We get $593,940
Answer:
Solution Given:
1 second = $ 521
19 minutes=19*60=1140 seconds
1140 seconds =$521*1140 =$593,940
Answer:
$593,940
Step-by-step explanation:
$521 for every second
First, you need to multiply 60 with 19, since there are 60 seconds in a minute.
We get: 60 × 19 = 1140
Now multiply $521 with 1140
We get: 521 × 19 = 593,940
Final result: $593,940
Hope this helps :)
On Monday, a local hamburger shop sold a combined total of 336 hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold. How many hamburgers were sold on Monday
Answer:
84
Step-by-step explanation:
Let the number of hamburgers be h and the number of cheeseburgers be c.
This means that:
h+c=336c=3hSubstituting c=3h into the first equation, it follows that 4h=336, and thus h=84.
if x is normally distributed with U = 283 and o = 21 find p(x) is greater than 315
The probability that the value of p(x) is greater than 315 is 0.063754
How to determine the probability that the value of p(x) is greater than 315?From the question, the given parameters about the distribution are
Mean value of the set of data = 283Standard deviation value of the set of data = 21The actual data value = 315The z-score of the data value is calculated using the following formula
z = (x - mean value)/standard deviation
Substitute the given parameters in the above equation
z = (315 - 283)/21
Evaluate the difference of 315 and 283
z = 32/21
Evaluate the quotient of 32 and 21
z = 1.524
The probability that the value of p(x) is greater than 315 is then calculated as:
P(x > 315) = P(z > 1.524)
From the z table of probabilities, we have;
P(x > 315) = 0.063754
Hence, the probability that the value of p(x) is greater than 315 is 0.063754
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Put y-x=-8 of a line into slope-intercept form, simplifying all fractions.
Answer: [tex]y= x-8[/tex]
Step-by-step explanation:
Slope intercept form has a general formula of [tex]y=mx +b[/tex]m represents the slope of the lineb represents the value of the lines y-intercept the equation must be rearranged into the general formula by isolating for 'y'[tex]y-x=-8[/tex]
to remove the x from the left side of the equation the opposite operation must be done to both sides[tex]y-x+x=-8+x[/tex]
the negative and positive x cancel out on the left side, leaving us with the equation with y by itselfnow you can rearrange to put the equation into [tex]y=mx+b[/tex]Final Answer: [tex]y=x-8[/tex]
Find the square.
(7m-3) 2
49m²-21m-9
Step-by-step explanation:
(7m - 3)² = 49m² - 42m + 9
play it through and do the actual multiplication behind the square :
(7m - 3)² = (7m - 3)(7m - 3) =
= 7m×7m + 7m×(-3) + (-3)×7m + (-3)(-3) =
= 49m² - 2×21m + 9 = 49m² - 42m + 9
Find the area of the surface given by z = f(x, y) that lies above the region R. f(x, y) = 3 + 4x3/2 R: rectangle with vertices (0, 0), (0, 5), (2, 5), (2, 0)
It looks like the function is
[tex]f(x,y) = 3 + 4x^{3/2}[/tex]
We have
[tex]\dfrac{\partial f}{\partial x} = 6x^{1/2} \implies \left(\dfrac{\partial f}{\partial x}\right)^2 = 36x[/tex]
[tex]\dfrac{\partial f}{\partial y} = \left(\dfrac{\partial f}{\partial y}\right)^2 = 0[/tex]
Then the area of the surface over [tex]R[/tex] is
[tex]\displaystyle \iint_R f(x,y) \, dS = \iint_R \sqrt{1 + 36x + 0} \, dA \\\\ ~~~~~~~~ = \int_0^5 \int_0^2 \sqrt{1+36x} \, dx \, dy \\\\ ~~~~~~~~ = 5 \int_0^2 \sqrt{1+36x} \, dx \\\\ ~~~~~~~~ = \frac5{36} \int_1^{73} \sqrt u \, du \\\\ ~~~~~~~~ = \frac5{36}\cdot \frac23 \left(73^{3/2} - 1^{3/2}\right) = \boxed{\frac5{54} (73^{3/2} - 1)}[/tex]
Working together a small pipe and large pipe can fill a big pool in 6 hour. It takes the smaller pipe 5 hours longer than the large pipe to fill the big pool working alone. How long does it take the smaller pipe to fill the pool by itself ?
