How much money do I need now if I am going to recieve $5000 every 6 months (starting in 6 months) for 10 years if the interest rates are 4%/a compounded semi-annually?

The correct answer is option (C) median.

The median will help Emily to find the number that appears in the middle of the 25 numbers that are arranged in ascending order.

The mean, median, and mode are the three most commonly used measures of central tendency for populations that do not have much data, that is, they do not need to be grouped.

The mean, also known as average, is the value obtained by dividing the sum of a cluster of numbers by the number of them.

When arranging the numbers from least to largest, the median sits exactly in the middle of the values that are above. The median is a set that is a value that is in the middle of the other values.

The number that appears most frequently in a set of numbers is called the mode.

So, The median will help Emily to find the number that appears in the middle of the 25 numbers that are arranged in ascending order.

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35miles Rick have to run to burn one pound of adipose tissue.

According to the given question.

Rick runs 5miles to burn 500 calories.

⇒ 1 mile burns the amount of calories = 500/5 = 100 calories.

As we know that

1 pound = 3,500 calories.

So the number of miles Rick needed to run to burn 1 pound of adipose tissue = 3500/100 = 35miles

Hence, 35miles Rick have to run to burn one pound of adipose tissue.

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Answer:

x1 = 5-3squareroot 5/2 x2= -5+3 squareroot 5 / 2

Step-by-step explanation:

Answer: x = 4

Step-by-step explanation:

Given equation

4x - 20 = -x

Add x on both sides

4x - 20 + x = -x + x

5x - 20 = 0

Add 20 on both sides

5x - 20 + 20 = 0 + 20

5x = 20

Divide 5 on both sides

5x / 5 = 20 / 5

[tex]\Large\boxed{x=4}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

Below in bold.

Step-by-step explanation:

Part A

At the x-intercepts  f(x) = 0, therefore:

2x^2 - 3x - 5 = 0

(2x - 5)(x + 1) = 0

x = 5/2, -1)

So the x intercepts are (-1, 0) and (5/2, 0).

Part B

The Coefficient  of x^2 is positive ( it is 2) So the graph opens upwards and the vertex will be a minimum.

Convert f(x) to vertex form, by completing the square:

f(x) = 2x^2 - 3x - 5

= 2(x^2 - 3/2x) - 5

= 2[(x - 3/4)^2 - 9/16] - 5

= 2(x - 3/4)^2 -18/16 - 80/16

= 2(x - 3/4)^2 - 49/8

So the coordinates of the vertex are

(3/4, -49/8)  or

(0.75, -6.125) in decimal form.

Part C

To graph f(x) you would first mark the points on the x axis which we found in Part 1 and the vertex found in Part 2. This vertex will be the bottom of the 'U'.

The graph is a parabola shaped roughly like a U, and will be symmetrical about the line x = 0.75 (which passes through the vertex).

You would also plot 2 more points above the x axis so as to get an accurate graph. 1 would be to the left of the line of symmetry and 1 to its right.

Suggest   x = - 2  and calculate f(-2) = 2(-2)^2 - 3(-2) - 5 =  11.

- that is the point (-2,11) and the other would be  x = 4,  f(x) = 15. (4, 15)

Once you have plotted these points draw a smooth u shaped curve through them.

From the graph, the equation of f(x) + g(x) is f(x) + g(x) = 2x + 3

The functions are given as:

f(x) = x + 3

g(x) = x

From the above functions, we can see that the function g(x) is the parent function of a linear function.

When the parent function of a linear function is added to another function to form a composite function, the new function would pass through the following points

(x, y)= (0, b) and (-b, -b)

Where b is the y-intercept of the other function

i.e b = 3 from f(x) = x + 3

So, we have the following points

(0, 3) and (-3, -3)

Next, we draw the points and we connect the points

When the equation of f(x) + g(x) is calculated, we have

f(x) + g(x) = 2x + 3

See attachment for the graph of the functions

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Answer:

120.

Step-by-step explanation:

That would be factorial 5, written 5!.

That  is 5*4*3*2*1

= 120.

