The equilibrium constant, k of the reaction in which case, the concentrations of the given reactants and products are as indicated is; Choice A; K = 3.1 x 10⁵
What is the equilibrium constant , k of the reaction as described in the task content?It follows from above that the concentrations of the reactants and products are as follows; [H2] = 0.10 M, [N2] = 0.10 M, and [NH3] = 5.6 M at equilibrium.
Hence, the equilibrium constant of the reaction in discuss is;
K = [5.6]²/[0.10]³[0.10]
k = 5.6² × 10⁴
k = 3.136 × 10⁵
K = 3.1 × 10⁵.
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Is HCI an acid or a base?
Answer:
Strong Acid
Explanation:
Hope this helps! :)
what is the correct iupac name for the following structure:CH2=CH-CH2-CH3
The correct IUPAC name of the following structure CH2=CH2-CH-CH3 is But - 1 - ene
IUPAC rules for alkene nomenclatureThe parent alkene is picked because it has the longest carbon chain with the double bond between carbon atoms.The suffix "ane" of the alkane is transformed to "ene."Depending on whether a double bond appears twice or three times in the parent chain, an alkene is referred to as a diene or triene.the positions of double bonds or side chains, indicated by the numerals 1, 2, 3, etc.Because it is the longest chain and is numbered from that end, the carbon atom in the double bond, which is written just before the suffix "ene," has the lowest number.The carbon chain is numbered so that the substituent receives the lowest number if both sides of a double bond receive the same number.Hence the structure CH2=CH-CH2-CH3 is named on the basis of the above rule as but - 1 - ene.
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silver
nitrate
solution
A current was passed through the circuit shown in figure above. In the
experiment, 5.4 g of silver metal was discharged at the cathode in electrolysis cell
B. What mass of copper was discharged at the cathode in cell A?
[Molar mass: Ag = 108 gmol¹; Cu= 63.5 gmol ¹]
Answer:
Silver
Explanation:
What mass of copper was discharge at the cathode in a cell
A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.
Br2(g) + I2(g) ↔ 2IBr(g)
When the mixture has come to equilibrium, the concentration of iodine monobromide is 1.190 M. What is the equilibrium constant for this reaction at 350°C?
Show step-by step explanation.
A) 3.55 × 10^3
B) 1.24
C) 1.47
D) 282
E) 325
The equilibrium constant of the reaction is 282. Option D
What is equilibrium constant?The term equilibrium constant refers to the number that often depict how much the process is able to turn the reactants in to products. In other words, if the reactants are readily turned into products, then it follows that the equilibrium constant will be large and positive.
Concentration of bromine = 0.600 mol /1.000-L = 0.600 M
Concentration of iodine = 1.600 mol/1.000-L = 1.600M
In this case, we must set up the ICE table as shown;
Br2(g) + I2(g) ↔ 2IBr(g)
I 0.6 1.6 0
C -x -x +2x
E 0.6 - x 1.6 - x 1.190
If 2x = 1.190
x = 1.190/2
x = 0.595
The concentrations at equilibrium are;
[Br2] = 0.6 - 0.595 = 0.005
[I2] = 1.6 - 0.595 = 1.005
Hence;
Kc = [IBr]^2/[Br2] [I2]
Kc = ( 1.190)^2/(0.005) (1.005)
Kc = 282
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What is Ką for H3PO4(aq) = H(aq) + H₂PO4 (aq)?
OA. K₂ [H₂PO4][H*][H₂PO4]
=
OB. K₂ =
O C. K₂ =
O D. Ka
=
[H₂PO4]
[H*][H₂PO4]
[H*][H₂PO4]
[H₂PO4]
[H3PO4]
[H+][H₂PO4]
Answer:
C.) [tex]K_a = \frac{[H^+][H_2PO_4^-]}{[H_3PO_4]}[/tex]
Explanation:
The general structure for a Ka expression is:
[tex]K_a = \frac{[H^+][A^-]}{[HA]}[/tex]
In this expression,
-----> Ka = equilibrium constant
-----> [A⁻] = base
-----> [HA] = acid
The products are in the numerator and the reactants are in the denominator. In this case, H₃PO₄ serves as an acid and H₂PO₄⁻ serves as a base.