The time taken for the smaller pipe to fill the pool by itself is 15.71 hours
Rate of workTime taken for both pipes = 6 hoursTime taken for long pipe = xTime taken for small pipe = x + 6Rate of work of both pipes = 1/6Rate of work of long pipe = 1/xRate of work of small pipe = 1/x + 61/6 = 1/x + 1/(x+6)
1/6 = (x+6)+(x) / (x)(x+6)
1/6 = (x+6+x) / x²+6x
1/6 = (2x+6)(x² + 6x)
cross product1(x² + 6x) = 6(2x+6)
x² + 6x = 12x + 36
x² + 6x - 12x - 36 = 0
x² - 6x - 36 = 0
Using quadratic formulax = 9.71 or -3.71
The value of x cannot be negative
Therefore, the
Time taken for long pipe = x
= 9.71 hours
Time taken for small pipe = x + 6
= 9.71 + 6
= 15.71 hours
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ASAP help me with this ty!
Answer:
96 degrees
Step-by-step explanation:
The angle bisectors splits the two angles mentioned down the middle so the 2 angles are equal to each other.
4x + 4 = 2(x + 13) Distribute the 2
4x + 4 = 2x + 26 Subtract 2x from both sides
2x + 4 = 26 Subtract 4 from both sides
2x = 22 Divide both sides by 2
x = 11 Plug that back into either the right side or the left side of the original equation
4x + 4
4(11) + 4
44 + 4
48. Each angle is 48 degrees. 48 + 48 is 96
Solve for x.
31-x=252
Answer: -221
Step-by-step explanation:
31 is smaller than 252. Therefore, since 31 MINUS x equals 252, x needs to be a negative number in order to complete the equation (recall that a negative number times a negative number equals a positive number).
Therefore, if we subtract 31 on both sides, in other words transpose, we get,
-x = 221
The coefficient of -x is -1, however it is not written as it's implied that if there is not written coefficient in from of a variable then the coefficient of the variable is 1 or -1, depending on its sign.
Therefore, dividing -1 on both sides, we get,
x = -221
Hence, the desired answer is -221.
Find the Riemann sum for
f(x) = 2x − 1, −6 ≤ x ≤ 4,
with five equal subintervals, taking the sample points to be right endpoints.
Explain, with the aid of a diagram, what the Riemann sum represents.
Mathematically speaking, the Riemann sum of the linear function is represented by A ≈ [[4 - (- 6)] / 5] · ∑ 2 [- 6 + i · [[4 - (- 6)] / 2]] - [[4 - (- 6)] / 5] · ∑ 1, for i ∈ {1, 2, 3, 4, 5}, whose representation is represent by the graph in the lower left corner of the picture.
What figure represents a Riemann sum with right endpoints?
Graphically speaking, Riemann sums with right endpoints represent a sum of rectangular areas with equal width with excess area for positive y-values and truncated area for negative y-values generated with respect to the x-axis. Mathematically speaking, this case of Riemann sums is described by the following expression:
A ≈ [(b - a) / n] · ∑ f[a + i · [(b - a) / n]], for i ∈ {1, 2, ..., n}
Where:
a - Lower limit
b - Upper limit
n - Number of rectangles
i - Index of a rectangle
If we know that f(x) = 2 · x - 1, a = - 6, b = 4 and n = 5, then the Riemann sum with right endpoints of the area below the curve is:
A ≈ [[4 - (- 6)] / 5] · ∑ 2 [- 6 + i · [[4 - (- 6)] / 2]] - [[4 - (- 6)] / 5] · ∑ 1, for i ∈ {1, 2, 3, 4, 5}
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Graph the function y=√x+1-4. Which point lies on the graph?
a.) (-2,3)
b.) (1,4)
c.) (-1,-4)
d.) (0,4)
Evaluate f(x)=−4ex−2−4 for x=4. round to the nearest 4 decimal
Answer:
25.2
Step-by-step explanation:
I'll assume you wrote:
[tex]f(x) = 4e^{x-2} - 4[/tex]
So when x = 4:
[tex]4e^{4-2} - 4 = 4e^2 - 4[/tex] ≅ [tex]4\cdot 7.3 - 4 = 25.2[/tex]
So,some please help me with this question !
=============================================================
Explanation:
Angles EBA and DBC are congruent because of the similar arc marking. Both are x each.
Those angles, along with EBD, combine to form a straight angle of 180 degrees. We consider those angles to be supplementary.