Answer:

120

Step-by-step explanation:

We have 5 digits that can be used to create different 5 digit numbers. We are also not allowed to repeat any numbers. Let's say we have 5 boxes to put the 5 numbers in.

Box 1

Box 2

Box 3

Box 4

Box 5

In the first box, we have 5 different choices. Since we aren't allowed to repeat any digits, the second box only has 4 different choices. And so on...

Box 1 --> 5 choices

Box 2 --> 4 choices

Box 3 --> 3 choices

Box 4 --> 2 choices

Box 5 --> 1 choice

Therefore the amount of 5 digit numbers that can be created is:

[tex]5\times4\times3\times2\times1[/tex] or 5 factorial (a factorial is all the product of all the positive integers equal to and less than the number), which is equivalent to:

120 5-digit numbers

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\qquad❖ \: \sf \:g(f( - 5)) = 5[/tex]

[tex]\textsf{\underline{\underline{Steps to solve the problem} }:}[/tex]

[tex]\qquad❖ \: \sf \:f(x) = |2x + 9| [/tex]

[tex]\qquad❖ \: \sf \:f( - 5) = |2( - 5) + 9| [/tex]

[tex]\qquad❖ \: \sf \:f( - 5) = | - 10+ 9| [/tex]

[tex]\qquad❖ \: \sf \:f( - 5) = | - 1| [/tex]

[tex]\qquad❖ \: \sf \:f( - 5) = 1[/tex]

next,

g(f(-5)) represents value of y at x = f(-5) = 1

hence,

[tex] \qquad \large \sf {Conclusion} : [/tex]

First you have to figure out the side length of the triangle.

sin(60)= X/8

Let's call x the side length.

8 sin(60)=X

X=6.93

The multiply it by 4

The area is 27.72

Answer:

C

Step-by-step explanation:

2/5 x1/5 = 2/25  If you divide 2 by 25, you get.08.  To change a decimal into a percent, you move the decimal two places to the right to get 8%

Answer:

Step-by-step explanation:

Comment

Begin by removing the brackets.

6+3(n-4)-8+2n

6 + 3n - 12 - 8 + 2n                 Collect like terms

3n + 2n + 6 - 12 - 8                 Combine

5n - 14

Answer

5n - 14

Using concepts of probability, it exists found that there exists a 4.7% probability that it arrives at American airlines (aa).

A probability exists given by the number of expected outcomes divided by the number of total outcomes.

Over a large number of trials, a percentage can also define the probability of a single event.

In this question, analyzing the problem on the internet, we have that over a considerable number of flights, of those which came on time, 4.7% of them were in  American airlines.

There exists a 4.7% probability that it arrives on American airlines(aa).

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Answer: 2316/16924 = 0.137 = 13.7%

Step-by-step explanation:

Answer:

1. BD bisects <CBE, AE || BD (Given)

2. <EBD ~= <CBD (Definition of < Bisectors)

3. <AEB ~= <EBD (Alternate Interior Angles Theorem)

4. <CAE ~= <CBD (Corresponding Angles Postulate)

5. <CAE ~= <AEB (Transitive Property of Congruence)

6. AB ~= BE (Converse of Isosceles Triangles Theorem)

The equation that represents the graph of the ellipse is x² / 4 + y² / 100 = 1. (Correct choice: D)

Herein we have a representation of an ellipse in the image attached aside, ellipses are characterized by the following standard formula:

(x - h)² / a² + (y - k)² / b² = 1     (1)

Where:

Please notice that ellipse will be vertical if b > a, otherwise it will be horizontal. The graph exhibits a vertical ellipse centered at the origin and therefore we conclude that (h, k) = (0, 0) and b > a (b = 10, a = 2). Finally, the equation that represents the graph of the ellipse is x² / 4 + y² / 100 = 1. (Correct choice: D)

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Answer:

○ [tex]h = \frac{2A}{b}[/tex]  

Step-by-step explanation:

We are given:

[tex]A = \frac{1}{2} b h[/tex]

To solve for [tex]h[/tex], we have to rearrange the equation to make [tex]h[/tex] the subject:

[tex]A = \frac{1}{2} b h[/tex]

⇒ [tex]2A = bh[/tex]     [multiplying both sides by 2]

⇒ [tex]\frac{2A}{b} = h[/tex]       [dividing both sides by b]

⇒  [tex]h = \frac{2A}{b}[/tex]      [swapping sides]

Answer:

8x³ - 2x² - 51x - 45

Step-by-step explanation:

(x - 3)(2x + 3)(4x + 5) ← expand the 2nd/3rd factors using FOIL

= (x - 3)(8x² + 10x + 12x + 15)

= (x - 3)(8x² + 22x + 15)

multiply each term in the second factor by each term in the first factor.

x(8x² + 22x + 15) - 3(8x² + 22x + 15) ← distribute parenthesis

= 8x³ + 22x² + 15x - 24x² - 66x - 45 ← collect like terms

= 8x³ - 2x²- 51x - 45

Expand first 2 bracket first to get:

2x^2 + 3x - 6x - 9 & simplify, then expand with last bracket.

2x^2 - 3x - 9 (4x + 5)

2x^2 x 4x = 8x^4

2x^2 x 5 = 10x^2

Repeat for the next two numbers next to the bracket.

You get => 8x^3 + 10x^2 - 12x^2 - 15x - 36x - 45

Final simplified answer of:

8x^3 - 2x^2 - 51x - 45

Hope this helps!

The correct option is D.

An equation to determine the area, a, of the patio that will be painted :

a = (x + 25)(x + 15) - 30

Geometric shapes are the mathematical figures that show how ordinary objects in our world are shaped. Shapes in geometry are the configurations of things with boundary lines, angles, and surfaces.

Length of the rectangular patio is (x+25).

Width of the rectangular patio is (x+15).

Length of bench is 5.

Width of the bench is 1.

Area of a rectangle is:

A = Length x Width

Area of rectangular patio is:

A[tex]_1[/tex] = (x + 25)(x + 15)

Area of bench is:

A[tex]_2[/tex] = 10 x 3

   = 30

The painting area is:

A = A[tex]_1[/tex] - A[tex]_2[/tex]

A = (x + 25)(x + 15) - 30

Therefore, the correct option is D.

An equation to determine the area, a, of the patio that will be painted :

a = (x + 25)(x + 15) - 30

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Answer:

[tex]y=-\dfrac{1}{3}x+4[/tex]

Step-by-step explanation:

Slope of line with given x and y intercepts

The x-intercept is when y = 0.  
Therefore, if the x-intercept is 5 ⇒ (5, 0).

The y-intercept is when x = 0.  
Therefore, the y-intercept is -15 ⇒ (0, -15).

Inputting these two points into the slope formula to find the slope of this line:

[tex]\sf slope\:(m)=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{-15-0}{0-5}=3[/tex]

Slope of function f(x)

If the function f(x) is perpendicular to the above line, then the slope of function f(x) is the negative reciprocal of the slope of the line.

[tex]\implies \sf slope\:of\:f(x)=-\dfrac{1}{3}[/tex]

Equation of f(x) in point-slope form

Use the found slope and the point (-6, 6) with the point-slope form of a linear equation to find the equation of function f(x):

[tex]\implies y-y_1=m(x-x_1)[/tex]

[tex]\implies y-6=-\dfrac{1}{3}(x-(-6))[/tex]

[tex]\implies y-6=-\dfrac{1}{3}(x+6)[/tex]

Expand and rearrange so that the equation is in the slope-intercept form of y=mx+b:

[tex]\implies y-6=-\dfrac{1}{3}x-2[/tex]

[tex]\implies y=-\dfrac{1}{3}x+4[/tex]

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For the levels of qualitative, the variable called dummy variables is used in the multiple regression method.

According to the statement

we have given that the by which method we use the different levels of a qualitative independent variable and we have to explain about it.

So, For his purpose, we know that the

A dummy variable is a variable that takes values of 0 and 1, where the values indicate the presence or absence of something.

And in the multiple regression method there are a lot of different variables which are used for a qualitative and for this a variable is used which is called the dummy variables.

By this variables we show the analysis between the given data. it gives the output in the 0 and 1 numbers.

So, For the levels of qualitative, the variable called dummy variables is used in the multiple regression method.

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Answer:

Multiply both sides of the first equation by 2.

Multiply both sides of the second equation by 3.

Step-by-step explanation:

The y terms are

-3y

2y

The LCM of 2 and 3 is 6.

We need the y terms to add to zero.

Multiply both sides of the first equation by 2 to get -6y.

Multiply both sides of the second equation by 3 to get 6y.

Then -6y + 6y = 0 eliminating the y terms after adding the equations.

The two non negative real numbers with a sum of 60 that have the largest possible​ product are 30 and 30.

What are non negative numbers?

Non-negative numbers are those that are either zero or positive (remember that 0 and 0 are the same). An integer that is either positive or zero is considered a non-negative integer. It is the result of adding all the natural numbers together with zero. It can be defined as the set "0, 1, 2, 3,...," and is also known as Z.

An integer that is either positive or zero is considered a non-negative integer.

Let us assume the two non negative numbers are [tex]x[/tex] and [tex]y[/tex].

According to the question,

Sum of two non negative numbers = 60

⇒ [tex]x+y=60[/tex]

⇒ [tex]y=60-x[/tex]

Their product will be given as,

⇒ [tex]P=xy[/tex]

⇒ [tex]P=x(60-x)[/tex]

⇒ [tex]P=60x-x^2[/tex]

For the product to be largest [tex]P'(x)=0[/tex]

⇒ [tex]P'(x) = 60-2x[/tex]

⇒ [tex]60-2x=0[/tex]

⇒ [tex]2x=60[/tex]

⇒ [tex]x=30[/tex]

Now, for the value of [tex]y[/tex]

⇒ [tex]y=60-x[/tex]

⇒ [tex]y=60-30[/tex]

⇒ [tex]y=30[/tex]

Therefore, the two non negative numbers are 30, 30.

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Assuming you mean [tex]f(x,y) = xy^2[/tex] over the domain

[tex]D = \left\{(x,y) ~:~ x\ge0 \text{ and } y\ge0 \text{ and } x^2 + y^2 \le 3\right\}[/tex]

we first observe that [tex]f(x,y) = 0[/tex] for all [tex](x,y)[/tex] on the coordinate axes.

There are no critical points elsewhere in the interior of [tex]D[/tex], since

[tex]\dfrac{\partial f}{\partial x} = y^2 = 0 \implies y=0[/tex]

[tex]\dfrac{\partial f}{\partial y} = 2xy = 0 \implies x = 0 \text{ or } y = 0[/tex]

Parameterize the circular arc boundary by [tex]x=\sqrt3\cos(t)[/tex] and [tex]y=\sqrt3\sin(t)[/tex], where [tex]0\le t\le\frac\pi2[/tex]. Then

[tex]f(x(t), y(t)) = g(t) = 3\sqrt3 \cos(t) \sin^2(t) = 3\sqrt 3 (\cos(t) - \cos^3(t))[/tex]

Find the critical points of [tex]g[/tex].

[tex]g'(t) = -3\sqrt3 \sin(t) + 9\sqrt3 \cos^2(t) \sin(t) = 0[/tex]

[tex]-3 \sin(t) (1 - 3 \cos^2(t)) = 0[/tex]

[tex]\sin(t) = 0 \text{ or } 1 - 3 \cos^2(t) = 0[/tex]

[tex]\sin(t) = 0 \text{ or } \cos^2(t) = \dfrac13[/tex]

[tex]\sin(t) = 0 \text{ or } \cos(t) = \pm\dfrac1{\sqrt3}[/tex]

In the first case, we get

[tex]t = \sin^{-1}(0) + 2n\pi \text{ or } t = \pi - \sin^{-1}(0) + 2n\pi[/tex]

where [tex]n[/tex] is an integer; the only solution on the boundary of [tex]D[/tex] is [tex]t=0[/tex] corresponding to the point [tex](\sqrt3,0)[/tex].

In the second case, we get

[tex]t = \cos^{-1}\left(\dfrac1{\sqrt3}\right) + 2n\pi \text{ or } t = -\cos^{-1}\left(\dfrac1{\sqrt3}\right) + 2n\pi[/tex]

with only one relevant solution at [tex]t=\cos^{-1}\left(\frac1{\sqrt3}\right)[/tex]  corresponding to [tex](1,\sqrt2)[/tex].

In the third case, we get

[tex]t = \cos^{-1}\left(-\dfrac1{\sqrt3}\right) + 2n\pi \text{ or } t = -\cos^{-1}\left(\dfrac1{\sqrt3}\right) + 2n\pi[/tex]

but there is no [tex]t[/tex] in this family of solutions such that [tex]0\le t\le\frac\pi2[/tex].

So, we find

[tex]\min\left\{xy^2 \mid (x,y) \in D\right\} = 0 \text{ at } (0,0)[/tex]

(but really any point on either axis works)

[tex]\max \left\{xy^2 \mid (x,y) \in D\right\} = 2 \text{ at } (1,\sqrt2)[/tex]

The probability of event A and event B IS  15/91.

What is the probability?

Probability determines the odds that a random event would occur. The odds lie between 0 and 1.

The probability of event A  = number of brown marbles / total number of marbles

= 6/14

The probability of event B = number of orange marbles / total number of marbles -1

= 5/13

P(A and B) =6/14 x 5/13

                 = 30/182

                 = 15/91

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Answer:

B.) 5/13

Step-by-step explanation:

15/3=5

91/7=13

5/13

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The values of the function if the function f(x) is reflected over y-axis is  g(x) = 10/21x

Reflection is a transformation technique that changes the position of an object on an xy-plane.

If the function f(x) is reflected over y-axis, the resulting function is y = f(-x). Given the following function;

f(x) = -2/7(5/3)x

This can also be written as;

f(x) = -10/21 x

Replace x as -x

f(-x) = -10/21(-x)

f(-x) = g(x) = 10/21x

Hence the values of the function if the function f(x) is reflected over y-axis is  g(x) = 10/21x

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Answer:

4368 ways

Step-by-step explanation:

Use nCk for this. 16C5. This is [tex]\frac{n!}{(n-k)!(k!)}[/tex]. This becomes[tex]\frac{16!}{(11!)(5!)}[/tex]. This is [tex]\frac{16*15*14*13*12}{5*4*3*2*1}[/tex] due to 16! and 5! canceling out. This becomes 4368.

The surface area of the rectangular prism is 2(lw + wh + lh). A rectangular prism has six rectangular faces.

The area of a rectangle with length and width is

Area = length × width

I.e., A = l × w sq. units

A rectangular prism has six rectangular faces and the length 'l', width 'w', and height 'h'.

So, the areas of each face are as follows:

A(R1) = l × w

A(R2) = l × h

A(R3) = w × h

A(R4) = l × w

A(R5) = l × h

A(R6) = w × h

Thus, the area of the prism = sum of areas of all the faces

⇒ Area of the prism = lw + lh + wh + lw + lh + wh

⇒ A = 2lw + 2lh + 2wh

⇒ A = 2(lw + lh + wh)

Therefore, the area of the rectangular prism is A = 2(lw + lh + wh).

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The piecewise function graphed below is given as follows:

A piecewise function is a function that has different definitions, depending on the input.

For x between -4 and -2, inclusive, the function is constant at 3, hence the definition is:

[tex]f(x) = 3, -4 \leq x \leq -2[/tex]

For x greater than -2 until 3, the function is a line with slope 1 and y-intercept 2, hence the definiton is:

[tex]f(x) = x + 2, -2 < x \leq 3[/tex]

For x greater than 3 until 5, the function is constant at -1, hence the definition is:

[tex]f(x) = -1, 3 < x \leq 5[/tex]

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Rejected masses x are those that weigh less than 9.02 oz or more than 9.48 oz.

To find the rejected masses:

Therefore, rejected masses x are those that weigh less than 9.02 oz or more than 9.48 oz.

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The correct question is given below:

A company did a quality check on all the packs of trail mix it manufactured. each pack of trail mix is targeted to weigh 9.25 oz. a pack must weigh within 0.23 oz of the target weight to be accepted. what is the range of rejected masses, ×, for the manufactured trail mixes?