Friction typically __________ objects. A. Speeds up B. Slows down C. Doesn't affect D. Destroys

(a) The speeds of the tips of both rotors; main rotor 178.3 m/s and  tail rotor 218.4 m/s.

(b) The speed of the main rotor is 0.52 speed of sound, and the speed of the tail rotor is 0.64 speed of sound.

v = ωr

where;

v(main rotor) = (444 rev/min x 2π rad x 1 min/60s) x (0.5 x 7.67 m)

v(main rotor) = 178.3 m/s

v(tail rotor) = (4,130 rev/min x 2π rad x 1 min/60s) x (0.5 x 1.01 m)

v(tail rotor) = 218.4 m/s

% speed (main motor) = 178.3/343 = 0.52 = 52 %

% speed (tail motor) = 218.4/343 = 0.64 = 64 %

Thus, the speed of the main rotor is 0.52 speed of sound, and the speed of the tail rotor is 0.64 speed of sound.

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Answer:

24.2 m/s

Explanation:

Mass is irrelevant in this situation....

Displacement:  ( to find time)

 x = xo + vo t - 1/2 at^2

 30= 0   + 0  - 1/2 (9.8)t^2

              t = 2.47 seconds

Velocity:

vf = a t   = 9.8 (2.473)  = 24.2 m/s

Solids have very small intermolecular space and when heated, do not expand as per the container volume. Basically, their expansion is not good.

Liquids, on the other hand, have a definite volume and their expansion is ideal. Also, they fill the container only to the desired level, unlike gases.

Answer:

A mechanical wave can only travel through a medium.

The maximum rate at which energy can be added to the circuit element mathematically given as

[tex]MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}[/tex]

Generally, the equation for P is  mathematically given as

[tex]P=\ln s \frac{\Delta T}{\Delta t}[/tex]

Therefore

[tex]Rate\ of\ Change\ of\ Temp =\frac{p}{lnS}[/tex]

[tex]\frac{p}{lnS}=\frac{7.4 \times 10^{-3}}{23 \times 10^{-6} \times 705}[/tex]

[tex]\frac{p}{lnS}=0.456^{\circ \mathrm{c}} / \mathrm{sec}[/tex]

Max temp Change

[tex]MaxT=5.6^{\circ} \mathrm{C}[/tex]

[tex]\text { time }=3 \times 60[/tex]

t=180s

In conclusion, Max Energy Rate

[tex]MER =23 \times 10^{-6} \times \frac{301 \times 5.6}{180}[/tex]

[tex]MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}[/tex]

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Answer:

.12 N

Explanation:

Velocity goes from 2 m/s    to   0  m/s   so average velocity = 1 m/s

.250 m / 1 m/s  =  .25 second to stop

change in velocity / change in time = accel

  2 m/s / .25 sec =  8 m/s^2

F = ma

  = .015 kg *  8 m/s^2  = .12 N

The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

The time of motion of the girl is calculated as follows;

h = vt + ¹/₂gt²

where;

Substitute the given parameters and solve for time of motion;

50.8 = 0 + ¹/₂(9.8)t²

2(50.8) = 9.8t²

101.6 = 9.8t²

t² = 101.6/9.8

t² = 10.367

t = √10.367

t = 3.22 seconds

vf = vi + gt

where;

vi is the initial vertical velocity = 0

vf = 0 + 9.8(3.22)

vf = 31.56 m/s

Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

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wind (b), also some others are:

- steam

- gas

- liquid fules

The workout of Peter that involves jumping rope, doing push-ups, kicking a ball through a pattern of cones, doing sit-ups, and then repeats the cycle is an example of circuit training.

A workout is any activity that requires much physical or mental effort, or produces strain.

There are several approaches that can be employed to achieve workout procedures and they are as follows:

Circuit training is a combination of six or more exercises performed with short recovery periods between them for either a set number of repetitions or a prescribed amount of time.

On the other hand, interval training is similar to circuit training but differs in the sense that a period of rest is allowed in between the exercises.

Therefore, the workout of Peter that involves jumping rope, doing push-ups, kicking a ball through a pattern of cones, doing sit-ups, and then repeats the cycle is an example of circuit training.

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The coefficient of kinetic friction on the horizontal surface, μ = 0.39.

The work done on the package by friction as it slides down the circular arc from A to B, W = -4.176.

Frictional force is the force which opposes the motion of an object over another.

Frictional force acts at the surface of contact of the objects.

