Given that it was less than 80º on a given day, what is the probability that it also rained that day? 0.3 0.35 0.65 0.7

[tex]a=3x^3\hspace{5em}b=4x^4 \\\\[-0.35em] ~\dotfill\\\\ c=ab^2\implies c=(\underset{a}{3x^3})(\underset{b}{4x^4})^2\implies c=(3x^3)(4^2x^{4\cdot 2}) \\\\\\ c=3x^3\cdot 16x^8\implies c=(3\cdot 16)x^{3+8}\implies c=48x^{11} \\\\[-0.35em] ~\dotfill\\\\ \boxed{bc}\implies (\underset{b}{4x^4})(\underset{c}{48x^{11}})\implies (4\cdot 48)x^{4+11}\implies \boxed{192x^{15}}[/tex]

Answer:

  bc = 192x^15

Step-by-step explanation:

Perform substitution as required, then simplify.

  bc = b(ab^2) = ab^3 = (3x^3)(4x^4)^3 = (3·4^3)(x^3)(x^(4·3))

  = 192x^(3+12)

  bc = 192x^15

__

Additional comment

The relevant rules of exponents are ...

  (ab)^c = (a^c)(b^c)

  (a^b)^c = a^(bc)

  (a^b)(a^c) = a^(b+c)

The domain is the water balloon's height increasing will be (0, 2), staying the same will be (2, 4), decreasing the fastest will be (6, 10), and the height of the water balloon at 16 seconds the will be 0.

The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds.

Part A:

As seen from the graphic, increase from 0 to 2 sec.

The domain is (0, 2), where the height of the water balloon increases.

Part B:

The water balloon stays the same from 2 to 4 sec.

The field means that the height of the water balloon remains the same (2, 4).

Part C:

Height decreasing fasted at 4 to 6 sec.

Because the slope is steepest downward from 4 to 6 sec as comfort to 6 to 10 sec.

The domain is where the height of the water balloon decreases rapidly (6, 10).

Part D:

The balloon's height will be almost near the ground as resistance will play its role.

But it will almost touch the ground.

The height of the water balloon will be 0 in 16 seconds.

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Answer:

Point A

Step-by-step explanation:

See attached worksheet.

The sum of the geometric series is 2199; option E.

S6 = a(rⁿ - 1) / r -1

= 1468(1/3^6 - 1) / (1/3 - 1)

= 1468(0.00137174211248 - 1) / -2/3

= 1468(-0.9986282578875) / -0.66666666666666

= -1,465.98628257885 / -0.66666666666666

= 2198.97942386829

Approximately,

S6 = 2199

Arithmetic series

Sn = n/2{2a + (n -1)d}

= 36/2 {2×27 + (36-1)-5/2}

= 18{54 + (35)-5/2}

= 18(54 + 175/2)

= 18(54 + 87.5)

= 18(141.5)

s36 = 2547

a36 = a + (n - 1) d

= 27 + (36 - 1)-5/2

= 27 + (35)-5/2

=27 + -175/2

= 27 - 87.5

= -60.5

S20 = n/2{2a + (n -1)d}

= 20/2{2×27 + (20-1)-5}

= 10(54 + (19)-5)

= 10{54 + (-95)}

= 10(54-95)

= 10(-41)

s20 = -410

Missing terms of the geometric sequence:

nth term = ar^n-1

448/135 = 63/80×r^(6-1)

448/135 = 63/80×r^5

r^5 = 448/135 ÷ 63/80

= 448/135 × 80/63

= 35,840/8,505

r = 5√35,840/5√8505

= 946.57/461.11

r = 2.05

Second term = a×r

= 63/80×2.05

= 1.614375

Third term = ar²

= 63/80×2.05²

= 63/80×4.2025

= 3.30946875

Fourth term = 63/80 × 2.05³

= 63/80×8.615125

= 6.7844109375

Therefore, none of these are correct

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Answer:

Find the interval of convergence of the following series

Possible Answers:

(4,6)

[4,6)

(4,6)

[4,6]

Correct answer:

(4,6)

Explanation:

Step-by-step explanation:

Find the interval of convergence of the following series

Possible Answers:

(4,6)

[4,6)

(4,6)

[4,6]

Correct answer:

(4,6)

Explanation:

Answer:

58, 66, 79, 84, 87 (see explanation for the exact answer)

Step-by-step explanation:

{58, 66, 79, 84, 87}

minimum = 58

lower quartile = 66

median = 79

upper quartile = 84

maximum = 87

Answer + Step-by-step explanation:

58, 60, 65, 67, 68, 72, 79, 79, 80, 81, 82, 86, 86, 87

The data set is in order then :

the minimum = 58

The maximum = 87

Determining the median :

first ,we notice that the data set has an even number (14) of numbers

Then

The median is the average of the two central values of the data set :

the two central values are the 7th and 8th numbers:

[tex]\text{median} =\frac{79+79}{2} =79[/tex]

Determining the lower quartile  :

The lower quartile is the median of the set :

58, 60, 65,  67 , 68, 72, 79

this set has an odd number (7) of values

Then

The central value is 67

Therefore

The lower quartile is 67

Determining the upper quartile  :

The upper quartile is the median of the set :

79, 80, 81,  82  , 86, 86, 87

this set has an odd number (7) of values

Then

The central value is the 4th number which is 82

Therefore

The upper quartile is 82

Interquartile range :

82 - 67 = 15

[tex]e-\frac{1}{e} +\frac{4}{3} 0r 3.687[/tex]  is the value when the equation is to integrate with respect to x or y

we integrate with respect to x

Area = [tex]\int\limits^b_a{(f(x)-g(x))} \, dx[/tex]

       = [tex]\int\limits^1_-1{e^{x}-x^{2} +1 } \, dx[/tex]

        =[tex]e^{x} -\frac{x^{3} }{3} +x[/tex]

   substitute 1 and -1 in place of x

  = [tex](e-\frac{1}{3}+1-\frac{1}{e} -\frac{1}{3} +1)[/tex]

  = [tex]e-\frac{1}{e} + \frac{4}{3} or 3.6837[/tex]

The diagram was attached in the given below.

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The angles and lengths of each of the given triangles are;

5) m∠B = 57.52°

6) B = 70.81°

7) AB = 55.43 Km

8) AC = 39.06 ft

The cosine rule is expressed as;

c = √[a² + b² - 2ab(cos C)]

5) Using cosine rule;

BC = √[21² + 13² - 2(21*13)(cos 91)]

BC = 24.89

Using sine rule, we can find angle B as;

21/sin m∠B = 24.89/sin 91

sin m∠B = (21 * sin 91)/24.89

sin m∠B = 0.8436

m∠B = sin⁻¹0.8436

m∠B = 57.52°

6) Using cosine rule;

14² = 11² + 13² - 2(11*13)(cos B)]

196 = 121 + 169 - 286(cos B)

cos B = (121 + 169 - 196)/286

cos B = 0.3287

B = cos⁻¹0.3287

B = 70.81°

7) Using cosine rule;

AB = √[24² + 36² - 2(24*36)(cos 134)]

AB = 55.43 Km

8) Using cosine rule;

AC = √[21² + 26² - 2(21*26)(cos 112)]

AC = 39.06 ft

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Answer:

Below in bold.

Step-by-step explanation:

This figure is a trapezoid.

We can find the missing side  length by applying the Pythagoras Theorem to the right triangle on the left of the figure.

The dotted line has length 12 cm and the base of the triangle = 25 - 18 = 7 cm

So x^2  = 12^2 + 7^2     (where x = missing length)

            =  144 + 49

            = 189

x = √189

  =  13.75 to nearest hundredth

So the perimeter

  =    18 + 12 + 25 + 13.75

  =    68.75 cm.

Area of a trapezoid = 1/2 (a + b) * h.

Area =  1/2 *(18 + 25) * 12

        =  258 cm^2.

Answer:

$700

Step-by-step explanation:

If he made a loss of 15%, then it means that selling price is 85% of the cost price.

If the cost price is x, then we have;

0.85x = 595

x = 595/0.85

x = $700

The verbal expression for the mathematical expression 5(x - 4) + 2 is the number 5 times the difference between an unknown x and the number 4 and plus 2.

It is defined as the combination of constants and variables with mathematical operators.

It is given that a mathematical expression as below:

= 5(x - 4) + 2

Here x is the unknown number

The number

Number 5 times the difference between an unknown x and number 4 and plus 2

Thus, the verbal expression for the mathematical expression 5(x - 4) + 2 is number 5 times the difference between an unknown x and number 4 and plus 2.

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x + 7 = -8

(x + 7) - (7) = -8 - (7)

x = -8 - 7 = -15

The correct answer is -15

❄ Hi there,

let us first consider this: What should we do to get x all alone, on one side of the equation?

Since

we should

[tex]\ \sf{x=-8-7}[/tex]

[tex]\triangleright \ \sf{x=-15}[/tex]

That's it!

❄

Inverse variation is the relationship that occurs between two quantities in which one decreases as the other increases.

The types of variation which exists are;

For instance;

The relationship between John's speed and distance is inversely proportional. If John's speed is 5km/h, his distance is 6km. Find John's distance when his speed increases to 6km/h.

s = k / d

where,

k = constant of proportionality

s = k / d

5 = k/6

30 = k

s = k / d

6 = 30/d

6d = 30

d = 30/6

d = 5 km

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Answer:

91.5 - 5.2 = 86.3

Step-by-step explanation:

The initial weight was 91.5 pounds.

The dog lost 5.2 pounds which means subtraction.

91.5 pounds subtracted by 5.2 pounds that the dog lost equals 86.3 pounds.

The conditional probability, in a single roll of two fair 6 sided dice, that the sum is greater than 6, given that neither die is a two : 17/25

We know that the conditional probability is given by,

P(B | A) = probability of occurrence of event B, given that event A has

               occurred

           = P(A ∩ B) / P(A)

Here, P(A ∩ B)  means the probability of happening two events A and B at the same time.

We also know that  if  P (B | A ) = P(B)   i.e.,   P(A ∩ B) = P(A) × P(B)  the two events A and B are independent of each other.

For this question, let the dice D1 and D2 are rolled once.  

Let the numbers displayed on the dice be d1 and d2 respectively.  

The dice D1 and D2 are independent.

We need to find the conditional probability that the sum is greater than 6, given that neither die is a two.

Let S represents the sum of the numbers displayed on the dice.

S = d1 + d2

The sum is even, if d1 = d2 is odd OR  if d1 = d2 is even

P(d1 = even) = 3/6

                    =1/2

P(d2=even) = 1/2

P(d1 = odd) = 1/2

P(d2 = odd) = 1/2

So, P(S = even) = [P(d1=even) × P(d2 = even)] + [P(d1= odd) × P(d2=odd)]

                          = [1/2 × 1/2] + [1/2 × 1/2]

                          = 1/2

So, we can say that, the sum is either even or odd which are equally likely and hence its probability is 1/2.

First we find the probability for the sum is greater than 6 i.e., P(S > 6)

The possible combination of d1 and d2 for the sum greater than 6 would be,

{(1,6), (2,5), (2, 6), (3, 4), (3, 5), (3, 6), (4,3), (4,4), (4,5), (4,6), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}

⇒ n(S > 6) = 21

The number of all possible outcomes = 36

So, P(S > 6) = 21/36

                   = 7/12

Now we find the probability that neither die is a two

⇒ P(neither die is a two) = [P(1) ∪ P(3 ≤ d1 ≤ 6)]  AND  [P(1) ∪ P(3 ≤ d1 ≤ 6)]

⇒ P(neither die is a two) = 5/6 × 5/6

⇒ P(neither die is a two) = 25/36

Now, we find the probability that the sum S > 6 AND  neither die is a two.

The possible combination for  the sum S > 6 AND  neither die is a two would be,

{(1,6), (3, 4), (3, 5), (3, 6), (4,3), (4,4), (4,5), (4,6), (5,3), (5,4), (5,5), (5,6), (6,1), (6,3), (6,4), (6,5), (6,6)}

⇒ n(S > 6 AND neither die is a two) = 17

So, P(S > 6 AND neither die is a two) = 17/36

Now we find the conditional probability P(S > 6 | neither die is a two)

⇒ P(S > 6 | neither die is a two) = P(S > 6 AND neither die is a two) ÷

                                                           (neither die is a two)

⇒ P(S > 6 | neither die is a two) = (17/36) / (25/36)

⇒ P(S > 6 | neither die is a two) = 17/25

Therefore, the conditional probability, in a single roll of two fair 6 sided dice, that the sum is greater than 6, given that neither die is a two : 17/25

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Answer: f(12) = 137, f(-7) = 42

Step-by-step explanation: In a function, what you want to do is plug in the value they give you for x. This means you substitute x with the value they are looking for.

In this case, they are looking at 12 and -7. Let's do 12 first.

The equation becomes (12^2) - 7. 12^2 is 144, and 144-7 is 137.

Now we do -7. The equation becomes (-7)^2 - 7. -7^2 is 49, and 49 - 7 is 42.

Hope this helped!

Answer:2,695

Step-by-step explanation: just add.

Answer:

False

Step-by-step explanation:

If two angles are right angles, then they are congruent.

Answer:

8 one-dollar bills

3 five-dollar bills

2 ten-dollar bills

Step-by-step explanation:

Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13

x + 5y + 10z = 43

x = 4z

x + y + z = 13

x + 5y + 10z = 43

x + 0y - 4z = 0

x + y + z = 13

5y + 14z = 43

-y - 5z = -13

5y + 14z = 43

-5y - 25z = -65

-11z = -22

z = 2

x = 4z

x = 4*2 = 8

x + y + z = 13

8 + y + 2 = 13

10 + y = 13

y = 3

Answer:

A ≈ 75 in²

Step-by-step explanation:

the area (A) of the circle is calculated as

A = πr² ( r is the radius )

here r = 5 and using 3 for π , then

A = 3 × 5² = 3 × 25 = 75 in²

Answer:

75 in^2

Step-by-step explanation:

Since the formula to find the area of a circle is already up, we can use that to solve the question.

The image gave us the value of the radius right away, so the question will be a lot easier to solve.

--> The reason why the radius is needed is that the 'r' in the formula means radius. We need the value of the radius to find the area of the circle.

Now, we can just replace r with 5.

--> A = 25 [tex]\pi[/tex]

Since the question told us to replace [tex]\pi[/tex] with 3, we can do that.

--> A = 25 x 3

--> A = 75

We can conclude that the area of the circle is 75 in^2.

The equation 35 = 15-24y represent the growth rate.

According to the statement

we have given that the

A weeping willow that is 15 feet in height grows to a maximum height of 35 feet in y years at a constant rate of 24 inches per year.

And we have to describe all conditions in the equation.

So,

firstly the given height of weeping pillow before growing is 15 feet.

It means the maximum real height it grows is to subtract from the maximum given height it grows.

it means we have to find the growth rate.

real height he grows is = 35-15 = 20 feet

And it grows at the 24 inches per year so, it means it become

24 y

By combining these we get the equations is

35 = 15-24y.

So, The equation 35 = 15-24y represent the growth rate.

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Disclaimer: This question was incomplete. Please find the full content below.

Question:

A weeping willow that is 15 feet in height grows to a maximum height of

35 feet in y years at a constant rate of 24 inches per year. Which of the following equations best describes this situation?

A. 37 = 15-24y

B. 35 = 15-24y

C. 35 = 15-22y

D. 39 = 15-27y

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Answer: 35= 15+2y

Step-by-step explanation:

I am taking the Khan Academy Lesson.

The answer choice which represents the domain and range of the function h(t) as given in the task content in which case, values are rounded to the nearest hundredth is; Domain: [0, 3.85] and Range: [0, 18.05].

It follows from convention that the domain of a function simply refers to the set of all possible input values for that function.

Also, the range of a function is the set of all possible output values for such function.

On this note, by observing the graph in the attached image, it follows that the Domain of the function in discuss is; [0, 3.85].

While the range is the difference between the minimum and maximum height attained and can be computed as follows;

At minimum height, t = 0; hence, h(t) = 0.

At maximum height; h'(t) = 0 where h'(t) = h'(t)=-9.74t+18.75 and hence, t = 1.92.

Hence, h(1.92) = 18.05.

The range is therefore; [0, 18.05].

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Answer:

  D.  x ≈ 2.60

Step-by-step explanation:

The equation we have graphed is the one shown in the attachment. It is slightly different from the one in this problem statement.

It is often convenient to find a graphical solution to an equation by writing it in the form ...

  f(x) = 0

Then the solutions are the x-intercepts of the graph, points that most graphing calculators can readily identify.

We have done this here by defining ...

  [tex]y_1=3x^2-6x-4\\\\y_2=-\dfrac{2}{x+3}+1[/tex]

The graph is of y₁ -y₂. X-values where y₁-y₂ = 0 are solutions to the original equation, y₁ = y₂.

This equation is seen to have three solutions, approximately ...

  x = {-3.05, -0.55, 2.60}

Of these, only x ≈ 2.60 is listed among the answer choices.

__

Additional comment

The value of y₁ -y₂ expressed in standard form is ...