As such, the equilibrium expression is:
[tex]K_a = \frac{[H^+][H_2PO_4^-]}{[H_3PO_4]}[/tex]
According to chemical equilibrium, the Ka for the given chemical equation is Ka=[H⁺][H₂PO₄⁻]/[H₃PO₄].
What is chemical equilibrium?Chemical equilibrium is defined as the condition which arises during the course of a reversible chemical reaction with no net change in amount of reactants and products.A reversible chemical reaction is the one wherein the products as soon as they are formed react together to produce back the reactants.
At equilibrium, the two opposing reactions which take place take place at equal rates and there is no net change in amount of the substances which are involved in the chemical reaction.At equilibrium, the reaction is considered to be complete . Conditions which are required for equilibrium are given by quantitative formulation.
Factors which affect chemical equilibrium are change in concentration , change in pressure and temperature and presence of catalyst.
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You perform an electrolysis of NaCl and collect one of the products in a test tube. You realize later you did not label the test tube. You dip a strip of damp pH paper into the test tube and get no reaction. You dip a dry strip of pH paper into the tube and there is no reaction. You hold a lit match near the mouth of the test tube and hear a loud 'pop'. Which product is in the test tube?
A. Chlorine gas
B. Sodium hydroxide (NaOH)
C. Hydrogen gas
D. Oxygen gas
The correct alternative is (b). NaOH will be present in the test tube, after performing electrolysis.
Aqueous electrolysis of salt solutions finds the salt ions in competition with electrolysis of water at the respective electrodes. That is, water can undergo reduction at the cathode as can the cation of the salt; while at the anode water can undergo oxidation as can the anion of the salt. The reactions are as follows:
Cathode:
H₂O(l) + 2e⁻ ⇄ 2OH⁻(aq) + H₂(g)
Anode:
2H₂O(l) ⇄ O₂(g) + 4H⁺(aq) + 4e⁻
The distinction can be determined by comparing the 'Standard Reduction Potentials' of the half-reactions.
For NaCl(s) => Na⁺(aq) + Cl⁻(aq) :
At the Cathode:
Na⁺ + e⁻ => Na⁰(s); εo = -2.71v
2H₂O(l) + 2e⁻ ⇄ 2OH⁻(aq) + H₂(g); εo = -0.83v (Dominant Rxn at cathode – more positive value)
At the Anode:
Cl⁻(aq) => Cl₂(g) + 2e⁻; εo = 1.36v
2H₂O(l) => O₂(g) + 4H⁺ + 4e⁻; εo = 1.23v (Dominant Rxn at anode – more positive value)
Since the more dominant reaction at the cathode(reduction) produces hydroxide ions, the solution would become alkaline with Na⁺ ions already present.
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The density of molybdenum is 10.28 g/cm^3 and it crystallizes in the face centered cubic unit cell. Calculate the edge length of the unit cell. (The atomic mass of Mo is 95.96 g/mole)
The edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.
What is cubic unit cell?The cubic unit cell is the smallest repeating unit when all angles are 90 degrees and all lengths are equal.
Volume of molybdenumThe volume of the molybdenum is calculated from mass and density of the molybdenum as shown below;
V = (zm/ρN)
where;
z is 2 for cubic unit cellm is mass of the molybdenumρ is density of the molybdenumV = (2 x 95.96) / (10.28 x 6.02 x 10²³)
V = 3.10 x 10⁻²³ cm³
Edge length of the unit cella³ = V
a = (V)^¹/₃
a = ( 3.10 x 10⁻²³)^¹/₃
a = 3.142 x 10⁻⁸ cm
a = 3.142 x 10⁻¹⁰ m
a = 314.2 x 10⁻¹² m
a = 314.2 pm
Thus, the edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.
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What is a catalyst?