The frictional force, F is related to the coefficient of kinetic friction on the horizontal surface, μ, and the normal reaction or weight, mg,  of the package as follows:

F = μmg

Work done against friction, W = F * d

W = μmgd

The Kinetic energy of the package is equal to the work done against friction.

Kinetic energy of the package = mv²/2

μmgd = mv²/2

μ = v²/2gd

μ = 4.8²/(2 * 9.81 * 3)

μ = 0.39

b. Work done on the package by friction as it slides down the circular arc from A to B is given as follows:

W = mv²/2 - mgh

W = v²/2 - gh

W = 4.8²/2 - 9.81 * 1.6

W = -4.176

In conclusion, the work done by friction is lost in the form of heat.

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Answer:

No

Explanation:

When a substance changes its state , there will not be any change in the mass of substance . For example , if we change 100 grams of water (liquid) to ice(solid) , the mass of ice will be same i.e., 100 grams . This shows there is no change in the mass even if a substance changes its state.

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Answer:

the earth receives the suns energy as radiation which is able to travel without the need of matter from point A to point B and this radiation is also in the form of heat.

Explanation:

Sun's energy fall on the earth in form of radiation and heats up the atmosphere and produces unequal heating due to its spherical nature and impacts climate of different areas.

The Sun is the only source of energy for the Earth's climate system. Fundamental to atmospheric composition is the warming of the atmosphere caused by solar radiation, which also causes global wind patterns and aids in the development of clouds, storms, and rainfall.

When the sun is at its maximum (peak in sunspots, prominences, and flares), it produces more ultraviolet (UV) radiation. More ozone is produced as a result of UV light, warming the stratosphere. The lower atmosphere and Earth's surface warm slightly as a result of the increased solar radiation.

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The fraction of the magnitude of the kinetic energy lost is [tex]\frac{(change) KE }{KE} = 1 - \frac{m}{m + M }[/tex]. = 0.955.

using the law of conservation of momentum,

[tex]mv=(m+M)V[/tex]

[tex]V= m ( \frac{1}{M+m} ) v\\[/tex]

kinetic energy lost,

Δ[tex]KE=KE_{i} -KE_{f}[/tex]

(see image )

now, for the other part

the fraction of the kinetic energy lost,

ΔKE/ KE = [tex]1- m (\frac{1}{m+M} )[/tex]

ΔKE/ KE = [tex]1 - 18 ( \frac{1}{18 + 380 } )[/tex]

ΔKE/ KE = 0.955.

what is kinetic energy ?

The energy that an object has as a result of motion is known as kinetic energy. It is stated as the effort needed to transfer a bulk body from rest to the given velocity. The body holds onto the kinetic energy it gained during its acceleration until its speed changes.

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Answer:

See below

Explanation:

A) bearing y reaches the FLOOR in the same amount of time   .5 seconds  since there is no initial vertical velocity component

B.  in .5 seconds y will travel     5 m/s * .5 s = 2.5 meters horizontally

C.  d = 1/2 a t^2

         = 1/2 (9.81)(.5^2) = 1.23 m table height

(a) Bearing y takes 0.2 seconds to reach the table. (b) Bearing y travels 1 meter horizontally before hitting the floor. (c)  The height of the table top above the floor level is 1.225 meters.

a) Time is taken for bearing y to reach the table:

For a horizontal motion, the equation to calculate time is:

Time (t) = Distance (d) ÷ Velocity (v)

Time (t) = Width of the table / Velocity of y

t = 1  / 5

t = 0.2 sec

So, bearing y takes 0.2 seconds to reach the table.

b) Horizontal distance traveled by bearing y before hitting the floor:

Distance (d) = Velocity (v) × Time (t)

d = 5 × 0.2

d = 1 m

So, Bearing y travels 1 meter horizontally before hitting the floor.

c) The height of the table top above the floor level:

h = (1/2) × g × t²

h = (1/2) × 9.8 × (0.5)²

h = (1/2) × 9.8 × 0.25

h = 1.225 m

So, the height of the table top above the floor level is 1.225 meters.

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Answer:

Density of a substance is the ratio of mass of the substance to its volume.

Answer:

Density of a substance is the ratio of mass of the substance to its volume.

(a) The angular speed of the human centrifuge is 4.7 rad/s.

(b) The linear speed (in m/s)  a person in the centrifuge would have at this is 18.8 m/s.

a = ω²r

where;

ω = √(a/r)

ω = √(9g/r)

ω = √(9 x 9.8 / 4)

ω = 4.7 rad/s

v = ωr

where;

v = (4.7 rad/s) x 4 m

v = 18.8 m/s

Thus, the angular speed of the human centrifuge is 4.7 rad/s. The linear speed (in m/s)  a person in the centrifuge would have at this is 18.8 m/s.

