If the two lines below are perpendicular and the slope of the red line is -
what is the slope of the green line?
O A.
A.
OB. -3
314
O D.
D. -
-10
10
15

Answer:

Euler's Formula = F+V=E+2

F=9

V=14

So, 9+14=E+2

23=E+2

23-2=E

21=E

Hence, E (edges) = 21

Step-by-step explanation:

The system that can help to model this are

We have the following equation. Remember that a good understanding of the question is what would help us to write the equation

The condition says:

The square of first number is equal to the sum of the second number and 16:

First number = x. Square of x = x²

second number = y + 16

For the second

The difference of 4 times the second number and 1 is equal to the first number multiplied by 7:

second number is y

4*y - 1= x*7

= 4y - 1 = 7x

Hence we would have the following as our equations

x² = y + 16

4y - 1 = 7x

The solution to the equation when graphed = 5, 9

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Answer:2

Step-by-step explanation:

Answer:

(3, -3 8/9)

Step-by-step explanation:

Use a slope calculation or a graph to find the slope of the line.

m = (y-y)/(x-x)

m = (-3- -5)/(7- -2)

m = 2/9

Then write the equation of the line. I used point-slope form. (You could use y=mx+b, slope-intercept form, but you'd have to first calculate b as well)

Point-slope form:

y -Y = m(x-X)

y - -3 = 2/9(x- 7)

y + 3 = 2/9(x - 7)

We know the x-coordinate of the point we're looking for is 3. Fill that in as well and calculate the y that goes with it.

y + 3 = 2/9(3-7)

y+3=2/9(-4)

y = -8/9 - 3

y = -3 8/9

In decimal form this is -3.8888repeating

see image.

The point at x=3 on the line between M(7,-3) and N(-2,-5) is (3, -3 8/9).

7.2 + c = 19

c = 19 - 7.2

c = 11.8

Answer:

Your answer is 5.

Step-by-step explanation:

7.2 + c = 19

or, 14 + c = 19

or, c = 19 - 14

or, c = 5       ans.

Hope its helpful :-)

Answer:

Option 2

Step-by-step explanation:

Since theta is in the third quadrant, the sine of theta is negative.

By the Pythagorean identity,

[tex]\sin \theta=-\frac{\sqrt{105}}{13}[/tex]

So, using the double angle formula for sine, we get that

[tex]\sin 2\theta=\frac{16\sqrt{105}}{169}[/tex]

The side length of the original field is 19 feet.

What is square?

Suppose the original square is x feet wide. Since its the length and width are the same,

So, length of side of enlarged field = x+5

Area of new enlarged field =  side²  = ( x + 5 )²

So, the enlarged shape would be = ( x + 5 ) ( x + 5)

  Then ,  ( x + 5 ) ( x + 5) = 576

               ( x + 5 )²= 576

                x + 5 = √576

               x + 5  = 24

                 x = 24 - 5 ⇒ 19

Hence, The side length of the original field is 19 feet.

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Answer:

r = 3.75

Step-by-step explanation:

C = 2(pi)r (write equation)

r = c / 2pi (rearrange for r)

r = 23.55 / 2(3.14) (plug in variables)

r = 23.55 / 6.28 (simplify)

r = 3.75 (solve)

The smallest positive integer having exactly 5 different positive integer divisors is 60.

To find the smallest positive integer having exactly 5 different positive integer divisors:

Therefore, the smallest positive integer having exactly 5 different positive integer divisors is 60.

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The Option A is correct that tells us that the There is a common ratio between the terms which represent the Characteristics of the G.P. Series.

According to the statement

we have to explain the characteristics of the Geometric Sequence.

So, For this purpose

We know that the

A geometric progression, also known as a geometric sequence, is a sequence of non-zero numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio.

From its definition it is clear that the

There is a common ratio between the terms.

And this point represent the characteristics of the Geometric Sequence not all other points.

Now, The option A is the correct rather than the other options.

So, The Option A is correct that tells us that the There is a common ratio between the terms which represent the Characteristics of the G.P. Series.

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Which statements describe characteristics of a geometric sequence? Check all that apply.

a.There is a common difference between terms

b.Each term is multiplied by the same number to arrive at the next term.

c.The sequence increases or decreases in a linear pattern

d.There is a common ratio between terms

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The ratio is different from the other three is StartFraction 6 Over 10 EndFraction; 6/10.

A ratio is a number representing a comparison between two named things.

StartFraction 2 Over 5 EndFraction = StartFraction 6 Over 10 EndFraction = StartFraction 8 Over 20 EndFraction = StartFraction 12 Over 30 EndFraction

2/5 = 6/10 = 8/20 = 12/30

2/5 = 0.4

6/10 = 0.6

8/20 = 0.4

12/30 = 0.4

Therefore, the ratio is different from the other three is StartFraction 6 Over 10 EndFraction; 6/10

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Answer:

a) $20,771.76

b) $20,817.67

c) $20,484.80

d) $20,864.52

Step-by-step explanation:

Compound Interest Formula

[tex]\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}[/tex]

where:

Part (a): semiannually

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000\left(1+\frac{0.055}{2}\right)^{2 \times 6}[/tex]

[tex]\implies \sf A=15000\left(1.0275}{2}\right)^{12}[/tex]

[tex]\implies \sf A=20771.76[/tex]

Part (b): quarterly

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000\left(1+\frac{0.055}{4}\right)^{4 \times 6}[/tex]

[tex]\implies \sf A=15000\left(1.01375}\right)^{24}[/tex]

[tex]\implies \sf A=20817.67[/tex]

Part (c): monthly

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000\left(1+\frac{0.055}{12}\right)^{12 \times 6}[/tex]

[tex]\implies \sf A=15000\left(1+\frac{0.055}{12}\right)^{72}[/tex]

[tex]\implies \sf A=20484.80[/tex]

Continuous Compounding Formula

[tex]\large \text{$ \sf A=Pe^{rt} $}[/tex]

where:

Part (d): continuous

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000e^{0.055 \times 6}[/tex]

[tex]\implies \sf A=20864.52[/tex]

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Using proportions, it is found that the radian measure of the central angle is given as follows:

[tex]\frac{4\pi}{3}[/tex] radians.

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

The entire circumference is equivalent to a central angle of [tex]2\pi[/tex] radians. Hence the radian measure of the central angle considering two-thirds of the circumference is given as follows:

[tex]\frac{2}{3} \times 2\pi = \frac{4\pi}{3}[/tex]

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Answer:

Step-by-step explanation:

c edge

The expression which shows how the distributive property of the can be used to multiply 8×29 as in the task content is; 8(20 + 9).

It follows from the task content that the given product to be multiplied is; 8×29.

Consequently, it follows from convention that the distributive property of multiplication allows that the multiplication in this case can be rewritten as follows;

8×29 = 8 (20 + 9)

Hence, we have; (8×20) + (8×9).

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Answer: someone already answered this check the link out

Step-by-step explanation. https://brainly.com/question/11711784

The equation of the line is b = am + c

Linear equations are equations that have a constant slope, average rate of change or gradients

The point is given as

(x, y) = (a, b)

The slope is given as

Slope = m

A linear equation is represented as

y = mx + c

Where me represents the slope

Substitute (x, y) = (a, b)

b = am + c

Hence, the equation of the line is b = am + c

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The length of the side of the square is [tex]44 cm[/tex].

Determine the length of the side of the square:

Radius of circle[tex]=28.[/tex]

Circumference[tex]=2\pi r[/tex]

                        [tex]2\pi (28)=176[/tex]

Side of the square[tex]=\frac{176}{4} =44cm.[/tex]

The length of the side of the square is [tex]44 cm[/tex].

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Answer:

(2)

Step-by-step explanation:

by substituting the values of x into f(x) and evaluating

f(0) = 3(0) - 5 = 0 - 5 = - 5 ≠ 0

f(3) = 3(3) - 5 = 9 - 5 = 4 ← True

f(4) = 3(4) - 5 = 12 - 5 = 7 ≠ 3

f(5) = 3(5) - 5 = 15 - 5 = 10 ≠ 0

Hence, statement 2 is true for the equation f(x) = 3x-5

The definition of an equation in algebra is a mathematical statement that proves two mathematical expressions are equal.

Types of Equations:

 Linear Equation: More than one variable may be present in a linear equation. An equation is said to be linear if the maximum power of the variable is consistently 1.

  Quadratic Equation: This equation is of second order. At least one of the variables in a quadratic equation needs to be raised to exponent 2.

  Cubic Equation: A third-order equation is this one. At least one of the variables in cubic equations needs to be raised to exponent 3.

  Rational Equation: A fractional equation having a variable in the numerator, denominator, or both is referred to as a rational equation.

Substituting the values of x into f(x) and evaluating

f(x) = 3x - 5

put x = 0

f(0) = 3(0) - 5

= 0 - 5 = - 5

put x = 3

f(3) = 3(3) - 5

= 9 - 5

= 4

put x = 4

f(4) = 3(4) - 5

= 12 - 5

= 7

put x = 5

f(5) = 3(5) - 5

= 15 - 5

= 10

hence statement 2 is true.

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The solution for the initial value problem is [tex]y_{g} = e^{-2x} (-12cos(x) + 5sin(x)) + 7e^{-4x}[/tex]

Given,

y" + 4y' + 5y = 35[tex]e^{-4x}[/tex]

y(0) = -5

y'(0) = 1

Solve this homogenous equation to get [tex]y_{h}[/tex]

According to differential operator theorem,

[tex]y_{h}[/tex] = [tex]e^{ax}[/tex]( A cos (bx) + B sin (bx)), where A and B are constants.

Therefore,

y" + 4y' + 5y = 0

([tex]D^{2}[/tex] + 4D + 5)y = 0

D = -2± i    

[tex]y_{h} = e^{-2x} ( A cos (x) + B sin (x))[/tex]

Now, solve for [tex]y_{p}[/tex]

A function of the kind [tex]ce^{-4x}[/tex] is the function on the right, we are trying a solution of the form [tex]y_{p} =ce^{-4x}[/tex], here c is a constant.

[tex]y_{p} " + 4y_{p} ' + 5y_{p} = 35e^{-4x} \\=16ce^{-4x} -16ce^{-4x} +5ce^{-4x} = 35e^{-4x} \\= 5ce^{-4x} =35e^{-4x} \\c=\frac{35}{5} =7\\y_{p} =7e^{-4x}[/tex]

Then the general solution will be like:

[tex]y_{g} =y_{h} +y_{p} \\[/tex]

    = [tex]e^{-2x} (Acos(x)+Bsin(x))+7e^{-4x}[/tex]

[tex]y_{g}(0)=-5=A+7=-12\\y_{g} '(0)=e^{-2x} (-Asin(x)+Bcos(x))-2e^{-2x} (Acos(x)+Bsin(x))-28e^{-4x} \\y'_{g} (0)=1=B-2A-28\\[/tex]

       B = 1 - 24 + 28 = 5

Then the solution for the given initial value problem is

[tex]y_{g} =e^{-2x} (-12cos(x)+5sin(x))+7e^{-4x}[/tex]

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Answer:

22

Step-by-step explanation:

| 2^3 - 4*3^2 |  - 4 = | 8 - 36| - 4 =  28-4 = 24

See attachment for the axis of symmetry and maximum point.

To plot the axis of symmetry:

Therefore, the maximum value occurs at the vertex, given by (h,k)=(-2,8).

So, see attachment for the axis of symmetry and maximum point.

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The trigonometry illustrates that the four angles whose cosine is the same as cos pi/3 will be 7∏/3, 13∏/3, 19∏/3, and 31∏/3

From the information, given cos (x), the value that is similar to cos x will be the sum of the angle and multiple of 360.

Therefore, for the angle cos(∏/3), the angles that are similar to this angle will be expressed as Cos(2∏n + ∏/3) where n is any positive integer.

Then the other four angles will be 7∏/3, 13∏/3, 19∏/3, and 31∏/3. Also, the statement that all angles that have the same cosine will have the same sine is false. The sine of an angle is simply equal to the cosine of the complementary angle.

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Answer:

I = (PTR)/100

1450=(5000*1*R)/100

1450*100=5000R

145000/50000=R

29=R

Step-by-step explanation:

We know,

[tex] S.I. = \rm\cfrac{P*R*T}{100}[/tex]

Given,

Principal P = 5000

Rate R = R(Assume)

Time T = 1

Interest = 1450

Plug:

[tex]1450 = \frac{5000 \times r \times 1}{100} [/tex]

Solve:

[tex]1450 \times 100 = 5000 \times r[/tex]

[tex]145000 \div 5000 = r[/tex]

[tex]r \: = \: 29 \%[/tex]

Rate = 29

Therefore,the rate of Interest is 29%.

Engine is currently in first gear as mentioned in question

Drive shaft speed be x

Answer:

700 rpm

Step-by-step explanation:

A driveshaft is a shaft that transmits mechanical power.

Its speed is measured in rpm (revolutions per minute).

Engine speed

Given engine speed:

Therefore, the drive-shaft speeds in the different gears are:

First gear

Drive-shaft speed = 2100 ÷ 3 = 700 rpm

Second gear

Drive-shaft speed = 2100 ÷ 1.6 = 1312.5 rpm

Third gear

Drive-shaft speed = 2100 rpm

Answer:

(3, ∝) or all values of x greater than +3

Step-by-step explanation:

The inequality is [tex]5.5x + 15.5 > 32[/tex]

Subtracting 15.5 from both sides yields

5.5x > 32 - 15.5 or 5.5x > 16.5

Dividing by 5.5 on both sides yields

x > 16.5/5.5 or x > 3

This means the inequality is valid for all values of x > 3

The solution set is the interval (3, ∝ )

The total number of ways by words are formed is 35 ways.

According to the statement

We have given that the 5 letters and we have to make word from them and the letters are repeated as equal to letters in given words.

And we have to find the possible ways.

So, The given words are:

TEXAS and MEXICO

Here X = 2 and E = 2 and all other words are one time used words.

We can find possible ways by use of combination and permutation.

So,

Total number of ways = [tex]3C_{1} ^{5} + 2C_{2} ^{5}[/tex]

here 3 because three letters are not repeatable and 2 letters are repeated for 2 times.

So,

Total number of ways = [tex]3C_{1} ^{5} + 2C_{2} ^{5}[/tex]

Total number of ways = [tex]3(\frac{5!}{1!} ) + 2(\frac{5!}{2!*3!} )[/tex]

Total number of ways = [tex]3(5) + 2(10)[/tex]

Total number of ways = 15 + 20

Total number of ways = 35.

So, The total number of ways by letters are formed is 35 ways.

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The answer of your question is option (B)

Based on the percentage discount that one gets from the promotion using a jar, the average discount amount the shoe store can expect to give each customer is $15.

The average discount in percentages will be:

= (3/6 x 10%) + (2/6 x 30%) + (1/6 x 60%)

= 5% + 10% + 10%

= 25%

The average discount in cash amounts is:

= 25% x 60

= $15

In conclusion, the average discount amount that the store can expect to give each customer in dollars is $15.

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Answer:

C.  Cube 2.

Step-by-step explanation:

Using PEMDAS  the first operation to be done is E (Exponent)  which is

2³.

Solving a logarithmic equation, it is found that the San Francisco earthquake was 24.71 times more intense than the Columbian earthquake.

As given in the problem, the intensities of the earthquakes are given by logarithms of base 10. Then, supposing that the intensities are R1 and R2, with R1 greater than R2, the ratio of the intensities, that is, how much intense R1 is than R2, is given as follows:

[tex]r = 10^{\frac{R_1}{R_2}}[/tex]

For this problem, the intensities are given as follows:

Then, the ratio of the intensities is given as follows:

[tex]r = 10^{\frac{7.8}{5.6}} = 24.71[/tex]

The San Francisco earthquake was 24.71 times more intense than the Columbian earthquake.

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