How many moles of solute particles are present in 1 mL (exact) of aqueous 0.0040 M Ba(OH)2?

Answer:

H3PO4 is stronger than H2PO4- because

H3PO4 dissociation constant is 6.9×10^-3

H2PO4^- dissociation constant is 6.2×10^-8

Answer:

See below

Explanation:

From the graph: initial temp = -10 ° C

    melting occurs at 0 ° C   (constant temp process)

     at '2'   the ice is melting.....going from a solid to a liquid at a constant temperature  

It follows that the reaction is spontaneous at high temperatures Option A.

The term ΔS is referred to as the change in the entropy of the system. Now recall that entropy is defined as the degree of disorderliness in a system. If a system is highly disorderly then it means that it has a high entropy. Also, ΔH has to do with the heat change that accompanies a reaction.

We know that both the entropy and the heat change can both either be positive or negative. Now we know that the equation ΔG = ΔH - TΔS can be used to ascertain whether or not a reaction will be spontaneous. If the result is negative, then the reaction will be spontaneous.

As such, when then it follows that the reaction is spontaneous at high temperatures Option A.

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H₂O would be the limiting reactant.

Balanced chemical equation:

6CO₂ + 6H₂O + light equation → C₆H₁₂O₆ + 6O₂

The amount of product that can be created is constrained by the reactant that is consumed first in a chemical reaction, commonly referred to as the limiting reactant (or limiting reagent).

Given

No. of moles of CO₂ = 18.6

Mass of H₂O = 2.38 × 10² g = 238g

No. of moles of H₂O = Given mass/ Molar mass

                                = 238 / 18 = 13.22 moles

Moles of H₂O = 13.22

According to the balanced chemical equation

6 moles of CO₂ react with 6 moles of H₂O

So the reactant that has less number of moles will be consumed first.

As the No. of moles of H₂O < No. of moles of CO₂

So, H₂O is the limiting reactant with 13.22 moles.

Hence, H₂O would be the limiting reactant.

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From the forgoing, we can conclude that the the correct statements are;

The redox reaction is one in which one specie is oxidized and the other is reduced. We can obtain the equilibrium constant from the relation;

E°cell = 0.0592/n log K

E°cell = cell potential

n = number of electrons

K = equilibrium constant

E°cell = -0.403 - 0.535 = -0.938 V

n = 2 electrons

Thus;

-0.938 =  0.0592/2 logK

-0.938 * 2/ 0.0592 = log K

K = 2 * 10^-31

Also;

ΔG = - nFE°cell

ΔG = - (2 * 96500 *  -0.938)

ΔG = 181kJ/mol

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Sorry for the sloppy writing I tried my best.

If you can't read the words in my photo it says

Evaporation

condensation precipitation and runoff

definition of these words

evaporation: The process of turning liquid into vapor

Condensation:water which collects as droplets on a cold surface when humid air is in contact with

Precipitation: the action or process of precipitating a substance from a solution

runoff: liquid, especially water or rainwater, that flows off or drains away

I hope this is helpful

Sincerely- Your Brainly Bestfriend

Answer:

Explanation:

34.1 / 47.2 x 100%   =   0.07%

The percent yield (% yield) of Fe in a reaction with CO if the theoretical yield in the experiment is calculated to be 47.2 g Fe is 72.25%.

The percent yield is the percent ratio of the weight of the product obtained to the theoretical yield.

The percent yield can be calculated by dividing the experimental yield by the theoretical yield and multiplying the result by 100 then express the final answer in %.

According to this question, the experimental yield is 34.1g and the theoretical yield is 47.2g. The percent yield can be calculated as follows:

Percent yield = 34.1/47.2 × 100

Percent yield = 72.25%

Therefore, the percent yield (% yield) of Fe in a reaction with CO if the theoretical yield in the experiment is calculated to be 47.2 g Fe is 72.25%.

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