HL=
Help me asap!! Thanks so much I appreciate it :)

HL=Help Me Asap!! Thanks So Much I Appreciate It :)

Answers

Answer 1

The value of length HL is 8.

How to find HL when two secant intersect outside a circle?

A secant is a line that intersects a circle in exactly two points

When two secants intersect outside a circle, the circle divides the secants into segments that are proportional with each other.

Therefore,

(EF + FL)FL = HL(GH + HL)

(10 + 14)10 = (HL + 30 - HL)HL

240 = 30(HL)

divide both sides by 30

Hence,

240 / 30 = 30HL / 30

8 = HL

Therefore,

HL = 8

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Related Questions

Find the measure of the indicated angle to the nearest degree.

Answers

Answer:

24.315°

Step-by-step explanation:

First use the pythagorean theorem to get the missing side since this is a right triangle.

a^2 + b^2 = c^2 →

b^2 = c^2 – a^2 →

b = (c^2 – a^2)^½

b = (17^2 – 7^2)^½

b = (289 – 49)^½

b = √240.

Then use the law of cosines to find the angle in between.

b^2 = a^2 + c^2 - 2ac * cos(B) →

b^2 - a^2 - c^2 = -2ac * cos(B) →

a^2 + c^2 – b^2 / 2ac = cos(B) →

cos^-1(a^2 + c ^2 – b^2 / 2ac) = C →

B = cos^-1(a^2 + c ^2 – b^2 / 2ac)

B = cos^-1(49 + 289 – √240 / 238)

B ≈ 75.685°.

A = 180 – B

A = 180 – 75.685

A = 24.315°

Find the surface area of the pyramid with a regular pentagon as its base. Round to the nearest tenth if necessary. (13 is the length of the edge not the slant)

Answers

The surface area of this pyramid with a regular pentagon as its base is equal to 851.09 square units.

How to calculate the surface area?

In Mathematics, a complete circle has a magnitude of 360° and when it is divided by the 10 triangles, the angle formed at the center of the pentagon would always be equal to 36°.

Also, the length of the apothem of a pentagon can be calculated by using this formula:

a = s/2tan(36)

Where:

a represents the length of the apothem of a pentagon.s represents the length of the sides of a pentagon.

Substituting the given parameters into the formula, we have;

a = 10/2tan(36)

a = 10/1.45

a = 6.90 units.

Next, we would determine the slant height of this pyramid by applying Pythagorean theorem:

c² = a² + b²

c² = 6.9² + 13²

c² = 47.61 + 169

c² = 216.1

c = √216.1

c = 14.72 units.

For the surface area, we have:

Mathematically, the surface area of a pyramid with a regular pentagon as its base can be calculated by using this formula:

SA = 1.72l² × (5/2 × l × h)

SA = 1.72(14.72)² × (5/2 × 14.72 × 13)

SA = 372.69 + 478.4

SA = 851.09 square units.

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algebra 2: help please


a scuba diver enters the water 1m away from her boat. She dives down and then resurfaces 12m away from her boat. Her diving path id in the shape of a quadratic function, where x is the distance away from the boat and y is the distance away from the surface of the water, and negative values of y are below the water. She reaches a maximum depth of 30.25m below the surface of the water.

Her diving partner wants to estimate the diver’s depths at different points away from the boat. What is the diver’s depth when she is 4m away from the boat?

Answers

Answer:

  24 m depth

Step-by-step explanation:

The quadratic function modeling depth will have zeros at x=1 and x=12, the distances in meters from the boat where the diver is at the surface.

Quadratic function

The factored form of a quadratic function can be written as ...

  y = a(x -p)(x -q)

where p and q are zeros of the function. The value 'a' is a vertical scale factor.

Here, we are given y=0 at the surface, at points where x=1 and x=12. This means the function can be written as ...

  y = a(x -1)(x -12)

Scale factor

To find the value of 'a', we can use the maximum depth value. That depth will be halfway between the function zeros, at x = (1+12)/2 = 6.5

  -30.25 = a(6.5 -1)(6.5 -12)

  30.25 = 5.5²·a = 30.25a   ⇒   a=1

Model of depth

Then the function modeling the diver's depth in meters is ...

  y = (x -1)(x -12)

And the depth at x=4 will be ...

  y = (4 -1)(4 -12) = 3(-8) = -24 . . . . meters

The diver's depth is 24 meters when she is 4 m away from the boat.