  [tex]3x^2-6x-4+\dfrac{2}{x+3}-1=0\\\\\dfrac{(x+3)(3x^2-6x-5)+2}{x+3}=0\\\\\dfrac{3x^3+3x^2-23x-13}{x+3}=0\\\\3x^3+3x^2-23x-13=0\quad(x\ne -3)[/tex]

The irrational solutions to this cubic can be found "exactly" by any of several applicable formulas. Numerical solutions are almost trivial to find with appropriate technology.

  x ≈ {−3.04857564747, −0.547524627423, 2.5961002749}.

Answer:

see photo

Step-by-step explanation:

Plato/Edmentum

Step-by-step explanation:

Since you haven't provided any functions, I can answer this question generally as to what the function would look like.

So when a polynomial has an even degree, then the two end behaviors will go in the same direction, and when it has an odd degree, then the two end behaviors will be in opposite directions. When a polynomial has a positive leading coefficient the right side will go towards infinity, and if a polynomial has a negative leading coefficient the right side will go towards negative infinity.

So let's look at the information:

As x approaches negative infinity, y approaches positive infinity.

Just given this we can't really say anything about the polynomial since we have to relate this to the right end behavior, or as x approaches infinity, so let's look at that.

As x approaches positive infinity, y approaches negative infinity.

This means that as x increases, y decreases, so that means the leading coefficient is negative. Since we know both end behaviors, and they're opposite (one y-value goes to negative infinity, and the other positive infinity), that means the polynomial is an odd degree.

So this means the polynomial will look something like this:

[tex]ax^n+bx^{n-1}+cx^{n-2}...[/tex]

where the leading coefficient "a" is negative and the degree of the polynomial (degree of leading coefficient) will be odd.

Answer:A

Step-by-step explanation:

edge 2023

a. The amount of paper that he is going to need would given as 12 square inches.

b. If it is 11 inches what is needed to cover the wall is given as 396

We have the area of a rhombus to be given as

0.5 *d1 * d2

We have d1 = 6 inches

d2 = 4 inches

then area would be

0.5 * 6 * 4

= 12 inches

b. The amount of paper used as length is 11 feet long

1 ft = 12 inches

then 11 feet = 11 * 12

= 132

Number needed = 4

132/4 = 33

Then the area would be 33 * 12 inches to cover the wall

= 396

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Answer:

12 and 396

Step-by-step explanation:

The mark on the tape measure that is closest to 3.16228 is 3.1875

The measurement is given as:

Length = 3.16228

The tape measure is marked in sixteenths of an inch i.e 1/16 or 0.0625

So, we have the following range:

0.0625, 0.125, 0.1875, 0.25,.....

Rewrite the range as follows:

3.0625, 3.125, 3.1875, 3.25,.....

The length 3.1622 is between 3.125 and 3.1875.

The difference between the measurement and the range is

3.16228 - 3.125 = 0.03728

3.1875 - 3.16228 = 0.02522

0.02522 is smaller than 0.03728

Hence, the mark on the tape measure that is closest to 3.16228 is 3.1875

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Complete question

The length of tile B 3.16228 is about inches. Which mark on the tape measure is closest to 3.16228 inches? Remember, the tape measure is marked in sixteenths of an inch.

Answer:

90

Step-by-step explanation:

First, we should find the area of the trapezoid, and then subtract the area of the removed triangle in order to find the shaded area.

Area of the trapezoid

1) Area of the rectangle in the middle.

Base Length: 10

Height Length: 10

Area: 10 x 10 = 100

2. Area of the triangles on the side

Base Length: (14 - 10)/2 = 2

Height Length: 10

Area: 2 x 10 x 1/2 = 10

There are two triangles: 10 x 2 = 20

Area of the trapazoid: 100 + 20 = 120

Area of the triangle that's been removed

Base Length: 10

Height Length: 10 - 4 = 6

Area: 10 x 6 x 1/2 = 30

Shaded area

Area of the trapezoid - Area of the triangle

120 - 30 = 90

Area of the shaded region is 90.

Answer:

y = (3/4)x + 1/2

Step-by-step explanation:

the slope-intercept form is in general

y = ax + b

with a being the slope, and b the y-intercept (the y-value when x = 0).

because we got the slope and a point we can start with the point-slope form and then transform the equation.

the point-slope form is in general

y - y1 = a(x - x1)

a is again the slope (the same value), and (x1, y1) is a point on the line.

so,

y - 2 = 3/4 × (x - 2) = (3/4)x - 3/2

y = (3/4)x - 3/2 + 2 = (3/4)x - 3/2 + 4/2 = (3/4)x + 1/2