Group of answer choices
A. A substance that speeds up the reaction by increasing the activiation energy.
B. A substance added to the reaction that lowers the activation energy by providing an alternate pathway for the reactions to go to completion.
C. A substance that slows down the reaction by lowering the activation energy.
D. A substance added to the reaction that raises the activation energy by providing an alternate pathway for the reactions to go to completion.
A catalyst is a substance added to the reaction that lowers the activation energy by providing an alternate pathway for the reactions to go to completion.
A catalyst is a substance that accelerates a chemical response, or lowers the temperature or strain needed to begin one, with out itself being ate up at some stage in the response. Catalysis is the procedure of adding a catalyst to facilitate a response.
Catalysts may be categorized as homogeneous, heterogeneous, or enzymatic. Homogeneous catalysts exist inside the identical phase as the reactants, whereas heterogeneous catalysts exist in a exclusive section than the reactants.
Catalysts are basically categorised into 4 kinds.Homogeneous, Heterogeneous, Heterogenized homogeneous catalyst and Biocatalysts. Homogeneous catalyst: In homogeneous catalysis, reaction mixture and catalyst both are gift inside the equal segment.
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The empirical formula for a compound is C3H3O the molecular mass is 110 what is its molecular formula
Answer:
emiprical formula is 55
Explanation:
(-^〇^-)
Hydrochloric Acid would best be described as a:
Group of answer choices
A. Arrhenius, BrØnsted-Lowrey and Lewis Base
B. Arrhenius, BrØnsted-Lowrey and Lewis Acid
C. BrØnsted-Lowrey and Lewis Acid
D. Arrhenius and Lewis Acid
Hydrochloric Acid would best be described as an Arrhenius and BrØnsted-Lowrey acid.
Is Hydrochloric Acid considered a Brønsted-Lowry acid?
Hydrochloric Acid HCl(g) is the proton donor and therefore a Brønsted-Lowry acid.
Is Hydrochloric Acid considered an Arrhenius acid?According to Arrhenius theory, hydrochloric acid is an acid which gives hydrogen ions in water but according to Bronsted-Lowry theory, hydrochloric acid is an acid because it donates a proton to the water molecule.
Is Hydrochloric Acid considered a Lewis acid?
Hydrochloric acid (HCl) cannot be classified as a Lewis acid since it cannot accept an electron pair.
Thus, hydrochloric Acid would best be described as an Arrhenius and BrØnsted-Lowrey acid.
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Which of the following transformations represent an increase in the entropy of the system.
Choose all that apply
26 g C5H12 (liquid, 156K)------>26 g C5H12 (liquid, 297K)
3 mol O2 (1.14 atm, 408K) ------>3 mol O2 (1.14 atm, 204K)
32 g Pb (liquid, 601.0K) ------>32 g Pb (solid, 601.0K)
26 g C5H12 (liquid, 309K) ------->26 g C5H12 (gas, 309K)
3 mol CH4 (8.17 L, 240K) ------->3 mol CH4 (16.3 L, 240K)
The transformations that result in increase in entropy are those that result in increased disorderliness and they are:
26 g C5H12 (liquid, 156K)------>26 g C5H12 (liquid, 297K) 26 g C5H12 (liquid, 309K) ------->26 g C5H12 (gas, 309K) 3 mol CH4 (8.17 L, 240K) ------->3 mol CH4 (16.3 L, 240K) What is entropy of a system?The entropy of a system is a measure of the degree of randomness or disorderliness of a system.
When a system changes from a more ordered state to a more disordered state, there is an increase in the entropy of the system.
Increase in temperature or volume also results in increase in entropy.
For example, when solid melts to form liquid, entropy increases. Also, when liquid changes to gas, entropy of the system increases.