If 3(x-3) = 5(2x + 1), then

Answers

x=-2

Step-by-step explanation:

Solution Given:

3(x-3) = 5(2x + 1)

Opening bracket we get

3x-9=10x+5

keeping common value in same side

-9-5=10x-3x

-14=7x

x=-14/7

x= -2

Answer:

-2 =x

Step-by-step explanation:

3(x-3) = 5(2x + 1)

To solve for x

Distribute

3x -9 = 10x +5

Subtract 3x from each side

3x-9-3x = 10x -3x+5

-9 = 7x+5

Subtract 5 from each side

-9-5 = 7x+5-5

-14 = 7x

Divide by 7

-14/7 = 7x/7

-2 =x

(Essay Worth 10 points)
(08.01 HC)
Use the function f(x) to answer the questions:
f(x) = 5x²+2x-3
Part A: What are the x-intercepts of the graph of f(x)? Show your work. (2 points)
Part B: Is the vertex of the graph of f(x) going to be a maximum or a minimum? What are the coordinates of the vertex? Justify your answers and show your work. (3 points)
Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph. (5 points)

Answers

The vertex of the function is a minimum and the coordinate of the vertex of the function is (0.2, -2.4)

Part A: What are the x-intercepts of the graph of f(x)

The function is given as:

f(x) = 5x^2 + 2x - 3

Expand the function

f(x) = 5x^2 + 5x - 3x - 3

Factorize the function

f(x) = (5x - 3)(x + 1)

Set the function to 0

(5x - 3)(x + 1) = 0

Solve for x

x = 3/5 and x =-1

Hence, the x-intercept is 3/5 and -1

Is the vertex of the graph of f(x) going to be a maximum or a minimum?

The vertex of the function is a minimum.

This is so because the leading coefficient of the function is positive

What are the coordinates of the vertex?

Here, we have:

f(x) = 5x^2 + 2x - 3

Differentiate and set to 0

10x + 2 = 0

Solve for x

x = -0.2

Substitute x = -0.2 in f(x) = 5x^2 + 2x - 3

f(0.2) = 5(0.2)^2 + 2(0.2) - 3

Evaluate

f(0.2) = -2.4

Hence, the vertex of the function is (0.2, -2.4)

What are the steps you would use to graph f(x)?

To do this, we simply plot the x-intercept and the vertex.

And then connect the points

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PLEASE HELP FAST!

A cylinder and a cone have the same volume. The cylinder has radius x
and height y. The cone has radius 1/2x. Find the height of the cone in terms of y.

Answers

The height of the cone in terms of y is h = 12x⁴y

How to find the volume of a cone and cylinder?

The cylinder and the cone have the same volume.

Volume of a cylinder = πr²h

where

r = radiush = height

Therefore,

Volume of a cylinder = πx²y

volume of a cone = 1 / 3 πr²h

where

r = radius of the coneh = height of the cone

Therefore,

πx²y = 1 / 3 × π × (1 / 2x)² × h

πx²y = πh / 12x²

πx²y × 12x² / π = h

h = 12x⁴y

Therefore, the height of the cone in terms of y is h = 12x⁴y

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Two marbles are to be pulled from a bag that contains 2 yellow marbles, 4 green marbles, and 6 orange marbles. After the first marble is drawn, it is not replaced. What is the probability that two red marbles are chosen from the vase?

Answers

Using it's concept, the probability that two red marbles are chosen from the vase is of 0%.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that there are no red marbles, hence the number of desired outcomes is of 0, and there is a 0% probability that two red marbles are chosen from the vase.

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Two linear equations are shown.

A coordinate grid with 2 lines. The first line is labeled y equals StartFraction one-third EndFraction x plus 2 and passes through (negative 6, 0) and (0, 2). The second line is labeled y equals StartFraction 4 over 3 EndFraction minus 5.
What is the solution to the system of equations?