So,
(angleEBA) + (angleEBD) + (angleDBC) = 180
( x ) + (4x+12) + (x) = 180
(x+4x+x) + 12 = 180
6x+12 = 180
6x = 180-12
6x = 168
x = 168/6
x = 28
Angles EBA and DBC are 28 degrees each.
This means angle D = 3x+5 = 3*28+5 = 89
-----------
Then we have one last set of steps to finish things off.
Focus entirely on triangle DBC. The three interior angles add to 180. This is true of any triangle.
D+B+C = 180
89 + 28 + C = 180
117+C = 180
C = 180 - 117
C = 63 degrees
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
[tex]\qquad❖ \: \sf \: \angle C = 63 \degree[/tex]
[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]
[tex]\qquad❖ \: \sf \:x + 4x + 12 + x=180°[/tex]
( Angle EBA= Angle DBC, and the three angles sum upto 180° due to linear pair property )
[tex]\qquad❖ \: \sf \:6x + 12 = 180[/tex]
[tex]\qquad❖ \: \sf \:6x = 180 - 12[/tex]
[tex]\qquad❖ \: \sf \:6x = 168[/tex]
[tex]\qquad❖ \: \sf \:x = 28 \degree[/tex]
Next,
[tex]\qquad❖ \: \sf \: \angle C + \angle D + x = 180°[/tex]
[tex]\qquad❖ \: \sf \: \angle C +3x + 5 + x = 180°[/tex]
[tex]\qquad❖ \: \sf \: \angle C +4x = 180 - 5[/tex]
[tex]\qquad❖ \: \sf \: \angle C +4(28) = 175[/tex]
( x = 28° )
[tex]\qquad❖ \: \sf \: \angle C +112 = 175[/tex]
[tex]\qquad❖ \: \sf \: \angle C = 175 - 112[/tex]
[tex]\qquad❖ \: \sf \: \angle C = 63 \degree[/tex]
[tex] \qquad \large \sf {Conclusion} : [/tex]
[tex]\qquad❖ \: \sf \: \angle C = 63 \degree[/tex]
what is the solution to square root 6x - 3 = 2 square root x?
Answer:
No solution
Step-by-step explanation:
[tex]\sqrt{6x-3}=2\sqrt{x} \\ \\ 6x-3=4x \\ \\ -3=2x \\ \\ x=-\frac{3}{2} [/tex]
However, this would make the right hand side of the equation undefined over the reals, so there is no solution.
solve this equations 3x+4x-8=6(x-3)+x
Answer:
no solutions
Step-by-step explanation:
Divide the following polynomial using synthetic division, then place the answer in the proper location on the grid. Write answer in descending powers of x. (x3 + 6x2 + 3x + 1 ) ÷ (x - 2)
When we divide [tex]x^{3} +6x^{2} +3x+1[/tex] by (x-2) we will get the quotient be [tex]x^{2} +8x+19[/tex] and remainder be 39.
Given two expressions be [tex]x^{3} +6x^{2} +3x+1[/tex] and (x-2).
We are required to divide the first expression by second expression.
Division means distributing parts of something. The number which is being divided is known as quotient.Divisor is a number which divides the number.
Expressions refers to the combination of numbers, fractions, coefficients, determinants, indeterminants. It expresses some relationship or show equation of line.
We know that relationship between quotient, divisor, divident and remainder is as under:
Dividend=Divisor*Quotient+Remainder
[tex]x^{3} +6x^{2} +3x+1[/tex]=(x-2)*([tex]x^{2} +8x+19[/tex])+39
Quotient=[tex]x^{2} +8x+19[/tex]
Remainder=39
Hence when we divide [tex]x^{3} +6x^{2} +3x+1[/tex] by (x-2) we will get the quotient be [tex]x^{2} +8x+19[/tex] and remainder be 39.
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find the coefficient of x^5 in the expression ( 1 - 2x) ^6
Answer:
-32x^5
Step-by-step explanation:
using binomial expression we have (1-2x)^6
(Subtracting rational coefficients-Mixed numbers)
Simplify by combining like terms:
1/3k - 8 3/4k
[?] ?
_k
?
Answer:
-8 5/12
Step-by-step explanation:
suppose you are using a=.01 to test the claim than mu is greater than or equal to 32 using a p-value. you are given the sample statistics n=40 , x bar =33.8 and o =4.3. Find the p-value.
0.0040, 0.0211, 0.1030, 0.9960
Using the z-distribution, the p-value for the test is of 0.0040.
What is the test statistic for the z-distribution?The test statistic is given by:
[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which:
[tex]\overline{x}[/tex] is the sample mean.[tex]\mu[/tex] is the value tested.[tex]\sigma[/tex] is the standard deviation of the population.n is the sample size.For this problem, the parameters are given as follows:
[tex]\overline{x} = 33.8, \mu = 32, \sigma = 4.3, n = 40[/tex]
Hence the value of the test statistic is given by:
[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
z = (33.8 - 32)/(4.3/sqrt(40))
z = 2.65.
What is the p-value?Using a z-distribution calculator, with z = 2.65 and a right-tailed test, as we are testing if the mean is greater than a value, the p-value is of 0.0040.
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Make a decision about the given claim. Use only the rare event rule, and make subjective estimates to determine whether events are likely. For example, if the claim is that a coin favors heads and sample results consist of 11 heads in 20 flips, conclude that there is not sufficient evidence to support the claim that the coin favors heads (because it is easy to get 11 heads in 20 flips by chance with a fair coin).
Claim: The mean age of students in a large statistics class is less than 31. A simple random sample of the students has a mean age of 30.4.
Choose the correct answer below.
A.
The sample is unusual if the claim is true. The sample is unusual if the claim is false. Therefore, there is not sufficient evidence to support the claim.
B.
The sample is not unusual if the claim is true. The sample is unusual if the claim is false. Therefore, there is sufficient evidence to support the claim.
C.
The sample is not unusual if the claim is true. The sample is not unusual if the claim is false. Therefore, there is sufficient evidence to support the claim.
D.
The sample is unusual if the claim is true. The sample is unusual if the claim is false. Therefore, there is sufficient evidence to support the claim.
The correct option regarding the sampling is C. The sample is not unusual if the claim is true. The sample is not unusual if the claim is false. Therefore, there is sufficient evidence to support the claim.
What do you mean sampling?Sampling is a process that is used in statistical analysis in which a predetermined number of observations are taken from a larger population
In this case, since the claim is mean pulse rate of students in a large statistics classes is greater than 72. The sample mean pulse rate was found to be 98.9 then the sample is not unusual if the claim is true. The sample is unusual if claim is false. Therefore there is sufficient evidence to support the claim.
The correct option is C.
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Which radical expression is equivalent to
[tex]~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] ~\dotfill\\\\ a^{\frac{1}{5}}\implies \sqrt[5]{a^1}\implies \sqrt[5]{a}[/tex]
Which relation is also a function?
A.
A dot plot graph shows on a coordinate plane passes through (4, minus 8), (2, minus 4), (2, minus 3), (1, minus 1), (0, 1), (minus 1, 2), (minus 1, 4), (minus 3, 5), and (minus 4, 7)
B. (,)
C. circle graph
A nonlinear function on a coordinate plane vertex at (minus 3, minus 2) passes through (minus 7, 0), and (minus 6, minus 4).
D.
x y
The relation that is also a function is described as follows:
A nonlinear function on a coordinate plane vertex at (minus 3, minus 2) passes through (minus 7, 0), and (minus 6, minus 4).
When a relation is a function?A relation is a function if each value of the input is mapped to only one value of the output.
In this problem, we have that:
For the dot plot graph, input 2 is mapped to -3 and -4, hence it is not a function.In a circle graph, each value of x is mapped to two values of y, hence it is not a function.Hence a function is given by:
A nonlinear function on a coordinate plane vertex at (minus 3, minus 2) passes through (minus 7, 0), and (minus 6, minus 4).
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Show Work Please Thank You
Answer:
[tex] \frac{\pi}{4} [/tex]
Step-by-step explanation:
[tex] \sf let \: y = { \tan }^{ - 1} ( \tan \frac{3\pi}{4} ) \\ \\ \sf \hookrightarrow \tan y = \tan \frac{3\pi}{4} \\ \\ \sf \hookrightarrow \tan y = \tan(\pi - \frac{\pi}{4} ) \\ \\ \sf \hookrightarrow \tan y = \tan( - \frac{\pi}{4} ) \\ \\ \sf \hookrightarrow \tan y = - \tan \frac{\pi}{4} \\ \\ \boxed {\hookrightarrow{ \bold{y = - \frac{\pi}{4} } } }[/tex]
What is the solution to this equation?
9x - 4(x - 2) = x + 20
9x - 4(x - 2) =x + 20
We move all terms to the left:
9x -4(x - 2) - (x + 20) = 0Multiply
9x - 4x -(x + 20) + 8 = 0We get rid of the parentheses.
9x - 4x - x - 20 + 8 = 0We add all the numbers and all the variables.
4x - 12 = 0We move all terms containing x to the left hand side, all other terms to the right hand side
4x=12x = 12/4x = 3Which equation does the graph represent?
Answer:
It is the second answer
Step-by-step explanation:
The standard form of an ellipse is
x^2/a^2 + y^2/b^2 or x^2/b^2 + y^2/a^2 = 1
If the x is the main axis we use the first form. If the y is the main axis we use the second form. We will use the second form.
our a is 3 and our b is 4
x^2/3^2 + y^2/4^2
PLEASE HELP ME WITH THIS QUESTION
6
Answer:
45
Step-by-step explanation:
Assuming this is a trapezoid,
[tex]\frac{29+WZ}{2}=37 \\ \\ 29+WZ=74 \\ \\ WZ=45[/tex]
Find the x-intercept and y-intercept for 8x-9y=15
The x and y-intercept of the equation [8x - 9y = 15] are ( 15/8, 0 ) and ( 0, -5/3 ) respectively.
What are the x and y-intercept?Given the equation;
8x - 9y = 15
First, we find the x-intercepts by simply substituting 0 for y and solve for x.
8x - 9y = 15
8x - 9(0) = 15
8x = 15
Divide both sides by 8
8x/8 = 15/8
x = 15/8
Next, we find the y-intercept by substituting 0 for x and solve for y.
8x - 9y = 15
8(0) - 9y = 15
- 9y = 15
Divide both sides by -9
- 9y/(-9) = 15/(-9)
y = -15/9
y = -5/3
We list the intercepts;
x-intercept: ( 15/8, 0 )
y-intercept: ( 0, -5/3 )
Therefore, the x and y-intercept of the equation [8x - 9y = 15] are ( 15/8, 0 ) and ( 0, -5/3 ) respectively.
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the difference between 2 numbers, a and b is 21. the difference of 5 times a and 2 times b is 18. What are the values of a and b?
Answer:
Step-by-step explanation:
a-b=21
5a-2b=18
Using elimination, we have
5a-5b=105
5a-2b=18
So:
3b=-87 so b=-29
Substituting, a=-8
(a,b)=(-8,-29)
. x is directly proportional to y. When x = 5, y = 3. Work out the value
of y when x =9
Answer: y = 5.4
Step-by-step explanation: This is a proportional statement. So we can set up a system of proportions.
So we know when x is 5, y is 3. Thus, we can set up a proportion [tex]\frac{x}{y}[/tex] such that substituting will give [tex]\frac{5}{3}[/tex].
Now, we know when x is 9, y is some unknown number. So we can set up the second proportion as [tex]\frac{9}{y}[/tex].
Since 5/3 and 9/y are directly proportional, these 2 expressions are therefore equal. So we have [tex]\frac{5}3}[/tex] [tex]= \frac{9}{y}[/tex].
Cross multiplying, we get [tex]5y = 27[/tex].
Dividing by 5, we get [tex]y = 5.4[/tex]
Hope this helped!
6. (a) In the given figure, AD and BC are two straight lines. If ZBAO = 50°, ZABO = 60° and ZPCD = 130° then find the values of x and y. 50 60% B 130
Answer: 70 and 60 degrees
Step-by-step explanation:
Angle AOB = 180 - 50 - 60 = 70 degrees so x is 70 degrees
Angle OCD = 180 - 130 = 50 so y = 180 - 70 - 50 = 60 degrees
What is the least common multiple of 6x^2+39x-21 and 6x^2+54x+84?
Answer:
B (2nd option)
Step-by-step explanation:
Factor each one.
6x^2+39x-21 is divisible by 3 -> 3(2x^2+13x-7) -> 3(2x-1)(x+7)
6x^2+54x+84 is divisble by 6 -> 6(x^2+9x+14) -> 6(x+2)(x+7)
The greatest common factor is 3(x+7), so taking that out of each polynomial, we have (2x-1) and 2(x+2). The least common multiple is the greatest common factor*(2x-1)*2(x+2) which, simplifying, is 12x^3+102x^2+114x-84, or B.