Based on the above transformations:
26 g C5H12 (liquid, 156K)------>26 g C5H12 (liquid, 297K) - entropy increases3 mol O2 (1.14 atm, 408K) ------>3 mol O2 (1.14 atm, 204K) - entropy decreases32 g Pb (liquid, 601.0K) ------>32 g Pb (solid, 601.0K) - entropy decreases 26 g C5H12 (liquid, 309K) ------->26 g C5H12 (gas, 309K) - entropy increases3 mol CH4 (8.17 L, 240K) ------->3 mol CH4 (16.3 L, 240K) - entropy increasesIn conclusion, an increase in disorderliness of a system results in entropy increase.
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Calculate the pOH of a 0.0143 M NaOH solution at 25 ⁰C.
1.845
6.993 x 10⁻¹³
12.155
-1.845
Answer:
A.) 1.845
Explanation:
You can find the pOH using the following equation:
pOH = -log[OH⁻]
Since NaOH dissociates into 1 Na⁺ and 1 OH⁻, the concentration of both ions is 0.0143 M.
pOH = -log[OH⁻]
pOH = -log[0.0143]
pOH = 1.845
Assuming the substance is one of those listed in the table presented in this lesson, what is the identity of the substance?
iron
copper
lead
aluminum
Answer: Iron
Explanation: IRON : Iron is an element with symbol Fe and atomic number 26 2) it is the fourth most common element in earth's crust 3) It is a heavy silvery grey metal belongs to the first transition series. 4) High ductility and malleability 5) It is a good conductor.
The identity of the substance is Iron.
Properties of IronChemical propertiesThe element iron has the atomic number 26 and the symbol FeElectronic configuration of Fe is [AR] 3d6 4s2The atomic weight of Iron is 55.847The element iron belong to the group VIII of the periodic tableIt is the fourth most prevalent element in the crust of the worldIt is a highly reactive element as it gets rusted readily in the moisture of airPhysical propertiesIt is a heavy metal in the first transition series The color of iron is silvery greyHigh malleability and ductilityIt has a strong electrical conductivity.Learn more about periodic table on
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A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.
Br2(g) + I2(g) ↔ 2IBr(g)
When the mixture has come to equilibrium, the concentration of iodine monobromide is
1.190 M. What is the equilibrium constant for this reaction at 350°C? Show step-by step explanation.
A) 3.55 × 10^3
B) 1.24
C) 1.47
D) 282
E) 325
The equilibrium constant for this reaction at 350°C is D. 282.
Equilibrium constantA dynamic chemical system approaches chemical equilibrium constant when enough time has passed and its composition no longer exhibits any discernible propensity to change further. The equilibrium constant of a chemical reaction is the value of its reaction quotient in this condition. The equilibrium constant is independent of the initial analytical concentrations of the reactant and product species in the mixture for a specific set of reaction conditions. Understanding equilibrium constants is crucial for comprehending many chemical systems as well as biological processes like the transport of oxygen by hemoglobin in the blood and the maintenance of acid-base homeostasis in the human body. There are many different kinds of equilibrium constants, including stability constants, formation constants, binding constants, association constants, and dissociation constants.
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A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.
Br2(g) + I2(g) ↔ 2IBr(g)
When the mixture has come to equilibrium, the concentration of iodine monobromide is
1.190 M. What is the equilibrium constant for this reaction at 350°C? Show step-by step explanation.
A) 3.55 × 10^3
B) 1.24
C) 1.47
D) 282
E) 325
Water is a(n)______ molecule, and it easily dissolves _______ molecules.
Which of the following will increase entropy in a reaction?
Group of answer choices
A. Using a larger particle
B. heating up the reaction
C. cooling down the reaction
D. Making less moles of products than there were reactants.
The condition that will increase the entropy in a reaction is heating up the reaction (option B).
What is entropy?Entropy in chemistry is the measure or degree of the disorder or randomness present in a chemical system.
In a chemical reaction, reacting substances called reactants collide with one another to form products.
However, the degree at which the reactants collide with one another is referred to as the entropy of the reaction.
Therefore, the condition that will increase the entropy in a reaction is heating up the reaction i.e. increase in temperature.
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is Sn^2+ + Br2 ---> Sn^4+ + 2Br^- a spontaneous or non-spontaneous redox reaction?