Answers

Answer:

x = 7; y = 4 1/3

Step-by-step explanation:

The solution is the point of intersection of the lines.

Read the point of intersection.

You can also solve the system using algebra.

y = 1/3 x + 2

y = 4/3 x - 5

1/3 x + 2 = 4/3 x - 5

x + 6 = 4x - 15

-3x = -21

x = 7

y = 1/3 x + 2

y = 1/3 × 7 + 2

y = 2 1/3 + 2

y = 4 1/3

Answer: x = 7; y = 4 1/3

5. During the season, the Rangers played 25 games. They won 14 of the games.
What fraction and percent of the games did they lose? Show your work in the
space below. Remember to check your solution.

Answers

Answer is 11/25 games lost which is 44%.

Step by step. 25 games minus 14 they won equals 11 games lost out of 25.

11 out of 25 = 11/25.

11/25 as a % - 11 divided by 25 = .44 which is 44%.

Check your work, 44% of 25 games = 11 games lost.
Problem solved.

Daniela recorded the low temperatures during the school day last week and this week. Her results are shown in the table below.

Low Temperatures during the School Day This Week and Last Week
Low Temperatures
This Week (Degrees Fahrenheit)

42

38

45

46

39
Low Temperatures
Last Week (Degrees Fahrenheit)

56

58

52

62

62

Daniela used the steps below to find a relationship between the difference in the mean temperatures and the mean absolute deviations of the data sets.

This Week Last Week

Step 1
Find the mean.
StartFraction 42 + 38 + 45 + 46 + 39 over 5 EndFraction = 42
Find the mean.
StartFraction 56 + 58 + 52 + 62 + 62 over 5 EndFraction = 58

Step 2
Find the mean absolute deviation.
StartFraction StartAbsoluteValue 42 minus 42 EndAbsoluteValue + StartAbsoluteValue 38 minus 42 EndAbsoluteValue + StartFraction StartAbsoluteValue 45 minus 42 EndAbsoluteValue + StartFraction StartAbsoluteValue 46 minus 42 EndAbsoluteValue + StartFraction StartAbsoluteValue 39 minus 42 EndAbsoluteValue over 5 EndFraction = 2.8
Find the mean absolute deviation.
StartFraction StartAbsoluteValue 56 minus 58 EndAbsoluteValue + StartAbsoluteValue 58 minus 58 EndAbsoluteValue + StartFraction StartAbsoluteValue 52 minus 58 EndAbsoluteValue + StartFraction StartAbsoluteValue 62 minus 58 EndAbsoluteValue + StartFraction StartAbsoluteValue 62 minus 58 EndAbsoluteValue over 5 EndFraction = 3.2
Step 3 Find the ratio of the differences of the means compared to the mean absolute deviation.
StartFraction 42 over 2.8 EndFraction = 15 Find the ratio of the differences of the means compared to the mean absolute deviation.
StartFraction 58 over 3.2 EndFraction = 18.125
Step 4 The difference in the means is about StartFraction 15 + 18 over 2 EndFraction = 16.5 times the mean absolute deviations.

In which step did Daniela make the first error?

Answers

Based on the information given about the temperature, Daniela made her error on step 3 because it says: "Find the ratio of the differences of the means compared to the mean absolute deviation.

How to illustrate the error?

From the information given, it van be seen that Daniela recorded the low temperatures during the school day last week and this week and her results are shown in the table.

Here, she didn't find the difference between the today and last week means. She just put the mean as a whole.

Therefore, Daniela made her error on step 3 because it says: "Find the ratio of the differences of the means compared to the mean absolute deviation. This was the error.

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Which equation represents a population of 370 animals that decreases at an annual rate of 11% ?

Answers

The equation represents a population of 370 animals that decreases at an annual rate of 11% is [tex]p=370(0.89)^{t}[/tex].

What is an exponential function?

It is defined as the function that rapidly decreases and the value of the exponential function is always positive. It denotes with exponent y = a^x

where a is a constant and a>1.

Given that,

A population of 370 animals that decreases at an annual rate of 11%

a = 370, r = 11%

p = [tex]a(1-r)^{t}[/tex]

 =  [tex]370(1-0.11)^{t}[/tex]

p  =  [tex]370(0.89)^{t}[/tex]

Hence, The equation represents a population of 370 animals that decreases at an annual rate of 11% is [tex]p=370(0.89)^{t}[/tex].

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Geometry: fill in the blanks, ASAP!!!

Answers

5. Alternate interior angles: ∠1 ≅ ∠5; ∠5 ≅ ∠7 and ∠4 ≅ ∠6

6. Alternate exterior angles: ∠3 ≅ ∠9 and ∠2 ≅ ∠8

7. Corresponding angles: ∠2 ≅ ∠6; ∠3 ≅ ∠7; ∠5 ≅ ∠9; ∠4 ≅ ∠8 and ∠1 ≅ ∠3

8. Vertical angles: ∠2 ≅ ∠4; ∠3 ≅ ∠5; ∠7 ≅ ∠9; and ∠6 ≅ ∠8 .

9.  ∠1 and ∠7.

What are the Special Pairs of Angles Formed by a Transversal and Parallel Lines?

If two lines that are cut across by a transversal are parallel, the following special angles are formed:

Corresponding angles which are congruent: they share the same corner and lie along a transversal.Alternate interior angles which are congruent: they lie opposite each other along the transversal inside each parallel lines.Alternate exterior angles which are congruent: they lie opposite each other along the transversal outside each parallel lines.Vertical Angles which are congruent: they are directly opposite each other and share the same vertex but they are non-adjacent.

Given the image given, we can identify the following special angles:

5. Alternate interior angles: ∠1 ≅ ∠5; ∠5 ≅ ∠7 and ∠4 ≅ ∠6

6. Alternate exterior angles: ∠3 ≅ ∠9 and ∠2 ≅ ∠8

7. Corresponding angles: ∠2 ≅ ∠6; ∠3 ≅ ∠7; ∠5 ≅ ∠9; ∠4 ≅ ∠8 and ∠1 ≅ ∠3

8. Vertical angles: ∠2 ≅ ∠4; ∠3 ≅ ∠5; ∠7 ≅ ∠9; and ∠6 ≅ ∠8 .

9.  ∠1 ≅ ∠3 and ∠3 ≅ ∠7. So the two angles would be ∠1 ≅ ∠7.

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what is the formula to calculate area of square ​

Answers

Answer:

Step-by-step explanation:

A square is made up of 4 sides that are equal in length. They can all be called "x" or "s" or whatever variable you want. The formula for the area of a square (and also the area of a rectangle) is Area = side × side.

If you called your sides "x", then the formula is A = x × x or A = x². Another way to note the area of either a square or a rectangle is to call the "bottom" the base and one of the sides the height and then the area formula looks like this:

A = b × h

or

A = length × width

They are all the same thing.

PLS HELP ITS MATH PLS

Answers

Answer:

Step-by-step explanation:

y=-1/2x+6

Let x = a bi and y = c di and z = f gi. which statements are true? check all of the boxes that apply. x y = y x (x × y) × z = x × (y × z) x – y = y – x (x y) z = x (y z) (x – y) – z = x – (y – z)

Answers

The first one , the second one ,the fourth one are true.

What is a commutative property in math?

This law simply states that with addition and multiplication of numbers, you can change the order of the numbers in the problem and it will not affect the answer.

1)  x + y = y + x  = a + c (b +  d ) i                                      true

2) ( xy )z = x (yz) = (a + bi)(c + di)( f + gi)                           true

3) x - y = a + bi - ( c - di ) = a - c + ( b- d )i

    y - x = c + di - ( a+bi) = c-a +(d-b)i                                  false

4) (x + y ) + z = x + ( y + z ) = a + c +f + (b +d + g)i                 true

5) (x - y ) - z = a + bi - ( c + di) - ( f + gi)

                    = a - c . f + ( b- d - g) i

         x - ( y - z ) = a + bi - ( c + di - f - gi )

                          = a - c + f + ( b - d + g ) i

{ put the hypothesis into the equation and get the proof }

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Please answer quickly! It would be great if you could include the question # and the answer in the answer section, and then explain it below. Thank you in advance!

Answers

Answer:

[tex]\textsf{19.} \quad S_{20}=1490[/tex]

33.  None of these are correct.

Step-by-step explanation:

Question 19

General form of an arithmetic sequence:

[tex]a_n=a+(n-1)d[/tex]

where:

[tex]a_n[/tex] is the nth terma is the first termd is the common difference between terms

Given values:

[tex]a_n[/tex] = 27n = 20d = -5

Substitute the given values into the formula and solve for a:

[tex]\implies 27=a+(20-1)(-5)[/tex]

[tex]\implies 27=a+(19)(-5)[/tex]

[tex]\implies 27=a-95[/tex]

[tex]\implies a=27+95[/tex]

[tex]\implies a=122[/tex]

Sum of the first n terms of an arithmetic series:

[tex]S_n=\dfrac12n[2a+(n-1)d][/tex]

where:

a is the first term.d is the common difference.

Given values:

a = 122n = 20d = -5

Substitute the given values into the formula and solve:

[tex]\implies S_{20}=\dfrac{1}{2}(20)[2(122)+(20-1)(-5)][/tex]

[tex]\implies S_{20}=10[244-95][/tex]

[tex]\implies S_{20}=10[149][/tex]

[tex]\implies S_{20}=1490[/tex]

Question 33

Sum of the first n terms of a geometric series:

[tex]S_n=\dfrac{a(1-r^n)}{1-r}[/tex]

where:

a is the first termr is the common ratio

Given values:

a₁ = 1458r = ¹/₃

Substitute the given values into the formula and solve:

[tex]\implies S_6=\dfrac{1458\left(1-\frac{1}{3}^6\right)}{1-\frac{1}{3}}[/tex]

[tex]\implies S_6=\dfrac{1456}{\frac{2}{3}}[/tex]

[tex]\implies S_6=\dfrac{1456 \cdot 3}{2}[/tex]

[tex]\implies S_6=2184[/tex]

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90 times 2.5 divided by 3 +200,000?

Answers

Answer:

200,075

Step-by-step explanation:

90 times 2.5 = 225

225 divided by 3 = 75

75 + 200,000 = 200,075

Answer: 200075

Step-by-step explanation:

90 * 2.5 = 225

225 / 3 = 75

75 + 200,000 = 200,075

Michael is constructing a circle circumscribed about a triangle. he has partially completed the construction. what should be his next step in the construction?

Answers

Answer:

Connect the arcs to make a perpendicular bisector

Solve the system of equations by substitution.

3 /8 x +1/3y =17/24

x + 7y = 8

Answers

By substitution, the value of x and y are 1 and 1 respectively.

How to solve system of equation?

3 / 8 x + 1 /3  y = 17 / 24

x + 7y = 8

x = 8 - 7y

Let's substitute the value of x in equation(ii)

3 / 8(8 - 7y) + 1 / 3 y = 17 / 24

3 - 21 / 8 y + 1 / 3 y = 17 / 24

1 / 3 y - 21 / 8 y = 17 / 24 - 3

8y - 63y/24 =  17 - 72/ 24

-55y / 24 = -55 / 24

cross multiply

-1320y = -1320

divide both sides by -1320

y = -1320 / -1320

y = 1

Hence,

x + 7(1) = 8

x = 8 - 7

x = 1

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I need help on how to solve for Z

Answers

Answer:

[tex]z=\frac{t^{2}(m-3) }{4}[/tex]    or    [tex]z=\frac{1}{4}t^{2} (m-3)[/tex]

Step-by-step explanation:

[tex]t=\sqrt{\frac{4z}{m-3} }[/tex]

[tex]t^{2} =\frac{4z}{m-3}[/tex]

[tex]4z=t^{2} (m-3)[/tex]

[tex]z=\frac{t^{2}(m-3) }{4}[/tex]

Hope this helps

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each quadratic function with its respective graph. Graph Functions Graph of quadratic functions on a coordinate plane. Upward parabola vertex is at (2, 1) in quadrant 1. Left slope at (1, 2), (0, 5) enters quadrant 3. Right slope is at (3, 2), (4, 5) in quadrant 1. arrow Both Graph shows downward parabola plotted on a coordinate plane. The parabola has vertex at (minus 1, 4). The parabola has left slope at (minus 3, 0) and right slope at (1, 0). arrowBoth Graph shows upward parabola plotted on a coordinate plane. The parabola has vertex at (3, minus 4). The parabola has left slope at (1, 0) and right slope at (5, 0). arrowBoth

Answers

The correctly matched quadratic functions are given as follows:

Part A) The function of the First graph is f(x) = (x-3) (x + 1) Part B) The function of the Second graph is f(x) = -2 (x - 1) ( x + 3) Part C) The function of the Third graph is f(x) = 0.5(x - 6) (x + 2)

What is a Quadratic Function?

Quadratics are polynomial equations of the second degree, which means that they contain at least one squared term.

Quadratic equations are another name for it. The quadratic equation has the following general form: ax2 + bx + c = 0.

How do we correctly match the graphs?

Recall that:
f(x) - a (x -c) (x - d)

where

a is the leading coefficientc and d are the roots or zeros of the function.

Part A) First graph

We are given to know

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive, the function therefore, is equal to

f(x) = (x-3) (x + 1); Find the value of the coefficient a.

The vertex is equal to the point (1, -4)

Substitute and solve for a

-4 = a(1-3)(1+1)

-4 = a(-2)(2)

a = 1

Hence, the function is equal to f(x) = (x-3) (x + 1)

Part B) Second Graph

We are also given to know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to f(x) = a (x-1)(x+3)

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

to solve for a, we must substitute:

8 = a(-1-1) (-1+3)

8 = a(-2)(2)

a = -2

Hence, the function is equal to: f(x) = -2 (x - 1) ( x + 3)

Part C)

We are given to know that the solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to f(x)  = a(x-6) (x+2).

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

We substitute and solve for a:

-8 = a(2-6) (2+2)

-8 = a(-4)(4)

a = 0.5

Hence, the function is equal to f(x) = 0.5(x - 6) (x + 2)

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Find the sum of the geometric series 9000-900 +...+ 0.009

Answers

Based on the calculations, the sum of this geometric series is equal to 9,990.

The standard form of a geometric series.

Mathematically, the standard form of a geometric series can be represented by the following expression:

[tex]\sum^{n-1}_{k=0}a_1(r)^k[/tex]

Where:

a₁ is the first term of a geometric series.r is the common ratio.

How to calculate the sum of a geometric series?

Also, the sum of a geometric series is given by this mathematical expression:

[tex]S=\frac{a_1(1-r^n)}{1-r}[/tex]

Given the following data:

First term, a = 9000.Common ratio, r = 900/9000 = 0.1

Substituting the given parameters into the formula, we have;

[tex]S=\frac{9000(1-0.1^3)}{1-0.1}\\\\S=\frac{9000(1-0.001)}{1-0.1}[/tex]

S = 9000(0.999)/0.9

S = 8,991/0.9

S = 9,990.

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Students in Ms. Valendra’s science class planted 13 in different places around the school yard. After one month, they measured the heights of the conifers. They rounded each measurement to the nearest 1/4

Answers

Considering the dot plot, it is found that the tallest conifer is 3.25 inches taller than the shortest conifer.

What does a dot plot shows?

It shows, with dots, the number of times that each of the measures appears in a data-set.

Researching this problem on the internet, and finding the dot plot, we have that:

The shortest conifer measures 6 and 1/4 = 6.25 inches.The tallest conifer measures 9.5 inches.

The difference is:

9.5 - 6.25 = 3.25 inches.

Hence the tallest conifer is 3.25 inches taller than the shortest conifer.

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Please explain to me how to do this

Answers

#43

1+2+3+..+200We may observe. 200+1=201,199+2=201,198+3=201

So

200/2=100 pairs of 201

Sum

100(201)=20100

#44

1+2+3+..+400

400/2=200 pairs of 401

Sum

200+40180200

#45

1+2+3+..+800

800/2=400 pairs of 801

Sum

400(801)320400

#46

1+2+3+..+2000

2000/2=1000 pairs of 2001

Sum

2001(1000)2001000

Answer:

43.  20,100

44.  80,200

45.  320,400

46.  2,001,000

Step-by-step explanation:

Gauss's method

General formula for the sum of the first n integers:

[tex]1+2+3+ \dots +n=\dfrac{1}{2}n(n+1)[/tex]

Question 43

Given sum:  

1 + 2 + 3 + ... + 200

Therefore, n = 200.

Substitute the value of n into the formula:

[tex]\implies \dfrac{1}{2}(200)(200+1)=100 \cdot 201=20100[/tex]

Question 44

Given sum:  

1 + 2 + 3 + ... + 400

Therefore, n = 400.

Substitute the value of n into the formula:

[tex]\implies \dfrac{1}{2}(400)(400+1)=200 \cdot 401=80200[/tex]

Question 45

Given sum:  

1 + 2 + 3 + ... + 800

Therefore, n = 800.

Substitute the value of n into the formula:

[tex]\implies \dfrac{1}{2}(800)(800+1)=400 \cdot 801 =320400[/tex]

Question 46

Given sum:  

1 + 2 + 3 + ... + 2000

Therefore, n = 2000.

Substitute the value of n into the formula:

[tex]\implies \dfrac{1}{2}(2000)(2000+1)=1000 \cdot 2001=2001000[/tex]

solve the following system {y=x^2-3 and {y=3x-3 graphically and algebraicallyPLEASE HELP ME IM BEGGING

Answers

Answer:

There are two solutions:  
x = 0, y = -3  Point (0, -3)
x = 3, y = -6  Point (3, 6)

The solutions are at the intersections of the two individual graphs corresponding to each of the two equations (see attached figure)

Step-by-step explanation:

Use a graphing calculator or tool to plot each equation. The point of intersection of the two is the solution to the system of equations. See attached image

Algebraically

The first equation must be equal to the second equation for a unique value of y and x

[tex]y = x^2 - 3 = 3x -3\\x^2 - 3 = 3x - 3[/tex]

Subtract 3x - 3 from both sides giving

[tex]x^2 - 3 - (3x -3) = 0\\x^2 -3 -3x + 3 = 0\\x^2 - 3x = 0\\[/tex]

Factoring out x we get
[tex]x(x-3) = 0[/tex]

This means that x = 0 and also
x -3 = 0, or x = 3

Substituting for x = 0 in y = 3x-3 gives
y = 3.0 - 3 = -3
So x= 0, y = -3 is one solution (0,-3)

Substituting for x = 3 in the same equation gives
y = 3(3) - 3 = 6
So x = 3, y = 6 is another solution (3, 6)

Leo is 23 years old and works for a company that matches his 401(k) contribution up to 4.6%. the interest rate for his 401(k) is 5.32%. if he puts away 8% of his $65,000 salary every year, how much would he have saved in 10 years? round your answer to the nearest cent. a. $7110,127.51 b. $104,564.67 c. $65,582.40 d. $62,269.66

Answers

The amount saved in 10 years is = $1,04,461.13

The correct option is B.

Future:

An annuity is a series of payments that are distributed evenly over time.

One way to express the future value of an annuity of payment P for n years is,

Total salary is $65000

The interest rate is 5.32%

Trent save 8%  of his salary every year.

Company puts  4.6% of salary every year.

[tex]\text { Future Value }=\mathrm{P} \times \frac{\left(1+\frac{i}{n}\right)^{n t}}{\frac{i}{n}}[/tex]

Given:

Total salary is $65000

The interest rate is 5.32%

Trent save 8% of his salary every year.

Company puts  4.6%of salary every year.

The 8% of salary is calculated as:

[tex]\text { Amount } &=\frac{8}{100} \times 65000\\[/tex]

               [tex]&=\$ 5200[/tex]

The following information is available on the company's put:

[tex]\text { Amount } &=\frac{4.6}{100} \times 65000\\[/tex]

                [tex]&=\$ 2990[/tex]

Total amount as follows:

[tex]\begin{aligned}\text { Amount } &=5200+2990 \\&=\$ 8190\end{aligned}[/tex]

The future value can be obtained as follows

[tex]\begin{aligned}\mathrm{FV} &=8190 \times \frac{(1+0.053)^{10}-1}{0.053} \\&=8190 \times 12.75 \\&=1,04,461.13\ \\\end{aligned}[/tex]

Hence, the amount saved in 10 years is = $1,04,461.13

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Urve revolves around the x-axis. if you cannot evaluate the integral exactly, use your calculator to approximate it. (round your answer to four decimal places. ) y = 16 − x2 from x = −1 to x = 1

Answers

The value of integration of y=16-[tex]x^{2}[/tex] from x=-1 to x=1 is 94/3.

Given the equation y=16-[tex]x^{2}[/tex] and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-[tex]x^{2}[/tex] from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16-[tex]x^{2}[/tex]

Find the integration of 16-[tex]x^{2}[/tex].

=16x-[tex]x^{3}/3[/tex]

Now find the value of integration from x=-1 to x=1.

=16(1)-[tex](1)^{3}/3[/tex]-16(-1)-[tex](-1)^{3}/3[/tex]

=16(1)-1/3+16-1/3

=32-2/3

=(96-2)/3

=94/3

Hence the value of integration of y=16-[tex]x^{2}[/tex] from x=-1 to x=1 is 94/3.

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ll
Your Turn:
Simplify the following expressions by combining like term
1) 4x + 7 + 2x
2) -4x+3y-3x+8+2y

Answers

Answer:

[tex]\Large\boxed{1)~6x+7}[/tex]

[tex]\Large\boxed{2)~-7x+5y+8}[/tex]

Step-by-step explanation:

Question 1: 4x + 7 + 2x

Given expression

4x + 7 + 2x

Move like terms together

= 4x + 2x + 7

= (4x + 2x) + 7

Combine like terms

[tex]\Large\boxed{=6x+7}[/tex]

Question 2: -4x+3y-3x+8+2y

Given expression

-4x + 3y - 3x + 8 + 2y

Move like terms together

= -4x - 3x + 3y + 2y + 8

= (-4x - 3x) + (3y + 2y) + 8

Combine like terms

[tex]\Large\boxed{=-7x+5y+8}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Graduate management aptitude test (gmat) scores are widely used by graduate schools of business as an entrance requirement. suppose that in one particular year, the mean score for the gmat was 473, with a standard deviation of 104. what values are three standard deviations within the mean?

Answers

The values that exist two standard deviations above and below the mean are 681 and 265.

How to determine the values?

The given parameters exist:

Mean = 473

Standard deviation =104

The values above and below the mean exist calculated utilizing:

[tex]$x=\bar{x} \pm n \sigma$[/tex]

In this case n = 2.

So, we have, [tex]$x=\bar{x} \pm 2 \sigma$[/tex]

The value above is:

x = 473 + 2 [tex]*[/tex] 104 = 681

The value below is:

x = 473 - 2 [tex]*[/tex] 104 = 265

Therefore, the values that exist two standard deviations above and below the mean are 681 and 265.

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Re-write the quadratic function below in Standard Form y=-5(x+1)²+7

Answers

Answer:

y = - 5x² - 10x + 2

Step-by-step explanation:

y = - 5(x + 1)² + 7 ← expand (x + 1)² using FOIL

  = - 5(x² + 2x + 1) + 7 ← distribute parenthesis by - 5

 = - 5x² - 10x - 5 + 7 ← collect like terms

 = -5x² - 10x + 2 ← in standard form

Answer: y = -5x² - 10x + 2

Step-by-step explanation:

Given quadratic function

y = -5 (x + 1)² + 7

Given requirement

Quadratic Standard Form: y = ax² + bx + c

Simplify the exponents

y = -5 (x + 1) (x + 1) + 7

y = -5 (x² + x + x + 1) + 7

y = -5 (x² + 2x + 1) + 7

Expand the parenthesis by distributive property

y = (-5) · x² + (-5) · 2x + (-5) · 1 + 7

y = -5x² + (-10x) + (-5) + 7

y = -5x² - 10x - 5 + 7

Combine like terms

[tex]\Large\boxed{y=-5x^2-10x+2}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

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