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Answer:

Approximately [tex]28^{\circ}[/tex].

Explanation:

The refractive index of the air [tex]n_{\text{air}}[/tex] is approximately [tex]1.00[/tex].

Let [tex]n_\text{glass}[/tex] denote the refractive index of the glass block, and let [tex]\theta _{\text{glass}}[/tex] denote the angle of refraction in the glass. Let [tex]\theta_\text{air}[/tex] denote the angle at which the light enters the glass block from the air.

By Snell's Law:

[tex]n_{\text{glass}} \, \sin(\theta_{\text{glass}}) = n_{\text{air}} \, \sin(\theta_{\text{air}})[/tex].

Rearrange the Snell's Law equation to obtain:

[tex]\begin{aligned} \sin(\theta_{\text{glass}}) &= \frac{n_{\text{air}} \, \sin(\theta_{\text{air}})}{n_{\text{glass}}} \\ &= \frac{(1.00)\, (\sin(45^{\circ}))}{1.50} \\ &\approx 0.471\end{aligned}[/tex].

Hence:

[tex]\begin{aligned} \theta_{\text{glass}} &= \arcsin (0.471) \approx 28^{\circ}\end{aligned}[/tex].

In other words, the angle of refraction in the glass would be approximately [tex]28^{\circ}[/tex].

In the left-hand rule, the field is represented by the forefinger and it is perpendicular to the motion.

A force perpendicular to the field's direction and the direction of the current flow is experienced by a current-carrying conductor when it is exposed to an external magnetic field. According to Fleming's Left Hand Rule, if the thumb, forefinger, and middle finger are arranged in a straight line on the left hand, the thumb will point in the direction of the force experienced by the conductor, and the forefinger will point in the direction of the magnetic field, and the middle finger will point in the direction of the electric current. This rule is employed to determine the magnetic force's direction within an electric motor.

Fleming’s Left-Hand Rule are essential rules applicable in magnetism and electromagnetism. They were created by John Ambrose Fleming in the late 19th century as an easy method of determining the direction of motion in an electric motor.

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Answer:

Mass of block = 6kg

wright = 6 × g = 60 N using g = 10 m/s^2 .

compression= 0.20m

spring constant =( weight / compression) =( 60/0.20) = 300 N/m .

Work done in compressing 0.20 m =( 1/2 × 300 × 0.20 × 0.20)= 6 joule.

Additional compression = 0.10 m

total compression = 0.20+ 0.10= 0.30 m.

Total work done = ( 1/2 × 300 × 0.30× 0.30) = 13.5 joule.

Hence work done in compressing from 0.20 m to 0.30 m will be = ( 13.5 - 6) = 7.5 joule.

Note :- work done in compressing a spring having spring constant K N/m by x m is equal to 1/2× (K) × X^ 2 .

A piston-work cylinder device with a set of stops initially contains 0.6 kg of steam at 1.0 MPa and 400°C. The location of the stops corresponds to 40 percent of the initial volume. Now the steam is cooled. compression work is 44.32 KJ,

The amount of labor put into the piston to cause its reciprocating motion is known as the piston work. It is calculated by multiplying the piston's displacement by the net force.

An expanding gas cylinder's force output is transferred by pistons to the crankshaft, which then drives the flywheel's rotation. A reciprocating engine is a device like this.

Piston work is the effort made by the piston to make its reciprocating motion. The piston's displacement is calculated by multiplying it by the net force.

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Answer:

Vo (vertical) = Vo sin 30 = 30 m/s / 2 = 15 m/s

Vo (horizontal) = Vo cos 30 = .866 30 m/s = 26 m/s

a) The wheel of the car decelerates at an angular acceleration of - 0.577 radians per square second.

b) The wheel of the car requires a time of 51.149 seconds to stop.

c) The wheel of the car travels a distance of 683.225 meters before stopping.

a) In this case we have a rotating wheel that decelerates at constant rate. The angular acceleration, in radians per square second, of the tires is determined by the following formula:

α = [ω'² - ω²] / (2 · θ)      (1)

Where:

The initial and final angular velocities, in radians per second, are now determined:

ω' = v' / R      (2)

ω = v / R      (3)

Where:

If we know that R = 0.80 m, v = 23.611 m / s, v' = 15.556 m / s and θ ≈ 427.257 radians, then the angular acceleration of the tire is:

ω' = (15.556 m / s) / (0.80 m)

ω' = 19.445 rad / s

ω = (23.611 m / s) / (0.80 m)

ω = 29.513 rad / s

α = [(19.445 rad / s)² - (29.513 rad / s)²] / [2 · (427.257 rad)]

α = - 0.577 rad / s²

b) The time required to stop the car, in seconds, is determined by the following expression:

t = (ω' - ω) / α     (4)

t = (0 rad / s - 29.513 rad / s) / (- 0.577 rad / s²)

t = 51.149 s.

c) First, we find the change in angular displacement of the tire:

θ = [ω'² - ω²] / (2 · α)      (5)

θ = [(0 rad / s)² - (29.513 rad / s)²] / [2 · (- 0.577 rad / s²)]

θ = 754.781 rad

Lastly, the distance traveled by the vehicle is:

s = R · θ     (6)

s = (0.80 m) · (754.781 rad)

s = 683.825 m

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a. The magnitude of the tension, T₂ in the vertical rope on the left end is T₂ = 655.62 N

b. The magnitude of the tension in the rope in the right end is T₁ = 530.4 N

c. The magnitude of the tension in the horizontal rope on the left end, T₃ is T₃ = 406.3 N

Tension force refers to a pulling force that is exerted by a string or cable about an axis.

a. The magnitude of the tension, T₂ in the vertical rope on the left end is given as follows:

Taking moment about the vertical axis

T₂ = 30.23 * 9.81 + 700 - T₁ * Sin40°

Solving for T₁ by taking the left end as the pivot;

T₁ Sin 40° * 2.00 = 700 * 0.55 + (30.23 * 9.81) * 1.0

T₁ * 1.285 = 681.5563

T₁ = 530.4 N

Therefore;

T₂ = 30.23 * 9.81 + 700 - 530.4 * Sin 40°

T₂ = 655.62 N

b. From calculation, the magnitude of the tension in the rope in the right end is T₁.

T₁ = 530.4 N

c. The magnitude of the tension in the horizontal rope on the left end, T₃ is determined thus:

Taking moments about the left end in the horizontal direction;

T₃ = T₁ * cos 40°

T₃ =  530.4 N * cos 40°

T₃ = 406.3 N

In conclusion, the tension at the rope in the various ends is determined by taking moments about the left end.

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43.DB(decibels)

⇉ Unit conversion

4.3(bels)

4.951NP

4.3(decades)

14.28(octaves)

Interpretations

⇉ Power quantity level

Basic unit dimensions

⇉ ( logarithmic quantity ).

They provided the intensity in decibels for the problem, but they are unsure by what factor to increase it (I) to make the sound loud enough for the elderly person to hear.

Neglect f entirely.

The following equation must be used to convert decibels (dB) to I:

I=(10^(dB/10))*10^-12

Divide the elder person's dB by the younger person's dB after doing this for each dB.

1.8372093023.

Decibels are used to measure sound (dB). A motorcycle engine operating is roughly 95 dB louder than regular conversation, which is around 60 dB louder than a whisper. Your hearing may begin to be harmed if exposed to noise over 70 dB for an extended period of time. Your ears can suffer instant damage from loud noise above 120 dB.

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In thicker materials the particles can move more easily, therefore the resistance has to decrease.

Hence Option (b) is correct.

Resistivity, which is sometimes represented by the Greek letter rho, is quantitatively equal to a specimen's resistance R times its cross-sectional area A times its length.

ρ = R × A/ l

R = ρ × l/ A

It means the Resistance of the material is inversely proportional to the area of the material.

As the area of the material increases, the resistance decreases and vice versa.

Hence, In thicker particles, there is a greater area available and that's why resistance has to decrease so that particles can move more easily.

Hence, Option (b) is correct.

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The work that the man does is the scalar product of the force applied by the man and the horizontal displacement of the bag.

In Physics, we define the work done as the product of the of force and distance. Hence, we generally define the work done as that which occurs when the force applied moves a distance in the direction of the force. This implies that the work done is not a vector but a  scalar quantity.

In relation to the man and the bag, the work done is the product of the force that the man applies and the displacement of the bag. As such, the reason for the tiredness of the man is that the internal energy that he possesses is transferred to moving the bag.

Thus, the work that the man does is the scalar product of the force applied by the man and the horizontal displacement of the bag.

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Answer:

Electromagnetic waves

Answer:Using the Nielsen form, determine the equation of motion for a mass m connected to a spring of constant k. Exercise 3.2 Using the

Explanation: