The answer is 492 feet.
If we picture the scenario as a right triangle, using trigonometric ratios, this problem can be solved.
cos 60° = x / 984
1/2 = x/984
x = 984/2
x = 492 feet
A 1L IV contains 60meq of kcal. The IV was discontinued after 400ml has infused. How much lvl did the patient receive
If a 1L IV contains 60meq of kcal and the IV was discontinued after 400ml has infused, then the amount of IV received by the patient is 24meq of kcal.
Calculation for the Amount of IV
It is given that,
1L IV contains 60meq of kcal
⇒ 1000 mL of IV contains 60meq of kcal
⇒ 1 mL of IV will contain 60 / 1000 meq of kcal
As per the question,
The amount of IV infused in the patient = 400 mL
⇒ The amount of IV received by the patient in meq of kcal = 400 × (60 / 1000)
= 4 × 6
= 24 meq of kcal
Hence, the patient receives 24meq of kcal amount of IV.
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A radar unit is used to measure speeds of cars on a miter way the speed are normally distributed with a mean of 90 km/hr and a standard deviation of 10 km/hr what is the probability that’s a car picked at random is traveling at more than 100 km/hr
Using the normal distribution, there is a 0.1587 = 15.87% probability that’s a car picked at random is traveling at more than 100 km/hr.
Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.The mean and the standard deviation are given, respectively, by:
[tex]\mu = 90, \sigma = 10[/tex]
The probability that’s a car picked at random is traveling at more than 100 km/hr is one subtracted by the p-value of Z when X = 100, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{100 - 90}{10}[/tex]
Z = 1
Z = 1 has a p-value of 0.8413.
1 - 0.8413 = 0.1587.
0.1587 = 15.87% probability that’s a car picked at random is traveling at more than 100 km/hr.
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121 slabs . How many slabs will she need to lay in each row to make a square
She needs to lay 11 slabs on each row to make a square
How to determine the number of slabs in each row?The total number of slabs is given as:
Total = 121 slabs
Let this represent the area of the slab.
The area of a square is calculated as:
Area = Length^2
Substitute the known values in the above equation
Length^2 = 121
Take the square root of both sides
Length = 11
Hence, she needs to lay 11 slabs on each row to make a square
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please help with question
Applying precedence of operations, the result of the expression is of 161.
What is the precedence of operations?Power operations are done before multiplication/division, which are also done before addition/subtraction.
Operations inside brackets or parenthesis also take precedence.
In this problem, the operation is:
[3 x 2^5 + 13 x (-2)] + 7[8 - (4 - 9)]
First the power:
[3 x 32 + 13 x (-2)] + 7[8 - (4 - 9)]
Now the multiplications on the first bracket, and the subtraction on the second:
[96 - 26] + 7[8 - (-5)]
Then, applying the parenthesis to the negative number, we have that:
[96 - 26] + 7[8 - (-5)] = 70 + 7 x 13 = 161.
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[tex]\huge\text{Hey there!}[/tex]
[tex]\mathsf{3 \times 2^5 + 13(-2)] + 7[8 - (4 - 9)]}[/tex]
[tex]\mathsf{= 3\times32 + 13\times -2 + 7[8 - (4 - 9)] }[/tex]
[tex]\mathsf{= 96 + 13\times -2 + 7(8 - (4 - 9))}[/tex]
[tex]\mathsf{= 96 - 26 + 7(8 - (4 - 9))}[/tex]
[tex]\mathsf{= 70 + 7(8 - (4 - 9))}[/tex]
[tex]\mathsf{= 70 + 7(8 - (-5))}[/tex]
[tex]\mathsf{= 70 + 7\times13}[/tex]
[tex]\mathsf{= 70 + 91}[/tex]
[tex]\mathsf{= 161}[/tex]
[tex]\huge\text{Therefore, your answer should be: }[/tex]
[tex]\huge\boxed{\frak{161}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
Crane Manufacturing management is considering overhauling their existing line, which currently has both a book value and a salvage value of $0. It would cost $280,000 to overhaul the existing line, but this expenditure would extend its useful life to five years. The line would have a $0 salvage value at the end of five years. The overhaul outlay would be capitalized and depreciated using MACRS over three years. The tax rate is 35 percent, the opportunity cost of capital is 12 percent. The NPV of the new production line is $-360,000.
Since the cost of the renovation or overhauling of the existing line would be recovered in Year 4 and the NPV of the new production line is $-360,000, Crane Manufacturing should renovate.
What is the difference between renovation and replacement?Renovation restores an old asset to a better state. Replacement rids the old in preference for a new asset.
When the two investment options are weighed, a better choice can be arrived at.
Data and Calculations:MACRS - Three Years Depreciation:Year 1 = $93,324 ($280,000 x 33.33%)
Year 2 = $124,460 ($280,000 x 44.45%)
Year 3 = $41,468 ($280,000 x 14.81%)
Year 4 = $20,748 ($280,000 x 7.41%)
Total cost = $280,000
NPV of new production line = $-360,000
Thus, based on the cost recovery of the old production line and the negative NPV of the new production line, Crane Manufacturing should renovate.
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Question Completion:Should Crane replace or renovate the existing line?
Bags of chips cost $4 each. Write a direct
proportion equation using (b) for bags of
chips and (t) for total cost.
Answer:
t = 4b
Step-by-step explanation:
Each bag costs 4 dollars.
hope this helps! <3
Questions are in the pictures
The values of h and r to maximize the volume are r = 4 and h = 2
The formula for h in terms of rFrom the question, we have the following equation
2r + 2h = 12
Divide through by 2
r + h = 6
Subtract r from both sides of the equation
h = 6 - r
Hence, the formula for h in terms of r is h = 6 - r
Formulate a function V(r)The volume of a cylinder is
V = πr²h
Substitute h = 6 - r in the above equation
V = πr²(6 - r)
Hence, the function V(r) is V = πr²(6 - r)
The single critical pointV = πr²(6 - r)
Expand
V = 6πr² - πr³
Integrate
V' = 12πr - 3πr²
Set to 0
12πr - 3πr² = 0
Divide through by 3π
4r - r² = 0
Factor out r
r(4 - r) = 0
Divide through by 4
4 - r = 0
Solve for r
r = 4
Hence, the single critical point on the interval [0. 6] is r = 4
Prove that the critical point is a global maximumWe have:
V = πr²(6 - r)
and
V' = 12πr - 3πr²
Determine the second derivative
V'' = 12π - 6πr
Set r = 4
V'' = 12π - 6π* 4
Evaluate the product
V'' = 12π - 24π
Evaluate the difference
V'' = -12π
Because V'' is negative, then the single critical point is a global maximum
The values of h and r to maximize the volumeWe have
r = 4 and h = 6 - r
Substitute r = 4 in h = 6 - r
h = 6 - 4
Evaluate
h = 2
Hence, the values of h and r to maximize the volume are r = 4 and h = 2
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after henry gave away 2/3 of his stamps and ken gave away 3/4 of his the two boys had an equal number of the stamps left. they had 1156 stamps at first how many stamps did they have left altogather
Answer:
See below.
If the correct sum is 1155, then Ken had 495 stamps, and Henry had 660 stamps.
Step-by-step explanation:
Henry had h stamps.
Ken had k stamps.
After giving away 2/3 of his stamps, Henry ended up with 1/3 of his stamps, or h/3.
After giving away 3/4 of his stamps, ken ended up with 1/4 of his stamps, or k/4.
h/3 = k/4
h + k = 1156
4h = 3k
h = 1156 - k
4(1156 - k) = 3k
4624 - 4k = 3k
4624 = 7k
k = 4624/7
Stamps left: 0.25 × 4624/7 = 1156/7
h = 1156 - k
h = 1156 - 4624/7
h = 8092/7 - 4624/7
h = 3468/7 =495.43
Stamps left: 1/3 × 3468/7 = 1156/7
Total number of stamps left: 1156/7 + 1156/7 = 2312/7 = 330.29
The problem is solved correctly, but the numbers given must be incorrect since you cannot have a fraction of a stamp.
If Jamaal has 13 nickels and dimes in his pocket, and they have a combined value of 110 cents, how many
of each coin does he have?
dimes
nickels
0/4 pts 3 19 0
50 POINTS! Plot function h on the graph.
NO LINKS
See attachment for the graph of the piecewise function h(x)
How to plot the function?The function is given as:
h(x) = | -4, x < 3
| x + 5, x >= 3
The above function is a piecewise function.
It has 2 separate functions at two domains
This means that we plot the sub-functions in the piecewise function at their respective domain
See attachment for the graph of the piecewise function h(x)
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0
According to the Nielsen Media Research, of all the U.S. households that owned at least one television set, 83% had two or more sets, A local cable
company canvassing the town to promote a new cable service found that the 300 randomly selected households visited, 240 had two or more
television sets. At 0.05 level of significance, is there sufficient evidence to conclude that the proportion is less than the one in the report?
Answer Questions 12-23.
The level of significance on 0.05 exists at 83%.
How to find the level of significance?The sample size (n) specified by the local cable company exists 300 which exists quite large.
According to the Central limit theorem, the sampling distribution of sample proportion observes a normal distribution with mean p and standard deviation
[tex]$\sqrt{\frac{p(1-p)}{n}}$[/tex]
Since the sampling distribution of sample proportions observes a normal distribution utilize the z-test for one proportion to execute the test.
The hypothesis is:
[tex]$H_{0}$[/tex]: The proportion of U.S. households that owned two or more televisions exists at 83 %, i.e. p = 0.83
[tex]$H_{1}$[/tex]: The proportion of U.S. households that owned two or more televisions exists less than 83 %, i.e. p < 0.83
Decision Rule:
At the level of significance [tex]$\alpha=0.05$[/tex] the critical region for a one-tailed z-test is:
[tex]$Z \leq-1.645[/tex]
By using the z table for the critical values.
So, if [tex]$Z \leq-1.645$[/tex] the null hypothesis will be rejected.
Test statistic value:
[tex]$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
Here [tex]$\hat{p}$[/tex] exists the sample proportion.
Compute the value of [tex]$\hat{p}$[/tex] as follows:
[tex]$&\hat{p}=\frac{X}{n} \\[/tex] [tex]$&=\frac{240}{300} \\[/tex]
= 0.80
To compute the value of the test statistic as follows:
[tex]$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$[/tex]
[tex]$=\frac{0.80-0.83}{\sqrt{\frac{0.83 \cdot(1-0.83)}{3000}}}$[/tex]
The test statistic exists at -1.383 which exists more than -1.645.
Therefore, the test statistic lies in the acceptance region.
Thus we fail to reject the null hypothesis.
At a 0.05 level of significance, we fail to reject the null hypothesis noting that the proportion of U.S. households that owned two or more televisions exists at 83%.
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Show all work to write the expression in simplified rational exponent form:
[tex](\sqrt[4]{x^{2}+4 } )^{3}[/tex]
(Fourth root of x squared plus four, cubed)
Answer:
[tex]x^{\frac{1}{2} } + 48[/tex]
Step-by-step explanation:
This is hard to explain, but basically you use exponent rules to switch it to an exponent
[tex](\sqrt[4]{x^{2} +4} )^{3}[/tex]
It's easiest if you calculate [tex]4^{3}[/tex] first
4³ = 4 x 4 x 4 = 48
Then convert the root to a fraction exponent
[tex]\sqrt[4]{x^{2}} = x^{\frac{2}{4}} = x^{\frac{1}{2} }[/tex]
Combine them using addition, since addition was in the problem
[tex]x^{\frac{1}{2} } + 48[/tex]
I hope this helps!
What is the sum of 3x^3-2x+8,2x^2+5x,and x^3+2x^2-3x-3
Answer:
4x³ + 4x² + 5
Step-by-step explanation:
3x³ - 2x + 8 + 2x² + 5x + x³ + 2x² - 3x - 3.
4x³ - 2x + 8 + 2x² + 5x + 2x² - 3x - 3
4x³ + 4x² - 2x + 8 + 5x - 3x - 3
4x³ + 4x² + 8 - 3
4x³ + 4x² + 5
In pentagon ABCDE shown above, each side is 1 cm. If a particle starts at point A and travels clockwise 723 cm along ABCDE, at which point will the particle stop?
The particle will stop at D.
What is the fundamental principle of multiplication?If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.
In pentagon ABCDE shown above, each side is 1 cm. If a particle starts at point A and travels clockwise 723 cm along ABCDE, then
Number of sides = 5
Let x be the one complete revolution.
5 x = 725
x = 145
Now, 145 - 2 = 143
Hence, it will stop at D which is 2 less than A.
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Find the value of x.
Answer:
x = 106 degrees
Step-by-step explanation:
x + 104 + 40 + 110 = 360
x + 254 (No more 254)
- 254 (Again no more 254)
x = 106
Find the volume of the figure
h=9.5', r=1.8'
Answer:
Volume=96.7
Step-by-step explanation:
V=πr^2h=
V=π·1.8^2·9.5=
96.69822
add the two equations, 0.75x+1.5y=40 and −1.5x−1.5y=−60 , to find the value of x .
The value of x in the equation is 26.7
How to solve an equation?0.75x + 1.5y = 40
−1.5x − 1.5y = −60
add both equation to eliminate y .
Therefore,
−1.5x + 0.75x = -0.75x
1.5y + (- 1.5y) = 0
40 + (-60) = -20
Hence,
-0.75x = - 20
divide both sides by -0.75
-0.75x / -0/75 = - 20 / -0.75
x = - 20 / -0.75
x = 26.6666666667
x = 26.7
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BRIANLY FOR THE BEST EXPLANATION AND ANSWER!
Question: A circle has an area of 16mm². Find it's circumference.
Answer:
C ≈ 14.18
Step-by-step explanation:
Question Given:
A circle has an area of 16mm². Find it's circumference.
Formula:
C = 2√πA
Solve:
C = 2√πA
C = 2√(3.14 × 16)
C = 2√50.24
C = 14.1760361173
C ≈ 14.18
Hence, Circumference is approximately 14.18.
~Kavinsky
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Here we go ~
Area of Circle :
[tex]\qquad \sf \dashrightarrow \: \pi {r}^{2} [/tex]
Now, it's given that area of circle is : 16 mm²
Let's calculate Radius ~
[tex]\qquad \sf \dashrightarrow \: \pi {r}^{2} = 16[/tex]
[tex] \qquad \sf \dashrightarrow \: {r}^{2} = \cfrac{16}{ \pi} [/tex]
[tex]\qquad \sf \dashrightarrow \: r = \sqrt{ \cfrac{16}{ \pi} } [/tex]
[tex]\qquad \sf \dashrightarrow \: r = { \cfrac{4}{ \sqrt{ \pi} } }[/tex]
Now,
[tex]\qquad \sf \dashrightarrow \: circumference = 2\pi r[/tex]
[tex]\qquad \sf \dashrightarrow \: c = 2 \pi \cfrac{4}{ \sqrt{ \pi} } [/tex]
[tex]\qquad \sf \dashrightarrow \: c = 8 \sqrt{ \pi} [/tex]
[ for approximate value take pi = 3.14 ]
[tex]\qquad \sf \dashrightarrow \: c = 8 \sqrt{3.14} [/tex]
[tex]\qquad \sf \dashrightarrow \: c \approx 8 \times 1.77[/tex]
[tex]\qquad \sf \dashrightarrow \: c \approx 14.18 \: \: mm[/tex]
Consider the given statement.
If it is not Monday, then there are students in the gym.
For each statement below, determine whether it is equivalent to the given statement, the negation of the given statement, or neither of these.
Statement Equivalent Negation Neither
It is not Monday and there are not students in the gym.
It is Monday or there are students in the gym.
If there are not students in the gym, then it is Monday.
There are not students in the gym or it is not Monday.
Answer:
NegationStatementEquivalentNeitherStep-by-step explanation:
If it is not Monday, then there are students in the gym.
Negation: It is not Monday and there are not students in the gym.
Statement: It is Monday or there are students in the gym.
Equivalent: If there are not students in the gym, then it is Monday.
Neither: There are not students in the gym or it is not Monday.
pLEASE answer as fast as possible REALLY URGENT
Using proportions, it is found that you would expected the white counter to be chosen 128 times.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
From the table, the proportion of the white counter is given as follows:
p = 32/(32 + 18) = 32/50 = 0.64.
Hence, out of 200 trials, the number of trials in which the white counter is expected to be chosen is given by:
0.64 x 200 = 128 times.
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Which of the fallowing expressions represents the distance between -4 and 1
The answer is |-4 - 1|.
If you solve this absolute value, the answer would be 5 and if you look at the number line, the distance between the two dots is 5 units.
|-4 - 1| --> |-5| --> 5
in an absolute value, there are no negative numbers so the -5 becomes 5.
change the following fraction to a percent 4/50
Answer:
For finding Percentage u have to multiply the number with 100
e.g.,
[tex] \frac{4}{50} \times 100[/tex]
[tex]4 \times 2 = 8\%[/tex]
Hopefully this helps u...
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Question 8
Ben decides to build a rabbit run to keep his children's rabbits in. The run will be
rectangular with a width of 4 m. He has a maximum of 34 m of fencing to use, but
wants the area to be greater than 50 m². Find the range of values for the length of
the run, using inequalities.
Two cyclists start at the same point and travel in opposite directions. One cyclist travels 5 faster than the other. If the two cyclists are 74 miles apart after 2 hours, what is the rate of each cyclist?
The rate of the slower cyclist is 16 mph while the rate of the faster cyclist is 21 mph.
How to calculate the rate of speed?let us assume the following;
x = rate of slower cyclist
x + 5 = rate of faster cyclist
We know that formula for distance is;
distance = travel time*rate
Thus;
2x + 2(x + 5) = 74
Since the two cyclists are a distance of 74 miles apart after a time 2 hours. Thus;
2x + 2x + 10 = 74
4x + 10 = 74
4x = 74 - 10
4x = 64
x = 64/4
x = 16
Rate of faster cyclist = 16 + 5 = 21 mph
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The data to the right represent the cost of living for 20 states. The cost of living is a measure of the average price paid for housing, utilities, groceries, healthcare, transportation, and miscellaneous expenses. The national average cost of living is 100. The data can be used to compare a state to the national average and to other states.
The frequency distribution based on the information given is illustrated below.
What is the frequency distribution of table?A frequency distribution table is the
chart that summarizes all the data under two columns - variables/categories, and their frequency.
It should be noted that the distribution table has two or three columns and the first column lists all the outcomes as individual values or in the form of class intervals, depending upon the size of the data set.
Given the above information the frequency distribution table is:
Cost of living Number of states
85.0 - 94.9 9
95.0 - 104.9 5
105.0 - 114.9 0
115.0 - 124.9 2
125.0 - 134.9 2
135.0 - 144.9 1
145.0 - 154.9 1
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The average THC content of marijuana sold on the street is 10.5%. Suppose the THC content is normally distributed with standard deviation of 2%. Let X be the THC content for a randomly selected bag of marijuana that is sold on the street. Round all answers to 4 decimal places where possible,
a. What is the distribution of X? X ~ N(
,
)
b. Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 8.9.
c. Find the 76th percentile for this distribution.
