blood flow decreasing as a result of cutaneous receptors triggered by ice-water immersion of one hand in the palm skin of the non-immersed opposite hand.
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Light propagates from soda lime glass (n = 1.518) into pyrex glass (n = 1.473). determine the critical angle for this situation.
Light propogates from soda lime glass into pyrex glass of different refractive indices indicating a change in the medium which can be used to find out the critical angle.
The critical angle is the angle of incidence for which the angle of refraction comes out to be 90°. It is related to the refractive indices (Plural of refractive index) by the following relation:
Sini = 1/u, where u is the ratio of refractive index of medium 2 and medium 1
According to the question, Light propogates from soda lime glass (Medium 1, u1=1.518) into pyrex glass(Medium 2, u2=1.473), i.e. from a denser medium to rarer medium. So, the ratio of refractive index becomes u2/u1= 1.473/1.518=0.97
Putting the ratio in the above-mentioned formula,
∴ Sini = 1/0.97
i= 75.9°
Hence, the critical angle(i) for the given situation is 75.9°.
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Give one example of a thermodynamic cycle that does not account for the carnot efficiency.
Thermo-Electrochemical converter (UTEC) is a thermodynamic cycle that does not account for the Carnot Efficiency.
The Carnot cycle is a hypothetical cycle that takes no account of entropy generation. It is assumed that the heat source and heat sink have perfect heat transfer. The working fluid also remains in the same phase, as opposed to the Rankine cycle, in which the fluid changes phase. A practical thermodynamic cycle, such as the Rankine cycle, would achieve at most 50% of the Carnot cycle efficiency under similar heat source and heat sink temperatures.
What is Thermo-Electrochemical converter?In a two-cell structure, a thermo-electrochemical converter converts potential energy difference during hydrogen oxidation and reduction to heat energy.
It employs the Ericsson cycle, which is less efficient than the Carnot cycle. In a closed system, it converts heat to electrical energy. There are no external input or output devices.
This means there will be no mechanical work to be done, as well as no exhaust. As a result, Carnot efficiency is not taken into account in this cycle. Carnot efficiency is accounted for by other options such as turbine and engine.
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The radiation emitted by a heat source reaches its peak wavelength at 6. 69 µm. determine the temperature (in celsius) of the source
the temperature of the source is 159.884°C
How to determine the temperature of the source ?given data:-
λmax=6.69
by using weins law:- Wien’s law, also called Wien’s displacement law, relationship between the temperature of a blackbody (an ideal substance that emits and absorbs all frequencies of light) and the wavelength at which it emits the most light .The wavelength at which maximum radiation is emitted is expressed by the Greek letter “ λ ”.T is the object's temperature in Kelvin, and the constant is 2,897 μm.The higher the object's temperature, the faster the molecules will vibrate and the shorter the wavelength will be.
λmax = constant / temperature(in kelvin) temperature(in kelvin) = constant/λmax temperature(in kelvin) =2897/6.69
temperature(in kelvin)=433.03
temperature(in celsius) = temperature(in kelvin)-273.15
temperature(in celsius)= 159.88
Thus from the above conclusion we can say that at peak wavelength at 6. 69 µm the temperature is 159.884°C.
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If the resistance in a circuit connected to a constant current is halved, how is the voltage in the circuit affected?.
Answer:
The voltage remains constant.
Answer:
The voltage in the circuit remains same. However the current drawn by the circuit will increase.
Explanation:
According to Ohm's Law:
V=IR
If we halved the resistance let:
R'=R/2
then
I'=2I in order to kept the Voltage same. Also the resistance is the opposition to the current. So, if resistance will halved then obviously current will double
So when we put these value in to Ohm's Law the results is:
V'=I'R'
V'=2I(R/2)
V'=IR which is equal to first voltage. Hence,
V'=V
A 1500-w heater is connected to a 120-v line for 2. 0 hours. how much heat energy is produced?
Answer:
10800 kJ
Explanation:
1 watt = 1 Joule /sec
1500 w = 1500 j/sec 2 hours = 7200 sec
1500 j/sec * 7200 sec = 10 800 000 j = 10 800 kJ
The aeroplane then continues at a CONSTANT VELOCITY for a further 800 m before leaving the runway. The length of the runway is 2 000 m. 8 m-s-1 1 .2 1.3 → Define the term vector. Convert 67 m-s¹ to km.h¹. 67 m-s¹ Calculate the: .3.1 3.2 1.3.3 3.4 30 s 800 m Acceleration of the aeroplane during the first 30 seconds Distance travelled by the aeroplane during the first 30 seconds Time taken by the aeroplane to travel the 800 m Length of the runway NOT USED when the aeroplane leaves the runway (2) (1 (4 (4 (3
800 = 0 + [tex]\frac{1}{2}[/tex]a(30)[tex]^{2}[/tex]
800 = 450a
a = 1.77m[tex]s^{-2}[/tex]
Distance = s = ut + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]s = 0+ [tex]\frac{1}{2}[/tex]1.77[tex]t^{2}[/tex]
s = [tex]\frac{1}{2}[/tex]1.77(30)[tex]^{2}[/tex]
s = 796.5m
Time taken = distance / velocityt = 800/8
t = 100 sec
Length of the runway not used = total length of runway-total length covered before leaving runway2000 -800
length = 1200m
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A disk rotates with constant angular acceleration of 5. 45~\text{rad/s}^25. 45 rad/s 2. starting from rest, it turns through 220 rad. how much time elapses while it turns through the 220 radians?
The time elapsed is 8.98 sec when it turns through the 220 radians.
given:
initial angular velocity (ω°) = 0 rad/secangular acceleration (α) =5.45 [tex]rad/sec^{2}[/tex]total angular displacement (Ф) = 220 radusing second equation of motion for rotation
we get ,
[tex]220=0.t + \frac{1}{2}.5.45.t^{2}[/tex]
t^2 =80.98
t=8.98sec
therefore time elapsed is 8.98sec .
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A conducting sphere of radius 5. 0 cm carries a net charge of 7. 5 µc. what is the surface charge density on the sphere?
The surface charge density on the sphere is 0.014C/[tex]m^{2}[/tex].
Given,
r=5.00cm=0.05m, q=7. 5 µc
We know surface charge density σ =q/V=[tex]\frac{7.5*10^{-6} }{\frac{4}{3}\pi 0.05^{3} }[/tex]=0.014C/[tex]m^{2}[/tex].
Surface charge densityIt is always important to know how charge is moving in an electric field. These fields will also build up electric charges. Therefore, estimation of the surface charge density is essential for a number of applications. It is also necessary to calculate the surface charge density of an electric object using its volume and surface area. The amount of electric charge that has collected in a given field is measured by the surface charge density. Using the dimensions provided, it determines the amount of electric charge. Dimensions of the electric body could be in the form of length, area, or volume. In one, two, or three dimensions, according to electromagnetism, surface charge density is a measurement of the amount of electric charge present in a given volume of space.
A conducting sphere of radius 5. 0 cm carries a net charge of 7. 5 µc. what is the surface surface charge density on the sphere?
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What quantities determine the resistance of a piece of material? choose all that apply
The resistance depends upon the length, area and material of the material.Option (a), (b) and (c) is correct.
Quantities that determine the resistance:
The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area. Resistance also depends on the material of the conductor.
A conductor's or circuit element's resistance typically rises as temperature rises. Some conductors exhibit negligible resistance at very low cooling rates. Even after the electromotive force is removed from these substances, known as superconductors, currents still flow through them.The conductance, 1/R, is the reciprocal of resistance and is measured in reciprocal ohm units, or mho.
The complete question is:
What quantities determine the resistance of a piece of material? Choose all that apply.
a)The length of the piece of material
b)The cross-sectional area of the piece of material
c)The type of material
d)The voltage across the material
e)The current flowing through the piece of material
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A 0.20-μf capacitor is connected to a 300-v battery. What potential energy is stored in the capacitor?
