HELP ‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️WILL MARK BRAINLYEST‼️‼️‼️

In my wallet, I have one-dollar bills, five-dollar bills, and ten-dollar bills. The total amount in my wallet is
$43. I have four times as many one-dollar bills as ten-dollar bills. Altogether, there are 13 bills in my wallet.
How many of each bill do I have?

Answer:

Step-by-step explanation:

To find the x intercepts, substitute in 0 for y and solve for x

So,

2x^2+2x-4 = 0

2(x^2+x-4) = 0

2/2(x^2+x-4) = 0/2

x^2+x-4 = 0

(x-1) (x+2) = 0

now,

x-1 = 0

x = 1

or

x+2 = 0

x = -2

The x intercepts for the parabola (1,0), (-2,0)

These are some of the ways you can make 15 by adding three numbers together.

The first way is doing  6+6+3.There are some more ways to do it too.

2nd way is 6+4+5.

3.   1+6+6

4.   5+5+5

The probability of correctly picking the two numbers is 2/10.

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

The more likely the event is to happen, the closer the probability value would be to 1. The less likely it is for the event not to happen, the closer the probability value would be to zero.

The probability of correctly picking the two numbers = (numbers that have to be selected to win / total numbers)

2/10

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The value of the mean absolute percentage error of the forecast for march found by the exponential smoothing method with a smoothing constant of 0. 3 is  16.94%

The equation is given as

∝At + (1-∝) Ft

The value for Alpha = 0.7

1 - ∝ = 1 - 0.7

= 0.3

Forecast in match = 62

Ft = 51. 5

the difference = 62 - 51.5

= 10.5

The error = 10.5/62 * 100

= 16.94%

Hence the value of the  mean absolute percentage error of the forecast for march found by the exponential smoothing method with a smoothing constant of 0. 3 is  16.94%

The past demand data shown below can be regarded as stationary.

Month Demand

January

50

February

55

March

62

April

45

What is the mean absolute percentage error of the forecast for March found by the exponential smoothing method with a smoothing constant of 0.3?

O a. 14.68%

Ob. 16.94%

O c. 12.57%

Od. 11.33%

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Answer:

30%

Step-by-step explanation:

1) Based on the given conditions, formulate:

30 meters/100 meters

2) Calculate 30 meters/100 meters:

3/10

3) Convert to percentage:

- 3/10 x 10/10

- 3x10/10x10

30/100

30/100 = 30%

You’re done!

Also, if you could label this brainliest that would be a great help!

Thanks xx

-Dante

Answer:

Hey! I'm gonna go ahead and give ya the "meaning" of the fundamental theorem of algebra but not the answer to the A. B. and C.

Step-by-step explanation:

fundamental theorem of algebra, theorem of equations proved by Carl Friedrich Gauss in 1799. It states that every polynomial equation of degree n with complex number coefficients has n roots, or solutions, in the complex numbers. The roots can have a multiplicity greater than zero.

[tex]1.2 \: degrees \: drop \: a \: day \\ 14 \: days \: in \: two \: weeks \\ net \: change = 14 \times 1.2 = 16.8 \: deg[/tex]

Using the formula for a z-distribution confidence interval of proportions, he also needs to know the confidence level.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

Of these 3 itens, the problem states that he knows the sample size and the sample proportion, hence he needs to know z to determine the confidence interval. z depends on the confidence level, which is the remaining parameter.

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By simplifying the fraction 10/28 ÷ 32/49 exists 35/64.

The first stage of dividing fractions exists to estimate the reciprocal (reverse the numerator and denominator) of the second fraction. Subsequently, multiply the two numerators. Then, multiply the two denominators. Finally, simplify the fractions if required.

To find the reciprocal of the divisor

Reciprocal of 32/49 = 49/32

Now, multiply it by the dividend, then we get

So, 1028 ÷ 3249 = 10/28 × 49/32

= (10 × 49)/(28 × 32) = 490/896

After decreasing the fraction, the answer exists at 35/64.

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Answer:

$40/unit?

Step-by-step explanation:

I'll assume the the fixed and variable costs are for 2000 units.

Fixed Costs = $35,000

Variable Costs = $45,000

Tota Costs = $80,000

The selling price can be anything. Free and we lose $80,000; $40 each, net profit of $0; $100 each for a net profit of $120,000.

In the absence of any infoprmation regarding selling price (e.g., 50% profit margin), I'd select the $40/unit selling price since that is breakeven.

Answer: $4.50

Step-by-step explanation:

Original Price: $6

Discount: 25%

Discounted Price: 6*25%= $1.5

                              $6-$1.5= $4.5

The statement that is true about the box plots is: D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

For a data distribution that is displayed by a box plot, the measure of variation that can be used to describe the data distribution is the interquartile range.

Interquartile range, which is a measure of variation can be determined from a box plot by finding the value of the third quartile and first quartile, the finding their difference. The difference is the interquartile range.

Interquartile range = third quartile - first quartile.

Interquartile range for crackers = 85 - 75

Interquartile range for crackers = 10

Interquartile range for trail mix = 105 - 90

Interquartile range for trail mix = 15.

The bigger the value of the interquartile range, the more variation there is that exist in a data distribution.

Interquartile range for trial mix is the largest, therefore, the statement that is true about the box plots is: D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

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we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.

Here we want to find the last digit of the product between all the whole numbers larger than 11 and smaller than 29.

Then we have the product:

P = 12*13*14*15*16*17*18*19*20*21*22*23*24*25*26*27*28

Now, notice that there is a 20 there.

Any number times 20 will end with a zero, then:

P = 20*(12*13*14*15*16*17*18*19*21*22*23*24*25*26*27*28)

Only with that, we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.

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Hi there,

please see below for solution steps :

‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗

First let us revise the rounding rules before getting down to the process of rounding :

[tex]\sf{763.9 \ to \ the \ nearest \ whole \ number :}\\\hfill\stackrel{\small\text{add 1 }}{3^{+1}}.\\\hfill\stackrel{\small\text{drop it}}{9}}[/tex]

[tex]\sf{763.9\approx764}[/tex]

‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗

C = 3r + 15 is the rule for the total cost, C, where r rides are taken given that the total cost charged for a day of fun at Aussie World consists of an entry fee of $15 and a rate of $3 per ride. This can be obtained by converting the statements to algebraic equation with variables and constants.

Here in the question it is given that,

The total cost charged for a day of fun at Aussie World consists of

We have to find a rule for the total cost, C, where r rides are taken.

For one ride the rate is 3 ⇒ therefore for r rides the rate is 3r

We can convert the statements to algebraic equation so that we get the required rule,

⇒ The total cost consists of entry fee and rate of rides

⇒ The total cost = entry fee + rate of rides

⇒ C = 15 + 3r (from the given information)

⇒ C = 3r + 15

Hence C = 3r + 15 is the rule for the total cost, C, where r rides are taken given that the total cost charged for a day of fun at Aussie World consists of an entry fee of $15 and a rate of $3 per ride.

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Answer:

75%

Step-by-step explanation:

3/4 ie 75/100. .........edge

Answer:

6.5%

Step-by-step explanation:

I = prt

5616 = 7200 × r × 12

r = 5616/(7200 × 12)

r = 0.065

r = 6.5%

Answer:

Tools used to construct a bisector are 1》pencil ,2》Eraser ,3》protector ,4》Compass ,5》Sharpner etc ....

Answer: 40 inches

Step-by-step explanation: If the 20 points on the line were spaced 1 inch apart, the result would be 20 inches. Each point you're going to is 1 inch in spacing and there is only going to be 20 inches of spacing (1 inch per point.)

For 2 inches spaced apart, the result would be simply 40 inches. You just need to add the distance of 20 more to the already distance of 20 points, since if 2 were to be divided, it would be 1, which is 20 inches in distance as stated. Another 20 points would be another inch in distance, and adding them gives you 2 inches in distance or 40 inches all together.

I apologize if I wasn't clear enough, I couldn't find a way to explain it as good as I thought it was in my mind.

Hope it helped though!

Using it's concept, the domain of the function is given as follows:

{x| –2 ≤ x <= 5}

The domain of a function is the set that contains all possible input values for the function.

The function described is defined for x between -2 and 5, hence the domain is given by the following interval:

{x| –2 ≤ x <= 5}

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Answer:

{x| –2 ≤ x < 5}

Step-by-step explanation:

Answer:

4.378 MPH

Step-by-step explanation:

          Distance in Miles

MPH= -------------------------

           Time in Hours

19.7/4.5 = 4.378 MPH

The corresponding angles are ∠2 and ∠6 i.e., ∠2≅∠6 according to the corresponding angles theorem. So, option 2 is correct.

The theorem states that,

The lines 'AB' and 'CD' are parallel and cut by a transverse 'EF' if and only if their corresponding angles are congruent.

The corresponding angles are those which lie on the same side of the transverse one is interior and the other is an exterior angle.

From the diagram,

Lines 'AB' and 'CD' are parallel and line 'EF' cuts these parallel lines.

So, the corresponding angles formed are:

(∠1, ∠5), (∠2, ∠6), (∠3, ∠7), and (∠4, ∠8)

According to the theorem, they are congruent. I.e.,

∠1 ≅ ∠5

∠2 ≅ ∠6

∠3 ≅ ∠7

∠4 ≅ ∠8

So, option 2 is correct.

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Disclaimer: The given question is incorrect. Here is the correct question.

Question: Lines 'c' and 'd' are parallel lines cut by the transversal 'p'. Which must be true by the corresponding angles theorem?

1) ∠1 = ∠7

2) ∠2 = ∠6

3) ∠3 = ∠5

4) ∠5 = ∠7

Answer:

figure A = 3 units

figure B = 9 x 3 = 27 units

scale factor =

[tex] \frac{3}{27 } = \frac{1}{9} [/tex]

so the scale factor = 9

The periodic time, t, of a pendulum range directly as the square root of its length, l. t = 6 when l = 9. If l = 25 then the periodic time, T exists at 10.

The period, or periodic time, of a periodic variation of a quantity, exists described as the time interval between two consecutive repetitions.

Given: The periodic time, t, of a pendulum goes directly as the square root of its length, l if t = 6 when l = 9.

If [tex]T \alpha\ l^2[/tex] then [tex]T^2[/tex] α [tex]\sqrt{l}[/tex]

[tex]T^2 = l[/tex]

Let, [tex]T^2 = kl,[/tex] where k exists constant

t = 6 when l = 9.

So, [tex]6^2 = k*9[/tex]

[tex]k = 6^2/9 = 4[/tex]

[tex]T^2 = 4*l[/tex]

If l = 25

[tex]T^2 = 4 * 25 = 100[/tex]

[tex]T = \sqrt{100}[/tex]

T = 10

Therefore, the periodic time, T exists 10.

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The p-value from the information about the recently televised broadcast is B. 0.9999.

From the information given, n = 5000 and the level of significance is 0.01.

The computed z value is -8.84.

From the z table, the probability value is the value corresponding to the row 8.8 and column 0.04.

This will give a value of 0.9999.

In conclusion, the correct option is B.

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Answer:

1178 because 31 dollars an hour for 38 hours you would multiply or times 31 and 38 and get 1178 for total money earned

The lower and the upper class limit are as follows

interval  lower limit  upper limit

10-14          10                14

15-19          15                19

20-24         20              24

25-29           25            29

This is further explained below.

Generally, The lower class limit and the upper-class limits are just the minima and maximum values that are allowed in each class, respectively: The gap that exists between the upper-class limit and the lower class limit is referred to as the class interval.

In conclusion, The lower and the upper class limit are as follows

interval  lower limit  upper limit

10-14          10                14

15-19          15                19

20-24         20              24

25-29           25            29

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Answer: A. V: x = –4; H: y = 4

Step-by-step explanation:

[tex] \sqrt[4]{ - 8} [/tex]