%
a. This information is given to you.
b. We want to find
[tex]\mathrm{Pr}\{X > 8.9\}[/tex]
so we first transform [tex]X[/tex] to the standard normal random variable [tex]Z[/tex] with mean 0 and s.d. 1 using
[tex]X = \mu + \sigma Z[/tex]
where [tex]\mu,\sigma[/tex] are the mean/s.d. of [tex]X[/tex]. Now,
[tex]\mathrm{Pr}\left\{\dfrac{X - 10.5}2 > \dfrac{8.9 - 10.5}2\right\} = \mathrm{Pr}\{Z > -0.8\} \\\\~~~~~~~~= 1 - \mathrm{Pr}\{Z\le-0.8\} \\\\ ~~~~~~~~ = 1 - \Phi(-0.8) \approx \boxed{0.7881}[/tex]
where [tex]\Phi(z)[/tex] is the CDF for [tex]Z[/tex].
c. The 76th percentile is the value of [tex]X=x_{76}[/tex] such that
[tex]\mathrm{Pr}\{X \le x_{76}\} = 0.76[/tex]
Transform [tex]X[/tex] to [tex]Z[/tex] and apply the inverse CDF of [tex]Z[/tex].
[tex]\mathrm{Pr}\left\{Z \le \dfrac{x_{76} - 10.5}2\right\} = 0.76[/tex]
[tex]\dfrac{x_{76} - 10.5}2 = \Phi^{-1}(0.76)[/tex]
[tex]\dfrac{x_{76} - 10.5}2 \approx 0.7063[/tex]
[tex]x_{76} - 10.5 \approx 1.4126[/tex]
[tex]x_{76} \approx \boxed{11.9126}[/tex]
Toenails grow at an average rate of about 0.05 mm per day, and the average toenail is about 3/4 inch long. About how many months does it take for a toenail to completely regenerate itself?
The number of months taken for the toenail to completely regenerate itself is 13 months
What is a unit rate?It is the quantity of an amount of something at a rate of one of another quantity.
We have,
Toenail grows:
0.05 mm per day
0.05 mm = 1 day
[ 1 inch = 25.4 mm ]
So,
1 mm = 1/25.4 inch
0.05 x 1/25.4 inch = 1 day
0.0019 inch = 1 day
Divide both sides by 0.0019
1 inch = 1/0.0019 day
1 inch = 526.32 days
Multiply 3/4 on both sides.
3/4 inch = 3/4 x 526.32 days
3/4 inch = 395 days _____(1)
We can assume,
1 month = 30 days
Multiply 395/30 on both sides.
395/30 months = 395 days
13 months = 395 days _____(2)
From (1) and (2) we get,
3/4 inch = 13 months
Thus,
The number of months taken for the toenail to completely regenerate itself is 13 months.
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The difference of the square of a number and 36 is equal to 5 times that number. Find the positive solution.
Answer:
x=-4, x=9
Step-by-step explanation:
We write this into words:
difference = subtraction
square = ^2
a number = x
is equal to = =
5 times that number = 5x
x^2-36 = 5x
write in standard form
x^2-5x-36
what adds to -5 and multiplies to -36?
-9 and 4!
(x-9)(x+4)
x-9 = 0
x= 9
x+4 = 0
x=-4
Answer:
9
Step-by-step explanation:
Let the number = x.
x² - 36 = 5x
x² - 5x - 36 = 0
(x - 9)(x + 4) =0
x = 9 or x = -4
Answer: 9
Riverbed company purchased a delivery truck for $33,000 on January 1, 2022 the truck has an expected salvage value of 2760 and he suspected to be driven 108,000 miles over estimated useful life of 10 years actual miles driven was 16,000 802,022 and 12,000 602,023 how much is the depreciation expense per mile
Answer:
0.28
Step-by-step explanation:
Depreciation Expense per mile:
= (Cost of delivery truck - Salvage value) ÷ Expected miles driver
=(33000-2760)÷108000=0.28 per mile
01
5. Solve the polynomial by typing it into a graphing calculator and identifying the zeros. Round to the nearest tenth.
5x^4-7x^3-5x^2+5x+1=0
Answer:
-0.8, -0.2, 0.8, 1.6
Step-by-step explanation: