I need help cancelling units. please help

I Need Help Cancelling Units. Please Help

Answers

Answer 1

Hello and Good Morning/Afternoon:

Let's take this problem step by step:

Let's write out the equation we would hypothetically use to convert 410 kilometers to meters:

  [tex]410 kilometers * \frac{1000 meters}{1 kilometers}[/tex]

Let's see if there are any errors:

there are 1000 meters in 1 kilometerwhen converting kilometer --> meter

              ⇒ we want to get rid of the kilometer symbol

                   ⇒ which is done in this problem

                        [tex]410 kilometers * \frac{1000 meters}{1 kilometers}=\frac{410 kilometers}{1 kilometers}*1000 meters = 410000meters[/tex]

Thus the answer is true

Answer: True

Hope that helps!


Related Questions

If f(x)=x²-3x - 4 and g(x) = x² + x, what is (f + g)(x)?

Answers

Answer: (f+g)(x)=2(x-2)(x+1).

Step-by-step explanation:

[tex]f(x)=x^2-3x-4\ \ \ \ \ g(x)=x^2+x\\(f+g)(x)=(x^2-3x-4)+(x^2+x)\\(f+g)(x)=x^2-3x-4+x^2+x\\(f+g)(x)=2x^2-2x-4\\(f+g)(x)=2*(x^2-x-2)\\(f+g)(x)=2*(x^2-2x+x-2)\\(f+g)(x)=2*(x*(x-2)+(x-2))\\(f+g)(x)=2*(x-2)*(x+1).[/tex]

Quick algebra 1 question for 10 points!

Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!

Answers

[tex]y = 2x {}^{2} - 4x - 16 \\ \delta = b {}^{2} - 4ac \\ \delta = ( - 4) {}^{2} - 4(2)( - 16) \\ \delta = 16 + 128 \\ \delta = 144 > 0 [/tex]

[tex]x = \frac{ - b + \sqrt{ \delta} }{2a} = \frac{4 + 12}{2 \times 2} = \frac{16}{4} = 4[/tex]

[tex]x = \frac{ - b - \sqrt{ \delta} }{2a} = \frac{4 - 12}{2 \times 2} \frac{ - 8}{4} = - 2[/tex]

[tex]x = 4 \: \: \: \: \: or \: \: \: \: x = - 2 \\ (x - 4) = 0 \: \: \: \: \: or \: \: \: \: \: (x + 2) = 0[/tex]

[tex]f(x) = \alpha (x - 4)(x + 2) \\ f(x) = \alpha x { }^{2} + 2 \alpha x - 4 \alpha x - 8 \alpha \\ f(x) = \alpha x {}^{2} - 2 \alpha x - 8 \alpha \\ by \: comparison \\ \alpha = 2[/tex]Factors are:

1) 2

2) x - 4

3) x + 2

Which property is shown in the following statement?

(46 + 17) + 3 = 46 + (17 + 3)

associative property of addition
commutative property of addition
identity property of addition

Answers

Answer:

Associative property of addition.

Step-by-step explanation:

The location of the parentheses makes no difference to the sum of these numbers.

The property shown in the statement "(46 + 17) + 3 = 46 + (17 + 3)" is the associative property of addition.

The associative property of addition states that when adding three or more numbers, the grouping of the numbers does not affect the sum

In the given statement, we have three numbers being added: 46, 17, and 3. The statement shows that the addition is grouped differently on each side of the equation, but the result is the same.

On the left side, we have (46 + 17) + 3.

This means we first add 46 and 17, which equals 63. Then we add 3 to the sum, resulting in 66.

On the right side, we have 46 + (17 + 3). Here, we first add 17 and 3, which equals 20. Then we add 46 to the sum, also resulting in 66.

As we can see, no matter how we group the numbers being added, the final sum is the same. This demonstrates the associative property of addition.

Therefore, the property shown in the given statement is the associative property of addition.

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Find the value of z.

Answers

Applying the angle of intersecting chords theorem, the value of z is: D. 100.

What is the Angle of Intersecting Chords Theorem?

According to the angle of intersecting chords theorem, in a circle like the one shown in the image above, where two chords intersect to form vertical angles, the theorem states that the angle formed equals half of the sum of the measures of the arcs intercepted by the angles.

Applying the angle of intersecting chords theorem, let's find x first:

73 = 1/2(96 + x)

Multiply both sides by 2

2 × (73) = 1/2(96 + x) × 2

146 = 96 + x

Subtract both sides by 96

146 - 96 = 96 + x - 96

50 = x

x = 50°

Therefore:

x + z + 96 + 114 = 360° [full circle measure]

Plug in the value of x

50 + z + 96 + 114 = 360

z + 260 = 360

Subtract both sides by 260

z + 260 - 260 = 360 - 260

z = 100°

The answer is: D. 100°.

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In 4 weeks, Mark earns an average of $400 per
week. If, after working another 2 weeks at a
constalat salary, his average carnings per week
are $500, how much did he earn in the last 3
weeks?

Answers

4x = 400 —> x = 100 weeks 1-4
400 + 2y = 500
2y = 100
y = 50 weeks 5-6

Last three weeks
Week 4 100
Week 5 50
Week 6 50

He earned about $200

Practice another write the function in terms of unit step functions. find the laplace transform of the given function. f(t) = t, 0 ≤ t < 4 0, t ≥ 4

Answers

Using the Laplace transform to solve the given integral equation  f(t) = t, 0 ≤ t < 4 0, t ≥ 4 is [tex]\frac{4(1-2e^-5s)/}{s}[/tex]

explanation is given in the image below:

Laplace remodel is an crucial remodel approach that's particularly beneficial in fixing linear regular equations. It unearths very wide programs in var- areas of physics, electrical engineering, manipulate, optics, mathematics and sign processing.

The Laplace transform technique, the function inside the time domain is transformed to a Laplace feature within the frequency area. This Laplace function could be inside the shape of an algebraic equation and it may be solved without difficulty.

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If takes 3/4 hour to paint 12by 12 room how long does it take to paint 15by 16 room

Answers

An hour and 15 minutes I believe which would be 1 and 1/4

Help for a brianlest at show your work

Answers

X^2-2(x-y)-z^3
First we substitute the variables for their known values and get
2^2-2(2-(-2))-(-3)^3
Simplify
4 + (-4+4) -(-27)
4+-27= -23
That’s your answer

To conduct a test of hypothesis with a small sample, we make an assumption that?

Answers

To conduct a test of hypothesis with a small sample, we make an assumption that the population is normally distributed .

What is normal distribution?

A probability distribution that is symmetric about the mean is the normal distribution, sometimes referred to as the Gaussian distribution. It demonstrates that data that are close to the mean occur more frequently than data that are far from the mean.

The normal distribution appears as a "bell curve" on a graph.

A probability bell curve is more properly described as the normal distribution.The mean and standard deviation of a normal distribution are 0 and 1, respectively. It has a kurtosis of 3 and zero skew.Not all symmetrical distributions are normal, but all normal distributions are symmetrical.Natural occurrences frequently resemble the usual distribution.

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What is the slope of the line that passes through the points (2, -4) and
(5,2)? Write your answer in simplest form.

Answers

Answer:

2

Step-by-step explanation:

Your slope is your change in y over your change in x.  The ordered pair is in the form of (x,y), so you subtract the y's and put that in your numerator (top)and subtract your x's and put that in your denominators (bottom).

2 - (-4) would be your top number.  To subtract a negative number is the same as adding a positive, so 2 - (-4) is the same as 2 +4, so your top number is 6.  

Now, to find the bottom number, you subtract the x's.

5-2 which is 3.

We now have the top and the bottom number

6/3 which is the same as 2.

2/1 is slope hope it helps

PLEASE HELP IM STUCK PLS

Answers

(-1,1)

The solution to the equation is the values that make both equations true. More simply put, it is where the two graphs intersect (cross). If we find the point where the two graphs both cross, we see the value is where x is -1 and y is 1, so the point is (-1,1).

We can also check this by plugging the values into the equations.

y = 2x + 3
1 = 2 * -1 + 3
1 = 1

y = -x
1 = -(-1)
1 = 1

Since both equations are true, the solution (-1,1) is correct.

Answer: (-1, 1)

Step-by-step explanation:

Method 1: Graphing

Since the graph is already given, we could directly refer to the intersecting point of the system of equations.

According to the graph, [ y = 2x + 3 ] and [ y = -x ] intersect at (-1, 1).

Therefore the solution is [tex]\Large\boxed{(-1,1)}[/tex]

Method 2: Substitution

Given equation

1) y = 2x + 3

2) y = -x

Substitute the y value in the 1) equation by the 2)

(-x) = 2x + 3

Add x on both sides

-x + x = 2x + 3 + x

0 = 3x + 3

Subtract 3 on both sides

0 - 3 = 3x + 3 - 3

-3 = 3x

Divide 3 on both sides

-3 / 3 = 3x / 3

x = -1

Substitute the x value into one of the equations to find the y value

y = -x

y = - (-1)

y = 1

Therefore, the solution is [tex]\Large\boxed{(-1,1)}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Functions f(x) and g(x) are composed to form h (x) = startroot x cubed minus 2 endroot. if f (x) = startroot x 2 endroot and g (x) = x cubed a, what is the value of a?

Answers

Function Composition exists when two functions f(x) and g(x) result in another function h(x), such that h(x) = f(g(x)). For function composition h(x) =  f(g(x)), the value of a exist -4.

What is function Composition?

Function Composition exists when two functions f(x) and g(x) result in another function h(x), such that h(x) = f(g(x)). In other words, put the outcome of one function into the other one.

Here, h(x) = f(g(x))

which means, h(x) = f(x³+ a)

[tex]$h(x) = \sqrt{x^3+a+2}[/tex]

[tex]$\sqrt{x^3-2} = \sqrt{x^3+a+2}[/tex]

To estimate the value of a, we separate equal terms:

1) Both are squared, so we can "eliminate" the square;

2) x³ = x³

3) -2 = a+2

a = -4

For function composition h(x) =  f(g(x)), the value of a exist -4.

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Write an equation in point-slope form of the line with a slope of 6 that passes through (-2, -5)

Answers

[tex](\stackrel{x_1}{-2}~,~\stackrel{y_1}{-5})\hspace{10em} \stackrel{slope}{m} ~=~ 6 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{6}(x-\stackrel{x_1}{(-2)})\implies y+5=6(x+2)[/tex]

18 1 / 2 miles of highway 1-35 Is undergoing repairs. The construction workers repairs The construction workers repair 2 1⁄4 Miles of hideaway each week Approximately How many weeks will it take for the repairs to be completed

Answers

Answer:

The exact amount of time would be 8 2/9 weeks, but if we are only counting full weeks, it would be finished in 9 weeks.

Step-by-step explanation:

y = xm

18 1/2 = 2 1/4x  Change both numbers into improper fractions

18 1/2 would be 37/2  The denominator (bottom number) stays 2.  To get the top number you would (2 x 18) + 1 or 37.  That makes 37/2 equivalent to 18 1/2.

Now do the same thing to 2 1/4.  The bottom number stays the same.  We get the top number (4 x 2) + 1 or 9.  That makes 9/4 equivalent to 2 1/4.

We know have

37/2 = 9/4 x  We can solve for x by multiplying both sides of the equation by 4/9

37/2(4/9) = (9/4)(4/9)x

148/18 = x  If we divide both the top and the bottom by 2 we would get 74/9 = x  If we divide 74 by 9 we get 8 2/9

h(x)=
8
1

x
3
−x
2
h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided by, 8, end fraction, x, cubed, minus, x, squared
What is the average rate of change of hhh over the interval -2\leq x\leq 2−2≤x≤2minus, 2, is less than or equal to, x, is less than or equal to, 2?h(x)=
8
1

x
3
−x
2
h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided by, 8, end fraction, x, cubed, minus, x, squared
What is the average rate of change of hhh over the interval -2\leq x\leq 2−2≤x≤2minus, 2, is less than or equal to, x, is less than or equal to, 2?

Answers

The average rate of change of the function over −2 ≤ x ≤ 2 is 1/2

How to determine the average rate of change?

The function is given as:

[tex]h(x) = \frac 18x^3 - x^2[/tex]

The interval is given as:

−2 ≤ x ≤ 2

Calculate h(2) and h(-2)

[tex]h(2) = \frac 18 * 2^3 - (2)^2[/tex]

h(2) = -3

[tex]h(-2) = \frac 18 * (-2)^3 - (-2)^2[/tex]

h(-2) = -5

The average rate of change is then calculated as:

[tex]m = \frac{h(-2) - h(2)}{-2-2}[/tex]

This gives

[tex]m = \frac{-5 + 3}{-4}[/tex]

Evaluate

m = 1/2

Hence, the average rate of change of the function over −2 ≤ x ≤ 2 is 1/2

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Complete question

[tex]h(x) = \frac 18x^3 - x^2[/tex]

What is the average rate of change of h over the interval −2 ≤ x ≤ 2

When we make inferences about the difference of two independent population proportions, what assumptions do we need to make? mark all that apply.

Answers

When we make inferences about the difference of two independent population proportions, we assume that it is a random sample, and the number of successes and failures are at least 15 in each group.

Two independent proportions tests involve comparing the proportions of two unrelated datasets.

For these two datasets to be regarded as an independent population, the following must be true or assumed to be true

The datasets must represent a random sampleEach dataset must contain at least 15 successes and failures

Hence, the above highlights are the assumptions of two independent population proportions.

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What are the exact solutions of x2 − 5x − 1 = 0 using x equals negative b plus or minus the square root of the quantity b squared minus 4 times a times c all over 2 times a?

Answers

Answer:

[tex]x=2.5+\frac{\sqrt{29}}{2}\\\\x=2.5-\frac{\sqrt{29}}{2}[/tex]

Step-by-step explanation:

So the question here is asking you to use the quadratic formula which is expressed as: [tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\[/tex]

A quadratic can generally be expressed as: [tex]y=ax^2+bx+c[/tex]

So using the equation you gave: [tex]0=x^2-5x-1[/tex]

We can identify the following values: a=1, b=-5, c=-1

Btw the equation explicitly write "1" as the coefficient of x, but since it's not provided it's implied that it's 1.

So plugging in the known values, we get the following equation:

[tex]x=\frac{5\pm\sqrt{(-5)^2-4(1)(-1)}}{2(1)}\\\\x=\frac{5\pm\sqrt{25+4}}{2}\\\\x=\frac{5\pm\sqrt{29}}{2}\\\\x=2.5+\frac{\sqrt{29}}{2}\\\\x=2.5-\frac{\sqrt{29}}{2}[/tex]

The last step just consists of taking the + and - solution, and since it asks for exact solutions you leave the 29 under the radical, and you don't approximate. There is no further simplification that can be done here.

ms bloom had 4 /7/12 boxes of pencils but 2/1/12 boxes of pencils were broken after she threw out the broken pencils how many boxes of pencils were left

Answers

Concluding, there are (2 + 12) boxes of pencils left.

How many boxes of pencils were left?

We know that Ms. Bloom had (4 + 7/12) boxes of pencils, and we also know that (2 + 1/12) of the boxes were broken.

The number of boxes of pencils left is given by the difference between the two above numbers, then we get:

N = (4 + 7/12) - (2 + 1/12) = (4 - 2) + (7/12 - 1/12) = 2 + 6/12

Now we can simplify the fraction:

N = 2 + 1/2

Concluding, there are (2 + 12) boxes of pencils left.

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PLEASE HELP IM SO STUCK

Answers

Answer:

(-4,0) , (0,9)

Step-by-step explanation:

x-intercept is the point where the line touches the x-axis, which means, y = 0.

So when y = 0,

-9x + 4(0) = 36

-9x = 36

x = [tex]\frac{36}{-9}[/tex]

x = -4

Therefore, the coordinates of the x - intercept is (-4,0)

y-intercept is the point where the line touches the y-axis, which means , x = 0.

so when x = 0,

-9(0) + 4y = 36

4y = 36

y = [tex]\frac{36}{4}[/tex]

y = 9

Therefore, the coordinates of the y - intercept is (0,9)

Answer:

x - intercept (-4,0)

y -intercept (0,9)

Step-by-step explanation:

Put in 0 for x.

-9(0) + 4y = 36

4y = 36  Divide both sides by 4

y = 9

(0,9) This is where the line will cross the y axis.

Put in 0 for y

-9y + 4(0) = 36

-9y = 36 Divide both sides by -9

Y = -4

The prices for different lengths of ribbon sold at a fabric store are shown in the table. Which statement best justifies whether or not the relationship between the length and price represents a function?

Answers

The statement that justifies the relationship is: D. it represents a function because no length has more than one price.

What is a Function?

For a relation to be considered a function, any of the following criteria must be met:

Every x-value has exactly one corresponding y-value that relates to it. That is, no x-value (input) can have two different y-value (output).Two different x-values (inputs) can correspond to the same y-value (output) but two different y-values (outputs) must not relate or correspond to an x-value (input).

In the scenario given:

Length of ribbon = input (x-value)

Price of ribbon = output (y-value).

We can observe that each length of ribbon (input) has its own price (output), therefore, we can conclude that the price of ribbon is a function of the length of the ribbon.

The answer is: D. This relationship represents a function because no length has more than one price.

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Put in decimal form, out to the nearest hundredth and explain how you got your answer.
This problem is meant to be done in order of operations.

Answers

Answer: [tex]\Large\boxed{2}[/tex]

Concept:

Here, we need to know the idea of the PEMDAS method.

PEMDAS is an acronym for the order of operations.

ParenthesisExponentsMultiplicationDivisionAdditionSubtraction

Solve:

Given expression

[tex]\dfrac{3^3~-~13}{11~-~2^2}[/tex]

Simplify the exponents

[tex]=\dfrac{27~-~13}{11~-~4}[/tex]

Simplify by subtraction

[tex]=\dfrac{14}{7}[/tex]

Simplify the fraction

[tex]\Large\boxed{=2}[/tex]

Hope this helps!! :)

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What is the behavior of the graph y=x4−2x3−11x2+12x+36 at each of its zeros?

Answers

The behavior sees the leading coefficient is already positive, then increasing the size of the inputs will simply result in the leading term being even more positively skewed. The line on the graph will start to slope to the right.

What is the behavior of the graph y=x4−2x3−11x2+12x+36 at each of its zeros?

The behavior of the graph of the polynomial function f(x) as the variable x approaches either positive or negative infinity represents the end behavior of the function. The final behavior of a polynomial function's graph is determined by the degree of the function as well as the leading coefficient.

Generally, the equation for is zeros  mathematically given as

y=x^4−2x^3−11x^2+12x+36

Therefore

(x+2)^2(x-3)^2=0

x=-2

x=3

since the graph attached has a positive leading coefficient and a positive degree

In conclusion, If the leading coefficient is already positive, then increasing the size of the inputs will simply result in the leading term being even more positively skewed. The line on the graph will start to slope to the right.

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5. Elias has 1/2 of a candy bar. He shares 1/4 of it with his best friend. How much of the candy bar did his best friend receive?​

Answers

Answer:

1/8

Step-by-step explanation:

say the bar has 20 pieces. he has 10 pieces. and he gave away 1/4 of those 10

1/4 x 10 = 2.5

20 / 2.5 = 8

So his friend recieved 1/8

you could also just do 1/2 x 1/4 which is 1/8

Answer:

1/8 of the candy bar.

Step-by-step explanation:

Elias has 1/2 of a candy bar.

He gave 1/4 of 1/2 to his friend.

[tex]\sf Friend's s\ share = \dfrac{1}{4} \ of \ \dfrac{1}{2}[/tex]

                      [tex]\sf =\dfrac{1}{4}*\dfrac{1}{2}\\\\=\dfrac{1}{8}[/tex]

What is the missing factor in this factor tree? 30 2x?

Answers

Answer:

15?

Step-by-step explanation:

2×15=30 i am not fully sure but this should be it

HELPPPP‼️‼️‼️

If x is the first of two consecutive odd integers, and the sum of the two integers is 72, what is the smaller of the two integers?

Answers

Answer:

x = 35.

Step-by-step explanation:

since they are odd, the second number isn't x + 1, it is x + 2.

x + x + 2 = 72

2x + 2 = 72

2x = 70

x = 35

X = 35 is the right answer

How fast must a 56. 5 g tennis ball travel to have a de broglie wavelength equal to that of a photon of green light (5400 angstroms)? (use scientific notation in your answer: 1. 0e39)

Answers

Answer:

Given:

Mass of the tennis ball=56.5 g

wavelength=5400 Angstroms

De-Broglie Wavelength = 5400 Angstrom.

= 5400 × 10⁻¹⁰ m.

Now, Using the Formula,

λ = h/mv

here,

h is the Planck's constant = 6.62 × 10⁻³⁴ J-s.

and v is the velocity of the tennis balls.

∴ 5400 × 10⁻¹⁰ = (6.62 × 10⁻³⁴)/ (0.054 × v)

⇒ 0.054v = (6.62 × 10⁻³⁴)/ (5400 × 10⁻¹⁰)

⇒ 0.054v = 0.0012 × 10⁻²⁴

⇒ v = 0.0012 × 10⁻²⁴/0.054

⇒ v = 0.023 × 10⁻²⁴ m/s.

Hence, the velocity of the tennis balls is 0.023 × 10⁻²⁴ m/s.

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Thirty percent of high-school senior boys play in the school band. If a certain high school has 60 senior boys, how many boys play in the school band?
(A) 12
(B) 18
(C) 22
(D) 30

Answers

B) 18 of high school boys play in the school band

factorize completely -3c²-4cb+4b²​

Answers

-3(3)^3 - 4(3)(4) + 4(4)^2
-3(9) - 4(12) + 4(16)
-27 - 48+ 64
-75+64
-11
The answer is-11

I'll focus on part (b) only.

Answers:Part (i):  The factorization is     (2b-3c)(2b+c)     Part (ii): The expression evaluates to    -11      

======================================================

Explanation:

Replace the variable b with the commonly used variable x and c with some other constant, let's say the letter m. These replacements will become apparent when we use the quadratic formula shortly later on.

After the replacements are made, we have -3c²-4cb+4b²​ turn into -3m²-4mx+4x²​

This is the same as 4x²​-4mx-3m²

Compare this to the format of ax²​+bx+c

We can see that

a = 4b = -4mc = -3m²

Once again, m is constant.

Let's compute the discriminant.

[tex]d = b^2 - 4ac\\\\d = (-4m)^2-4(4)(-3m^2)\\\\d = 16m^2+48m^2\\\\d = 64m^2\\\\[/tex]

This discriminant is under the square root as part of the quadratic formula.

So 4x²​-4mx-3m² would have roots of...

[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-b\pm\sqrt{d}}{2a}\\\\x = \frac{-(-4m)\pm\sqrt{64m^2}}{2(4)}\\\\x = \frac{4m\pm\sqrt{(8m)^2}}{8}\\\\x = \frac{4m\pm 8m}{8}\\\\x = \frac{4(m\pm 2m)}{4*2}\\\\x = \frac{m\pm 2m}{2}\\\\x = \frac{m+ 2m}{2} \ \text{ or } \ x = \frac{m-2m}{2}\\\\x = \frac{3m}{2} \ \text{ or } \ x = \frac{-m}{2}\\\\[/tex]

The whole time, the term "m" is treated as a constant. It is fixed to some unchanging number.

So why did we go through all that trouble to use the quadratic formula in the first place? It turns out that this formula is helpful to factoring quadratics. Recall that the roots of a polynomial tie very closely to its factorization.

For example, x²-4 factors to (x-2)(x+2) to have roots of x = 2 or x = -2. You could use the quadratic formula to solve x²-4 = 0 or x²+0x-4 = 0 and you should get x = 2 or x = -2 as the two solutions.

Anyways, back to the problem at hand.

Let's use the first root we found to form one of the factors needed.

The idea is to do a bit of algebra to get everything to one side. If fractions are present, then multiply both sides by the LCD to clear them out. We need to have 0 isolated on its own side.

[tex]x = \frac{3m}{2} \\\\ 2x = 3m\\\\ 2x-3m = 0[/tex]

So (2x-3m) is one factor

Through similar steps, you would find that the root [tex]x = \frac{-m}{2}[/tex] yields the factor of (2x+m)

Therefore, the factors are (2x-3m) and (2x+m)

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In summary so far, 4x²​-4mx-3m² factors to (2x-3m)(2x+m)

From here we replace x with b and replace m with c, so that we return back to the original variables used.

(2x-3m)(2x+m) becomes (2b-3c)(2b+c)

This can be confirmed using WolframAlpha. You could use the FOIL rule to expand out (2b-3c)(2b+c) and you should get 4b²​-4bc-3c²​ aka -3c²-4cb+4b²​

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Those previous sections talked about part (i)

Part (ii) is where we plug in b = 4 and c = 3. In other words, we replace every copy of b with 4, and every copy of c with 3.

If you use the original expression, then,

-3c²-4cb+4b²​ = -3(3)²-4(3)(4)+4(4)²​ = -3(9)-4(12)+4(16) = -11

Or you could use the factored expression.

(2b-3c)(2b+c) = (2*4-3*3)(2*4+3) = (8-9)(8+3) = (-1)*(11) = -11

This very partially confirms that -3c²-4cb+4b² = (2b-3c)(2b+c) is indeed the case. Unfortunately you'd have to use infinitely many numeric examples to confirm the answer to part (i); however, something like the FOIL rule is far more efficient.

If 12 oz. of sausage contains 300 calories, how many calories w ould 7 oz, contain? how would i write a formula

Answers

Answer:

175 cal

Step-by-step explanation:

if 12oz = 300 cal

then, 7 oz = ?

cross multiplication

12×?= 7×300

? = 2100/12

? = 175 cal

NB: you can replace the question mark with any variable.

Solve the compound inequality and graph the solution on a number line

5x + 9 ≤ 2 and x + 6 > 12

Answers

Answer:

First:

5x + 9 < 2

x= 9/5= 1,8 < 2

Second:

x + 6 < 12

x= 12/6= 2 < 12

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