A 0.20-μf capacitor is connected to a 300-v battery, the potential energy is stored in the capacitor will be 9 * [tex]10^{-3}[/tex] J
The energy stored in a capacitor is nothing but the electric potential energy and is related to the voltage and charge on the capacitor. If the capacitance of a conductor is C, then it is initially uncharged and it acquires a potential difference V when connected to a battery.
Its two plates hold opposite charges and the separation between them creates an electric field. That's why a capacitor stores energy.
Capacitance = 0.20 * [tex]10^{-6}[/tex]
voltage = 300 V
Potential energy stored in a capacitor = 1/2 *C * [tex]V^{2}[/tex]
= 1/2 * 0.20 * [tex]10^{-6}[/tex] * [tex](300)^{2}[/tex]
= 9000 * [tex]10^{-6}[/tex]
= 9 * [tex]10^{-3}[/tex] J
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Please help! I need this due for homework.
Explanation:
I don't know the exact word which u have to put in the blank spaces.
But Newton's Third Law States:
If a force is exerted there will always be an equal and opposite reactive force.
A 0. 20-kg ball is attached to a vertical spring. the spring constant is 28 n/m. when released from rest, how far does the ball fall before being brought to a momentary stop by the spring?
A 0. 20-kg ball is attached to a vertical spring. The spring constant is 28 n/m. when released from rest, the ball will fall at a distance of x = 0.14 m before being brought to a momentary stop by the spring.
The spring constant is the force needed to stretch or compress a spring, divided by the distance that the spring gets longer or shorter. It's used to determine stability or instability in a spring
Elastic potential energy is Potential energy stored as a result of deformation of an elastic object, such as the stretching of a spring. It is equal to the work done to stretch the spring, which depends upon the spring constant k as well as the distance stretched.
When ball is released from rest with spring , it will loose some potential energy . Hence , loss in potential energy of the ball = gain in potential energy of spring
m*g*x = 1/2 * k * [tex]x^{2}[/tex]
0.20 * 9.8 * x = 1/2 * 28 * [tex]x^{2}[/tex]
x = (2 * 0.20 * 9.8) / 28
x = 0.14 m
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450n 360n 710n 1400n 230n a block is placed in oscillation on a frictionless horizontal surface attached to a spring that is also attached to a wall. If, when stretched away from equilibrium by 15cm and released, it oscillates with a period of 0. 25s, and if the mass of the block is 15kg, what force was required to stretch the spring by the initial 15cm?.
Answer:
m = 15, P = .25, x = .15
F = -K x for spring
ω = (K/m)^1/2
ω^2 = K / m
K = m ω^2 = m (2 π f)^2 = m 4 π^2 / P^2
K = 4 π^2 m / P^2
F = K x = x * 4 π^2 m / P^2
F = .15 * 4 * π^2 * 15 / .25^2
F = 1420 N
Find the distance traveled by a particle with position (x, y) as t varies in the given time interval. x = 2 sin2(t), y = 2 cos2(t), 0 ≤ t ≤ 4
The distance traveled by the particle at the given time interval is 0.28 m.
Position of the particle at time, t = 0
The position of the particle at the given time is calculated as follows;
x = 2 sin2(t)
y = 2 cos2(t)
x(0) = 2 sin2(0) = 0
y(0) = 2 cos2(0) = 2(1) = 2
Position of the particle at time, t = 4x = 2 sin2(t)
y = 2 cos2(t)
x(4) = 2 sin2(4) = 0.28
y(4) = 2 cos2(4) = 2(1) = 1.98
Distance traveled by the particle at the given time intervald = √[(x₄ - x₀)² + (y₄ - y₀)²]
d = √[(0.28 - 0)² + (1.98 - 2)²]
d = 0.28 m
Thus, the distance traveled by the particle at the given time interval is 0.28 m.
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Officials want to reduce the possibility of oil leaks into bodies of freshwater drinking sources. therefore, the government insists that oil refineries undergo monthly inspections. for what reason would the government regulate monthly inspections at oil refineries? save the refinery money increase domestic oil production protect the public from pollution encourage foreign oil imports to drive down prices
Answer:
protect public from pollution
Explanation: got it right
(Repost) I need help with this physics question. Thanks in advance! Answer ASAP.
The time taken for the tiny saliva to travel is 0.55 second.
The horizontal distance traveled at speed of 4 m/s is 2.2 m.
The horizontal distance traveled at speed of 20 m/s is 11 m.
Time of motion of the tiny saliva
The time taken for the tiny saliva to travel is calculated as follows;
h = vt + ¹/₂gt²
where;
v is initial vertical velocity = 0g is the acceleration due to gravityh = 0 + ¹/₂gt²
h = ¹/₂gt²
2h = gt²
t² = 2h/g
t = √(2h/g)
Substitute the given parameters and solve for time of motion;
t = √(2 x 1.5 / 10)
t = 0.55 second
Horizontal distance traveled at speed of 4 m/sX = Vx(t)
X = (4 m/s)(0.55)
X = 2.2 m
Horizontal distance traveled at speed of 20 m/sX = (20)(0.55)
X = 11 m
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You start walking from a point on a circular field of radius 0.5 km and 1 hour later
you are at the same point. What is your average speed for the whole journey?
Answer:
1). average velocity= displacement/time
= here displacement is zero
= 0/1
= 0 m/s
2). average speed= total distance/time
=2πr/1
=(2×22/7×5/10)/1
22/7
3.14 km/h
hope it helps you
please mark brainliest
Explanation:
Answer:
[tex]\sf \fbox{speed = 3.14 kmph}[/tex]
Explanation:
Given:
Radius of circular field (r) = 0.5 Km
Time taken to complete one round of field (t)= 1 hour
To find:
Average speed for the whole journey=?
Solution:
To find the average speed we will have to find the actual distance covered in given time, & the actual distance covered would be equal to the
[tex] \sf \: perimeter \: of \: circular \: field = 2 \pi r \\ \sf 2 \pi r = 2 \times 3.14 \times 0.5 = 3.14 \: km[/tex]
Distance covered in 1 hour is 3.14 km,
[tex]\small \sf Average \: speed = \frac{Distance}{Time} = \frac{3.14}{1} \\ \small \sf \fbox{speed = 3.14 kmph}[/tex]
[tex] \small\sf \: Thanks \: for \: joining \: brainly \: community! [/tex]
Two objects of mass 3 kg and 2 kg are thrown with velocities 2 ms-1 and 3 ms-1 , respectively. Calculate the momentum of both. Which has a greater momentum?
Answer:
They have the SAME momentum ....see below
Explanation:
Momentum = m v
3 3kg * 2 m/s = 6 kg-m/s
2 2kg * 3 m/s = 6 kg - m/s
A boy on board a cruise ship drops a 30. 0 gm marble into the ocean. If the resistive force proportionality constant is 0. 500 kg/s, what is the terminal speed of the marble in m/s?.
The terminal speed of the marble is 0.588 m/s.
Given:
We know that,
F = mg ......(1)
where,
F = force
m = mass
g = acceleration due to gravity
Also,
v = F/k ......(2)
where,
v = terminal speed
k = proportionality constant
Substituting the value of F from equation (1) in equation (2)
v = mg/k .......(3)
Given,
m = 30 g = 0.030 kg
k = 0.500 kg/s
g = 9.8 m/s²
To find,
v =?
Put the values in equation (3)
v = mg/k
v = 0.03(9.8)/ 0.500
= 0.294/0.500
= 0.588 m/s
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Which of the following describe advantages of using radio waves over other electromagnetic waves to transmit information to Earth? Select ALL that apply.
A
Radio waves travel faster.
B
Radio waves take less energy to produce.
C
Radio waves transmit more types of information.
D
Radio waves have a lower frequency, which makes them safer for humans.
E
Radio waves have higher energy, which makes their signal easier to capture.
The correct options are:
D
"Radio waves have a lower frequency, which makes them safer for humans."
B
"Radio waves take less energy to produce."
Why do we radio waves over other electromagnetic waves to transmit information to Earth?
Radio waves are electromagnetic waves with frequencies on the range from 10 KHz to 10 THz.
Now, remember that all electromagnetic waves have the same speed, which is the speed of light, and the energy of a wave is proportional to its frequency.
Particularly, we can see that radio waves have small frequencies (smaller than infrared light) so these waves carry very little energy.
With that in mind, the correct options are.
D
"Radio waves have a lower frequency, which makes them safer for humans."
B
"Radio waves take less energy to produce."
These are the two main reasons of why we use radio waves.
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Please Help!!!
Which statement best describes the types of bonds shown in the diagram?
an ionic bond; a hydrogen ion is bonding with a chlorine atom
a covalent bond; the hydrogen atom’s single electron is being shared with the chlorine atom
a covalent bond; the hydrogen atom’s two electrons are being shared with the chlorine atom
an ionic bond; the hydrogen chloride molecule has an electrical charge
Answer: B
Explanation:
The statement that best describes the types of bonds shown in the diagram is a covalent bond; the hydrogen atom’s single electron is being shared with the chlorine atom, therefore the correct answer is the option B
What is a covalent bond?When two similar or dissimilar atoms form bonds with each other by sharing their valence electron the bond is known as the covalent bond.
The ionic bond is the result of the transfer of the electrons
Ionic bonds are formed between the pair of one electronegative atom and an electropositive atom.
As shown in the diagram there is sharing of the electrons between the hydrogen and the chlorine atom, and we know that covalent bonds are formed by the sharing of the electrons
Since the diagram's covalent bonds are best described by the statement that the hydrogen atom's single electron is shared with the chlorine atom, option B is the right response.
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Among merge sort and quick sort, which algorithm takes more spaces? what strategy is used by the other algorithm to use less space and run slightly faster in average case?
Merge sort requires more space than quick sort. Bogo sort is used by the other algorithm to use less space and run slightly faster in average case.
To find the answer, we need to know more about the Maxillary space.
What is Maxillary space?Quicksort consumes less space and has better cache locality than merge sort, which uses more space. An in-place sorting algorithm is quick sort. No additional storage space is required for sorting when it is done in-place. Because Join Sort does not exist, Quick Sort has the advantage of space since Merge Sort needs a temporary array to merge the sorted arrays.Thus, we can conclude that, merge sort requires more space than quick sort. Bogo sort is used by the other algorithm to use less space and run slightly faster in average case.
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The fixed assets turnover ratio of gd products is 13. 6 and that of its competitor, ap goods inc. , is 6. 0. what does this financial data primarily imply?
The correct answer is GD Products collects receivables more quickly than AP Goods.
Analysts typically utilize the fixed asset turnover ratio (FAT) to gauge operating performance. This efficiency ratio assesses a company's capacity to generate net sales from its fixed-asset investments, specifically property, plant, and equipment (PP&E). It compares net sales (income statement) to fixed assets (balance sheet) (PP&E). Utilized as a net of accumulated depreciation is the fixed asset balance. A greater fixed asset turnover ratio shows that a business has utilized fixed asset investments to drive sales effectively. A greater ratio suggests that management is making better use of its fixed assets. No information can be gleaned from a high FAT ratio about a company's capacity to produce reliable earnings or cash flows.
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A clock on a moving spacecraft runs 1s slower per day relative to an identical clock on earth. What is the relative speed of the spacecraft?
The craft is moving at a speed of v = 0.024c or around 7 million metres per second or 16 million miles per hour.
The time dilation factor is equal to 3600/3599 if we only want 3599 seconds of the craft's time to pass for every hour (3600 seconds) of Earth time. However, there is a connection as well.
γ = [tex]\frac{3600}{3599}[/tex] = Dilation factor
Also, γ = 1/ √[tex]1-v^{2}[/tex]/[tex]c^{2}[/tex]
which we can solve algebrically to yield,
[tex]\frac{v}{c}[/tex] = √1-1/γ[tex]^{2}[/tex]
we get,
[tex]\frac{v}{c}[/tex] = 0.024
v= 0.024c
Accordingly, the craft is moving at a speed of v = 0.024c, or around 7 million metres per second or 16 million miles per hour.
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When the atmosphere becomes loaded with particles, only the _____ wavelengths are able to penetrate the atmosphere.
Visible light are able to penetrate the atmosphere
What is Wavelength?A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is often defined in wireless systems in metres (m), centimetres (cm), or millimetres (mm).
The electromagnetic spectrum is made up of a variety of electromagnetic radiations, including radio waves, microwaves, infrared light, visible light, ultraviolet light, X-rays, and gamma rays. Because the earth's atmosphere blocks off the majority of the electromagnetic spectrum's wavelengths, most electromagnetic energy from space cannot reach the planet's surface.
. A portion of the electromagnetic spectrum that humans can see with our eyes is the visible light or spectrum. The electromagnetic spectrum's band that can most easily reach Earth's surface is also this one.
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A wave of wavelength 1.2m travels 11.2m to a wall in 2s. what's the frequency of the wave
Answer: f = 4.67 Hz
Explanation:
We can approximate the wave as a traveling wave, therefore the speed of the wave is constant
v = d / t
the total distance remember, in going to the wall and back is
d = 2 11.2 = 22.4 me
we substitute
v = 22.4 / 4.0
v = 5.6 m / s
now we can use the relationship between the speed of the wave, its wavelength and u frequency
v =λ f
f = v /λ
f = 5.6 / 1.2
f = 4.67 Hz
If the current in an inductor is doubled, by what factor is the stored energy multiplied?
a. 4
b. 1/4
c. 2
d. 1/2
e. 1
_______________
[tex]I_2=2I_1[/tex]
[tex]L=\text{const}[/tex]
_______________
[tex]\displaystyle \frac{W_2}{W_1}\; - \;?[/tex]
_______________
[tex]\displaystyle \boldsymbol{\frac{W_2}{W_1}}=\frac{\dfrac{LI_2^2}{2} }{\dfrac{LI_1^2}{2} } =\frac{I_2^2}{I_1^2} =\bigg(\frac{I_2}{I_1} \bigg)^2=\bigg(\frac{2I_1}{I_1} \bigg)^2=2^2=\boldsymbol{4}[/tex]
What is the volume of a solution, in milliliters, that contains 1. 5 g lino3 and has a concentration of 0. 40 m?
The volume of a solution, in milliliters, that contains 1. 5 g lino3 and has a concentration of 0. 40 m will be 54.35 m L.
Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution.
Molarity = n / V
where
n = number of moles
V = volume of solution in l
Molar mass of [tex]LiNO_{3}[/tex] = M of Li + M of N + 3 * M of O
= 7 + 14 + (3*16)
= 69 g/ mole
since , M = n / V
n = m / molar mass of [tex]LiNO_{3}[/tex]
substituting the value of n
Molarity = (m / molar mass of [tex]LiNO_{3}[/tex] ) / V
V = m / molar mass of [tex]LiNO_{3}[/tex] * Molarity
= 1.5 / 69 * 0.40
= 54.35 mL
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The cost of operating an electrical appliance is based upon its
Aage.
Bease of use.
Cwattage and time used.
D original purchase price.
Answer:
wattage and time used
Explanation:
Look
If a electrical appliance has more power or wattage it will use more energy and cost more
If a electrical appliance is used for more time the cost is more
Hence Option C is correct
A 0. 22 kg clay target is fired at an angle of 35° to the horizontal. it reaches a maximum height of 4. 6 m. what is its initial speed when it is launched?
A 0. 22 kg clay target is fired at an angle of 35° to the horizontal. It reaches a maximum height of 4. 6 m. Its initial speed when it is launched will be u = 16.66 m/s
Projectile motion is the motion of an object thrown (projected) into the air. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.
The object's maximum height is the highest vertical position along its trajectory. The horizontal displacement of the projectile is called the range of the projectile. The range of the projectile depends on the object's initial velocity.
h (max) = [tex]u^{2}[/tex] [tex]sin^{2}[/tex](theta) / 2g
given
theta = 35°
Maximum height = 4. 6 m.
u = ?
4.6 = [tex]u^{2}[/tex] * [tex]sin^{2}[/tex](35) / 2* 9.8
u = 16.66 m/s
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