Sn^2+ + Br2 ---> Sn^4+ + 2Br^- is referred to as a non-spontaneous redox reaction.
What is a Non spontaneous reaction?This type of reaction doesn't favor the formation of the product and must be endothermic.
In the reaction above under the given conditions, ΔG is positive and it is intended to form Sn(s) and Br(l) through the reduction of tin cation to make bromine liquid and tin solid. This therefore points to the direction of the reaction being non-spontaneous one.
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Suppose you have 4.0 moles of aqueous barium chloride, and you mix this with aluminum sulfate solution. How many moles of aluminum chloride can you produce?
Answer:
2.7
Explanation:
The equation of the reaction is
3 BaCl2 + Al2(SO4)3 = 3 BaSO4 + 2 AlCl3
So, frok the coefficients of the equation, the answer is 2.7
2.67 moles of aluminum chloride can be produce if we have 4.0 moles of aqueous barium chloride, and we mix this with aluminum sulfate solution.
The balanced chemical reaction is :
3BaCl₂ + Al₂(SO₄)₃ ---> 3BaSO₄ + 2AlCl₃
When aqueous barium chloride is mixed with aluminum sulfate solution, a double displacement reaction occurs. The barium ions from barium chloride react with the sulfate ions from aluminum sulfate to form insoluble barium sulfate precipitate. At the same time, the aluminum ions from aluminum sulfate react with the chloride ions from barium chloride to form aluminum chloride.
Given :
Number of Moles of BaCl₂ = 4.0 moles
From the balanced chemical reaction,moles of AlCl₃:
= (4.0 moles BaCl₂) (2 moles AlCl₃/3 moles BaCl₂)
= 2.67 moles AlCl₃
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Your first post will be about one of the following topics: how stoichiometry is used
in formulating airbags, producing contrails, or formulating rocket engines .It must
be a minimum of 1 paragraph (at least 6-8 complete sentences), use lesson
specific vocabulary, and be classroom appropriate.
Stoichiometry is used in formulating airbags that shows relationship between product and reactants.
How stoichiometry is used in formulating airbags?
The quick chemical decomposition of solid sodium azide (NaN3) that allows the air bag to inflate fast at any time when the car hit anything. The decomposition reaction is initiated in a car by a small ignition that occurs due to collision sensing mechanism. The nitrogen gas produced during the reaction inflates the air bag which protect the person in the car.
So we can conclude that Stoichiometry is used in formulating airbags that shows relationship between product and reactants.
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Stoichiometry is important in formulating airbags, producing contrails, or formulating rocket engines so as to ensure the required amount of products are formed.
What is stoichiometry?Stoichiometry is the molar relationship between the reactants and products of a reaction.
It is the ratio in which moles of reactants of a reaction combine to form moles of products.
Stoichiometry is important in determining the amount of reactants required to produce a given amount of products.
For example, stoichiometry is important in formulating airbags, producing contrails, or formulating rocket engines in order to ensure the mass of reactants used is enough to produce the required products.
In conclusion, stoichiometry of a reaction provides the knowledge about the amount of reactants required to form products.
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If you mix 20.0 mL of a 3.00 M sugar solution with 30.0 mL of a 6.38 M sugar solution, you will end up with a sugar solution of ______ M
Taking into account the definition of molarity, the final sugar solution has a concentration of 5.028 M.
Definition of molarityMolar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
molarity= number of moles÷ volume
Molarity is expressed in units [tex]\frac{moles}{L}[/tex].
This caseIn this case, you mix 20.0 mL (0.02 L) of a 3.00 M sugar solution with 30.0 mL (0.03 L) of a 6.38 M sugar solution. To know the concentration of the sugar solution, you need to find the total moles of sugar solution from the mixtures as follow:
0.02 L× 3 M= 0.06 moles of sugar.0.03 L× 6.38 M= 0.1914 moles of sugar.total moles of sugar solution= 0.06 moles + 0.1914 moles= 0.2514 moles.Now, the total volume of the solution is calculated adding the volume of the two solutions:
total volume= 20 mL + 30 mL= 50 mL= 0.05 L
Replacing the values inf the definition of molarity:
molarity= 0.2514 moles÷ 0.05 L
Solving:
molarity= 5.028 M
Finally, the final sugar solution has a concentration of 5.028 M.
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Anyone know this please and thank you
Answer:
The correct answer is a hypothesis.
Perform the following operation and express the answer in scienfific notation 7.5x1-^9 - 2.5 x 10^8
Write equations that show NH3 as both a conjugate acid and a conjugate base.
Answer:
hope this helps
Explanation:
˙˚ʚ(´◡`)ɞ˚˙
How could you prepare 4-methyl-3-hexanone from ketone containing no more than six carbon atom?
First base abstract a proton from acidic hydrogen gives carbanion.
What is a carbon atom?
A carbon chain's fundamental carbon atoms are those at each end. For instance, butane contains two basic carbon atoms. A secondary carbon atom, represented by the symbol 2°, is a carbon atom joined to two more carbon atoms.The first electron shell of carbon has two electrons, whereas the second one contains four of the available eight spaces. Carbon has two electron shells. Atoms share their outermost shell's electrons when they combine to form bonds. Since the outer shell of carbon has four vacant spaces, it can form bonds with four additional atoms.The first two electrons fill the inner shell, which is the conduction (inner) shell, and the remaining four are left in the second shell, which is the valence (outer) shell because carbon has an atomic number of six (six protons and six electrons in a neutral atom).Here First base abstract, a proton from acidic hydrogen gives carbanion
Which undergoes enolate form, then it reacts with CH3I, gives4-methyl-3-hexanone as below:
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Aluminum has a face-centered cubic lattice with all atoms at lattice points. Its atomic mass is 26.982 amu. (4 r = 1(2)^1/2 ; Avogadro's # is 6.022 x 10^23)
a) If each aluminum atom has a radius of 143 pm, what is the edge length of the unit cell?
b) Calculate the density of aluminum metal.
(a) The edge length of the unit cell is 286 pm.
(b) The the density of aluminum metal is 1.27 x 10⁻²³ g/cm³.
What is edge length of the aluminum atom?
The edge length of the aluminum atom is calculated as follows;
a = 2r
where;
r is the radius of the atoma is edge lengtha = 2 x 143 pm = 286 pm
Volume of the aluminum atomV = a³
V = (286 x 10⁻¹²)³
V = 2.34 x 10⁻²⁹ m³
Density of the aluminum metalρ = ZM/VN
where;
Z is 4 for face-centered cubicM is mass of aluminum atom (g/mol), 26.982 amu = (1.66 x 10⁻²⁴ x 26.982) = 4.479 x 10⁻²³ g/molV is volumeN is Avogadro's numberρ = (4 x 4.479 x 10⁻²³) / ( 2.34 x 10⁻²⁹ x 6.023 x 10²³)
ρ = 1.27 x 10⁻¹⁷ g/m³
ρ = 1.27 x 10⁻¹⁷ g/m³ x (1 m³ / 10⁶ cm³)
ρ = 1.27 x 10⁻²³ g/cm³
Thus, the edge length of the unit cell is 286 pm and the the density of aluminum metal is 1.27 x 10⁻²³ g/cm³.
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On a sunny day, you can sometimes see dust in the air. Explain why the dust moves.
Answer:
Explanation:
When wind passes through. the dust, the dust then also moves throughout the air, when you move and breath in a room, you create slight wind (like a fan moving to creating wind) and this slight wind moves the dust particles.
1. State the three factors that increase the rate of dissolving a solid substance in solution.
2. An oven-cleaning solution is 40.0% (by mass) NaOH.
If one jar of this product contains 458 g of solution, how much NaOH (by mass) does it contain?
Answer:
The rate of dissolving is influenced by several factors, including stirring, temperature of solvent, and size of solute particles.
Determine the osmotic pressure (atm) of an aqueous sugar solution with a
concentration of 2.5 M at 25 °C?
Answer:
61 atm
Explanation:
You can calculate osmotic pressure using the following equation:
π = i MRT
In this equation,
-----> π = osmotic pressure (atm)
-----> i = van't Hoff's factor
-----> M = molarity (M)
-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)
-----> T = temperature (K)
The van't Hoff's factor is the amount of ions the substance dissociates into. Since sugar does not dissociate, this value is 1. After converting Celsius to Kelvin, you can plug the values into the equation and simplify.
i = 1 R = 0.08206 atm*L/mol*K
M = 2.5 M T = 25 °C + 273.15 = 298.15 K
π = i MRT
π = (1)(2.5 M)(0.08206 atm*L/mol*K)(298.15 K)
π = 61 atm
Write the chemical equation for the autoionization of water and label the conjugate
acid-base pairs.
The equation for the autoionization of water is-
NH3 + H2O → NH4+ + OH− (H2O acts as an acid)
HCl + H2O → H3O+ + Cl− (H2O acts as a base)
What do you mean by the autoionization of water ?Autoionization of water, the autoionization constant Kw, and the relationship between [H⁺] and [OH⁻] in aqueous solutions.
Water can undergo autoionization to form and ions.
The expression for the autoionization constant is
[tex]The expression for the autoionization constant isK_\text{w}=[\text{H}_3\text{O}^+][\text{OH}^-]\quad\quad\text{(Eq. 1)}K w =[H 3 O + ][OH − ][/tex]
In this way the autoionization of water,
NH3 + H2O → NH4+ + OH− (H2O acts as an acid)
HCl + H2O → H3O+ + Cl− (H2O acts as a base) is given.
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What is the maximum amount of methanol (CH3OH), in mol, that could be formed when 2 mol of carbon dioxide and 3 mol of hydrogen are placed in a
container and react according to the equation: CO2 + 3 H2 → CH3OH + H2O
a) 1
b) 2
C) 3
d) 5
Answer:
a) 1
Explanation:
Unfortunately, we are not given the limiting reagent. The limiting reagent is the reactant which is completely used up first. We can identify it by converting both reactants into the product. The reactant which produces the smallest amount of product is the limiting reagent.
You can convert the moles of CO₂/H₂ to moles CH₃OH using the mole-to-mole ratio. This ratio is made up the balanced equation coefficients of the relevant substances.
1 CO₂ + 3 H₂ -----> 1 CH₃OH + H₂O
2 moles CO₂ 1 moles CH₃OH
--------------------- x ---------------------------- = 2 moles CH₃OH
1 mole CO₂
3 moles H₂ 1 moles CH₃OH
------------------- x --------------------------- = 1 mole CH₃OH
3 moles H₂
Because H₂ produces the smallest amount of CH₃OH, it is the limiting reagent. This means that all the H₂ is used up before CO₂ runs out. Therefore, the actual amount of CH₃OH produced is 1 mole.
When 2 mol of carbon dioxide and 3 mol of hydrogen, then one mole of methanol will be produced. Therefore, option (a) is correct.
What is the limiting reagent?A limiting reagent is a substance or reactant that is completely consumed in the completion of a chemical reaction and is also known as limiting reactant.
When reactants are not present in stoichiometric quantities, the limiting reactant decides the maximum amount of product that can be formed in a chemical reaction from the reactants.
Given the balanced chemical equation of formation of methanol:
CO₂ + 3 H₂ → CH₃OH + H₂O
From the above reaction, we can say that 1 mole of carbon dioxide reacts with three moles of hydrogen gas to form one mole of methanol.
Then, 2mol of carbon dioxide will react with 6 moles of hydrogen gas.
But we have only 3 mol of hydrogen gas therefore, hydrogen gas acts as a limiting reagent that will be consumed first.
Therefore, three moles of hydrogen gas will produce one mole of methanol maximum.
Learn more about limiting reagents, here:
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