How would you distinguish benzoic acid and benzyl alcohol by their infrared spectra?

Answers

Answer 1

The OH peaks in the IR spectra of benzyl alcohol and benzoic acid should be compared and contrasted.

What is the IR spectra of Benzoic acid?The right-hand portion of the infrared spectrum of benzoic acid, between wavenumbers 1500 and 400 cm-1, is referred to as the fingerprint region. It results from a special combination of intricately overlapping vibrations of the atoms within the benzoic acid molecule.What is the IR spectra of Benzyl alcohol?A C-Cl bond is frequently shown by a peak at 700.There are a few more peaks at 1500 that are directed at a C=C bond.What is IR spectra?

The percent transmittance (or absorbance) of the radiation through the molecule against the radiation's wave number forms the IR spectrum.

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Answer 2

It is important to contrast and compare the OH peaks in the IR spectra of benzyl alcohol and benzoic acid.

What does benzoic acid's IR spectrum look like?The fingerprint region is the region between wavenumbers 1500 and 400 cm-1 on the right side of the infrared spectrum of benzoic acid.The benzoic acid molecule's atoms vibrate in a unique pattern that involves intricately overlapping vibrations, which causes it.

What does benzyl alcohol's IR spectrum look like?A peak at 700 is typically used to indicate a C-Cl bond.At 1500, there are a couple more peaks that are focused on a C=C bond.

How do IR spectra work?The IR spectrum is made up of the radiation's wave number divided by its percent transmittance (or absorbance) through molecules.

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Related Questions

Describe how the pH of anti-acid powder can be determined
Describe how solid ammonium chloride can be separated from a mixture of ammonium chloride and anhydrous calcium chloride
please help it's agent​

Answers

There exist ways in separating mixtures of chloride salts such as that sodium chloride and ammonium chloride. It can be accomplished by crystallization, filtration, or sublimation.

What is pH of Anti-acid powder?

An antacid exists as a substance that neutralizes stomach acidity and stands habituated to relieve heartburn, indigestion, or an upset stomach.

Antacids increase the pH of the stomach contents toward neutrality. An antacid that increases the pH from 1.5 to 3.5 produces a 100-fold decrease in the concentration of gastric acid. Furthermore, the reduction of acidity exists escorted by inhibition of pepsin activity, another essential component of the digestive juice.

There exist ways in separating mixtures of chloride salts such as that sodium chloride and ammonium chloride. It can be accomplished by crystallization, filtration, or sublimation. The easiest approach among the three exists separation by sublimation.

Ammonium chloride sublimes upon heating. The sublimation exists as a decomposition of ammonium chloride forming ammonia and hydrogen chloride.

Sodium chloride on the other hand doesn't sublime and includes a more increased melting point than ammonium chloride. If we want to divide the mixture, we have to heat it to 330-350 degrees Celsius and manage the gas that will be produced.

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Assuming the salt is sodium chloride, what is the approximate molar concentration of salt in ocean water if the density of ocean water is 1.028 kg/l?

Answers

Molar concentration of Sodium chloride (NaCl) means the number of moles of sodium chloride present in 1L of water.

Molar mass of NaCl = Molar mass of Na + Molar mass of Cl

Molar mass of NaCl = 23 + 35.5

Molar mass of NaCl = 58.5g

∴ 1L of water contains 55.55 moles of water. Hence,

Mass of ocean water = 55.55 × 18 = 999.9g

Since, 1L of ocean water has a mass of 999.9g of which 3.5% is the salt.

hence, (999.9) (0.035) = 34.99g

So, No. of moles of NaCl = Mass of NaCl / 58g NaCl per mol

No. of moles of NaCl = 34.99/58.5

No. of moles of NaCl = 0.59 moles

So, Molar concentration or Molarity would be 0.59 moles present in 1L of solution.

Hence, Molarity or Molar Concentration = Moles of NaCl/ Volume of solution (in L)

Molarity = 0.59/1L

⇒ Molarity = 0.59M

Hence, the molarity is 0.59M

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Pick the word that best completes the following sentence. A
mixture is a mixture in which the composition is
uniform throughout the mixture.
a homogeneous
b heterogeneous
C compound

Answers

The answer is A :) homogeneous!

C4h5n(aq) h2o(l)⇌c4h5nh (aq) oh−(aq) express your answers as chemical formulas. enter your answers in the order given in the question separated by commas

Answers

In aqueous solutions, the hydrogen ion, also known as the hydronium ion, is a Bronsted-Lowry acid, while the hydroxide ion is a base as a result of the self-dissociation reaction.

        [tex]C_4H_5N(aq) + H_2O(l)[/tex] ⇄ [tex]C_4H_5NH (aq) + OH^-(aq)[/tex]

        [tex]Bronsted-\\Lowry Acid[/tex]                    [tex]Conjugate Acid[/tex]

Brønsted–Lowry acid-base theory:

Any species that may transfer a proton (H+) to another molecule is a Brnsted-Lowry acid. Any species that can take a proton from another molecule is a Brnsted-Lowry base. In essence, a Brnsted-Lowry base is a proton acceptor (PA) and an acid is a proton donor (PD).

According to the Arrhenius theory, acids are defined as chemicals that dissociate in an aqueous solution to produce hydrogen ions (H+), whereas bases are defined as substances that produce OH (hydroxide ions).

The hydrogen ion, or hydronium ion, is a Brønsted–Lowry acid in aqueous solutions, and the hydroxide ion is a base, by virtue of the self-dissociation reaction.

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A dark purple liquid is diluted by adding water.

The diluted liquid becomes a pale purple colour.

Explain the process that causes this change.

Refer to particles in your answer

Answers

Answer: The process is diffusion.

Explanation:

a dark liquid will have the highest concentration of dark purple atoms/molecules so it gives a concentrated colour.

when water is added to it, the colourless water molecules fill up the gaps between the purple particles and so their colour fades and becomes lighter and lighter as we add more water. see the image attached where imagine the red particles are water and the blue particles are purple particles. thats why the colour fades.

When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, what hybrid orbitals are used by phosphorus in the pcl4 cations?

Answers

When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, hybrid orbitals that  are used by phosphorus in the pcl4 cations are one orbital of s and three orbital of p as it is sp³hydridised.

What is sp³ hybridization?

Hybridization is a process or system which specifies the shape and geometry of any element or molecule with bond angles too.

The pcl4 cation is sp³ hybridized because of the phosphorus behave as a central atom here and the 4 chloride molecules are attached with the p- orbitals to the phosphorus molecule.

Therefore, pcl4 cation  is sp³ hybridized.

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What best describes how chlorine molecules, cl2, would behave if mixed with water?

Answers

The chlorine molecules, cl2, would behave if mixed with water is best described by the polarity concept.

What is polarity?

Polarity is a phenomena by which the dissolving power of any molecule can be known if they are polar will completely dissociate in water and if non polar will partially dissociate in water

Here chlorine is very poorly dissolve in water due to its non polar nature and water is polar. Some compounds are polar for short time of period and attend a partially positive and a partially negative charge within them.

Therefore,  Cl2 is a non polar compound describes the polarity.

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1) Calculate the empirical formula for a chemical compound that gives the following analysis: 66.6 g titanium and 33.4 g oxygen.
a) Ti_2O_3
b) Ti_2O
c) TiO_3
d) Ti_2

2) The empirical formula for a compound shows the symbols of the elements with subscripts indicating what?

a) actual numbers of atoms in a molecule
b) number of moles of the compound in 100 g
c) smallest whole-number ratio of the atoms
d) atomic masses of each element

3) In the tin oxide laboratory activity, what was the color of the vapor emitted when the nitric acid was added to the tin?

a) orange-brown
b) pink
c) green
d) blue

4) What is the empirical formula for a compound that is 36.6 percent potassium, 33.2 percent chlorine, and 29.9 percent oxygen?

KClO_2
KClO_3
K_2Cl_2O
K_2Cl_2O_5

5) What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?

P_3O_7
PO_3
P_2O_3
P_2O_5

Answers

1. The empirical formula of the compound is Ti₂O₃

2. The correct answer to the question is: smallest whole-number ratio of the atoms (Option C)

3. The correct answer to the question is: orange-brown (Option A)

4. The empirical formula of the compound is KClO₂

5. The empirical formula of the compound is P₂O₅

1. How to determine the empirical formulaTi = 66.6 gO = 33.4 gEmpirical formula =?

Divide by their molar mass

Ti = 66.6 / 48 = 1.3875

O = 33.4 / 16 = 2.0875

Divide by the smallest

Ti = 1.3875 / 1.3875 = 1

O = 2.0875 / 1.3875 = 3/2

Multiply by 2 to express in whole number

Ti = 1 × 2 = 2

O = 3/2 × 2 = 3

Thus, the empirical formula of the compound is Ti₂O₃

2. What is empirical formula?

This is the simplest formula of a compound which shows the smallest whole number ratio of the atoms present in the compound

With the above definition, we can conclude that the correct answer to the question is: smallest whole-number ratio of the atoms (Option C)

3. What colour is shown when nitric acid is added?

In the tin oxide laboratory activity, the colour of the vapor emitted when nitric acid is added to the tin is: orange-brown

NOTE: This colour is visible when we carryout the practical experiment

Thus, the correct answer to the question is orange-brown (Option A)

4. How to determine the empirical formulaK = 36.6%Cl = 33.2%O = 29.9%Empirical formula =?

Divide by their molar mass

K = 36.6 / 39 = 0.9385

Cl = 33.2 / 35.5 = 0.907

O = 29.9 / 16 = 1.8688

Divide by the smallest

K = 0.9385 / 0.907 = 1

Cl = 0.907 / 0.907 = 1

O = 1.8688 / 0.907 = 2

Thus, the empirical formula of the compound is KClO₂

5. How to determine the empirical formulaP = 43.6%O = 56.4%Empirical formula =?

Divide by their molar mass

P = 43.6 / 31 = 1.406

O = 56.4 / 16 = 3.525

Divide by the smallest

P = 1.406 / 1.406 = 1

O = 3.525 / 1.406 = 5/2

Multiply by 2 to express in whole number

P = 1 × 2 = 2

O = 5/2 × 2 = 5

Thus, the empirical formula of the compound is P₂O₅

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The formation of protons over neutrons (thus producing about a 7:1 ratio) was favored in the early universe because:____.
a. it takes more energy to create a proton from a neutron than a neutron from a proton. b. it takes more energy to create a neutron from a proton than a proton from a neutron. c. the more massive neutrons made better targets for nucleon collisions. d. the positively charged protons were repelled away from the explosion.

Answers

Because it requires more energy to create a neutron from a proton than it does to create a proton from a neutron, protons were formed more frequently than neutrons in the early universe. The correct answer is option b.

To find the answer, we need to know more about the early universe.

How the formation of proton over neutrons was favored in the early universe?A neutron is produced with greater energy than a proton. However, later on, some of the protons were changed into neutrons. Contrary to some claims, the proton is a stable particle that never decays, but the neutron is unstable outside of the nucleus and decays with a half-life of around 10.5 minutes. However, very few would have had time to decay on the timeline you mention in your question. Every matter particle should have been accompanied by an antimatter particle, and every proton, neutron, and electron, by an anti-neutron and a positron, respectively. Where did all the antimatter go is the great mystery. There have been a few attempts to explain this, but they have failed.

Thus, we can conclude that, the correct answer is option b.

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Brainliest Available! Thank you in advance!


What is the molar solubility of aluminum hydroxide, Al(OH)3, if Ksp for Al(OH)3 is 3.0 × 10−34?


AL(OH)3 (s) ⇌ AL3+ (aq) + 3OH- (aq)

Answers

Answer:

  3.0×10⁻¹³ M

Explanation:

The solubility product Ksp is the product of the concentrations of the ions involved. This relation can be used to find the solubility of interest.

Equation

The power of each concentration in the equation for Ksp is the coefficient of the species in the balanced equation.

  Ksp = [Al₃⁺³]×[OH⁻]³

Solving for [Al₃⁺³]

The initial concentration [OH⁻] is that in water, 10⁻⁷ M. The reaction equation tells us there are 3 OH ions for each Al₃ ion. If x is the concentration [Al₃⁺³], then the reaction increases the concentration [OH⁻] by 3x.

This means the solubility product equation is ...

  Ksp = x(10⁻⁷ +3x)³

For the given Ksp = 3×10⁻³⁴, we can estimate the value of x will be less than 10⁻⁸. This means the sum will be dominated by the 10⁻⁷ term, and we can figure x from ...

  3.0×10⁻³⁴ = x(10⁻⁷)³

Then x = [Al₃⁺³] will be ...

  [tex][\text{Al}_3^{\,+3}]=\dfrac{3.0\times10^{-34}}{10^{-21}}\approx \boxed{3.0\times10^{-13}\qquad\text{moles per liter}}[/tex]

We note this value is significantly less than 10⁻⁷, so our assumption that it could be neglected in the original Ksp equation is substantiated.

__

Additional comment

The attachment shows the solution of the 4th-degree Ksp equation in x. The only positive real root (on the bottom line) rounds to 3.0×10^-13.

Equilibrium constant for the reaction is

[tex]\sf K_{sp}=[Al^{3+}][OH^-]^3[/tex]

Let [Al³+] be s[OH-] is 10^{-7}

So

[tex]\\ \rm\Rrightarrow s=\dfrac{3.0\times 10^{-34}}{(10^{-7})^3}[/tex[

[tex]\\ \rm\Rrightarrow s=\dfrac{3.0\times 10^{-34}}{10^{-21}}[/tex]

[tex]\\ \rm\Rrightarrow s=3.0\times 10^{-13}M[/tex]

What volume would a 0. 250 mole sample of h2 gas occupy if it had a which a a pressure of 1. 70 atm and a temperature of 35 C?

Answers

The volume of  0. 250 mole sample of [tex]H_{2}[/tex] gas occupy if it had a pressure of 1. 70 atm and a temperature of 35 °C is  3.71 L.

Calculation,

According to ideal gas equation which is known as ideal gas law,

PV =n RT

P is the pressure of the hydrogen gas  = 1.7 atmVis the volume of the hydrogen gas = ?n is the number of the hydrogen gas = 0.25 moleR is the universal gas constant = 0.082 atm L/mole KT is the temperature of the sample = 35°C = 35 + 273 = 308 K

By putting all the values of the given data like pressure temperature universal gas constant and number of moles in equation (i) we get ,

1.7 atm×V = 0.25 mole ×0.082 × 208 K

V = 0.25 mole ×0.082atm L /mole K × 308 K /1.7 atm

V = 3.71 L

So, volume of the sample of the hydrogen gas occupy is  3.71 L.

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In an electric current, the ___ particles flow or are pushed along a path

positive

negative

neutral

Answers

the negative particles flow or are pushed along a path

Any request or distribution of phi should contain only the minimum amount of phi required to complete the intended task. True or false?.

Answers

True

The bare minimum required standard

The minimal necessary standard restricts uses, disclosures, and requests for PHI to the bare minimum amount required to fulfil the use's or disclosure's intended purposes.

What is HIPAA Minimum necessary standard ?

Under the Privacy Rule's Minimum Necessary Standard, covered entities are required to take all necessary precautions to ensure that protected health information (PHI) is only accessed as much as is required to carry out the duties at hand.

When a health care provider seeks something or discloses something to them for medical treatment, the minimum necessary criterion does not apply. Additionally, it does not apply to disclosures or uses made to an individual or with that person's consent.In order to reduce the possibility of a breach or employee wrongdoing, this guideline aims to establish the precedent of handling PHI as little as feasible.

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A cylinder with a movable piston contains 2.00 g of helium, He , at room temperature. More helium was added to the cylinder and the volume was adjusted so that the gas pressure remained the same. How many grams of helium were added to the cylinder if the volume was changed from 2.00 L to 3.90 L

Answers

Heya....

Here's your answer.....

PV = nRT... R is a constant...

so PV/nT = constant...

P1V1 / n1T1 = P2V2 / n2T2...P is constant.T is constant.. so

V1 / n1 = V2 / n2

since n = mass / mw

V1 / (mass 1 / mw) = V2 / (mass 2 / mw)

and since molecular mass = constant

V1 / mass 1 = V2 / mass 2

mass 2 = V2 x mass 1 / V1 = 2.90L x 2.00 g / 2.00 L = 2.9 g

mass 2 - mass 1 = 2.90 g - 2.00 g = 0.90 g

ie.. 0.90 g of He was added.

Thanks...!!!

What is the compound number (enter both the number and letter without spaces e. g. 1d, 2h) for trans-cinnamic acid?

Answers

99 140-10-3.

99 140-10-3 is the compound number for trans-cinnamic acid.

What do you mean by compound numbers?A subscript is the little number that appears to the right of an element's symbol. That figure represents how many atoms of that element are contained in the complex.What is the purpose of trans-Cinnamic acid?The creation of trans-cinnamic acid's methyl, ethyl, and benzyl esters is its primary usage, while it is also used to make flavors, colors, and medications. These esters play a significant role in perfume composition. The sweetener aspartame is a precursor of the acid.

What other name would you give trans-Cinnamic acid?

Phenolacrylic acid

The class of chemical compounds known as cinnamic acids includes trans-cinnamic acid, often referred to as (e)-cinnamic acid or phenylacrylic acid. These are organic aromatic compounds that generate 3-phenylprop-2-enoic acid from benzene and a carboxylic acid group.

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When an electron in a hydrogen atom jumps from an orbital farther from the nucleus to an orbital closer to the nucleus, it?

Answers

When an electron in a hydrogen atom jumps from an orbital farther from the nucleus to an orbital closer to the nucleus, the energy is emitted.

The energy of electron decreases. When it goes, the electron release a photon of electromagnetic energy.

When an electron jumps from higher energy orbital to lower energy orbital, the difference in the energies of these two orbitals is radiated as quantum.

E = hc/wavelength

The photon is emitted with the electron moving from higher energy level to lower energy level.

The wavelength of emitted radiation would be (27/32) × wavelength.

Thus we concluded that the energy of photon is exact energy that is lost by the electron moving to its lower energy level.

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10 mL of 2(M) NaOH solution is added to 200 mL of 0.5 (M) of NaOH solution. What is the final concentration?​

Answers

Hello its me Sanya yadav

The chemical formula H2O represents one molecule of water.

How many total atoms are present in this molecule? Use the words atom, molecule, and subscript in your answer.

Answers

There is a total of three atoms present in the water (H₂O) molecule.

What is an atom?

An atom is the smallest particle of an element that may or may not be capable of independent existence.

What is a molecule?

A molecule is the smallest particle of an element or compound that can exist freely.

What is a subscript?

Subscripts are the numbers that come below after a symbol. They tell you the number of atoms of an element. If there is no subscript then it is understood that the subscript is 1.

How to calculate the number of atoms in a molecule?

For calculating the number of atoms in a molecule, add the subscripts of that molecule, and you will get the total atoms of it.

For example, in molecule C₂H₅O, there are 2 carbon atoms, 5 hydrogen atoms, and 1 oxygen atom.

Add the subscripts

2 + 5 + 1 = 8

Hence, there is a total of 8 atoms in C₂H₅O.

For the H₂O molecule,

2 + 1 = 3

Hence, there is a total of 3 atoms present in one water molecule.

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What atomic or hybrid orbital on the central br atom makes up the sigma bond between this br and an outer f atom in bromine trifluoride, brf3 ?

Answers

Atomic or hybrid orbital on the central br atom makes up the sigma bond between this br and an outer f atom in bromine trifluoride, brf3 is sp2 hybridization

Trigonal hybridization is another name for sp2 hybridization. It entails combining one's' orbital with two 'p' orbitals of equal energy to create a new hybrid orbital known as sp2. A trigonal symmetry combination of s and p orbitals that is kept at 120

One of the hybrid orbitals formed when one s orbital and two p orbitals are mathematically merged to form three new equivalent orbitals orientated toward the corners of a triangle is sp2 hybridization.

The only feasible molecule geometry for sp2 hybridized center atoms is trigonal planar. When all of the bonds are in place, the shape is trigonal planar as well.

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Certain drugs, such as ssris, block the reuptake of a neurotransmitter into the presynaptic cell. what effect does this have onsynaptic communication?

Answers

Selective serotonin reuptake inhibitors (SSRIs) are drugs that are antidepressants. These blocks the reuptake of a neurotransmitter leading to increases in their activity in the synaptic cells.

What are neurotransmitters?

Neurotransmitters are defined as the signaling molecules that are secreted by the nerve cells and act as signal transporter between the neurons and the other cells of the body.

The SSRIs class of drugs affects this neurotransmitter and blocks the pathway to the presynaptic cell. This, in turn, affects synaptic communication by increasing the amount of those SSRIs in the body and acting as a stimulant to treat various diseases.

Therefore, the SSRIs block the neurotransmitter and result in their effects.

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I WILL MARK U BRAINLIEST IF U ANSWER THIS QUESITON

Answers

Answer:

c )   16

Explanation:

C4 H10 O    +   6 O2  =====>  4  CO2  +   5  H2O

1 + 6 + 4 + 5 = 16

Answer:

C.) 16

Explanation:

An equation is balanced when there are equal amounts of each element on both sides of the reaction. These values can be modified by adding coefficients.

The unbalanced equation:

C₄H₁₀O + O₂ -----> CO₂ + H₂O

Reactants: 4 carbon, 10 hydrogen, 3 oxygen

Products: 1 carbon, 2 hydrogen, 3 oxygen

The balanced equation:

1 C₄H₁₀O +  6 O₂ -----> 4 CO₂ + 5 H₂O

Reactants: 4 carbon, 10 hydrogen, 13 oxygen

Products: 4 carbon, 10 hydrogen, 13 oxygen

Now, you can add the coefficients:

1 + 6 + 4 + 5 = 16

A student sets up the following equation to convert a measurement.
(The ? stands for a number the student is going to calculate.)
Fill in the missing part of this equation.
Note: your answer should be in the form of one or more fractions multiplied together.

Answers

Answer:

[tex]\frac{1 kJ}{1,000 J}[/tex]  ·  [tex]\frac{1,000 mmol}{1 mol}[/tex]

Explanation:

The final answer has a different set of units. In particular, millimoles (mmol) changes to moles (mol) and joules (J) changes to kilojoules (kJ). To make this change, you need to multiply the first value by proportions.

When writing these proportions, it is important that they are arranged in a way that allows for the cancellation of units. For instance, since J is located in the numerator, it must be located in the denominator of the conversion. Furthermore, since mmol is located in the denominator, it must be located in the numerator of the conversion.

Proportions:

1,000 J = 1 kJ

1,000 mmol = 1 mol

The full expression:

[tex]-1.3*10^4\frac{J}{mmol*^oC}[/tex]  ·  [tex]\frac{1 kJ}{1,000 J}[/tex]  ·  [tex]\frac{1,000 mmol}{1 mol}[/tex]  =  [tex]? \frac{kJ}{mol*^oC}[/tex]
                        ^           ^

As you can see, the old units cancel out and you are left with kJ in the numerator and mol in the denominator.

If butane had a volume of 500 mL. at a pressure of 1.5 atm and a temperature of
20 °C, what would the new volume of the gas be at a temperature of 30 °C and a pressure
of 500 Torr

Answers

Question:

If butane had a volume of 500 ml. at a pressure of 1.5 atm and a temperature of 20 °C, what would the new volume of the gas be at a temperature of 30 °C and a pressure of 500 Torr?

Solution Given:

Let P be the pressure V be volume and and T be temperature.

Volume of Butane [[tex]V_1[/tex]] = 500 ml

Pressure of Butane [[tex]P_1[/tex]] = 1.5 atm

Temperature [[tex]T_1[/tex]] =20°C=20+273=293K

New Volume of Butane [[tex]V_2[/tex]] = ?

New Pressure of Butane [[tex]V_2[/tex]] =500 Torr=500*0.00131579=0.657895 atm

Note: 1 Torr= 0.00131579 atm

New Temperature of Butane [[tex]V_2[/tex]] =30°C=30+273=303K

Now

By using combined gas law equation:

[tex]V_2=V_2*\frac{P_1*T_2}{P_2*T_1}[/tex]

[tex]V_2=500*\frac{1.5*303}{0.657895*293}=1178.9 ml[/tex]

The new volume of Butane is 1178.9 ml

Benzoic acid is a common food preservative. the pka of benzoic acid is 4. 20. what is true of the relative strengths of benzoic acid (ba) and its conjugate base (b-)?

Answers

Here BA is benzoic acid and B- is conjugate base;

BA is weaker than B- because the Ka < Kb

--> BA is stronger than B- because the Ka > Kb

BA is stronger than B- because the Ka < Kb

BA is weaker than B- because the Ka > Kb

A conjugate acid-base pair, according to the Brnsted-Lowry definition of acids and bases, consists of two substances that are distinct only in that they contain a proton (H+). When a proton is supplied to a base, a conjugate acid is created, and vice versa when a proton is taken away from an acid, a conjugate base is created. Yuki Jung was the creator.

The power of an acid (or base) is inversely proportional to the power of its conjugate base (or conjugate acid): The conjugate base of an acid is weaker the stronger it is. The conjugate base of a weaker acid has a stronger base. A pair of chemical species known as conjugate acid and conjugate base exhibit opposing chemical behaviors.

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URGENT PLEASE HELP

In an experiment, hydrochloric acid reacted with different volumes of sodium thiosulfate in water. A yellow precipitate was formed during the reaction. A cross drawn at the base of each flask became gradually invisible due the formation of this yellow precipitate. The time taken for the cross to become invisible was recorded. A partial record of the experiment is shown.


Experimental Record
Flask Volume of
HCl Volume of
Sodium Thiosulfate Volume of
Water Time
1 10 mL 10 mL 40 mL 14 seconds
2 10 mL 20 mL 30 mL
3 10 mL 30 mL 20 mL
4 10 mL 40 mL 10 mL


Based on your knowledge of factors that affect the rates of chemical reactions, predict the trend in the last column of the experimental record. Use complete sentences to explain the trend you predicted. You do not have to determine exact values for time; just describe the trend you would expect (increase or decrease) and why it occurs.

Answers

The trend will be such that the time taken for the cross to disappear will be increasing.

Rate of reactions

The rate of reactions is affected by the concentration of reactants. The more concentrated the reactants are, the more the rate of the reaction, and vice versa. This is based on the condition that all other factors are kept constant.

In the illustrated reaction, the volume of sodium thiosulfate decreases downward while the volume of water increases. This means that the sodium thiosulfate gets more diluted as we move downward.

Thus, the reaction rate will keep decreasing. In other words, more time would be needed for the cross to disappear as the concentration of sodium thiosulfate decreases.

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Copper has a delta.hfus = 13.0 kj/mol. what mass of copper releases 112.4 kj of heat as it freezes? use q equals n delta h.. 9.42 g 6.75 g 549 g 1590 g

Answers

The mass of copper releases 112.4 kj of heat as it freezes is 549 gm.

What is heat of fusion?

The most typical illustration is when solid ice transforms into liquid water. The molecules within in the substance become less structured as a result of this process, which is also known as melting or heat of fusion.

Calculation for mass of copper;

The heat of fusion for copper is given as 13.0 kj/mol.

Hfus(Cu) = 13.0 kJ/mol

The heat released during the process is  112.4 kj.

Q = 112.4 kJ;

The formula for molar heat of substance is;

Q = n(Cu) · Hfus(Cu).

Where n(Cu) is the number of moles of copper present in the solution.

Write formula in terms of Number of moles.

n(Cu) = Q / Hfus(Cu)

Substitute the given values;

n(Cu) = 112.4 kJ / 13.0 kJ/mol.

n(Cu) = 8.65 mol (number of moles of copper present)

m(Cu) = n(Cu) · M(Cu).

Where, m(Cu) is the mass of copper.

M(Cu) is the molecular mass of the copper.

Substitute the values in the formula to get the mass.

m(Cu) = 8.65 mol × 63.546 g/mol.

m(Cu) = 549.428 g

Therefore, the mass of copper present in the solution was 549.428 g.

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Answer: C.) 549 g

Explanation:

An analytical chemist has determined by measurements that there are 8. 5 moles of magnesium in a sample of talc. how many moles of hydrogen are in the sample?

Answers

The moles of hydrogen in the talc sample are 5.67 moles.

Talc are the hydrous silicate minerals. The chemical formula of talc is Mg₃Si₄O₁₀(OH)₂.

From the formula it can be determined that there are: 3 moles of Mg, 4 moles of Si, 12 moles of O and 2 moles of H.

Moles are a type of SI unit of measurement of the amount of substance.

According to the question, magnesium = 8.5 moles

Also, 3 moles of Mg = 2 moles of H

Therefore, moles of H = 8.5 moles × (2 moles H / 3 moles Mg)

                 moles of H = 5.67 moles

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Increased total serum lactic dehydrogenase (LD) activity, confined to fractions 4 and 5 is most likely to be associated with: A. Pulmonary infarction B. Hemolytic anemia C. Myocardial infarction D. Acute viral hepatitis​

Answers

Answer:

D.Acute Viral Hepatitis

inflammation of the liver caused by infection with one of the five hepatitis viruses

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Calculate [hy3−] in a solution prepared by mixing 10. 00 ml of 0. 0305 m voso4, 9. 20 ml of 0. 0305 m edta, and 10. 00 ml of buffer with a ph of 4. 0

Answers

The concentration of [ Hy³] = 4.861 *28⁻²³

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or answer. A focused answer is one which has a exceedingly massive quantity of dissolved solute. A dilute answer is one that has a tremendously small amount of dissolved solute.

Given,

 Molarity of VoSo4 ,M = 0.02M

     Vol of VoSo4 , V = 10 ml

Molarity of EDTA = 0.02 M

vol of EDTA = 9.10 ml = 0.0091 L

& 10 ml of buffer with pH =4

NOW,

     no. of moles of EDTA = molarity * Volume (L)

                                         =  0.02 M * 0.0091 L

                                        = 182 * 10^-6 moles

                                        = 1.82 * 10^-4 moles

Now,

       ∝ Y^3- = [tex]\frac{[Y^3-]}{moles of edta}[/tex]

         [ Y^3-] = ∝ Y^3- * moles of EDTA

Given,

at pH = 4,   ∝ Y^3- = 3*10^-9

    ∴ ∝ Y^3- =  3*10^-9

        [ Y^3-] = 3*10^-9 * 1.82 * 10^-4

                   = 5.46 * 10^-13

Now, K f = [H2Y^2-]/[vo^2+][y3-]

           [vo^2+] = 18.7

[H2Y2-] = K f * [ v o+][Y^2-]

    [H2Y2] = 3.762 * 10^-13

 [ HY^3-] = 4.8 * 10^-23

So, the concentration of the    [ HY^3-] is 4.8 * 10^-23

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2. 109×103 g of ethylene glycol, c2h4(oh)2, are dissolved in 2. 40×103 g of water. what is the mole fraction of ethylene glycol?

Answers

The mole fraction of ethylene glycol is 0.203.

What is a mole fraction?

The mole fraction represents the number of moles of a specific component divided by the total number of moles present in the given solution.

It is a method of expressing the concentration of a solution

Mole fraction can be represented by x. Let a solution consists of components A and B then, the mole fraction is

[tex]Mole fraction of solute, n_A = \frac{n_A}{n_A+n_B}[/tex]

[tex]Mole fraction of solvent, n_B = \frac{n_A}{n_A+n_B}[/tex]

The molar mass of ethylene glycol = 62 g

Given the mass of ethylene glycol = 2.109 x 10³ g

The molar mass of water = 18 g

Given the mass of water= 2.40×10³ g

No moles of ethylene glycol,  [tex]n_A[/tex] = [tex]\frac{2.109 \times 10^3 g}{62 g}[/tex]

                                                =34.02

No of moles of water, [tex]n_B[/tex] = [tex]\frac{2.40 \times 10^3 g}{18 g}[/tex] = 133.33

Mole fraction of ethylene glycol = [tex]x = \frac{n_A}{n_A +n_B}[/tex]  = [tex]\frac{34.02}{34.02+133.33} = \frac{34.02}{167.35}[/tex]

                                                      =  0.203

Hence, The mole fraction of ethylene glycol is 0.203

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